Find the circumference of 78.5

Answer:

4.76

Step-by-step explanation:

had this on a test today!

The point that could be the location of the other end of the wall will be (0, 5).

By using one or more elements or coordinates, a reference frame can properly pinpoint location alongside other mathematical components on such space, including Euclidean space.

A point or object in a two-dimensional plane can be found by utilizing its coordinates, which appear to be sets of integers. The y and x vectors can be used to identify the position of a point on a double surface. a group of photos used to identify certain areas.

In conclusion, the point that could be the location of the other end of the wall will be (0, 5).

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The surface is parameterized by

\(\vec s(u,v) = x(u, v) \, \vec\imath + y(u, v) \, \vec\jmath + z(u, v)) \, \vec k\)

and the normal to the surface is given by the cross product of the partial derivatives of \(\vec s\) :

\(\vec n = \dfrac{\partial \vec s}{\partial u} \times \dfrac{\partial \vec s}{\partial v}\)

It looks like you're given

\(\begin{cases}x(u, v) = u + v\\y(u, v) = 2u^2\\z(u, v) = u - v\end{cases}\)

Then the normal vector is

\(\vec n = \left(\vec\imath + 4u \, \vec\jmath + \vec k\right) \times \left(\vec \imath - \vec k\right) = -4u\,\vec\imath + 2 \,\vec\jmath - 4u\,\vec k\)

Now, the point (2, 2, 0) corresponds to u and v such that

\(\begin{cases}u + v = 2\\2u^2 = 2\\u - v = 0\end{cases}\)

and solving gives \(u = v = 1\), so the normal vector at the point we care about is

\(\vec n = -4\,\vec\imath+2\,\vec\jmath-4\,\vec k\)

Then the equation of the tangent plane is

\(\left(-4\,\vec\imath + 2\,\vec\jmath - 4\,\vec k\right) \cdot \left((x-2)\,\vec\imath + (y-2)\,\vec\jmath + (z-0)\,\vec k\right) = 0\)

\(-4(x-2) + 2(y-2) - 4z = 0\)

\(\boxed{2x - y + 2z = 2}\)

Answer:

4/6, 8/12, 16/24, etc. are examples of equivalent fractions, but there are none with the denominator of 10.

Step-by-step explanation:

Hope this helps, and have a great day! :D

Answer:

201.06

Step-by-step explanation:

Aaron's taxable income is negative (-$10,100), it means that he does not have any taxable income.

To determine the amount of taxable income for Aaron Rentz in 2020, we need to consider his wages, interest income, and any deductions or credits he may be eligible for.

From the given information, Aaron has $900 of wages and $1,400 of interest income.

In 2020, the standard deduction for a single individual was $12,400. Since Aaron is a qualifying child of his parents, he may not be able to claim his own personal exemption.

To calculate Aaron's taxable income, we subtract the standard deduction from his total income:

Taxable Income = Total Income - Standard Deduction

Taxable Income = $900 + $1,400 - $12,400

Taxable Income = $2,300 - $12,400

Taxable Income = -$10,100

Since Aaron's taxable income is negative (-$10,100), it means that he does not have any taxable income.

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answer:

∠B = 70°

step-by-step explanation:

∠A = ∠B

8x + 6 = 4x + 38

4x + 6 = 38

4x = 32

x = 8

4(8) + 38

32 + 38

= 70

Answer:

sorry homie im bad at math but download conects

Step-by-step explanation:

i just cheat my way through life

The number of combinations of 6 boys and 20 girls that can exist among 26 children born in a hospital on a given day is 230,230.

]To calculate the number of combinations, we can use the concept of binomial coefficients. The formula for calculating the number of combinations is C(n, k) = n! / (k!(n-k)!), where n is the total number of objects and k is the number of objects we want to select.

In this case, we have 26 children in total, and we want to select 6 boys and 20 girls. Plugging these values into the formula, we get C(26, 6) = 26! / (6!(26-6)!) = 230,230. Therefore, there are 230,230 different combinations of 6 boys and 20 girls that can exist among the 26 children born in the hospital on that given day.

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Answer:

b. (4,2)

Step-by-step explanation:

step one: isolate x in the first equation

substitute x=6-y: \(\begin{bmatrix}2\left(6-y\right)-2y=4\end{bmatrix}\)

\(\begin{bmatrix}12-4y=4\end{bmatrix}\)

\(-4y=-8\)

\(y=2\)

step two: isolate y in the second equation, substitute y=2

\(x=6-y\)

\(x=6-2\)

\(x=4\)

Answer:

b

Step-by-step explanation:

Given the 2 equations

3x + 3y = 18 → (2)

2x - 2y = 4 → (2)

Multiplying (1) by 2 and (2) by 3 and adding the result will eliminate the y- term

6x + 6y = 36 → (3)

6x - 6y = 12 → (4)

Add (3) and (4) term by term to eliminate y

12x + 0 = 48

12x = 48 ( divide both sides by 12 )

x = 4

Substitute x = 4 into either of the 2 equations and solve for y

Substituting into (1)

3(4) + 3y = 18

12 + 3y = 18 ( subtract 12 from both sides )

3y = 6 ( divide both sides by 3 )

y = 2

solution is (4, 2 ) → b

Answer: 45 liters

Step-by-step explanation:

If Roger jars 15 liters of jam in 2 days, we can divide to see how much liters of jam Roger can jar in 1 day. We can divide 15 by 2 to find how much jam can be jarred in one day.

15 / 2 = 7.5.

Roger can jar 7.5 liters of jam every day.

Now we can multiply 7.5 by 6 to find how much jam Roger can jar at the end of 6 days.

7.5 x 6 = 45.

Therefore, Roger can jar 45 liters of jam in 6 days.

Answer:

Step-by-step explanation:

Selling price (SP) = Rs. 252

Profit% = 5%

\(CP=\frac{100}{100+profit}*SP\\\\\ = \frac{100}{105}*252\\\\\)

CP = Rs. 240

Profit = 252 - 240 = Rs. 12

Answer:

79.56

Step-by-step explanation:

Separate the box into two then add the area and then multiply the price with the combined areas.

Answer:

She will pay $71.4 [The thing is that one dimension is not shown, so the number I did put is all of the shown dimensions.

Step-by-step explanation:

How I did it: 8.5(3.6)+ 8.5(3)+ 8.5(1.2)+8.5(0.6)

Answer:

x = 116

Explanation:

We can name the angles as follows:

So, taking into account the figure, the sum of angle A and the angle with measure 26 is equal to 90. Then, the value of angle A is:

A + 26 = 90

A + 26 - 26 = 90 - 26

A = 64

Then, angles A and B are part of an isosceles triangle. So, the measure of them is the same:

B = A

B = 64

Finally, the sum of angles B and x is 180 degrees because they form a straight line. So, the value of x is:

B + x = 180

64 + x = 180

64 + x - 64 = 180 - 64

x = 116

Therefore, the answer is x = 116

Answer: 628

Step-by-step explanation:

2πr^2+2πrh

2(3.14)(5)^2+2(3.14)(5)(15)

2(3.14)(25)+2(3.14)(75)

2(78.5)+2(235.5)

157+471

628

The magnitude of vector A of the following components AX and AY is 88.95m

In this question we will apply the pythagoras theorem which will be depicted as

\(R = \sqrt{AX^{2} + AY^{2} }\) . . . . . . . . . (1)

where , R = resultant magnitude of vector

            AX and AY are the components of vector

As per the question

AX = 83m

AY = 32m

Putting the values in the equation (1) we get

                               \(R= \sqrt{83^{2} +32^{2} }\)

                               \(R =\sqrt{6889+1024}\)

                               \(R=\sqrt{7913}\\\)

                               R  =  88.95m

Thus the magnitude of vector A for the following components is 88.95m

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Answer:

1. DC

2. BC

3. EA

4. ABC

5. BAC, DCA, DAC (i think any of these options work)

6. BAD

7. CDA, ABC

8. 360

Step-by-step explanation:

Answer:

0.46428571428

Step-by-step explanation:

Answer:

Step-by-step explanation:

3/8 + 1/8 = 4/8 = 1/2 = 0.5

1/2 - 2/7 = 3/14 = 0.214285714286

3/14 + 1/4 = 13/28 = 0.464285714286

Hope this helps! <3

Given information: Expected sales revenue = $57756Target labour cost percentage = 18%To find: How much money can you spend on labour that day? Solution: Let's assume the amount that can be spent on labour is x. According to the question, Target labour cost percentage is 18%.

Therefore, the amount that will be spent on labour cost = 18% of expected sales revenue. So, we can write it as:

x = 18% of expected sales revenue orx

= (18/100) × 57756Simplify it

,x = 10396.08 (rounded to two decimal places)Thus, the amount that can be spent on labour that day is $10,396.08.

Shawna and Beatrice, by virtue of their status as the offerees, had the option of accepting or rejecting the offer. The acceptance must meet the requirements of a valid contract.

The acceptance must be communicated clearly and immediately. In addition, the acceptance must conform to the offer's terms. In Hyde v Wrench (1840), the court held that an acceptance must be unconditional and absolute and that if the acceptance is not in line with the terms of the offer, it is a counteroffer that terminates the original offer. Since Shawna and Beatrice had not yet responded to the offer, there was no acceptance of the contract. Therefore, there was no legal agreement between the parties as a contract must have both an offer and an acceptance in order to be considered valid.

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Working together, they can complete the task in 4 hours and 48 minutes.

A certain amount of time (T) is taken to complete a certain work (W). The number of units of work done per unit time is called the rate of work (R). Hence, Work (W) = Rate (R) Time (T) Whenever some work is done, the total work itself can be taken as one unit.

Tracy needs 8 hours to complete the task.

Then we can find the ratio of work over time as:

1 task/8 hours = 1/8 task per hour.

This means that she can complete 1/8 of the task per hour.

Dave needs 12 hours to complete the task, then his ratio is:

1 task/12 hours = 1/12 task per hour.

This means that he can complete 1/12 of the task in one hour.

If they work together, then the ratios can be added:

R = \(\frac{1}{8}\) +  \(\frac{1}{12}\)

  = \(\frac{3+2}{24}\)

  = \(\frac{5}{24}\)

So, working together, in one hour they can complete  \(\frac{5}{24}\) of the task, now we can find the number of hours needed to complete the task as:

\(\frac{5}{24}\)×\(x\)= 1 task

x = \(\frac{24}{5}\) hours = 4.8 hours

knowing that an hour is 60 minutes, then 0.8 of an hour is 60*0.8 = 48 minutes.

Then x = 4 hours and 48 minutes.

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The firm's production function can be divided into two ranges: when 0 ≤ Z ≤ 5 and when 5 < Z.

(a) In the range of 0 ≤ Z ≤ 5, the production function exhibits constant returns to scale (CRS) because doubling the input, L, leads to a proportional increase in output. The output is given by f(L) = max{0, 2L - 2}.

In the range of 5 < Z, the production function exhibits decreasing returns to scale (DRS) because doubling the input, L, results in less than a proportional increase in output. The output is given by f(L) = min{2L^2, 8}.

(b) To derive the cost function, we need to find the minimum cost of producing a given level of output, denoted as C(Y).

When 0 ≤ Z ≤ 5, the cost function is C(Y) = wL, where w represents the wage rate.

When 5 < Z, the cost function is C(Y) = wL + FC, where FC is the fixed cost associated with the production technology in this range.

(c) The supply function represents the quantity of output that the firm is willing to produce at a given price level. In this case, the supply function can be derived by comparing the marginal cost of production with the given price.

When 0 ≤ Z ≤ 5, the supply function is given by:

Y = min{f(L) | wL ≤ P}

When 5 < Z, the supply function is given by:

Y = min{f(L) | wL + FC ≤ P}

In both cases, the firm will choose the level of output that minimizes its cost of production while satisfying the price constraint.

It's important to note that the above explanations are based on the information provided in the question. If there are any errors or missing details, it may affect the accuracy of the response.

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Answer:

\(a_{n}\) = 3n + 4

Step-by-step explanation:

there is a common difference between consecutive terms , that is

10 - 7 = 13 - 10 = 16 - 13 = 3

this indicates the sequence is arithmetic with nth term

\(a_{n}\) = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

here a₁ = 7 and d = 3 , then

\(a_{n}\) = 7 + 3(n - 1) = 7 + 3n - 3 = 3n + 4

Answer:

The nth term = 3n + 4.

Step-by-step explanation:

The formula for the nth term of an arithmetic progression is a(n) = dn + a(1) - d.

So this breaks down simply to,

a(n) = dn + a(1) - d a(n) = 3n + 7 - 3 a(n) = 3n + 4

the criteria used when deciding upon the inclusion of a variable are A - Theory, B - t-statistic, C - Bias, and D - Adjusted R^2.

When deciding upon the inclusion of a variable, the following criteria are commonly used:

A - Theory: Theoretical justification is often considered to include a variable in a model. It involves assessing whether the variable is relevant and aligns with the underlying theory or conceptual framework.

B - t-statistic: The t-statistic is used to determine the statistical significance of a variable. A variable with a significant t-statistic suggests that it has a meaningful relationship with the dependent variable and may be included in the model.

C - Bias: Bias refers to the presence of systematic errors in the estimation of model parameters. It is important to consider the potential bias introduced by including or excluding a variable and assess whether it aligns with the research objectives.

D - Adjusted R^2: Adjusted R^2 is a measure of the goodness of fit of a regression model. It considers the trade-off between the number of variables included and the overall fit of the model. Adjusted R^2 helps in assessing whether the inclusion of a variable improves the model's explanatory power.

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The measure of arcSTU is 210 degrees

For the first question, we will use the theorem that states that the angle at the center of a circle is twice the angle at the circumference

Given the following

m<STU = 105 degrees

Substitute to have:

105 = 1/2 arcSTU

arcSTU = 2(105)

arcSTU = 210 degrees

Hence the measure of arcSTU is 210 degrees

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Answer:

m∠D = 49°
m∠E = 41°
m∠F = 90°

Step-by-step explanation:

        We know a triangle's angles add up to 180, so we can create an equation and solve for x. We also know the little box represents 90 degrees.

Given:

        90° + 5x° + 14° + 3x° + 20° = 180°

Combine like terms:

        8x° + 124° = 180°

Subtract 124 from both sides of the equation:

        8x° = 56°

Divide both sides of the equation by 8:

        x = 7

        Now, we will plug this value of x back into the angles to solve. Again, the little box represents that Angle F is equal to 90 degrees.

m∠D = 5x° + 14° = 5(7)° + 14° = 49°
m∠E = 3x° + 20° = 3(7)° + 20° = 41°
m∠F = 90°

The z-score is greater than 2 (the cutoff for a usual event at the 95% confidence level)

The answer is "Yes" because the z-score is 2.98, which is not a usual value since it lies outside the range of usual events, namely outside 2 standard deviations of the mean of the sample means.

To calculate the z-score, we use the formula:

z = (x - μ) / (σ / √(n))

where x is the sample mean, μ is the population mean, σ is the population standard deviation, and n is the sample size.

Plugging in the given values, we get:

z = (562 - 518) / (118 / √(60)) = 2.98

Since the z-score is greater than 2 (the cutoff for a usual event at the 95% confidence level), we can conclude that the high school's claim is justified.

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Answer:

7B

Step-by-step explanation:

Thats what the graph shows... lol.

Answer:

B.

Step-by-step explanation:

x^4

please mark brainliest

\((x)(x)(x)(x)\\\\=x^{1+1+1+1} ~~~ ;[x^a \cdot x^b = x^{a+b}]\\\\=x^4\)

Given the graph of the hyperbola:

The general equation of the given hyperbola is:

Where (h, k) is the center of the hyperbola

So, by comparing the equations:

Center = (h, k) = (-5, -2)

The hyperbola opens up and down

Since a =

The coordinates of the vertices are: (h, k + a ) and (h, k - a)

h = -5, k = -2, a = 6

So, the coordinates are:

The slopes of the asymptotes are:

The equation of the asymptotes are: