find an angle α that is coterminal with an angle, in radians, measuring −5π2, where 0≤α<2π. give your answer as an exact answer involving π, if necessary.

Answers

Answer 1

Coterminal angles are angles in standard position with the same terminal side. Therefore, an angle α that is coterminal with an angle measuring −5π/2 radians, where 0 ≤ α < 2π is 3π/2.

So to find an angle α that is coterminal with an angle, in radians, measuring −5π/2, we need to add or subtract a full rotation of 2π.0 ≤ α < 2π gives the domain of angles that lie within one complete revolution (0 to 360°), which corresponds to an interval of 0 to 2π in radians. We want to find an angle α that is coterminal with −5π/2 (in the third quadrant) and lies between 0 and 2π.

Since 2π is equivalent to 0 radians, we can add 2π to −5π/2 to get an angle in the interval [0, 2π].

-5π/2 + 2π = -π/2

We know that -π/2 radians is in the fourth quadrant, so we add another 2π to find a coterminal angle in the first quadrant.

-π/2 + 2π = 3π/2

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Related Questions

Forces are applied along various points on a lever arm as shown below.Calculate the net torqu and describe the direction of rotation from the axis of rotation that would result in a net moment(torque) of zero

Forces are applied along various points on a lever arm as shown below.Calculate the net torqu and describe

Answers

The net torque applied on the lever be 180 N-m.

The direction of torque is perpendicular to both force and axis of lever and it acts outwards.

The outcome would be a net moment (torque) of zero for any force at any position on the axis of rotation for which the torque is 180 N-m and directed in the opposite direction.

What is torque?

Torque is a unit of measurement for the force that can cause an item to revolve about an axis. Torque accelerates an object in an angular direction, much like force does in linear kinematics.

A torque is a vector quantity. The torque vector's direction is determined by the force acting on the axis.

Torque is defined mathematically as: force × perpendicular distance.

So, net torque applied on the lever :

= + (15N)×(20m) + (5N)×(15m) - (5N)×(5m) -(10N)×(17m)

= 180 N-m.

Additionally, torque works outward and has a direction that is perpendicular to both force and axis.

The outcome would be a net moment (torque) of zero for any force at any position on the axis of rotation for which the torque is 180 N-m and directed in the opposite direction.

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Which of the following characterizes the particles in this diagram?

A. Two positive charges
B. One positive charge and one negative charge
C. Two negative charges
D. Two neutral charges

Which of the following characterizes the particles in this diagram?A. Two positive chargesB. One positive

Answers

Answer:

B

Explanation:

One positive charger and one negative charger

why does a bus resist changes in motion more than a motorcycle

Answers

Answer:

inertia is the resistance to change, so it would make sense for the bus to not change direction and would then also resist changes in motion where as a motorcyle whouldnt be as resistent

Explanation:

Answer:

The bus has more mass than the motorcycle.

Explanation:

Higher masses resist the change in motion greater than smaller ones.

What is the density of an object with the mass of 125g and a volume of 176 m

Answers

Answer:

the density is mass over volume, so you divide 125g over 25 cm3, giving a result of 5 g/cm3

Answer:

The density is mass over volume

so you divide 125g over 25 cm3

giving a result of 5 g/cm3

you welcome have a good day!

What happens to the energy of a wave if the amplitude is doubled?

Answers

It essentially quadruples the energy.

Explanation if you’d like:
The energy transported by a wave is directly proportional to the square of the amplitude so. whatever change occurs in the amp, the square that affect infects energy. This means the doubling of the amplitude results in a quadrupling of the energy

3. Ryder hits a tennis ball 2.0 m from the ground. The initial velocity is directed horizontally and is 17.2 m/s. The ball hits the ground 11.0 m away from the player after passing over a 1.0 m high net that is 6.0 m horizontally from the player.
2K,1C
4T,1C

How long does it take for the ball to reach the ground?
What was the magnitude of the final velocity of the ball?

Answers

Answer:

Explanation: 6 m / s , with the center of the ball leaving the racquet horizontally 2 . 37 m above the court surface. The net is 12 m away and 0 . 90 m high.

A mass of 0.450 kg rotates at costant speed with a period of 1.45s at a radius R of 0.140 m in the apparatus used in this laboratory. What is the rotation period for a mass of 0.550 kg at the same radius? Show your work. (Extra information that might or might not be important: For the apparatus used in this laboratory, the centripetal force is the same for a fixed radius R of rotation. This wasn't stated in this question but it was in the question before it.)

Answers

Rotation period for a mass of 0.550 kg at the same radius is 1.45 s.

The rotation period of a mass in circular motion is given by:

T = 2πR/v

where T is the period, R is the radius of the circular path, and v is the velocity of the mass.

For the first mass with a mass of 0.45 kg, radius R of 0.140 m, and period T of 1.45 s, we can calculate the velocity as follows:

v = 2πR/T = 2π(0.140 m)/(1.45 s) = 0.6066 m/s

Now, we can use the velocity and radius values to find the period for the second mass with a mass of 0.550 kg:

T = 2πR/v = 2π(0.140 m)/(0.6066 m/s) = 1.45 s

Therefore, the rotation period for a mass of 0.550 kg at the same radius is 1.45 s.

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What is the frequency of a wave with a period of 8s?

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I don’t know the answer

distinguish between refraction,reflection and total internal reflection

Answers

Refraction, reflection, and total internal reflection are distinct optical phenomena. They involve the bending, bouncing, and complete reflection of light, respectively. These phenomena have practical applications and contribute to our understanding of light behavior and optical devices.

Refraction, reflection, and total internal reflection are fundamental phenomena associated with the behavior of light when it interacts with different mediums or interfaces. Let's explore each of these concepts and understand their distinctions:

1. Refraction:

Refraction refers to the bending of light as it passes from one medium to another with a different optical density. When light encounters a change in medium, its speed and direction change, causing the light ray to deviate. This deviation occurs because light travels at different speeds in different materials. The amount of bending depends on the angle of incidence and the refractive indices of the two mediums involved. Snell's law governs the mathematical relationship between the angles of incidence and refraction. Refraction is responsible for various optical phenomena, such as the bending of light in lenses and the dispersion of white light into its constituent colors in a prism.

2. Reflection:

Reflection occurs when light encounters a boundary between two mediums and bounces back into the same medium from which it originated. The angle of incidence is equal to the angle of reflection, according to the law of reflection. Reflection plays a fundamental role in our ability to see objects, as light rays reflected from surfaces enter our eyes. Mirrors and other reflective surfaces exploit the principle of reflection.

3. Total Internal Reflection:

Total internal reflection occurs when light travels from a medium with a higher refractive index to a medium with a lower refractive index, and the angle of incidence exceeds a critical angle. In such cases, instead of bending or refracting, the light is completely reflected back into the denser medium. Total internal reflection is responsible for various phenomena, including the shiny appearance of diamonds and the working of optical fibers. It enables light to propagate through the fiber by repeated internal reflections.

In conclusion, refraction, reflection, and total internal reflection are distinct optical phenomena. Refraction involves the bending of light when it transitions between different mediums, reflection refers to the bouncing back of light from a surface, and total internal reflection occurs when light is reflected back into a denser medium at an angle greater than the critical angle. These phenomena have practical applications and contribute to our understanding of light behavior and the functioning of various optical devices.

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For the following two distributions of density of some material,

(i) rho = t −1/2 exp (− x2 /(4µt)) ,

(ii) rho = rho0 − 2x ,

1. Sketch rho as a function of x for a couple of different times.

2. Verify that rho satisfies the diffusion equation

∂rho/∂t = µ ∂2rho/∂x2 .

3. What is the flux of material, q, past any point x at any time t?

Answers

The density distributions (i) and (ii) can be sketched as functions of x for different times, providing insights into their behavior over time.

How can we demonstrate that the density distributions (i) and (ii) satisfy the diffusion equation?

The flux of material (q) past any point x at any time t can be determined by multiplying the density gradient (∂rho/∂x) with the diffusion coefficient µ. This represents the flow of material per unit area perpendicular to the x-axis, indicating the rate of material transport.

To sketch the density distributions (i) and (ii), we can plot the density values as a function of x for various time values. For distribution (i), the density decreases with increasing distance from the origin, forming a bell-shaped curve that decreases over time.

The rate of decrease depends on the diffusion coefficient µ. For distribution (ii), the density linearly decreases with increasing distance from the origin and remains constant over time. These sketches provide visual representations of how the density of the material changes spatially and temporally.

To verify that the density distributions satisfy the diffusion equation, we need to compare the equations with the given distribution forms.

By taking the partial derivative of density with respect to time (∂rho/∂t) and the second partial derivative of density with respect to x (∂²rho/∂x²), we can confirm whether they are proportional to each other with a factor of µ. If the resulting equations match, it indicates that the distributions satisfy the diffusion equation.

The flux of material (q) past any point x at any time t is determined by multiplying the density gradient (∂rho/∂x) with the diffusion coefficient µ. This represents the rate at which material is flowing through a specific point in the x-direction.

It provides information about the amount of material passing through a given area per unit time, highlighting the transport properties of the material.

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Match the following temperatures in °C and Kelvin
0°C
150 K
20 °C
500 K
:: 227 °C
III
:: 293 K
:: 273 K
:: -123 °C

Answers

The temperature in Celsius and Kelvin are;

0°C = 273 K150 K = -123⁰C20 ⁰C = 293 K500 K  = 227⁰C

What is the measure of the following temperatures?

The temperature of a body is the measure of the degree of hotness or coldness of a body.

Also temperature can be defined as the measure of the average kinetic energy of a body.

The conversion of the temperature in degrees Celsius to kelvin is calculated as follows;

0°C = 273 K

150 K = 150 - 273 = -123⁰C

20 ⁰C = 20 + 273 = 293 K

500 K = 500 - 273 = 227⁰C

Thus, to convert from degrees Celsius to Kelvin we simply add 273 K and to convert from Kelvin scale to Celsius scale we simply subtract 273 from the Celsius temperature.

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. A marble sphere with a diameter of 1/4 inch is fully immersed in the oil of density 0.961 g/cm3 . Calculate the buoyant force exerted on the marble sphere by the oil.

Answers

Answer:

See below    ( was it REALLY 1/4 INCH??)

Explanation:

Calculate the volume of the sphere

v = 4/3 pi r^3

 this times the density of the oil will give g displacement

   then f = ma

4/3 pi (.25 in  * 2.54 cm/inch) ^3  * .961 = 1.0307 gm

1.0307 gm   is   .0010307 kg

f = ma = .0010307 * 9.8 = .0101 N

Describe how reactivity changes as you go down Group 1A.

Answers

Answer:

it is a the answer is a btw

Explanation:

a ball is tossed vertically into the air. when the ball reaches its highest point, what is its acceleration

Answers

Answer:

9.81 m/s^2 downwards

Explanation:

At the top only weight acts on the ball. Therefore,

\(net \: force = ma \\ weight = ma \\ mg = ma \\ a = g \\ a = 9.81 {ms}^{ - 2} \)

The handles of the tools like screwdrivers and pliers used by electricians for repair work usually have plastic or rubber covers on them. Can you explain why?

Answers

Answer:

Rubber or plastic covers are bad conductors of electricity. So they do not allow the electric current to pass through it.

Explanation:

Rubber and plastic are bad conductors of electricity, therefore when handling a tool with a rubber handle, the electricity will not pass through it.

Answer:

rubber and plastic are insulators and are bad conductors of electricity

Incident ray X passes parallel to the principal axis of a concave lens. Incident ray Y passes parallel to the principal axis of a convex lens.

How do the rays behave differently after passing through each lens?

Ray X continues moving in the same direction, and ray Y refracts and passes through the focal point located behind the lens.
Both rays refract and move as though they passed through the focal point.
Ray X appears as though it passed through the focal point in front of the lens, and ray Y passes through the focal point on the other side of the lens.
Both rays continue moving in the same direction.

Answers

Answer:

Explanation:

It would be option C. Ray x appears as though it passed through the focal point in front of the lens, and ray Y passes through the focal point on the other side of the lens.

Answer:

c. Ray X appears as though it passed through the focal point in front of the lens, and ray Y passes through the focal point on the other side of the lens.

Explanation:

Consider a system of two rigid bodies, where the entire system is in planar motion, and the more massive of the two bodies is pinned to ground. Which general location is the best choice (most convenient as it does not require tracking throughout the collision) to apply angular momentum conservation

Answers

The best location to apply angular momentum conservation in this system is at the point of contact between the two rigid bodies.

Since the more massive body is pinned to the ground, it cannot rotate around any axis. Therefore, the angular momentum of the system can only change due to the motion of the smaller body. The point of contact between the two bodies is the location where the angular momentum of the smaller body can be easily tracked, as it is the point at which the smaller body is in contact with the ground and the larger body. Applying angular momentum conservation at this point means that we only need to consider the motion of the smaller body and its change in angular momentum during the collision, rather than tracking the angular momentum of the entire system.

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2. An airboat with mass 3.50 x 102 kg, including the passenger, has an engine that produces a net horizontal force of 7.70 x 102 N, after accounting for forces resistance. a. Find the acceleration of the airboat b. Starting from rest, how long does it take the airboat to reach a speed of 12.0 m/s

Answers

The acceleration of the airboat  is 2.2m/s^2 and starting from rest, it take the airboat to reach a speed of 12.0 m/s is 5.45s

Given mass of airboat (m) = 3.50 x 10^2kg

horizontal force of engine (F) = 7.70 x 10^2N

We know that from newtons laws of motion Force = mass x acceleration such that F = ma

(a) Now a = F/m = 7.70 x 10^2 / 3.50 x 10^2 = 2.2m/s^2

(b) Initial speed of airboat (u) = 0m/s

final speed (v) = 12m/s

We have acceleration a = 2.2m/s

Then we have another newtons law as: v = u+ at where t is the time taken

So t = v/a = 12/2.2 = 5.45s

Hence it takes to reach 5.45s a speed of 12m/s

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What are the four things that are dependent on the size of an electromagnetic force?

Answers

answer: loop countthe currentthe wire size and the presence of an iron core

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The four things that are dependent on the size of an electromagnetic force are magnitude of force, distance, current and the magnetic strength.

What is electromagnetic force?

An electromagnetic force is generated from a strong electric field associated with a magnetic field. A looping current generates a magnetic field around it where, the direction of magnetic field lines are perpendicular to the electric field.

The strength of electromagnetic field definitely depends on the wire size, number of turnings, material of coli and its magnetic strength. There are both electromagnetic force of attraction and repulsion as well.

The things which are dependent on the electromagnetic force are the distance over it can act, the loop current, magnetic strength and its magnitude of magnetic field.

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you pull a box with a constant force of 250 n. the box moves 10 m along a straight path on a rough surface at a constant speed. how much thermal energy is generated in the system of the box and the rough surface?

Answers

The thermal energy of the box which is pulled with a force of 250 N to a distance of 10 meters is 2500 J

The force to pull the box = 250 N

The box is moved to a distance of 10 meters

The thermal energy can be found using the formula,

                    W = F x d

where W is the thermal energy

           F is the Force

           d is the distance moved

Let us substitute the known values in the above equation, we get

                      W = 250 x 10

                          = 2500 J

Therefore, the thermal energy of the box is 2500 J

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When a bouncy ball is dropped from a second floor window, at what point is the kinetic energy highest?

A. Just after the ball dropped
B. Just before the ball hits the ground for the first time
C. After the ball has bounced several time
D. after the ball bounces away into the bushes, never to be found again ​

Answers

Answer:

Explanation:

Because the total energy available to the ball doesn't change whatsoever during its entire trip from the window to the ground,

TE = KE + PE which says that the total energy available to a system is equal to the kinetic energy of the system plus the potential energy, and that this value will not ever change (because energy cannot be created or destroyed. Sound familiar?) If the ball is being held still before it is dropped from some height off the ground, it is here that the total energy can be determined, and that total energy at this point is all potential, since the ball is not moving while someone is holding it and getting ready to drop it. The SECOND it starts to fall, the potential energy begins to be converted to kinetic. As the potential energy is losing value, the kinetic is gaining it at the same rate (again, energy doesn't just disappear; it has to go somewhere. Here, it goes from potential to kinetic a little at a time). When the ball finally hits the ground, or an INSTANT BEFORE it hits the ground, the potential energy is 0 because the height of something on the ground has a height of 0. At this instant, right before the ball hits the ground, is where the KE is the greatest. All the energy at that point has been converted from potential to kinetic.

Long story short, choice B is the one you want.

the motions of the planets against the background stars in our sky can best be described as

Answers

The motions of planets against the background stars in our sky are not uniform and follow a complex pattern.

The apparent motion of planets is caused by their orbit around the sun, as well as the rotation of the Earth on its axis. The planets move in an eastward direction relative to the stars, but sometimes they appear to move westward. This is known as retrograde motion and occurs when the Earth overtakes and passes the planet in its orbit around the sun. The pattern of retrograde motion is different for each planet, depending on the length of its orbit and its distance from the sun. The outer planets, such as Jupiter and Saturn, have longer orbits and move more slowly than the inner planets, such as Mercury and Venus.

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A rocket has a mass of 80,000 kg and accelerates at a rate of 35 m/s2. Calculate the force that provides this acceleration. Give your answer in newtons.

Answers

The force that causes an acceleration of 35 m/s² with a mass of 80,000 kg is 2,800,000 N.

Solution:

Force (N) = mass (kg) × acceleration (m/s²)

According to this question, a rocket has a mass of 80,000 kg and accelerates at a rate of 35 m/s². The force can be calculated as follows:

F = 80,000kg × 35m/s²

F = 2,800,000N

The force is equal to the outlet mass flow rate times the outlet velocity times the free stream mass flow rate minus the free stream velocity. Acceleration is the rate of change of velocity over a specified time. Calculate acceleration by dividing the change in velocity by the change in time.

This characteristic is known as the velocity ratio  and is calculated by dividing the distance traveled by the force by the distance traveled by the load. Force is push or pull. Shear is the component of force acting perpendicular to a plane. Push is force, but not all force counts as push. So they are not exactly the same and the given statement is incorrect.

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The right answer is "2800000 N"

Answer explanation:

Force = mass × acceleration

= 80,000 kg × 35 m/s2

= 2,800,000 N.

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What is another name for elastic energy

Answers

Another name for elastic energy is potential energy

The world’s fastest elevator is in Taipei, Taiwan. It can lift passengers 1,010 m in 39 s. What is the speed of this elevator?

Answers

Answer: 25.90 m/sec

Explanation:

Speed = Distance / Time

Speed = 1010 / 39

Speed = 25.90 m/s

The long, light-colored lines extending from many craters on the Moon are called rays and are ______.

Answers

Answer:

The long, light-colored lines extending from many craters on the Moon are called rays and are "crater rays".

Explanation:

Hope this helps :)

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Imagine that you are a circus performer riding a uni-cycle (forwards) across the stage. What is the direction of the angular velocity of the single wheel?

Answers

The direction of the angular velocity of the single wheel is the clockwise direction

Angular velocity

The angular velocity is the number of revolutions per second of the single wheel. It is given by ω = v/r where

v = linear speed of the wheel and r = radius of the wheel.Direction of the angular velocity of the single wheel

Since the wheels moves forward and the velocity of the wheel is always tangential to the wheel causing it to move forward, its angular velocity is in the clockwise direction

So, the direction of the angular velocity of the single wheel is the clockwise direction

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The angular velocity is also known as the rotational velocity. The direction of the angular velocity of the single wheel is clockwise.

What is angular velocity?

The angular velocity or rotational velocity, also known as the angular frequency vector, is a vector measure of rotation rate that relates to how fast an item spins or revolves relative to another point, i.e. how quickly the angular position or orientation of an object changes with time.

\(\omega = \dfrac vr\)

where v is the velocity and r is the radius.

The Direction of angular velocity is that the wheel goes forward and the velocity of the wheel is always tangential to the wheel, forcing it to move forward, therefore, the angular velocity is clockwise.

Hence, the direction of the angular velocity of the single wheel is clockwise.

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Match each word with its definition. Match the items in the left column to the items in the right column.

1. displacement
2. distance
3. scalar
4. mass
5. kinematics
6. vector
7. time

A. the length of the entire path an object travels from start to end
B. the change of position of an object from start to finish
C. the property a body possesses as evidenced by its inertia
D. a quantity expressed as a magnitude and a unit
E. displacement is this type of quantity
F. an area of physics dealing with mathematical methods of describing motion
G. that which allows us to place events in their order of happening

Answers

The items in the left column matched to the items in the right column:

A. the length of the entire path an object travels from start to end - Distance B. the change of position of an object from start to finish - displacement C. the property a body possesses as evidenced by its inertia - mass D. a quantity expressed as a magnitude and a unit - Scaler E. displacement is this type of quantity - vector F. an area of physics dealing with mathematical methods of describing motion - Kinematics G. that which allows us to place events in their order of happening - time.

What is distance?

This is the length between two different points; say point A to B. It is measured in meters ( m).

In conclusion, the length of the entire path an object travels from start to end is regarded as distance

Vectors are quantities which have both magnitude and direction.

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: In the spring of 2021, the New Horizons spacecraft reached a distance of 50 astronomical units ("AU") from Earth. At that time, how many km was New Horizons from Earth? Note: One astronomical unit is the distance from the Earth to the Sun or about 150 million km. Question 3 (6 points): The planet Mars completes one orbit of the Sun in 687 days. Use scientific notation to express this time in units of seconds. You may use the character ∧
for the power of 10 , like 4.5×10 ∧
4 (4.5 times 10 to the 4 th power).

Answers

The time taken by the planet Mars to complete one orbit of the Sun is 5.94 x 10⁷ seconds.

Given information: In the spring of 2021, the New Horizons spacecraft reached a distance of 50 astronomical units ("AU") from Earth. One astronomical unit is the distance from the Earth to the Sun or about 150 million km.

Calculation: To find how many km was New Horizons from Earth, we need to multiply the distance in AU by the conversion factor. 1 AU = 150 million km 50 AU = 50 x 150 million km = 7.5 billion km Thus, the New Horizons spacecraft was 7.5 billion km from Earth in the spring of 2021. Now, let's move on to the second question. The planet Mars completes one orbit of the Sun in 687 days. We need to express this time in seconds using scientific notation.

To convert days to seconds, we need to multiply the number of days by the conversion factor. 1 day = 86400 seconds 687 days = 687 x 86400 seconds= 5.94 x 10⁷ seconds (using scientific notation) Therefore, the time taken by the planet Mars to complete one orbit of the Sun is 5.94 x 10⁷ seconds.

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A massless rope passes over a massless pulley suspended from the ceiling. A 4-kg block is attached to one end and a 5-kg block is attached to the other end. The acceleration of the 5-kg block is

Answers

The acceleration on the 5kg block is 1.088m/s^2

Data;

mass(a) = 4kgmass (b) = 5kgacceleration of the 5kg block.The Acceleration on the 5kg block

To solve this question, we just need to use Newton's second law of motion which states that "the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it."

\(F_n_e_t = M_t_o_t_a_l * a\\F = ma\\F_n_e_t = mg\\\)

But then the force on both sides will be

\(mg = ma\\5g - 4g= (4+5) a\\(5-4)g = 9a\\g = 9a\\a = \frac{g}{9} \\a = \frac{9.80}{9} \\a = 1.088 m/s^2\)

The acceleration on the 5kg block is 1.088m/s^2

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