Find the area of a circle with radius, r = 66cm. give your answer rounded to 3 sf.

Answer: c

Step-by-step explanation:

Answer:

Step-by-step explanation:

Cycles of reduction:

Material will be left:

Answer:

36 grams

Step-by-step explanation:

We have 576 grams of the mercury like substance.

Half of it's lifespan is 64 hours.

The time is 256 hours.

256 ÷ 64 = 4

Material will be left:

576 x \((1/2^{4} )\)

576 x 1/16 =  36 grams

Answer:

y = 3x

Step-by-step explanation:

Slope-intercept form of an equation is a shortcut, fill-in-the-blank form you can use to write the equation of a line.

Slope-intercept eq:

y = mx + b

You fill in slope where the m is. And you fill in the y-intercept for the b.

In your problem they gave you two points. You can calculate slope with two points. Subtract the y's, 3-0, put that on top of a fraction. And subtract x's, 1-0, put that on the bottom of the fraction. The slope, m, is 3/1, which is 3.

slope:

m = 3-0 / 1-0 = 3/1 =3

The y-intercept is actually given in your problem. The y-intercept is the point where the line crosses the y-axis. The y-intercept is the point where the x is 0. They gave you the point (0,0) that is the y-intercept. So b = 0.

Fill the m and b in with the given numbers!

y = 3x + 0 Simplify.

y = 3x

The values of the five other trigonometric functions for \(\sin \theta = -\frac{4}{11}\) in Quadrant III

\(\cos \theta = -\frac{9}{11}\)

\(\csc \theta = -\frac{11}{4}\)

\(\sec \theta = -\frac{11}{9}\)

Given that \(\sin \theta = -\frac{4}{11}\) and \(\theta\) is in Quadrant III, we can determine the values of the other trigonometric functions using the relationships between them. In Quadrant III, both sine and cosine are negative.

First, we find \(\cos \theta\) using the Pythagorean identity \(\sin^2 \theta + \cos^2 \theta = 1\):

\(\sin^2 \theta + \cos^2 \theta = \left(-\frac{4}{11}\right)^2 + \cos^2 \theta = 1\)

Simplifying the equation, we have:

\(\frac{16}{121} + \cos^2 \theta = 1\)

\(\cos^2 \theta = 1 - \frac{16}{121} = \frac{105}{121}\)

\(\cos \theta = \pm \sqrt{\frac{105}{121}}\)

Since \(\theta\) is in Quadrant III and both sine and cosine are negative, we take the negative value:

\(\cos \theta = -\sqrt{\frac{105}{121}} = -\frac{9}{11}\)

Next, we can determine \(\csc \theta\) and \(\sec \theta\) using the reciprocal relationships:

\(\csc \theta = \frac{1}{\sin \theta} = \frac{1}{-\frac{4}{11}} = -\frac{11}{4}\)

\(\sec \theta = \frac{1}{\cos \theta} = \frac{1}{-\frac{9}{11}} = -\frac{11}{9}\)

The values of the five other trigonometric functions for \(\sin \theta = -\frac{4}{11}\) in Quadrant III are:

\(\cos \theta = -\frac{9}{11}\)

\(\csc \theta = -\frac{11}{4}\)

\(\sec \theta = -\frac{11}{9}\)

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Step-by-step explanation:

Answer:

5 more than the absolute value of the cube of a number

Answer:

4 are pink

Step-by-step explanation:

We have an uneven denominator So basically we Times  2/5 by 2/2

and we get 4/10

So out of the 10, 4 are Pink.

I hope this helps!

One possible transformation is a reflection in the x-axis followed by a dilation centered at the origin with a scale factor of 3.

A dilation can be defined as a transformation that multiplies the distance between every point in an object and a fixed point, called the center of dilation, by a constant factor called the scale factor.

Before the dilation, the figure was reflected from the first quadrant to the second quadrant, which is a lateral reflection, hence the figure was reflected over the x-axis.

The height of the blue triangle is of 1 unit, while the height of the larger triangle is of 3 units, hence the scale factor is given as follows:

k = 3/1

k = 3.

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Answer:

4n+2

Step-by-step explanation:

3) To determine the time at which the fish population is zero:

We have the quadratic equation: -2x^2 + 40x - 72 = 0

Using the quadratic formula: x = (-b ± √(b^2 - 4ac)) / (2a)

Substituting the values from our equation: a = -2, b = 40, c = -72

x = (-40 ± √(40^2 - 4(-2)(-72))) / (2(-2))

Simplifying further:

x = (-40 ± √(1600 - 576)) / (-4)

x = (-40 ± √(1024)) / (-4)

x = (-40 ± 32) / (-4)

So, the solutions for x (temperature) that result in a population of zero are:

x1 = (-40 + 32) / (-4) = -8 / (-4) = 2

x2 = (-40 - 32) / (-4) = -72 / (-4) = 18

Therefore, the fish population will be zero at temperature x = 2°C and x = 18°C.

6) To determine the temperature that results in the largest population of fish (maximum point):

The x-coordinate of the vertex can be found using the formula: x = -b / (2a)

In our equation, a = -2 and b = 40:

x = -40 / (2(-2)) = -40 / (-4) = 10

So, the temperature x = 10°C will result in the largest population of fish. The y-coordinate of the vertex represents the maximum population.

1) The given function is a quadratic function.

2) Characteristics of a quadratic function include:

- It is a polynomial function of degree 2.

- The graph of a quadratic function is a parabola.

- It has a vertex, which is either a minimum or maximum point, depending on the coefficient of the leading term.

- The graph is symmetric about the vertical line passing through the vertex.

- The function can have either a positive or negative leading coefficient, which determines the concavity of the parabola.

3) To determine the time at which the fish population is zero, we need to find the value of x (temperature) that makes the function p(x) equal to zero:

-2x^2 + 40x - 72 = 0

To solve this quadratic equation, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

In this case, a = -2, b = 40, and c = -72. Plugging in these values into the quadratic formula, we can find the values of x that result in a population of zero.

4) An alternative strategy to determine when the fish population is zero is by factoring the quadratic equation if possible. However, the given quadratic equation doesn't appear to be easily factorable, so using the quadratic formula is a more suitable approach.

5) Both strategies should give the same answer. Whether using the quadratic formula or factoring, the solutions for x (temperature) that result in a population of zero should be identical. The quadratic formula is a general method that works for all quadratic equations, even when factoring is not immediately apparent.

6) To determine the temperature that results in the largest population of fish, we need to find the vertex of the quadratic function. The x-coordinate of the vertex can be found using the formula:

x = -b / (2a)

In this case, a = -2 and b = 40. Plugging in these values, we can calculate the temperature (x) at which the fish population is maximized. The y-coordinate of the vertex will represent the largest population of fish.

open bard bing AI

Yes, the test in an "if" function must evaluate to either a True or a False value.

An "if" function, also known as a conditional statement, is used to perform specific actions based on whether a certain condition is met or not. The test or condition within the "if" function needs to be evaluated as either True or False in order for the program to decide which action to execute. If the test evaluates to True, the program will perform the action within the "if" block, and if it evaluates to False, it will either execute the action in the "else" block (if present) or simply skip the "if" block.

When using an "if" function in programming, it is essential for the test or condition within the statement to result in a boolean value, which is either True or False. This is because the program needs to determine whether the condition is met or not, so it can decide which set of actions to execute. If the condition evaluates to True, the code within the "if" block will be executed, while if it evaluates to False, the code within the "else" block (if present) will be executed, or the "if" block will be skipped altogether.

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Answer:

20 \(x^{4}\) \(y^{6}\)

Step-by-step explanation:

A = \(\frac{1}{2}\) ( 5 x³ \(y^{4}\) )( 8 x y² ) = 20 \(x^{4}\) \(y^{6}\)

The function g(x)=-1/2f(x)+3 containing points (a) (0, 4) and (a) (2, 0).

The function g(x) = -1/2f(x) + 3 is obtained by applying certain transformations to the original function f(x) = 3^x - 3.

To find the points on the graph of g(x), we need to substitute the x-values from the given points into the function g(x) and determine the corresponding y-values.

Given:

Original function f(x) = 3^x - 3

Points on f(x): (0, -2) and (2, 6)

To find the points for g(x), we substitute the x-values into g(x) = -1/2f(x) + 3:

1. For the point (0, -2):

g(0) = -1/2f(0) + 3

      = -1/2(-2) + 3

      = 1 + 3

      = 4

2. For the point (2, 6):

g(2) = -1/2f(2) + 3

      = -1/2(6) + 3

      = -3 + 3

      = 0

Therefore, the points for the function g(x) = -1/2f(x) + 3 are:

(a) (0, 4)

and

(a) (2, 0)

Hence, the correct answer is:

(a) (0, 4) and (a) (2, 0).

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Answer:

with what?

Step-by-step explanation:

The intercept in a regression equation is the point where the regression line intersects with the y-axis. In the context of hurricane wind speed and central pressure, the intercept represents the predicted value of the dependent variable (wind speed) when the independent variable (central pressure) is zero.

However, this interpretation is not necessarily meaningful in this context, as it is unlikely for the central pressure of a hurricane to be exactly zero. Instead, the intercept can be interpreted as the average predicted wind speed when central pressure is at its minimum or near its minimum (i.e., the closest value to zero in the data set). It is important to note that this interpretation assumes that the relationship between wind speed and central pressure is linear, and that the range of central pressure values in the data set is sufficiently close to zero to make this interpretation meaningful. If the relationship is not linear or if the range of central pressure values is far from zero, the intercept may not have a meaningful interpretation in the context of the data.

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Answer:

Step-by-step explanation:

Let's call the number of boys "b" and the number of girls "g". From the ratio, we know that b/g = 11/9.

Also, we know that b = g + 124, so we can substitute the second equation into the first:

b/g = 11/9

b = g + 124

g + 124 / g = 11/9

Cross multiply:

9g + 1112 = 11g

Solve for g:

-2g = -1112

g = 556

So there are 556 girls and 556 + 124 = 680 boys at the school.

The total number of students at the school is 556 + 680 = 1236.

Extra people required is 50.

Each of the five workers should increase their efficiency to a rate of 15 sandwiches per 10 hour shift.

Proportions are defined as the concept where two or more ratios are set to be equal to each other.

Question 1 :

Number of associates = 30

Number of direct workers = 30 - 2 = 28

You work 8 hours a day and 5 days a week with two 15 minutes break or 30 minutes break per day.

Direct rate = 150 units per hour

Number of working hours in a week with break = 8 × 5 = 40 hours per week Number of working hours in a week = 7.5 hours per day × 5 days a week

                                                            = 37.5 hours per week

Units that department produce in a 40 hour week = 37.5 × 150 = 5625 units

28 people produce 5625 units in a week

Let x people produce 10,000 + 5625 = 15,625 units in a week

Using proportion,

28 : 5625 = x : 15,625

28 / 5625 = x / 15,625

x = (28 × 15,625) / 5625 = 77.78 ≈ 78

Extra people required = 78 - 28 = 50

Question 2 :

Number of sandwiches made in 10 minutes = 1

Number of sandwiches made in 10 hours = 60

5 workers are there. one worker makes 60/5 = 12 sandwiches

But Deli want number of sandwiches in 10 hours = 75

One worker should make 75/5 = 15 sandwiches instead of 12.

Number of sandwiches made in 8 minutes should be 1.

So the working efficiency on each worker should be increased and produce each one should produce 15 sandwiches in a 10 hour shift.

Hence extra people required in question 1 is 50 and efficiency of each worker in question 2 should be increased to 15 sandwiches in 10 hours shift.

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Answer:

1/12

Step-by-step explanation:

multiple of 3 and a multiple of 4 implies it can only be 12.

Since you only have the numbers from 1 to 12,

the prob(the 12) = 1/12

Answer:

x+8 =15

x=15-8

x=7 .

this is the answer

Answer:

3x + 8 = 15

(If you wanted to solve it then:) x = 7/3

Step-by-step explanation:

Let's convert that into an equation.

Let "x" be the number.

3x + 8 = 15

If the question was to answer it, look below:

3x + 8 = 15

3x = 7

x = 7/3

Hope this helped! If not, please let me know! <3

Answer:200

Step-by-step explanation: length plus hight

mko

Answer:

Sqrt92

9.6 or rounded to the nearest whole #, 10

Step-by-step explanation:

The value of m and b of the given equation:

m = 1

b = 7

One or two variables make up a linear equation. Neither the numerator nor the denominator of a fraction can be a variable in a linear equation raised to a power higher than 1. All of the points on a coordinate grid sit on the same line when you identify the values that together make a linear equation true and plot those values.

the linear equation = 2 + 3x + 5 - 2x = y

simplifying the equation:

   (2 + 5) + (3x - 2x) = y

       7 + x = y

Comparing this linear equation to the slope-intercept form can help you better understand how it works.

y = mx + b

Where,

m = slope of the line'

b = y-intercept

comparing the equations we get:

m = 1

b = 7

The value of m and b of the given equation:

m = 1

b = 7

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Answer:

7x^(2) - 3x + 8

Step-by-step explanation:

(9x^(2) + 8) - (2x^(2) + 3x)

distribute the "-" sign.

9x^(2) + 8 - 2x^(2) - 3x

Now combine like terms; (an "x^(2)" goes with an "x^(2)", not with an "x")

9x^(2) - 2x^(2) -3x + 8

7x^(2) - 3x + 8

Angle ABC is greater than angle C, as required. Given triangle ABC with AC greater than AB, and BD drawn such that AD is congruent to AB, we need to prove that angle ABC is greater than angle C.

To begin with, we can draw a diagram to visualize the situation. In the diagram, we see that BD is an altitude of triangle ABC, as well as a median since it divides the base AC into two equal parts. We also see that triangles ABD and ABC are congruent by the side-side-side (SSS) criterion, which means that angle ABD is equal to angle ABC.

Now, we can use this information to prove our statement. Since triangle ABD and triangle ABC are congruent, their corresponding angles are also equal. Therefore, we know that angle ABD is equal to angle ABC.

Next, we observe that angle ABD is a right angle, since BD is an altitude of triangle ABC. This means that angle ABC is the sum of angles ABD and CBD.

Since AD is congruent to AB, we also know that angles ABD and ADB are congruent. Therefore, angle CBD is greater than angle ADB.

Putting all of this together, we can conclude that angle ABC is greater than angle C, as required.

In summary, we have shown that given triangle ABC with AC greater than AB and BD drawn such that AD is congruent to AB, angle ABC is greater than angle C. This is because angles ABD and CBD add up to angle ABC, and angle CBD is greater than angle ADB.

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The probability that the chosen coin is the one with two heads, given that the coin flipped came up heads, is 2/3.

To determine the probability that the chosen coin is the one with two heads, we can use Bayes' theorem.

Let's define the events:

A = Coin chosen is the one with two heads

B = Coin flipped comes up heads

We want to find P(A|B), which represents the probability that the chosen coin is the one with two heads given that the coin flipped came up heads.

According to Bayes' theorem:

P(A|B) = (P(B|A) * P(A)) / P(B)

P(B|A) is the probability of getting heads when the chosen coin has two heads. Since all flips of this coin will result in heads, P(B|A) = 1.

P(A) is the probability of choosing the coin with two heads initially. Since there are three coins and only one of them has two heads, P(A) = 1/3.

P(B) is the probability of getting heads regardless of which coin is chosen. To calculate this, we need to consider all possible outcomes:

If the coin with two heads is chosen, the outcome will always be heads.

If the coin with two tails is chosen, the outcome will always be tails.

If the fair coin is chosen, the probability of getting heads is 1/2.

Therefore, P(B) = (1/3 * 1) + (1/3 * 0) + (1/3 * 1/2) = 1/2.

Now, we can substitute these values into Bayes' theorem:

P(A|B) = (1 * 1/3) / (1/2) = (1/3) / (1/2) = 2/3

So, the probability that the chosen coin is the one with two heads, given that the coin flipped came up heads, is 2/3.

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The sine function that has an amplitude of 5, a midline of 2 and a period

of 7/2​ is,

⇒ 5 Sin(7π)x + 2

Since, A sine wave, also known as a sinusoid, is the graph of the sine function. Any curve that can be expressed in the form is referred to as a sinusoid. (A and B are both positive.) Sinusoids are the most generic version of the sine function.

Given the amplitude of the function is 5, the vertical shift is 2, and the period of 7/2

Therefore, the values of constants can be written as,

a = 5

b = (2π)/(7/2) = 7π

d = 2

Substituting the values in the sine function,

a sin b (x-c) + d

= 5 Sin(7π)(x-0) + 2

= 5 Sin(7π)x + 2

Hence, the sine function that has an amplitude of 5, a midline of 2 and a

period of 7/2​ is,

= 5 Sin(7π)x + 2

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Answer:

Step-by-step explanation:

A)

The formula for determining the area of a rectangle is given as

Area = length × width

Given that the length and width are (2x + 6) units and (5x + 3) units, the expression for the area is

(2x + 6)(5x + 3) = 10x² + 6x + 30x + 18

Area = 10x² + 36x + 18

B)

The degree is 2 because the highest power of the terms is 2. It is classified as a trinomial because it has 3 terms.

C) it is closed under multiplication. the exponents in the polynomials are whole numbers(2 and 1). The whole numbers are closed under addition, which means that the new exponents formed are also whole numbers. The exponents were whole numbers before multiplication and doesn't change after multiplication.

Answer:

A: (2x+7)(5x+9)

2x x 5x=10x^2

2x x 9= 18x

7 x 5x= 35x

7 x 9=63

   added \/ 18x and 35x

10x^2 + 53x + 63

B: a 2nd degree trinomial

C:  it is closed under multiplication. the exponents of the terms  are whole numbers. The whole numbers are closed under addition, which means that the new exponents formed are also whole numbers. The exponents were whole numbers before multiplication and doesn't change after multiplication.

Step-by-step explanation:

Answer:

3600 seconds

Step-by-step explanation:

Answer:

Find the domain for

y

=

√

x

−

1

so that a list of

x

values can be picked to find a list of points, which will help graphing the radical.

Tap for more steps...

Interval Notation:

[

1

,

∞

)

Set-Builder Notation:

{

x

|

x

≥

1

}

To find the radical expression end point, substitute the

x

value

1

, which is the least value in the domain, into

f

(

x

)

=

√

x

−

1

.

Tap for more steps...

0

The radical expression end point is

(

1

,

0

)

.

(

1

,

0

)

Select a few

x

values from the domain. It would be more useful to select the values so that they are next to the

x

value of the radical expression end point.

Tap for more steps...

x

y

1

0

2

1

3

1.41

image of graph

Step-by-step explanation:

Answer: y+8=m(x+8)

Step-by-step explanation: because you follow the form y-y1=m(x-x1)