Find f-1(x), if f(x) = 3x – 6. Justify your
reasoning with math calculations and/or a written
explanation.

If the value of sin x = 0.2, then the values for sin(π - x) is 0.2.

Given that,

the value of sin x = 0.2

We have to find the value of sin(π - x).

We know the trigonometric rule that,

sin(π - x) = sin (x)

for any value of x.

So here whatever the value of x, the value of  sin(π - x) is sin (x) itself.

So here sin x = 0.2.

So, by the rule,

sin(π - x) = sin (x) = 0.2

Hence the value is 0.2.

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The height of the projectile after 4 seconds is 421.28 ft.

The projectile is in the air for 8.015 seconds.

The horizontal distance traveled by the projectile is 881.77 ft.

The maximum height of the projectile is 464.1 ft.

To solve this problem, we can use the kinematic equations of motion for a projectile.

Let's assume that the initial height of the projectile is zero.

What is the height of the projectile after 4 seconds:

We can use the equation:

\(y = yo + vot + 1/2at^2\)

where

y = height of the projectile

yo = initial height (zero in this case)

vo = initial vertical velocity = 220 sin(60°) = 190.53 ft/sec

a = acceleration due to gravity \(= -32.2 ft/sec^2\) ( negative since it acts downwards)

t = time = 4 sec

Plugging in the values, we get:

\(y = 0 + (190.53)(4) + 1/2(-32.2)(4)^2 = 421.28 ft\)

Therefore, the height of the projectile after 4 seconds is 421.28 ft.

Long is the projectile in the air:

The time of flight of a projectile can be calculated using the equation:

t = 2vo sinθ / g

where θ is the launch angle and g is the acceleration due to gravity.

Plugging in the values, we get:

t = 2(220 sin(60°)) / 32.2 = 8.015 sec

Therefore, the projectile is in the air for 8.015 seconds.

Horizontal distance traveled by the projectile:

The horizontal distance traveled by the projectile can be calculated using the equation:

\(x = xo + vot + 1/2at^2\)

where

x = horizontal distance traveled

xo = initial horizontal position (zero in this case)

vo = initial horizontal velocity = 220 cos(60°) = 110 ft/sec

a = acceleration due to gravity (zero in the horizontal direction)

t = time = 8.015 sec

Plugging in the values, we get:

\(x = 0 + (110)(8.015) + 1/2(0)(8.015)^2 = 881.77 ft\)

Therefore, the horizontal distance traveled by the projectile is 881.77 ft.

Maximum height of the projectile:

The maximum height of a projectile can be calculated using the equation:

\(ymax = yo + (vo^2 sin^2 \theta ) / 2g\)

Plugging in the values, we get:\(ymax = 0 + (190.53^2 sin^2(60\degree )) / (2)(32.2) = 464.1 ft\)

Therefore, the maximum height of the projectile is 464.1 ft.

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Answer:

See below.

Step-by-step explanation:

Multiplying terms with exponents make the exponents add together.

13.) x² · x⁵ = x⁷

14.) b⁵ ·  b³ = b⁸

15.) y⁴ · y⁷ = y¹¹

16.) m⁴ · m¹ = m⁵

Answer:

(0,2)

(3,0)

Step-by-step explanation:

If BCDE is congruent to OPQR, then DE is congruent to QR .

Congruence means the same point on two different shapes , like parallels

so BC is congruent to OP

and

DE is congruent to QR

In plain English, two objects are said to be congruent if they overlap, i.e., have the same size and shape. If two angles have the same measure, they are said to be congruent. They are congruent if the sides' lengths line up.

Two triangles are said to be congruent if their sides and angles are an exact match.

Conditions for Congruence of Triangles:

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The taylor series as per the power series operation is sin(x) = 0 + 1x + 0x + −1/3!+3 + 0x

given,

f(x) = sinx

c = 3pi/4

the required series will be .

f(x) = f(c) + f' (c)( x-c ) + f''(c)/2! + .... f x n(c)/n! (x-c)^n

f(c) = sin(c)

     = sin(3pi/4)

      = 1/2

on solving the equation becomes,

sin(x) = 0 + 1x + 0x + −1/3!+3 + 0x

Assume that f(x) is a real or composite function and that it is a differentiable function of a real or composite neighbourhood number. The following power series is then described by the Taylor series.

The Taylor series can be expressed using sigma notation, where f(n)(a) = nth derivative of f n! = factorial of n.

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The volume of the solid obtained by rotating the region bounded by the curve y = 1 - (x - 5)² in the first quadrant about the y-axis is 51π cubic units.

To find the volume of the solid obtained by rotating the region bounded by the curve y = 1 - (x - 5)² in the first quadrant about the y-axis, we can use the method of cylindrical shells.

The formula for the volume using cylindrical shells is:

V = 2π ∫ [a, b] x * h(x) dx

Where:

- V is the volume of the solid

- π represents the mathematical constant pi

- [a, b] is the interval over which we are integrating

- x is the variable representing the x-axis

- h(x) is the height of the cylindrical shell at a given x-value

In this case, we need to solve for x in terms of y to express the equation in terms of y.

Rearranging the given equation:

x = 5 ± √(1 - y)

Since we are only interested in the region in the first quadrant, we take the positive square root:

x = 5 + √(1 - y)

Now we can rewrite the volume formula with respect to y:

V = 2π ∫ [c, d] x * h(y) dy

Where:

- [c, d] is the interval of y-values that correspond to the region in the first quadrant

To determine the interval [c, d], we set the equation equal to zero and solve for y:

1 - (x - 5)² = 0

Expanding and rearranging the equation:

(x - 5)² = 1

x - 5 = ±√1

x = 5 ± 1

Since we are only interested in the region in the first quadrant, we take the value x = 6:

x = 6

Now we can evaluate the integral to find the volume:

V = 2π ∫ [0, 1] x * h(y) dy

Where h(y) represents the height of the cylindrical shell at a given y-value.

Integrating the expression:

V = 2π ∫ [0, 1] (5 + √(1 - y)) * h(y) dy

To find h(y), we need to determine the distance between the y-axis and the curve at a given y-value. Since the curve is symmetric, h(y) is simply the x-coordinate at that point:

h(y) = 5 + √(1 - y)

Substituting this expression back into the integral:

V = 2π ∫ [0, 1] (5 + √(1 - y)) * (5 + √(1 - y)) dy

Now, we can evaluate this integral to find the volume

V = 2π ∫ [0, 1] (5 + √(1 - y)) * (5 + √(1 - y)) dy

To simplify the integral, let's expand the expression:

V = 2π ∫ [0, 1] (25 + 10√(1 - y) + 1 - y) dy

V = 2π ∫ [0, 1] (26 + 10√(1 - y) - y) dy

Now, let's integrate term by term:

\(V = 2\pi [26y + 10/3 * (1 - y)^\frac{3}{2} - 1/2 * y^2]\)] evaluated from 0 to 1

V = \(2\pi [(26 + 10/3 * (1 - 1)^\frac{3}{2} - 1/2 * 1^2) - (26 * 0 + 10/3 * (1 - 0)^\frac{3}{2} - 1/2 * 0^2)]\)

V = 2π [(26 + 0 - 1/2) - (0 + 10/3 - 0)]

V = 2π (25.5)

V = 51π cubic units

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1. Jada's data set has a mean of 5, Diego's data set has a mean of 6, and Lin's data set has a mean of 4.

2. The data set that has the greatest variability is Lin's data set because it has the highest standard deviation of 3.6.

In Mathematics and Geometry, the mean for this set of data can be calculated by using the following formula:

Mean = [F(x)]/n

Question 1.

In this scenario and exercise, we would determine the mean of the three data sets based on the number of text messages sent by Jada, and Diego, and Lin over 6 days as follows;

Mean number of text for Jada = (4 + 4 + 4 + 6 + 6 + 6)/6

Mean number of text for Jada = 30/6

Mean number of text for Jada = 5.

Mean number of text for Diego = (4 + 5 + 5 + 6 + 8 + 8)/6

Mean number of text for Diego = 36/6

Mean number of text for Diego = 6.

Mean number of text for Lin = (1 + 1 + 2 + 2 + 9 + 9)/6

Mean number of text for Lin = 24/6

Mean number of text for Lin = 4.

Question 2.

In Statistics, variability is a measure of the spread of a data set. Also, we would use standard deviation to determine the variability in each data set as follows;

Standard deviation = √(1/n × ∑(xi - u₁)²)

Standard deviation for Jada = √(1/6 × [(4 - 5)² + (4 - 5)² + (4 - 5)² + (6 - 5)² + (6 - 5)² + (6 - 5)²]

Standard deviation for Jada = √(6/6) = 1

Standard deviation for Diego = √(1/6 × [(4 - 6)² + (5 - 6)² + (5 - 6)² + (6 - 6)² + (8 - 6)² + (8 - 6)²]

Standard deviation for Diego = √(14/6) = 1.53

Standard deviation for Lin = √(1/6 × [(1 - 4)² + (1 - 4)² + (2 - 4)² + (2 - 4)² + (9 - 4)² + (9 - 4)²]

Standard deviation for Lin = √(76/6) = 3.6

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

The distance from the center of the Earth to the point where the net gravitational force is zero is one-ninth the distance from the Earth to the Moon.

Let's assume that the distance from the center of the Earth to this point is denoted as x.

Given:

Mass of the Moon (M\(_{moon}\)) = 1/81 × M\(_{earth}\)

Distance from Earth to Moon (d\(_{moon}\)) = distance on center

According to the principle of gravitational equilibrium, the gravitational force from the Earth and the gravitational force from the Moon acting on an object at that point must balance out. Mathematically, we can express this as:

F\(_{earth}\) = F\(_{moon}\)

The gravitational force between two objects can be calculated using Newton's law of universal gravitation:

F \(_{gravity}\)= G × (m₁ × m₂) / r²

Where:

G is the gravitational constant (approximately 6.67430 x 10⁻¹¹m²/kg/s²)

m₁ and m₂ are the masses of the two objects

r is the distance between the centers of the two objects

Considering the gravitational forces involved:

F\(_{gravity}\)\(_{earth}\) = G ₓ (M\(_{EARTH}\)  ₓ m\(_{OBJECT}\)) / (d\(_{earth}\))²

F\(_{gravity}\) \(_{moon}\) = G ₓ (M \(_{moon}\) ₓ m\(_{object}\)) / (d \(_{moon}\))²

Since we are looking for the point where the net gravitational force is zero, we set these two forces equal to each other:

G × (M\(_{earth}\) × m\(_{object}\)) / (d\(_{earth}\))²   =     G × (M \(_{moon}\) × m\(_{object}\)) / (d \(_{moon}\))²

Canceling out the common factors of G and m\(_object}\), and substituting the given values:

(M\(_{earth}\) × 1) / (d\(_{earth}\))² = (M \(_{moon}\) × 1) / (d \(_{moon}\))²

Rearranging the equation:

(d\(_{earth}\))²/ (M\(_{earth}\)) = (d \(_{moon}\))² / (M \(_{moon}\))

Taking the square root of both sides:

d\(_{earth}\) / √(M \(_{moon}\))) = d_moon / √(M \(_{moon}\))

Substituting the given values:

d\(_{earth}\) /√(M\(_{earth}\)) = d\(_{moon}\) / √(1/81 × M\(_{earth}\))

Simplifying further:

d\(_{earth}\)  / √(M\(_{earth}\)) =d\(_{moon}\)  / (1/9 × √(M\(_{earth}\)))

Multiplying both sides by √(M\(_{earth}\)):

d\(_{earth}\) = (1/9) × d\(_{moon}\)

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The parent function of the transformed function is y = f ( x ) = x

Given data ,

Let the parent function be represented as f ( x )

Now , the value of f ( x ) is

The transformed function is represented as y

where y = 2 ( x - 5 )

On simplifying , we get

y = 2( x - 10 )

If the original function is y = f(x), assuming the horizontal axis is the input axis and the vertical is for outputs, then:

The function is shifted horizontally left by 10 units and multiplied by a scale factor of 2 units.

Hence , the parent function is f ( x ) = x

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Answer:

BC = 4

Step-by-step explanation:

The diagram shows a circle with radius AE and chord BD.

Assuming that the radius bisects the chord, then AE is perpendicular to BD. So the measure of angle ACB is 90°.

This means that triangle ACB is a right triangle, with legs AC and BC, and hypotenuse AB.

The length of the radius is:

\(AE = 3 + 2 = 5\)

As AB is also the radius, AB = 5.

To find the length of BC, use Pythagoras Theorem:

\(AC^2+BC^2=AB^2\)

    \(3^2+BC^2=5^2\)

      \(9+BC^2=25\)

\(9+BC^2-9=25-9\)

           \(BC^2=16\)

        \(\sqrt{BC^2}=\sqrt{16}\)

            \(BC=4\)

Therefore, the length of line segment BC is 4.

Answer:

392.50

Step-by-step explanation:

1,000-150=850

850 x .40 = 340

150 x .35 = 52.5

340 + 52.5 = 392.50

Answer:

$268

Step-by-step explanation:

I got 100% on the quiz

Answer:

its equals the same, the third one. this is very easy.

Answer:

Step-by-step explanation:

heyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyy

Answer:

ok,soo I found out that when you add one of the y values to positive 9 it gives you the exact x value which is correct

The exponential function is in the form

y = a * b^t where a is the initial value and b is the growth( decay) rate

a = 1500

b = 1 - percent decrease in decimal form

b = 1 - .0675

.9325

y = 1500 ( .9325)^t

Answer:

The equation that matches the table is y = -5x + 7 ⇒ C

Step-by-step explanation:

The form of the linear equation is y = m x + b, where

The rule of the slope is m =  \(\frac{y2-y1}{x2-x1}\) , where

From the given table

→ Choose any two points from the table

∵ Points (0, 7) and (1, 2) are in the table

∴ x1 = 0 and y1 = 7

∴ x2 = 1 and y2 = 2

→ Substitute them in the rule of the slope above

∵ m = \(\frac{2-7}{1-0}=\frac{-5}{1}\)

∴ m = -5

→ Substitute it in the form of the equation above

∵ y = -5x + b

∵ b is the value of y at x = 0

∵ At x = 0, y = 7

∴ b = 7

∴ y = -5x + 7

∴ The equation that matches the table is y = -5x + 7

Answer:

104 Dollars

Step-by-step explanation:

Principal ammount= 500

(R) Interest rate= 5.2%

Time involved= 4 years

I= P x r x t

Hope this helped

Step-by-step explanation:

m∠2 = m∠4

y + 10 = 3y - 24

y - 3y = -24 - 10

-2y = -34

y = -34/-2

y = 17

m∠2 = y + 10

m∠2 = 17 + 10

m∠2 = 27°

The decision of which two homework assignments to complete depends on Mofor's individual circumstances and priorities.

If Mofor only has time to do two homework assignments out of the five subjects, he will need to choose which subjects to prioritize. The specific subjects he chooses to work on will depend on various factors such as his strengths, weaknesses, upcoming deadlines, and personal preferences. Here are a few strategies he could consider:

1. Prioritize based on importance: Mofor can prioritize the homework assignments that carry more weight in terms of grades or have upcoming deadlines. This way, he ensures that he completes the assignments that have a higher impact on his overall academic performance.

2. Focus on challenging subjects: If Mofor finds certain subjects more difficult or time-consuming, he can prioritize those assignments to allocate more time and effort to them. This approach allows him to concentrate on improving his understanding and performance in subjects that require extra attention.

3. Balance workload: Mofor can choose to distribute his efforts evenly across subjects, selecting two assignments from different subjects. This strategy ensures that he maintains a balanced workload and avoids neglecting any particular subject.

The decision of which two homework assignments to complete depends on Mofor's individual circumstances and priorities. It is essential for him to consider his academic goals, time constraints, and personal strengths to make an informed decision.

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The probability that a single randomly selected can contain 11.9 ounces or less is 0.179.

B. The probability that a randomly selected can contain 11.9 ounces or less can be calculated using the normal distribution. Specifically, we can use the Cumulative Distribution Function (CDF) to find the probability that a randomly selected can will contain 11.9 ounces or less.

We know that the mean of the cans is 12 ounces with a standard deviation of 0.4 ounces. We can use the Z-score to calculate the probability. The Z-score is equal to (11.9 - 12) / 0.4 = -0.25. We then use the Z-score to calculate the probability.

Specifically, we can use the CDF to calculate the probability that a randomly selected can will contain 11.9 ounces or less. The CDF for the normal distribution is given by

P(X ≤ x) = ½[1 + erf(x - μ/σ√2)].

When we plug in the Z-score of -0.25 into the equation, we get

P(X ≤ 11.9) = ½[1 + erf(-0.25)] = 0.179. Therefore, the probability that a single randomly selected can contain 11.9 ounces or less is 0.179.

For the quality control inspector, we can use the sample mean to calculate the probability that the cans will contain 11.9 ounces or less. Specifically, if the sample mean is 11.9 ounces or less, then the probability that the cans will contain 11.9 ounces or less is 1.

If the sample mean is greater than 11.9 ounces, then we can use the normal distribution to calculate the probability. Specifically, we can use the Z-score to calculate the probability. The Z-score is equal to (11.9 - sample mean) / 0.4. We then use the Z-score to calculate the probability using the CDF.

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Answer: 400,00 km

Step-by-step explanation: 1:50,000 = 8:x

8 * 50,000 = 400,000

So, 8km on the map is 400,000 km in real life.

Would appreciate brainly <3

Answer:

Step-by-step explanation:

Given that :

_______low tech _____consumer products

n _______14 ___________ 12

Mean ___ 157 __________218

Variance _ 1563 ________1602

The point estimate of the difference between the means of the two populations :

Difference between the sample mean of low tech and consumer product

Sample mean (low tech) - sample mean (consumer product)

157 - 218

= - 61

The domain of the rational function h(x) = (x - 3)/(x² - 4) is equal to (-∞, -2)  ∪ (-2, 2) ∪ (2, ∞).

The possible points that would lie on h(x) = x² - x + 1 are (3, 7).

True: (1, -1) is a point of the graph of f(x) = -2(x + 1)² + 7.

In Mathematics, a domain is the set of all real numbers for which a particular function is defined.

From the graph of h(x) = (x - 3)/(x² - 4), the domain in interval notation and set builder notation is as follows;

Domain = (-∞, -2)  ∪ (-2, 2) ∪ (2, ∞)

Domain = {x|x ≠ 2, -2}.

Next, we would determine possible x-value for the given quadratic function as follows;

h(x) = x² - x + 1

7 = x² - x + 1

7 - 1 = x² - x

6 = x² - x

x² - x - 6 = 0.

x² - 3x + 2x - 6 = 0.

x(x - 3) + 2(x - 3) = 0

(x + 2)(x - 3) = 0

x = 3 or x = -2.

For second quadratic function f(x) = -2(x + 1)² + 7, we have:

f(x) = -2(x + 1)² + 7

-1 = -2(1 + 1)² + 7

-1 = -2(2)² + 7

-1 = -8 + 7

-1 = -1 (True).

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-7 by 2

4 + 2h ≤ -3

subtract 4 from both sides

2h ≤ -7

divide by 2

h = -3.5 (-7 by 2)

most likely go with -3.5

Answer:

Step-by-step explanation:

Thanks for my points back

sododossofods

Answer:

415 miles

Step-by-step explanation:

Start with the speed equation:

speed = distance/time

Now solve the speed equation for distance:

distance = speed × time

Apply the speed equation solved for distance to the two parts of the trip.

4 hours at 55 mph:

distance = 55 mph × 4 hours = 220 miles

3 hours at 65 mph:

distance = 65 mph × 3 hours = 195 miles

Add the two distances to find the total distance:

total distance = 220 miles + 195 miles = 415 miles

Answer: 415 miles

Answer:

415 miles

Step-by-step explanation:

Simon drove 55 miles per hour for 4 hours then 65 miles per hour for 3 hours.

How far did he drive?

d=rt

For the first part of the trip:

d = 55 * 4 = 220 miles

For the second part of the trip:

d = 65*3 =195 miles

Add the miles together

220+195 = 415 miles