So, the two points that define the latus rectum are (2,10) and (-2,10).
The equation of the parabola with vertex (0,0) and focus (0,5) is x^2 = 20y. The general form of the parabolic equation with a vertical axis is given as x^2 = 4ay where the focus is (0,a) and the vertex is (0,0).
Here, a = 5, so we can find the equation of the parabola asx^2 = 4 × 5y ⇒ x^2 = 20y The latus rectum is the line segment passing through the focus and perpendicular to the axis of the parabola.
For the given parabola, the axis is vertical, so the latus rectum is horizontal. The length of the latus rectum of a parabola is given as 4a. Thus, the length of the latus rectum for the given parabola is 4 × 5 = 20.
The latus rectum passes through the vertex, so we can determine the two points that define the latus rectum as follows: Latus rectum passing through (0,0) and having length 20 lies along the line y = 10.
The two points on this line that are 20 units apart and symmetric about the focus (0,5) are (2,10) and (-2,10). So, the two points that define the latus rectum are (2,10) and (-2,10).
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PLSSSS HELP IF YOU TURLY KNOW THISSSS
Answer: 7/20
Step-by-step explanation :7/20 is 0.350 converted into a fraction
How many point-slope equations can you write to represent a single line?
an infinite number of equations
5 equations
2 equations
1 equation
There can be only one equation to represent a single line of point-slope equations, so option D is correct.
What is a line?An object having an endless length and no width, depth, or curvature is called a line. Since lines can exist in two, three, or higher-dimensional environments, they are one-dimensional things.
The point-slope equation can be written as,
\(y - y_1 = m (x - x_1)\)
Here \(m\) is the slope of the line,
As you can see from the above equation, there can be many points in a line, but there is only one equation for the line.
For example, if you take a line 2y + x = 4 and put different coordinates of points but the equation, you will get the same.
Therefore, there can be only one equation to represent a single line of point-slope equations.
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Which ordered pairs are solutions to the equation? Show your work for all points and if they are solutions.
3y - 7x = -2
(4/7 , 2/3)
(0 , -2/3)
(11 , 25)
(2 , 4)
(2/7 , 0 )
(-4 , -10)
Show your work
Answer:
First solve for x or y
3y - 7x = -2
3y = 7x - 2
y = (7/3)x - 2/3
Now substitute the x value into this equation and if it equals the yvue, then it's a solution.
y = (7/3)(4/7) - 2/3
y = 4/3 - 2/3
y = 2/3 ✓
y = (7/3)0 - 2/3
y = -2/3 ✓
y = (7/3)11 - 2/3
y = 77/3 - 2/3
y = 75/3 = 25 ✓
y = (7/3)2 - 2/3
y = 14/3 - 2/3
y = 12/3 = 4 ✓
y = (7/3)(2/7) - 2/3
y = 2/3 - 2/3
y = 0 ✓
y = (7/3)-4 - 2/3
y = -28/3 - 2/3
y = -30/3 = -10 ✓
They are all solutions
The following table shows the number of candy bars bought at a local grocery store and the
total cost of the candy bars:
Candy Bars: 3, 5, 8, 12, 15, 20, 25
Total Cost: $6.65, $10.45, $16.15, $23.75, $29.45, $38.95, $48.45
If B represents the number of candy bars purchased and C represents the total cost of the candy bars, write the linear model that models the cost of any number of candy bars.
The linear model that represents the cost of any number of candy bars can be written as: C = $1.90B + $0.95
To write the linear model that models the cost of any number of candy bars, we need to find the equation of a line that best fits the given data points. We'll use the variables B for the number of candy bars purchased and C for the total cost of the candy bars.
Looking at the given data, we can see that there is a linear relationship between the number of candy bars and the total cost. As the number of candy bars increases, the total cost also increases.
To find the equation of the line, we need to determine the slope and the y-intercept. We can use the formula for the equation of a line: y = mx + b, where m is the slope and b is the y-intercept.
First, let's find the slope (m) using two points from the given data, for example, (3, $6.65) and (25, $48.45):
m = (C2 - C1) / (B2 - B1)
= ($48.45 - $6.65) / (25 - 3)
= $41.80 / 22
≈ $1.90
Now, let's find the y-intercept (b) using one of the data points, for example, (3, $6.65):
b = C - mB
= $6.65 - ($1.90 * 3)
= $6.65 - $5.70
≈ $0.95
Therefore, the linear model that represents the cost of any number of candy bars can be written as:
C = $1.90B + $0.95
This equation represents a linear relationship between the number of candy bars (B) and the total cost (C). For any given value of B, you can substitute it into the equation to find the corresponding estimated total cost of the candy bars.
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Liam deposits $3,500 in a saving account that pays 1.5% interest, compounded quarterly.
a.Find the balance after a year.
B. Compare the interest compounded annually.
Therefore the balance after a year comes out to be $3552.80 and the balance comes out to be after compounded annually is $3552.50
What is compound interest ?Compound interest is the interest on savings that is computed using both the original principal and the interest accrued over time.
It is believed that Italy in the 17th century was where the idea of "interest on interest" or compound interest first emerged. It will accelerate the growth of a sum more quickly than simple interest, which is only applied to the principal sum.
Money multiplies more quickly through compounding, and the higher the
Here,
The Liam deposits $3,500 in a saving account that pays 1.5% interest,
Thus rate=1.5% and principle amount =3500
Therefore it is compounded quartely ,
The balance after year=
C=P\(e^{rt}\)
C=3500*\(e^{1.5*4}\)
C=3552.80
Therefore the balance after a year comes out to be $3552.80
Therefore the balance comes out to be after compounded annually is
$3552.50
So there is only $0.30 difference between the amounts
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explain why the function defined by M(t) = 2t + 1 has no maximum value on the interval [0,4)
The function defined by M(t) = 2t + 1 has no maximum value on the interval [0,4) as the derivative of m(t) is not equal to zero.
The maxima of the function can be calculated by the derivative of the function. The derivative is equated to 0 to calculate the critical points. If the second derivative is negative at this critical point then a maximum exists at this point.
The function is M(t) = 2t + 1 . Differentiate the function with respect to t. Now equate the derivative to 0. This will give the critical point. Since 2 is not equal to 0, the critical point does not exist on the curve of the function. Therefore, the function M(t) = 2t + 1does not have a maxima. M(t) = 2t + 1
d/dt M(t) = d/dt 2t + 1
= 2
d/dt m'(t) = 0
2 not equal to 0
The function does not have a critical point. Therefore, the maxima do not exist for the function.
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A custotuer requires during the next four months respectively 50,65,100, and 70 units of a commodity (no backlogs wllowed). Productions costs are $5,$8,$4, and $7 per unit during these months. The storage cost from one month to the next are $2 per unit (assessed on the end of the month inventory). Each unit at the end of the month 4 could be sold for $15 /unit. The production capacities for each month are 90, 75, 80 , and 50 units respectively. Currently, there are 15 units in inventory. Formulate a Linear Program that will minimize the objective function (sum of the production and inventory costs - revenue from selling end of period inventory at month 4). Note, inventory cost is assessed only for the first 3 periods. Model and solve the problem in AMPL and answer the quiz.
The formulated Linear Program aims to minimize the objective function, which is the sum of production and inventory costs minus the revenue from selling the end-of-period inventory at month 4.
In this problem, we need to determine the optimal production and inventory levels over the four-month period to minimize costs and maximize revenue. We can formulate this as a linear programming problem with the following decision variables:
Let x1, x2, x3, x4 represent the production quantities for months 1, 2, 3, and 4, respectively.
Let y1, y2, y3, y4 represent the end-of-month inventory levels for months 1, 2, 3, and 4, respectively.
The objective function we want to minimize is:
Minimize: (5x1 + 8x2 + 4x3 + 7x4) + (2y1 + 2y2 + 2y3) - (15y4)
Subject to the following constraints:
1. Initial inventory: y1 = 15 (given)
2. Production capacity constraints:
x1 <= 90 (month 1 capacity)
x2 <= 75 (month 2 capacity)
x3 <= 80 (month 3 capacity)
x4 <= 50 (month 4 capacity)
3. Inventory balance equations:
y1 + x1 - 50 = y2 (month 1)
y2 + x2 - 65 = y3 (month 2)
y3 + x3 - 100 = y4 (month 3)
y4 + x4 - 70 = 0 (month 4, no carryover inventory)
4. Non-negativity constraints:
x1, x2, x3, x4, y1, y2, y3, y4 ≥ 0
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The sum of two numbers is 79. Three times the first number added to 5 times the second number is 283. What are the two numbers?
Answer:
The two numbers are 56 and 23.
Step-by-step explanation:
Let the two numbers be A and B.
We are told that:
A+B = 79, and
2) 3A + 5B = 283
Rearrange the first expression to isolate A:
A = 79-B
Now use this value of B in the second expression:
3A + 5B = 283
3(79-B) + 5B = 283
237-3B + 5B = 283
2B = 46
B = 23
If B=23, we can find A from (1):
A+B = 79
A+23 = 79
A = 56
CHECK:
Does A+B = 79?
56 + 23 = 79? YES
Does 3A + 5B = 283?
3(56) + 5(23) = 283?
168 + 115 = 283? YES
7) Amy teaches Chinese lessons for $65 per
student for a 6-week session. From one group
of students, she collects $1950. Find how many
students are in the group.
A) 34 students
C) 30 students
B) 20 students
D) 32 students
Answer:
30
Step-by-step explanation:
1950 ÷ 65 = 30
total money ÷ money for one student
Find the coordinates of the other endpoint of the segment, given its midpoint and one endpoint. (Hint: Let (x,y) be the unknown number endpoint. Apply the midpoint formula, and solve the two equations for x and y. midpoint (-6, -20), endpoint (-4,-16)The other endpoint is___(Type an ordered pair.)
Given the coordinates:
midpoint(-6, -20)
Endpoint 1(-4, -16)
To find endpoint 2, apply the midpoint formula below:
\(x_{m,\text{ }}y_{m\text{ }}=\text{ (}\frac{x1+x2}{2},\text{ }\frac{y1+y2}{2})\)Where,
(xm, ym) = (-6, -20)
(x1, y1) = (-4, -16)
(x2, y2) = unknown
Let's find the mising coordinates (x2, y2)
\(\begin{gathered} \text{For x2:} \\ -6\text{ = }\frac{-4+x2}{2} \\ \\ -12\text{ = -4 + x2} \\ \\ x2\text{ = -12 + 4} \\ \\ x2\text{ = -8} \end{gathered}\)\(\begin{gathered} \text{For y2:} \\ -20\text{ = }\frac{-16+y2}{2} \\ \\ -40\text{ = -16 + y2} \\ \\ y2\text{ = -40 + 16} \\ \\ y2\text{ = }-24 \end{gathered}\)Therefore, the other endpoint is (-8, -24)
ANSWER:
(-8, -24)
A year ago, my dog weighed 3kgs. I weighed him today and he weighs 4/10 more. How much does he weigh now?
HELP ME ASAP PLEASE!
Answer: He now weighs 4.2 kg because 4/10 of 3 is 1.2 and 1.2+3=4.2
Identify the properties of the graph of the following. Sketch the graph with the use of Reflective Point:
1. y=(x-5)²+4
2. y=2x²+8x+5
Therefore , the solution of the given problem of graph comes out to be (0,29) and (0,5).
Explain graph.Graphs are used by academics to logically depict or chart events or values visually. A graph point often depicts the relationship between two or more things. The non-linear storage structure known as a graph is made up of nodes, often referred to as vertices, and edges. Glue ought to be used to join the nodes, also known as vertices. In this graph, the vertex numbers are 1, 2, 3, or 5, whereas the edge numbers were 1, 2, 1, 3, 2, 4, etc (2.5). (3.5). (4.5). (4.5). graphics that graphically represent exponential growth in statistical diagrams like line graphs, charts, and bar graphs. a logarithmic graph with a triangle form
Here,
Given :
=> y=(x-5)²+4
So,
x =0
then y value :
=> y = (0-5)² +4
=> y = 25 +4
=> y = 29
=> (0,29)
and
=> y=2x²+8x+5
So,
x = 0 ,
then y value :
=> y = 2(0)² + 8(0) + 5
=> y = 5
=> (0,5)
Therefore , the solution of the given problem of graph comes out to be (0,29) and (0,5).
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How do I Evaluate 16 2/3?
Answer:
6.34960 correct to 5 decimal places.
Step-by-step explanation
16 ^ 2/3
= cube root of 16^2
∛(16^2)
= ∛(256)
= 6.349604208.
The 2 in the 2/3 means the square of 16, and the 3 in 2/3 mean 16^1/3
which is the same as the cube root.
The evaluation of mixed fractions \(16\dfrac{2}{3}\) in improper fractions using the simplification rule is \(\dfrac{50}{3}\).
The combination of a proper fraction and a whole number is called a mixed fraction.
When the numerator is greater than the denominator, such type of fraction is called an improper fraction.
To evaluate \(16 \dfrac{2}{3}\) , convert the mixed number to an improper fraction and then simplify it.
Multiply the whole number \((16)\) by the denominator \((3)\) and add the numerator \((2)\).
\((16 \times 3 )+ 2 \\= 48 + 2\\ = 50\)
The sum is written with the denominator \(3\) as \(\dfrac{50}{3}\) .
The evaluation of mixed fractions \(16\dfrac{2}{3}\) in improper fractions is \(\dfrac{50}{3}\).
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Write an expression to display a loss of 42 yards on the football field
Answer:
Step-by-step explanation:
An expression to display a loss of 42 yards on the football field would be: -42 yards.
The negative sign in front of the number 42 indicates a loss or a decrease in the yards, which represents a loss of 42 yards on the football field.
El concepto de interes compuesto quiza no sea muy familiar, pero se trata de algo relativamente simple: cada vez que un capital genere intereses estos se añadirán obteniendo asi un monto más grande, que producirá mayores intereses.
¿Qué capital obtendria una persona en 30 años al invertir un peso a una tasa de interes compuesto del 5% mensual?
Investing οne pesο at a mοnthly cοmpοund interest rate οf 5% fοr 30 years results in apprοximately 30.1267 pesοs.
What is the tοtal amοunt οbtained after investing οne pesο at a mοnthly cοmpοund interest rate οf 5% fοr 30 years?Tο calculate the tοtal amοunt οf mοney that sοmeοne wοuld have after 30 years οf investing οne pesο at a mοnthly cοmpοund interest rate οf 5%, we wοuld need tο use the fοllοwing fοrmula:
\(A = P(1 + r/n)^{(nt)\)
Where:
A = the tοtal amοunt οf mοney at the end οf the investment periοd
P = the principal amοunt invested (in this case, οne pesο)
r = the annual interest rate (in this case, 5%)
n = the number οf times the interest is cοmpοunded per year (since the interest is cοmpοunded mοnthly, n = 12)
t = the number οf years οf the investment periοd (in this case, 30)
Plugging in these values, we get:
\(A = 1(1 + 0.05/12)^{(12*30)\)
\(A = 1.05^{(360)\)
\(A = 30.1267\)
Therefοre, after 30 years οf investing οne pesο at a mοnthly cοmpοund interest rate οf 5%, the tοtal amοunt οf mοney that wοuld be οbtained is apprοximately 30.1267 pesοs.
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Complete Question:
The concept of compound interest may not be very familiar, but it is something relatively simple: each time a capital generates interest, it will be added, thus obtaining a larger amount, which will produce higher interest.
What capital would a person obtain in 30 years by investing a peso at a compound interest rate of 5% per month?
surface area using a parametric description find the area of the following surfaces using a parametric description of the surface
The half-cylinder {(1, 0, z): r = 4,0 < 0 < 7,0 < z s 7}
The area of the half-cylinder can be found using a parametric description of the surface.
To find the area of the half-cylinder, we can parametrize the surface using cylindrical coordinates. Let's consider the surface as a function of two parameters, θ and z. We can define the parametric equations as follows:
x = r cos(θ)
y = r sin(θ)
z = z
In this case, the radius r is given as 4, the angle θ varies from 0 to 2π, and the height z varies from 0 to 7.
To calculate the surface area, we use the formula for the surface area of a surface described by parametric equations:
A = ∫∫ ||rθ × rz|| dθ dz
Here, ||rθ × rz|| represents the magnitude of the cross product of the partial derivatives of the parametric equations with respect to θ and z.
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Find f(1), f(2), f(3), f(4) and f(5) if f(n) is defined recursively by f(0) = 3 and for n 0,1,2,....
Question a) f(n+1)=-2f(n)
Question b) f(n+1) = 3f(n)+7
Question c) f(n+1)=f(n)^2 -2f(n)-2
Question d) f(n+1) = 3^f(n)/3
The values for f(1), f(2), f(3), f(4), and f(5) using the recursive formula f(n+1) = 3^(f(n)/3) are:
f(1) = 3, f(2) = 3, f(3) = 3, f(4) = 3, f(5) = 3.
To find the values of f(1), f(2), f(3), f(4), and f(5) for each given recursive definition, we can use the initial condition f(0) = 3 and the recursive formulas.
(a) f(n+1) = -2f(n):
Using the recursive formula, we can find the values as follows:
f(1) = -2f(0) = -2(3) = -6
f(2) = -2f(1) = -2(-6) = 12
f(3) = -2f(2) = -2(12) = -24
f(4) = -2f(3) = -2(-24) = 48
f(5) = -2f(4) = -2(48) = -96
So, the values for f(1), f(2), f(3), f(4), and f(5) using the recursive formula f(n+1) = -2f(n) are:
f(1) = -6, f(2) = 12, f(3) = -24, f(4) = 48, f(5) = -96.
(b) f(n+1) = 3f(n) + 7:
Using the recursive formula, we can find the values as follows:
f(1) = 3f(0) + 7 = 3(3) + 7 = 16
f(2) = 3f(1) + 7 = 3(16) + 7 = 55
f(3) = 3f(2) + 7 = 3(55) + 7 = 172
f(4) = 3f(3) + 7 = 3(172) + 7 = 523
f(5) = 3f(4) + 7 = 3(523) + 7 = 1576
So, the values for f(1), f(2), f(3), f(4), and f(5) using the recursive formula f(n+1) = 3f(n) + 7 are:
f(1) = 16, f(2) = 55, f(3) = 172, f(4) = 523, f(5) = 1576.
(c) f(n+1) = f(n)^2 - 2f(n) - 2:
Using the recursive formula, we can find the values as follows:
f(1) = f(0)^2 - 2f(0) - 2 = 3^2 - 2(3) - 2 = 1
f(2) = f(1)^2 - 2f(1) - 2 = 1^2 - 2(1) - 2 = -3
f(3) = f(2)^2 - 2f(2) - 2 = (-3)^2 - 2(-3) - 2 = 7
f(4) = f(3)^2 - 2f(3) - 2 = 7^2 - 2(7) - 2 = 41
f(5) = f(4)^2 - 2f(4) - 2 = 41^2 - 2(41) - 2 = 1601
So, the values for f(1), f(2), f(3), f(4), and f(
using the recursive formula f(n+1) = f(n)^2 - 2f(n) - 2 are:
f(1) = 1, f(2) = -3, f(3) = 7, f(4) = 41, f(5) = 1601.
(d) f(n+1) = 3^(f(n)/3):
Using the recursive formula, we can find the values as follows:
f(1) = 3^(f(0)/3) = 3^(3/3) = 3^1 = 3
f(2) = 3^(f(1)/3) = 3^(3/3) = 3^1 = 3
f(3) = 3^(f(2)/3) = 3^(3/3) = 3^1 = 3
f(4) = 3^(f(3)/3) = 3^(3/3) = 3^1 = 3
f(5) = 3^(f(4)/3) = 3^(3/3) = 3^1 = 3
So, the values for f(1), f(2), f(3), f(4), and f(5) using the recursive formula f(n+1) = 3^(f(n)/3) are:
f(1) = 3, f(2) = 3, f(3) = 3, f(4) = 3, f(5) = 3.
Note: In the case of (d), the recursive formula leads to the same value for all values of n.
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What is the temperature increase in degrees Fahrenheit that is equivalent to a temperature increase of 10°C?
Answer: \(50^{\circ}F\)
Step-by-step explanation:
Given
Temperature increase is \(10^{\circ}C\)
We know, conversion scale of Celcius to Fahrenheit is
\(0^{\circ}C\times \dfrac{9}{5}+32=32^{\circ}F\)
for \(10^{\circ}C\), it is
\(\Rightarrow 10\times \dfrac{9}{5}+32\\\\\Rightarrow 18+32=50^{\circ}F\)
It is equivalent to \(50^{\circ}F\)
What is the value of the expression below?
72 ÷ 4.5x3+8
Answer:
56
Step-by-step explanation:
Apply PEMDAS:
\(72 / 4.5*3+8\\\\16*3+8\\\\48+8\\\\\boxed{56}\)
Suppose the derivative of function f is
f'(x) =(x+1)^2(x-3)^5(x-6)^4
On what interval is f increasing?
The function f is increasing on the interval (6, ∞).
The function f will be increasing in the intervals where f'(x) > 0.
To find these intervals, we can examine the sign of each factor of f'(x), which is (x + 1)²(x - 3)⁵(x - 6)⁴.
We can analyze the sign of f(x) by considering the factors individually:
(x+1)²: This factor is always positive since it is the square of a real number.
(x - 3)⁵: This factor is positive when x>3 and negative when x< 3.
(x - 6)⁴: This factor is positive when x>6 and negative when x< 6.
We need to consider the overlapping regions of positivity for each factor.
When x>6, all three factors are positive, so f ′ (x) is positive.
When 3<x<6: In this interval, the factor (x+1)² is positive, but both (x−3)⁵ and (x−6)⁴ are negative.
Thus, f ′ (x) is negative.
When x<−1: In this interval, (x+1)² is negative, while (x−3)⁵ and (x−6)⁴ are positive.
Hence, f ′ (x) is negative.
Therefore, the function f(x) is increasing on the interval x>6.
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It takes a man 6 hours to row a boat 24km upstream and covers a distance of 36 km downstream in 6 hours. What will be the speed of the man in still water
Answer:
5 km/h
Step-by-step explanation:
Speed of man in still water = s
Speed of current = c
Speed upstream = s - c
Distance upstream = 24 km
Time upstream = 6 hours
Speed downstream = s + c
Distance downstream = 36 km
Time downstream = 6 hours
Speed Equation
speed = distance/time
distance = speed × time
d = st
We write a distance equation for upstream and a second distance equation for downstream.
Upstream:
d = st
24 = (s - c) × 6
Divide both sides by 6 and switch sides:
s - c = 4 Equation 1
Downstream:
d = st
36 = (s + c) × 6
Divide both sides by 6 and switch sides.
s + c = 6 Equation 2
We now have two equations in two variables. We use equations 1 and 2 as a system of equations.
s - c = 4
s + c = 6
Add the equations to use the addition method.
2s = 10
s = 5
Answer: 5 km/h
g what are the limits for outliers? (round your answers to the nearest whole number. negative amounts should be indicated by a minus sign.)
The distribution of component size is likely skewed to the right so it is mild positive skewed. so, the correct option is A). Lower limit for outliers is -279 and upper limit is 1016.
The fact that the largest component (California) has more than three times as many members as the smallest component (Rhode Island) suggests a potentially right-skewed distribution. So, the correct answer is mild positive skewed and option is A).
To determine the limits for outliers, we need to calculate the lower and upper bounds. Using the interquartile range (IQR) method, we can calculate the lower and upper bounds as:
Lower bound = Q1 - 1.5 x IQR
Upper bound = Q3 + 1.5 x IQR
Where Q1 is the first quartile, Q3 is the third quartile, and IQR is the interquartile range.
Using a calculator or statistical software, we can find:
Q1 = 197
Q3 = 542
IQR = Q3 - Q1 = 345
Substituting these values, we get:
Lower bound = 197 - 1.5 x 345 = -279
Upper bound = 542 + 1.5 x 345 = 1016
Therefore, any component size less than -279 or greater than 1016 would be considered an outlier.
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--The given question is incomplete, the complete question is given
" The American Society of PeriAnesthesia Nurses (ASPAN; www.aspan.org) is a national organization serving nurses practicing in ambulatory surgery, preanesthesia, and postanesthesia care. The organization consists of the 40 components listed below.
State/Region Membership
Alabama 95
Arizona 399
Maryland, Delaware, DC 531
Connecticut 239
Florida 631
Georgia 384
Hawaii 73
Illinois 562
Indiana 270
Iowa 117
Kentucky 197
Louisiana 258
Michigan 411
Massachusetts 480
Maine 97
Minnesota, Dakotas 289
Missouri, Kansas 282
Mississippi 90
Nebraska 115
North Carolina 542
Nevada 106
New Jersey, Bermuda 517
Alaska, Idaho, Montana, Oregon, Washington 708
New York 891
Ohio 708
Oklahoma 171
Arkansas 68
California 1,165
New Mexico 79
Pennsylvania 575
Rhode Island 53
Colorado 409
South Carolina 237
Texas 1,026
Tennessee 167
Utah 67
Virginia 414
Vermont, New Hampshire 144
Wisconsin 311
West Virginia 62 A. What do you conclude about the shape of the distribution of component size?
multiple choice 1
A) Mild negative skewness
B) Mild positive skewness
B. What are the limits for outliers? (Round your answers to the nearest whole number. Negative amounts should be indicated by a minus sign.)"--
Use the bar model to add these fractions
Answer:
Not Sure how to solve this...
Step-by-step explanation:
BUT
5 minutes is equal to \(\frac{1}{12}\)
10 minutes is equal to \(\frac{1}{6}\)
15 minutes is equal to \(\frac{1}{4}\)
30 minutes is equal to \(\frac{1}{2}\)
A sample of people attending a professional football game averages 13.7 years of formal education while the surrounding community averages 12.1. The difference is significant at the .05 level. What could we conclude
The formal education levels of the sample differ significantly from the formal education levels of the surrounding community, the sample is not representative of the surrounding community.
In statistics, the t-test is a hypothesis testing approach that determines whether there is a significant difference between the mean values of two groups. T-test is conducted to determine the difference between two group means, and it is done through comparing the p-value to the significance level. Here, the t-test is used to compare the average formal education levels of people attending a professional football game and the surrounding community.The difference between the formal education levels of the people attending the game and the surrounding community is significant at the .05 level.
Hence, we can say that the formal education levels of the people attending the game significantly differ from the surrounding community at a .05 level of significance. Furthermore, since the p-value is less than the significance level, we can reject the null hypothesis.
To know more about t-test, click here
https://brainly.com/question/1189751
#SPJ11
The only room visible in the KELLER house is ANNIE’S, where by lamplight ANNIE in a shawl is at a desk writing a letter; at her bureau HELEN in her customary unkempt state is tucking her doll in the bottom drawer as a cradle, the contents of which she has dumped out, creating as usual a fine disorder.
—The Miracle Worker,
William Gibson
Based on the stage directions, where does this scene in the play take place?
in Annie’s room at the Perkins Institute for the Blind
in Annie’s room in the Keller residence
in a classroom at the Perkins School for the Blind
in Annie’s room at a hotel near the Keller home
Answer:
The Answer is B
Step-by-step explanation:
Answer:
the answer is b he is right
Step-by-step explanation:
factor the trinomial below. x^2+13x+42
Answer:
(x + 6)(x + 7)
Step-by-step explanation:
To factor the trinomial x^2 + 13x + 42, we need to find two numbers that multiply to 42 and add up to 13.
One way to do this is to list all the pairs of factors of 42 and see which pair adds up to 13:
1, 42 -> 1 + 42 = 43
2, 21 -> 2 + 21 = 23
3, 14 -> 3 + 14 = 17
6, 7 -> 6 + 7 = 13
So the pair of factors that we want is 6 and 7. We can use these numbers to rewrite the middle term of the trinomial:
x^2 + 13x + 42 = x^2 + 6x + 7x + 42
Next, we can group the first two terms and the last two terms:
x^2 + 6x + 7x + 42 = (x^2 + 6x) + (7x + 42)
Now, we can factor out the greatest common factor from each group:
x(x + 6) + 7(x + 6)
Notice that we have a common factor of (x + 6) in both terms. We can factor this out:
(x + 6)(x + 7)
Solve the problem. A vendor sells hot dogs and bags of potato chips. A customer buys 3 hot dogs and 5 bags of potato chips for $16.25. Another customer buys 5 hot dogs and 4 bags of potato chips for $19.50. Find the cost of each item.
A. $2.75 for a hot dog; $2.00 for a bag of potato chips
B.$2.50 for a hot dog; $1.75 for a bag of potato chips
C.$2.50 for a hot dog: $2.00 fora bag of potato chips
D. $1.75 for a hot dog; $2.50 for a bag of potato chips
Answer
ok the answer is C
Step-by-step explanation:
1.75*4=7
.75*2=1.5
7+1.5=8.50
TBH, i am not sure what im doing. Here is a pic of the question.
Answer:
7
Step-by-step explanation:
The order of operations tells you to start any evaluation by looking at the innermost set of parentheses first.
Here, that means your first step is to find the value of h(-3). You do that by finding the input (x) value -3 in the table for h(x), and locating the corresponding output, h(x), which is 2.
Now, the problem becomes evaluating g(2).
You do the same thing for that function: locate the input x=2 in the table for g(x) and find the corresponding output: 7.
Now, you know ...
g(h(-3)) = g(2) = 7
Which shows how to find the value of this expression when x=-2 and Y = 5? (3x^3y^-2)^2
3^2(-2)^6/5^4
3(-2)^6/5^4
3^2(5)^6/(-2)^4
3/(2)^65^4
plz answer I'll give Brainliest to first (as long as it's right lol)
Using the Pythagorean Theorem, prove whether or not the following triangle is a right triangle. Remember to show your work.
A triangle with side lengths of 15m, 9m, and 12m.
Answer:
This is a right triangle.
Step-by-step explanation:
\( \sqrt{ {9}^{2} + {12}^{2} } = \sqrt{81 + 144} = \sqrt{225} = 15\)