The 13th term of the given Arithmetic sequence is 38.
Arithmetic sequence:A list of integers with a distinct pattern is known as an arithmetic sequence. It is an arithmetic sequence if you can subtract any number in the sequence from the one before it and get a value that is either constant or always the same. Here the constant value is called a common difference.
The formula for the nth term of the Arithmetic sequence is given by
a\(_{n}\) = a+(n-1)dHere we have
Arithmetic sequence: 2, 5, 8, 11,....
Where first term a = 2
And common difference d = term2 - term 1 = 5 - 2 = 3
As we know nth term of AP = a + (n-1)d
=> 13th term of AP = a + (13-1)d = a + 12d
From the give data, a = 2 and d = 3
=> 13th term = a + 12d
= 2 + 12(3)
= 2 + 36
= 38
Therefore,
The 13th term of the given Arithmetic sequence is 38
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please helpp
meeee
agf akgfkef eafef f
Answer:
The lines help u see where they go
Step-by-step explanation:
Answer: (maybe not 100% correct i d k)
Primary Sorce:
Anne Frank's Diary
Photo of a Migrant Worker
American Indian Treaty
Letter by George Washington
Not Primary Source:
1927 and 1992 Article About Babe Ruth
Movie About the Civil War
History Textbook
Fiction Set in 1780s
Blog About Black Holes
algebra due soon in a few pls hurry thx
Answer:
(x, y) --> (x - 1, y - 4)
Step-by-step explanation:
I already answered this, the x coordinate goes one to the left and the y coordinate goes down by 4.
Differentiate (Tanx)÷(2cosx)
Answer:
\(\displaystyle \frac{d}{dx} = \frac{sin^2x + 1}{2cos^3x}\)
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
BracketsParenthesisExponentsMultiplicationDivisionAdditionSubtractionLeft to RightPre-Calculus
Trigonometric FunctionsCalculus
Derivatives
Derivative Notation
Derivative Property [Multiplied Constant]: \(\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)\)
Derivative Rule [Quotient Rule]: \(\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}\)
Trig Derivative: \(\displaystyle \frac{d}{dx}[tanu] = u'sec^2u\)
Trig Derivative:
\(\displaystyle \frac{d}{dx}[cosu] = -u'sinu\)
Step-by-step explanation:
Step 1: Define
\(\displaystyle y = \frac{tanx}{2cosx}\)
Step 2: Differentiate
[Derivative] Quotient Rule: \(\displaystyle \frac{d}{dx} = \frac{\frac{d}{dx}[tanx](2cosx) - \frac{d}{dx}[2cosx](tanx)}{(2cosx)^2}\)[Derivative] Simplify [Derivative Property - Multiplied Constant]: \(\displaystyle \frac{d}{dx} = \frac{\frac{d}{dx}[tanx](2cosx) - 2\frac{d}{dx}[cosx](tanx)}{(2cosx)^2}\)[Derivative] Evaluate [Trig Derivatives]: \(\displaystyle \frac{d}{dx} = \frac{sec^2x(2cosx) - (-2sinx)(tanx)}{(2cosx)^2}\)[Derivative] Evaluate exponents: \(\displaystyle \frac{d}{dx} = \frac{sec^2x(2cosx) - (-2sinx)(tanx)}{4cos^2x}\)[Derivative] Multiply: \(\displaystyle \frac{d}{dx} = \frac{2secx + \frac{2sin^2x}{cosx}}{4cos^2x}\)[Derivative] Add: \(\displaystyle \frac{d}{dx} = \frac{\frac{2sin^2x + 2}{cosx}}{4cos^2x}\)[Derivative] Divide: \(\displaystyle \frac{d}{dx} = \frac{sin^2x + 1}{2cos^3x}\)Topic: AP Calculus AB/BC (Calculus I/II)
Unit: Derivatives
Book: College Calculus 10e
Can someone help me please I will mark u brilliant
Answer:
i believe it would be likely
Step-by-step explanation:
hope this helps! :D
have a miraculous day!! <3
find the surface area of the pyramid
Area of the square base = (6 ft) × (6 ft) = 36 ft²
Area of each triangular face = 1/2 × (6 ft) × (5 ft) = 15 ft²
Then the surface area of the pyramid is
36 ft² + 4 × (15 ft²) = 96 ft²
Divide( use long division):
6×^3+2x-17x^2+15 by 2x-3
Answer:
3x² - 4x - 5
Step-by-step explanation:
Definitions:
Dividend: The polynomial which has to be divided.Divisor: The expression by which the dividend is divided.Quotient: The result of the division.Remainder: The part left over.Long Division Method of dividing polynomials:
Divide the first term of the dividend by the first term of the divisor and put that in the answer.Multiply the divisor by that answer, put that below the dividend and subtract to create a new polynomial.Repeat until no more division is possible.Write the solution as the quotient plus the remainder divided by the divisor.Given:
Dividend: 6x³ + 2x - 17x² + 15Divisor: 2x - 3Rearrange the dividend in descending order of the exponents:
6x³ - 17x² + 2x + 15
Now use the method of long division to divide (6x³ - 17x² + 2x + 15) by (2x - 3):
\(\large \begin{array}{r}3x^2-4x-5\phantom{)}\\2x-3{\overline{\smash{\big)}\,6x^3-17x^2+2x+15\phantom{)}}}\\{-~\phantom{(}\underline{(6x^3-9x^2)\phantom{-b)))))))).)}}\\-8x^2+2x+15\phantom{)}\\-~\phantom{()}\underline{(-8x^2+12x)\phantom{)))..}}\\-10x+15\phantom{)}\\-~\phantom{()}\underline{(-10x+15)\phantom{}}\\0\phantom{)}\\\end{array}\)
Therefore, the quotient is:
\(\boxed{\boxed{3x^2-4x-5}}\)
Plz plz plz plz help me do this will give brainleiest.
Answer:
50 in²
Step-by-step explanation:
The area of the rectangle = 8 × 4 = 32 in²
area of Δ NPO = \(\frac{1}{2}\) × PO × PN = \(\frac{1}{2}\) × 3 × 4 = 6 in² ( PN = RM )
area of Δ PQR = \(\frac{1}{2}\) × RP × 3 = \(\frac{1}{2}\) × 8 × 3 = 12 in² ( RP = MN )
area of MNOPQR = 32 + 6 + 12 = 50 in²
How are the two angles related?
The two angles are related in that they are supplementary angles
Supplementary angles would add tuo to 180 degrees according to the angle Theorem.
Adding the two given angles :
52+128 = 180These angles are supplementary
The angles aren't vertical in that , vertical angles should have the same vertex. Complementary angles on the other hand add to 90 degrees. While the angles doesn't share the same side, hence, they aren't adjacent.
Hence, the angles are related as they are supplementary angles .
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CH
If r(x) = 3x - 1 and s(x) = 2x + 1, which expression is equivalent to
(6)?
)
Answer:
\(\dfrac{17}{13}\)
Step-by-step explanation:
Given that,
r(x) = 3x - 1 and s(x) = 2x + 1
We need to find an expression equivalent to \(\dfrac{r}{s}(6)\).
We know that,
\(\dfrac{r}{s}(6)=\dfrac{r(6)}{s(6)}\)
Put x = 6 in the above expression
\(=\dfrac{3(6)-1}{2(6)+1}\\\\=\dfrac{18-1}{12+1}\\\\=\dfrac{17}{13}\)
So, the equivalent expression is equal to \(\dfrac{17}{13}\).
hannah got 23 out of 25 point on her math test what percent of the questions did she get correct
I will give brainliest and ratings if you get this correct
Using Cramer's rule for first-order condition:
x₁ = -149/444x₂ = -69/222x₃ = 139/444Using Hessian for the second-order condition, critical point (x₁, x₂, x₃) = (-149/444, -69/222, 139/444) is the unique minimum of y.
How to determine 1st and 2nd order condition?(a) Using Cramer's rule for the first-order condition:
To optimize the function y, find the critical points where the gradient is equal to zero. The gradient of y is given by:
∇y = [6x₁ - x₂ - 3x₃ - 5, -x₁ + 12x₂ + 2x₃ - 4, 2x₂ + 8x₃ + 2 - 3x₁]
Setting the gradient equal to zero:
6x₁ - x₂ - 3x₃ - 5 = 0 (1)
-x₁ + 12x₂ + 2x₃ - 4 = 0 (2)
2x₂ + 8x₃ + 2 - 3x₁ = 0 (3)
Using Cramer's rule to solve this system of linear equations, the determinant of the coefficient matrix is:
|A| =
| 6 -1 -3 |
|-1 12 2 |
|-3 2 -3|
|A| = 444
The determinant of the matrix obtained by replacing the first column of A with the constants on the right-hand side of the equations is:
|A₁| =
| 5 -1 -3 |
| 0 12 2 |
| 0 2 -3|
|A₁| = -149
The determinant of the matrix obtained by replacing the second column of A with the constants is:
|A₂| =
| 6 5 -3 |
|-1 0 2 |
|-3 0 -3|
|A₂| = -138
The determinant of the matrix obtained by replacing the third column of A with the constants is:
|A₃| =
| 6 -1 5 |
|-1 12 0 |
|-3 2 2|
|A₃| = -278
Therefore, using Cramer's rule:
x₁ = |A₁|/|A| = -149/444
x₂ = |A₂|/|A| = -69/222
x₃ = |A₃|/|A| = 139/444
(b) Using the Hessian for the second-order condition:
To check whether the critical point found in part (a) is a maximum, minimum or saddle point, we need to use the Hessian matrix evaluated at the critical point. The Hessian of y is given by:
(y) =
| 6 0 -3 |
| 0 12 2 |
|-3 2 8 |
Evaluating H(y) at the critical point (x₁, x₂, x₃) = (-149/444, -69/222, 139/444):
H(y) =
| 6 0 -3 |
| 0 12 2 |
|-3 2 8 |
The eigenvalues of H(y) are 2, 6, and 18, which are all positive. Therefore, H(y) is positive definite, and the critical point is a minimum.
Therefore, the critical point (x₁, x₂, x₃) = (-149/444, -69/222, 139/444) is the unique minimum of y.
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given line A has a slope of m=-2/5, what is the slope of a line parallel to line A
Given line A has a slope of m = -2/5, the slope of a line parallel to line A is m = -2/5
What is the slope of a line?The slope of a line y = mx + c where
m = slope of line and c = y - interceptIs given by m = Δy/Δx where
Δy = change in y and Δx = change in xHow to find the slope of a line [parallel to another line?Given a line y = mx + c where
m = slope of line and c = y - interceptAlso, given another line y' = m'x + c' where
m' = slope of line and c' = y - intercept.If y is parallel to y' then their slopes are equal. That is m = m'
How to find the slope of the line parallel to line A?Given that line A has a slope of m = -2/5, then by the condition above, the slope of a line paralllel to line A must also equal m.
So, the slope of a line parallel to line A is m = -2/5
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Choose the pair of complimentary angles
Answer:
Step-by-step explanation:
Complementary angles are those whose sum is =90°
so
A) no
B)yes
C)no
D)no
when the t-statistic for a parameter estimate is large in absolute value, you can be confident that the true parameter is not
The parameter estimate's t-statistic calculates the discrepancy between the estimate and the actual parameter. If the absolute value is high, the true parameter is probably very different from the estimate.
The parameter estimate's t-statistic calculates the discrepancy between the estimate and the actual parameter. It is derived by multiplying the discrepancy between the two by the estimate's standard error. The true parameter is probably far from the estimate, according to a large absolute value of the t-statistic. As a result, one cannot have confidence in the estimate because it is not a trustworthy representation of the real parameter. This is because a significant t-statistic indicates that the estimate is likely to be inaccurately estimating the true parameter and is either too high or too low. As a result, it is obvious that the true parameter is unlikely to be represented by the estimate when the t-statistic for a parameter estimate has a high absolute value.
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The complete question is
when the t-statistic for a parameter estimate is large in absolute value, you can be confident that the true parameter is not .How do you interpret a large t-statistic in a parameter estimate?
True or False: “All prime numbers are odd numbers.” Justify with numbers, words, and/or a diagram.
If you look at (almost) every prime number, every prime number is odd except 2, so the answer is false.
You can check this by looking at the prime numbers between 1-100.
If f(x)=rootx-3 and g(x)=1-x^2, then what do you notice about the domaine of (f•g)(x)
The domain will be x ≥ 3 for f(x)=√x-3 and g(x)=1-x².
In case a function f gives a way to effectively create a single value y utilizing for that reason a value for x at that point that chosen x-value is said to have a place to the domain of f. there are some conditions to be checked such as denominators cannot equal 0, radicands of even roots can't have a negative value, logarithms can as it was being taken of positive values. Since we are given that f\(\sqrt{x-3}\) and g(x)=1-x², for g(x) since it's a polynomial function its domain had to be real numbers, whereas for f(x) is all positive and real numbers.
for the given condition (f•g)(x)
=> (f•g)(x)= f(x)*g(x)
=> (f•g)(x) = √(x-3) * (1 - x²)
=>(f•g)(x) = √(x-3)-x²(√x-3)
So the domain for (f•g)(x) will be all positive real numbers x≥3 x ∈ [3,∞)
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Change
69
7
to a mixed number
Answer:
9 6/7
This is the answer
PLEASE HELP MEEEE ILL MARK AS BRAINLIEST
For which table would 70 be the missing value, x?
Answer:
Table 3 → 5 (5× 14=70)
Theprofit(indollars)earnedbysellingwappletreesisrepresentedby w2 − 4w + 14. The profit (in dollars) earned by selling w pear trees is
represented by 2w + 10. Write a polynomial that represents how much more profit is earned by selling w apple trees than w pear trees.
\(w^2 - 6w + 4\) is a polynomial that represents how much more profit is earned by selling w apple trees than w pear trees.
The profit earned by selling w pear trees is 2w + 10
To find the difference in profit, we need to subtract the profit earned by selling w pear trees from the profit earned by selling w apple trees:
\((w^2 - 4w + 14) - (2w + 10)\)
Simplifying the expression:
\(w^2 - 6w + 4\)
Therefore, the polynomial that represents how much more profit is earned by selling w apple trees than w pear trees is \(w^2 - 6w + 4\).
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1. AB = 32
BE = 6x + 8
Answer:
x = 4
Step-by-step explanation:
6x + 8 = 32
6x = 32 ‐ 8
6x = 24
x = 24/6
x = 4
Convert 200 pounds to kilograms. (1 pound = 0.454 kilogram) help ASAP
Answer:
90. 718 kg
Step-by-step explanation:
0.454x 200= 90.718
if u round it it's 90.8kg
Answer: 90.8
Step-by-step explanation:
200x0.454=90.8
Since 1 pound is 0.454 kg, you multiply the 200 with the 0.454 because there are 200 pounds!
What value for x maxes the two ratios equivalent?
1/5 : 3/4
x : 1
A. 3/20
B. 4/15
C. 15/4
D. 20/3
With your team, create a piecewise-defined function with at least three “pieces.” The function does not need to be a step-function with horizontal line segments, but it needs to meet the definition of a function. Make a table and a graph for your function, and write an equation for each part. Be sure to state the domain for each part, as well as the domain for the whole function.
On solving the provided question we can say that The following is the data table of the function.
what is function?The subject of mathematics includes quantities and their variations, equations and related structures, shapes and their locations, and places where they can be found. The term "function" refers to the relationship between a set of inputs, each of which has an associated output. A connection between inputs and outputs in which each input leads to a single, distinct result is known as a function. Each function is given a domain and a codomain, or scope. Usually, f is used to denote functions (x). input is an x. There are four main types of functions accessible. based on the following factors: on functions, one-to-one functions, many-to-one functions, inside functions, and on functions.
here,
the provided functions that can be formed are
x -infinity < x < -10
f(x) = 2x + 10 -10 < x < 10
4X - 10 10 < x < infinty
The following is the data table of the function.
x y
-20 -20
-15 -15
-10 -10
-5 0
0 10
5 20
10 30
15 50
20 70
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An example of the piecewise defined function is: \(f(x)= \begin{cases}x & -\infty < x \leq-10 \\ 2 x+10 & -10 < x \leq 10 \\ 4 x-10 & 10 < x < \infty\end{cases}\)
what is function?The subject of mathematics includes quantities and their variations, equations and related structures, shapes and their locations, and places where they can be found. The term "function" refers to the relationship between a set of inputs, each of which has an associated output.
A connection between inputs and outputs in which each input leads to a single, distinct result is known as a function. Each function is given a domain and a codomain, or range.
Usually, f is used to denote functions (x). input is an x. There are four main types of functions accessible. based on the following factors: on functions, one-to-one functions, many-to-one functions, inside functions, and on functions.
The following is the data table of the function.
x y
-20 -20
-15 -15
-10 -10
-5 0
0 10
5 20
10 30
15 50
20 70
The provided functions that can be formed are
\(f(x)= \begin{cases}x & -\infty < x \leq-10 \\ 2 x+10 & -10 < x \leq 10 \\ 4 x-10 & 10 < x < \infty\end{cases}\)
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12 Sam is wondering if there is a pattern that he can use to divide the whole number 3 by powers of 10. Part A Write a whole number. Then write a decimal equivalent to the whole number with zero tenths and hundredths.
The pattern can be written as a whole number by the general equation written as, \(E = \dfrac{n} { 10^k }\).
What is an expression?In mathematics, expression is defined as the relationship of numbers, variables, and functions using mathematical signs such as addition, subtraction, multiplication, and division.
Decimal equivalent to 12 with zero tenths and hundredths: 12.00
To divide 3 by powers of 10, we can simply move the decimal point to the left by the same number of places as the exponent of 10. For example:
3 ÷ 10 = 0.3
3 ÷ 100 = 0.03
3 ÷ 1000 = 0.003
and so on.
So in general, to divide a whole number n by a power of 10 with exponent k, we can write:
The pattern can be written as:-
\(E = \dfrac{n} { 10^k }\)
Then we can move the decimal point in the numerator k places to the left to get the decimal equivalent.
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what are three ratios that are equivalent to 8 5
Answer:
15:24, 20:32 and 40:64.
Step-by-step explanation:
hope this helps
Answer:
The ratios that work is 15:24 because 5 x 3= 15, 24 x 3 = 24 as they both have a 3 as factors. There's also 20:32 as they both have a 4 as factors and lastly 16:10 because they both have a 2 as factors.
Step-by-step explanation:
The ratios that work is 15:24 because 5 x 3= 15, 24 x 3 = 24 as they both have a 3 as factors. There's also 20:32 as they both have a 4 as factors and lastly 16:10 because they both have a 2 as factors.
PLEASEEEEE HELPPP
I need help for numbers 22, 24, 26, 28, 30, 32, 34, 36
Answer:
Step-by-step explanation:
use SOH CAH TOA to remember sin cos and tan functions
Sin = oppostive/hypotenuse
Cos = adjacent/hypotenuse
Tan = opposite/adjacent
22. cos(x) = b/c
24. sin(x) = 2/2sqrt(17) = 1/sqrt(17)
26. tan(x) = 2/8 = 1/4
28. cos(y) = 2/2sqrt(17) = 1/sqrt(17)
30. sin(30)
in a 30 60 90 triangle, the side opposite 30 is 1, the side opposite 60 is sqrt(3), the side opposite 90 is 2.
sin(30) = opposite/hypotenuse = 1/2/1 = 1/2
32.
in a 45 45 90 triangle, the side opposite 45 is 1, the side opposite 45 is 1, the side opposite 90 is sqrt2.
sin = opposite/hypotenuse = 1/sqrt(2)
34. cos(30) = sqrt(3)/2
36. tan(31) = AC/9 --> AC = 9tan(31) = 5.408
Answer:
22. \(\dfrac{b}{c}\)
24. \(\dfrac{\sqrt{17} }{17}\)
26. \(\dfrac14\)
28. \(\dfrac{\sqrt{17} }{17}\)
30. \(\dfrac12\)
32. \(\dfrac{\sqrt{2} }{2}\)
34. \(\dfrac{\sqrt{3} }{2}\)
36. AC = 5.41 (nearest hundredth)
Step-by-step explanation:
Using trig ratios:
\(sin(\theta)=\dfrac{O}{H}\\\\\\cos(\theta)=\dfrac{A}{H}\\\\\\tan(\theta)=\dfrac{O}{A}\)
where \(\theta\) is the angle, O is the side opposite the angle, A is the side adjacent the angle, H is the hypotenuse of a right angle
22. \(cos(x)=\dfrac{b}{c}\)
24. \(sin(x)=\dfrac{2}{2\sqrt{17} }=\dfrac{\sqrt{17} }{17}\)
26. \(tan(x)=\dfrac{2}{8}=\dfrac14\)
28. \(cos(y)=\dfrac{2}{2\sqrt{17} }=\dfrac{\sqrt{17} }{17}\dfrac{}{}\)
30. \(sin(30)=\dfrac12\)
32. \(sin(45)=\dfrac{\sqrt{2} }{2}\)
34. \(cos(30)=\dfrac{\sqrt{3} }{2}\)
36. \(tan(31)=\dfrac{AC}{9}\)
\(\implies AC=9tan(31)=5.41\) (nearest hundredth)
3 times what equals -18
Answer:
-6
Step-by-step explanation:
Let "what" be termed as "x".
Set the equation:
3 * x = -18
Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Divide 3 from both sides:
(3x)/3 = (-18)/3
x = -18/3
x = -6*
*Note: When you divide a negative number with a positive number, your answer will be negative.
-6 is your answer.
~
The value of number which is 3 times to -18 is -6 .
Given,
3 *x = -18
So,
Let "what" be termed as "x".
Form the equation including the variable x ,
3 * x = -18
Isolate the variable, x.
Note the equal sign, what you do to one side, you do to the other. Divide 3 from both sides:
(3x)/3 = (-18)/3
x = -18/3
x = -6
-6 is the required answer .
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THIS QUESTION IS WORTH 50 POINTSMatt and his friends hike 42 mi over a holiday weekend. they hike for 5 hours on saturday, 6 hours on sunday, and 3 hours on monday. they go hiking the following weekend. if they hike at the same rate as they hiked over the holiday weekend, how long will it take to hike 12 mi
A circle has a diameter of 16 cm. What is its circumference?
Use 3.14 for it, and do not round your answer. Be sure to include the correct unit in your answer.
Answer:
the answer is 50.27 cm for your question
Mr. Thompson sold 4 vacuum cleaners in the first month. In the second month, he sold 3 times as many vacuum cleaners as the first month. In the third
month, he sold 5 times as many vacuum cleaners as the first month.
a. How many vacuum cleaners did Mr. Thompson sell in the three months?
bers
Mr. Thompson sold ____
vacuum cleaners in the three months.
b. He sold the vacuum cleaners for $435 each. How much money did Mr. Thompson earn? (Be sure to put a comma in your answer.)
bers
Mr. Thompson earned $ ________