find a coefficient for the linear equation ax-y=4 such that the graph of the equation would pass through the point M(3,5)

Answer:

153.6

Step-by-step explanation:

Answer:

153.6

Step-by-step explanation:

32x4=128

128x3=384

384x2=768

768/5=153.6

Answer:

Step-by-step explanation:

Remark

If the entire circle was shaded the radius sweeping out the circle would go through 360 degrees.

So the way to solve this problem is to multiply the entire area of the circle by (81/360)

Area of the sector = (81/360) * pi * r^2

pi = 3.14

r =8.91 cm

Area of the sector = (81/360) * 3.14 * 8.91^2

Area of the sector = 56.09

Rounded to the nearest tenth, the answer is 56.1

Answer: 56.1 cm^2

IT is Given triangle NED, and that sin(N) = 4/5, tan(N) will be equal to 4/3.

Trigonometric ratio can be defined in terms of ratios of perpendicular, bases and hypotenuse. These are defined only in right angled triangles (triangles whose one angle is of 90 degree measure).

Trigonometric ratios are for a right angled triangle are from the perspective of a particular non-right angle.

In a right angle triangle, the two such angles are there which are not right angled(not of 90 degrees) and the slant side is called hypotenuse.

WE have been Given that a triangle NED, and that sin(N) = 4/5,

we know that sin N = perpendicular/ hypotenuse

sin(N) = 4/5

Then base² = hypotenuse²  - perpendicular²

Base = 3

tan(N) = perpendicular/ Base

tan(N) = 4/3

Therefore, the tan(N) will be equal to  4/3.

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Answer:

Step-by-step explanation:

The starting equation is

12-(3x+13)=0

First add 3x+13 to both sides so that only 12 is on the left

12=3x+13

now subtract 13 from both sides to isolate your variable

-1=3x

Finally divide both sides by 3 to get your final answer

x=-1/3

Answer:

Step-by-step explanation:

The determinant is the price of related goods, specifically the price of fuel. The increase in fuel prices would lead to a decrease in the demand for Ford F150 trucks, shifting the demand curve to the left.

The price of related goods is an important determinant of demand.

The drastic increase in fuel prices is likely to shift the demand curve for Ford F150 trucks to the left.

This is because consumers tend to reduce their demand for vehicles with lower fuel efficiency when fuel prices increase.

The determinant of this shift in demand is the price of related goods, specifically, the price of gasoline.

When the price of gasoline increases, it affects the demand for vehicles that are less fuel-efficient, such as trucks.

Therefore, the price of related goods is an important determinant of demand.

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Answer:

what grade is this

Step-by-step explanation:

I can check it and then I'll get back to you in 30 min

In general, observational studies are more problematic than randomized controlled trials because they can produce spurious relationships.

Observational studies rely on the natural variation in exposures and outcomes that occur in the population, without any intervention or manipulation by the researcher.

This can lead to confounding variables, which are factors that are associated with both the exposure and the outcome and can produce a false association between them.

Randomized controlled trials, on the other hand, assign participants to different exposure groups at random, which reduces the risk of confounding and allows for a more accurate assessment of causality.

Therefore, researchers must be cautious when interpreting observational studies and consider the potential for spurious relationships.

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Step-by-step explanation:

The formula for probability is favourable outcome/ Total outcome. So the answer might be 7/30.

Answer:

slope: -1/2

y-intercept: 8

Step-by-step explanation:

y=mx+b is the linear equation

m=slope

b=y-intercept

To evaluate the integral ∫2 tan^3(x) sec(x) dx, we can use the substitution method and trigonometric identities. By making suitable substitutions and applying trigonometric identities, we can simplify the integral and find its antiderivative.

Let's start by making the substitution u = tan(x). This substitution helps simplify the expression involving tangent and secant functions.

Differentiating both sides with respect to x, we get du/dx = sec^2(x).

Rearranging the equation, we have dx = du/sec^2(x).

Now, let's substitute the values in the integral:

∫2 tan^3(x) sec(x) dx = ∫2 u^3 du/sec^2(x)

                     = ∫2 u^3 du/(1 + tan^2(x))

Using the identity 1 + tan^2(x) = sec^2(x), we can simplify further:

∫2 u^3 du/(1 + tan^2(x)) = ∫2 u^3 du/sec^2(x)

                         = ∫2 u^3 du/((1 + u^2)/1)

                         = ∫2 u^3 du/(1 + u^2)

Integrating with respect to u, we have:

= (1/4) u^4 + C

= (1/4) tan^4(x) + C

Therefore, the antiderivative of 2 tan^3(x) sec(x) dx is (1/4) tan^4(x) + C, where C is the constant of integration.

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Answer:

672 had dark hair, 592 had blond hair, and 48 had red hair

Step-by-step explanation:

To solve this problem, we need to first find the total number of people for each hair color based on the given ratio.

Let's start by finding the common factor that we can use to scale the ratio up to the total number of people, which is 1,312:

42 + 37 + 3 = 82

We can then divide 1,312 by 82 to get the scaling factor:

1,312 ÷ 82 = 16

This means that for every 16 people, there are 42 with dark hair, 37 with blond hair, and 3 with red hair.

To find the actual number of people with each hair color in the town meeting, we can multiply the scaling factor by the number of people for each hair color in the ratio:

Dark-haired people: 42 × 16 = 672

Blond-haired people: 37 × 16 = 592

Red-haired people: 3 × 16 = 48

Therefore, there are 672 people with dark hair, 592 people with blond hair, and 48 people with red hair at the town meeting.

Those activities that enable a person to describe in the detail the system that solves the need is called "System design".

The method of defining the components of a system consists, modules, and components, the various interfaces of those components, and the data that flows through that system is known as system design.

Some key features regarding the system design are-

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Given:

The graph passes through the points (0,-20) and (4,10).

To find:

The equation of line that most closely represents the line depicted in the graph.

Solution:

If a line passing through two points, then the equation of line is

\(y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)\)

The given line passes through the points (0,-20) and (4,10). So, the equation of line is

\(y-(-20)=\dfrac{10-(-20)}{4-0}(x-0)\)

\(y+20=\dfrac{10+20}{4}(x)\)

\(y+20=\dfrac{30}{4}x\)

\(y+20=\dfrac{15}{2}x\)

Subtracting 20 from both sides, we get

\(y=\dfrac{15}{2}x-20\)

The function form is

\(f(x)=\dfrac{15}{2}x-20\)

f of x equals fifteen halves times x minus 20.

Therefore, the correct option is B.

Answer:

Your answer is B

Step-by-step explanation:

f of x equals fifteen halves times x minus 20

A uniformly better estimator of θ can be obtained using the Rao-Blackwell theorem.

The Rao-Blackwell theorem states that if we have an unbiased estimator and a sufficient statistic, then we can obtain a uniformly better estimator by taking the conditional expectation of the estimator given the sufficient statistic.

In this case, since T(X) = X(1) is a jointly sufficient statistic for θ and E[X(1)] = θ, we can use the Rao-Blackwell theorem to improve the estimator.

Let's denote the improved estimator as θ' and calculate its conditional expectation given T(X):

E[θ' | T(X)] = E[X(1) | T(X)]

Since T(X) = X(1), we have:

E[θ' | T(X)] = E[X(1) | X(1)] = X(1)

Therefore, the improved estimator θ' is simply X(1), the first order statistic of the random sample.

This improved estimator is uniformly better than X(1) because it has the same unbiasedness property as X(1) but with potentially lower variance. By conditioning on the sufficient statistic, we have utilized more information from the data, leading to a more efficient estimator.

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The formula for Integration of UV:

f the two functions are of the type u,v then the formula for the Integration of u and v may be written as follows: ∫ uv dx = u ∫ v dx – ∫ (u' ∫ v dx) dx.

Integration of Trigonometric functions involves basic simplification techniques. These techniques use different trigonometric identities which can be written in an alternative form that are more amenable to integration.

Identify the integral of the form ∫u.vdx. Choose u(x) using the LIATE rule and differentiate it. Choose v(x) and Integrate dv. Then plug in all the values obtained so far, in the formula ∫u.v = u. ∫v.dx- ∫( ∫v.dx.u'). dx and evaluate the integral.

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Answer:

\( \sqrt{50 } \times \sqrt{4} \)

Answer:

8

Step-by-step explanation:

-3 + 11 = 8

blank = 8

\(\huge\purple {\mid {\fbox {\tt {Solution!}}\mid}}\)

\( \longmapsto- 3 + 11 \\ \longmapsto8\)

Answer:B Get a more random person sample from the town

Step-by-step explanation:

Answer:

its A

Step-by-step explanation:

i just did this

Step-by-step explanation:

13.8564064606

hope it helps

Answer

(x2−2–√)2=2(x2−2)2=2

x2−2–√=±2–√x2−2=±2

x2=2–√±2–√x2=2±2

x2=0x2=0 or 22–√22

x=0x=0 or ±22–√−−−−√±22

x=0,±8−−√4x=0,±84

Step-by-step explanation:

hope it helps

Answer:

10.50$

Step-by-step explanation:

Answer:

PT = 24

Step-by-step explanation:

PT = TQ

3x + 6 = 5x - 6

12 = 2x

x = 6

PT = 3(6) + 6

PT = 18 + 6

PT = 24

Answer:

24

Step-by-step explanation:

From the pic,PT=TQ

therefore,

3x+6=5x-6

5x-3x=6+6

2x=12

therefore, x=12/2

                  =6

therefore, PT=3×6+6

                      =24

Cheryl is working with qualitative data as she collects information on the different colors of cars, which involves classifying the cars into distinct categories based on their color

Cheryl is collecting data on car color, which is a qualitative type of data.

Qualitative data is descriptive in nature and categorizes or classifies characteristics or attributes. It does not involve numerical measurements or values. Instead, it represents qualities or characteristics that can be observed and described. In the case of car color, the data collected would fall into different categories or groups based on the color of the cars.

For example, the data could include categories such as red, blue, green, white, black, silver, etc. Each car would be classified into one of these categories based on its color. The data is not represented by numerical values, but rather by labels or names that describe the different colors.

In contrast, quantitative data involves numerical measurements or values. It represents quantities or amounts that can be measured or counted. This type of data can be further categorized as discrete or continuous. Discrete data consists of separate and distinct values that are counted, while continuous data represents a range of values that can be measured on a continuous scale.

Since car color does not involve numerical measurements or values, it falls under the category of qualitative data. Cheryl is collecting information about the different categories or classifications of car colors, which helps to describe and categorize the cars based on their visual attributes.

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Answer:

.20

Step-by-step explanation:

The word percent literally means "Out of 100". With that being said, 20% can be written as a fraction, mixed number or whole number as follows: 1/5 (fraction), 20/100 (mixed number) or .20 (whole number).

Answer:

1329 students

Step-by-step explanation:

20/100 ×6645

Reduce the fraction 20/100 with 20

So..20 goes into 20 1 time and 20 into 100 5 times

1/5×6645

Use 5 as the greatest common factor now

so...5 into 5 goes 1 time and 5 into 6645 goes 1329

1/1 × 1329 = 1329

Or... you could just convert 20% into a decimal by carring the . two places to the left

which is 0.2

0.2 × 6645 = 1329

The statement "There is a basis for P_n consisting of polynomials all of which have the same degree" is true.

This is a consequence of the existence and uniqueness theorem for solutions to systems of linear equations. We know that any polynomial of degree at most n can be written as a linear combination of monomials of the form x^k, where k ranges from 0 to n. Therefore, the space P_n has a basis consisting of these monomials.

Now, we can construct a new set of basis vectors by taking linear combinations of these monomials, such that each basis vector has the same degree. Specifically, we can define the basis vectors to be the polynomials:

1, x, x^2, ..., x^n

These polynomials clearly have degrees ranging from 0 to n, and they are linearly independent since no polynomial of one degree can be written as a linear combination of polynomials of a different degree. Moreover, since there are n+1 basis vectors in this set, it follows that they form a basis for the space P_n.

Therefore, the statement "There is a basis for P_n consisting of polynomials all of which have the same degree" is true.

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Answer:

B

Step-by-step explanation:

Answer:

c and e

Step-by-step explanation:

The estimate is 7/15.

The given expression is

4/5-1/3

We see that the denominators of both functions are different

So, the numerators can't be added/subtracted directly.

For this, we need to find the equivalent fraction of the given fractions, and the equivalent fractions should have the same denominator.

Now, the denominators are 5 and 3.

To have a common denominator in both fractions, we find the LCM of the denominators.

∴ The LCM of 5 and 3 = 15

Converting the fraction 4/5 into a fraction with 15 as the denominator,

4/5=4×3/5×3=12/15.

The same for 1/3

1/3= 1×5/3×5=5/15

Replacing 4/5 and 1/3 with the equivalent fractions in the given expression, we get,

12/15-5/15=(12-5)/15=7/15

Hence, the estimate is 7/15.

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formula: A=bh

A=72

b=12

72=12h

h=72/12

h=6

The distance that she runs from one corner of the field to another is given as follows:

147.1 yards.

The Pythagorean Theorem states that for a right triangle, the length of the hypotenuse squared is equals to the sum of the squared lengths of the sides of the triangle.

The distance in this problem is the diagonal of a rectangle, which is the hypotenuse of a right triangle in which the length and the width are the sides, hence:

d² = 85² + 120²

d = sqrt(85² + 120²)

d = 147.1 yards.

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A drop of water is denser than a ping-pong ball.

Usually, water is made of particles that are firmly pressed together. In differentiation, plastic (the material ping pong balls are made of) may be a lightweight fabric and the particles are not as firmly stuffed together.

The thickness of a ping pong ball is 0.0840 g/cm³, though water’s thickness is 997 kg/m³. Subsequently, ping pong balls aren’t about as thick as water and will continuously coast and surface greatly quickly.

The ping pong ball appears to oppose gravity and coast within the air.

Ping-pong balls drift within the water since they are amazingly lightweight, empty, and filled with air. Too, the water’s surface pressure makes it simple for the ping pong ball to drift.

In expansion, water is denser than ping pong balls, making them look for the most noteworthy point of water.

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The sound which we hear when the pig pong ball is bounced on the floor

is 19.48 DB

The repeating of sounds, especially in rhyme, is the form of repetition that most people connect with poetry. Alliteration, assonance, and onomatopoeia are other sound patterns in poetry that give additional meaning in addition to rhyme. Every one of these audio elements has a certain purpose in a poem.

a) \(\sum \ log(n)\)

by expanding the series for each value of n is

log (1) + log (2) + log(3) + log (4) + ......... + log ( 96)

simplify the expanded form we get

0 + 0.3010 + 0.4771+0.6020 ......................... + 1.982

=> 149.9963

b) \(\sum_{n=0}\) to infinity \(\sqrt{0.9^n}\)

formula for the sum of number in geometric progression

is  a/1-r

to find the ratio of the successive terms

plugging into the formula

r = \(\frac{a_{n+1}}{a_n}\)

r = \(\frac{\sqrt{0.9^{n+1}} }{\sqrt{0.9^n} }\)

=> r = \(\frac{\sqrt{0.9^n \times 0.9} }{\sqrt{0.9^n} .1}\)

=> r = \(\frac{\sqrt{0.9} }{1}\)

=> r = \(\sqrt{0.9}\)

=> a = \(\sqrt{0.9^0}\)

=> a = \(\sqrt{1}\)

=>  a= 1

by applying the formula having the value a =1 is

\(\frac{1}{1-\sqrt{0.9} }\)

rationalize the denominator by multiplying with \(1+\sqrt{0.9}\)

=> \(\frac{1+\sqrt{0.9} }{(1-\sqrt{0.9} ) (1+\sqrt{0.9}) }\)

=> 19.4868

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