Answer:
The electric field at a point midway between the two charges, E = -1.8 * 10⁴ N/C
Explanation:
Let the midpoint of the two charges be considered as the origin, and charge A = 30.0 * 10⁻⁹ C be moving in the +x- axis and the charge B = 60.0 * 10⁻⁹ C be moving in the -x-axis.
Electric field, E = kQ/r² where k is a constant = 9.0 * 10⁹ N.m²/C², Q = quantity of charge, r = distance of separation
In the given question,r = 30.0 cm = 0.03 m; the midway point between A and B = 0.03/2 = 0.015 m
Electric field due to charge A
Ea = +(9.0 * 10⁹ N.m²/C² * 30.0 * 10⁻⁹ ) / ( 0.015 m)²
Ea = +1.8 * 10⁴ N/C
Electric field due to charge B
Eb = -(9.0 * 10⁹ N.m²/C² * 60.0 * 10⁻⁹ ) / ( 0.015 m)²
Eb = -3.6 * 10⁴ N/C
The resultant electric field E = Ea + Eb
E = (+1.8 * 10⁴ + -3.6 * 10⁴) N/C
E = -1.8 * 10⁴ N/C
Therefore, the electric field at a point midway between the two charges, E = -1.8 * 10⁴ N/C
2. The following diagram shows a metal ball and ring apparatus. The ring and ball are both made of brass. At room temperature, the ball is just the right size to pass through the ring. When the ball is heated, it is unable to pass through the ring. Which of the following is NOT true? A The volume of the ball increased. B The mass of the ball increased. C. The speed at which the particles move increased. D The spaces between the particles increased. Not True
The statement that is NOT true is "the spaces between the particles increased.
option D.
What is effect of temperature on volume?If we consider the solids and liquids, when the temperature increases the molecules gain energy and start moving in all directions. This expands the substance and the volume of the substance increases.
Similar, when the ball is heated, the volume of the ball increases due to thermal expansion.
As the temperature increases, the average kinetic energy of the particles within the ball also increases, causing them to move faster.
However, the spaces between the particles do not necessarily increase. In fact, the expansion of the ball occurs due to the particles themselves moving farther apart, but the intermolecular spacing within the ball remains relatively constant.
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Describe an experiment to illustrate the fact that sound does not travel through a vacuum but rather require a medium for its propagation.
In the experiment, place a ringing alarm clock inside a vacuum chamber, and observe that when the chamber is evacuated, the sound from the alarm clock cannot be heard, illustrating that sound does not travel through a vacuum.
To illustrate that sound requires a medium for its propagation and does not travel through a vacuum, you can perform the following experiment:
Take two identical bells or sound-producing devices and place them in separate chambers, one in a vacuum chamber and the other in a chamber filled with air.
Ensure that both chambers are isolated from external noise sources.
Activate the sound-producing devices simultaneously, creating sound waves in both chambers.
Observe and listen for the sound produced in each chamber.
In the chamber filled with air, you will hear the sound clearly, as air molecules transmit the sound waves, allowing them to propagate and reach our ears.
However, in the vacuum chamber, you will not hear any sound because there is no medium (such as air) for the sound waves to travel through. Without molecules to transmit the vibrations, the sound cannot reach our ears.
This experiment demonstrates that sound requires a medium, such as air or other substances, to propagate and be perceived by our ears. In a vacuum, where there is an absence of molecules, sound cannot travel.
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the driving force on the train was 12000N how large must be the force applied in order to stop the train
Answer:
Anywhere above 12000N in order to decelerate the train since F=mass*acceleration
6. A 286 kg gold nugget is attached to the ceiling by a spring with a constant of 9500 N/m and
released from a height of 1.70 m above the floor. If the spring stretches 59.0 cm, what is the elastic
potential energy associated with the spring-nugget system?
4764 joule is potential energy associated with the spring-nugget system
Potential energy ,P =mgh
mass= 286 kg
g=9.8 m/s^2
h= 1.70 m
P =mgh
P=×286 kg×9.8×1.70
P=4764 joule
Potential energy is a form of stored energy that is dependent on the relationship between different system components. When a spring is squeezed or extended, its potential energy increases. If a steel ball is lifted above the ground as opposed to falling to the ground, it has higher potential energy. It is capable of performing more work when raised. Potential energy is a characteristic of systems rather than of particular bodies or particles; for instance, the system made up of Earth and the elevated ball has greater potential energy as they get further apart.
Potential energy develops in systems having components whose configurations, or relative positions, determine the amount of the forces they apply to one another.
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Identify the energy levels from which the 410.2 nm emission line of the Balmer series of the
hydrogen atom originates, i.e., state the values of ninitial and nfinal. What is the frequency of the
radiation involved in the transition between these levels?
The energy level from which is emitted is n = 6
The frequency is\(7.3 * 10^14\) Hz
What is the energy level?The Rydberg equation is a mathematical formula that relates the wavelengths of light emitted by an atom to the energy levels of its electrons.
Using the Rydberg equation;
1/λ= RH (1/\(n_{2}^2\) - 1/\(n_{1} ^2\))
1/\(410.2 * 10^-9\) = \(1.097 * 10^7\)(1/\(2^2\) - 1/ /\(n_{1} ^2\))
1/\(4.102 * 10^-7\) = \(1.097 * 10^7\)(1/4 - 1/\(n_{1} ^2\))
1/\(4.102 * 10^-7\) * 1/ \(1.097 * 10^7\) = (1/4 - 1/\(n_{1} ^2\))
0.22 = 0.25 - 1/\(n_{1} ^2\)
0.22 - 0.25 = - 1/\(n_{1} ^2\)
-0.03 = - 1//\(n_{1} ^2\)
\(n_{1}\) = 6
Using;
f = c/λ
\(3 * 10^8/4.102 * 10^-7 \\f = 7.3 * 10^14 Hz\)
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can anyone write for me all the equation of linear motion
All the equations of motion are as follows, Displacement (s) equation, Final velocity (v) equation, Average velocity (v_avg) equation, Displacement (s) equation with average velocity, and Displacement (s) equation.
Equations of MotionIn terms of its motion as a function of time, equations of motion define how a physical system behaves. In more detail, the equations of motion define how a physical system behaves as a collection of mathematical functions expressed in terms of dynamic variables.
s = ut + (1/2)at^2v = u + atv_avg = (u + v) / 2s = v_avg * ts = (u + v) / 2 * tv^2 = u^2 + 2asIn conclusion, equations of motion define how a physical system behaves in terms of how its motion changes over time.
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The position of a particle is r⃗ (t)=(3.0t2iˆ+5.0jˆ−6.0tkˆ)m. (a) Determine its velocity and acceleration as functions of time. (b) What are its velocity and acceleration at time t = 0?
Explanation:
It is given that,
The position of a particle is given by :
\(r(t)=(3t^2i+5j-6tk)\ m\)
(a) Velocity of a particle is given by :
\(v=\dfrac{dr(t)}{dt}\)
Putting values,
\(v=\dfrac{d}{dt}(3t^2+5-6t)\\\\v=(6ti-6k)\ m/s\)
The acceleration of the particle is given by :
\(a=\dfrac{dv}{dt}\\\\a=\dfrac{d}{dt}(6t-6)\\\\a=6i\ m/s^2\)
(b) At t = 0,
Velocity, v = 6k m/s
Acceleration, a = 6i m/s²
What is the change in potential energy of a wood mass 2kg thrown up with a velocity of 12m/s and comes down ?
When the wood comes down the change in potential energy of mass 2 kg and velocity 12 m/s is 144 J.
When the object is thrown vertically upwards, the height increases. The potential energy also increases with respect to the height. The potential energy is maximum, and the kinetic energy is zero when the stone moves vertically upwards.
When the object comes down, the potential energy decreases and results in increasing in kinetic energy. When the stone comes down, the potential energy is converted to kinetic energy, and the change in potential energy results in kinetic energy.
From the given,
mass of the wood (m) = 2kg
the velocity of the wood (v) = 12 m/s
kinetic energy (K.E) = mv² / 2
= (2×12×12) / 2
= 144 J
Thus, the change in kinetic energy is 144 J.
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I WILL MARK YOU AS BRAINLIEST!!! An object is launched straight up into the air with an initial velocity of 40 meters per second, from a height 30 m above the ground. Assuming that gravity pulls it down, changing its position by about 4.9 /2, after how many seconds will the object hit the ground? Enter your answer as a number rounded to the nearest tenth, such as: 42.5
Answer:
8.9 seconds
Explanation:
The height of the object at time t is:
y = h + vt − 4.9t²
where h is the initial height, and v is the initial velocity.
Given h = 30 and v = 40:
y = 30 + 40t − 4.9t²
When y = 0:
0 = 30 + 40t − 4.9t²
4.9t² − 40t − 30 = 0
Solving with quadratic formula:
t = [ -(-40) ± √((-40)² − 4(4.9)(-30)) ] / 2(4.9)
t = [ 40 ± √(1600 + 588) ] / 9.8
t = 8.9
It takes 8.9 seconds for the object to land.
Can you please match
Answer:
match what lol ?
Answer: Match what?
I love your profile pic.
Explanation:
A 50 N object is on Earth. What is its mass?
Answer: 5.10 KG
Explanation: W = 50 N
BY FORMULA
W = MG
M = W/G
M = 50 /9.8
M= 5.10 KG
Levi is driving at a speed or 10m/a and sees chimdi on the road 99m away. How long will it take his car to accelerate uniformly to a stop leaving 3 meters between the girl and his bumper?
Levi will take 19.23 seconds to accelerate uniformly to a stop, leaving 3 meters between Chimdi and his bumper.
To determine how long it will take for Levi's car to accelerate uniformly to a stop, we need to calculate the time it takes for the car to cover the distance between Chimdi and his bumper.
The initial distance between Levi's car and Chimdi is 99 meters, and he wants to leave 3 meters between them when the car comes to a stop. Therefore, the total distance the car needs to cover is 99 meters - 3 meters = 96 meters.
We also know that the car is traveling at a speed of 10 m/s. However, we need to convert this speed to meters per second squared (m/s²) to calculate the time for acceleration.
Let's assume the car decelerates uniformly. We can use the equation:
v^2 = u^2 + 2as,
where v is the final velocity (0 m/s since the car comes to a stop), u is the initial velocity (10 m/s), a is the acceleration, and s is the distance.
Rearranging the equation, we have:
a = (v^2 - u^2) / (2s)
a = (0^2 - 10^2) / (2 * 96)
a = -100 / 192
a ≈ -0.52 m/s²
The negative sign indicates deceleration.
Now, we can use the equation:
v = u + at,
where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.
Substituting the known values, we have:
0 = 10 + (-0.52) * t
Simplifying, we find:
0 = 10 - 0.52t
0.52t = 10
t ≈ 19.23 seconds
Therefore, it will take approximately 19.23 seconds for Levi's car to accelerate uniformly to a stop, leaving 3 meters between Chimdi and his bumper.
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You are moving a wagon with a friend's help you push on the left side of the wagon with 25 of force while your friend pulls from the right side of the wagon with a force of 15N,
What is the net force?
Answer:
10N to the left side towards you
Explanation:
The net force is the resultant force that acts on a body.
Force is a push or pull on a body.
Push to left side = 25N
Pull to the right = 15N
Net force = Push to left side - Pull to the right = 25N - 15N
Net force = 10N to the left side towards you
The net force is therefore 10N to the left side towards you
A body is thrown up into the air takes a time of 4s to reach the height. What is the velocity with which the body was thrown up.(g=10ms2)
Answer:
40m/s
Explanation:
V= u + at
v= 0
a= -10
t= 4
0= u -40
u= 40m/s
just trial!!!!!!!
PLEASE HELP a current of 0.5 A flows with a resistance of 50 ohms what is the e.m.f applied NEED HELP ASAP AND BRAINLIEST
Answer:
25 volts
Explanation:
voltage = current × resistance
\(v = i \times r \\ v = 0.5 \times 50 \\ v = 25v\)
Dillon wonders if he can block the radio waves released by the remote control used to operate his radio-controlled car. He covers the remote control in different materials and tries to use it to operate his car. He records his observations in the table below. Why does the remote control not work when covered with aluminum foil? A) because the aluminum foil blocks the batteries B) because the aluminum foil blocks the microwaves C) because the aluminum foil blocks the radio waves D) because the aluminum foil blocks the sound waves
The remote control operated on Dillon's radio controlled car does not work when covered in aluminum foil because the aluminum foil blocks the radio waves. (option C)
Radio-controlled cars operate using radio waves, which are a type of electromagnetic radiation. When the remote control is covered with aluminum foil, the foil acts as a barrier that blocks the radio waves from reaching the car. This is why the remote control does not work when covered with aluminum foil.
It is important to note that radio waves are not the same as microwaves or sound waves. Microwaves are a type of electromagnetic radiation that is used for cooking food in microwave ovens, while sound waves are mechanical waves that travel through the air and are used for hearing. Therefore, options B and D are incorrect. Additionally, the aluminum foil does not block the batteries in the remote control, so option A is also incorrect.
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Rhea is driving north in a straight line. After driving for 2.4 kilometers, she turns west, and drives for 3.1 km. At the end of her drive, what is the magnitude of her displacement vector? To find the magnitude of a resultant vector, use the Pythagorean theorem: a² + b² = c² A) 3.9 km B) 5.5 km (this one is incorrect) C) 2.8 km D) 2.3 km
Option A) 3.9 km is the correct answer. the magnitude of Rhea's displacement vector is approximately 3.92 km.
In order to find out the magnitude of Rhea's displacement vector, we have to add up all of the displacement vectors.
Then we can use the Pythagorean theorem to calculate the magnitude of the resultant vector.
Since Rhea is first driving north for 2.4 km and then west for 3.1 km, we can represent her displacement vectors as follows: Δx = 0 km and Δy = 2.4 km for the first vector, and Δx = -3.1 km and Δy = 0 km for the second vector.
We can then add these vectors together by adding their components: Δx = 0 km + (-3.1 km) = -3.1 km and Δy = 2.4 km + 0 km = 2.4 km.
This gives us a resultant vector of -3.1 km east and 2.4 km north.
Using the Pythagorean theorem, we can find the magnitude of this vector: \(\sqrt{(\(-3.1 km)^{2} + (2.4 km)^{2} ) } = \sqrt{(9.61 + 5.76) km^{2} } = \sqrt{15.37 km^{2} } \approx 3.92 km.\)
Therefore, the magnitude of Rhea's displacement vector is approximately 3.92 km.
Therefore, option A) 3.9 km is the correct answer.
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A particle charge of 2.7 µC is at the center of a Gaussian cube 55 cm on edge. What is the net electric flux through the surface?
Answer:
3.05×10⁵ Nm²C⁻¹
Explanation:
According to Gauss' law,
∅' = q/e₀............... Equation 1
Where ∅' = net flux through the surface, q = net charge, e₀ = electric permittivity of the space
From the question,
Given: q = 2.7 μC = 2.7×10⁻⁶ C,
Constant: e₀ = 8.85×10⁻¹² C²/N.m²
Substituting these values into equation 1
∅' = (2.7×10⁻⁶)/(8.85×10⁻¹²)
∅' = 3.05×10⁵ Nm²C⁻¹
Please help with these MCQs.
1. Filter absorbs __________________.
- only primary coloured lights
- only secondary coloured lights
- only tertiary coloured lights
- all colors of white light
2. The light that has passed through a filter, is always ______________.
- dim
- bright
- sharp
- blur
1. Filter absorbs all colors of white light.
2. The light that has passed through a filter, is always dim.
Which colors are being absorbed by the filter?The filter selectively transmits the red and blue portions of the incident white light spectrum, but absorbs most of the green wavelength.
Color filters absorb certain wavelengths of color and transmit the other wavelengths allowing them to be seen.
Therefore in conclusion, the right filter can reduce glare, increase contrast, and make lunar features pop.
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If the atmospheric pressure is 15 lb/in^2, what is the corresponding downward force on the top of a horizontal square area 5 inches on each side?
Answer:
The downward force on the top of the horizontal square area can be found using the formula:
force = pressure x area
Given that the atmospheric pressure is 15 lb/in^2 and the square area is 5 inches on each side, the area can be calculated as:
area = length x width
= 5 inches x 5 inches
= 25 square inches
Substituting the values in the formula, we get:
force = 15 lb/in^2 x 25 square inches
= 375 lb
Therefore, the corresponding downward force on the top of the horizontal square area is 375 pounds.
battery
connected to a light bulb.
Based on potential energy,
which direction should the
current flow?
A 2.40 kg ball is attached to an unknown spring and allowed to oscillate. The figure below shows a graph of the ball’s position �� as a function of time . What are the oscillation’s: a. period; b. frequency; c. angular frequency; d. amplitude; and e. What is the force constant of the spring?
(a) The period of the oscillation is 0.8 s.
(b) The frequency of the oscillation is 1.25 Hz.
(c) The angular frequency of the oscillation is 7.885 rad/s.
(d) The amplitude of the oscillation is 3 cm.
(e) The force constant of the spring is 148.1 N/m.
The given parameters:
Mass of the ball, m = 2.4 kgFrom the given graph, we can determine the missing parameters.
The amplitude of the wave is the maximum displacement, A = 3 cm
The period of the oscillation is the time taken to make one complete cycle.
T = 0.8 s
The frequency of the oscillation is calculated as follows;
\(f = \frac{1}{T} \\\\f = \frac{1 }{0.8} \\\\f = 1.25 \ Hz\)
The angular frequency of the oscillation is calculated as follows;
\(\omega = 2\pi f\\\\\omega = 2\pi \times 1.25\\\\\omega = 7.855 \ rad/s\)
The force constant of the spring is calculated as follows;
\(\omega = \sqrt{\frac{k}{m} } \\\\\omega ^2 = \frac{k}{m} \\\\ k = \omega ^2 m\\\\k = (7.855)^2 \times 2.4\\\\k = 148.1 \ N/m\)
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14. Which of the following denotes impedance?
A. H
B. R
C. Z
D. XL
the weight of an object is measured in air to be 7N the object is then immersed in water and its apparent weight is measured to be 4N determined the buoyant force and state whether or not the object float
The buoyant force can be determined by subtracting the apparent weight of the object in water from its weight in air. In this case, the buoyant force would be 7N - 4N = 3N.
Based on the information provided, since the buoyant force (3N) is less than the weight of the object (7N), the object will not float.
Floating occurs when the buoyant force is greater than or equal to the weight of the object.
In this scenario, the object will experience a net downward force, indicating that it will sink rather than float in water.
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What are supernovae?
A. stars that have reached the end of their lifetimes because their nuclear fuel is exhausted
B. stars that suddenly brighten by 100 to 10,000 times in a day
с. stars that have just been born
D. galaxles that have binary systems
Answer:
A
Explanation:
AAAaaaaaaaaaaaaaaaaaaaaaaaaa
Answer:
A. Stars that have reached the end of their lifetimes because their nuclear fuel
Explanation:
plato
In a two-slit experiment, the slit separation is 3.00 × 10-5 m. The interference pattern is created on a screen that is 2.00 m away from the slits. If the 7th bright fringe on the screen is a linear distance of 10.0 cm away from the central fringe, what is the wavelength of the light? In a two-slit experiment, the slit separation is 3.00 × 10-5 m. The interference pattern is created on a screen that is 2.00 m away from the slits. If the 7th bright fringe on the screen is a linear distance of 10.0 cm away from the central fringe, what is the wavelength of the light? 214 nm 204 nm 224 nm 100 nm 234 nm
Answer:
The value is \(\lambda = 214.3 \ nm \)
Explanation:
From the question we are told that
The slit separation is \(d = 3.00 * 10^{-5} m\)
The distance of the screen is \(D = 2.00\ m\)
The order of fringe is n = 7
The path difference is \(y = 10.0 \ cm = 0.1 \ m\)
Generally the path difference is mathematically represented as
\(y = \frac{n * \lambda * D}{ d}\)
=> \(0.1 = \frac{7 * \lambda * 2.00 }{ 3.00 * 10^{-5}}\)
=> \(\lambda = \frac{0.1 *3.00 * 10^{-5} }{7 * 2.00 }\)
=> \(\lambda = \frac{0.1 *3.00 * 10^{-5} }{7 * 2.00 }\)
=> \(\lambda = 2.143 *10^{-7} \ m \)
=> \(\lambda = 214.3 \ nm \)
A golfer is attempting to reach the elevated green by hitting his ball under a low-hanging branch in one tree A, but over the top of a second tree B. If the launch speed of the golf ball is v0 = 115 mi/hr, what launch angle will put the first impact point of the ball closest to the pin? How far from the pin (distance d) is this impact point?
A golfer is attempting to reach the elevated green by hitting his ball under a low-hanging branch in one tree A, but over the top of a second tree B. If the launch speed of the golf ball is vo = 115 mi/hr, what launch angle 0 will put the first impact point of the ball closest to the pin. The first impact point of the ball closest to the pin will be approximately 407.5 ft from the launch point.
The equation for the range of a projectile is R = (V0² / g) * sin(2θ)The golfer has to hit the ball under a low-hanging branch in tree A and over the top of tree B to reach the elevated green.
Let's denote the distance between the golfer and the green as d. The range (R) of the projectile will equal the distance to the pin (d) if the ball lands at the same level as it was launched. If the ball has to land at a higher elevation than the launch point, the launch angle must be greater than the optimal angle that maximizes range.
Assuming the golfer is hitting from a horizontal surface (i.e. the ball is launched from the same level as the pin), the launch angle that will give the first impact point of the ball closest to the pin is 60°.At the launch angle of 60°, the distance to the pin (d) will be the range of the projectile (R).The velocity of the golf ball at launch is vo = 115 mi/hr.
The horizontal distance to the pin, which is the range of the projectile, is given by the equation;
R = (V0² / g) * sin(2θ)
where g = acceleration due to gravity = 32.2 ft/s² (let's convert the velocity to ft/s first)
vo = 115 mi/hr = 115 x 5280 ft/hr = 607200 ft/hr ≈ 168666.7 ft/hr
The initial velocity of the projectile, V0 = 168666.7 ft/hr. The optimal angle of launch is given by the equation:θ = 45° (for maximum range)The angle of launch required to achieve the shortest distance to the pin is 60°Let's substitute the values of V0 and θ into the range equation.
To calculate the range of the projectile R = (V0² / g) * sin(2θ)R = (168666.7² / 32.2) * sin(2(60))R ≈ 407.5 ft
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Consider the low-speed flight of a Space Shuttle as it is nearing a landing. If the air pressure and temperature at the nose of the shuttle are 1.05 atm and 300 K, respectively, calculate the density and specific volume. (Round the final answer to two decimal places.) The density is kg/m3. The specific volume is m3/kg.
Answer:
d = 1.24 kg/m³
v = 0.81 m³/kg
Explanation:
To do this, we need to analyze the given data and know the expressions we need to use here to do calculations.
We have a pressure of 1.05 atm and 300 K of temperature. To determine the density, we need to use a similar expression of an ideal gas. In this case, instead of using moles, we will use density:
P = dRT
d = P/RT (1)
Where:
R: universal constant of gases
d: density.
From here we can determine the specific volume by using the following expression:
v = 1/d (2)
Now, as we are looking for density, we need to convert the units of pressure in atm to Pascal (or N/m) and the conversion is the following:
P = 1.05 atm * 1.013x10⁵ N/m atm = 106,365 N/m
Now, using R as 287 the density would be:
d = 106,365 / (287 * 300)
d = 1.24 kg/m³Finally the specific volume:
v = 1 / 1.41
v = 0.81 m³/kgHope this helps
Which is a benefit of using synthetic polymers, such as nylon?
Synthetic polymers are lightweight.
O Synthetic polymers are produced in small
quantities.
Synthetic polymers are biodegradable.
Synthetic polymers are inexpensive to recycle.
Answer: Synthetic polymers are lightweight.
Explanation:
A benefit of using synthetic polymers is the fact that synthetic polymers are lightweight.
A polymer is a molecule composed of many repeating subunits.
Synthetic polymers are artificial polymers created by humans.
Most of the synthetic polymers are not biodegradable (unlike natural fibers such as cotton).
Synthetic polymers are classified according to their use into plastics, elastomers and synthetic fibers.
The advantages of synthetic polymers include: hard to break, being lightweight, and they last for a long time.
In conclusion, a benefit of using synthetic polymers is the fact that synthetic polymers are lightweight.
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please help thank you
which of the following statements BEST describes the difference between an atom and an ion ?
Answer:
well the correct answer is
d. An atom contains equal numbers of protons and electrons whereas an ion contains unequal numbers of protons and electrons .Explanation:
A charged atom is known as an ion, well it can be negative as well as positive charge.
if atom has more protons than electrons then it get positively charged and known as cationif the atom has more electrons that the number of protons then the atom get negatively charged and known as anion