The values of angles are measured and classified as follows:
1) ∠RQU = 124°(obtuse)
2) ∠TQU = 34° (acute)
3) ∠UQS = 89° (acute)
What is an angle?
An angle is a figure in plane geometry that is created by two rays or lines that have a shared endpoint. The two rays are termed the sides of an angle, and the common termination is called the vertex. Angles are typically expressed as degrees (°). A "protractor" is a crucial geometrical instrument that aids in measuring angles in degrees. Two sets of numbers on a protractor are oriented in opposition to one another. On the outside rim, one set goes from 0 to 180 degrees, while on the inner rim, the other set goes from 180 to 0 degrees.
We are asked to find the measure of the following angles:
1) ∠RQU
The side QR is aligned with the 0° line of the protractor.
Now find the angle through which the side QU passes.
Take the reading of the outer rim.
∠RQU = 124°
It is greater than 90°, so it is an obtuse angle.
2) ∠TQU
∠TQU = ∠RQU - ∠RQT
∠RQT = 90°
so,
∠TQU = ∠RQU - ∠RQT = 124 - 90 = 34°
It is less tah 90°, so it is an acute angle.
3)∠UQS
∠UQS = ∠RQU - ∠RQS
∠RQS = 35°
∠UQS = ∠RQU - ∠RQS = 124 - 35 = 89°
This is also an acute angle.
Therefore the values of angles are measured and classified as follows:
1) ∠RQU = 124°(obtuse)
2) ∠TQU = 34° (acute)
3) ∠UQS = 89° (acute)
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can anyone help me with this?
If the first and the last term of an arithmetic progression, with common difference
\(1 \times 1\frac{1}{2} \)
, are
\(? \times 2\frac{1}{2} \)
and 19 respectively, how many term has the sequence?
The number of terms in the given arithmetic sequence is n = 10. Using the given first, last term, and the common difference of the arithmetic sequence, the required value is calculated.
What is the nth term of an arithmetic sequence?The general form of the nth term of an arithmetic sequence is
an = a1 + (n - 1)d
Where,
a1 - first term
n - number of terms in the sequence
d - the common difference
Calculation:The given sequence is an arithmetic sequence.
First term a1 = \(1\frac{1}{2}\) = 3/2
Last term an = \(2\frac{1}{2}\) = 5/2
Common difference d = 1/9
From the general formula,
an = a1 + (n - 1)d
On substituting,
5/2 = 3/2 + (n - 1)1/9
⇒ (n - 1)1/9 = 5/2 - 3/2
⇒ (n - 1)1/9 = 1
⇒ n - 1 = 9
⇒ n = 9 + 1
∴ n = 10
Thus, there are 10 terms in the given arithmetic sequence.
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Disclaimer: The given question in the portal is incorrect. Here is the correct question.
Question: If the first and the last term of an arithmetic progression with a common difference are \(1\frac{1}{2}\), \(2\frac{1}{2}\) and 1/9 respectively, how many terms has the sequence?
please help and thank you
Answer:
I think its 368.28 cubic inches
Step-by-step explanation:
I scared of exam how do i do
Answer:
.
Step-by-step explanation:
x + y = 8 and y = -x - 1
Answer:
It is given to us that
y =-x-1
put this value in the given equation we will get ouelr answer
x + y =8
x + -x -1 =8
sorry mate we doesn't get our answer because x will be cancelled here
what is the height of figure 1?
Answer:
4
Step-by-step explanation:
need help on these questions. Help anyone, please!
Step-by-step explanation:
a linear function is defined as
y = ax + b
the variable x is only occurring with the exponent of 1.
this represents a straight line in a graphic representation (hence the name "linear").
if the exponent of the variable x is not 1, then it is not a linear function
P : y = 3/x + 2³
it is not linear.
the exponent of x = -1, as 1/x = x^-1. -1 is different to 1, which would be needed as exponent of x to make it linear.
Q : y = (1/3)x² + 3
it is not linear.
the exponent of x = 2. and 2 is different to 1, which would be needed as exponent of x to make it linear.
GIVING 35$ TO WHOEVER DOES THIS!
Answer:
A = 2(7) + (1/2)(4)(4 + 9) = 14 + 26 = 40 m²
Consider the trajectory tracking problem with acceleration being the control input: x [t + 1] 1 δ x [t] 0 = + u[t]. v [t + 1] 0 1 v [t] δ Let x[t] = vt be the reference trajectory to track.
a) Reformulate the state-space model with the position and speed errors being the state.
b) Using the reformulated model, find a linear controller that stabilizes the system.
c) Find a linear controller that destabilizes the system.
Given the state-space model with acceleration being the control input,Let x [t + 1] 1 δ x [t] 0 = + u[t]. v [t + 1] 0 1 v [t] δWhere x[t] = vt is the reference trajectory to track.
The reference trajectory to track is x[t] = vt.The position and speed errors being the state can be found using the following steps. State-space model of the system: {x[t+1]=x[t] + δv[t]v[t+1]=v[t] + δu[t]}Let the position and speed errors be e1[t] = x[t] - v*tand e2[t] = v[t] - v.
From the above state-space model:{x[t+1] = v*t + e1[t] + δv[t]v[t+1] = v + e2[t] + δu[t]}Differentiate e1[t] and e2[t] with respect to time t: {e1[t + 1] = e1[t] + δe2[t + 1] = e2[t] + δNow, we can write the state-space model with errors in state:{e1[t + 1] e2[t + 1] = 1 δ 0 1 e1[t] e2[t] + 0 δ 1 0 δ u[t].
Now, a linear controller that stabilizes the system can be found as below:Let A = [1 δ; 0 1] and B = [0; δ].Let the state-feedback control law be given by u[t] = -K[e1[t]; e2[t]] such that the eigenvalues of the closed-loop system are negative. Therefore,K can be found using the following formulae:
K = (B'PB + R)^{-1}(B'PA)
where,P is a positive definite solution of the algebraic Riccati equationA'PA - P + Q - A'PB(B'PB + R)^{-1}B'PA = 0andR and Q are positive definite matrices.The destabilizing controller can be found by using K = [0 1].Then, the closed-loop system becomes{x[t+1] = (1- δ^2) x[t] + δv[t]v[t+1] = (1- δ^2) v[t] + δu[t]}.
In order to stabilize the system, a linear controller has been found using the reformulated model. The destabilizing controller can also be found. Thus, this is how the state-space model can be reformulated and linear controllers can be found to stabilize or destabilize the system.
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I want you to make sure that you have learned the basic math used in establishing the existence of Nash equilibria in mixed strategies. Hope that the following questions help! 1. First, please answer the following questions which by and large ask definitions. (a) Write the definition of a correspondence. (b) Write the definition of a fixed point of a correspondence. 1 (c) In normal form games, define the set of (mixed strategy) best replies for a given player i. Then define the "best reply correspondence," denoted by B in class. (d) Formally prove that a mixed strategy profile α∗ is a Nash equilibrium if and only if it is a fixed point of the (mixed strategy) best reply correspondence. 2. Now I ask about Brower's fixed point theorem, a well-known fixed point theorem which we didn't formally cover in class (but can be learned through this problem set!). (a) Formally state Brower's fixed point theorem. Find references by yourself if you don't know the theorem. You can basically copy what you found, but make sure that you define all symbols and concepts so that the statement becomes self-contained and can be understood by readers who do not have access to the reference you used. (b) Prove that Brower's fixed point theorem is a corollary of Kakutani's fixed point theorem. In other words, prove the former theorem using the latter. 3. When we discussed Kakutani's fixed point theorem in class, I stated several conditions and explained that the conclusion of Kakutani's theorem does not hold if one of the conditions are not satisfied, but only gave examples for some of those conditions. Now, in the following questions let us check that other conditions cannot be dispensed with (I use the same notation as in class in the following questions). (a) Provide an example without a fixed point in which the set S is not closed, but all other conditions in Kakutani's theorem are satisfied. Explain why this is a valid counterexample. 21 Recall that the concept of a fixed point is well-defined only under the presumption that a correspondence is defined as a mapping from a set to itself. 2 To be precise, when we require that "the graph of F be closed" in your example, interpret the closedness as being defined with respect to the relative topology in S².
1. Definition of a correspondence: A correspondence is a mathematical concept that defines a relation between two sets, where each element in the first set is associated with one or more elements in the second set. It can be thought of as a rule that assigns elements from one set to elements in another set based on certain criteria or conditions.
2. Definition of a fixed point of a correspondence: In the context of a correspondence, a fixed point is an element in the first set that is associated with itself in the second set. In other words, it is an element that remains unchanged when the correspondence is applied to it.
3. Set of (mixed strategy) best replies in normal form games: In a normal form game, the set of (mixed strategy) best replies for a given player i is the collection of strategies that maximize the player's expected payoff given the strategies chosen by the other players. It represents the optimal response for player i in a game where all players are using mixed strategies.
Best reply correspondence: The "best reply correspondence," denoted by B in class, is a correspondence that assigns to each mixed strategy profile the set of best replies for each player. It maps a mixed strategy profile to the set of best responses for each player.
4. Nash equilibrium and fixed point of best reply correspondence: A mixed strategy profile α∗ is a Nash equilibrium if and only if it is a fixed point of the best reply correspondence. This means that when each player chooses their best response strategy given the strategies chosen by the other players, no player has an incentive to unilaterally change their strategy. The mixed strategy profile remains stable and no player can improve their payoff by deviating from it.
5. Brower's fixed point theorem: Brower's fixed point theorem states that any continuous function from a closed and bounded convex subset of a Euclidean space to itself has at least one fixed point. In other words, if a function satisfies these conditions, there will always be at least one point in the set that remains unchanged when the function is applied to it.
6. Proving Brower's theorem using Kakutani's fixed point theorem: Kakutani's fixed point theorem is a more general version of Brower's fixed point theorem. By using Kakutani's theorem, we can prove Brower's theorem as a corollary.
Kakutani's theorem states that any correspondence from a non-empty, compact, and convex subset of a Euclidean space to itself has at least one fixed point. Since a continuous function can be seen as a special case of a correspondence, Kakutani's theorem can be applied to prove Brower's theorem.
7. Conditions for Kakutani's fixed point theorem: Kakutani's fixed point theorem requires several conditions to hold in order to guarantee the existence of a fixed point. These conditions include non-emptiness, compactness, convexity, and upper semi-continuity of the correspondence.
If any of these conditions are not satisfied, the conclusion of Kakutani's theorem does not hold, and there may not be a fixed point.
8. Example without a fixed point: An example without a fixed point can be a correspondence that does not satisfy the condition of closedness in the relative topology of S², where S is the set where the correspondence is defined. This means that there is a correspondence that maps elements in S to other elements in S, but there is no element in S that remains unchanged when the correspondence is applied.
This is a valid counterexample because it shows that even if all other conditions of Kakutani's theorem are satisfied, the lack of closedness in the relative topology can prevent the existence of a fixed point.
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How do you write a homogeneous system in parametric vector form?
A homogeneous system in parametric vector form:
(x1,x2,x3) = (s,s,-0.25s)
Parametric vector Form:
Any equation expressed as a parameter is a parametric equation. The general equation y = mx + b (where m and b are parameters) of a straight line in the form of a slope intersection is an example of a parametric equation. Example: one of the variables to t(x = t). Then we can rewrite this equation as y = t²+5.
So the set of parametric equations is x = t and y=t²+5.
According to the Question:
We are to solve them in parametric form.
X₁ + 2X₂ + 12X₃ = 0 ----------------------- (1)
2X₁ + X₂ + 12X₃ = 0 ----------------------- (2)
-X₁ + X₂ = 0 ----------------------- (3)
From equation 3 we get
x₁ = x₂
Substitute in 1 and 2 to get
3x₁ + 12x₃ = 0 and
3x₁ + 12x₃ = 0
Thus, we find these two equations are dependent. So we can have infinite solutions in parametric form only.
No unique solution is possible
Let x₁ = x₂ = s
Since 3x₁ +12x₃ = 0
x₁ = -4x₃
Or x₃ = -0.25s
So solution in parametric form is
(x1,x2,x3) = (s,s,-0.25s) for all real values.
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can sb help this is due tmw
not sure how the format is for the question but i think its
for the second column: y=2+2, y=6+2, y=7+2
for third column: 4, 8, 9
for the fourth column: (2,4), (6,8), (7,9)
for the according to the table:
(6,8), when his brother is 6 he is 8
for the graph: graph out the points (2,4), (6,8), (7,9)
another solution can be when he is 5 his brother is 3
(these should be right)
Answer:
8) Table
2...
y = 2 + 24(2,4)6...
y = 6 + 28(6,8)7...
y = 7 + 29(7,9)According to table 6, the point (6,8) means when his brother is 8 Trisjohn is 6
For the graph plot points at (2,4) (6,8) and (7,9) and connect with a straight line
When Kimarius is 5 his brother is 3
Have a lovely day :)
Give the least common multiple: 3a, 15 _____
Answer:
Answer: LCM of 3 and 15 is 15. 2.
Step-by-step explanation:
Hope this helps
When writing a repeating decimal as a fraction does the number of repeating digits you use matter?explain
Answer: no it does matter because it just the same numbers repeating
Step-by-step explanation:
Divide y^7/y^5. Write the quotient as one power. The variable is not equal to zero.
If it requires 10^4 silkworms to produce enough silk to make a scarf in a given amount of time, but it requires 10^19 silkworms to produce enough silk to make a sheet in the same amount of time. How many times more silkworms are needed for the sheet than the scarf? Hint: Divide number of silkworms to make a sheet by the number of silkworms to make a scarf.
Simplify: (6^-4)^6
Simplify: 13^4 x 14^4
When multiplying powers with the same base, keep the base and multiply the exponents. Explain, in complete sentences, whether this statement is true or false, and why.
f x + 12 ≤ 5 − y and 5 − y ≤ 2(x − 3), then which statement is true?
HELP I WILL HIVE BRAINLIEST!!!
Answer:
To me its A but i fully dont know im sorry if you get this wrong :(
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
need this one 18.3x9.27
Answer:
169.641
Step-by-step explanation:
Calculator
Answer:
18.3 x 9.27
= Use the multiplication method.
= 169.641
Use the Distance Formula and the Pythagorean Theorem to find the distance between each pair of points. M (10, −4) and N (2, −7)
Answer:
\(d=\sqrt{73}\approx8.54\)
Step-by-step explanation:
So we have the two points (10,-4) and (2,-7).
And we want to find the distance between them using the Distance Formula and the Pythagorean Theorem. Let's do each one individually.
1) Distance Formula.
The distance formula is:
\(d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2\)
Let's let (10,-4) be (x₁, y₁) and let's let (2,-7) be (x₂, y₂). So:
\(d=\sqrt{((2)-(10))+((-7)-(-4))^2\)
Simplify:
\(d=\sqrt{(2-10)^2+(-7+4)^2\)
Subtract:
\(d=\sqrt{(-8)^2+(-3)^2\)
Square:
\(d=\sqrt{64+9}\)
Add:
\(d=\sqrt{73}\)
Approximate:
\(d\approx8.54\)
So, the distance between (10,-4) and (2,-7) is approximately 8.54 units.
2) Pythagorean Theorem
Please refer to the graph.
So, we want to find the distance. This will be the length of the red line, or the hypotenuse.
First, let's find the length of the two legs.
The longer leg will be the difference between the two x-coordinates. So, the length of the longer leg is:
\((10-2)=8\)
Note: It doesn't matter if we do 2-10, which gives -8, since we are going to square anyways. Also, distance is always positive, so 8 would be our answer.
And the shorter leg is the difference between the two y-coordinates. Namely:
\((-7-(-4))=-3=3\)
So, the shorter leg is 3 units.
So now, we can use the Pythagorean Theorem, which is:
\(a^2+b^2=c^2\)
Substitute 8 for a and 3 for b. So:
\((8)^2+(3)^2=c^2\)
Square:
\(64+9=c^2\)
Add:
\(c^2=73\)
Take the square root:
\(c=\sqrt{73}\approx8.54\)
This is the same as our previous answer, so we can confirm that it's correct.
So, using both the distance formula and the Pythagorean Theorem, the distance between the two points is approximately 8.54.
And we're done!
Distance formula: d = √(x2-x1)²+(y2-y1)²
= √(2-10)²+(-7-(-4))²
= √-8²+(-3)²
= √64+9
= √73
≈ 8.54
Best of Luck!
PLEASE HELP I WILL GIVE BRAINLIEST
Answer:
206
Step-by-step explanation:
replace n in the sequence with 12 to find the 12th term
T 12 = (12)^2 + 5(12) + 2 = 206
Part 1: Use the first 4 rules of inference to provide
logical proofs with line-by-line justifications for the following
arguments.
(2) 1. A > (E > ~F)
2. H v (~F > M)
3. A
4. ~H /E > M
To provide Logical Proofs with line-by-line justifications for the following arguments,
Let's use the first 4 rules of inference.
Given below is the justification for each step of the proof with the applicable rule of Inference.
E > M1. A > (E > ~F) Premise2. H v (~F > M) Premise3. A Premise4. ~H Premise5. A > E > ~F 1, Hypothetical syllogism6.
E > ~F 5,3 Modus Ponens 7 .
~F > M 2,3 Disjunctive Syllogism 8.
E > M 6,7 Hypothetical SyllogismIf
A is true, then E must be true because A > E > ~F.
Also, if ~H is true, then ~F must be true because H v (~F > M). And if ~F is true,
Then M must be true because ~F > M. Therefore, E > M is a valid based on the given premises using the first four rules of inference.
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Samantha drives 4.2 miles each workday. How
far will Samantha drive after 18 workdays?
Answer:
75.6 miles
Step-by-step explanation:
Multiply 4.2 by 18
A Moving to another question will save this response. ≪ Question 16 4 points Jean purchases a house for $750,000 and is able to secure an interest only, 5 year fixed rate mortgage for $600,000 at 5% interest. After five year, the house appreciates to $792078.31. What is Jean's equity as a percent of the house value? Write your answer as a percent rounded to two decimal points without the % sign (e.g. if you get 5.6499%, write 5.65 ). Nastya takes our a 10-year, fixed rate, fully amortizing loan for $622422 with 5.2% interest and annual payments. What will be her annual payments? Round your answer to the nearest cent (e.g. if your answer is $1,000.567, enter 1000.57).
Nastya's annual payments on the loan will be approximately $7,350.68 (rounded to the nearest cent).
To find Jean's equity as a percent of the house value, we need to calculate the equity and divide it by the house value, then multiply by 100 to get the percentage.
Jean's equity is the difference between the house value and the mortgage amount. So, the equity is $792078.31 - $600,000 = $192,078.31.
To calculate the percentage, we divide the equity by the house value and multiply by 100: ($192,078.31 / $792078.31) * 100 = 24.26%.
Therefore, Jean's equity as a percent of the house value is 24.26%.
Now, let's move on to Nastya's question.
To calculate Nastya's annual payments on a fully amortizing loan, we need to use the formula for calculating the monthly payment:
P = r * PV / (1 - (1 + r)^(-n))
Where:
P = Monthly payment
r = Monthly interest rate (annual interest rate / 12)
PV = Present value of the loan
n = Total number of payments
Given:
PV = $622,422
Annual interest rate = 5.2%
n = 10 years
First, we need to convert the annual interest rate to a monthly interest rate: 5.2% / 12 = 0.43333%.
Next, we substitute the values into the formula and solve for P:
P = (0.0043333 * 622422) / (1 - (1 + 0.0043333)^(-10))
Using a calculator, we get P ≈ $7,350.68.
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when a positive integer is expressed in base 7, it is $ab 7$, and when it is expressed in base 5, it is $ba 5$. what is the positive integer in decimal?
17 is the integer expressed in base 10.
Given that,
The base 7 representation of a positive integer is AB and its base 5 representation is BA, where A and B are digits from 1 to 4, inclusive.
We have to find what is the integer expressed in base 10.
We know that,
Base 7 representation of a positive integer AB.
Can be written as 7A+B in base 10.
Base 5 representation of BA can be written as 5B+A in base 10.
So, 7A+B= 5B+A
6A=4B
A=2/3B
Now, A and B must be in 1 to 4.
The digits between 1 and 4 who are 2/3 of another is 2 and 3.
A=2 and B=3
So,
Base 7 is 23
And Base 5 is 32
Base 7 is 23 is 17 of base 10.
And Base 5 is 32 is 17 of base 10.
A=17
Therefore, 17 is the integer expressed in base 10.
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what is 5.951 to the hundred
Answer:
5.95
Step-by-step explanation:
The sum (5z+4) +(3z-6)
Answer:
(5z + 4) + (3z - 6) = 8z - 2
Step-by-step explanation:
(5z + 4) + (3z - 6)
Combine them by their like terms.
(5z + 3z) + (4 + (-6))
Add 5z and 3z.
8z + (4 + (-6))
Add 4 and -6.
8z + (-2)
Simplify.
8z - 2
Choose all numbers that are even.
A 17525 B 41680 C 55822 D 87318 E 93256
Any number ending with a even number is even
B. 41680
C. 55822
D. 87318
E. 93256
Answers are B, C, D, E
Question No: 6
A store offers a discount card for $65. If you have the card, you receive 10% off all purchases.
How much do you need to spend to make buying the card worth while?
x >
Answer:
$650
Step-by-step explanation:
You need to get at least $65 in savings to make the card worthwhile
10% of x is 65
multiply both sides by 10
100% of 10x is 65
get rid of 10x since we don't need that
100% of our answer is 650
Use the remainder theorem to find the remainder when f(x) = x3 − 5x2 + 4x − 10 is divided by (x + 5). Group of answer choices −10 −280 10 280
The remainder when f(x) = x³ - 5x² + 4x - 10 is divided by (x + 5) is (b) -280
How to determine the remainder of the polynomial division?The functions are given as
f(x) = x3 − 5x2 + 4x − 10 is divided by (x + 5)
Rewrite them as
f(x) = x³ - 5x² + 4x - 10 is divided by (x + 5)
Set the divisor to 0
So, we have
x + 5 = 0
Determine the value of x
This gives
x = -5
By the remainder theorem
Substitute x = -5 in the function f(x)
So, we have
f(-5) = (-5)³ - 5(-5)² + 4(-5) - 10
Evaluate the expression
f(-5) = -280
By the remainder theorem, this represents the remainder
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A jeweler had a fixed amount of gold to make bracelets and necklaces. The amount of gold in each bracelet is 6 grams and the amount of gold in each necklace is 16 grams. The jeweler made a total of 7 bracelets and necklaces using 72 grams of gold. Determine the number of bracelets made and the number of necklaces made .
the jeweler made ___ bracelets and ____ necklaces ?
Answer:
The jeweler made 4 bracelets and 3 necklaces!
Proof:
Bracelets : 4 * 6 = 24 grams
Necklaces: 3 * 16 = 48 grams
24 g + 48 g = 72 g