Answer:
y=-2x+15
Step-by-step explanation
A perpendicular line always has the opposite reciprocal slope of the line it is 90 degrees from.
Since the slope of the other line is 1/2, the slope of this line must be -2. And with the slope of a line -2 with point (4,7), you can start plugging in numbers.
y=-2x+b
7= -2(4)+b
7= -8+b
15=b
Therefore, the equation of the line is y=-2x+15
What is angle D equal??
Please help me on this question. Thanks
Answer:
E. p - 7 + 7 = 22 + 7
Step-by-step explanation:
p - 7 + 7 = 22 + 7 ( -7 + 7 = 0)
p = 22 + 7
p - 7 = 22//
50 Points! Multiple choice algebra question. Photo attached. Thank you!
The exact value of cos theta if the terminal side of theta in standard position contains the point (6,-8) is, 3 / 5
We have to given that;
the terminal side of theta in standard position contains the point (6,-8)
Hence, For given condition we get;
The exact value of cos theta if the terminal side of theta in standard position contains the point (6,-8) is,
Here, x = 6, y = - 8
Hence, We get;
r = √x² + y²
r = √6² + 8²
r = √36 + 64
r = √100
r = 10
So, The exact value of cos theta if the terminal side of theta in standard position contains the point (6,-8) is,
cos θ = x / r
cos θ = 6 / 10
cos θ = 3 / 5
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5.
a.
A study conducted at a school showed that the batteries used by calculators lasted an average of 101 days with a margin of error of ‡9 %.
What is the minimum average number of days a teacher can expect to have the batteries last in her classroom?
b.
There are roughly 279 days from the first day of school until the last day of school, the teacher has 24
TI-84 calculators and each one requires 4 triple A batteries. If the teacher can buy triple A batteries wholesale at 52 cents a battery, how much do you think she will need to spend at most on batteries for calculators over the year?
a. The teacher can expect the batteries to last at least 92.09 days on minimum average.
b. The teacher will need to spend at most $49.92 on batteries for calculators over the year.
What is minimum average day?
a. The margin of error of ‡9% means that we can be 95% confident that the true average number of days the batteries will last is within 9% of the sample average. To find the minimum average number of days a teacher can expect to have the batteries last in her classroom, we subtract the margin of error from the sample average:
Minimum average = 101 - (0.09)(101) = 92.09 days (rounded to two decimal places)
Therefore, the teacher can expect the batteries to last at least 92.09 days on average.
What is spend ?
b. The total number of batteries required for the 24 TI-84 calculators is:
24 calculators x 4 batteries per calculator = 96 batteries
The total cost of the batteries will be:
96 batteries x $0.52 per battery = $49.92 (rounded to two decimal places)
Therefore, the teacher will need to spend at most $49.92 on batteries for calculators over the year, assuming all batteries need to be replaced.
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What is the slope of the line that passes through the points
(
−
8
,
−
3
)
(−8,−3) and
(
−
24
,
1
)
?
(−24,1)? Write your answer in simplest form.
If a_1=3a 1 =3 and a_n=(a_{n-1})^2+4a n =(a n−1 ) 2 +4 then find the value of a_4a 4 .
The fourth term a₄ of the sequence is 29933
How to determine the value of a₄ of the sequence?From the question, we have the following definition of the function that can be used in our computation:
a₁= 3
aₙ = (aₙ₋₁)² + 4
The above definitions imply that we simply square the previous term and then add 4 to the squared result to get the current term
Using the above as a guide,
so, we have the following representation
a₂ = (3)² + 4
a₂ = 13
Also, we have
a₃ = (13)² + 4
a₃ = 173
Lastly, we have
a₄ = (173)² + 4
Evaluate the equation
a₄ = 29933
Hence, the value of a₄ is 29933
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Which value is equivalent to 8?
Answer:
I cant see the answers to help you.
Step-by-step explanation:
Identify the polygon that has vertices A(−10,−1), P(−7,3), E(−3,0), and X(−6,−4), and then find the perimeter and area of the polygon.
Answer:
square; perimeter 20 units; area 25 square units.
Step-by-step explanation:
As the attachment shows, each side of the polygon is the hypotenuse of a 3-4-5 right triangle, so has length 5 units. The perimeter is the sum of those lengths, 4×5 = 20; the area is the product of the lengths of adjacent sides, 5×5 = 25.
The figure is a square of side length 5 units.
The perimeter is 20 units; the area is 25 square units.
identify which equations have one solution, infinitely many solutions, or no solution 3u+40+2u=6u-30-u
Answer:
I did the math there is no answer
Help thank you! A B C or D
Answer:
below
Step-by-step explanation:
'x' cannot be zero because you would then have an illegal fraction with a zero denominator
the only interval listed that does not include zero is ( 1, +inf)
Answer:
D.
Step-by-step explanation:
f(x) = |x|
|x| = x for x > or = 0
|x| = -x for x < 0
At x = 0
Left limit = Right limit = Function value = 0
|x| = is continuous at x = 0.
Left derivative (at x = 0) = -1
Right derivative (at x = 0) = 1
Find the missing side. 31° Z z = [?] Round to the nearest tenth. Remember: SOHCAHTOA 21
A²+B²= C²
31²+ 21²= z²
961+441 = z²
1402= z²
z= 37.443290454
4, 12, 20, ...
Find the 41st term.
Answer:
324
Step-by-step explanation:
All you're simply doing is adding 8 to each number up until the 41st term OR an easier way, using the arithmetic sequence formula as shown below in the red box:
an is the term you want to find, in this case: the 41st term.
a1 is the first term in the list of ordered numbers
n is the term position, in this case, the same as an
d is the difference whether if it's adding or subtracting.
Now match the numbers in the formula and solve using PEMDAS from left to right!
(Parenthesis, exponents, multiply, divide, add, subtract)
Find the measure of angle 0.
35°
83°
23°
23
Step-by-step explanation:
The answer is 23 because it is closer to the 0
Answer: the answer is 141
Step-by-step explanation:
bro its not that hard the guy up top is a bum just add all the angles together thats the answer and remember the formula is (n-2)180 for INTERIOR i wrote it in caps cuz some of yall goofy fr
If f(x)=x² – 4x, what is the value of 2f(a-1)?
The correct value of 2f(a-1) is 2a^2 - 12a + 10.
To find the value of 2f(a-1), we need to substitute (a-1) into the function f(x) and then multiply the result by 2.
Given: f(x) = x^2 - 4x
Substituting (a-1) into the function:
f(a-1) = (a-1)^2 - 4(a-1)
Expanding and simplifying:
f(a-1) = (a^2 - 2a + 1) - (4a - 4)
f(a-1) = a^2 - 2a + 1 - 4a + 4
f(a-1) = a^2 - 6a + 5
Now, we multiply the result by 2:
2f(a-1) = 2(a^2 - 6a + 5)
Expanding:
2f(a-1) = 2a^2 - 12a + 10
Therefore, the value of 2f(a-1) is 2a^2 - 12a + 10.
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You roll a standard number cube. Find P(number greater than 2). 1 1/3 5/6 2/3
The probability of rolling a number greater than 2 on a standard number cube is 2/3.
Since we are interested in the probability of rolling a number greater than 2, we need to count the favorable outcomes and divide them by the total number of possible outcomes.
The numbers greater than 2 on the cube are 3, 4, 5, and 6, which means there are four favorable outcomes.
Since the cube has six possible outcomes in total, the probability of rolling a number greater than 2 is 4/6, which simplifies to 2/3.
Therefore, the probability of rolling a number greater than 2 on a standard number cube is 2/3.
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Which expression is equivalent to x-6?
Answer:
X^-2 x X^3 or C
Step-by-step explanation:
why because a negative and a positive when multiplied make a negative
\( \Huge \color{lime}{\boxed{{x}^{3} \times {x}^{3}}}\)
.....Step-by-step explanation.....
\( \large \underline \color {pink}{lets \: solve \:↬} \)
\(\large \pink {\sf{⇒ \: {x}^{ - 3} \times {x}^{ - 3} }} \\ \\ \large \red{ \tt{(by \: exponent \: rule \: of \: power \: are \: added)}} \\ \\ \pink {\sf{ ⇒ \: {x}^{ - 3 + ( - 3)} } } \\ \\ \large \pink { \sf{ ⇒ \: {x}^{ - 3 - 3} }} \\ \\ \large \pink { \sf{⇒ \: {x}^{ - 6} }} \\ \\ \)
\(\large\color {blue}{\boxed{\mathfrak{❥\:Velvet\:Pearl}}}\)
Which statements about the reflection are true? Check all that apply.
Clayton could use the relationship (x, y) right-arrow (y, x) to find the points of the image.
Clayton could negate both the x and y values in the points to find the points of the image.
C’ will remain in the same location as C because it is on the line of reflection.
C’ will move because all points move in a reflection.
The image and the pre-image will be congruent triangles.
The image and pre-image will not have the same orientation because reflections flip figures.
The statements that are true are:
Clayton could use the relationship (x, y) right-arrow (y, x) to find the points of the image.
Clayton could negate both the x and y values in the points to find the points of the image.
C’ will move because all points move in a reflection.
The image and the pre-image will be congruent triangles.
The image and pre-image will not have the same orientation because reflections flip figures.
Options A, B, D, E, and F.
What is a reflection?There are two ways of reflection.
Along x-axis:
(x, y) – (x, -y)
Along y-axis:
(x, y) - (-x, y)
We have,
Clayton could use the relationship (x, y) → (y, x) to find the points of the image.
This is the y = x reflection rule.
This is true.
Clayton could negate both the x and y values in the points to find the points of the image.
Reflection of (x, y) along the x-axis and y-axis consecutively will give us
(-x, -y).
This is true.
C’ will remain in the same location as C because it is on the line of reflection.
This is not true.
C’ will move because all points move in a reflection.
This is true.
The image and the pre-image will be congruent triangles.
This is true.
The image and pre-image will not have the same orientation because reflections flip figures.
This is true.
Thus,
All statements are true except the statement:
C’ will remain in the same location as C because it is on the line of reflection.
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Curtis bought a skateboard which he later sold at a 30% loss for £14. How much did Curtis pay for
the skateboard originally?
Answer:
18 pounds if I'm correct
graph the line passing through (−4,−1) whose slope is m=-4/5
Answer:
\(y=-\frac{4}{5}x-\frac{21}{5}\)
Step-by-step explanation:
The fastest way is to use point-slope form with \(m=-\frac{4}{5}\) and \((x_1,y_1)=(-4,-1)\):
\(y-y_1=m(x-x_1)\\y-(-1)=-\frac{4}{5}(x-(-4))\\y+1=-\frac{4}{5}(x+4)\\y+1=-\frac{4}{5}x-\frac{16}{5}\\y=-\frac{4}{5}x-\frac{21}{5}\)
To graph the line passing through (-4,-1) with slope m = -4/5, we can use the slope-intercept form of the equation of a line, which is:
y = mx + b
where m is the slope and b is the y-intercept.
Substituting m = -4/5, x = -4, and y = -1, we can solve for b:
-1 = (-4/5)(-4) + b
-1 = 3.2 + b
b = -4.2
Therefore, the equation of the line is:
y = (-4/5)x - 4.2
To graph the line, we can plot the given point (-4,-1) and then use the slope to find additional points. Since the slope is negative, the line will slope downwards from left to right. We can find the y-intercept by setting x = 0 in the equation:
y = (-4/5)x - 4.2
y = (-4/5)(0) - 4.2
y = -4.2
So the y-intercept is (0,-4.2).
Using this point and the given point (-4,-1), we can draw a straight line passing through both points.
Here is a rough sketch of the graph:
|
|
| *
| /
| /
| /
-----*--------
|
|
|
|
|
The point (-4,-1) is marked with an asterisk (*), and the y-intercept (0,-4.2) is marked with a dash. The line passing through these two points is the graph of the equation y = (-4/5)x - 4.2.
A group of 20 people were asked to remember as many items as possible from a list before and after being taught a memory device. Researchers want to see if there is a significant difference in the amount of items that people are able to remember before and after being taught the memory device. They also want to determine whether or not men and women perform differently on the memory test. They choose α = 0.05 level to test their results. Use the provided data to run a Two-way ANOVA with replication.
A B C
Before After
Male 5 7
4 5
7 8
7 8
7 8
7 8
5 6
7 7
6 7
Female 5 8
5 6
8 8
7 7
6 6
8 9
8 8
6 6
7 6
8 8
Answer:
1. There is no difference in amount of items that people are able to remember before and after being taught the memory device.
2. There is no difference between performance of men and women on memory test.
Step-by-step explanation:
Test 1:
The hypothesis for the two-way ANOVA test can be defined as follows:
H₀: There is no difference in amount of items that people are able to remember before and after being taught the memory device.
Hₐ: There is difference in amount of items that people are able to remember before and after being taught the memory device.
Use MS-Excel to perform the two-way ANOVA text.
Go to > Data > Data Analysis > Anova: Two-way with replication
A dialog box will open.
Input Range: select all data
Rows per sample= 10
Alpha =0.05
Click OK
The ANOVA output is attaches below.
Consider the Columns data:
The p-value is 0.199.
p-value > 0.05
The null hypothesis will not be rejected.
Conclusion:
There is no difference in amount of items that people are able to remember before and after being taught the memory device.
Test 2:
The hypothesis to determine whether or not men and women perform differently on the memory test is as follows:
H₀: There is no difference between performance of men and women on memory test.
Hₐ: There is a difference between performance of men and women on memory test.
Consider the Sample data:
The p-value is 0.075.
p-value > 0.05
The null hypothesis will not be rejected.
Conclusion:
There is no difference between performance of men and women on memory test.
Find the interest earned given the following:Amount needed: $269,000Time in years: 6Interest: 8%Compounded: semiannually
Answer:
\(I=\text{ \$}161,678\)Step-by-step explanation:
Compound interest is represented by the following equation:
\(\begin{gathered} A=P(1+\frac{r}{n})^{nt} \\ \text{where,} \\ P=\text{ principal amount invested} \\ r=\text{ interest rate} \\ n=\text{ times compounded per unit ''t''} \\ t=\text{ time in years} \end{gathered}\)Therefore, for the given information:
\(A=269,000\cdot(1+\frac{0.08}{2})^{12}\)Solve for the future amount, and then subtract it from the principal. The product would be the interest earned:
\(\begin{gathered} A=430,678 \\ \text{Hence,} \\ I=A-P \\ I=430678-269000 \\ I=\text{ \$}161,678 \end{gathered}\)You roll a 6-sided die two times.
What is the probability of rolling an even number and then rolling a number less than 4?
Write your answer as a percentage.
%
Guys pls hurry
The triangle above has the following measures.
s = 29 m
r= 63 m
Find the m/Q.
Round to the nearest tenth and include correct units.
Show all your work.
The value of m∠Q as shown in the right-angled triangle below is 62.59°.
The Formula used is:
m∠Q = cos⁻¹(s/r)........................ (1)
Where:
s = 29 m
r = 63 m
Now, Substitute these values into equation 1
m∠Q = cos⁻¹(29/63)
m∠Q = cos⁻¹(0.46)
m∠Q = 62.59°
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Solve : (6a -5b -8c) - ( 15b + 2a - 5c)
Answer:
4a - 20b - 3c
Step-by-step explanation:
6a - 5b - 8c - 15b - 2a + 5c
= 4a - 20b - 3c
I HOPE IT WILL HELP YOU.
Thank you.
I HOPE YOUR DAY GOES GREAT.
The function f(x) = 3x + 13 x + 4 1 is a transformation of the function g(x) = r(x) To make the transformation visible, rewrite the rule for f in the form f(x) = q (x) + d (r) where q, r, and d are polynomials.
The rule for f in the desired form is: f(x) = (3x^2 + 12x + 13r(x) + 52) / (x + 4)
How to rewrite the rule for f in the formTo rewrite the rule for f in the form f(x) = q(x) + d(r), we need to first write g(x) in terms of r(x).
We know that g(x) = r(x) / (x + 4) + 1, so we can rewrite it as:
g(x) = r(x) / (x + 4) + (x + 4) / (x + 4)
g(x) = (r(x) + x + 4) / (x + 4)
Now, we can see that f(x) is a transformation of g(x) with q(x) = 3x and d(r) = 13. So, we can write:
f(x) = q(x) + d(r)
f(x) = 3x + 13(r(x) + x + 4) / (x + 4)
f(x) = (3x(x + 4) + 13r(x) + 52) / (x + 4)
Therefore, the rule for f in the desired form is: f(x) = (3x^2 + 12x + 13r(x) + 52) / (x + 4)
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The general admission rate to an amusment park is 12$. Each ride ticket cost $2.75 . Which if the following reprrsents the cost for a day at the amusement park as a function of the number of ride tickets purchased ?
The cost for a day at the amusement park as a function of the number of ride tickets purchased is y = 12 + 2.75x
What are linear equations?Linear equations are equations that have constant average rates of change. Note that the constant average rates of change can also be regarded as the slope or the gradient
How to determine the function of the number of ride tickets purchasedThe given parameters are:
Admission rate to the amusement park = $12
Cost of each ticket = $2.75
Let the number of tickets be x, and the total cost be y
So, the function can be represented as
y = Admission rate to the amusement park + Cost of each ticket * x
This gives
y = 12 + 2.75 * x
Evaluate the product
y = 12 + 2.75x
Hence, the cost for a day at the amusement park as a function of the number of ride tickets purchased is y = 12 + 2.75x
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24 is 120% of what?
Answer:
\(\frac{24}{20}= \frac{120}{100}\)
Step-by-step explanation:
120/100 * x = 24
1.2 * x = 24
x = 20
24 is 120% of 20
The answer missing blanks to your problems are \(\frac{24}{20}= \frac{120}{100} \\\)
Hope this helps :)
Have a nice day!
Recall that with base-ten blocks: 1 long 10 units, 1 flat 10 longs, and 1 block 10 flats. What is the fewest number of multibase blocks that can be used to represent the corresponding numeral in the given base?
a. 20 longs in base seven
b. 10 longs in base three
a. The answer is: The fewest number of multibase blocks required to represent 20 longs in base seven is 2 flats.
b. The answer is: The fewest number of multibase blocks required to represent 10 longs in base three is 3 flats and 1 unit.
a. To represent 20 longs in base seven, we need to find the fewest number of multibase blocks required.
In base seven, we have the following conversions:
1 long = 1 unit
1 flat = 10 units
1 block = 10 flats
To represent 20 longs, we can use 2 flats (each flat representing 10 units) and 0 units since there are no remaining units.
So, the fewest number of multibase blocks required would be 2 flats.
Therefore, the answer is: The fewest number of multibase blocks required to represent 20 longs in base seven is 2 flats.
b. To represent 10 longs in base three, we need to find the fewest number of multibase blocks required.
In base three, we have the following conversions:
1 long = 1 unit
1 flat = 3 units
1 block = 3 flats
To represent 10 longs, we can use 3 flats (each flat representing 3 units) and 1 unit since there is one remaining unit.
So, the fewest number of multibase blocks required would be 3 flats and 1 unit.
Therefore, the answer is: The fewest number of multibase blocks required to represent 10 longs in base three is 3 flats and 1 unit.
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Simplify the following expression completely.
x2 + 6x + 9
—————-
x2 + 2x - 3
Answer:
The answer is that image below. If it isn't correct, I'm sorry.
Sara is a librarian and works at least 10 hours per week. If Sara would like to work extra shifts, they are added to her
schedule in two-hour increments. Which equation models the number of hours that Sara will work at the library this
week? Assume x is the number of two-hour increments and y is the total number of hours worked.
Answer:
y = 10 + 2x
or
y = 2x + 10
Step-by-step explanation:
She works a fixed 10 hours each week, so we start with
y = 10
Now she adds 2-hour increments. She can have 0, 1, 2, or another number of increments. x represents the number of increments. Since each increment is 2 hours, 2x represents the number of hours added by the increments. Now we add 2x to the fixed number of hours.
y = 10 + 2x
or
y = 2x + 10
Answer:
y = 2x + 10
Step-by-step explanation: