Find the equation of the line. Use exact numbers. y =__ x +__​

Find The Equation Of The Line. Use Exact Numbers. Y =__ X +__

Answers

Answer 1

EXPLAIN:

Ex:  the line is:  y = ax + b

The line go through 2 points ( 0 ; -5 ) and ( 5 ; 0 )

So: \(\left \{ {{0=5a+b} \atop {-5=0a+b}} \right. =>\left \{ {{b=-5a} \atop {b=-5}} \right. =>\left \{ {{a=1} \atop {b=-5}} \right.\)

The line: y = x - 5 = (1)x + (-5)

ANSWER: y = (1)x + (-5)

ok done. Thank to me :>


Related Questions

Jacqueline bought a bicycle at wholesale cost for $210 dollars. If the bicycle is normally $300 from the local bike shop, what is the percent markup the bike shop adds to the wholesale cost?

Answers

If Jacqueline bought a bicycle at wholesale cost for $210 dollars. If the bicycle is normally $300 from the local bike shop, Then 30% markup the bike shop adds to the wholesale cost

What is Percentage?

Percentage, a relative value indicating hundredth parts of any quantity.

Given,

Jacqueline bought a bicycle at wholesale cost for $210 dollars.

The actual price of bicycle is normally $300 from the local bike shop.

We need to find the percent markup the bike shop adds to the wholesale cost.

For this we need to find the difference and we have to divide it by actual price

300-210/300=90/300=0.3

Now multiply 0.3 with 100 as hundredths to get the percentage value

0.3×100=30

Hence 30 percent markup the bike shop adds to the wholesale cost

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Find F Such That F′(X)=6x−5,F(9)=0

Answers

F(9) = 3(9)^2 - 5(9) + 198 = 0, as required by the initial condition.

Therefore, F(x) = 3x^2 - 5x + 198.

To find the function F(x) such that F'(x) = 6x - 5 and F(9) = 0, we need to integrate F'(x) with respect to x to get F(x).

First, we integrate 6x - 5 with respect to x:

∫ (6x - 5) dx = 3x^2 - 5x + C

Here, C is the constant of integration.

Next, we can use the initial condition F(9) = 0 to solve for C:

F(9) = 3(9)^2 - 5(9) + C = 0

C = 243 - 45 = 198

So, the function F(x) that satisfies F'(x) = 6x - 5 and F(9) = 0 is:

F(x) = 3x^2 - 5x + 198

Each term in this function has a derivative, and when we take the derivative of the entire expression, we get 6x - 5, which is the given derivative. Additionally, plugging in x=9 to the function yields F(9) = 3(9)^2 - 5(9) + 198 = 0, as required by the initial condition.

Therefore, F(x) = 3x^2 - 5x + 198.

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jeff and chad decide to flip a coin 3 times to see who pays for lunch. chad picks heads and he must get heads at least twice out of 3 flips to win and have jeff pay for his lunch. what is the probability chad gets at least 2 heads on 3 flips?

Answers

The probability that chad gets at least 2 heads on 3 flips is 1/2 which was found using the sample space.

How does probability explain work?Simply put, probability is the likelihood that something will occur. When we don't know how an event will turn out, we might discuss the likelihood or likelihood of several outcomes. Statistics is the study of occurrences that follow a probability distribution.

Given: To decide who will pay for lunch, Jeff and Chad decide to flip a coin three times. Chad chooses heads, and in order to win and have Jeff pay for his lunch, he must get heads at least twice out of three times.

Let,

H = Heads

T = Tails

Sample space =  {HHH, HTH,THH,TTH, HHT, HTT,THT,TTT​}

Total number of possible outcomes = 8

Probability that chad gets at least 2 heads is given as:

P(A)=P(getting two heads)+P(getting 3 heads)

= 3/8 + 1/8

= 4/8

= 1/2

Therefore,  the probability chad gets at least 2 heads on 3 flips is 1/2 which was found using the sample space.

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Find the areas of the sectors formed by NMP. Round your answer to the hundredth of a square centimeter.

Find the areas of the sectors formed by NMP. Round your answer to the hundredth of a square centimeter.

Answers

Consider that the area of a sector of a circle is given by:

\(A=\frac{\theta}{360}\pi r^2\)

where θ is the angle of the sector and r is the radius.

For θ=40 and r = 8cm, you obtain:

\(A=\frac{40}{360}\pi(8cm)^2=22.34cm^2\)

The area of the small sector is about 22.34 cm^2.

Now, for θ=320 and r = 8cm, you obtain:

\(A^{\prime}=\frac{320}{360}\pi(8cm)^2=178.72cm^2\)

The area of the small sector is about 178.72 cm^2.

simplify √5(8+3√6)
I cant figure this problem out can someone help me?

Answers

The answer is correct
simplify 5(8+36) I cant figure this problem out can someone help me?

can someone answer page 3 question 3, page 5 question 3, all of page 6

Answers

The answers to the questions involving trigonometry are: 90, BC/AB ÷ BC/AB = 1, g = 6.5, <I = 62 degrees, h= 13.8, 12.0, x = 6.8, x = 66.4, 160.6, The pole = 6.7

What is trigonometrical ratios?

Trigonometric ratios are special measurements of a right triangle, defined as the ratios of the sides of a right-angled triangle.  There are three common trigonometric ratios: sine, cosine, and tangent

For page 3 question 3,

a) <A + <B = 90 since <C = right angle

b) SinA = BC/AB and CosB = BC/AB

The ratio of the two angles BC/AB ÷ BC/AB = 1

I notice that the ratio of sinA and cosB gives 1

b) The ratio of CosA and SinB will give

BC/AB ÷ BC/AB

= BC/AB * AB/BC = 1

For page 5 number 3

Tan28 = g/i

g/12.2 = tan28

cross multiplying to have

g = 12.2*tan28

g = 12.2 * 0.5317

g = 6.5

b) the angle I is given as 90-28 degrees

<I = 62 degrees

To find the side h we use the Pythagoras theorem

h² = (12.2)² + (6.5)²

h² = 148.84 +42.25

h²= 191.09

h=√191.09

h= 13.8

For page 6

1) Sin42 = x/18

x=18*sin42

x = 18*0.6691

x = 12.0

2) cos28 = 6/x

xcos28 = 6

x = 6/cos28

x [= 6/0.8829

x = 6.8

3)  Tan63 = x/34

x = 34*tan63

x= 34*1.9526

x = 66.4

4) Sin50 123/x

xsin50 = 123

x = 123/sin50

x = 123/0.7660

x =160.6

5)  Sin57 = P/8

Pole = 8sin57

the pole = 8*0.8387

The pole = 6.7

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Suppose T: ℝ3→ℝ2 is a linear transformation. Let U, V and W be the vectors given below, and suppose that T(U) and T(V) are as given. Find T(W).
U = 1, -3, 3 V = −1,3,−2 W = −3,9,−7 T(U) = 2,2 T(V) = 0,1

T(W) = ???

Answers

By using the concept of Linear Transformation, the value of T(W) obtained is T(W) = (2, 6)

What is Linear Transformation?

A function through one vector space to the next that respects this same underlying (linear) structure of the each vector space is called a linear transformation. A linear operator, or map, is another name for a linear transformation. The transformation is known as just an endomorphism as well as, if invertible, an automorphism when the range of a transformation matches the domain. The underlying field of the two vector spaces must be identical.

Let u, v be two element of a vector space V and let c be a scalar

T is said to be a Linear Transformation if

i) T(u + v) = T(u) + T(v)

ii) T(cu) = cT(u)

T: \(\mathbb{R}^{3} \rightarrow \mathbb{R}^2\) is a linear transformation

U = (1, -3, 3), V = (−1,3,−2)

W = \(c_1\) U + \(c_2\) V

(-3, 9, -7) = \(c_1\)(1, -3, 3) + \(c_2\)(-1, 3, -2)

\(c_1 - c_2 = -3\) ...... (1)

\(3c_1 - 2c_2 = -7\) ..... (2)

Multiplying (1) by 2

\(2c_1 - 2c_2 = -6\) .... (3)

Subtracting  (2) from (3),

\(c_1 = 1\)

Putting the value of \(c_1\) in (1)

1 - \(c_2\) = -3

\(c_2 = 3 + 1\\c_2 = 4\)

T(W) =  T(U) +  4T(V)

T(W) = (2, 2) + 4(0, 1)

T(W) = (2, 6)

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A plastic pool gets filled up with 10L of water per hour.

a) After 2 hours how much water is in the pool? Write an equation.

b) After how many hours will the pool be 80L?

c) Is part b) linear or nonlinear?

Answers

a) The amount of water in the pool after 2 hours can be calculated using the equation.

Water in pool = 10L/hour × 2 hours = 20L.

b) The pool will be 80L when the equation is satisfied: 80L = 10L/hour × Time.

Solving for Time, we find Time = 8 hours.

c) Part b) is linear.

a) To calculate the amount of water in the pool after 2 hours, we can use the equation:

Water in pool = Water filling rate × Time

Since the pool gets filled up with 10L of water per hour, we can substitute the values:

Water in pool = 10 L/hour × 2 hours = 20L

Therefore, after 2 hours, there will be 20 liters of water in the pool.

b) To determine the number of hours it takes for the pool to reach 80 liters, we can set up the equation:

Water in pool = Water filling rate × Time

We want the water in the pool to be 80 liters, so the equation becomes:

80L = 10 L/hour × Time

Dividing both sides by 10 L/hour, we get:

Time = 80L / 10 L/hour = 8 hours

Therefore, it will take 8 hours for the pool to contain 80 liters of water.

c) Part b) is linear.

The equation Water in pool = Water filling rate × Time represents a linear relationship because the amount of water in the pool increases linearly with respect to time.

Each hour, the pool fills up with a constant rate of 10 liters, leading to a proportional increase in the total volume of water in the pool.

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what does x equal
4x+5x+=6+11

Answers

4x+5x+=6+11

9x=17

x=17/9

☞ user58580~ ♥

Answer:

x= 17/9

Step-by-step explanation:

4x+5x=6+11

Combine like terms

9x=17

x=17/9

Please s helppppppo!!!!

Please s helppppppo!!!!

Answers

Answer:

22

Step-by-step explanation:

Hey There!

So if you didn't know angle H is a right angle. So we are given two angles and they want us to find the missing angle

Remember all of the angles of a triangle add up to equal 180

so we subtract the given angles from 180 to find the missing angle

180-90-68=22

so we can conclude that angle G = 22

here is a list of ingredients to make biscuits
200g of butter
180g of caster sugar
400g of plain flour
20g of chocolate chips

Andrew only has 300g of plain flour.
How much of the other ingredients should he use?

Answers

Answer:    150 grams of butter

135 grams of caster sugar

15 grams chocolate chips

300 grams of flour

Step-by-step explanation:

if 300 grams equals 3/4 of 400 grams than all we have to do is get 3/4 of all the other ingredients.

Roberto packed for a weekend trip to his cousin's house. He took a yellow shirt, orange shirt, and a brown shirt. He also packed a pair of blue jeans and a pair of black jeans.

How many different shirt and pant combinations could Roberto wear while at his cousin's house?


A.5

B.6

C.7

D.8

Answers

I think it’s D hope it’s right
It’s A.5 hope it helped

If the sun’s mass is 1.989 × 10^30 kg (1 ), what is the mass in kg of this exoplanet?

Answers

The mass of an exoplanet can be estimated using the mass of the sun and the size of the exoplanet.

What is mass?

Mass is the measure of the amount of matter in an object. It is measured in kilograms (kg), grams (g), and other metric units. Mass is a measure of an object's inertia (the resistance of an object to change its motion) and is related to weight, which is the gravitational force on an object. Mass is different from weight because mass is the same wherever you are, while weight can change depending on where you are in the universe.

The mass of an exoplanet depends on its size and composition, so it is not possible to calculate the exact mass of an exoplanet without knowing more information. However, it is possible to estimate the mass of an exoplanet by using the mass of the sun as a reference point. The mass of the sun is 1.989 × 10³⁰kg, so if we assume that the exoplanet has a similar density to the sun, then the mass of the exoplanet can be calculated by dividing the mass of the sun by the exoplanet's volume.

For example, if the exoplanet is the same size as Earth, it would have a volume of 1.08321 × 10¹² km³ (2). If we divide the mass of the sun (1.989 × 10^30 kg) by this volume, then the mass of the exoplanet would be approximately 1.841 × 10¹⁸ kg. This is approximately 1,841,000,000,000,000,000,000 kg or 1.841 × 10¹⁸ kg.

Therefore, the mass of an exoplanet can be estimated using the mass of the sun and the size of the exoplanet. However, due to the various compositions of different exoplanets, the exact mass of an exoplanet is impossible to calculate without additional information.

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The mass of an exoplanet can be estimated using the mass of the sun and the size of the exoplanet.

What is mass?

Mass is the measure of the amount of matter in an object. It is measured in kilograms (kg), grams (g), and other metric units. Mass is a measure of an object's inertia (the resistance of an object to change its motion) and is related to weight, which is the gravitational force on an object. Mass is different from weight because mass is the same wherever you are, while weight can change depending on where you are in the universe.

To calculate the mass of this exoplanet, we must first determine its mass relative to the sun. If the mass of the exoplanet is 1/10th that of the sun, then the mass of the exoplanet would be 1.989 × 10²⁹ kg. If the mass of the exoplanet is 1/100th that of the sun, then the mass of the exoplanet would be 1.989 × 10²⁸kg. If the mass of the exoplanet is 1/1000th that of the sun, then the mass of the exoplanet would be 1.989 × 10²⁷ kg. If the mass of the exoplanet is 1/10000th that of the sun, then the mass of the exoplanet would be 1.989 × 10²⁶ kg. And so on.

Therefore, the mass of the exoplanet depends on its relative mass to the sun. To calculate the exact mass of the exoplanet, you would need to know the exact mass ratio between the exoplanet and the sun.

For example, if the exoplanet is the same size as Earth, it would have a volume of 1.08321 × 10¹² km³ (2). If we divide the mass of the sun (1.989 × 10^30 kg) by this volume, then the mass of the exoplanet would be approximately 1.841 × 10¹⁸ kg. This is approximately 1,841,000,000,000,000,000,000 kg or 1.841 × 10¹⁸ kg.

Therefore, the mass of an exoplanet can be estimated using the mass of the sun and the size of the exoplanet. However, due to the various compositions of different exoplanets, the exact mass of an exoplanet is impossible to calculate without additional information.

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Please help!! (25 points max.)

Please help!! (25 points max.)

Answers

Answer:

a

Step-by-step explanation:

2. Divide R3 520 in the ratio 11:12:17.​

Answers

Answer:

Rs 3520 is divided in the ratio 11:12:17 as rs 968, rs 1056, and rs 1469

Step-by-step explanation:

According to the question, we have to divide rs 3520 in the ratio 11:12:17

let the common ratio be x

so, total share= (11+12+17)x = 40 x

for the first person, share would be (11x/40x)*(Rs 3520)

=Rs 968

for the second person, share would be (12x/40x)*(Rs 3520)

=Rs 1056

for the third person, share would be (17x/40x)*(Rs 3520)

=Rs 1496

The shares are Rs 968, Rs 1056, and Rs 1469

hope this helps :)

Jai bought a helmet and a pair of skates.


The helmet cost £60.


He sold both items for £370.


Jai made a 115% profit on the cost of the helmet and a 25% profit on the total cost.


What was the percentage profit on the skates?


Give your answer to 1 decimal place.

Answers

Jai earned a percentage profit of 85.6% on the skates.

Given: Helmet cost = £60

Total cost = £60 + cost of skates = S Cost at which he sold both = £370Gain on helmet = 115%Gain on total cost = 25%Profit made on the skates = ?

First of all, we need to calculate the cost of skates.

Say the cost of the skates is S.

Cost at which he sold both items = Cost of the helmet + Cost of the skates + Profit earned

Let us consider that Jai earns a profit of P on the skates.

Therefore, Total cost + Profit = 370S + 60 + P = 370S + P = 310P = 310 - S ......(1)

From the given data, it is known that Jai earned a profit of 115% on the helmet cost which is £60.

Hence, profit earned on the helmet = 115% of £60= (115/100)*£60 = £69

Now, we know that Jai earned a 25% profit on the total cost.

Therefore, Profit earned on total cost = 25% of the total cost = 25% of (60+S) = (25/100) * (60+S) = 15 + 0.25S

Now,  Total profit earned = Profit on helmet + Profit on total cost + Profit on skates= £69 + £15 + 0.25S + P

From (1), we know that P = 310 - S Substituting P in the equation of Total profit earned

, we get, Total profit earned = £69 + £15 + 0.25S + (310 - S)£54 + 0.75S

Let us now calculate the percentage profit earned on the skates.

Now, Percentage profit earned on the skates = (Profit earned on skates / Cost of the skates) * 100

From the equation of Total profit earned, Profit earned on skates = Total profit earned - (Profit earned on helmet + Profit earned on total cost)Profit earned on skates = £54 + 0.75S - (£69 + £15)Profit earned on skates = 0.75S - £30

Now, Profit earned on skates is equal to P as mentioned in (1)P = 310 - S0.75S - £30

= 310 - S0.75S + S

= 310 + £300.25S

= 340S = £1360

Percentage profit earned on the skates = (Profit earned on skates / Cost of the skates) * 100= [£1360 - (S+£60)] / S * 100

= (£1360 - £196) / £1360 * 100

= £1164 / £1360 * 100

= 85.59%

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Find the constants m and b in the linear function f(x)=mx+b so that f(7)=9 and the straight line represented by f has slope −3.
m=
b=

Answers

To find the constants m and b in the linear function f(x) = mx + b, we can use the given conditions f(7) = 9 and a slope of -3.

The value of f(7) represents the y-coordinate of the point on the line when x = 7. So, substituting x = 7 into the equation, we get 9 = 7m + b.

The slope of a linear function is given by the coefficient of x, which in this case is -3. So, we have m = -3.

Now, we can substitute the value of m into the equation obtained from f(7). We get 9 = 7(-3) + b, which simplifies to 9 = -21 + b.

Solving for b, we find b = 30.

Therefore, the constants for the linear function f(x) = mx + b that satisfy the given conditions are m = -3 and b = 30.

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Which of the following is true with respect to use of the linear regression model to accommodate non-linear relationships? Select all correct answers.
-The linear regression model may be extended to accommodate some forms of non-linear relationships between the response and predictor(s).
-Some forms of non-linear relationships may be accommodated in a linear model if we include transformed versions of the predictor(s).
-Polynomial regression is one method for incorporating non-linear associations in a linear model.

Answers

The linear regression model can be extended to accommodate certain forms of non-linear relationships between the response and predictor(s).  Polynomial regression is one specific method for incorporating non-linear associations within the linear regression framework.

It involves understanding the flexibility of the linear regression model and the techniques available to address non-linear relationships. While the linear regression model assumes a linear relationship between the response variable and predictors, it can still be useful in accommodating certain types of non-linear relationships.

By applying appropriate transformations to the predictor variables, such as taking their squares, logarithms, or other non-linear functions, we can introduce non-linear associations into the linear regression model. This allows the model to capture curvature or other non-linear patterns in the data.

Polynomial regression is a specific approach to incorporating non-linear relationships within the linear regression framework. It involves adding polynomial terms of the predictor variables to the model, such as squared or cubed terms. By including these polynomial terms, the model can account for non-linear relationships and capture more complex patterns.

It's important to note that while linear regression can be extended to accommodate some non-linear relationships, there may be cases where more advanced non-linear regression techniques or alternative models are necessary to adequately capture complex non-linear associations. Nonetheless, the inclusion of transformed predictor variables and the use of polynomial regression are valuable approaches to address non-linear relationships within the linear regression framework.

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Which of the following could be an example of a function with a domain
(-∞0,00) and a range (-∞,4)? Check all that apply.
A. V = -(0.25)* - 4
-
□ B. V = − (0.25)*+4
c. V = (3)* +4
□ D. V = − (3)* — 4
-

Which of the following could be an example of a function with a domain(-0,00) and a range (-,4)? Check

Answers

The correct options that could be an example of a function with a domain (-∞0,00) and a range (-∞,4) are given below.Option A. V = -(0.25)x - 4 Option B. V = − (0.25)x+4

A function can be defined as a special relation where each input has exactly one output. The set of values that a function takes as input is known as the domain of the function. The set of all output values that are obtained by evaluating a function is known as the range of the function.

From the given options, only option A and option B are the functions that satisfy the condition.Both of the options are linear equations and graph of linear equation is always a straight line. By solving both of the given options, we will get the range as (-∞, 4) and domain as (-∞, 0).Hence, the correct options that could be an example of a function with a domain (-∞0,00) and a range (-∞,4) are option A and option B.

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Two of the masses given are unknown (blue and red). Goal is to determine the value of one of them (blue). Show every step to obtain results.

=>Mass of known object (orange)= 150g
=>Period of unknown object (blue) 14.93
14.93/10 = 1.493s

***Find K (constant) and the Mass of unknown object(blue)***

SHOW ALL STEPS

Hints:
-Can use the known mass to find the spring constant first (don't change during experiment)

-Instead of measuring one period, measure 10 oscillations to reduce error.

Answers

The mass of the unknown object (blue) is approximately 0.857 kg, and the constant K is approximately 0.0682.

To determine the value of the unknown mass (blue) and the constant K, we can use the formula for the period of oscillation of a mass-spring system:

T = 2π√(m/K)

where T is the period, m is the mass, and K is the spring constant.

Given information:

Mass of known object (orange) = 150g

Period of unknown object (blue) = 14.93s

Step 1: Convert the mass of the known object to kilograms:

Mass of known object (orange) = 150g = 0.15kg

Step 2: Rearrange the formula to solve for K:

T = 2π√(m/K)  =>  K = (4π²m) / T²

Step 3: Substitute the known values into the formula to find K:

K = (4π² * 0.15) / (14.93)² ≈ 0.0682

Step 4: Substitute the known values and the calculated value of K into the formula to find the mass of the unknown object (blue):

T = 2π√(m/K)  =>  m = (T²K) / (4π²)

m = (14.93)² * 0.0682 / (4π²) ≈ 0.857 kg

Therefore, the mass of the unknown object (blue) is approximately 0.857 kg, and the constant K is approximately 0.0682.

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By writing the individual factors on the left in exponential form, performing the needed operations, and finally changing back to rectangular coordinates, show that (a) i(1 - √3i)(√3 + i) = 2(1 + √3i); (b) 5i/(2 + i) = 1 + 2i;

Answers

To show the given equations, we can convert the complex numbers to their exponential form, perform the necessary operations, and then convert the result back to rectangular coordinates. By following this approach, we can demonstrate that (a) i(1 - √3i)(√3 + i) = 2(1 + √3i) and (b) 5i/(2 + i) = 1 + 2i.

(a) To solve i(1 - √3i)(√3 + i) = 2(1 + √3i):

1 - √3i can be written in exponential form as √4e^(-π/3i) = 2e^(-π/6i).

√3 + i can be written as 2e^(π/6i).

So, i(1 - √3i)(√3 + i) becomes i * 2e^(-π/6i) * 2e^(π/6i).

By multiplying the exponential factors, we get 2 * i * i = 2 * (-1) = -2.

Converting -2 back to rectangular coordinates, we have -2 = 2(-1 + 0i), which simplifies to -2 = -2.

(b) To solve 5i/(2 + i) = 1 + 2i:

We can multiply the numerator and denominator by the conjugate of the denominator, which is 2 - i.

The expression becomes (5i * (2 - i)) / ((2 + i) * (2 - i)).

Simplifying the numerator, we have 10i - 5i^2 = 5i + 5 = 5(1 + i).

In the denominator, (2 + i) * (2 - i) = 4 - i^2 = 4 + 1 = 5.

So, the expression becomes (5(1 + i)) / 5.

Canceling out the 5, we are left with 1 + i, which is equivalent to the right-hand side of the equation.

By following the steps outlined above, we have shown that (a) i(1 - √3i)(√3 + i) = 2(1 + √3i) and (b) 5i/(2 + i) = 1 + 2i.

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Let f : A -> B and g: C-> D be continuous functions. let us define a map f x g : A x C -> B x D by the equation f x g(a,c) = (f(a),g(c)). show that f x g is continous.

Answers

For any ε > 0, there exists a δ > 0 such that for any (a, c) in A x C, if ||(a, c) - (a_0, c_0)|| < δ, then ||(f(a), g(c)) - (f(a_0), g(c_0))|| < ε. This shows that the map f x g is continuous.

To show that the map f x g : A x C -> B x D is continuous, we need to demonstrate that it preserves the continuity of the individual functions f and g.

Let (a_0, c_0) be an arbitrary point in A x C, and let ε > 0 be given. Since f is continuous, there exists δ_1 > 0 such that for any point a in A, if ||a - a_0|| < δ_1, then ||f(a) - f(a_0)|| < ε/2.

Similarly, since g is continuous, there exists δ_2 > 0 such that for any point c in C, if ||c - c_0|| < δ_2, then ||g(c) - g(c_0)|| < ε/2.

Now, let δ = min(δ_1, δ_2). Consider any point (a, c) in A x C such that ||(a, c) - (a_0, c_0)|| < δ. This implies that both ||a - a_0|| < δ and ||c - c_0|| < δ, which in turn implies that ||f(a) - f(a_0)|| < ε/2 and ||g(c) - g(c_0)|| < ε/2.

By the triangle inequality, we have: ||(f(a), g(c)) - (f(a_0), g(c_0))|| = ||(f(a) - f(a_0), g(c) - g(c_0))|| <= ||f(a) - f(a_0)|| + ||g(c) - g(c_0)|| < ε/2 + ε/2 = ε.

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Find the value of x. A. 13 B. 9 C. 12 D. 10

Find the value of x. A. 13 B. 9 C. 12 D. 10

Answers

Answer:

D. 10

Step-by-step explanation:

9+4=13

x+3=13

x=10

The value of x is 10 which is correct option (D).

What is the Angles of Intersecting Secants Theorem?

Angles of Intersecting Secants Theorem states that, If two lines intersect outside a circle, then the measure of an angle formed by the two lines is one half the positive difference of the measures of the intercepted arcs.

Given that,

Length of CW = 9 units,

Length of WV = 4 units,

Length of WU = 3 units,

Length of TW = x units,

⇒ Length of CW + Length of WV = Length of CV

⇒ 9 + 4

⇒  13

⇒ Length of TW + Length of WU = Length of CV

⇒ x + 3 = 13

⇒ x = 10 - 3

x = 10

Hence, the value of x is 10 which is correct option (D).

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abanklends money for a year at an interest rate of 7%, and the inflation rate for that year turns out to be 5%. what is the bank's real rate of return for that year? 2.0% 3.5% 12.0% 6.0%

Answers

The bank's real rate of return for that year is 2.0%.

To calculate the real rate of return, we subtract the inflation rate from the nominal interest rate. In this case, the nominal interest rate is 7% and the inflation rate is 5%.

Real rate of return = Nominal interest rate - Inflation rate

Real rate of return = 7% - 5%

Real rate of return = 2.0%

Therefore, the bank's real rate of return for that year is 2.0%.

The real rate of return represents the actual increase in purchasing power or wealth after adjusting for inflation. It measures the return on an investment after accounting for the effects of inflation.

In this scenario, the bank lends money at an interest rate of 7%. However, the inflation rate for that year is 5%. The inflation rate erodes the purchasing power of money over time. Therefore, to determine the bank's real rate of return, we subtract the inflation rate from the nominal interest rate.

By subtracting 5% (inflation rate) from 7% (nominal interest rate), we get a real rate of return of 2.0%. This indicates that the investment made with the bank has a real return of 2.0% after accounting for the effects of inflation.

It's important to consider the real rate of return when evaluating the profitability or value of an investment. The real rate of return reflects the true growth or decline in purchasing power and provides a more accurate assessment of the investment's performance.

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Natalie needs to compare the number of employees by job title for the last five years. Which of the following charts should Natalie use?
Answers: A. Pie chart
B.Clustered column chart
C.Histogram
D.Scatter chart

Answers

Natalie should use Clustered Column Chart.

What is a Clustered Column Chart?
A clustered column chart is a vertical representation that shows data in groups (columns) that are connected to one another. Each column's data is separated into categories according to an attribute like year, age, sex, or race.For the purpose of comparing various variables, many bars are clustered in the same class in a clustered-column (bar) chart which is a specific kind of column (bar) chart. Hence, (B.) Clustered Column Chart is the correct option.

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simplify the monomial. the final answer should contain positive exponents only

(-8x^4y^3)(2x^5y^2)+7x^9y^5

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The simplified mοnοmial is \(-9x^9y^5\).

What is mοnοmial ?

In algebra, a mοnοmial is an expressiοn that has a single term, with variables and a cοefficient. Fοr example, 2xy is a mοnοmial since it is a single term, has twο variables, and οne cοefficient. Mοnοmials are the building blοcks οf pοlynοmials and are called 'terms' when they are a part οf larger pοlynοmials. In οther wοrds, each term in a pοlynοmial is a mοnοmial.

Mοnοmial is defined as an expressiοn that has a single nοn-zerο term. It cοnsists οf different parts like the variable, the cοefficient, and its degree. The variables in a mοnοmial are the letters present in it. The cοefficients are the numbers that are multiplied by the variables οf the mοnοmial. The degree οf a mοnοmial is the sum οf the expοnents οf all the variables.

When we multiply mοnοmials with the same base, we add their expοnents. Using this prοperty, we can simplify the expressiοn as fοllοws:

\((-8x^4y^3)(2x^5y^2)+7x^9y^5\)

\(= (-8 * 2)(x^4 * x^5)(y^3 * y^2) + 7x^9y^5\)

\(= -16x^9y^5 + 7x^9y^5\)

\(= (7 - 16)x^9y^5\)

\(= -9x^9y^5\)

Therefοre, the simplified mοnοmial is \(-9x^9y^5\).

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can you answer this fast please please

can you answer this fast please please

Answers

Answer:

top option: The function is nonlinear and does not have a constant rate of change

Step-by-step explanation:

This is a parabolic function, meaning that it increases exponentially. Therefore, it is nonlinear and does not have a constant slope (rate of change).

What evidence is needed to prove two triangles are similar by the SSS similarity theorem?

Answers

If in two triangles, sides of one triangle are proportionate to (i.e., in the same ratio of) the sides of the other triangle, then their corresponding angles are equal and consequently the two triangles are similar, asserts the Side-Side-Side (SSS) criterion.

Consider the same figure as given above. It is observed that DP/PE = DQ/QF and also in the triangle DEF, the line PQ is parallel to the line EF.

So, ∠P = ∠E and ∠Q = ∠F.

Hence, we can write: DP/DE = DQ/DF= PQ/EF.

The above expression is written as

DP/DE = DQ/DF=BC/EF.

It means that PQ = BC.

Hence, the triangle ABC is congruent to the triangle DPQ.

(i.e) ∆ ABC ≅ ∆ DPQ.

Thus, by using the AAA criterion for similarity of the triangle, we can say that

∠A = ∠D, ∠B = ∠E and ∠C = ∠F.

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Simplify (1 +152 + 5)² + 12 ÷ 2

Answers

Answer:

24342.

Step-by-step explanation:

(1 +152 + 5)² + 12 ÷ 2

= 156^2 + 12 / 2

= 24336 + 6

= 24342.

Help please I don’t understand it thanks:)

Help please I dont understand it thanks:)

Answers

Step-by-step explanation:

well, you must have some additional graphs (coordinate grids with lines going across them (probably in two different colors or patterns - one for Mary, one for Kim), while the horizontal x-axis is most likely for time (and there should be segments called A, B and C), while the vertical y-axis is most likely for the distance the riders were going.

we don't see this information. but I can try to give you some general guidance.

now you need to check these lines that go across the grid.

the higher up a point of a line is, the more distance a rider was adding to her ride at that point of time, meaning the higher the speed of that particular rider at that very moment. and the lower the point, ..., well you get it, right ?

now based on these lines you can answer the questions yourself.

when you follow the line for Mary, for example, in what segment of the x-axis (time) is the line the highest (she was riding fastest) or the lowest (she was riding the slowest)? maybe it is only for a part (or even only a few points) of the line in that interval.

when a rider stopped, guess what distance the rider was traveling while stopping ? exactly, 0. so, when a driver stopped, you will see the corresponding line go just flat parallel to the the x-axis for the period of time of stopping.

and you find the rider that lives 0.7 miles from school by seeing that the line goes flat parallel to the x-axis at y = 0.7 miles, and stays flat probably until the end of the chart.

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