find the distance a ball traveled if it is 20N and it took 800J to move it

Answer:

c

Explanation:

The amount of mass used up in holding a nucleus together the mass defect represent.

Thus, The term "mass defect" refers to the discrepancy between the actual atomic mass and the expected mass obtained by multiplying the mass of the protons and neutrons in the nucleus by a constant factor.

The anticipated mass obtained by combining the masses of the nucleons is less than the actual atomic mass. The binding energy that is produced when a nucleus forms accounts for this extra mass.

The mass defect is a result of some of the mass being converted to energy during the formation of a nucleus. The real mass of an atomic nucleus is therefore less than the mass of the constituent particles.

Thus,  The amount of mass used up in holding a nucleus together the mass defect represent.

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The angle between the ladder and the ground is changing at rate of 2.4ft/s.

A right tringle is formed when ladder is against the wall,

x²+y² = 13²

dy/dt = -4ft/s

y = 5 feet

2[dx/dt] + 2[dy/dt] = 0

y = 10, x= √69 z = 13ft

2×√69[dx/dt] + 2×5×(-4) = 0

16.6[dx/dt] = 40

dx/dt = 40/16.6

dx/dt = 2.4 ft/s

The angle between the ladder and the ground is changing at rate of 2.4ft/s.

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Answer:

I'm sorry I

Explanation:

I don't know I'm sorry I will tell you another answer

Answer:

D. flammability

Explanation:

I took the test and got it right

Explanation:

Given that,

Height of Siberian Huskey = 60 cm

Distance of Siberian Huskey and a plane mirror = 3 m

The characteristic of a plane mirror are as follows :

(a) The height of the formed image = 3 m

(b) The formed image is virtual, upright and same size that of object.

Hi there!

Part 1:

If the blocks are moving at a constant velocity:

∑F = 0

Begin by summing the forces acting on each block. Let the upward direction be positive.

∑F₁ = Ta - M₁g - Tb

∑F₂ = Tb - M₂g

Sum the forces:

∑F = Ta - M₁g - Tb + Tb - M₂g

∑F = Ta - M₁g - M₂g = 0

Solve for Tension A:

Ta = M₁g + M₂g (Let g = 9.8 m/s²)

Ta = 4.2(9.8) + 2.6(9.8) = 66.64 N

Now, solve for tension B using the summation of ∑F₁:

0 = Tb - M₂g

Tb = (2.6* 9.8) = 25.48 N

Part 2:

We can use the same method, but incorporate the acceleration:

∑F = Ta - M₁g - M₂g

(M₁ + M₂)a = Ta - M₁g - M₂g

(M₁ + M₂)a + M₁g + M₂g = Ta

(4.2 + 2.6)(1.2) + 4.2(9.8) + 2.6(9.8) = 74.8 N

∑F₂ = Tb - M₂g

M₂a + M₂g = Tb  = 28.6 N

Part 3:

Since the top string experiences most of the tension, we can use its equation to calculate the maximum acceleration:

∑F = Ta - M₁g - M₂g

(M₁ + M₂)a = Ta - M₁g - M₂g

a = (90 - M₁g - M₂g)/(M₁ + M₂)

a = 3.435 m/s²

Answer:

Sound travels fastest through solids.

Explanation:

This is because molecules in a solid medium are much closer together than those in a liquid or gas, allowing sound waves to travel more quickly through it. In fact, sound waves travel over 17 times faster through steel than through air.

Sound waves move the fastest through the solid. The speed of the sound wave  in the liquid and gas is low,

A sound wave is produced when a medium begins to vibrate. When an entity vibrates, a pressure wave is formed, which causes sound.

Solids transmit sound the fastest. Because the molecules in a solid medium are much closer together than in a liquid or gas, sound waves can move through it much faster.

Hence, sound waves move the fastest through the solid.

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Hypervisors, guest machines, and host machines are important concepts in virtualization. A hypervisor is a software that allows multiple operating systems to run on a single hardware host machine.

Hypervisors are a type of virtualization software that allows multiple operating systems to run on a single hardware host machine. The host machine runs the hypervisor software, which creates virtual machines (VMs) that act as if they are independent machines running on their hardware.

The hypervisor acts as the main answer to maintain the operating systems and resource allocation.The guest machines, also known as virtual machines, are created by the hypervisor and are instances of a guest operating system that runs on the host machine.

Guest machines are isolated from each other, allowing different operating systems and applications to run without interfering with each other.

The host machine is the physical machine that runs the hypervisor software. It provides the necessary hardware resources, such as CPU, memory, and storage, to the guest machines.

The hypervisor manages the allocation of these resources to the guest machines based on their requirements.A diagram to illustrate this is as follows: [Insert diagram here]

Hypervisors, guest machines, and host machines are important concepts in virtualization. A hypervisor is a software that allows multiple operating systems to run on a single hardware host machine. The guest machines are virtual machines created by the hypervisor, which act as independent machines. The host machine is the physical machine that runs the hypervisor software and provides the necessary hardware resources to the guest machines. These concepts are important in understanding the virtualization technology and its benefits.

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The RMS current , Power and Maximum voltage have values 0 to 1 , V1/2 to 0 and infinity to zero.

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They try not to influence the subjects

Explanation:

Answer:

In mathematics, an ellipse is a plane curve surrounding two focal points, such that for all points on the curve, the sum of the two distances to the focal points is a constant.

I don’t know how ellipse change tho sorry

Answer:

distance=speed×time.

45×20=900m.

Answer:

3.5 hours

Explanation:

Answer:

x-rays, Infrared rays, microwaves.

\(\\ \sf\longmapsto P.E=mgh\)

\(\\ \sf\longmapsto P.E=102(120)(10)\)

\(\\ \sf\longmapsto P.E=122400J\)

Explanation:

The expected result of the experiment is that the liquid air will boil because the extreme difference in temperature will cause heat to be transferred from the ice to the liquid air ( B ).

The temperature of the liquid air = - 200 °C

The temperature of the block of ice = - 12 °C

Since they are in a thermally insulated flask, the heat will be transferred until both the objects' temperature becomes equal. So the temperature of liquid air rises and the temperature of ice decreases. The boiling point of liquid air is - 194.35 °C. So the liquid air boils.

Option A would have been correct if the final statement was decrease in temperature and not increase in temperature. Option C is incorrect because the ice becomes colder. Option D is incorrect because liquid air will boil.

Therefore, the expected result of the experiment is that the liquid air will boil because the extreme difference in temperature will cause heat to be transferred from the ice to the liquid air and the molecules of the liquid air will begin to leave the liquid ( B ).

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Answer:

B

Explanation:

mass is the amount of matter present in any object or body.

here in the option b, it says they each contain the same amount of matter,

which means they each has the same mass.

The kinetic energy of an ion released from rest and accelerated through a potential difference of 2.5 kV is 2500 eV.


Kinetic energy is the energy an object has due to its motion. When an ion is released from rest and accelerated through a potential difference, it gains kinetic energy. The amount of kinetic energy gained is equal to the potential difference multiplied by the charge of the ion.

Since the ion is released from rest, its initial kinetic energy is 0. The potential difference is 2.5 kV, or 2500 V. The charge of the ion is 1 e, or 1.6 x 10⁻¹⁹ C.

Therefore, the final kinetic energy of the ion is:
KE = qV
KE = (1.6 x 10⁻¹⁹ C)(2500 V)
KE = 4 x 10⁻¹⁶ J
KE = 2500 eV

So the correct answer is (a) 2500 eV.

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Answer:

Yes.

Globally, energy usage is by far the most significant source of greenhouse gas emissions from human activity. About two-thirds of worldwide greenhouse gas emissions are associated with the use of fossil fuels to provide energy for heating, electricity, transportation, and industry.

Hope this helped :)

The statement that must be true of an extended body experiencing a net force of zero is that the center of mass of the extended body is not accelerating.

When an extended body experiences a net force of zero, it means that the vector sum of all the forces acting on the body is zero. According to Newton's second law of motion, F = ma, where F is the net force, m is the mass, and a is the acceleration. Since the net force is zero, the acceleration of the body is also zero. In an extended body, different parts of the body may experience different forces, causing them to accelerate or decelerate. However, the center of mass of the body represents the point where the body's total mass is concentrated. If the net force is zero, the center of mass remains at rest or moves with a constant velocity, indicating that it is not accelerating.

Therefore, the correct statement is that the center of mass of the extended body is not accelerating.

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If two balls are projected with initial velocity v and 2v respectively, the ball that is projected with a velocity of 2v would reach the ground first.

The term projectile has to do with the kind of motion that uses a parabolic path. The parabolic path is a path that is curved. For instance, if you trough a ball from one point to the other, the ball does not follow a straight path, the path of the ball is curved.

The time that it takes for the ball to reach the ground from the point of projection is dependent on the initial velocity of the ball. Thus, if the ball has been projected with a higher initial velocity then the ball would reach the ground faster and vice versa.

Thus, given that the velocity 2v is twice the velocity v, the ball that is projected at this velocity would reach the ground first.

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Answer:

0.58

Explanation:

Using the frictional force formula expressed as;

\(F_f = \mu R\\\)

\(\mu\) is the coefficient of kinetic friction

R is the normal reaction

\(\mu = \frac{F_f}{R}\)

\(F_f = Wsin \theta\\R = W cos\theta\\\mu = \frac{Wsin \theta}{W cos \theta}\\\mu = \frac{sin\theta}{cos \theta} \\\mu = tan \theta\)

Given

\(\theta = 30^0\\\mu = tan 30^0\\\mu = 0.58\)

hence the coefficient of kinetic friction is 0.58

Answer:

The answer is 0 kg..

The full answer choices are:  

A)0 kg

B)500 kg⋅m2/s

C)1000 kg⋅m2/s

D)The change in angular momentum of the meterstick cannot be determined from this information.

Explanation:

The force applied from the 1.0kg object which is equal to 10N, gives a torque equal to τ=Fdsinθ=(10 N)(0.25m)sin90°=2.5Nm. This torque is exerted so that it would cause a counterclockwise rotation. The force of gravity exerted on the rod itself is equal to the weight of the rod, and causes a torque equal to τ=Fdsinθ=(5 N)(0.25m)sin90°=1.25Nm, and will cause a clockwise rotation. The 0.5kg object also exerts a torque on the rod equal to τ=Fdsinθ=(5 N)(0.25m)sin90°=1.25Nm, also in a clockwise direction. The net torque then on the rod is equal to zero. The rod will not rotate when released, and its angular momentum will not change.

Basically, when you do the math for angular momentum which is equal to the net torque exerted on the meterstick, you can see that there is no change. For the force, just approximate 9.8 to 10 to make it easier. Also It's Sin90 because it's perpendicular. Sin90 = 1

B) The change in the angular momentum of the meterstick is 480 kg m2/ s.

The center of mass of the system can be set up as

xcm = (0.25 m)(0.5 kg)( 0 m)(1.0 kg)(0.5 m)(0.5 kg)/(0.5 kg1.0 kg0.5 kg)

= 0.25 m

The moment of  inertia of the meterstick- object system about its center of mass can be calculated as

Icm = (1/12) mL2

where L is the length of the meterstick.

Substituting the given values,

we get Icm = (1/12)(0.5 kg)(1.0 m) 2 = 0.042 kg m2

The distance of the center of mass from the pivot point is

d = 0.25 m The total mass of the system is

m = 0.5 kg1.0 kg0.5 kg = 2.0 kg

The total moment of  inertia of the meterstick- object system about the pivot point is

I =  Icm md2 = 0.042 kg m2(2.0 kg)(0.25 m) 2 = 0.192 kg m2

The angular haste of the system after one second can be set up using the principle of conservation of energy1/2) I ω2 =  mgh

where h is the height of the center of mass of the system above the pivot point.

The original height of the center of mass of the system is

h = (0.25 m)(0.5 kg)( 0 m)(1.0 kg)(0.5 m)(0.5 kg)/(0.5 kg1.0 kg0.5 kg

= 0.25 m

Substituting the given values,

we get1/2)(0.192 kg m2) ω2 = (2.0 kg)(9.81 m/ s2)(0.25 m)

working for ω,

we get ω = 2.44 rad/ s

The final angular instigation of the meterstick- object system is

Lf =  I ω = (0.192 kg m2)(2.44 rad/ s) =468 kg m2/ s

The change in angular instigation of the meterstick- object system is

ΔL =  Lf- Li = 468 kg m2/ s- 0 kg m2/ s = 468 kg m2/ s

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The complete question is as follows:

a meterstick with a uniformly distributed mass of 0.5 kg is supported by a pivot placed at the 0.25 m mark from the left, as shown. at the left end, a small object of mass 1.0 kg is placed at the zero mark, and a second small object of mass 0.5 kg is placed at the 0.5 m mark. the meterstick is supported so that it remains horizontal, and then it is released from rest. one second after it is released, what is the change in the angular momentum of the meterstick? responses 0

A)0

B)480kg⋅m2/s

C)1000 kg⋅m2/s

D)The change in angular momentum of the meterstick cannot be determined from this information.

The resultant answer are

1) Generally, To solve this problem, you first need to calculate the ground speed of the plane, which is the speed at which the plane is moving relative to the ground. To do this, you subtract the speed of the wind from the speed of the plane.

Ground: ground speed = plane speed - wind speed ground speed

= 4.5 x 102 km/h - 3.2 x 102 km/h

= 130 km/h

Then you can use the distance and ground speed to find the time it takes the plane to fly between the two stations using the formula:

time = distance/speed time ]

= 300 km / (1.3 x 102 km/h)

= approximately 2.3076h

The velocity of the person as viewed by an observer on a stationary submarine is the vector sum of the velocity of the person and the velocity of the aircraft carrier.

This is given by the Pythagorean theorem, where the velocity is the square root of the sum of the squares of the x- and y-velocities.

In this case, the x-velocity of the person is 3.0 m/s and the x-velocity of the aircraft carrier is 20.0 m/s.

The y-velocity of both the person and the aircraft carrier is 0 m/s. Therefore, the velocity of the person as viewed by an observer on a stationary submarine is the

√ (3.0 m/s + 20.0 m/s)^2 + 0^2 = 23m/s.

To find the time it takes for the dolphin to catch the fish, we need to use the concept of relative velocity. The relative velocity of the fish with respect to the dolphin is the velocity of the fish minus the velocity of the dolphin. In this case, the relative velocity of the fish is

15.0 km/h - 37.0 km/h = -22.0 km/h.

To find the time it takes for the dolphin to catch the fish, we divide the distance between the fish and the dolphin by the relative velocity. In this case,

t = 50.0 m / (-22.0 km/h)

= 2.27 s.

To find the velocity of the dog relative to the road, we need to use the concept of relative velocity. The velocity of the dog relative to the road is the vector sum of the velocity of the dog in the x- and y-directions. In this case, the x-velocity of the dog

is 2.0 m/s * cos(45) = 1.41 m/s and the y-velocity of the dog is

2.0 m/s * sin(45) = 1.41 m/s.

The velocity of the road is 30.0 m/s in the north direction.

Therefore, the velocity of the dog relative to the road is

1.41 m/s east + 1.41 m/s north

= sqrt(1.41^2+1.41^2)

= 2 m/s at angle of 45o east of north.

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Assuming Usain Bolt begins at rest (with zero initial velocity) and his motion is uniformly accelerated, his position at time t is given by

where a denotes the average acceleration and t denotes the time. Because the distance covered in our problem is S=100 m and the time taken is t=9.58 s, the average acceleration can be calculated by rearranging the previous formula:

1175.50 kg m/s

Usain Bolt's weight is 93.89 kg.

The average velocity in a 100-meter sprint is 12.52 metres per second.

The momentum can be calculated by taking the product of mass and velocity and multiplying it by

The following factors provide momentum:kg m/s

where denotes mass and denotes velocity

Thus, Usain Bolt's momentum can be calculated by plugging in the given values for

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From Newton's second law of motion, the average force on the ball by the racket is 98 Newtons. The correct answer is option C

Given that a 0.07 kg tennis ball, initially at rest, leaves a racket with a speed of 56 m/s. And the time for contact with the racket is 0.04 s, that is,

mass m = 0.07 kg

velocity v = 56 m/s

time t = 0.04 s

force f = ?

To calculate the average force on the ball by the racket, let us apply Newton's second law of motion.

Impulse = change in momentum

ft = mv

Substitute all the parameters into the equation above

0.04f = 0.07 x 56

make f the subject of the formula

f = 3.92 / 0.04

f = 98 N

Therefore, the average force on the ball by the racket is 98 Newtons. The correct answer is option C

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The average force on the ball by the racket is 98 N. The correct option is the third option - 98 N

From the question, we are to determine the average force on the ball by the racket.

From the formula,

\(F = \frac{mv}{t}\)

Where F is the force

m is the mass

v is the velocity

and t is the time

From the given information

m = 0.07 kg

v = 56 m/s

t = 0.04 s

Putting the parameters into the formula,

we get

\(F = \frac{0.07 \times 56}{0.04}\)

\(F = \frac{3.92}{0.04}\)

F = 98 N

Hence, the average force on the ball by the racket is 98 N. The correct option is the third option - 98 N

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At a depth of 500 meters in the mine, the estimated vertical stress is 13.5 MPa, and the estimated horizontal stress is 11.57 MPa. Specific details to consider are Chalk Strength, Chalk Permeability, Chalk Heterogeneity.

Before proceeding with the excavation of the cavern beneath the sea, the main geological information that would be important to have includes the properties and characteristics of the chalk formation. Some specific details to consider are:

a) Chalk Strength: It is essential to determine the strength and stability of the chalk formation to ensure that it can support the excavation without collapsing or experiencing excessive deformation. This would involve assessing parameters such as the cohesion, friction angle, and compressive strength of the chalk.

b) Chalk Permeability: Understanding the permeability of the chalk is crucial, especially since the cavern will be beneath the sea. The permeability will impact the water flow within the chalk and may affect stability, seepage, and potential groundwater inflow into the excavation.

c) Chalk Heterogeneity: Chalk formations can exhibit variations in their composition, including the presence of layers or discontinuities such as faults or joints. Understanding the geological structure and heterogeneity of the chalk will help in assessing the potential for rock mass instability, water ingress, or the presence of other geological hazards.

To estimate the vertical and horizontal in-situ stresses at a depth of 500 meters in the mine, we can use the principles of rock mechanics and consider the given parameters.

Vertical Stress:

The vertical stress is the stress component acting vertically downward due to the weight of the overlying rock. It can be calculated using the average unit weight of the rock and the depth.

Vertical Stress = Unit Weight of Rock × Depth

Vertical Stress = 27 kN/m³ × 500 m

Vertical Stress = 13,500 kN/m² or 13.5 MPa

Horizontal Stress:

The horizontal stress can be estimated using the in-situ stress ratio, which is influenced by Poisson's ratio. The relationship between the horizontal and vertical stresses can be expressed as:

Horizontal Stress = Vertical Stress × (2 × Poisson's Ratio) / (1 - Poisson's Ratio)

Horizontal Stress = 13.5 MPa × (2 × 0.3) / (1 - 0.3)

Horizontal Stress = 13.5 MPa × 0.6 / 0.7

Horizontal Stress = 11.57 MPa

Therefore, at a depth of 500 meters in the mine, the estimated vertical stress is 13.5 MPa, and the estimated horizontal stress is 11.57 MPa.

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Answer:

Wegener was a German meteorologist, geophysicist and polar researcher. In 1915 he published 'The Origin of Continents and Oceans', which outlined his theory of Continental Drift. Wegener was a member of four expeditions to Greenland.

Explanation:

hope it helps

Alfred Wegner is a German weather scientist. His claim about the continental drift was that the continents were moving. He had 4 evidence to support his claim