Answer:
83.33s
Explanation:
velocity=300km/hr ,acceleration =1m/s2
But before we can make this calculation,we have to make sure that both the acceleration and velocity are in the same units.So I decided to Chang the velocity to m/s.
Converting 300km/hr into m/s;
Changing 300km into m=300000m
Changing 1hr into secs=3600sec
Velocity in m/s=83.33m/s
But Time =velocity/acceleration
=83.33/1
=83.33sec
You have to decide what you want. Your question says "Find the average velocity", but the choices you listed are all times, not velocities.
(300 km/hr) x (1 hr / 3600 sec) = 83.33 meters/sec
-- If the airplane starts from rest and accelerates uniformly at 1 m/s², it'll take 83.33 seconds to reach takeoff speed.
-- If it starts from rest and accelerates uniformly to 83.33 m/s, then its average speed is 41.67 m/s no matter what its acceleration may be.
A neon sign transformer has a 490W AC output with an rms voltage of 17kV
when connected to a normal household outlet. There are 500 turns of wire in the primary coil.
(A) When the transformer is running at full power, what is the current in the secondary coil?
(B) What is the current in the primary coil?
(A) To determine the current in the secondary coil, we need to use the equation P = IV, where P is the power (490W), I is current, and V is the voltage (17kV). Solving for I, we get:
I = P/V = 490W/17kV = 0.029A
Therefore, the current in the secondary coil is 0.029A.
(B) To find the current in the primary coil, we can use the equation V = NΔΦ/Δt, where V is the voltage (120V for a normal household outlet), N is the number of turns in the primary coil (500), ΔΦ is the change in magnetic flux, and Δt is the time. We can assume that the frequency of the AC output is 60Hz, so Δt = 1/60s.
Since the transformer is running at full power, we can assume that the magnetic flux is constant and therefore ΔΦ = 0.
Thus, we can simplify the equation to V = NΔΦ/Δt = 500 x 0/ (1/60) = 0.
This means that there is no current flowing in the primary coil, as the transformer is not drawing any power from the household outlet.
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when the wolfe creek object hit it released so much energy that it set off an explosion the equivalent of a nuclear blast. everything that was in the crater either or was hurled out into the surrounding countryside
The Wolfe Creek object is believed to be a meteorite that impacted the Earth in the remote Wolfe Creek Crater in Western Australia. When the object hit, it released a tremendous amount of energy, causing an explosion equivalent to a nuclear blast.
This explosion was powerful enough to hurl everything within the crater out into the surrounding countryside.
To understand why the impact released so much energy, we can look at the physics involved.
When a fast-moving object like a meteorite collides with the Earth's atmosphere, it experiences a tremendous amount of friction and compression.
This causes the object to heat up and eventually explode upon impact.
The energy released during the explosion is equivalent to a nuclear blast because both involve the rapid release of a massive amount of energy.
In the case of a nuclear blast, this energy is released through a nuclear reaction.
In the case of the Wolfe Creek object impact, the energy is released through the explosive force of the impact itself.
The impact created a crater, which is a bowl-shaped depression in the ground.
The explosion was so powerful that it launched debris from within the crater outward, scattering it across the surrounding countryside.
This is similar to what happens during a volcanic eruption, where material from within the volcano is expelled and distributed over the surrounding area.
The Wolfe Creek object impact released a tremendous amount of energy, causing an explosion equivalent to a nuclear blast.
The force of the explosion hurled everything within the crater out into the surrounding countryside.
This event highlights the immense power and destructive potential of large impacts from space objects.
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On February 20, 1962, John Glenn became the first American to orbit Earth.
If John Glenn weighed 640 N on Earth's surface,
a) how much would he
have weighed if his Mercury spacecraft had (hypothetically) remained
at twice the distance from the center of Earth?
b) Why is it said that an
astronaut is never truly "weightless?"
a. John Glenn would have weighed 160 N if his Mercury spacecraft had (hypothetically) remained at twice the distance from the center of Earth
b. An astronaut is never truly weightless because the earth still exerts a gravitational pull on the astronaut since the spaceships are not at an infinite distance from the earth who in space is actually experiencing free fall due to gravity.
From Newton's law of Universal gravitation:
F = Gm₁m₂/d²Where F is the gravitational force acting on two objects of masses m₁ and m₂ respectively.d is the distance of separation between the two objects.G is the Universal gravitational constantFrom the question, the distance between the spacecraft and the center of the earth is twice the distance on the earth's surface.
All other values remained constant, therefore, only the change in distance will affect the force.
Weight or force of gravity on John on the earth's surface is given as:
F = 640 NThe equation for calculating the new force or weight, Fₓ will simply be;
Fₓ = F/d²since d = 2
Fₓ = 640 / 2²
Fₓ = 160 N
Therefore, John Glenn would have weighed 160 N if his Mercury spacecraft had (hypothetically) remained at twice the distance from the center of Earth.
b. The spacecraft carrying astronauts orbit the earth at very high speeds. So astronauts even though experiencing free fall due to the gravitational force of the earth, never really fall onto the earth's surface.
An astronaut is never truly weightless because the earth still exerts a gravitational pull on the astronaut since the spaceships are not at an infinite distance from the earth who in space are actually experiencing free fall due to gravity.
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In terms of net charge, how does an electrically polarized object differ from an electrically charged object?.
Answer:
An electrically polarized object can have zero net charge, while a charged object cannot have zero net charge.
I hope this helps :D
what safety measures would you suggest to protect from harmful waves
Answer:
If you're talking about the sun than:
Time, Distance and Shielding Time, distance, and shielding actions minimize your exposure to radiation in much the same way as they would to protect you against overexposure to the sun:
If you're talking about the ocean than:
Water safety precautions for teens and young adults:
Never go into the water if you can’t swim.
If you can’t swim, learn. Any age can receive swimming lessons.
Always wear a life jacket while boating or taking part in boating activities such as tubing or skiing.
Never swim alone or in an unsupervised area.
Know your swimming strength.
Don’t rough house around water. Never push, jump on or hang on to others in or around water.
Never drink alcohol while taking part in water or boating activities. Alcohol affects your motor skills therefore making it harder to swim, float, keep balance or drive.
Explanation:
A 500 lines per mmmm diffraction grating is illuminated by light of wavelength 580 nmnm . For the steps and strategies involved in solving a similar problem, you may view a Video Tutor Solution.
These steps should guide you through solving a problem involving a diffraction grating, such as calculating the angle of diffraction for a given order and wavelength. Remember to pay attention to the units and use appropriate formulas for the specific situation.
To solve a similar problem involving a diffraction grating, you can follow these steps:
1. Understand the given information:
- Determine the number of lines per unit length (lines/mm) of the diffraction grating.
- Identify the wavelength of light incident on the grating.
2. Convert units, if necessary:
- If the lines per unit length are given in lines/mm, convert it to lines/m by dividing by 1000.
3. Calculate the spacing between adjacent lines of the grating:
- The spacing (d) between adjacent lines of the grating is the reciprocal of the number of lines per unit length.
d = 1 / (lines/m)
4. Determine the order of the diffraction:
- The order of the diffraction refers to the constructive interference pattern produced by the grating. The order can be identified as an integer (m = 0, 1, 2, ...) based on the specific problem.
5. Apply the formula for the angular position of the diffracted light:
- The formula is given by: sin(theta) = m * lambda / d
where theta is the angle of diffraction, m is the order of diffraction, lambda is the wavelength of light, and d is the spacing between adjacent lines of the grating.
6. Calculate the angle of diffraction:
- Plug in the known values of m, lambda, and d into the formula and solve for theta.
7. Optional: Convert the angle of diffraction to degrees, if necessary.
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A coordinate system (in meters) is constructed on the surface of a pool table, and three objects are placed on the table as follows: a m1=1.7−kg object at the origin of the coordinate system, a m2=3.2−kg object at (0,2.0), and a m3=5.1−kg object at (4.0,0). Find the resultant gravitational force exerted by the other two objects on the object at the origin. magnitude N direction - above the +x-axis
The resultant gravitational force exerted by the other two objects on the object at the origin is `2.60 x 10^-10 N` and the direction is above the +x-axis.
In a coordinate system that is constructed on the surface of a pool table with objects m1, m2 and m3 placed on it, the resultant gravitational force exerted by the other two objects on the object at the origin can be calculated using the following steps:
Step 1: Determine the distance between objects m1 and m2 using the Pythagorean theorem. The distance is given by `sqrt(2^2 + 0^2) = 2 meters`.Step 2: Determine the distance between objects m1 and m3 using the distance formula. The distance is given by `sqrt((4 - 0)^2 + (0 - 0)^2) = 4 meters`.
Step 3: Calculate the magnitude of the force exerted by object m2 on object m1. This is given by `F = G(m1)(m2)/(r^2) = 6.67 x 10^-11 (1.7)(3.2)/(2^2) = 2.29 x 10^-10 N`.
Step 4: Calculate the magnitude of the force exerted by object m3 on object m1. This is given by `F = G(m1)(m3)/(r^2) = 6.67 x 10^-11 (1.7)(5.1)/(4^2) = 1.25 x 10^-10 N`.
Step 5: Calculate the magnitude of the resultant force exerted by the other two objects on the object at the origin. This is given by `F = sqrt(F2^2 + F3^2) = sqrt((2.29 x 10^-10)^2 + (1.25 x 10^-10)^2) = 2.60 x 10^-10 N`.
Step 6: Determine the direction of the resultant force. Since the force exerted by object m3 is along the x-axis and the force exerted by object m2 is along the y-axis, the direction of the resultant force is above the +x-axis.Given the above information, the resultant gravitational force exerted by the other two objects on the object at the origin is `2.60 x 10^-10 N` and the direction is above the +x-axis.
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A friend advised the owner of the bowl to keep it out of direct sunlight to avoid blinding the fish, which might swim into the focal point of the parallel rays from the sun. Is the focal point actually within the bowl
The focal point of parallel rays from the sun is actually outside the bowl.
When parallel rays pass through a convex lens like a fishbowl, they converge at a point called the focal point.
In this case, the friend advised the owner to keep the bowl out of direct sunlight to avoid blinding the fish because the focused rays of sunlight could potentially harm the fish's eyes.
However, it's important to note that the focal point is not within the bowl itself. So, while the fish might be at risk if exposed to direct sunlight, the actual focal point where the rays converge is outside the bowl.
In conclusion, the focal point of parallel rays from the sun is outside the fishbowl, not within it. This means that the fish's eyes are not at risk from the focused rays of sunlight inside the bowl.
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What are the forces applied?
The forces applied on the bucket are tension and gravitational.
What is the gravitational force?
According to Newton’s gravitational law, it is the force exerted due to attraction between two objects that is directly proportional to the product of their masses and is inversely proportional to the square of distance between them.
The force applied to the bucket containing water is gravitational force. The gravitational force acts in downward direction and there is no change in the state of motion. There is another force as well which is the muscular force by which we hold the bucket in the upward direction with the help of our muscles. Tension is also exerted on the bucket as this force is seen in existence when any object is being pulled up with the help of string or rope. It is always seen in the direction which is parallel to the rope.
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An object is placed 10 cm in front of a concave lens. If the image formed at a distance of 5 cm from concave lens, calculate the focal length of the lens?
Answer:
I would be 5 centimeters I think
pluto's moon charon orbits pluto every 6.4 days with a semimajor axis of 19,700 kilometers. calculate the combined mass of pluto and charon.
compared to mean distance. To be before 551 plus 8 97.5, or 5448.5 million, would be necessary. The total mass of Pluto & Charon is 1.5 x 1022 kilograms (Mpluto+MCharon).
What does a planet's semimajor axis mean?A semimajor axis (the average distance to the Sun) is expressed in units of a astronomical unit (AU), which is the average distance of the Earth to the Sun. For instance, Neptune is typically 30 times closer to the Sun than that of the Earth.
What stands for the semimajor axis?One can also state that cube of a planet's mean distance is equivalent to a square of its measure of distance period because a planet's semi-major axis is equal to its mean distance.
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Find the field strength. Information given
Weight: 0, point, 96, N,0. 96N
Mass: 3, point, 3, g,3. 3g
Field strength is 0.03234 N/kg. The formula to determine the field strength is given by:
F = mg Here, F is the field strength, m is the mass, and g is the gravitational field strength.
Substituting the values given: Weight = 0.96 N Mass = 3.3 g = 0.0033 kg = 9.8 m/s² Therefore, F = mg = 0.0033 kg × 9.8 m/s² = 0.03234 N the field strength is the gravitational force acting on a unit mass. It is measured in newtons per kilogram. The field strength is an expression of the strength of a gravitational field. In this case, the mass of the object is 3.3 g, which can be converted to kilograms by dividing by 1000.
The weight of the object is given as 0.96 N. Using the formula
F=mg, where m is the mass and g is the gravitational field strength, we can calculate the field strength as 0.03234 N/kg.
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How can the density of an object be determined?”
Answer:
First you need to know the mass (grams) of the object and its volume, then what you do is Divide the mass by the volume in order to get an object's Density.
Explanation:
hope that helped good luck :)
Answer:
m/p, aka mass/volume.
Explanation:
for example if you had an object that had a mass of 10 and volume of 5, the density of that object would be 10/5, or 2.
p
4. Which of the following statements is not accurate regarding identifying factors on the health pyramid?
All three sides of the health triangle affect each other.
Personal actions are categorized on the health pyramid by the intended purpose of the initial actions.
Physical health is the base of the triangle and is the most important part of the health triangle.
Working out a gym would be categorized in the physical health category.
Pyramid collision, recommendations are made specifically for each person depending on their age, gender, and amount of physical activity. The consumption of cereals, milk, veggies, fruit, and oils are the main.
A health impact pyramid: what is it?
The Health Benefit Pyramid is a diagram that shows the many levels of impact that can come from interventions in public health. Attempts to deal with the social determinants that potentially affect your health are at the bottom of the pyramid, suggesting interventions with the highest potential impact. Housing, financial stability, public safety, jobs, education, and the environment are a few examples of these. The broader determinants of health are these.
What are the four primary categories of factors that affect health?
Numerous variables affect health, including These circumstances are referred to as social determinants, which are the socioeconomic factors that influence life expectancy and quality of life and support health. Examples of these factors include accommodation, education, access to food, and transportation. Too frequently, people lack control over their ability to access these resources that influence their health.
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Find a real root of the equation f(x)=x^2-2x-5=0, using bisection method in five stages.
A real root of the equation f(x) = x^2 - 2x - 5 = 0, found using the bisection method in five stages, is approximately x = -0.046875. To find a real root of the equation f(x) = x^2 - 2x - 5 = 0 using the bisection method, we can start by identifying an interval [a, b] that contains the root. Let's choose the interval [-3, 0], where f(a) = f(-3) = 4 and f(b) = f(0) = -5. Since f(a) and f(b) have opposite signs, there must be a root within this interval.
Stage 1:
- Start with interval [a, b] = [-3, 0]
- Calculate the midpoint c = (a + b) / 2 = (-3 + 0) / 2 = -1.5
- Evaluate f(c) = (-1.5)^2 - 2(-1.5) - 5 = -0.25
- Since f(c) has the same sign as f(a), replace a with c: [a, b] = [-1.5, 0]
Stage 2:
- Calculate the new midpoint c = (a + b) / 2 = (-1.5 + 0) / 2 = -0.75
- Evaluate f(c) = (-0.75)^2 - 2(-0.75) - 5 = -4.4375
- Since f(c) has the same sign as f(a), replace a with c: [a, b] = [-0.75, 0]
Stage 3:
- Calculate the new midpoint c = (a + b) / 2 = (-0.75 + 0) / 2 = -0.375
- Evaluate f(c) = (-0.375)^2 - 2(-0.375) - 5 = -2.7461
- Since f(c) has the same sign as f(a), replace a with c: [a, b] = [-0.375, 0]
Stage 4:
- Calculate the new midpoint c = (a + b) / 2 = (-0.375 + 0) / 2 = -0.1875
- Evaluate f(c) = (-0.1875)^2 - 2(-0.1875) - 5 = -1.2217
- Since f(c) has the same sign as f(a), replace a with c: [a, b] = [-0.1875, 0]
Stage 5:
- Calculate the new midpoint c = (a + b) / 2 = (-0.1875 + 0) / 2 = -0.09375
- Evaluate f(c) = (-0.09375)^2 - 2(-0.09375) - 5 = -0.6104
- Since f(c) has the same sign as f(a), replace a with c: [a, b] = [-0.09375, 0]
After five stages, the interval [a, b] has become [-0.09375, 0]. Since the interval is small, we can approximate the root as the midpoint of this interval:
Root ≈ (a + b) / 2 = (-0.09375 + 0) / 2 = -0.046875
Therefore, a real root of the equation f(x) = x^2 - 2x - 5 = 0, found using the bisection method in five stages, is approximately x = -0.046875.
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Volcanic Island Arcs, such as Japan, form when a(n) __________ plate is subducted below a(n) _________________ and takes seawater with it. A rock and water mixture will break through the crust.
Volcanic Island arcs form when an oceanic tectonic plate is subducted below a tectonic plate taking seawater with it.
Volcanic island arcs occur offshore during volcanoes. They occur due to the subduction of an oceanic plate under another tectonic plate. Volcanic Island arcs occur mostly in ocean basins.
Due to the subduction of oceanic plates under tectonic plates, Island Arcs are found, mostly along the margins of continent.
Hence we can conclude that Volcanic Island arcs Form when an oceanic tectonic plate is subducted below a tectonic plate taking seawater with it.
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Which equation can you use to calculate the mechanical advantage of a simple machine?
MA = delta x1 / delta x0
MA = delta xi - delta x0
MA = delta xi * delta x0
MA = delta x0 / delta x1
The equation that can be used to calculate the mechanical advantage of a simple machine is as follows: MA = delta x0 / delta x1 (option D).
How to calculate mechanical advantage?Mechanical advantage is the ratio of the output force produced by a machine (especially a simple machine) to the applied input force.
The mechanical advantage (MA) is used to analyze the forces in simple machines like levers and pulleys.
Mechanical advantage = Fo/Fi
Where;
Fo = output forceFi = input forceAccording to this question, option D best describes the equation that can be used to calculate the mechanical advantage of a simple machine.
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Waves from separate sea areas move away as swell and produce an interference pattern when they come together. If Sea A has wave heights of 2.5 meters and Sea B has wave heights of 3.5 meters, what would be the height of waves resulting from constructive interference
The height of the waves resulting from constructive interference would be 6 meters.
When waves from separate sea areas come together and produce an interference pattern, the resulting wave height depends on the type of interference that occurs.
In constructive interference, the wave crests from the two sources align, resulting in an amplified wave height. To calculate the height of the waves resulting from constructive interference, the individual wave heights together.
Given:
Wave height of Sea A (h_A) = 2.5 meters
Wave height of Sea B (h_B) = 3.5 meters
Height of waves resulting from constructive interference (h_resultant) = h_A + h_B
h_resultant = 2.5 meters + 3.5 meters
= 6 meters
Therefore, the height of the waves resulting from constructive interference would be 6 meters.
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A playground ride consists of a disk of mass M = 50 kg and radius R = 2.4 m mounted on a low-friction axle. A child of mass m = 16 kg runs at speed v = 2.8 m/s on a line tangential to the disk and jumps onto the outer edge of the disk. ANGULAR MOMENTUM (a) Consider the system consisting of the child and the disk, but not including the axle. Which of the following statements are true, from just before to just after the collision? The axle exerts a force on the system but nearly zero torque. The torque exerted by the axle is nearly zero even though the force is large, because || is nearly zero. The angular momentum of the system about the axle changes. The momentum of the system doesn't change. The momentum of the system changes. The angular momentum of the system about the axle hardly changes. The torque exerted by the axle is zero because the force exerted by the axle is very small. (b) Relative to the axle, what was the magnitude of the angular momentum of the child before the collision? |C| = kg·m2/s (c) Relative to the axle, what was the angular momentum of the system of child plus disk just after the collision? |C| = kg·m2/s (d) If the disk was initially at rest, now how fast is it rotating? That is, what is its angular speed? (The moment of inertia of a uniform disk is ½MR2.) = radians/s (e) How long does it take for the disk to go around once? Time to go around once = s ENERGY (f) If you were to do a lot of algebra to calculate the kinetic energies before and after the collision, you would find that the total kinetic energy just after the collision is less than the total kinetic energy just before the collision. Where has most of this energy gone? Increased translational kinetic energy of the disk. Increased thermal energy of the disk and child. Increased chemical energy in the child.
When the child jumps on the disk, the system's precise energy changes, torque and constrain applied by the pivot are true. The overall active vitality diminishes.
How does angular momentum apply when the child jumps on the disk?(a) The following statements are true:
The pivot applies a constraint on the framework but about zero torque. The pivot gives a constraint to back the child and the disk, but it applies insignificant torque since the drive is connected at the center of mass of the disk, coming about in a zero lever arm.The precise energy of the framework almost the pivot changes. Sometimes recently the collision, the child's precise force is zero, but after the collision, the child exchanges precise energy to the disk, causing the system's precise force to alter.These other statements are untrue:
The torque applied by the hub isn't about zero, as the pivot applies a constraint on the framework.The force of the framework changes since the child's energy is exchanged to the disk upon collision.The precise force of the framework around the pivot barely changes; it really changes as clarified prior.The torque applied by the pivot isn't zero; it is fair moderately little compared to the torque applied by the child on the disk.(b) The greatness of the precise energy of the child some time recently the collision relative to the pivot is given by |C| = mvr, where m is the mass of the child, v is the speed of the child, and r is the radius of the disk. Stopping within the values, |C| = (16 kg) × (2.8 m/s) × (2.4 m) = 107.52 kg·m²/s.
(c) Fair after the collision, the precise force of the framework of the child also disk relative to the pivot is moderated and remains the same as sometime recently the collision. In this manner, the precise force is still |C| = 107.52 kg·m²/s.
(d) On the off chance that the disk was at first at rest, its introductory precise speed is zero. After the collision, precise force is preserved. Utilizing the equation for precise force (L = Iω) and the given moment of inactivity for a uniform disk (I = 1/2MR²), able to fathom the precise speed (ω):
107.52 kg·m²/s = (1/2)(50 kg)(2.4 m)² × ω
Understanding ω gives ω ≈ 0.893 radians/s.
(e) The time taken for the disk to create one total turn (go around once) is given by T = 2π/ω. Stopping within the esteem for ω, we have T = 2π/0.893 ≈ 7.03 seconds.
(f) The statement is deficient, and without assist data, it isn't enough to decide where most of the vitality has gone. The whole vitality of the framework may alter due to different components such as contact, dissipative powers, or the transformation of vitality into other shapes.
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When an object is placed a little farther from a concave mirror than the focal length, the image is A. magnified and real. B. magnified and virtual. C. smaller and real. D. smaller and virtual. E. smaller and reversed.
When an object is placed a little farther from a concave mirror than the focal length, the image is magnified and virtual. The correct option is B, magnified and virtual.
When an object is placed at a distance greater than the focal length of a concave mirror, the image formed is real, inverted, and smaller in size than the object.
However, when the object is placed slightly farther from the concave mirror than the focal length, the image formed is virtual, magnified and upright.
The image is virtual because the reflected light rays appear to diverge from a point behind the mirror, and magnified because the image is formed by the intersection of the diverging reflected rays.
This type of image is often used in devices such as magnifying glasses and shaving mirrors.
Therefore, the correct option is B. when an object is placed a little farther from a concave mirror than the focal length, the image is magnified and virtual.
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The pitch of a sound is determined primarily by its A. frequency.
B. duration.
C. speed.
D. amplitude.
The pitch of a sound is determined primarily by its a. frequency
Pitch refers to how high or low we perceive a sound to be, and it is directly related to the frequency of the sound wave. Frequency is measured in Hertz (Hz) and represents the number of cycles a sound wave completes in one second and a higher frequency corresponds to a higher pitch, while a lower frequency results in a lower pitch.
Duration (Option B) refers to the length of time a sound lasts, and it does not directly impact the pitch and speed (Option C) is the rate at which sound waves travel through a medium, typically around 343 meters per second in air, but this also does not influence the pitch. Amplitude (Option D) refers to the maximum displacement of a sound wave from its equilibrium position, and it determines the loudness of the sound rather than its pitch. In summary, the pitch of a sound is primarily determined by its frequency, with higher frequencies resulting in higher pitches and lower frequencies resulting in lower pitches. Other factors, such as duration, speed, and amplitude, do not directly impact the pitch of a sound.
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A force of 16 lb is required to hold a spring stretched 4 inches beyond its natural length. How much work is done in stretching it from its natural length to 10 inches beyond its natural length?
The work done in stretching the spring from its natural length to 10 inches beyond its natural length is 112 lb·in.
The work done in stretching a spring is given by the formula:
\(\[ W = \frac{1}{2} k (x_f^2 - x_i^2) \]\)
In this case, the spring is stretched 4 inches beyond its natural length, so the initial displacement is 4 inches. The force required to hold the spring at this displacement is 16 lb. We can use Hooke's Law to find the spring constant:
\(\[ k = \frac{F}{x_i} = \frac{16 \, \text{lb}}{4 \, \text{in}} = 4 \, \text{lb/in} \]\)
Now, we can calculate the work done in stretching the spring to 10 inches beyond its natural length:
\(\[ W = \frac{1}{2} (4 \, \text{lb/in}) \left( (10 \, \text{in})^2 - (4 \, \text{in})^2 \right) = 112 \, \text{lb·in} \]\)
Therefore, the work done in stretching the spring is 112 lb·in.
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17. What is the gain in gravitational potential energy of a body of weight 2000 N as it rises from a height of 20 m to a height of 25 m above the earth's surface?
(A) 400 J
(B) 1 000 J
(C) 10 000 J
(D) 20 000 J
Answer:
C) 10000 J
Explanation:
∆p.e =mg∆h
= 2000 × 5
= 10000J
John and henry are both workers at a retail store. their direct supervisor has told them to maintain quick service above all else. later, their customer relations director tells them that they should always work to maintain excellent customer service above all else. both john and henry are confused as to what their priorities should be. this is an example of a conflict based on ______. a. personality differences b. power struggle c. poor communication d. jealousy please select the best answer from the choices provided a b c d
Poor communication
This is an example of a conflict based on poor communication. Because of the reason is that in customer service a person should have skills to communicate in a good manner. It is important because if the person has this skill that he can communicate with others best.
Then he can impress the customer and realize customer about the qualities of their product. In every kind of business, communication skills play major role. Therefore, both john and Henry are confused as their priorities should be on focus to improve their communication skills.
What is poor communication ?When there is a disconnect between what is said and what is heard, poor communication frequently results. In other words, the individual to whom the communication is being directed misinterprets what you are trying to convey. There is no longer mutual understanding.
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juanda una vuelta en bicicleta a una pista circular de 10m de radio
¿cuanto vale el desplasamiento=
Answer:
I don't understand
Explanation:
An apple is thrown across the cafeteria with a force of 10 N and at an acceleration of 6 m/s2. What is the mass of the apple? ... please answer asap
Answer:
Explanation:
F = m * a
The apple's acceleration is not influenced by the acceleration due to gravity for this question. In real life it most certainly is influenced by gravity.
F = m * a
F = 10 Newtons.
a = 6 m/s^2
m = 10/6 = 1.66 kg. Mighty large apple
two identical cylindrical vessels with their bases at the same level each contain a liquid of density 1.17 g/cm3. the area of each base is 2.94 cm2, but in one vessel the liquid height is 0.906 m and in the other it is 1.50 m. find the work done by the gravitational force in equalizing the levels when the two vessels are connected.
The work done by the gravitational force in equalizing the levels when the two vessels are connected is 0.03733 J.
The work done by the gravitational force in equalizing the levels when the two vessels are connected can be found using the formula:
Work = force x distance
where force is the weight of the liquid and distance is the difference in height between the two vessels. The weight of the liquid in each vessel can be calculated as the product of the volume and density of the liquid, and the difference in height can be found by subtracting the height of the lower vessel from the height of the higher vessel.
The weight of the liquid in each vessel can be calculated as:
Weight = density x volume x gravity
where density is 1.17 g/cm³, volume is the product of the area of the base and height of the liquid, and gravity is 9.81 m/s².
For the vessel with a liquid height of 0.906 m, the volume can be calculated as:
Volume = area of base x height of liquid = 2.94 cm² x 0.906 m = 0.00266244 m³
So, the weight of the liquid in this vessel is:
Weight = 1.17 g/cm³ x 0.00266244 m³ x 9.81 m/s² = 0.031105 N
Similarly, for the vessel with a liquid height of 1.50 m, the volume can be calculated as:
Volume = area of base x height of liquid = 2.94 cm² x 1.50 m = 0.00441 m³
So, the weight of the liquid in this vessel is:
Weight = 1.17 g/cm³ x 0.00441 m³ x 9.81 m/s² = 0.051456 N
The difference in height between the two vessels is:
Height difference = 1.50 m - 0.906 m = 0.594 m
Therefore, the work done by the gravitational force in equalizing the levels when the two vessels are connected is:
Work = force x distance = (0.051456 N + 0.031105 N) x 0.594 m = 0.03733 J
Therefore, the work done by the gravitational force in equalizing the levels when the two vessels are connected is 0.03733 J.
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7) Find F1 and F2
HELP PLEASEEE
The force F1 is equal and opposite to the downward force thus, F1 is equal to 60 N. The force F2 is inclined to 30 ° from leftward force and it is equal to 38.97 N in magnitude.
What is force?Force is an external agent acting on a body to deform it or to change its state of motion or rest. Force is a vector quantity and it is characterised by its magnitude and direction.
If two forces acting on a body from the same directions, then the net force will be the sum of these two forces. If they are acting from opposite directions, they will cancel each other in magnitude.
The force F1 is equal and opposite to the force acting downward. Thus its magnitude is 60 N. The force F2 is inclined to 30 ° from horizontal direction.
F2 = 45 cos 30 = 38.9 N.
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How do I find the average time and average velocity (m/s) for a sphere?
Radio waves of frequency 1.667 GHzGHz arrive at two telescopes that are connected by a computer to perform interferometry. One portion of the same wave front travels 1.260 mm farther than the other before the two signals are combined.
Required:
a. Will the two waves combine constructively or destructively?
b. Calculate the value of m for the path difference between the two signals
Explanation:
The frequency of radio waves is 1.667 GHz
One portion of the same wave front travels 1.260 mm farther than the other before the two signals are combined.
There are two conditions for interference either constructive or destructive.
For constructive interference , the path difference is n times of wavelength and for destructive interference, the path difference is (n+1/2) times of wavelength
We can find wavelength in this case as follows :
\(\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{1.667\times 10^9}\\\\\lambda=0.1799\ m\)
If we divide path difference by wavelength,
\(\dfrac{\delta}{\lambda} =\dfrac{1.26}{0.1799}\\\\\dfrac{\delta}{\lambda} =7\\\\\delta =7\lambda\)
It means that the path difference is 7 times of the wavelength. it means the two waves combine constructively and the value of m for the path difference between the two signals is 7.