Find the measure of the missing angles

The best assessment of the linearity of the relationship between the day of the month and account balance would be "Because the residual plot has no obvious pattern, and the scatterplot appears linear, it is appropriate to use the line of best fit to predict the account balance based on the day of the month."The correct answer is option C.

When assessing linearity, it is important to examine both the scatterplot and the residual plot. The scatterplot is used to visualize the relationship between the variables, while the residual plot helps us assess the appropriateness of a linear model by examining the pattern of the residuals (the differences between observed and predicted values).

If the scatterplot appears reasonably linear, it suggests that there is a linear relationship between the variables. In this case, since the scatterplot appears linear, it supports the use of a linear model to predict the account balance based on the day of the month.

Furthermore, the residual plot is used to check for any patterns or systematic deviations from the line of best fit. If the residual plot exhibits no obvious pattern and the residuals appear randomly distributed around zero, it indicates that the linear model captures the relationship adequately.

Therefore, if the residual plot shows no obvious pattern, it provides further evidence in favor of using the line of best fit to predict the account balance based on the day of the month.

In conclusion, when the scatterplot appears linear and the residual plot shows no obvious pattern, it is appropriate to use the line of best fit to predict the account balance based on the day of the month.

For more such questions on linearity,click on

https://brainly.com/question/2030026

#SPJ8  

Answer:

person above

Step-by-step explanation:

the obvious

Answer:

k = 6

Step-by-step explanation:

-3=k+3

1) you must isolate the variable (k)

2) subtract each side by 3, to get k=-6

> -3-3=k+3-3

-6=k

now your variable is isolated, so you have your answer.

Answer:

\(5x^4-\frac{25x^4}{x+8}+\frac{5x^5}{(x+8)^2}\)

Step-by-step explanation:

\(f(x)=x^5\\f'(x)=5x^4\\g(x)=1-\frac{5}{x+8}\\g'(x)=\frac{5}{(x+8)^2}\\\\\frac{d}{dx}f(x)g(x)\\\\=f'(x)g(x)+f(x)g'(x)\\\\=5x^4(1-\frac{5}{x+8})+x^5(\frac{5}{(x+8)^2})\\\\=5x^4-\frac{25x^4}{x+8}+\frac{5x^5}{(x+8)^2}\)

Answer:I can’t see

Step-by-step explanation:show fullscreen

7π/12 lies in the second quadrant, so we expect cos(7π/12) to be negative.

Recall that

\(\cos^2x=\dfrac{1+\cos(2x)}2\)

which tells us

\(\cos\left(\dfrac{7\pi}{12}\right)=-\sqrt{\dfrac{1+\cos\left(\frac{7\pi}6\right)}2}\)

Now,

\(\cos\left(\dfrac{7\pi}6\right)=-\cos\left(\dfrac\pi6\right)=-\dfrac{\sqrt3}2\)

and so

\(\cos\left(\dfrac{7\pi}{12}\right)=-\sqrt{\dfrac{1-\frac{\sqrt3}2}2}=\boxed{-\dfrac{\sqrt{2-\sqrt3}}2}\)

Answer:

\(\text{27}\)

Step-by-step explanation:

Given that :

\(\text{Dimension of poster board} = 1 \ \text{yd} \ \text{by} \ 1 \ \text{yd}\)

\(\text{Dimension of each poster board} = \dfrac{1}{3} \ \text{yd} \ \text{by} \ \dfrac{1}{9} \ \text{yd}\)

Number of poster signs that can be cut :

\(\text{Area of poster sign} = \dfrac{1}{3} \times \dfrac{1}{9} = \dfrac{1}{27} \ \text{yard}^2\)

\(\text{Area of poster board} = 1 \ \text{yard}^2\)

Number of poster signs that can be cut :

\(\dfrac{\text{Area of poster board}}{\text{Area of poster sign}}\)

\(1 \ \text{yard}^2\div (\dfrac{1}{27} ) \ \text{yard}^2\)

\(1 \div \dfrac{1}{27}\)

\(1 \times \dfrac{27}{1}\)

\(\bold{= 27 \ poster \ signs}\)

suppose they are independent of a geometric random variable with parameter p. Let M = max(x1,....,xN) (a) Find P{M<} by conditioning on N is  nλe^(-nλx)

Given fx (x) = λe^λx

Fx (x) = 1 – e^-λx      x…0

To find distribution of Min (X1,….Xn)

By applying the equation

fx1 (x) = [n! / (n – j)! (j – 1)!][F(x)]^j-1[1-F(x)]^n-j f(x)

For minimum j = 1

[Min (X1,…Xn)] = [n!/(n-1)!0!][F(x)]^0[1-(1-e^-λx)]^n-1λe^-λx

= ne^[(n-1) λx] λe^(λx)

= nλe^(-λx[1+n-1])

= nλe^(-nλx)

learn more about of variable here

https://brainly.com/question/6472483

#SPJ4

Answer:

y-intercept = 7

Step-by-step explanation:

y intercept is where the line meets with the y axis which is the vertical axis.

hope this helped!

Answer:

I think the answer is 5 i haven't learned this yet but I think the answer is 5 if not can someone correct me ?

Step-by-step explanation:

Answer:

the answer should be 5 if i not correct sorry

Step-by-step explanation:

Answer:

Hi

please mark brainliest ❣️

Thanks

Step-by-step explanation:

10 + x / 3 = 12

Cross multiply

10 + x = 12× 3

10 + x = 36

Collect like terms

x= 36 - 10

x = 26

1. In this case, we want the reliability to be 95%, so the probability of not breaking down is 0.95.

2. Probability of no breakdowns = (reliability of a single machine)^3. Probability of at least one breakdown = 1 - Probability of no breakdowns

1. To determine how often the computer should be scheduled for maintenance, we need to consider the reliability and the desired level of operational condition. Since the duration for trouble-free operation follows a gamma distribution with a mean of 40 days, this means that, on average, the computer can operate for 40 days before a breakdown occurs.

To ensure operational condition with a 95% probability, we can calculate the maintenance interval using the concept of reliability. The reliability represents the probability that the machine will not break down within a certain time period. In this case, we want the reliability to be 95%, so the probability of not breaking down is 0.95.

Using the gamma distribution parameters, we can find the corresponding reliability for a specific time duration. By setting the reliability equation equal to 0.95 and solving for time, we can find the maintenance interval:

reliability = 0.95

time = maintenance interval

Using reliability and the gamma distribution parameters, we can calculate the maintenance interval.

2. To calculate the probability that at least one of the three machines will break down within the first scheduled maintenance time, we can use the complementary probability approach.

The probability that none of the machines will break down within the first scheduled maintenance time is given by the reliability of a single machine raised to the power of the number of machines:

Probability of no breakdowns = (reliability of a single machine)^3

Since the breakdown times between the machines are statistically independent, we can assume that the reliability of each machine is the same. Therefore, we can use the reliability calculated in the first part and substitute it into the formula:

Probability of at least one breakdown = 1 - Probability of no breakdowns

By calculating this expression, we can determine the probability that at least one of the three machines will break down within the first scheduled maintenance time.

For more such questions on Probability

https://brainly.com/question/23286309

#SPJ8

The numbers 0, 1, and -1 are zeros of multiplicity 1.

What is quadratic equation?

it's a second-degree quadratic equation which is an algebraic equation in x. Ax2 + bx + c = 0, where a and b are the coefficients, x is the variable, and c is the constant term, is the quadratic equation in its standard form. A non-zero term (a 0) for the coefficient of x2 is a prerequisite for an equation to be a quadratic equation. The x2 term is written first, then the x term, and finally the constant term is written when constructing a quadratic equation in standard form. In most cases, the numerical values of letters a, b, and c are expressed as integral values rather than fractions or decimals.

To find the zeros of the function \(y=7x^3-7x\), we can set y equal to zero and solve for x:

\(7x^3 - 7x = 0\)

Factor out 7x:

\(7x(x^2 - 1) = 0\)

Factor the quadratic expression:

7x(x - 1)(x + 1) = 0

The zeros of the function are the values of x that make y equal to zero. From the factored expression, we see that the zeros are:

x = 0 (with multiplicity 1)

x = 1 (with multiplicity 1)

x = -1 (with multiplicity 1)

Therefore, the correct choice is: The numbers 0, 1, and -1 are zeros of multiplicity 1.

Learn more about quadratic equation , by the following link.

https://brainly.com/question/1214333

#SPJ1

Answer:

I think its C

Step-by-step explanation:

The value of given expressions is -4\(x^{-2}\) + 3\(y^{0}\) = 19 and 2\(x^{0}\)\(y^{-2}\) = 0.08

Simplifying an equation is simply another way of saying solving a math problem. When you simplify a phrase, you are attempting to write it in the simplest way feasible. In conclusion, there should be no more adding, subtracting, multiplying, or dividing to do.

Given expression 1. -4\(x^{-2}\) + 3\(y^{0}\)  2. 2\(x^{0}\)\(y^{-2}\)

Expression for x =2 and y=5

-4x-2 + 3y0

= -4(2)-2 + 3(5)0

= 16+3

=19

Now

2x0y-2

= 2(2)0x(5)-2

= 2 x (1/25)

= 2 x 0.04

= 0.08

Therefore the value of given expressions is -4\(x^{-2}\) + 3\(y^{0}\) = 19 and 2\(x^{0}\)\(y^{-2}\) = 0.08

To learn more about simplification visit

https://brainly.com/question/4356706

#SPJ1

Answer:

See Explanation

Step-by-step explanation:

Please note that I'll replace all � with +

1. |10|

This implies the absolute value of 10 and it always returns the positive value;

Hence;

\(|10| = 10\)

2. |-4|

Using the same law applied in (1)

\(|-4| = 4\)

3.  5/8 - 3/8 = ?

Take LCM

\(= \frac{5 - 3}{8}\)

Subtract the numerator

\(= \frac{2}{8}\)

Divide the numerator and denominator by 2

\(= \frac{1}{4}\)

Hence:

\(\frac{5}{8} - \frac{3}{8} = \frac{1}{4}\)

4. 7/8 - 5/6

Take LCM

\(= \frac{21 - 20}{24}\)

\(= \frac{1}{24}\)

Hence;

\(\frac{7}{8} - \frac{5}{6} = \frac{1}{24}\)

5. 6 * (-7/2)

\(= 6 * \frac{-7}{2}\)

Multiply the numerator

\(= \frac{-42}{2}\)

\(= -21\)

Hence:

\(6 * \frac{-7}{2} = -21\)

5. 6/5 /(-12/25)

\(= \frac{6}{5} / \frac{-12}{25}\)

Change the divide to multiplication

\(= \frac{6}{5} * \frac{-25}{12}\)

Divide 6 and 12 by 6

\(= \frac{1}{5} * \frac{-25}{2}\)

Divide 5 and 25 by 5

\(= \frac{1}{1} * \frac{-5}{2}\)

\(= \frac{-5}{2}\)

Hence;

\(\frac{6}{5} / \frac{-12}{25} = \frac{-5}{2}\)

6.  3 + 4^2  * 2

\(= 3 + 4^2 * 2\)

Solve the exponent

\(= 3 + 16 * 2\)

Apply B.O.D.M.A.S

\(= 3 + 32\)

\(= 35\)

\(3 + 4^2 * 2 = 35\)

7.  2/3 + 5/6

\(= \frac{2}{3} + \frac{5}{6}\)

Apply LCM

\(= \frac{4 + 5}{6}\)

\(= \frac{9}{6}\)

Divide the numerator and denominator by 3

\(= \frac{3}{2}\)

Convert to mixed fraction

\(= 1\frac{1}{2}\)

Hence;

\(\frac{2}{3} + \frac{5}{6} = 1\frac{1}{2}\)

8.  16 - 12/(-4)

\(= 16 - \frac{12}{-4}\)

Solve the fraction

\(= 16 - (-3)\)

Open the bracket

\(= 16 + 3\)

\(= 19\)

Hence;

\(16 - \frac{12}{-4} = 19\)

9.   -9(3w + x + 2)

\(= -9(3w + x + 2)\)

Open brackets: Distributive property

\(= -9*3w -9* x -9 * 2\)

\(= -27w -9 x -18\)

Hence;

\(-9(3w + x + 2) = -27w -9 x -18\)

10.  -2(w + 2) + 5w

\(= -2(w + 2) + 5w\)

Open bracket: using distributive property

\(= -2*w -2 * 2 + 5w\)

\(= -2w -4 + 5w\)

Collect Like Terms

\(= 5w-2w -4\)

\(= 3w -4\)

Hence;

\(-2(w + 2) + 5w = 3w- 4\)

11.   16x^2 + 8 + 10x + 2x^2 + 14x

\(= 16x^2 + 8 + 10x + 2x^2 + 14x\)

Collect Like Terms

\(= 16x^2 + 2x^2 + 10x + 14x+ 8\)

\(= 18x^2 + 24x + 8\)

Expand the expression

\(= 18x^2 + 12x + 12x + 8\)

Factorize:

\(= 6x(3x + 2) + 4(3x +2)\)

\(= (6x + 4)(3x +2)\)

Hence;

\(16x^2 + 8 + 10x + 2x^2 + 14x = (6x + 4)(3x +2)\)

12. b = -5 and y = 6

\(b + 9y =?\)

Substitute -5 for b and 6 for y

\(= -5 + 9 * 6\)

\(= -5 + 54\)

\(= 49\)

Hence;

\(b + 9y = 49\)

13.    y = -3

\(y^2 + 5y + 4 =?\)

Substitute -3 for y

\(= (-3)^2 + 5(-3) + 4\)

Open all brackets

\(= 9 -15 + 4\)

\(= -2\)

Hence;

\(y^2 + 5y + 4 = -2\)

14.  

\((-4)^3\)

Open bracket:

\(= -4 * -4 * -4\)

\(= -64\)

Hence;

\((-4)^3 = -64\)

\((-7)^2\)

Open bracket:

\(= -7 * -7\)

\(= 49\)

Hence;

\((-7)^2 = 49\)

15.  Express as fractions:

\(\frac{3}{5^3}\)

Evaluate the denominator

\(= \frac{3}{125}\)

Hence:

\(\frac{3}{5^3} = \frac{3}{125}\)

\((\frac{-1}{3})^2\)

Evaluate the exponent

\(= (\frac{-1}{3})*(\frac{-1}{3})\)

\(=\frac{1}{9}\)

Hence:

\((\frac{-1}{3})^2=\frac{1}{9}\)

16. Evaluate

\((-7)^0 =\)

Evaluate the exponent

\((-7)^0 = 1\)

\(2 * (1/3)^0\)

Evaluate the exponent

\(= 2 * 1\)

\(= 2\)

Hence;

\(2 * (1/3)^0 = 2\)

17. Evaluate

\(3v^2(-5v^4)\)

Open bracket

\(= 3 * v^2*-5* v^4\)

Reorder

\(= 3 *-5* v^4 * v^2\)

\(= -15* v^4 * v^2\)

Apply law of indices

\(= -15* v^{4 +2}\)

\(= -15* v^6\)

\(= -15v^6\)

Hence:

\(3v^2(-5v^4) = -15v^6\)

18.

\(2y^2w^4*6y*2w^8\)

Rewrite as

\(2 *y^2 * w^4*6 * y*2 * w^8\)

Reorder the terms

\(=2*6 * w^4 * w^8*y^2 * y*2\)

\(=12 * w^4 * w^8*y^2 * y*2\)

Apply law of indices

\(=12 * w^{4+8} *y^{2+2}\)

\(=12 * w^{12} *y^4\)

\(=12 w^{12} y^4\)

Hence:

\(2y^2w^4*6y*2w^8 =12 w^{12} y^4\)

19.

\((\frac{4p^3}{3p^7})^{-2}\)

Apply law of indices

\(= (\frac{4p^{3-7}}{3})^{-2}\)

\(= (\frac{4p^{-4}}{3})^{-2}\)

Apply law of indices

\(= (\frac{4}{3p^4})^{-2}\)

Apply law of indices

\(= (\frac{3p^4}{4})^{2}\)

\(= (\frac{3p^4}{4}) * (\frac{3p^4}{4})\)

Evaluate

\(= \frac{9p^8}{16}\)

Hence;

\((\frac{4p^3}{3p^7})^{-2} = \frac{9p^8}{16}\)

20.

\(\frac{x^{-2}}{x^{-3}}\)

Apply law of indices

\(= x^{-2 - (-3)}\)

\(= x^{-2 +3}\)

\(= x^1\)

\(= x\)

Hence:

\(\frac{x^{-2}}{x^{-3}} =x\)

Answer: So 5 + x = 8 beacase x is 3

Step-by-step explanation:

please mark this answer as brainlist

The value of the expression is 15.625.

We have,

Expression:

(2.5)³

The base is 2.5 and the power is 3.

We always combine the like terms in an expression when we simplify.

We also keep all the like terms on one side of the expression if we are dealing with two sides of an expression.

This can be written as,

= 2.5 x 2.5 x 2.5

Convert the decimals into fractions.

= 25/10 x 25/10 x 25/10

Simplify the fractions.

= 15.625

Thus,

The value of the expression is 15.625.

Learn more about expressions here:

https://brainly.com/question/3118662

#SPJ4

274.32 is the answer. Tell me if I need to be more precise.

Answer:

9/8

Step-by-step explanation:

.........................

Answer:

The  probability is  \(P(12.7 < x < 16.8 ) = 0.45\)

Step-by-step explanation:

From the question we are told that

The completion times for a job task range from 10.1 minutes to 19.2 minutes

Generally given that the completion times is uniformly distributed then  the probability that it will require between 12.7 and 16.8 minutes is mathematically represented as

         \(P(12.7 < x < 16.8 ) = \frac{ 16.8 - 12.7}{ 19.2 - 10.1 }\)

          \(P(12.7 < x < 16.8 ) = 0.45\)

Answer:

44 square units

Step-by-step explanation:

The area of a trapezoid with bases b₁ and b₂ and height h is given by the formula

\(A=\left(\dfrac{b_1+b_2}{2}\right)h\)

If you're wondering how we get this formula, check the attached illustration (remember the area of a parallelogram is its base multiplied by its height)! Moving on to our trapezoid, the pairs of points (-5,-3)(4,-3) and (6,-7)(-7,-7) form two horizontal segments, which form b₁ and b₂, and our height is the distance between the y-coordinates -3 and -7, which is 4. We can find b₁ and b₂ by finding the distance between the x coordinates in their pairs of points:

\(b_1=|-5-4|=|-9|=9\\b_2=|6-(-7)|=|6+7|=13\)

Putting it altogether:

\(A=\left(\dfrac{9+13}{2}\right)(4)=\left(\dfrac{22}{2}\right)(4)=(11)(4)=44\)

So the area of our trapezoid is 44.

The annual interest rate for a simple interest loan would be 16%.

Answer:

could you show the answers

Step-by-step explanation:

= 1/6 mi + 4/9mi

= 9 + 24

54

=33/54mi

= 9.444444...

Answer:

pretty sure its C

Step-by-step explanation:

I think this because 1600 rounds up to 2000 and 1483 rounds down to 1000 and 2000>1000

Answer:

40

Step-by-step explanation:

angles QPR and RPS are complimentary, so they equal 90, or angle QPS, so you can set up the equations like so:

7x - 9 + 4x + 22 = 90

Combine like terms:

11x + 13 = 90

Subtract 13 from each side:

11x = 77

Divide each side by 11:

x=7

Then use this value in the angle that you are finding:

7(7) - 9

49 - 9

40

40 is your answer

Hope this helps!

Answer: The Associative Property

Step-by-step explanation:

Example:

\(a * (b * c) = (a * b) *c\)

\(2 *(4 * 5) = (2 * 4) * 5\)

Answer:

From the question, Stacey deposits $2600 six times over a thirty year period since she makes the deposit every five years. Her amount accures by the formular. A = P(1+r/n)^nt. Where her principal P = $2,600. Rate, r =6% =0.06. Time = 30 years and the period of compounding per unit time, n = 6 years. So we have A =2, 600(1+(0.06/6))^(6*30) = 2, 600 (1 + 0.01)^(180) = 2600* 5.9958 = $15, 587. To the nearest cent we have $15, 590.

Step-by-step explanation:

:)

The types of discontinuities are: removable discontinuity at x = -3 and vertical asymptotes at x = 0 and x = 3.

A. To find f(x) + g(x), we add the two functions together:

f(x) + g(x) = (x + 2)/(x^2 - 9) + 11/(x^2 + 3x)

To add these fractions, we need a common denominator. The common denominator in this case is (x^2 - 9)(x^2 + 3x). So, we rewrite the fractions with the common denominator:

f(x) + g(x) = [(x + 2)(x^2 + 3x) + 11(x^2 - 9)] / [(x^2 - 9)(x^2 + 3x)]

Simplifying the numerator:

f(x) + g(x) = (x^3 + 3x^2 + 2x^2 + 6x + 11x^2 - 99) / [(x^2 - 9)(x^2 + 3x)]

Combining like terms:

f(x) + g(x) = (x^3 + 16x^2 + 6x - 99) / [(x^2 - 9)(x^2 + 3x)]

B. To find the excluded values, we look for values of x that would make the denominators zero, as division by zero is undefined. In this case, the excluded values occur when:

(x^2 - 9) = 0  --> x = -3, 3

(x^2 + 3x) = 0 --> x = 0, -3

So, the excluded values are x = -3, 0, and 3.

C. To classify each type of discontinuity, we examine the excluded values and the behavior of the function around these points.

At x = -3, we have a removable discontinuity or hole since the denominator approaches zero but the numerator doesn't. The function can be simplified and defined at this point.

At x = 0 and x = 3, we have vertical asymptotes. The function approaches positive or negative infinity as x approaches these points, indicating a vertical asymptote.

Therefore, the types of discontinuities are: removable discontinuity at x = -3 and vertical asymptotes at x = 0 and x = 3.

For more questions on vertical .

https://brainly.com/question/30195815

#SPJ8