find the directional derivative of f(x, y) = xy at p(7, 7) in the direction from p to q(10, 3).

Answers

Answer 1

The directional derivative of f at point p(7,7) in the direction of q(10,3) is -1.4.

The directional derivative of f(x,y) at point p(7,7) in the direction of q(10,3) can be found using the formula:

D_v f(p) = ∇f(p) · v

where ∇f(p) is the gradient of f at point p, and v is the unit vector in the direction of q - p.

First, let's find the gradient of f:

∇f(x,y) = <∂f/∂x, ∂f/∂y> = <y, x>

So at point p(7,7), we have:

∇f(p) = <7, 7>

Next, we need to find the unit vector in the direction of q - p:

v = (q - p) / ||q - p||

= <10 - 7, 3 - 7> / ||<10 - 7, 3 - 7>||

= <3, -4> / 5

= <0.6, -0.8>

Now we can find the directional derivative:

D_v f(p) = ∇f(p) · v

= <7, 7> · <0.6, -0.8>

= 7(0.6) + 7(-0.8)

= -1.4

So the directional derivative of f at point p(7,7) in the direction of q(10,3) is -1.4.

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Related Questions

This question will make you think. This is for a lot of points so please answer correctly and clearly state the answer. If you want to reach out to me: you can find my number like this: 8133208481. For all of those haters and reporters goody-two-shoes, this is totally not my number...........this is a math equation

This question will make you think. This is for a lot of points so please answer correctly and clearly

Answers

Answer:

6

Step-by-step explanation:

Let x by the unknown number.

Given:

Eighty-five more than the square of a number is the same as the square of the quantity that is 17 less than the number.

Therefore, the equation representing the given information is:

\(\boxed{x^2+85=(x-17)^2}\)

To solve for x, expand the right side:

\(\implies x^2+85=(x-17)^2\)

\(\implies x^2+85=(x-17)(x-17)\)

\(\implies x^2+85=x^2-34x+289\)

Subtract x² from both sides of the equation:

\(\implies 85=-34x+289\)

Add 34x to both sides:

\(\implies 34x+85=289\)

Subtract 85 from both sides:

\(\implies 34x=204\)

Divide both sides by 34:

\(\implies x=6\)

Therefore the unknown number is 6.

A bacteria culture doubles every 5 hours. Determine the hourly growth rate of the bacteria
culture. Round your answer to the nearest tenth of a percent.

Answers

\(\sqrt[5]{2}-1 = 1 +x - 1\)Answer:

14.87% per hour

Step-by-step explanation:

Let's pretend we're starting with one bacteria.

Double of one is two

We're gonna have to use this formula: A = P(1 + x)ⁿ

A = Amount (which is 2)

P = Initial amount (which is 1)

x = percentage per time (hour)

n = amount of time (hours)

So our equation will look like this:

2 = 1(1 + x)⁵

First, we need to root both sides to isolate (1 + x)

\(\sqrt[5]{2} = \sqrt[5]{(1+x)}\)

\(\sqrt[5]{2} = 1 +x\)

Then subtract both sides by 1

\(\sqrt[5]{2}-1 = 1 +x - 1\)

\(x=\sqrt[5]{2}-1\)

\(\sqrt[5]{2} = 1.148698355\)

1.148698355 - 1 = 0.148698355

x = 0.148698355

I don't know how to do whatever this is

I don't know how to do whatever this is

Answers

Answer: y values in order: 2, 1, 0.5

Step-by-step explanation:

Just take the x values and put them in place of the x in the above equation.

As for -1, you're flipping 0.5 over to a fraction of 1/0.5, which equals 2, so that's the first y value.

*This is because any negative exponent gets the number in the denominator with 1 in the numerator, then the denominator can change depending on the value of the exponent

For 0, anything to the power of 0 is 1, so that's the second y value.

And then for 1, the number doesn't change, so just put 0.5 in the third y-value.

Also I see it says for you to sketch a graph, in this case the picture I have showing is what the graph would look like

Hope this helps at least :)

I don't know how to do whatever this is

Use the point (h,k) to help you write a possible equation for the graph below

Use the point (h,k) to help you write a possible equation for the graph below

Answers

By using the vertex of the quadratic equation, we will get the equation:

y = -2*(x + 6)^2

How to write the quadratic equation?

For a quadratic equation with a leading coefficient "A" and a vertex (h, k), the equation can be written as:

y = A*(x - h)^2 + k

Here we can see that the vertex is (-6, 0), so we have:

y = A*(x + 6)^2

We also can see that the parabola passes through the point (-4, -8), replacing these values above we will get:

-8 = A*(-4 + 6)^2

-8 = A*(2)^2

-8 = 4A

-8/4 = A

-2 = A

Then the quadratic equation is:

y = -2*(x + 6)^2

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I really need help with this please and thanks

I really need help with this please and thanks

Answers

1/3 is the correct answer because 3/10 is too unequal or else it would be 3.333333/10, 30% is the same as 3/10, and 3% is just 3/100.

Suppose the following lotteries.
⚫ Lottery A gives $2 million with 10%, $1 million with 80%, and $0 with 10%.
⚫ Lottery B gives $2 million with 12%, $1 million with 3%, and $0 with 82%.
⚫ Lottery C gives $2 million with 40%, $1 million with 10%, and $0 with 40%.
⚫ Lottery D gives $2 million with 3%, $1 million with 24%, and $0 with 73%.
Show one example of preference relations which violate Independence of the expected utility theorem, and explain the reason.

Answers

The introduction of B should not have impacted the preference between A and C.

Preference relations that violate Independence of the expected utility theorem:

Independence of irrelevant alternatives (IIA) refers to a preference relation principle that states that the decision maker's preference between two choices should be the same, regardless of the presence or absence of a third, unrelated option.

Suppose the following preferences:

Lottery A: 0.1 chance to win $2,000,000, 0.8 chance to win $1,000,000, 0.1 chance to win nothing

Lottery B: 0.12 chance to win $2,000,000, 0.03 chance to win $1,000,000, 0.85 chance to win nothing, and

Lottery C: 0.4 chance to win $2,000,000, 0.1 chance to win $1,000,000, 0.4 chance to win nothing.

Lottery A over B: A is chosen over B with probability 1

Lottery C over A: C is chosen over A with probability 0.5

Lottery C over B: C is chosen over B with probability 0

Suppose you're trying to decide between A and B, and you choose A. This implies that you have a specific preference between the two options. Similarly, if you choose C over A, it implies that you have a specific preference between those two options as well.

However, if you now compare C to B, you'll see that C is selected over B with probability 0, indicating that there is no preference between the two alternatives. This is in violation of the Independence of irrelevant alternatives theorem because the introduction of B should not have impacted the preference between A and C. Thus, this violates the Independence of the expected utility theorem.

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When dividing polynomials using factorization, canceling identical factors in the denominator and the numerator will give the _______.

Answers

Answer:

quotient

Step-by-step explanation:

Answer:

quotient

Step-by-step explanation:

Cancelling identical factors in the numerator and the denominator will give the quotient. For example,x2+5x+6x+3=(x+2)(x+3)x+3 = x + 3

 

what is the square root of 5 times 3 divided by 2 to the power of 10

Answers

Answer:

0.0065509804

Step-by-step explanation:

Answer:

If you follow the order of operations it would be 0.12103072956 or approximately

0.12

0.121

0.1210

0.12103

0.121031

find the taylor polynomials p1, ..., p5 centered at a=0 for f(x)=7e−x.

Answers

Taylor polynomials p1, ..., p5 centered at a=0 for f(x)=7e^(-x) are:

p1(x) = 7 - 7x

p2(x) = 7 - 7x + 3.5x^2

p3(x) = 7 - 7x + 3.5x^2 - 1.17x^3

p4(x) = 7 - 7x + 3.5x^2 - 1.17x^3 + 0.205x^4

p5(x) = 7 - 7x + 3.5x^2 - 1.17x^3 + 0.205x^4 - 0.025x^5

To find the Taylor polynomials p1, ..., p5 centered at a=0 for f(x)=7e^(-x), we need to calculate the derivatives of f(x) and evaluate them at x=0:

f(x) = 7e^(-x)

f(0) = 7

f'(x) = -7e^(-x)

f'(0) = -7

f''(x) = 7e^(-x)

f''(0) = 7

f'''(x) = -7e^(-x)

f'''(0) = -7

f''''(x) = 7e^(-x)

f''''(0) = 7

Using these derivatives, we can write the Taylor polynomials p1, ..., p5 centered at a=0 as:

p1(x) = f(0) + f'(0)x = 7 - 7x

p2(x) = p1(x) + (1/2!) f''(0)x^2 = 7 - 7x + (1/2)(7)x^2 = 7 - 7x + 3.5x^2

p3(x) = p2(x) + (1/3!) f'''(0)x^3 = 7 - 7x + (1/2)(7)x^2 - (1/6)(7)x^3 = 7 - 7x + 3.5x^2 - 1.17x^3

p4(x) = p3(x) + (1/4!) f''''(0)x^4 = 7 - 7x + (1/2)(7)x^2 - (1/6)(7)x^3 + (1/24)(7)x^4 = 7 - 7x + 3.5x^2 - 1.17x^3 + 0.205x^4

p5(x) = p4(x) + (1/5!) f^(5)(0)x^5 = 7 - 7x + (1/2)(7)x^2 - (1/6)(7)x^3 + (1/24)(7)x^4 - (1/120)(7)x^5 = 7 - 7x + 3.5x^2 - 1.17x^3 + 0.205x^4 - 0.025x^5

Therefore, the Taylor polynomials p1, ..., p5 centered at a=0 for f(x)=7e^(-x) are:

p1(x) = 7 - 7x

p2(x) = 7 - 7x + 3.5x^2

p3(x) = 7 - 7x + 3.5x^2 - 1.17x^3

p4(x) = 7 - 7x + 3.5x^2 - 1.17x^3 + 0.205x^4

p5(x) = 7 - 7x + 3.5x^2 - 1.17x^3 + 0.205x^4 - 0.025x^5

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Integrate the ODE
dy/dx = x² √y, 0 < x < 2, y(0) = 1
using Euler's method (Δx = 0, 2) to compute y(2). Obtain analytical solution to the ODE and compare y(2) obtained using Euler's method with that obtained analytically.

Answers

we find that the numerical approximation using Euler's method gives y(2) ≈ 1.865, while the analytical solution gives y(2) = 2.5.

Using the formula y(n+1) = y(n) + Δx * f(x(n), y(n)), where f(x, y) = x² √y, we can calculate the values of y at each step. Here's the step-by-step calculation:

Step 1: For x = 0, y = 1 (initial condition).

Step 2: For x = 0.2, y = 1 + 0.2 * (0.2)² * √1 = 1.008.

Step 3: For x = 0.4, y = 1.008 + 0.2 * (0.4)² * √1.008 = 1.024.

Step 4: For x = 0.6, y = 1.024 + 0.2 * (0.6)² * √1.024 = 1.052.

Step 5: For x = 0.8, y = 1.052 + 0.2 * (0.8)² * √1.052 = 1.094.

Step 6: For x = 1.0, y = 1.094 + 0.2 * (1.0)² * √1.094 = 1.155.

Step 7: For x = 1.2, y = 1.155 + 0.2 * (1.2)² * √1.155 = 1.238.

Step 8: For x = 1.4, y = 1.238 + 0.2 * (1.4)² * √1.238 = 1.346.

Step 9: For x = 1.6, y = 1.346 + 0.2 * (1.6)² * √1.346 = 1.483.

Step 10: For x = 1.8, y = 1.483 + 0.2 * (1.8)² * √1.483 = 1.654.

Step 11: For x = 2.0, y = 1.654 + 0.2 * (2.0)² * √1.654 = 1.865.

Therefore, using Euler's method with a step size of Δx = 0.2, we approximate y(2) to be 1.865.

To obtain the analytical solution to the ODE, we can separate variables and integrate both sides:

∫(1/√y) dy = ∫x² dx

Integrating both sides gives:

2√y = (1/3)x³ + C

Solving for y:

y = (1/4)(x³ + C)²

Using the initial condition y(0) = 1, we can substitute x = 0 and y = 1 to find the value of C:

1 = (1/4)(0³ + C)²

1 = (1/4)C²

4 = C²

C = ±2

Since C can be either 2 or -2, the general solution to the ODE is:

y = (1/4)(x³ + 2)² or y = (1/4)(x³ - 2)²

Now, let's evaluate y(2) using the analytical solution:

y(2) = (1/4)(2³ + 2)² = (1/4)(8 + 2)² = (1/4)(10)² = 2.5

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if someone in 2022 is now 89, how old were they in 1971?

Answers

Answer:38

Step-by-step explanation:

they were born in 1933 and 1971 minus 1933 is 38.

how do you explain how to get the answer for 4 1/5 divided by 2 1/3

Answers

Answer:

2 3/5

Step-by-step explanation:

1/5÷1/3

and solve

1×3

5/1

=3/5

Therefore:

1/5÷1/3=3/5

AABC is reflected over the yaxis.

What are the vertices of AA'B'C'?

AABC is reflected over the yaxis.What are the vertices of AA'B'C'?

Answers

Answer:

A'=(-1, 5)  B'=(-2, 3)  C'=(-5, 4)

Step-by-step explanation:

Reflecting over the y-axis changes the only the first point changes into a negative, while the second stays the same.



The voltage V of an audio system's speaker can be represented by V=4 √P, where p is the power of the speaker. An engineer wants to design a speaker with 400 watts of power. What will the voltage be?

Answers

The voltage of the speaker when the power is 400 watts will be given by ± 80 volt.

Given the equation is,

V = 4 √P

here V is the voltage of an audio system's speaker and P is the power of the audio system's speaker.

Here it is given that we have to design a speaker with 400 watts of power. So the equation becomes when P = 400

V = 4 √400

We know that, √400 = ± 20

So, V = 4 * (± 20) = ± 80

Hence the voltage of the speaker will be given by ± 80 volt.

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PLS HELP ILL GIVE BRAINLIST AND FOLLOW U

PLS HELP ILL GIVE BRAINLIST AND FOLLOW U

Answers

Answer:

61.2

Step-by-step explanation:

base=6

height=10

Area of parellelogram=base x height

=6x 10.2

=61.2 sq.ft

MARK ME BRAINLIEST THANKS MY ANSWER PLEASE

julie can make 60 cake pops in 4 hours
how many cake pops can she make in 1 hour?

Answers

Answer:

15 cake pops

Step-by-step explanation:

60 cake pops = 4 hours

x cake pops = 1 hour

60/4 = 15

hence Julia can make 15 cake pops per hour

simplify (2/9*3/6)+(3/4%12/5)-[1/4-(1/4*2/3)]

Answers

The simplified value of the given expression is 49/288.

To simplify the given expression (2/9 * 3/6) + (3/4 % 12/5) - [1/4 - (1/4 * 2/3)], first, we need to simplify the brackets. Let's start by simplifying the expression inside the brackets.[1/4 - (1/4 * 2/3)]

Step 1: Multiply 1/4 and 2/3= 1/4 × 2/3= 2/12= 1/6Step 2: Subtract 1/6 from 1/4= 1/4 - 1/6= (3/12) - (2/12)= 1/12Therefore, [1/4 - (1/4 * 2/3)] = 1/12

Now, let's substitute this value in the original expression and simplify it.(2/9 * 3/6) + (3/4 % 12/5) - 1/12Step 1: Simplify the multiplication expression2/9 * 3/6= (2*3)/(9*6)= 6/54= 1/9Step 2: Simplify the modulo expression 3/4 % 12/5= (3/4) / (12/5)= (3/4) × (5/12)= 15/48= 5/16

Now, substituting these values in the original expression, we get1/9 + 5/16 - 1/12= 16/144 + 45/288 - 12/144= (16+45-12)/288= 49/288Therefore, the simplified value of the given expression is 49/288.

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A financial transaction that is added to a ledger balance is called a credit. Please select the best answer from the choices provided T or F

Answers

Question:

A financial transaction that is added to a ledger balance is called a credit.

Answer:

The answer is True, I just took the test

27^2/3 * sqrt{16 } ÷5^0
(2^2 * 2^1/3)^0
12x^7/4x^3
\sqrt

Answers

The value of the numerical expression will be 36. Then the correct option is 36.

What is Algebra?

Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.

The definition of simplicity is making something simpler to achieve or grasp while also making it a little less difficult.

The numerical expression is given below.

\(\rightarrow \dfrac{\left ( 27 \right)^{2/3} \times \sqrt{16}}{5^0}\)

Simplify the expression, then we have

⇒ (∛(27)² × √16) / 5⁰

⇒ (3)² × 4

⇒ 9 × 4

⇒ 36

The value of the numerical expression will be 36. Then the correct option is 36.

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The complete question is given below.

Compute the expression \(\dfrac{\left ( 27 \right)^{2/3} \times \sqrt{16}}{5^0}\)

a) 36

b) 35

c) 34

d) 1

The length of a planet's orbit around a star is approximately 29,870,000 km.
It takes the planet about 1670 Earth days to complete a full orbit.
What is the planet's average speed in kmh-' to 3sf?

Answers

Answer:

745 k/hr

Step-by-step explanation:

mathematically, 1 day = 24 hours

1670 days = 1670 * 24 = 40,080 hours

The speed is thus;

(29,870,000)/40,080 = 745.259

= 745 km/h

any direction cosine matrix component is the cosines of the angle between an unit vector in one axis system and an unit vector in the other axis system

Answers

Direction Cosine expresses the relationship of a vector or line in three dimensions with each of the three axes. The direction cosine is the cosine of the angle formed by this line with the x, y, and z axes, in that order.

The operation is used to calculate the magnitude of the vector is dividing by cosine.

cosine function

cos θ = ca / ​​H

ca=adjacent leg (x-axis) and

H= hypotenuse (vector module)

H = ca / ​​cos θ

therefore, to find the magnitude of the vector, the method is to divided by the cosine.

Cosine matrix in one direction (DCM) is a  3 x 3 rotation matrix C, the columns of which represent unit vectors in the body axes projected along the reference axes, specifies the direction cosine matrix, which represents the attitude of the body frame relative to the reference frame.

Direction Cosine

Direction cosine is the cosine of the angle formed by a line in three-dimensional space with the x, y, and z axes. In three dimensions, direction cosines can be calculated for a vector or a straight line. It is the cosines of the angle formed by the line intersected by the three axes.

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Fill in the blanks
Needs to be answered asappp

Fill in the blanksNeeds to be answered asappp

Answers

Answer:

I'm guessing the y axis would be velocity and the x axis would be time, seconds then the top box could be time v velocity

The baker's recipe for a loaf of bread calls for 12 oz of flour. If he uses all of his flour to make loaves of bread, how many loaves can he bake in seven days?

Answers

This question is incomplete

Complete Question

A baker uses 5.5 Ibs of flour daily

The baker's recipe for a loaf of bread calls for 12 oz of flour. If he uses all of his flour to make loaves of bread, how many loaves can he bake in seven days?

Answer:

51.3 loaves of bread

Step-by-step explanation:

Converting 5.5 Ibs to oz (ounces)

1 Ibs =>12 oz

5.5 Ibs => x

Cross Multiply

12 × 5.5 => 88 oz

1 loaf of bread =>12 oz

Hence, in 1 day

12 oz =>1 loaf of bread

88 oz => x

x =>88 oz/ 12 oz

x => 7.3333333333 loaves of bread

Hence, he can make 7.3333333333 loaves of bread in 1 day

Hence, in 7 days

1 day => 7.3333333333 loaves

7 days => x

x => 7 × 7.3333333333 loaves

x => 51.333333333 loaves of bread

Approximately => 51.3 loaves of bread

if the sum of the measures of the interior angles of a convex polygon is 5040°,how many sides does the polygon have?
A.22
B.26
C.30
D 34​

Answers

To answer this question, we need to use the formula for finding the sum of the interior angles of a convex polygon, n = 30

Sum of interior angles = (n-2) x 180 degrees
Here, n represents the number of sides of the polygon. We are given that the sum of the interior angles is 5040 degrees. So we can set up an equation as follows:
5040 = (n-2) x 180
Simplifying this equation, we get:
n - 2 = 28
Therefore, the polygon has 30 sides, which means the answer is option C. It is important to note that this formula only applies to convex polygons, which are polygons with all interior angles less than 180 degrees and no sides that "cave in". If the polygon is not convex, this formula will not work.

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____ diagrams are used in conjunction with detailed use case descriptions or with activity diagrams.

Answers

Sequence diagrams are used in conjunction with detailed use case descriptions or with activity diagrams.

Sequence diagrams are a type of interaction diagram that display the sequential flow of actions and interactions between objects and components in a system.

These diagrams help to visualize the timing and order of events, making it easier to understand and design complex processes.

By incorporating sequence diagrams with use case descriptions and activity diagrams, a clearer and more comprehensive understanding of a system's functionality can be achieved.

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5. Check convergence for the following series: a. Σ=1 2η2 +1 3n2-4 n 21 b. Σ=0 Ln5η C. Σ=2 In (n) Ln=2 m2

Answers

(a) The series Σ(1/(2n²+1) + 1/(3n²-4n+1)) converges, (b)  The series Σ(ln(5n)) from n=0 diverges and  (c) the series Σ(ln(n)/ln(2)) from n=2 to m² diverges. to check convergence we can do :


a. Σ(1/(2n²+1) + 1/(3n²-4n+1))
b. Σ(ln(5n)) from n=0
c. Σ(ln(n)/ln(2)) from n=2 to m²
a. To check convergence for the series Σ(1/(2n²+1) + 1/(3n²-4n+1)), we'll use the Comparison Test. Since both terms in the sum are positive and the denominators are greater than n²we can compare it with the series Σ(1/n²) which converges according to the p-series test (p=2 > 1). Therefore, the series Σ(1/(2n²+1) + 1/(3n²-4n+1)) converges.


b. For the series Σ(ln(5n)) from n=0, we'll use the Divergence Test. As n approaches infinity, ln(5n) doesn't approach 0 but increases indefinitely. Hence, the series Σ(ln(5n)) from n=0 diverges.
c. To check the convergence for the series Σ(ln(n)/ln(2)) from n=2 to m², we'll use the Integral Test. Let's first note that ln(n)/ln(2) is positive, continuous, and decreasing for n ≥ 2. The integral from 2 to infinity of ln(x)/ln(2) dx doesn't converge, as it's an improper integral of a function that decreases too slowly (ln(x) decreases much slower than any power function). Therefore, the series Σ(ln(n)/ln(2)) from n=2 to m² diverges.

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A. we can conclude that Σ(2n^2+1)/(3n^2-4n+21) is also convergent.

B.  we can conclude that Σln(n) is divergent. Therefore, Σln(5n) is also divergent.

C. Σ2^mm is a known divergent series, we can conclude that ΣIn(n)Ln(2m^2) is also divergent.

a. To check the convergence of this series, we can use the comparison test. We know that 2n^2+1 < 3n^2 for all n > 1. Therefore, we can write:

Σ(2n^2+1)/(3n^2-4n+21) < Σ(3n^2)/(3n^2-4n+21)

Now, we can use the limit comparison test with the series Σ(3n^2)/(3n^2-4n+21) and Σ(1/n^2), which is a known convergent series. Taking the limit of the ratio of these two series as n approaches infinity, we get:

lim n→∞ (3n^2)/(3n^2-4n+21) / (1/n^2) = lim n→∞ (3n^4)/(3n^2-4n+21) = 3

Since this limit is finite and nonzero, and since Σ(1/n^2) is convergent, we can conclude that Σ(2n^2+1)/(3n^2-4n+21) is also convergent.

b. To check the convergence of this series, we can use the integral test. We know that ln(x) is a monotonically increasing function for x > 1, and that ln(5) > 1. Therefore, we can write:

Σln(5n) > Σln(n)

Now, we can use the integral test with the series Σln(n) and the integral ∫ln(x)dx from 1 to infinity. Evaluating this integral, we get:

∫ln(x)dx = xln(x) - x + C

Taking the limit of this expression as x approaches infinity, we get:

lim x→∞ (xln(x) - x + C) = infinity

Since this limit is infinite, we can conclude that Σln(n) is divergent. Therefore, Σln(5n) is also divergent.

c. To check the convergence of this series, we can use the Cauchy condensation test. We know that In(n) is a monotonically increasing function for n > 1. Therefore, we can write:

ΣIn(n)Ln(2m^2) < ΣIn(2m)Ln(2m^2)

Now, we can use the Cauchy condensation test with the series ΣIn(2m)Ln(2m^2) and Σ2^m In(2^m)Ln(2(2^m)^2), which simplifies to:

Σ2^m In(2^m)Ln(2^(2m+2)) = Σ2^m(m ln(2) + ln(2))Ln(2^2) = 4ln(2)Σ2^mm

Since Σ2^mm is a known divergent series, we can conclude that ΣIn(n)Ln(2m^2) is also divergent.

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Find when and .Both values are .Both values are . and and

Answers

from the question;

we to find |x| when x = 15 and when x = -15

by definition of absolute value we have

\(\lvert x\rvert\text{ = x}\)

Thats for every value of x, the absolute value is always positive

Hence,

\(\begin{gathered} \text{when x = 15} \\ \lvert15\rvert=\text{ 15} \end{gathered}\)

Also

\(\begin{gathered} \text{when x = - 15} \\ \lvert-15\rvert\text{ = 15} \end{gathered}\)

Therefore the correct answer is

Both values are 15

option B

show that the vectors ⟨1,2,1⟩,⟨1,3,1⟩,⟨1,4,1⟩ do not span r3 by giving a vector not in their span:

Answers

To show that the vectors ⟨1,2,1⟩, ⟨1,3,1⟩, ⟨1,4,1⟩ do not span ℝ³, we can find a vector that cannot be written as a linear combination of these vectors.

To determine if the vectors ⟨1,2,1⟩, ⟨1,3,1⟩, ⟨1,4,1⟩ span ℝ³, we need to check if any vector in ℝ³ can be expressed as a linear combination of these vectors.

Let's consider a vector ⟨a, b, c⟩ that we want to test if it belongs to the span of the given vectors. In order for ⟨a, b, c⟩ to be in their span, there must exist scalars x, y, and z such that:

x⟨1, 2, 1⟩ + y⟨1, 3, 1⟩ + z⟨1, 4, 1⟩ = ⟨a, b, c⟩

Expanding the equation, we have:

⟨x + y + z, 2x + 3y + 4z, x + y + z⟩ = ⟨a, b, c⟩

From this, we can equate the corresponding components:

x + y + z = a

2x + 3y + 4z = b

x + y + z = c

Now, we need to find a vector ⟨a, b, c⟩ that does not satisfy these equations. One such example is when a = 1, b = 2, and c = 3. Solving the equations, we get:

x + y + z = 1

2x + 3y + 4z = 2

x + y + z = 3

Solving these equations simultaneously, we find that there is no solution. Therefore, the vector ⟨1, 2, 3⟩ cannot be expressed as a linear combination of the given vectors ⟨1, 2, 1⟩, ⟨1, 3, 1⟩, and ⟨1, 4, 1⟩.

Since we have found a vector that does not belong to their span, we can conclude that the vectors ⟨1, 2, 1⟩, ⟨1, 3, 1⟩, ⟨1, 4, 1⟩ do not span ℝ³.

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determine whether the given sequence could be arithmetic. if so, identify the first difference and the next term. −4, 4, 12, 20, 28,....

Answers

The next term in the sequence is 36.

Yes, the given sequence could be arithmetic. To determine the first difference, we subtract consecutive terms:

4 - (-4) = 8

12 - 4 = 8

20 - 12 = 8

28 - 20 = 8

The first difference between consecutive terms is 8. To find the next term, we add the first difference to the last term:

28 + 8 = 36

Therefore, the next term in the sequence is 36.

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Please help, thank youuuu

Please help, thank youuuu

Answers

The area of the composite figure is

321 square m

How to find the area of the composite figure

The area is calculated by dividing the figure into simpler shapes.

The simple shapes used here include

triangle anda quarter of a circle

Area of triangle = 1/2 x base x height

height = √(22² + 15²) = 16

= 1/2 x 15 x 16

= 120 square m

Area of quarter of circle = 1/4 x π x r²

= 1/4 x π x 16²

= 201 square m

Total area

= 201 square m + 120 square m

=  321 square m

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