Answer:
\(x=\frac{\sqrt{14} }{2}\)
Step-by-step explanation:
Notice that you are given an isosceles right-angle triangle to solve, since each of its two acute angles measures \(45^o\). Then such means that the sides opposite to these acute angles (the so called "legs" of this right angle triangle) must also be of the same length (x).
We can then use the Pythagorean theorem that relates the square of the hypotenuse to the addition of the squares of the triangles legs:
\((\sqrt{7})^2=x^2+x^2\\7=2\,x^2\\x^2=\frac{7}{2} \\x=+/-\sqrt{\frac{7}{2}} \\x=+/-\frac{\sqrt{14} }{2}\)
We use just the positive root, since we are looking for an actual length. then, the requested side is:
\(x=\frac{\sqrt{14} }{2}\)
A deli wraps its cylindrical containers of hot food items with plastic wrap. The containers have a diameter of 5.5 inches and a height of 3 inches. What is the minimum amount of plastic wrap needed to completely wrap 8 containers? Round your answer to the nearest tenth and approximate using π = 3.14.
51.8 in2
99.3 in2
595.8 in2
794.4 in2
The minimum amount of plastic wrap needed to completely wrap 8 containers is 794. 4 in². Option D
What is the minimum amount?The area of each circular end is:
A = πr²
A = 3.14 × (2.75)²
A = 23.68in²
The area of the rectangular side is:
A = h * circumference
circumference = 5.5in * π
circumference = 17.27in
Using the given height of 3 inches, we get:
A = 3in * 17.27
A = 51.81in²
Therefore, the total surface area of each container is:
A = 2 * 23.68 + 51.81
A = 98.17in²
To wrap 8 containers, we need to multiply the surface area of each container by 8:
Total surface area = 8 × 98.17
Total surface area = 794. 4 in²
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Simplify (2a^3a^4)^5. Show all work
Answer:
(2a^3a^4)^5 simplifies to 32a^35.
Step-by-step explanation:
To simplify (2a^3a^4)^5, we can use the properties of exponents which states that when we raise a power to another power, we can multiply the exponents. Therefore, we can rewrite the expression as:
(2a^3a^4)^5 = 2^5 * (a^3a^4)^5
Next, we can simplify the expression inside the parentheses by multiplying the exponents:
a^3a^4 = a^(3+4) = a^7
Substituting this into our expression, we get:
(2a^3a^4)^5 = 2^5 * (a^3a^4)^5 = 2^5 * a^35
Finally, we can simplify this expression by using the property of exponents that states that when we multiply two powers with the same base, we can add their exponents. Therefore, we can rewrite the expression as:
2^5 * a^35 = 32a^35
Therefore, (2a^3a^4)^5 simplifies to 32a^35.
suppose that prices of a gallon of milk at various stores in one town have a mean of $3.55 with a standard deviation of $0.14 . using chebyshev's theorem, what is the minimum percentage of stores that sell a gallon of milk for between $3.27 and $3.83 ? round your answer to one decimal place.
Therefore, the minimum percentage of stores that sell a gallon of milk for between $3.27 and $3.83 is 75%, rounded to one decimal place.
What is standard deviation?Standard deviation is a measure of the amount of variation or dispersion in a set of data values. It measures how spread out the data is from the mean or average value. A low standard deviation indicates that the data is closely clustered around the mean, while a high standard deviation indicates that the data is more spread out. It is calculated as the square root of the variance, which is the average of the squared differences from the mean.
Here,
Chebyshev's theorem states that for any dataset, regardless of its distribution, at least 1 - 1/k² of the data will fall within k standard deviations of the mean, where k is any positive number greater than 1. To find the minimum percentage of stores that sell a gallon of milk for between $3.27 and $3.83, we can first find how many standard deviations away from the mean these prices are:
$3.27 is (3.27 - 3.55)/0.14 = -2 standard deviations from the mean
$3.83 is (3.83 - 3.55)/0.14 = 2 standard deviations from the mean
Thus, the distance between $3.27 and $3.83 is 4 standard deviations (2 in each direction).
Using Chebyshev's theorem with k = 2 (since we want to know the minimum percentage within 2 standard deviations), we have:
=1 - 1/2²
= 1 - 1/4
= 0.75
This means that at least 75% of stores sell a gallon of milk for between $3.27 and $3.83.
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Natasha is wrapping gifts for the holidays to donate to a local community center. Natasha has 240 square feet of wrapping paper. If Natasha can wrap 8 gifts with 15 sq feet of paper; how many gifts can she wrap in total?
Answer:
Natasha can wrap 128 gifts in total
Step-by-step explanation:
Let us use the ratio method to solve the question
∵ Natasha has 240 square feet of wrapping paper
∵ Natasha can wrap 8 gifts with 15 square feet
→ By using the ratio method
→ Gift : square feet
→ 8 : 15
→ x : 240
→ By using cross multiplication
∵ x × 15 = 8 × 240
∴ 15x = 1920
→ Divide both sides by 15
∵ x = 128
∵ x represents the number of gifts
∴ Natasha can wrap 128 gifts in total
-5yz + yz +2yz simplify these expressions
Answer:
-2yz
Step-by-step explanation:
To simplify the expression -5yz + yz + 2yz, we can combine the yz terms that have the same coefficient:
-5yz + yz + 2yz = (-5 + 1 + 2)yz
Simplifying the coefficients gives:
= -2yz
Therefore, the simplified expression is -2yz.
Answer:
\(-2yz\)
Step-by-step explanation:
\(-5yz + yz + 2yz = (-5 + 1 + 2)yz\)
\((-5 + 1 + 2)yz = -2yz\)
Therefore, the simplified expression is:
\(-2yz\)
PLEASE HELP!!!
ACE is an isosceles triangle. What is the measure of the vertex angle?
Answer:
30 degrees
Step-by-step explanation:
all angles in all triangles total 180*
each base angle of an isosceles triangle equals 75*
since 75* + 75* = 150*
150* of the triangle are accounted for
Since 180* - 150* = 30* then the vertex angle should be 30* so that the angles of the triangle are all equal
Q6.
Here are two rectangles.
4x
A
2.5
All measurements are in centimetres.
The area of rectangle A is equal to the area of rectangle B.
Work out the perimeter of rectangle B.
2x-3
B
The perimeter of rectangle B is equal to 29 centimeters.
What does a perimeter mean?
The perimeter of a shape is the space surrounding it. Space inside a shape is measured by area. Learn how to compute the area and perimeter of various forms.
Given the area of the rectangle, A is equal to the area of rectangle B.
That is 2.5(4x)=(2x-3)7
10x=14x-21
4x=21
x=5.25
The perimeter of rectangle B is the sum of all sides= 2(2x-3+7)
The perimeter of B = 4x+8=29 cm.
Therefore perimeter of rectangle B is 29 centimeters.
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An investor wants to save money to purchase real estate. She buys an annuity with yearly payments that earn 5.3% interest compounded annually payments will be made at the end of each year find the total value of the annuity in 16 years if each yearly payment is 693.
The total value of the annuity in 16 years, with yearly payments of $693 and an interest rate of 5.3% compounded annually, is approximately $12,739.62.
To calculate the total value of the annuity in 16 years, we can use the formula for the future value of an annuity:
FV = P * ((1 + r)^n - 1) / r
Where:
FV is the future value of the annuity,
P is the yearly payment,
r is the interest rate per compounding period, and
n is the number of compounding periods.
In this case, the yearly payment (P) is $693, the interest rate (r) is 5.3% or 0.053, and the number of compounding periods (n) is 16.
Let's substitute these values into the formula and calculate the total value of the annuity:
FV = 693 * ((1 + 0.053)^16 - 1) / 0.053
FV = 693 * (1.053^16 - 1) / 0.053
Using a calculator, we can evaluate the expression inside the parentheses:
1.053^16 ≈ 1.9738
Substituting this value back into the formula:
FV = 693 * (1.9738 - 1) / 0.053
FV = 693 * 0.9738 / 0.053
FV ≈ 12739.62
Therefore, the total value of the annuity in 16 years, with yearly payments of $693 and an interest rate of 5.3% compounded annually, is approximately $12,739.62.
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3 6 9 12 15 18 21 24 27 30 is odd or even numbers?
Answer: Half of them are even and half of them are odd.
Step-by-step explanation:
The even numbers are 6, 12, 18, 24, and 30. An even number is defined as a number that is divisible by 2, meaning it has no remainder when divided by 2. For example, 6 divided by 2 equals 3 with no remainder, so 6 is even.
The odd numbers are 3, 9, 15, 21, and 27. An odd number is defined as a number that is not divisible by 2, meaning it has a remainder of 1 when divided by 2. For example, 9 divided by 2 equals 4 with a remainder of 1, so 9 is odd.
Therefore, out of the given numbers, half of them are even and half of them are odd.
________________________________________________________
Given a normal population whose mean is 555 and whose standard deviation is 72, find each of the following:
The probability that a random sample of 21 has a mean between 564 and 587.
Probability =
The probability that a random sample of 21 has a mean between 564 and 587 is of:
0.2641 = 26.41%.
How to obtain probabilities using the normal distribution?The z-score of a measure X of a variable that has mean symbolized by \(\mu\) and standard deviation symbolized by \(\sigma\) is obtained by the rule presented as follows:
\(Z = \frac{X - \mu}{\sigma}\)
The z-score represents how many standard deviations the measure X is above or below the mean of the distribution, depending if the obtained z-score is positive or negative.Using the z-score table, the p-value associated with the calculated z-score is found, and it represents the percentile of the measure X in the distribution.The parameters for this problem are given as follows:
\(\mu = 555, \sigma = 72, n = 21, s = \frac{72}{\sqrt{21}} = 15.7\)
The probability that a random sample of 21 has a mean between 564 and 587 is the p-value of Z when X = 587 subtracted by the p-value of Z when X = 564, hence:
X = 587:
\(Z = \frac{X - \mu}{\sigma}\)
By the Central Limit Theorem
\(Z = \frac{X - \mu}{s}\)
Z = (587 - 555)/15.7
Z = 2.04
Z = 2.04 has a p-value of 0.9798.
X = 564:
Z = (564 - 555)/15.7
Z = 0.57
Z = 0.57 has a p-value of 0.7157.
0.9798 - 0.7157 = 0.2641 = 26.41%.
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H
6:00 PM
What is a frostbite?
Find the zeros of the function. Enter the solutions from least to greatest. f(x) = (x - 2)(3x + 3)
The zeros of the given function are x = 2 and x = -1
Zeros of a functionFrom the question, we are to determine the zeros of the given function
The given function is
f(x) = (x - 2)(3x + 3)
To determine the zeros of a function, we will set the function equal to zero
That is,
(x - 2)(3x + 3) = 0
Then,
x - 2 = 0 OR 3x + 3 = 0
x = 2 OR 3x = -3
x = 2 OR x = -3/3
x = 2 OR x = -1
Hence, the zeros of the given function are x = 2 and x = -1
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Yessusuwideosjhddsvhssbsgshyshdgs
Answer:
what
Step-by-step explanation:
Answer:
um, sorry i dont speak gibberish
Step-by-step explanation:
Solve x^2+8x+22=0 by completing the square.
Answer: x = √-6 - 4
Step-by-step explanation:
x^2+8x+22=0
(x+4)^2 - 16 + 22 = 0
(x+4)^2 + 6 = 0
(x+4)^2 = -6
√(x+4)^2 = √-6
x = √-6 - 4
√6 = 2.449
Which of the following is false about the central limit theorem (CLT)? O If we take more samples from the original population, the sampling distribution is more likely to be nearly normal. O If the population distribution is normal, the sampling distribution of the mean will also be nearly normal, regardless of the sample size. O As the sample size increases, the sampling distribution of the mean is more likely to be nearly normal, regardless of the shape of the original population distribution. O The CLT states that the sampling distribution will be centered at the true population parameter.
Only the first statement is false. The rest are true statements about the Central Limit Theorem.
The Central Limit Theorem (CLT) is a fundamental theorem in probability and statistics which states that, given a sufficiently large sample size from a population with a given mean and standard deviation, the sampling distribution of the mean will be nearly normal, regardless of the shape of the original population distribution.
It is important to note that the first statement presented is false. Taking more samples from the population will not necessarily result in a more normal sampling distribution. The CLT does not guarantee that the sampling distribution will be normally distributed, only that it is more likely to be so as the sample size increases.
The second statement is true. If the population distribution is normal, the sampling distribution of the mean will also be nearly normal, regardless of the sample size. The third statement is also true. As the sample size increases, the sampling distribution of the mean is more likely to be nearly normal, regardless of the shape of the original population distribution.
Finally, the fourth statement is also true. The CLT states that the sampling distribution will be centered at the true population parameter. This means that the mean of the sampling distribution will be equal to the mean of the population.
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What is the order pairs for
(-4,7) , (-6,-4) and (15,8) , (-17,9)
(-4,7) , (-6,-4) and (15,8) , (-17,9)
6. Determine the system of equations based on the following relationships and then solve
for the two integers.
a. Fourteen more than twice the first integer gives the second integer
b. The second integer increased by one is the square of the first integer
Answer: (-3,8) and (5,24)
The two pairs of integers that satisfy the given conditions are (-3, 8) and (5, 24).
To solve the system of equations, let's assign variables to the two integers. Let the first integer be represented by 'x' and the second integer by 'y'.
According to the given information:
a. Fourteen more than twice the first integer gives the second integer:
This can be expressed as: 2x + 14 = y
b. The second integer increased by one is the square of the first integer:
This can be expressed as: y + 1 = x^2
Now, we have a system of equations:
1) 2x + 14 = y
2) y + 1 = x^2
To solve this system, we can substitute the value of 'y' from equation 1) into equation 2):
2x + 14 + 1 = x^2
2x + 15 = x^2
Rearranging the equation, we have:
\(x^2 - 2x - 15 = 0\)
Factoring the quadratic equation, we get:
(x - 5)(x + 3) = 0
Setting each factor equal to zero:
x - 5 = 0 --> x = 5
x + 3 = 0 --> x = -3
Substituting the values of 'x' back into equation 1), we can find the corresponding values of 'y':
For x = 5:
2(5) + 14 = y
10 + 14 = y
y = 24
For x = -3:
2(-3) + 14 = y
-6 + 14 = y
y = 8
Therefore, the two pairs of integers that satisfy the given conditions are (-3, 8) and (5, 24).
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Two Tickets to an ice skating performance costs $36. For five tickets it costs $90, and for 9 tickets it costs $162.
The proportional relationship that gives the cost of x tickets is:
\(y = 18x\)
What is a proportional relationship?A proportional relationship is a function in which the output variable is given by the input variable multiplied by a constant of proportionality, that is:\(y = kx\)
In which k is the constant of proportionality.Two tickets to an ice skating performance costs $36, hence, when \(x = 2, y = 36\), then:
\(y = kx\)
\(36 = 2k\)
\(k = \frac{36}{2}\)
\(k = 18\)
Hence, the relationship is described by:
\(y = 18x\)
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Which statement best describes the transformation from f(x) to g(x)? The graph of f(x) was translated left 4 units and up 3 units to obtain g(x). The graph of f(x) was translated right 3 units and up 4 units to obtain g(x). The graph of f(x) was translated left 3 units and down 4 units to obtain g(x). The graph of f(x) was translated left 4 units and down 3 units to obtain g(x).
Step-by-step explanation:
let's just look at the first (outmost left) point.
from f(x) to g(x) it moved 4 units down and 3 units left.
so, this should be the 3rd answer option in your list.
The correct statement which best describes the transformation from f(x) to g(x) is,
⇒ The graph of f(x) was translated left 3 units and down 4 units to obtain g(x).
Given that;
The graph of f (x) and g (x) is shown in figure.
Now, By graph we get;
The transformation from f(x) to g(x) it moved 4 units down and 3 units left.
Hence, The correct statement which best describes the transformation from f(x) to g(x) is,
⇒ The graph of f(x) was translated left 3 units and down 4 units to obtain g(x).
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Simplify: - 4x 5x - 1 + 3-6x 3-6x
Answer:
−45−1+3−63−6
−46−1+3−63−6
−46+2−63−6
Solution:
−46−63−6+2
Step-by-step explanation:
I hope that this is what you are looking for
Have a nice day/night
Wind power is a source of mechanical or electrical power that is generated by the turning of large wind turbines. Usually a turbine has 3 long arms or blades. Suppose the distance from the center of a turbine to the tip of an arm is 116 feet. What distance does the tip of each arm travel in one revolution?
Determine if the following statements are true or false.
The tip of each arm travels a distance of 364.36 feet in one revolution.
The following statements "Wind power is a source of mechanical or electrical power that is generated by the turning of large wind turbines. Usually a turbine has 3 long arms or blades. Suppose the distance from the center of a turbine to the tip of an arm is 116 feet" are true.
Wind power is a type of energy source that is clean, affordable, and renewable. It is an eco-friendly alternative to other forms of electricity generation that produce harmful greenhouse gases and pollutants. Wind power is a mechanical or electrical energy source that is produced by the rotation of large wind turbines.
A wind turbine has three long arms or blades, which are connected to a central hub. The distance from the center of a turbine to the tip of an arm is 116 feet, and the distance that each tip travels in one revolution is determined below.
As we know, the formula for the circumference of a circle is C = πd, where C is the circumference, d is the diameter, and π is a constant value of approximately 3.14. The diameter is twice the radius, so the radius of the turbine is 116/2 = 58 feet.
Therefore, the distance each tip of the arm travels in one revolution is: C = πdC = π(2r)C = π(2 × 58)C = 364.36 feet.
Therefore, the tip of each arm travels a distance of 364.36 feet in one revolution. Hence, the given statement is true.
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Solve the system by the method of your choice. Identify inconsistent systems and systems with dependent equations, using set notation to express solution sets
The given system of equations is
\(\begin{gathered} y=3x+5\rightarrow(1) \\ 5x-2y=-7\rightarrow(2) \end{gathered}\)Substitute y in equation (2) by equation (1)
\(5x-2(3x+5)=-7\)Simplify the left side
\(\begin{gathered} 5x-2(3x)-2(5)=-7 \\ 5x-6x-10=-7 \end{gathered}\)Add the like terms on the left side
\(\begin{gathered} (5x-6x)-10=-7 \\ -x-10=-7 \end{gathered}\)Add 10 to both sides
\(\begin{gathered} -x-10+10=-7+10 \\ -x=3 \end{gathered}\)Divide both sides by -1
\(\begin{gathered} \frac{-x}{-1}=\frac{3}{-1} \\ x=-3 \end{gathered}\)Substitute x in equation (1) by -3 to find y
\(\begin{gathered} y=3(-3)+5 \\ y=-9+5 \\ y=-4 \end{gathered}\)The solution of the system of equations is {(-3, -4)}
Since the system has only one solution then it is an independent consistent system.
Jenifer is flying her kite and it gets stuck in a tree. She knows the string on her kite is 25 feet long and she is 12 feet from the tree.
How long of a ladder (in feet) will she need to get her kite out of the tree?
Answer:
13
Step-by-step explanation:
25 - 12 = 13
I think this is what you're asking, I don't know.
Given that f (x) = StartFraction 120 Over x squared EndFraction , What is the domain of the function f ? a. only positive integers c. only negative integers b. All non zero real numbers. d. All real numbers including zero
For the function "f (x) = 120/x²", the domain of the function "f" is (b) All non zero real numbers.
The "Domain" of a function is the set of all possible "input-values" for which the function is defined. In this case, the function is defined as:
f (x) = 120/x²
The only restriction on the input values is that the denominator cannot be equal to zero, because division by zero is undefined.
So, the domain of the function f is all non-zero real numbers.
Therefore, the correct option is (b): All non-zero real numbers.
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The given question is incomplete, the complete question is
Given that f (x) = 120/x², What is the domain of the function f ?
(a) only positive integers,
(b) All non zero real numbers,
(c) only negative integers,
(d) All real numbers including zero.
6. Journalise the following transactions
1. Bricks for Rs 60,000 and timber for Rs 35,000 purchased for
the construction of building. The payment was made by cheque.
2. Placed in fixed deposit account at bank by transfer from current
account Rs 13,000.
3. Appointed Mr. S.N. Rao as Accountant at Rs 300 p.m. and
Received Rs 1000 as security Deposit at 5% p.a. interest.
4. Sold goods to shruti for Rs 80,000 at 15% trade discount and
4% cash discount. Received 75% amount immediately through a
cheque.
5. Purchased goods from Richa for Rs 60,000 at 10% trade
discount and 5% cash discount. 60% amount paid by cheque
immediately.
6.
On 18th jan,Sold goods to shilpa at the list price of Rs 50,000
20% trade discount and 4% cash discount if the payment is made
within 7 days. 75% payment is received by cheque on Jan 23rd.
7. On 25th jan, sold goods to garima for Rs 1,00,000 allowed her
20% trade discount and 5% cash discount if the payment is made
within 15 days. She paid 1/4th of the amount by cheque on Feb 5th
and 60% of the remainder on 15th in cash.
8. Purchased land for Rs 2,00,000 and paid 1% as brokerage and
Rs 15,000 as registration charges on it. Entire payment is made by
cheque.
9. Goods worth Rs 25,000 and cash Rs 40,000 were taken away
by the proprietor for his personal use.
10. Sold goods costing Rs 1,20,000 to charu at a profit of 33% 3 %
on cost less 15% trade discount.
9
11. Paid rent of building Rs 60,000 by cheque. Half the building is
used by the proprietor for residential purpose.
12. Sold goods costing Rs 20,000 to sunil at a profit of 20% on
sales less 20% trade discount .
13. Purchased goods for Rs 1000 from nanda and supplied it to
helen for Rs 1300. Helen returned goods worth Rs 390, which in
turn were returned to nanda.
14. Received invoice at 10% trade discount from rohit and sons
and supplied these goods to madan, listed at Rs 3000.
1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)
2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)
3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)
4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)
5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)
6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)
7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)
8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)
9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)
10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)
11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)
12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)
13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)
14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)
Here are the journal entries for the given transactions:
1. Bricks and timber purchased for construction:
Debit: Bricks (Asset) - Rs 60,000
Debit: Timber (Asset) - Rs 35,000
Credit: Bank (Liability) - Rs 95,000
2. Transfer to fixed deposit account:
Debit: Fixed Deposit (Asset) - Rs 13,000
Credit: Current Account (Asset) - Rs 13,000
3. Appointment of Mr. S.N. Rao as Accountant:
Debit: Salary Expense (Expense) - Rs 300
Debit: Security Deposit (Asset) - Rs 1,000
Credit: Accountant (Liability) - Rs 300
4. Goods sold to Shruti:
Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000
Credit: Sales (Income) - Rs 80,000
5. Goods purchased from Richa:
Debit: Purchases (Expense) - Rs 60,000
Credit: Accounts Payable - Richa (Liability) - Rs 60,000
6. Goods sold to Shilpa:
Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000
Credit: Sales (Income) - Rs 50,000
7. Goods sold to Garima:
Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000
Credit: Sales (Income) - Rs 1,00,000
8.Purchase of land:
Debit: Land (Asset) - Rs 2,00,000
Debit: Brokerage Expense (Expense) - Rs 2,000
Debit: Registration Charges (Expense) - Rs 15,000
Credit: Bank (Liability) - Rs 2,17,000
9. Goods and cash taken away by proprietor:
Debit: Proprietor's Drawings (Equity) - Rs 65,000
Credit: Goods (Asset) - Rs 25,000
Credit: Cash (Asset) - Rs 40,000
10. Goods sold to Charu:
Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000
Credit: Sales (Income) - Rs 1,20,000
Credit: Cost of Goods Sold (Expense) - Rs 80,000
Credit: Profit on Sales (Income) - Rs 40,000
11. Rent paid for the building:
Debit: Rent Expense (Expense) - Rs 60,000
Credit: Bank (Liability) - Rs 60,000
12. Goods sold to Sunil:
Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000
Credit: Sales (Income) - Rs 24,000
Credit: Cost of Goods Sold (Expense) - Rs 20,000
Credit: Profit on Sales (Income) - Rs 4,000
13. Goods purchased from Nanda and supplied to Helen:
Debit: Purchases (Expense) - Rs 1,000
Debit: Accounts Payable - Nanda (Liability) - Rs 1,000
Credit: Accounts Receivable - Helen (Asset) - Rs 1,300
Credit: Sales (Income) - Rs 1,300
14. Goods received from Rohit and Sons and supplied to Madan:
Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)
Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700
Debit: Accounts Receivable - Madan (Asset) - Rs 3,000
Credit: Sales (Income) - Rs 3,000
for such more question on journal entries
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HELP AGAIN I NEED IT BADLY
Answer:
A. 5b - w + 8
Step-by-step explanation:
3w + 6 - 4w + 3b + 2 + 2b
= 3w - 4w + 3b + 2b + 6 + 2
= -w + 5b + 8
= 5b - w + 8
=> A. 5b - w + 8
What’s the range of ()=−4|−2|−3
Answer:
4
Step-by-step explanation:
Find the value of each variable?
A. Ax3= -30
B. -9xb=45
The answer
A=-10
B= -5
The solutions to the given variables are given as follows:
A = -10.B = -5.What are the solutions of the equations for the variables?To solve an equation for a given variable, we isolate the variable and find it's value.
The first equation is:
3A = -30.
To isolate A, we apply the division, which is the inverse operation of the multiplication, hence:
A = -30/3
A = -10. (negative number divided by positive is negative).
The second equation is:
-9B = 45.
Hence we isolate B similarly to the previous item, applying the division, hence:
B = -45/9
B = -5.
The solutions are A = -10 and B = -5.
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Bouncing Baby Company sells their cribs for the following amounts to stores:
Number of Cribs Price
10 $1320
50 $6600
Which of the following statements about the price of the cribs are true if the price remains proportional to the number of cribs? Select TWO that apply.
A
6 cribs cost $660
B
22 cribs cost $2640
C
40 cribs cost $5280
D
55 cribs cost $7920
E
80 cribs cost $10,560
F
250 cribs cost $11
Answer:
C and E
Step-by-step explanation:
Ik u prolly dont care about the explanation but ill just say it
the ratio is 1:132 or 1 crib is $132. So 40 x 132 = 5280 and 80 x 132 = 10560
For the test im doing the answer is C and D yw ;D
Please help me ! I’ll give anyone a 5 star rating for the correct answers.
Answer:
A)Josh
B)Mila
C) Amir