Find the line parallel to y = -3x + 2
that includes the point (4,3).
Simplify and solve for y.
y-3=-3(x-4)
y = − 3x + [?]

The representation, in polar coordinates, of the point (1 , 5pi/6) is (-1, 11pi/6).

It should be noted that polar coordinate simply means a coordinate system where the point on the plane is determined by a distance and reference point.

In this case, the representation, in polar coordinates, of the point (1 , 5pi/6) is (-1, 11pi/6). When graphing the polar coordinate, the pole should be moved in a direction opposite the given positive angle.

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Answer:

-1

Step-by-step explanation:

trust

The expression (f(x+h) - f(x)) / h simplifies to 2x + h - 3.

To find and simplify the expression (f(x+h) - f(x)) / h for the given function f(x) = x^2 - 3x + 2, we follow these steps:

1. Substitute f(x+h) and f(x) into the expression:

  (f(x+h) - f(x)) / h = [(x+h)^2 - 3(x+h) + 2 - (x^2 - 3x + 2)] / h

2. Expand and simplify the numerator:

  [(x^2 + 2xh + h^2) - 3(x+h) + 2 - (x^2 - 3x + 2)] / h

  = [x^2 + 2xh + h^2 - 3x - 3h + 2 - x^2 + 3x - 2] / h

  = [2xh + h^2 - 3h] / h

3. Factor out h from the numerator:

  h(2x + h - 3) / h

4. Cancel out the h in the numerator and denominator:

  2x + h - 3

Therefore, the expression (f(x+h) - f(x)) / h simplifies to 2x + h - 3.

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Answer:

-1,-2,-3,-6,1,2,3,6

Step-by-step explanation:

Answer:    -6, -3, -2, -1, 1, 2, 3, 6

Step-by-step explanation:

You take the factors of the last over the first.

Factors of 6: 1,2,3,6

Factors of 1:  1:

Put all the factors of 6 over 1, you will get the negative and positive versions

Possible roots:

±1, ±2, ±3, ±6

Possible Roots put in order:

-6, -3, -2, -1, 1, 2, 3, 6

The set of all vectors v that are orthogonal to u is the set of all vectors of the form v = (7s, s, t), where s and t are parameters.

Given u = (1, -7, 1) and v = (75, -1).

We are to determine all vectors v that are orthogonal to u.

Note: Two vectors are orthogonal if their dot product is zero.

v is orthogonal to u if v.

u = 0 ⇒ v1 + (-7)v2 + v3 = 0 ...... (1)

So, the set of all solutions of the linear system (1) above will give the set of all vectors that are orthogonal to u.

The augmented matrix of the system is:

\($$\left(\begin{array}{ccc|c}1&-7&1&0\\0&0&0&0\end{array}\right)$$\)

The system has infinitely many solutions.

The solution can be expressed as v = (7s, s, t).

where s and t are parameters.

Hence the answer is: The set of all vectors v that are orthogonal to u is the set of all vectors of the form v = (7s, s, t), where s and t are parameters.

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Answer:

x = 0.5

Step-by-step explanation:

2x - 3 = - 2 ( add 3 to both sides )

2x = 1 ( divide both sides by 2 )

x = \(\frac{1}{2}\) = 0.5

Answer:

x = 0.5

Step-by-step explanation:

Okay, let's start with writing down the equation:

2x - 3 = -2

Now, you can move the - 3 to the other side, and when you change the side, you change the sign, meaning the new sign for that would be positive.

2x = 3 - 2

2x = 1

Now, you have to divide both sides by 2, so you can get the x alone.

x = 0.5

Answer:

a(2+3) i thinkk :((

Step-by-step explanation:

John's savings amount as a function of time is S(t) = $24,000 / 25. Initially, he needs to save $24,000 for a new car. After the first month, he has saved $1,000. The savings amount is directly proportional to the time elapsed. The constant of proportionality is 1/24. Thus, John's savings amount can be determined based on the remaining amount he needs to save.

John's savings amount can be represented as a function of time and is proportional to the amount he still needs to save. Let's denote the amount John needs to save as N(t) at time t, and his savings amount as S(t) at time t. Initially, John needs to save $24,000, so we have N(0) = $24,000.

We know that John has saved $1,000 after the first month, which means S(1) = $1,000. Since his savings amount is proportional to the amount he still needs to save, we can write the proportionality as:

S(t) = k * N(t)

where k is a constant of proportionality.

We need to find the value of k to determine John's savings amount at any given time.

Using the initial values, we can substitute t = 0 and t = 1 into the equation above:

S(0) = k * N(0)  =>  $1,000 = k * $24,000  =>  k = 1/24

Now we have the value of k, and we can write John's savings amount as a function of time:

S(t) = (1/24) * N(t)

Since John's savings amount is proportional to the amount he still needs to save, we can express the amount he still needs to save at time t as:

N(t) = $24,000 - S(t)

Substituting the expression for N(t) into the equation for S(t), we get:

S(t) = (1/24) * ($24,000 - S(t))

Simplifying the equation, we have:

24S(t) = $24,000 - S(t)

25S(t) = $24,000

S(t) = $24,000 / 25

Therefore, John's savings amount at any given time t is S(t) = $24,000 / 25.

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The probability that either house sales or interest rates will increase in the next 6 months is estimated to be 0.79.

To find the probability that either house sales or interest rates will go up in the next 6 months, we can use the concept of union in probability theory. The union of two events A and B, denoted as A ∪ B, represents the event that either A or B or both occur.

Given the probabilities that house sales will increase (0.25) and interest rates on housing loans will go up (0.74), we need to calculate the probability of the union of these two events. However, we must consider that the events are not mutually exclusive, meaning that it is possible for both house sales to increase and interest rates to go up simultaneously.

To calculate the probability of the union, we can use the formula: P(A ∪ B) = P(A) + P(B) - P(A ∩ B), where P(A) represents the probability of event A, P(B) represents the probability of event B, and P(A ∩ B) represents the probability of both events A and B occurring.

Substituting the given probabilities into the formula, we have P(A ∪ B) = 0.25 + 0.74 - P(A ∩ B). Since we do not have the information regarding the joint probability of both events occurring (P(A ∩ B)), we cannot determine the exact probability of the union. However, we can say that the probability of either house sales or interest rates going up is estimated to be 0.79, assuming that the joint probability is not significant.

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The inequality five-sixths m minus five is less than one-half m plus 3 false is false for 35 option (B) is correct.

It is defined as the expression in mathematics in which both sides are not equal they have mathematical signs either less than or greater than known as inequality.

It is given that:

The set of integers:

S:{−24, 2, 20, 35}

Plug the value 35 in the inequality:

= 5/6(35 - 5) < 1/2(35 + 3)

= 5/6(30) < 1/2(38)

= 25 < 19  (False)

Thus, the inequality five-sixths m minus five is less than one-half m plus 3 false is false for 35 option (B) is correct.

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The graph of Y > -2x + 4 can be drawn by plotting points on a coordinate plane and connecting them with a dashed line. The dashed line should be above the line Y=-2x+4.

A sample graph is shown below:

[Graph of Y > -2x + 4]

(0,4), (1,1), (2,-2), (3,-5), (4,-8)

To graph Y > -2x + 4, you need to plot points on a coordinate plane. Start by finding the intersection point of the line Y=-2x+4 and the x-axis, which will be (0,4). From there, you can calculate the coordinates of the other points by substituting x values into the equation and solving for y. For example, when x=1, y=-2x+4=-2+4=2, so the point (1,2) would be plotted. Then, plot the other points (2,-2), (3,-5), and (4,-8). Finally, connect the points with a dashed line to represent Y > -2x+4.

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Answer:

A

Step-by-step explanation:

I think that's da answer I hope it help ya

Answer:

9/10, 1 3/15, 1 6/10, 2 2/9

Step-by-step explanation:

Let's make all the numbers a fraction.

1 6/10, 1 3/15, 9/10, 2 2/9

Find the LCD of the fractions.

1 6/10 = 144/90

1 3/15 = 108/90

9/10 = 81/90

2 2/9 = 200/90

Order the fractions least to greatest.

9/10, 1 3/15, 1 6/10, 2 2/9

To calculate the center line of a control chart, you compute the average of the mean for every period.

A control chart is a graphical representation of a process's performance over time. It is utilized to determine whether a process is in control (i.e., consistent and predictable) or out of control (i.e., unstable and unpredictable).

The center line is used to represent the procedure average on a control chart. When the procedure is in control, the center line is the process's average. When the process is out of control, it can be utilized to assist in identifying where the out-of-control signal began.

The control chart is a valuable quality control tool because it helps detect process variability, identify the source of variability, and determine if process modifications have improved process quality. Additionally, the chart can serve as a visual guide, alerting employees to process variations and assisting them in responding appropriately.

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Answer:

C

Step-by-step explanation:

The domain is the left side of the table

The total cost for 10 hours of work would be 25 + 50(10) = 525.

Cost is the monitorial associated with the purchase of production of food or service if can include the prices of material of which is over it and other expenses that are related to the production of the code of service cost is a major fraction of when deciding whether to purchase a product something as it is and indicator of the value of the product of sound service.
The marginal cost of producing 5 items can be calculated using the equation C(x)=1300+4x/10. The marginal cost is the cost associated with producing one additional item. To calculate the marginal cost, we can plug in x=5 into the equation.

The equation in slope-intercept form for cost, c, after h hours of service is c = 25 + 50h.

The total cost for 8 hours of work would be 25 + 50(8) = 425.

The total cost for 10 hours of work would be 25 + 50(10) = 525.

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Given that the central angle of a sector of a circle is 120° and the radius of the circle is 17 cm.

Area of a sector of a circle is given as: Area of sector.

= (θ/360°)πr²

θ =is the central angle and r being the radius of the circle.

Substitute the given values of θ and r in the above formula, we get:

Area of sector

= (120°/360°)π(17) ²

= (1/3)π(289)

= 289π/3 cm²

=96.02 cm²

Therefore, the area of the sector is 96.02 cm² (rounded off to two decimal places).

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After 24.0 days, 2.00 milligrams of an original 128.0-milligram sample remain, and 6 half-lives have occurred.

To determine the number of half-lives that occurred, we must use the half-life formula:

Final amount = Initial amount x (1/2)^(number of half-lives)Here, the initial amount of the sample is 128.0 milligrams, and the final amount is 2.0 milligrams.

Putting these values in the formula, we get:

\(2.0 = 128.0 x (1/2)^(number of half-lives)2.0/128.0 = (1/2)^(number of half-lives)log(2.0/128.0) = number of half-lives x log(1/2)log(2.0/128.0) = number of half-lives x (-0.3010)Number of half-lives = log(2.0/128.0) ÷ (-0.3010)Number of half-lives ≈ 6.13 ≈ 6\)

Therefore, 6 half-lives have occurred.

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a. the capital formation from the end of the second year to the end of the sixth year is approximately $2430.83. b. it would take approximately 8.10 years for the capital stock to exceed $200,000.

a) The capital formation from the end of the second year to the end of the sixth year can be calculated by integrating the rate of net investment flow function, i(t), over the given time period.

To calculate the capital formation, we integrate i(t) from t = 2 to t = 6:

∫(2 to 6) 200e^(0.2t) dt

To integrate this function, we can use the power rule of integration for exponential functions:

∫e^kt dt = (1/k)e^kt + C

Applying the power rule, we can integrate i(t) as follows:

∫(2 to 6) 200e^(0.2t) dt = (1/0.2) * 200 * e^(0.2t) | (2 to 6)

Simplifying further:

(1/0.2) * 200 * e^(0.2 * 6) - (1/0.2) * 200 * e^(0.2 * 2)

Calculating the exponential values:

(1/0.2) * 200 * e^(1.2) - (1/0.2) * 200 * e^(0.4)

Simplifying:

1000 * e^(1.2) - 1000 * e^(0.4)

Using a calculator, we find that the capital formation from the end of the second year to the end of the sixth year is approximately **$2430.83**.

b) To determine the number of years required before the capital stock exceeds $200,000, we need to set up an equation and solve for t.

Given that the capital stock is the accumulation of net investment flow, we can set up the following equation:

∫(0 to t) 200e^(0.2x) dx > 200,000

To solve this equation, we integrate i(t) over the given time period and set it greater than 200,000:

∫(0 to t) 200e^(0.2x) dx > 200,000

Applying the power rule and integrating:

(1/0.2) * 200 * e^(0.2x) | (0 to t) > 200,000

Simplifying further:

1000 * e^(0.2t) - 1000 > 200,000

1000 * e^(0.2t) > 201,000

Now, we solve for t by isolating the exponential term:

e^(0.2t) > 201

Taking the natural logarithm (ln) of both sides to remove the exponential:

0.2t > ln(201)

Solving for t:

t > ln(201) / 0.2

Using a calculator, we find that t is approximately **8.10 years**.

Therefore, it would take approximately 8.10 years for the capital stock to exceed $200,000.

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Answer:Option C Both gift boxes have the same length for a given volume

Step-by-step explanation:

Step-by-step explanation:

step 1

David's gift box

Calculate the side length of the box for a given volume

we have

For  ------>

For  ------>

For  ------>

For  ------>

therefore

Both gift boxes have the same length for a given volume

Answer:

the answer is ronald

Step-by-step explanation:

plato

Answer:

Student 2's is correct

Step-by-step explanation:

(I did this with algebra not graphing btw)

Just substitute the points for both equations, and if they're both true it's the answer:

Student 1 (10,2):

y = 1/2x + 6
2 = 1/2(10) + 6
2 = 5 + 6
2 = 11

Since this is already false, this answer is false

Student 2:

y = 1/2x + 6
5 = (1/2)(-2) + 6
5 = -1 + 6
5 = 5

True, now move onto the next equation

y = 2x +9
5 = (2)(-2) + 9
5 = -4 + 9
5 = 5

Also true, which means Student 2 is correct.

Answer:

Divide 1/3

Step-by-step explanation:

To get rid of the 1/3 fraction on x, we want to multiply by 3 or divide by 1/3

Answer:

divide by 1/3

Step-by-step explanation:

The type of set that allows you to position rollers diagonally and set from multiple points of origin is an oblong set.

An oblong set is a type of parallel set consisting of two parallel rectangular bars or blocks, with rollers positioned diagonally between them. The oblong shape of the set allows for the rollers to be positioned at a diagonal angle, which can be useful when setting up workpieces that need to be adjusted at an angle or from multiple points of origin.

In contrast, a half oval set and a half circle set are both types of circular sets that consist of rollers positioned in a semi-circular shape. These types of sets are useful for supporting workpieces that have a curved or circular shape, but they do not provide the flexibility to position rollers at a diagonal angle or from multiple points of origin.

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When the graph is decreasing, the rectangles give an underestimate and when the graph is increasing, they give an overestimate. These trends are accentuated to a greater extent by areas of the graph that are steeper.

We only need to add up the areas of all the rectangles to determine the area beneath the graph of f. It is known as a Riemann sum. The area underneath the graph of f is only roughly represented by the Riemann sum. The subinterval width x=(ba)/n decreases as the number of subintervals n increases, improving the approximation. Increased sections result in an underestimation while decreasing sections result in an overestimation. We now arrive at the middle rule. The height of the rectangle is equal to the height of its right edges for a right Riemann sum and its left edges for a left Riemann sum. The rectangle height is the height of the top edge's midpoint according to the midpoint rule, a third form of the Riemann sum.

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Answer:

ln(20×5)=InX^2

In100=InX^2

X^2=100

X=10

The solution of the given expression will be x = 10

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication and division.

The solution of the given equation is:-

ln(  20 × 5)   =   InX²

In100   =    InX²

X²   =    100

X    =    10

Therefore the solution of the given expression will be x = 10

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Answer:

pls like and follow my page ....thank you

Step-by-step explanation:

using elimination method...you will have it as

12x+15y =34 .............1

-6x+5y = 3 ...............2

multiply equation 1 by 6 and equation 2 by 12

72x + 90y = 204.........4

-72x + 60y = 36..........5

asd equation 2 and 1...

0x + 150y = 240

y= 240/250 ..

after getting your answer ..

substitute for y in either of equation 1 and 2 to get your x

The use of meta-matrices mean in data analysis enables researchers to synthesize and interpret diverse sources of information, facilitating a deeper understanding of the research topic or question.

In the context of data analysis, the use of meta-matrices mean involves combining and integrating qualitative and quantitative data into a single matrix or framework. Meta-matrices are used to summarize and analyze multiple data sources, such as different studies, research articles, or datasets, in order to identify patterns, themes, or relationships across the data.

The meta-matrices mean specifically refers to the process of calculating the average or mean values across multiple meta-matrices. This can be done by aggregating the data from different sources and summarizing them using statistical measures such as means, medians, or proportions.

The use of meta-matrices mean allows researchers to gain a comprehensive understanding of the data by considering both qualitative and quantitative aspects. It helps to provide a more holistic view of the phenomenon under investigation and can uncover insights that may not be apparent when analyzing the data separately. By integrating data from various sources, researchers can identify commonalities, differences, and trends, and draw more robust conclusions.

Overall, the use of meta-matrices mean in data analysis enables researchers to synthesize and interpret diverse sources of information, facilitating a deeper understanding of the research topic or question.

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The cheetah can go at a speed of 70 miles per hour.

To determine the speed at which the cheetah can go, we need to add the additional speed to the cat's speed.

Given that the cat can run at 27.5 miles per hour and the cheetah can run 42.5 miles per hour faster, we can calculate the cheetah's speed as:

Cheetah's speed = Cat's speed + Additional speed

Cheetah's speed = 27.5 mph + 42.5 mph

Cheetah's speed = 70 mph

Therefore, the cheetah can go at a speed of 70 miles per hour.

This means that the cheetah can run at a speed of 70 miles per hour, which is obtained by adding the additional speed of 42.5 miles per hour to the cat's speed of 27.5 miles per hour. The cheetah's speed of 70 miles per hour indicates its capability to cover a considerable distance in a given amount of time.

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It is more convenient to integrate with respect to y.

What is the quadratic equation?

The solutions to the quadratic equation are the values of the unknown variable x, which satisfy the equation. These solutions are called roots or zeros of quadratic equations. The roots of any polynomial are the solutions for the given equation.

To sketch the region enclosed by the curves y = 3x² and y = 5x - 2x² and determine whether to integrate with respect to x or y, we can analyze the intersection points and the shape of the curves.

First, let's find the intersection points by setting the equations equal to each other:

3x² = 5x - 2x²

Combining like terms:

5x² - 5x = 0

Factoring out x:

x(5x - 5) = 0

Solving for x:

x = 0 or x = 1

So the curves intersect at x = 0 and x = 1.

Next, we can analyze the behavior of the curves to determine the orientation of the region.

For y = 3x², we have a parabola that opens upwards. This curve lies below the x-axis and is symmetric with respect to the y-axis.

For y = 5x - 2x², we have a downward-opening parabola. This curve lies above the x-axis and is symmetric with respect to the y-axis.

Based on this information, we can sketch the region enclosed by the curves.

The region enclosed by the curves is bounded by the curves themselves and the x-axis. It is the area between the curves from x = 0 to x = 1.

To determine whether to integrate with respect to x or y, we can observe that the region is vertically oriented, meaning it extends vertically between the curves.

Therefore, it is more convenient to integrate with respect to y.

To draw a typical approximating rectangle, we can choose a small interval along the y-axis and draw a rectangle that spans between the curves for that particular y-interval. This rectangle will represent an approximation of the region's area.

Hence, it is more convenient to integrate with respect to y.

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