Find the absolute extreme values taken on by f on the set D f(x,y)=2−3x+2y where D is the region enclosed by the triangle with vertices (0,0),(4,0),(0,6)(0,0),(4,0),(0,6).

The information provided hows an investment that yields a simple interest.

A simple interest is calculated as follows;

Therefore, Dante's investment after 3 years at the rate of 2% (that is 0.02) would be;

ANSWER:

After 3 years, Dante would have $3,710 in his account

The value of each exponential expression is given as follows:

a) 81.

b) 36.

The standard format of an exponential expression is given as follows:

\(a^b\)

In which:

When we have a negative exponent, the equivalent expression with a positive exponent is obtained inverting the base.

Hence, for item a, we have that:

\(\frac{1}{3^{-4}} = 1 \times 3^4 = 81\)

For item b, we have that:

\(\left(-\frac{1}{6}\right)^{-2} = (-6)^2 = 36\)

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Answer:

The marked price is Rs 823.86

Step-by-step explanation:

Let the cost price be Rs x. The marked price of the mobile is 25% above its cost price. Therefore:

The marked price = x + 25%(x) = 1 + 0.25x = 1.25x

When the mobile phone is sold at a gain of 10%. the profit is Rs 725, to find the cost price we use:

x + 10%(x) = 725

x + 0.1(x) = 725

1.1x = 725

x = 725/1.1 = 659.09

The cost price is Rs 659.09. Therefore the marked price is given as:

Marked price  = 1.25x = 1.25(659.09) = 823.86

The marked price is Rs 823.86

Answer:

B) Variable Expense

Step-by-step explanation:

trust me

yes youre right its b trust him

a.we get, `A = √(2α³/π)`.

b.`⟨H⟩ = (3/4)hω - (h²/4ma²)` where `a = α/√(mω/h)`.

c.we can say that the variational principle is valid in this case.

(a) Let's find the normalization constant A.

We know that the integral over all space of the absolute square of the wave function is equal to 1, which is the requirement for normalization.  `∫⟨ψ|ψ⟩dx= 1`

Hence, using the given trial wavefunction, we get, `∫⟨ψ|ψ⟩dx = ∫ |A/(x^2+α²)|²dx= A² ∫ dx / (x²+α²)²`

Using a substitution `x = α tan θ`, we get, `dx = α sec² θ dθ`

Substituting these in the above integral, we get, `A² ∫ dθ/α² sec^4 θ = A²/(α³) ∫ cos^4 θ dθ`

Using the identity, `cos² θ = (1 + cos2θ)/2`twice, we can write,

`A²/(α³) ∫ (1 + cos2θ)²/16 d(2θ) = A²/(α³) [θ/8 + sin 2θ/32 + (1/4)sin4θ/16]`

We need to evaluate this between `0` and `π/2`. Hence, `θ = 0` and `θ = π/2` limits.

Using these limits, we get,`⟨ψ|ψ⟩ = A²/(α³) [π/16 + (1/8)] = 1`

Therefore, we get, `A = √(2α³/π)`.

Hence, we can now write the wavefunction as `ψ(x) = √(2α³/π)/(x²+α²)`.  

(b) Using the wave function found in part (a), we can now determine the expectation value of energy using the time-independent Schrödinger equation, `Hψ = Eψ`. We can write, `H = (p²/2m) + (1/2)mω²x²`.

The first term represents the kinetic energy of the particle and the second term represents the potential energy.

We can write the first term in terms of the momentum operator `p`.We know that `p = -ih(∂/∂x)`Hence, we get, `p² = -h²(∂²/∂x²)`Using this, we can now write, `H = -(h²/2m) (∂²/∂x²) + (1/2)mω²x²`

The expectation value of energy can be obtained by taking the integral, `⟨H⟩ = ⟨ψ|H|ψ⟩ = ∫ψ* H ψ dx`Plugging in the expressions for `H` and `ψ`, we get, `⟨H⟩ = - (h²/2m) ∫ψ*(∂²/∂x²)ψ dx + (1/2)mω² ∫ ψ* x² ψ dx`Evaluating these two integrals, we get, `⟨H⟩ = (3/4)hω - (h²/4ma²)` where `a = α/√(mω/h)`.

(c) Since we have an approximate ground state wavefunction, we can expect that the expectation value of energy ⟨H⟩ should be greater than the true ground state energy.

Hence, the value obtained in part (b) should be greater than the true ground state energy obtained by solving the Schrödinger equation exactly.

Therefore, we can say that the variational principle is valid in this case.

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Answer: C, D

Step-by-step explanation:

Step-by-step explanation:

kruitika- 42

Gordorn-31

so krutila was 11 when they gave birth to Gordon

she was 23 when they gave birth to pip

The youngest of them is pip so pip is =19

16340 can be written in scientific notation as 1.63 × 10⁴.

Scientific Notation is a way of representing large numbers in decimal forms multiplied by the power(exponent) in terms of decimal places. The purpose of representing large numbers in scientific notation is to enable easier calculation.

This means that 16,340 in scientific notation can be expressed as:

= 1.634 × 10⁴

= 1.63 × 10⁴ ( to 2 significant figures)

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Answer:

39858075

Step-by-step explanation:

Hello,

One basic way to see it is to compute the values.

   75 = 25 * 3

   225 = 75 * 3

   675 = 225 * 3

   etc ...

We can notice that this is multiplied by 3 every 10 years so we can compute as below.

year         population

1970 25

1980 75

1990 225

2000 675

2010 2025

2020 6075

2030 18225

2040 54675

2050 164025

2060 492075

2070 1476225

2080 4428675

2090 13286025

2100 39858075

So the correct answer is 39858075

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

The art teacher can make a maximum of 24 identical kits using all the crayons and drawing paper for proper distribution.

To determine the largest number of identical kits the art teacher can make using all the crayons and drawing paper, we need to find the greatest common divisor (GCD) of the quantities.

The GCD represents the largest number that can divide all the quantities without leaving a remainder.

The GCD of the quantities of crayons can be found by considering the prime factorization:

\(72 = 2^3 * 3^2\\\\48 = 2^4 * 3\\\\48 = 2^4 * 3\\\\48 = 2^4 * 3\\\\\)

The GCD of the crayons is \(2^3 * 3\), which is 24.

Now, we need to find the GCD of the quantity of drawing paper:

120 = \(2^3 * 3 * 5\)

The GCD of the drawing paper is also \(2^3 * 3\), which is 24.

Since the GCD of both the crayons and drawing paper is 24, the art teacher can make a maximum of 24 identical kits using all the crayons and drawing paper.

Each kit would contain an equal distribution of crayons and drawing paper.

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The truth of the given function that we have here is  The function increases at a constant multiplicative rate.

The table is given as

x            0   1    2      3

f(x)         2   3   4.5   6.75

We have x ranging from 0 to 3 while y ranges from 2 to 6.75.

The observations that we can make about the y values is that they produce the next value at the same rate of multiplication.

This is shown here

2 x 1.5 = 3

3 x 1.5 = 4.5

4.5 x 1.5 = 6.75

Hence we can conclude that it increases at a constant multiplicative rate of 1.5.

A table representing the function f(x) = 2(three-halves) Superscript x is shown below. A 2-column table has 4 rows. The first column is labeled x with entries (0, 1, 2, 3). The second column is labeled f (x) with entries 2, 3, 4.5, 6.75. What is true of the given function? The function increases at a constant additive rate. The function increases at a constant multiplicative rate. The function has an initial value of 0. As each x value increases by 1, the y values increase by 1.

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Answer:

23

Step-by-step explanation:

because 460 divided by 20 is 23 so the car gets 23 mpg because 460 represents miles and 20 represents gallons of gas

The car's gas mileage is 23 if the test of a new car results in 460 miles on 20 gallons of gas.

Fraction number consists of two parts, one is the top of the fraction number which is called the numerator and the second is the bottom of the fraction number which is called the denominator.

It is given that:

Gas mileage is the number of miles you can drive on a gallon of gasoline.

A test of a new car results in 460 miles on 20 gallons of gas.

Let x be the car's gas mileage.

The value of the x can be found as follows:

x = 460/20

x = 23

20 gallons of gas and 460 miles are represented by the numbers.

Thus, the car's gas mileage is 23 if the test of a new car results in 460 miles on 20 gallons of gas.

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Answer:

b = 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + b ( m is the slope and b the y- intercept )

Here m = - 2 , then

y = - 2x + b ← is the partial equation

To find b substitute (5, - 7 ) into the partial equation

- 7 = - 10 + b ⇒ b = - 7 + 10 = 3

Answer:x=23

Step-by-step explanation:

Answer:

h=23

Step-by-step explanation:

if u plug 49 in the equation , you make h subject of formula by collecting like terms you'll have something like

h=49-26

h=23

Answer:

Step-by-step explanation:

Answer:

number 8 is d 16 good luck

The equation of the plane passing through the point (2, 8, -5) and containing the line x = 2 - 4t, y = 1 + 2t, z = 3 + 4t is given by 2x - 4y + 8z = -23. To derive this equation, we need to first find a vector parallel to the given line. To do this, we can take the difference of two points that lie on the line. Let us take the points P(2, 1, 3) and Q(2 - 4t, 1 + 2t, 3 + 4t) as our two points. The vector PQ is then given by: PQ = (2 - 4t - 2, 1 + 2t - 1, 3 + 4t - 3) = (-4t, 2t, 4t).

Since the given plane passes through the point (2, 8, -5), we can take the vector from this point to any point on the line, say the point Q, as our normal vector for the plane. This vector is then given by: n = (2 - 4t - 2, 8 - 1, -5 - 3) = (-4t, 7, -8).

Now, using the formula Ax + By + Cz = D for a plane passing through the origin and with a normal vector n = (A, B, C), the equation of the plane is given by A(x - x0) + B(y - y0) + C(z - z0) = 0, where (x0, y0, z0) is any point that lies on the plane.

Substituting A = -4t, B = 7, C = -8, x0 = 2, y0 = 8, z0 = -5 into the above equation, we get: -4t(x - 2) + 7(y - 8) - 8(z + 5) = 0. Simplifying this equation, we get 2x - 4y + 8z = -23, which is the equation of the plane that passes through the point (2, 8, -5) and contains the line x = 2 - 4t, y = 1 + 2t, z = 3 + 4t.

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The system of inequalities is:

y ≤ -0.05*x^2 + 6x

y >  1.5x + 45

(30, 90) is not a solution of that system, while (60, 160) is a solution.

We know that the revenue y is given by:

y ≤ -0.05x^2 + 6x

And we know that the costs are 1.5x + 45, and the revenue must be larger than that, so we also have the inequality:

y >  1.5x + 45

So the system is:

y ≤ -0.05*x^2 + 6x

y >  1.5x + 45

Now, the point (30, 90) means that we need to replace x by 30 and y by 90, replacing that in the second inequality, we will get:

90 > 1.5*30 + 45 = 90

90 > 90

This is false, so the point is not a solution of this inequality, meaning that the point is not a solution of the system.

For the second point we do the same: x= 60, y = 160, replacing that in the second inequality we get:

160 > 1.5*60 + 45 = 135

160 > 135

This is true, now we need to check with the other inequality.

160 ≤  -0.05*60^2 + 6*60 = 180

This is also true.

So the point (60, 160) is a solution to the system.

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Answer:

30,90= not a solution
60,160= a viable solution

Step-by-step explanation:

Polynomial expression for the given  conditions is formulated in the equation

y(x)=1*(x-2)^3(x-0)^2

The polynomial for the conditions with leading coefficient 1 that has the given zeros, multiplicities, and degree. Zero: 2, multiplicity: 3 Zero: 0, multiplicity: 2 Degree: 5 is given as

According to the given condition

The given conditions to write the polynomial equations are as follows

Zero 2  and Multiplicity 3

Zero 0 and Multiplicity 2  

Degree of polynomial expression  = 5

The leading coefficient of polynomial expression = 1

Let us consider the polynomial equation has only one variable and hence in the general form we can write the equation of polynomial as follows

From the general form of polynomial expression as shown in equation (1) we can write

Polynomial expression for the given  conditions is formulated in the equation

y(x)=1*(x-2)^3(x)^2-------(2)

So the polynomial for the conditions given in the question is expressed as

y(x)=1*(x-2)^3(x)^2

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\(\dfrac{\sin \alpha}{\cos \alpha + \sin \alpha} - \dfrac{\cos \alpha}{\cos \alpha - \sin \alpha}\\\\\\=\dfrac{\sin \alpha(\cos \alpha - \sin \alpha) - \cos \alpha(\cos \alpha + \sin \alpha)}{(\cos \alpha + \sin \alpha)(\cos \alpha -\sin \alpha)}\\\\\\=\dfrac{\sin \alpha \cos \alpha - \sin^2 \alpha - \cos^2 \alpha - \cos \alpha \sin \alpha}{\cos^2 \alpha - \sin^2 \alpha}\\\\\\=\dfrac{-(\sin^2 \alpha + \cos^2 \alpha)}{\cos 2 \alpha}\\\\\\=-\dfrac{1}{\cos 2 \alpha}\\\)

\(=-\left(\dfrac{1}{\tfrac{1- \tan^2 \alpha}{1 + \tan^2 \alpha}} \right)~~~~~~~~~~~~~~~~~~; \left[\cos 2\theta = \dfrac{1 - \tan^2 \theta}{1+ \tan^2 \theta} \right]\\\\\\\ = -\left(\dfrac{1+ \tan^2 \alpha}{1- \tan^2 \alpha}\right)\\\\\\= \dfrac{1+\tan^2 \alpha}{\tan^2 \alpha -1}\)

A and B are mutually exclusive, with P(A) is 0.7 and P(B) is 0.2, the probability of event B given event A (P(B|A)) and the probability of event B given event A (P(BIA)) are both 0.2.

To find the probability of B given A, we can use the formula:

P(B|A) = P(A and B) / P(A)

Given:

P(A) = 0.5

P(B) = 0.1

P(A and B) = 0.3

P(B|A) = 0.3 / 0.5

= 0.6

Therefore, the probability that B will occur if A occurs is 0.6.

Given:

P(A) = 0.3

P(B) = 0.4

Since A happening guarantees that B must also happen, the events A and B are not independent. In this case, we can use the formula:

P(A or B) = P(A) + P(B) - P(A and B)

P(A or B) = 0.3 + 0.4 - 0.3

= 0.4

Therefore, the probability of A or B occurring is 0.4.

Given:

P(A) = 0.7

P(B) = 0.2

Since A and B are mutually exclusive events, they cannot occur together. In this case, we have:

P(A and B) = 0

Therefore, P(B|A) = P(BIA)

= 0.

P(BIA) = P(B)

= 0.2.

So, P(BIA) < P(B) is true.

When events A and B are mutually exclusive, with P(A) = 0.7 and P(B)

= 0.2, the probability of event B given event A (P(B|A)) and the probability of event B given event A (P(BIA)) are both 0.2.

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Answer:

3 i think

Step-by-step explanation:

Answer:

Sure, here are the answers to your questions:

a. The maximum value of f(x,y) is 674.

b. The point(s) where the function attains its maximum are (-6,3) and (6,3).

c. The minimum value of f(x,y) is -5.

d. The point(s) where the function attains its minimum are (0,0) and (-3,-1).

Here are the steps on how I got the answers:

First, we need to find the critical points of the function. This can be done by finding the points where the gradient is equal to zero.

The gradient of f(x,y) is given by the following vector:

∇f(x,y) = (4x - 4, 6y)

Setting this vector equal to zero, we get the following system of equations:

4x - 4 = 0

6y = 0

Solving this system of equations, we get the following critical points:

(-6,3)

(6,3)

Next, we need to evaluate the function at each critical point and at the boundary points of the domain.

The boundary points of the domain are given by the following points:

(-13,0)

(13,0)

(0,-13)

(0,13)

Evaluating the function at each of these points, we get the following values:

f(-13,0) = -674

f(13,0) = -674

f(0,-13) = -674

f(0,13) = -674

f(-6,3) = 674

f(6,3) = 674

f(0,0) = -5

f(-3,-1) = -5

Finally, we need to compare the values of the function at the critical points and at the boundary points to find the maximum and minimum values.

The maximum value of the function is 674, which is attained at the points (-6,3) and (6,3).

The minimum value of the function is -5, which is attained at the points (0,0) and (-3,-1)

Step-by-step explanation:

Answer:

9.42 meters

Step-by-step explanation:

radius= 1.5

double the radius to get the diameter

diameter= 3

to find the circumference the equation is π × d

3.14 × 3= 9.42

circumference= 9.42

Answer: B

The guy above is wrong! The correct answer is 7.07, and I double checked with a circumference calculator.

Step-by-step explanation:

-To find the circumference of a circle, you can use the formula C = πd.

-By using this formula the answer found is 7.07

This is 100% the right answer, trust me.

Brainliest?

Answer:

is there a picture because this can't be solved without a picture

Answer:

approx 149.85 cm^2

Answer:

I think you just have to plug the 7 in for x so b(x)=6

Step-by-step explanation:

(5·7)-5=30

(3·7)-16=5

30/5=6