Vector is perpendicular to x axis or i component.
Hence i component is 0
j component is 63.5
\(\\ \sf\longmapsto \overrightharpoon{A}=0\hat{i} +63.5\hat{j}\)
To calculate the density of an object which of the following values do you need to know a. Buoyancy b. Volume c. Weight d. Mass
Answer: Volume and mass
Explanation: I took the quiz lol
A proposed answer to a scientific problem is a _.
*Hypothesis
*Experiment
*Conclusion
*Theory
Answer:
A proposed answer to a s scientific problem is a hypothesis.
With an explanation please!
A car of mass 500kg is moving at 10m/s. The engine does work on the car and the speed increases to 16m/s. How much work is done by the engine to increase the speed of the car?
Answer:
39,000 Joules of Work
Explanation:
Work can be found out through the change in Kinetic Energy.
W = ΔKE
Change in KE is:
\(W = KE_{Final} - KE_{Initial}\)
Expand the equation you get:
\(W=\frac{1}{2} mv^{2}_{f} -\frac{1}{2} mv^{2}_{i}\)
Plugin the known values and solve:
\(W=\frac{1}{2} (500)(16)^{2} -\frac{1}{2} (500)(10)^{2}\)
\(W=(250)(256) -(250)(100)\)
\(W=64000-25000\)
\(W=39000 J\)
the after the switch has been closed for a long time, what is the voltage across the inductor in volts? select one:a.2b.20c.0d.40'\
The voltage across the inductor is 0 volts (c) because the inductor in a circuit reaches a steady-state condition.
What is the voltage across the inductor?When the switch in a circuit is closed for a long time, the inductor reaches a steady state. In this steady state, the inductor behaves like a short circuit, causing the voltage across it to be zero volts. This occurs because inductors resist changes in current flow. Initially, when the switch is closed, the inductor resists the sudden change in current, causing a back-emf to be generated. However, as time goes on and the current stabilizes, the inductor no longer opposes the flow of current, resulting in a voltage drop of zero volts across the inductor.
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A ball is launched from the ground with a horizontal speed of 30 m/s and a vertical speed of 30 m/s. How long will it take to get to the top of its trajectory?
The ball will take 3 seconds to get to the top of its trajectory When it is launched from the ground with a horizontal speed of 30 m/s and a vertical speed of 30 m/s
What is Trajectory ?When any object is thrown from horizontal at an angle θ except 90°, then the path followed by it is called trajectory, the object is called projectile and its motion is called projectile motion.
Here, we have a type of motion called projectile motion and it is pretty similar to an upside down parabola. The top of the trajectory is the vertex of the parabola and is also when v = 0.
Given :
Horizontal speed= 30m/sVertical Speed= 30 m/sThis problem is now relatively easy because we only need to find the vertical distance so we can ignore horizontal speed and use
vy = vy0 + ayt
Plug in our givens
0 = 30 - 10t
solve for t
t = 3 seconds
Hence, The ball will take 3 seconds to get to the top of its trajectory When it is launched from the ground with a horizontal speed of 30 m/s and a vertical speed of 30 m/s
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Help with physics needed. Would appreciate the help
The height of the hill, given the radius and mass of the Earth can be found to be 2.5 km.
How to find the height of the hill ?We can use the conservation of energy to solve this problem. The potential energy of the stone at the top of the hill is equal to its gravitational potential energy, which is given by:
PE = mgh
Solving for height , we get:
h = (G x M x m) / (R x m x g)
h = (6.67 x 10^-11 x 6 x 10^24 x 40) / ((6.4 x 10^6 + h) x 9.8)
h = 2.5 km
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How harmful are the emissions from cosmetics, hygiene, and cleaning products? Claim
Evidence 1
Evidence 2
Evidence 3
Reasoning
The claim can be Cosmetics, hygiene, and cleaning product emissions may be dangerous.
Evidence 1: Effect of Air Quality
Volatile organic compounds (VOCs), including formaldehyde, benzene, and toluene, can be found in a variety of cosmetic, hygiene, and cleaning goods. These VOCs have the potential to evaportate and cause indoor air pollution.
Environmental impact is evidence number two
Cosmetics, hygiene, and cleaning goods can have a detrimental environmental impact during manufacturing, usage, and disposal. Microplastics and certain chemicals are among the substances present in these items that may find their way into rivers and endanger aquatic life.
Evidence 3: Worker health effects
Occupational health risks can be present for workers who manufacture and produce hygiene, cleaning, and cosmetic items.
Reasoning: It is clear from the research that emissions from cosmetic, hygiene, and cleaning goods have the potential to be harmful.
Thus, this way, harmful are the emissions from cosmetics, hygiene, and cleaning products.
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HELPPPPPPPPPPP PLEASEEEEEEEEEEE
Complete this sentence. The solubility of a sample will ____________ when the size of the sample increases.
stay the same
decrease
increase
be unable to be determined
the answer is not decrease
The solubility of the sample will decrease
An atom with only 1 to 3 valence electrons will tend to____ those valence electrons.
-neutralize
-gain/add
-share
-lose/subtract
An atom with only 1 to 3 valence electrons will tend to lose/subtract those valence electrons. That is option D.
What are Valence electrons?Valence electrons are those electrons that are located at the outermost layer of an atom.
During a chemical reaction, elements that have 1 or 2 or 3 valence electrons donate or give out their electron to form a chemical bond with another aton if an element.
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a force of 1150 N acts parallel to ramp to push a 250 kg gun safe into a moving van. The ramp is frictionless and inclined at 17 degree
a) what is the acceleration of the safe up the ramp?
b) If we consider friction in this problem, with a friction force of 120 N, what is the acceleration of the safe
A force of 1150 N acts parallel to ramp to push a 250 kg gun safe into a moving van. The ramp is frictionless and inclined at 17 degree
a) To find the acceleration of the safe up the ramp,
1. Determine the component of the force parallel to the ramp: F_parallel = 1150 N
2. Calculate the gravitational force acting on the safe along the ramp: F_ gravity = m * g * sin(theta) = 250 kg * 9.81 m/s^2 * sin(17 degrees) ≈ 729.6 N
3. Calculate the net force acting on the safe: F_ net = F_ parallel - F_ gravity = 1150 N - 729.6 N ≈ 420.4 N
4. Use Newton's second law to find the acceleration: F_ net = m * a, so a = F_ net / m = 420.4 N / 250 kg ≈ 1.68 m/s^2
The acceleration of the safe up the ramp is approximately 1.68 m/s^2.
b) To find the acceleration of the safe considering friction, follow these steps:
1. Determine the friction force: F_friction = 120 N
2. Calculate the net force acting on the safe, considering friction: F_net_with_friction = F_parallel - F_gravity - F_friction = 1150 N - 729.6 N - 120 N ≈ 300.4 N
3. Use Newton's second law to find the acceleration with friction: a_with_friction = F_net_with_friction / m = 300.4 N / 250 kg ≈ 1.20 m/s^2
When considering friction, the acceleration of the safe up the ramp is approximately 1.20 m/s^2.
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An arrow leaves a bow at 60 m/s at an angle of 30 degrees to the horizon.
60 m/s
30
Which best gives the total time of flight for the arrow before it returns to its original
height?
P.4C
Answer: 11
Explanation:
After a storm, a hospital may have to rely on backup generators to power some equipment. Which is the energy conversion provided by the generators?
A. mechanical to electrical energy
B. thermal to mechanical energy
C. nuclear to mechanical energy
D. thermal to electric energy
Answer:
in a generator mechanical energy is a device that converts a form of energy into electricty
The energy conversion provided by the generators is: mechanical to electrical energy. Hence, option (A) is correct.
What is working principle of electric generators?An electric generator is a device that generates electric energy, which can either be immediately delivered to houses, businesses, and other structures or stored in batteries. Electromagnetic induction is the basis for how electric generators operate.
A horseshoe-shaped magnet's poles are quickly rotated around a conductor coil, which is a copper coil that has been tightly wound onto a metal core. An armature is made up of a conductor coil and a core. The armature is rotated by a mechanical energy source, such as a motor, by means of a shaft connection.
The magnetic field that exists between the magnet's two poles is broken off when the coil turns. The conductor's electrons will interact with the magnetic field, causing an electric current to flow through it.
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Mars moves in an elliptical orbit around the Sun. The location of the Sun relative to this ellipse is
Answer:
It is when the focus of the ellipse that is closer to the point where Mars is moving the fastest.
Explanation:
I hope it helps! Have a great day!
Anygays-
A 7.0 kg cannonball flying rightward at 12 hits a stationary rock. The cannonball keeps moving in the same
S
m
m
direction at 2.0 after the collision but sends the rock flying at 14 towards right
S
S
What is the mass of the rock?
Answer:
5.0 kg
Explanation:
use the equation; (m1v1i) + (m2v2i) = (m1v1f) + (m2v2f)
Why is a spherical bob preferred to bobs of other shapes for use in simple pendulum experiments
Answer
A spherical bob creates more control for the simple pendulum experiment. An irregular bob like a large piece of paper for instance, will create too much air resistance for a basic classical experiment to yield predictable results within the academic lab.
Question. 1 How much heat is necessary to warm 500g of water from 20°C to 65°C?
Answer:
The heat necessary to warm 500g of water from 20°C to 65°C is 37,620 J.
Explanation:
GIVEN: m = 500 gm, T₂ = 65°C AND T₁ = 20°C, we know that c (specific heat capacity) = 4180
TO FIND: The heat necessary to warm 500g of water from 20°C to 65°C.
SOLUTION:
By using the heat equation,
Q=m c ΔT
ΔT = T₂ - T1
ΔT = 65 - 20 = 45°C
In this case,
Q = 0.2 × 4180 × 45 = 37,620 J
Problem Three. In the circuit shown, the battery EMF is 10.0 V, the inductance L is 12.0mH, and the resistance R is 2.00Ω 11. If the switch is connected to point a, find the time (in ms) it takes for the current to reach 80.0% of its maximum value? (A) 3.21 (B) 4.22 (C) 2.56 (D) 8.67 (E) 9.66 12. After the inductor is fully charged, the switch is connected to point b. Find the current (in amps) after two time constants have passed. (A) 0.321 (B) 0.235 (C) 0.586 (D) 0.972 (E) 0.677
For Problem Three:
11. The time constant for this circuit is given by τ = L/R = 12.0mH / 2.00Ω = 6.00ms. To find the time it takes for the current to reach 80% of its maximum value, we can use the equation I = Imax * (1 - e^(-t/τ)), where Imax = EMF/R is the maximum current that the circuit will reach. Solving for t, we get t = -τ * ln(1 - 0.80 * R/EMF) = -6.00ms * ln(1 - 0.80 * 2.00Ω/10.0V) ≈ 3.21ms. Therefore, the answer is (A) 3.21ms.
12. After the switch is connected to point b, the circuit behaves like a simple RL circuit. The current in an RL circuit at any time t is given by I = Imax * e^(-t/τ), where Imax = EMF/R is the maximum current that the circuit will reach and τ = L/R is the time constant. After two time constants have passed (i.e. t = 2τ), the current in the circuit will have decayed to I = Imax * e^(-2) ≈ 0.135 * Imax. Therefore, we need to find Imax first: Imax = EMF/R = 10.0V/2.00Ω = 5.00A. Then, the current after two time constants have passed is I = 0.135 * Imax = 0.135 * 5.00A ≈ 0.677A. Therefore, the answer is (E) 0.677A.
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Calculate the wavelength and frequency of the photon emitted if an electron in a one-dimensional box of length 1.00 nm (1.00 x 10-ºm) makes a transition from n=3 to n=2 and the energy difference is entirely converted into the energy of the photon.
Given the length of the one-dimensional box, L, as 1.00 nm (1.00 × 10⁻⁹ m), the energy of an electron in the box can be calculated using the formula En = n²h²/8mL², where n is the quantum number, h is Planck's constant, m is the mass of an electron, and L is the length of the box.
To find the energy difference between two levels, n₁ and n₂, we use the formula ΔE = E(n₂) - E(n₁), where E represents the energy.
Using the values n₁ = 3 and n₂ = 2, and substituting the given constants, we find ΔE = 3.07 × 10⁻¹⁹ Joules.
The frequency of the photon emitted is calculated using the formula ν = ΔE / h, where ν represents frequency and h is Planck's constant. Substituting the calculated value of ΔE, we find ν = 4.63 × 10¹⁴ Hz.
To determine the wavelength of the emitted photon, we use the equation λ = c / ν, where λ represents the wavelength and c is the speed of light. Substituting the given values, we find λ = 6.47 × 10⁻⁷ m or 647 nm.
Therefore, the wavelength of the emitted photon is 6.47 × 10⁻⁷ m or 647 nm, and the frequency is 4.63 × 10¹⁴ Hz or 463 THz.
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the three main classes of asteroids, based on similarities in their infrared reflectance spectra, are c, s, and m. how do the different types of meteorites match up to the main asteroid classes?
C-type asteroids correspond to carbonaceous chondrites. S-type asteroids are similar to the most common stony meteorites. M-type asteroids are similar to iron meteorites.
Asteroids are classified into three broad composition classes: C-, S-, and M-types.
The most common asteroids are C-type (chondrite). They are dark in appearance and are most likely made of clay and silicate rocks. They are among the solar system's oldest objects.
The S-types ("stony") are composed of silicates and nickel-iron.
M-types are metallic (nickel-iron). The composition of asteroids changes according to the distance from the Sun. After they formed and partially melted, some experienced high temperatures, with iron sinking to the centre and forcing basaltic (volcanic) lava to the surface.
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****PLEASE HELP**** THERE ARE TWO QUESTIONS (ITS EASY)
but I think it's a and f
and
b and e
The tree branch in the preceding problem sags, and the child's feet rest on the ground. If the tension in the rope is reduced to 220 N, what is the value of the normal force being exerted on the child's feet?
The complete question is
A 45-kg child sits on a 3.2-kg tire swing. The tension on the rope is 470 N. The tree branch sags and the child's feet rest on the ground. If the tension in the rope is reduced to 220 N, what is the value of the normal force being exerted on the child's feet?
Answer:
Therefore the Normal force is being exerted on the child's feet is 252.36( 250N).
Explanation:
We are given
mass of child = 45kg
mass of the tire = 3.2kg
g = 9.8 m/s^2
We have the first case in which the tire is in swing so tension in that case will be which is the resultant force.
Fr = Resultant force
Ft = Tension force
Fg= Gravitational force
Fr = Fg + Ft
0 = -mg + Ft
Ft = mg
= (45+3.2)*9.8
= 48.2 * 9.8
Ft = 472.36N ( which is close to 470)
In the second case the child is in the rest position, The resultant force will be zero.
Fr = Ft + Fn + Fg ( Normal force is denoted by Fn )
0 = Ft + Fn + Fg
Fn = -Fg -Ft
Fn = mg -Ft
= 472.36 - 220
Fn = 252.36N ( close to 250N)
Therefore the Normal force being exerted on the child's feet will be 252.36N.
You are sitting in a chair on an elavator. The elavator accelerates downward, you and the chair land on the cround with the chair landing first and then you on the chair.
Explain the Net Forces at 3 points for each object
The points are: Before the Elevator Accelerates Downward, In Freefall, At Impact
Analyze whether the Normal Force would need to increase, and where the direction of the net force is for each object.
Answer:
fdsbgdfshtrsnbfgsbnhgr
Explanation:
cdfrgresgtrshtrwhtrwhtwjhdgngdabfeahydrtgnb
A bra rod i 2m long at a certain temperature. What i it length for temperature rie of 100k,if the expanivity of bra i 18×10-6k-1
The length of brass rod after expansion is 2.0036m.
How to calculate length?By definition, the length increase is:
Delta L = Alpha L_0 Delta TΔL=αL
naΔT
where alpha = 18 times 10^{-6}K^{-1}α=18×10−6
K-1
is expansion, L0 = 2 ml
na=2m is the initial length and Delta T = 100KΔT=100K is the temperature change. How to get:
Delta L = 18 times 10^{-6}cdot 2cdot 100 = 3.6 times 10^{-3} = 0.0036mΔL=18×10
−6
⋅2⋅100=3.6×10
−3
= 0.0036 meters
So the final length is:
L = L0 + delta L = 2 m + 0.0036 m = 2.0036 ml = l
0
na
+ΔL=2m+0.0036m=2.0036m
Linear expansion is the rate of increase in length of a solid sample per unit rise in temperature. If the length of the sample increases from l1 to l2 as the temperature increases by θ°, the expansion (α) is given by
l2 = l1(1 + αθ). This relationship assumes that α is independent of temperature.
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What nuclear reaction is shown in the equation below?
A. Nuclear fusion
B. Nuclear fission
C. Positron emission
D. Beta decay
The carbon isotope was cobined with the proton to produce the nitrogen isotope hence it is a fusion reaction.
What is a nuclear fusion?The term nuclear fusion refers to a kind of reaction in which two nuclei fuse together to give rise to a single nuclei with the evolution of energy.
We can see that the carbon isotope was cobined with the proton to produce the nitrogen isotope hence it is a fusion reaction.
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Answer:
A. Nuclear fusion
Explanation:
got it right, trust
A beam of light passes through the air (n = 1. 00) and enters a diamond (n - 2. 42) at an angle of incidence of 40 degrees. Use Snell's Law to find the angle of refraction in the diamondIf the diamond is placed in a tank of water (n - 1. 33) and the beam of light enters the diamond at the same angle of incidence, what would be the new angle of refraction Show all work
Explanation:
This is the correct answer...
I hope you understand...
water displacement was used as an output for gas production in this experiment. how did vapor pressure play a role in the experiment?
In the context of an experiment using water displacement as an output for gas production, vapor pressure can play a role in the experiment in a few ways like gas Collection, gas Solubility, water Vapor Contribution.
1. Gas Collection: The vapor pressure of water can affect the gas collection process. When a gas is generated in the experiment, it displaces water in a container or tube. The vapor pressure of water determines the partial pressure of water vapor in the gas phase, which can affect the total pressure inside the container or tube. This information is crucial for accurately measuring the volume of gas produced by accounting for the partial pressure of water vapor.
2. Gas Solubility: The vapor pressure of water also influences the solubility of certain gases in water. Different gases have varying solubilities in water, and the vapor pressure of water can affect the rate at which gases dissolve or come out of solution. This can impact the gas production rate in the experiment, as gases may dissolve in water before being collected.
3. Water Vapor Contribution: Water vapor itself can be produced as a result of the experimental conditions, especially if water is heated or if the reaction produces water as a byproduct. The presence of water vapor adds to the total pressure inside the gas collection system. Therefore, when measuring the volume or pressure of the gas collected, it is essential to consider and account for the contribution of water vapor to the total pressure.
It is important to carefully consider the vapor pressure of water and its potential effects on gas collection and measurement accuracy in the experimental setup. By understanding and accounting for these factors, researchers can ensure accurate and reliable results in the experiment.
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A hiker walks 23.87 m, E and 12.90 m, N. What is the direction of his resultantdisplacement?
23.38 ° to the positive x-axis
Explanation
Step 1
draw the vectors
Step 2
add the vectors, ( component to component)
so
a) get the components of V1
\(\begin{gathered} 23.87\text{ at 0\degree} \\ so \\ V_{1x}=23.87\text{ cos 0=23.87} \\ V_{1y}=23.87\text{ sin 0= 0} \end{gathered}\)b) components of V2
\(\begin{gathered} 12.9\text{ at 90 \degree} \\ so \\ V_{2x}=\text{ 12.9 cos 90=0} \\ V_{2y}=12.9\text{ sen 90=12.9} \end{gathered}\)c) add
\(\begin{gathered} Vdis_x=23.87+0=23.87 \\ Vdis_y=0+12.9 \end{gathered}\)so, the magnitude of the displacement is
\(\begin{gathered} \lvert Vd\rvert=\sqrt[]{V^2_x+V^2_y} \\ replace \\ \lvert Vd\rvert=\sqrt[]{23.87^2+12.9^2} \\ \lvert Vd\rvert=27.132 \end{gathered}\)finally, the direction
as we have a rigth triangle
let
opposite side= 12.9
adjacent side=23.8
Now, use the tan function to find the angles
so
\(\begin{gathered} \tan \emptyset=\frac{opposite\text{ side }}{\text{adjancent side}} \\ \text{replace} \\ \tan x=\frac{12.9}{23.87} \\ \text{isolate x} \\ x=\tan ^{-1}(\frac{12.9}{23.87}) \\ x=28.38 \end{gathered}\)therefore, the direction of the resultant is
23.38 ° to the positive x-axis
I hope this helps you
A gymnast balancing on a beam will put her arms out. Why does this help?
By keeping their centre of gravity over the beam, a gymnast may balance himself. The gymnast increases their moment of inertia, or resistance to rotational motion, by spreading their arms out to the sides, making it harder to unintentionally tilt or spin. As a result, their body is more stable, aiding in balance maintenance. Moreover, the centre of mass can be slightly adjusted with the arm movements to make up for any minor deviations from the equilibrium position. The gymnast can also orient oneself in relation to the beam using the visual clues provided by the arms. Overall, while balancing on a beam, a gymnast can gain various advantages from extending their arms to the side, including increased stability and many more.
A common brick is about 1.8 times denser than water. what is the apparent weight of a 0.20 m3 block of bricks under water?
Answer:
Pressure of .2 m^3 of bricks:
Pb = ρ g H = 1.8 ρw * 9.80 m/s^2 * .20 m = 1800 * 9.8 * .2 = 3530 Pascals
ρb = 1.8 ρw = 1.8 since the density of bricks is 1.8 that of water
Pw = 1 * 9.8 * 1000 * .2 = 1960 Pascals
W = P * A pressure * Area = Force
Pnet = 1570 Pascals - pressure due to bricks under water
F = 1570 N/m^2 * .2m^2 = 63 N force on pile of bricks
which wave has a higher frequency and why?
Explanation:
the figure in the left side has higher frequency.
because it has more nos. of wave in 1sec.