By answering the presented question, we may conclude that the value of the trigonometry is cot x = -√3 / 4
what is trigonometry?The study of the connection between triangle side lengths and angles is known as trigonometry. The concept first originated in the Hellenistic era, during the third century BC, due to the application of geometry in astronomical investigations. The subject of mathematics known as exact techniques deals with certain trigonometric functions and their possible applications in calculations. There are six commonly used trigonometric functions in trigonometry. Sine, cosine, tangent, cotangent, secant, and cosecant are their separate names and acronyms (csc). The study of triangle characteristics, particularly those of right triangles, is known as trigonometry. As a result, geometry is the study of the properties of all geometric forms.
cot x = cos x / sin x.
we have cos x = 1/7 and sin x < 0.
\(sin^2 x + cos^2 x = 1\\sin^2 x + (1/7)^2 = 1\\sin^2 x = 1 - (1/7)^2 = 48/49\\\)
sin x = -√(48/49) = -(4/7)√3
cot x = cos x / sin x = (1/7) / (-(4/7)√3)
cot x = -√3 / 4
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Can someone help me with this problem. It’s the Pythagorean theorem.
Answer:
x = 15/\(\sqrt{3}\) and y = 30/\(\sqrt{3}\)
Step-by-step explanation:
I just used this trick I remembered from Honors Geometry. I am now in Honors Algebra II w/ Trig. So this trick is what is used for 30-60-90 special right triangles
in some situations it might not be possible to carry out a randomized controlled experiment, even when the aim is to investigate causality in the collected data. in these type of situations, the researcher should be worried about potential g
it might not be possible to carry out a randomized controlled experiment, even when the aim is to investigate causality in the collected data the researcher should be worried about potential g idiographic
Type of causal reasoning is an idiographic explanation
we know that there are 2 types of approach for understanding the social life
Idiographic
nomothetic
and here idiographic approach use for understanding single or individual type case or event but a nomothetic approach that is used for understanding large scale social pattern
so here also cause of the single situation is exhaustively examined
so correct answer is an idiographic explanation
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What is the answer please hurry I need helpp
The given function is f(x) = 15(1.02)^x, where x is the number of years from the date at which money is initially deposited.
This means that $15 were initially deposited into the account, and the amount grows at an annual rate of 2% (which is represented by 1.02 being raised to the power of x).
Therefore, the correct answer is: $15 were initially deposited into the account, which grows at an annual rate of 2%.
Hope I helped you...
A line segment has endpoints at (–1, 4) and (4, 1). Which reflection will produce an image with endpoints at (–4, 1) and (–1, –4)?
Answer:
This is the answer
y = − x
So yeah hope this helps...
Match each scenario involving projectile motion with the equation that describes the height of the object at time t. Tiles h = -4.9t2 + 5 h = -4.9t2 + 1.5 h = -16t2 + 73t + 1.5 h = -16t2 + 5 h = -16t2 + 73t + 5 h = -4.9t2 + 73t + 1.5 Pairs Dwayne throws a ball with an initial velocity of 73 feet/second. Dwayne holds the ball 5 feet off the ground before throwing it. A watermelon falls from a height of 5 feet to splatter on the ground below. Marcella shoots a foam dart at a target. She holds the dart gun 1.5 meters off the ground before firing. The dart leaves the gun traveling 73 meters/second. Greg drops a life raft off the side of a boat 1.5 meters above the water.
Answer:
h = -16t^2 + 73t + 5h = -16t^2 + 5h = -4.9t^2 + 73t + 1.5h = -4.9t^2 + 1.5Step-by-step explanation:
The general equation we use for ballistic motion is ...
\(h(t)=\frac{1}{2}gt^2+v_0t+h_0\)
where g is the acceleration due to gravity, v₀ is the initial upward velocity, and h₀ is the initial height.
The values of g commonly used are -32 ft/s², or -4.9 m/s². Units are consistent when the former is used with velocity in ft/s and height in feet. The latter is used when velocity is in m/s, and height is in meters.
_____
Dwayne throws a ball with an initial velocity of 73 feet/second. Dwayne holds the ball 5 feet off the ground before throwing it. (h = -16t^2 + 73t + 5)
A watermelon falls from a height of 5 feet to splatter on the ground below. (h = -16t^2 + 5)
Marcella shoots a foam dart at a target. She holds the dart gun 1.5 meters off the ground before firing. The dart leaves the gun traveling 73 meters/second. (h = -4.9t^2 + 73t + 1.5)
Greg drops a life raft off the side of a boat 1.5 meters above the water. (h = -4.9t^2 + 1.5)
_____
Additional comment on these scenarios
The dart and ball are described as being launched at 73 units per second. Generally, we expect launches of these kinds of objects to have a significant horizontal component. However, these equations are only for vertical motion, so we must assume the launches are straight up (or that the up-directed component of motion is 73 units/second).
The area of a rectangle is 38.5 square inches. The base of the rectangle is 4 inches. What is the height of rectangle?
Pls help me on this one. PLSSS :(
Answer:
The answer is 9.625
Step-by-step explanation:
So what you have is the area and the base of the rectangle. To find the height, just divide 4 into 38.5
38.5 / 4 = 9.625
To double check just multiple 9.625 by 4
9.625 x 4 = 38.5
Hope this helps
Simplify: 4x(x^2 – 3x + 1)
A)4x^3 - 7x^2 +5
B)4x^2 – 12x^2 + 4
C) 4x^3 - 12x^2 + 4x
D)4x^2 - 12x + 1
Answer:
its c
Step-by-step explanation:
4x*x^2= 4x^3
-3x*4x =-12x^2
1*4x = 4x
= 4x^3 -12x^2 + 4x
Ella and some friends are going to a movie. Each movie ticket costs $5.
Create an equation that shows the relationship between how many friends, n, attend the movie and the total cost in
dollars, c.
Answer: c = 5n
Step-by-step explanation:
Cost of movie ticket = $5 per person
Number of people attending the movie = n
The total cost c, will be the multiplication of the cost of movie ticket per person by the total.number of people attending the movie. This will be:
c = 5 × n
c = 5n
2
y
b
P
0
The equation of the line / in the diagram is y = 5-x.
The line cuts the y-axis at P.
a
Write down the co-ordinates of P.
Write down the gradient of the line 1.
NOT TO
SCALE
Given that the equation of the line in the diagram is `y = 5 - x`. The line cuts the y-axis at P. So, the coordinates of point P are (0,5) and the gradient of the line is `-1`.
The equation of the line can be written as `y = -1x + 5`.Therefore, the y-intercept of the line is 5. Therefore, the coordinates of point P are (0,5).
To find the gradient of the line, we have to write the equation of the line in the form of `y = mx + c`.
We can rewrite `y = -1x + 5` as `y = (-1)x + 5`.From the above form of the equation, we can see that the gradient `m` is `-1`.Therefore, the gradient of line 1 is `-1`.Hence, the required answer is: Coordinates of point P is `(0,5)`.The gradient of the line is `-1`.
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Find the squares of a+3b
Answer:
3ab
Step-by-step explanation:
because it is answer
prove that for each natural number n > 43, we can write n = 6xn 9yn 20zn 15. strong induction 117 for some nonnegative integers xn, yn, zn. then prove that 43 cannot be written in this form
For each natural number n > 43, we can express it as n = 6xn + 9yn + 20zn + 15, where xn, yn, and zn are nonnegative integers. Additionally, we have shown that 43 cannot be written in this form.
To prove that for each natural number n > 43, we can write n = 6xn + 9yn + 20zn + 15, where xn, yn, and zn are nonnegative integers, we will use strong induction. The base case will be n = 44, and we will assume that the statement holds for all natural numbers up to k, where k > 43. Then we will prove that it holds for k+1.
Base Case:
For n = 44, we can express it as:
44 = 6(1) + 9(1) + 20(1) + 15
Inductive Hypothesis:
Assume that for every natural number m, where 44 ≤ m ≤ k, we can express m as:
m = 6x + 9y + 20z + 15
for some nonnegative integers x, y, and z.
Inductive Step:
We need to prove that for k+1, we can express it in the given form.
For k+1, there are three cases to consider:
Case 1: k+1 is divisible by 6
In this case, we can express k+1 as:
(k+1) = 6x' + 9y' + 20z' + 15
where x' = x + 1, y' = y, and z' = z. Since k+1 is divisible by 6, we can add one more 6 to the expression.
Case 2: k+1 is divisible by 9
In this case, we can express k+1 as:
(k+1) = 6x' + 9y' + 20z' + 15
where x' = x, y' = y + 1, and z' = z. Since k+1 is divisible by 9, we can add one more 9 to the expression.
Case 3: k+1 is not divisible by 6 or 9
In this case, we can express k+1 as:
(k+1) = 6x' + 9y' + 20z' + 15
where x' = x + 2, y' = y + 1, and z' = z - 1. By adding 26, 19, and subtracting 1*20, we can obtain k+1.
Thus, we have shown that for each natural number n > 43, we can write n = 6xn + 9yn + 20zn + 15, where xn, yn, and zn are nonnegative integers.
Now, let's prove that 43 cannot be written in this form. If we assume that 43 can be expressed as:
43 = 6x + 9y + 20z + 15
Simplifying the equation:
28 = 6x + 9y + 20z
Considering the equation modulo 3, we have:
1 ≡ 0 (mod 3)
This is a contradiction since 1 is not congruent to 0 modulo 3. Therefore, 43 cannot be written in the given form.
In conclusion, we have proven by strong induction that for each natural number n > 43, we can express it as n = 6xn + 9yn + 20zn + 15, where xn, yn, and zn are nonnegative integers. Additionally, we have shown that 43 cannot be written in this form.
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If the price charged for a candy bar is p(x) cents, then x thousand candy bars will be sold in a certain city, where p(x)=151-x/10. a. Find an expression for the total revenue from the sale of x thousand candy bars. b. Find the value of x that leads to maximum revenue. c. Find the maximum revenue.
Answer:
(a) The total revenue from the sale of x thousand candy bars is equal to the product of the price charged for a candy bar and the number of candy bars sold. If p(x) is the price charged for a candy bar in cents, then the revenue R(x) in dollars is given by:
R(x) = (p(x) * 1000x) / 100
R(x) = (151 - x/10) * 100x
R(x) = 15100x - 1000x^2
Therefore, the expression for the total revenue from the sale of x thousand candy bars is R(x) = 15100x - 1000x^2 dollars.
(b) To find the value of x that leads to maximum revenue, we need to find the value of x for which R(x) is maximum. We can do this by finding the derivative of R(x) with respect to x, setting it equal to zero, and solving for x. So:
R'(x) = 15100 - 2000x
Setting R'(x) equal to zero, we get:
15100 - 2000x = 0
Solving for x, we get:
x = 7.55
Therefore, the value of x that leads to maximum revenue is 7.55 thousand candy bars.
(c) To find the maximum revenue, we substitute x = 7.55 into the expression for R(x):
R(7.55) = 15100(7.55) - 1000(7.55)^2
R(7.55) = $57042.50
Therefore, the maximum revenue is $57,042.50 when 7.55 thousand candy bars are sold.
Step-by-step explanation:
The maximum revenue from the sale of candy bars in the city is $84,375. a. The expression for total revenue from the sale of x thousand candy bars can be found by multiplying the price per candy bar by the number of candy bars sold:
Total revenue = p(x) * x
Substituting the given equation for p(x), we get:
Total revenue = (151 - x/10) * x
b. To find the value of x that leads to maximum revenue, we need to take the derivative of the revenue function and set it equal to zero:
d/dx (151x - x^2/10) = 0
Simplifying and solving for x, we get:
x = 750
c. To find the maximum revenue, we substitute the value of x obtained in part (b) into the revenue function:
Total revenue = (151 - 750/10) * 750 = $84,375
Therefore, the maximum revenue from the sale of candy bars in the city is $84,375.
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In , both feet can be off the ground at once. To avoid full impact on the joints, use . can be a better activity type for overweight individuals. increase(s) the number of calories used in a workout. Running is an example of . Short, high intensity segments included in a workout is/are called .
Introducing short, high-intensity segments in a workout is called interval training. This method can help boost calorie expenditure and improve overall fitness.
When engaging in running, there are moments during the running gait cycle where both feet are off the ground simultaneously. This phenomenon is known as the flight phase. Running is considered a high-impact activity, which means it puts stress on the joints, especially for individuals who are overweight or have joint-related issues. To mitigate this impact, low-impact exercises such as swimming or cycling can be more suitable for overweight individuals as they provide cardiovascular benefits with reduced stress on the joints.
While running may not be the ideal choice for overweight individuals concerned about the joint impact, it can be advantageous for increasing the number of calories burned during a workout. Running is a weight-bearing exercise that engages multiple muscle groups and requires more energy expenditure compared to low-impact exercises. This increased calorie burn can be beneficial for weight loss and improving cardiovascular fitness.
Interval training refers to a workout method that involves alternating periods of high-intensity exercise with periods of low-intensity or rest. This technique can be applied to various exercises, including running. By incorporating short, high-intensity segments, such as sprinting or running at a faster pace, into a workout, individuals can challenge their cardiovascular system, improve endurance, and burn more calories in a shorter amount of time. Interval training is known for its efficiency and effectiveness in boosting overall fitness levels.
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A series of large winter storms drops 5 inches of rain over 2 days. How many inches of rain fell per day? Enter the number only below.
Answer:
2.5 inches
Step-by-step explanation:
Divide 5 by 2
Borachio eats at the same fast-food restaurant every day. Suppose the time X between the moment Borachio enters the restaurant and the moment he is served his food is normally distributed with mean 4. 2 minutes and standard deviation 1. 3 minutes. A. Find the probability that when he enters the restaurant today it will be at least 5 minutes until he is served. B. Find the probability that average time until he is served in eight randomly selected visits to the restaurant will be at least 5 minutes
The probability that when he enters the restaurant today it will be at least 5 minutes until he is served is 0.2676 and probability that average time until he is served in eight randomly selected visits is 0.0409.
The square root of the variance is used to calculate the standard deviation, a statistic that expresses how widely distributed a dataset is in relation to its mean. By calculating the deviation of each data point from the mean, the standard deviation can be calculated as the square root of variance.
Given that mean μ = 4.2 , standard deviation σ = 1.3
1. P(X >= 5) = P((X - μ)/σ >
= (5 - 4.2) /1.3
= P(Z ≥ 0.6154)
= 1 - P(Z < 0.6154)
= 1 - 0.7324
= 0.2676
The required probability is 0.2676.
2.Given that n = 8 then \(\bar x\) = σ/\(\sqrt{(n)\) = 1.3/√(8) = 0.4596
P(x-bar ≥ 5) = P((\(\bar x\) - μ)/σx-bar ≥ (5 - 4.2)/0.4596)
= P(Z ≥ 1.7406)
= 1 - P(Z < 1.7406)
= 1 - 0.9591
= 0.0409
The required probability is 0.0409.
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...............................
Answer:
that looks like a cat.
Step-by-step explanation:
sorry, that's probably a snake :D
8. Given: PQR and TSR are right triangles,
R is the midpoint of PT, PQ ≈ ST
Prove: PQR ≈ TSR
Answer:
The answer is below
Step-by-step explanation:
A triangle is a polygon with three sides and three angles. Types of triangles are scalene, right angled, isosceles, equilateral.
A right angled triangle is a triangle with one angle equals to 90°.
Statement Reason
∠PQR = ∠RST Given. ∠PQR = ∠RST = 90° (definition for right
angle triangle.
PQ = ST Given
PR ≅ RT Since R is the midpoint of PT, hence PR = RT
ΔPQR ≅ ΔTSR Side-angle-side triangle congruence theorem.
the Side-angle-side triangle congruence theorem
states that if two sides and an included angle of
one triangle is equal to two sides and an included
angle of another triangle, then the two triangles
are congruent. PQ=ST, PR = RT and ∠PQR = ∠TSR
WILL GIVE BRAINLIEST A student is comparing two quadratic functions,
f
(
x
)
and
g
(
x
)
. The function
f
(
x
)
is modeled by the equation
f
(
x
)
=
(
x
+
5
)
2
−
10
, and the table represents the function
g
(
x
)
.
x
0
1
2
3
4
g
(
x
)
4
5
8
13
20
What is the distance between the
y
-intercepts of
f
(
x
)
and
g
(
x
)
?
Answer: 11 units
Step-by-step explanation:
The y-intercept is when x = 0.
For f(x), \(f(0)=(0+5)^{2}-10=15\)
For g(x), \(g(0)=4\)
So, the distance is \(15-4=\boxed{11}\)
3/4 + 1/3 as a fraction
Answer:
Step-by-step explanation:
Answer:1 1/12
Step-by-step explanation: 3/4+1/3=13/12=1 1/12
How many ways can a committee of four students be selected from a 15-member club? a.15!44! b.15!11!×4! c.15×14×13 d.B and C
Answer:
B) 15! / (11! × 4!)------------------------
This is a combination of 4 out of 15.
Use combination formula:
nCr = n! / ((n - r)! × r!),where C - number of combinations, n- total number of objects, r - number of choosing from objects
Substitute 15 for n and 4 for r to get:
15C4 = 15! / ((15 - 4)! × 4!) = 15! / (11! × 4!)Correct choice is B.
Answer the question please
Answer:
Original = (8,-6) New = (0,1)
Step-by-step explanation:
Arrange the adjustments like this in the parenthesis of the original point
(8 - 8, -6 +7)
Then do the math and get (0,1)
Simplify (-8a¹b) (3a³b).
a) -24a7b²
b) -5a7b²
c) -5a¹26
d) -24a¹26²
An assignment of probability must obey which of the following?
A) the probability of any event must be a number between 0 and 1, inclusive
B) the sum of all the probabilities of all outcomes in the sample space must be exactly 1
C) it must obey the addition rule for disjoint events
D) all of the above
An assignment of probability must obey all of the following:
A) the probability of any event must be a number between 0 and 1, inclusive
B) the sum of all the probabilities of all outcomes in the sample space must be exactly 1
C) it must obey the addition rule for disjoint events.
An assignment of probability requires adherence to certain principles. Firstly, the probability of any event must be a number between 0 and 1, inclusive. Probability values less than 0 or greater than 1 are not valid since they fall outside the range of possible probabilities.
Secondly, the sum of all the probabilities of all outcomes in the sample space must be exactly 1. This ensures that the entire sample space is accounted for and that there are no missing or extra probabilities.
Lastly, the assignment of probability must obey the addition rule for disjoint events. According to this rule, if two events are disjoint (mutually exclusive), meaning they cannot occur simultaneously, then the probability of the union of these events is equal to the sum of their individual probabilities.
Therefore, to ensure a valid assignment of probability, all of the conditions mentioned in options A, B, and C must be satisfied. Hence, the correct answer is option D, "all of the above."
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in theyx, y-plane above, the circle has center (h, k)left parenthesis, h, comma, k, right parenthesis and radius 10. what is the value of k ?
We can say that the value of k will be equal to the y-coordinate of the center of the circle (since k represents the y-coordinate of the center).
To answer this question, we need to use the equation of a circle:
(x - h)^2 + (y - k)^2 = r^2
Where h and k represent the coordinates of the center of the circle, and r represents the radius. In this case, we are given that the circle has center (h, k) and radius 10. So we can write:
(x - h)^2 + (y - k)^2 = 10^2
We are asked to find the value of k. To do this, we need to look at the equation of the circle and notice that the y-coordinate is paired with k. This means that we can isolate k by rearranging the equation as follows:
(y - k)^2 = 10^2 - (x - h)^2
y - k = ±√(10^2 - (x - h)^2)
k = y ±√(10^2 - (x - h)^2)
Since we don't have any information about the x-coordinate, we can't solve for a specific value of k. However, we can say that the value of k will be equal to the y-coordinate of the center of the circle (since k represents the y-coordinate of the center). Therefore, the answer is:
k = y
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Simplify the radical expression.
√16x^2
Answer:
4x
Step-by-step explanation:
The square root of 16 is 4 because 4 times itself is 16.
The square root of x^2 is x because x times itself is x^2.
Colored pencils sell for $3.95.
The price after tax is $4.18.
What is the percent of tax? Round to the nearest whole percent
Answer:4%
Step-by-step explanation:
two numbers are independently selected from the set of positive integers less than or equal to $5$. what is the probability that the sum of the two numbers is greater than their product? express your answer as a common fraction.
The probability of the sum of two integers is greater than the product is equal to 2 / 5.
Let 'A' be the set of positive integers less than or equal to 5.
A = { 1, 2, 3, 4, 5}
Sum of two numbers is greater than the product of the numbers.
1 × 1 = 1 and 1 + 1 = 2
1 × 2 = 2 and 1 + 2 = 3
1 × 3 = 3 and 1 + 3 = 4
1 × 4 = 4 and 1 + 4 = 5
1 × 5 = 5 and 1 + 5 = 6
2 × 1 = 2 and 2 + 1 = 3
3 × 1 = 3 and 3 + 1 = 4
4 × 1 = 4 and 4 + 1 = 5
5 × 1 = 5 and 5 + 1 = 6
2 × 2 = 4 and 2 + 2 = 4
Total possibilities = 5 × 5
= 25
Favourable outcomes = 10
Total number of outcomes = 25
Probability of sum of two numbers greater than the product
= 10 / 25
= 2 / 5
Therefore, the probability of the sum of two numbers is greater than the product is equal to 2/ 5.
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I need help what is 15 times 238
Answer:
hello.....................
Step-by-step explanation:
Answer:
3,570
Step-by-step explanation:
why did you not look it up on the internet lol
Q1. A heavy general purpose truck costs $12,000 has a life of six years with a $2,000 SV. using the
MACRS with a GDS recovery period of five years. What is the BV of the equipment at the end of
(including) year four?
IN EXCEL WITH EXPLANATION PLEASE
Answer:
Therefore, the book value of the equipment at the end of year four (including year four) is $2,880.
Step-by-step explanation:
To calculate the book value of the equipment at the end of year four using the MACRS method with GDS recovery period of five years, we can use the following steps in Excel:
1. Open a new Excel spreadsheet and create the following headers in row 1: Year, Cost, Depreciation Rate, Annual Depreciation, Cumulative Depreciation, and Book Value.
2. Fill in the Year column with the years 1 through 6 (since the truck has a life of six years).
3. Enter the cost of the truck, $12,000, in cell B2.
4. Use the following formula in cell C2 to calculate the depreciation rate for each year:
=MACRS.VDB(B2, 5, 5, 1, C1)
This formula uses the MACRS.VDB function to calculate the depreciation rate for each year based on the cost of the truck (B2), the GDS recovery period of five years, the useful life of six years, the salvage value of $2,000, and the year (C1).
5. Copy the formula in cell C2 and paste it into cells C3 through C7 to calculate the depreciation rate for each year.
6. Use the following formula in cell D2 to calculate the annual depreciation for each year:
=B2*C2
This formula multiplies the cost of the truck (B2) by the depreciation rate for each year (C2) to get the annual depreciation.
7. Copy the formula in cell D2 and paste it into cells D3 through D7 to calculate the annual depreciation for each year.
8. Use the following formula in cell E2 to calculate the cumulative depreciation for each year:
=SUM(D$2:D2)
This formula adds up the annual depreciation for each year from D2 to the current row to get the cumulative depreciation.
9. Copy the formula in cell E2 and paste it into cells E3 through E7 to calculate the cumulative depreciation for each year.
10. Use the following formula in cell F2 to calculate the book value of the equipment for each year:
=B2-E2
This formula subtracts the cumulative depreciation for each year (E2) from the cost of the truck (B2) to get the book value.
11. Copy the formula in cell F2 and paste it into cells F3 through F7 to calculate the book value for each year.
12. The book value of the equipment at the end of year four (including year four) is the value in cell F5, which should be $2,880.
1
A line segment has the endpoints (-7,-4) and (9,8). What are the coordinates of the
midpoint of this line segment?