fill in the blank. the minimum daytime temperature typically occurs ___ the time of maximum outgoing earth energy.

Answer: Yo! hope this helps you dude

When ice is placed into a beaker filled with water, the water level does not drop because of the concept of displacement. When the ice is added, it displaces an amount of water equal to its own volume. This means that the ice takes up space in the beaker, pushing out an equal amount of water to make room for itself. Therefore, the total volume of water and ice in the beaker remains the same, and the water level does not drop.

This is due to the fact that the density of ice is lower than that of water and when the ice is placed into the water, it will float on the surface, pushing out an amount of water equal to its own volume.

Additionally, when the ice melts, it will release the same amount of water it displaced before and the water level will not change.

Explanation:

The empirical formula for this vitamin : C₃H₄O₃

The empirical formula is the smallest comparison of atoms of compound =mole ratio of the components

The principle of determining empirical formula

Mass of C in CO₂ :(MW C = 12 g/mol, CO₂=44 g/mol)

\(\tt \dfrac{12}{44}\times 1.4991=0.409~g\)

Mass of H in H₂O :(MW H = 1 g/mol, H₂O = 18 g/mol)

\(\tt \dfrac{2.1}{18}\times 0.4092=0.0455~g\)

Mass O = Mass sample - (mass C + mass H) :

\(\tt 1-(0.409+0.0455)=0.5455~g\)

mol ratio C : H : O =

\(\tt \dfrac{0.409}{12}\div \dfrac{0.0455}{1}\div \dfrac{0.5455}{16}\\\\0.0341\div 0.0455\div 0.0341\rightarrow 1\div 1.33\div 1=3\div 4\div 3\)

Answer:

0.430 Litre

Explanation:

The first thing that you need to do here is to convert the mass of lithium bromide to moles by using the compound's molar mass.\(100g \frac{1 moleNaCl}{58.5g} = 1.71 moles of NaCl\)

Now, the molarity of the solution is simply a measure of the number of moles of solute, which in your case is NaCl, present for every 1.00 L of the solution.

In order to have a 4.00-M solution of NaCl, you need to have 4.00 moles of NaCl for every 1.00 L of this solution.

You know that your sample contains 1.71 moles of NaCl, so you can use the molarity of the solution as a conversion factor to determine how many liters of this solution can be made.

\(1.71 mole NaCl \frac{ 1 L Solution}{4 mole NaCl} = 0.43 L solution\).

The molar heat of the solution of sulfuric acid is 21.4 kJ/mol, rounded to 1 decimal place.

let's calculate the heat absorbed by the water when dissolving CaCl2:

n = m/M = 0.9638 g / 110.98 g/mol = 0.00868 mol (moles of CaCl2 dissolved)

q1 = nΔH = (0.00868 mol)(-83 kJ/mol) = -0.722 kJ (heat absorbed by water)

Next, let's calculate the heat released by the sulfuric acid:

n = 0.0978 mol (moles of H2SO4 added)

ΔT = 5.0 oC (temperature change of water)

m = 100 g (mass of water)

q2 = -mcΔT = -(100 g)(4.184 J/g oC)(5.0 oC) = -2092 J = -2.092 kJ (heat released by sulfuric acid)

Now, we can set these two values equal to each other and solve for the calibration factor:

q1 = q2

-0.722 kJ = -2.092 kJ

q = 1.370 kJ (total heat exchanged)

c = q/ΔT = (1.370 kJ)/(1.6 oC) = 0.856 kJ/oC (calibration factor)

Finally, we can calculate the molar heat of the solution of sulfuric acid:

ΔH = -q/n = -(-2.092 kJ)/0.0978 mol = 21.4 kJ/mol (molar heat of solution of sulfuric acid)

Therefore, the molar heat of the solution of sulfuric acid is 21.4 kJ/mol, rounded to 1 decimal place.

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Answer:

Let it be x

\({ \tt{ (oxidation \: state \: of \: nitrogen) + 2x = overall \: charge}} \\ { \tt{ - 4 - 2 x = 0}} \\ { \tt{2x = - 4}} \\ { \tt{x = - 2}}\)

Answer:

The percentage of IF₅ (by mole) in the final product mixture will be 50%. This is determined by the stoichiometry of the reaction, the given molar mass of the reactants, and the ideal gas law.

Explanation:

Answer:

hi how are you doing today Jasmine

Answer:

For Example, When n-Hexane Is Passed Over Chromium Oxide (Cr2O3) Supported Over Alumina (Al2O3) at 600 degree Celsius, Benzene Is Produced

Answer:

15 gram

Explanation:

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The unknown material with a mass of 25.0g, and the volume is 3.19 cm³ is iron with a density of 7.85g/cm³.

DENSITY:

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The formula of the compound formed from K and P is K₃P. Potassium and oxygen is K₂O and the compound formed from potassium and F is KF.

Ionic compounds are formed between metals and non-metals. Metals donate their valence electron to non-metals. Potassium, K forms the compound with Br as KBr, by donating one electron to bromine. Formula of compound between K and N  is K₃N and that between K and S is K₂S

Similarly the table can be filled as follows:

compounds of sodium: Na₃P,  Na₂O, NaF, NaBr, Na₃N and Na₂S.

compounds of Mg : Mg₃P₂, MgO, MgF₂, MgBr₂, Mg₃N₂, MgS

compounds of Al : AlP, Al₂O₃, AlF₃, AlBr₃, AlN, Al₂S₃

Compounds of Fe : FeP, FeO, FeF, FeBr, FeN, FeS.

compound of Cu : CuP, CuO, CuF, CuBr, CuN, CuS

and compounds of Ba are: Ba₃P₂, BaO, BaF₂, BaBr₂, Ba₃N₂,BaS

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Answer:

Explanation:

To calculate the molar internal energy of a gas at a given temperature, you need to know the molar specific heat capacities at constant volume and constant pressure for the gas. These values are typically provided in tables of thermodynamic data, which can be found in various sources such as textbooks or online. Since you mentioned that you want to take the translational and rotational degrees of freedom into consideration, you will need to use the molar specific heat capacity at constant volume, which accounts for these degrees of freedom.

Once you have the molar specific heat capacity at constant volume for the gas, you can use the equation U = Cv * T, where U is the molar internal energy, Cv is the molar specific heat capacity at constant volume, and T is the temperature in kelvins. In your case, the temperature is 298.15 K, so plugging in the appropriate values and solving for U will give you the molar internal energy of carbon dioxide at that temperature.

It's important to note that the molar specific heat capacity at constant volume is typically a function of temperature, so you will need to use the appropriate value for the temperature you are interested in. Additionally, different sources may provide slightly different values for the molar specific heat capacity, so it's always a good idea to consult multiple sources to get a sense of the range of possible values.

1. The number of mole of C₃H₈ needed to make 15.5 moles of CO₂ is 5.2 moles

2. The number of moles of O₂ needed is 25.8 moles

The number of mole of C₃H₈ needed can be obtained as illustrasted below:

C₃H₈ + 5O₂ -> 3CO₂ + 4H₂O

From the balanced equation above,

3 moles of CO₂ was obtained from 1 mole of C₃H₈

Therefore,

15.5 moles of CO₂ will be obtain from = (15.5 × 1) / 3 = 5.2 moles of C₃H₈

Thus, number of mole of C₃H₈ needed is 5.2 moles

We can obtain the number of mole of O₂ needed as follow:

C₃H₈ + 5O₂ -> 3CO₂ + 4H₂O

From the balanced equation above,

3 moles of CO₂ was obtained from 5 moles of O₂

Therefore,

15.5 moles of CO₂ will be obtain from = (15.5 × 5) / 3 = 25.8 moles of O₂

Thus, number of mole of O₂ needed is 25.8 moles

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Complete question:

How many moles of C₃H₈ are needed to make

15.5 moles of CO₂? How much O₂ will be needed?

C₃H₈ + 5O₂ -> 3CO₂ + 4H₂O

Answer:

question 1, i'd say not enough information

question 2, do you know of potassium bromine lowers the entropy of the water solution or raises the entropy level? if so entropy is either A or C

question 3, i'd say entropy is less than 0, but i don't know because i never learned this in school

Explanation:

we don't know the original volume of gas and only know the elements that are in it

Answer:

d

Explanation:

since it is much convenient since the email will not get lost and it's contents will not be forgotten

The formula of the hydrate is NiCl2·4.27H2O. The name of the hydrate is nickel (II) chloride tetrahydrate.

To determine the formula and name of the hydrate, we need to first find the value of "x" in the formula NiCl2·xH2O using the given information.

Mass of water = Initial mass - Mass of anhydrous salt

Mass of water = 0.470 g - 0.256 g

Mass of water = 0.214 g

The molar mass of H2O is 18.015 g/mol, so the number of moles of water present in the hydrated salt can be calculated as:

Moles of water = Mass of water / Molar mass of water

Moles of water = 0.214 g / 18.015 g/mol

Moles of water = 0.0119 mol

The number of moles of anhydrous salt can be calculated by dividing its mass by its molar mass:

Moles of anhydrous salt = Mass of anhydrous salt / Molar mass of anhydrous salt

Moles of anhydrous salt = 0.256 g / (Ni: 58.69 g/mol + 2Cl: 2 x 35.45 g/mol)

Moles of anhydrous salt = 0.00279 mol

The ratio of moles of water to moles of anhydrous salt is equal to "x" in the formula NiCl2·xH2O:

Moles of water / Moles of anhydrous salt = x

0.0119 mol / 0.00279 mol = x

x ≈ 4.27

Therefore, the formula of the hydrate is NiCl2·4.27H2O. The name of the hydrate is nickel (II) chloride tetrahydrate.

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Answer:

It is A, The daughter product has the wrong atomic number

Explanation:

Have trust, please i beg of you.

:) thank me later, love ya

The daughter's product has the wrong atomic number. Hence, option A is correct.

Nuclear equations represent the reactants and products in radioactive decay, nuclear fission, or nuclear fusion.

Beta decay - A common mode of radioactive decay in which a nucleus emits beta particles. The daughter nucleus will have a higher atomic number than the original nucleus.

Hence, the daughter's product has the wrong atomic number.

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Answer:

Sedimentary rocks

Explanation:

My explanation is that when an animal decomposes it body returns to the ground eventually being used in the rock cycle and rocks form this through the rock cycle when broken down by weathering and erosion.

Hope this helps you

Answer:

sedimentary rocks

They form from deposits that accumulate on the Earth's surface.

Empirical formula is N₂O

An empirical formula for a compound is the formula of a substance written with the smallest integer subscript

Here given data is

N = 0.2144 g

O = 0.1224 g

We have to calculate the empirical formula = ?

So mass of compound/moles

Empirical formula =  0.2144 g/14g/mol = 0.0153 mol

Empirical formula =  0.1224 g/16g/mol = 0.0076 mol

Then smallest mole value is 0.0076 mol

Divide the nitrogen mole by smallest value then

N = 2.0008

O = 1

Then take the closest whole number

Then the ratio is 2 : 1

So the empirical formula is N₂O

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The Nobel gases, Group 8 elements  have the  smallest atomic radIi in the periodic table.

Atomic radius decreases as you move across a period. This is because Within  a period, a new electron is being added to the same shell , and at the same time a new proton is added , This causes an attraction and causes the electron to pull nearer to the nucleus causing the radius to shrink and reduce in size.

In decreasing order of atomic radius, we have alkali metals>halogens> transition metal  > Nobel gases

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The final temperature of the water is: T_final = 45.0°C

We can use the formula for the specific heat capacity of the water to solve this problem:

q = mcΔT

First, we can calculate the initial energy of the water:

q = mcΔT

q = (10.0 g) (4.184 J/g°C) (25.0°C)

q = 1,046 J

Next, we can calculate the final temperature after absorbing 840 J:

q = mcΔT

840 J = (10.0 g) (4.184 J/g°C) (ΔT)

ΔT = 20.0°C

Therefore, the final temperature of the water is:

T_final = T_initial + ΔT

T_final = 25.0°C + 20.0°C

T_final = 45.0°C

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The formula you provided calculates the percent change in pH based on the difference between the pH at 5 drops and the pH at 0 drops. Here's how you can use the formula:

1. Determine the pH at 5 drops and the pH at 0 drops.

Let's say the pH at 5 drops is 4 and the pH at 0 drops is 7.

2. Plug the values into the formula:

Percent Change of pH = 100% × (pH at 5 drops - pH at 0 drops) / pH at 0 drops

Percent Change of pH = 100% × (4 - 7) / 7

3. Calculate the numerator:

4 - 7 = -3

4. Calculate the denominator:

Percent Change of pH = 100% × (-3) / 7

5. Calculate the percent change:

Percent Change of pH = -300% / 7

Therefore, the percent change in pH from 0 drops to 5 drops is approximately -42.86%.

The vapor pressure of the SiCl₄ in the mmHg at the 33.0 °C is the 312 mmHg.

The Clausius - Clapeyron equation is as :

ln ( P₂ / P₁ ) = ΔHvap / R ( 1 / T₁ - 1 / T₂ )

P₂ = P₁eˣ

Where,

The temperature, T₁  = 5.4 °C = 278.55 K

The temperature, T₂  = 33.0 °C= 306 K

The pressure, P₁ = 100 mmHg

ΔHvap is the heat of the vaporization = 30.2 kJ /mol = 30200 J/mol

The gas constant, R = 8.314 J / mol K

x = ΔHvap / R ( 1 / T₁ - 1 / T₂ )

x = 30200 / 8.314 ( 1/ 278.55 - 1/ 306 )

x = 1.05

P₂ = 100 \(e^{1.05}\)

P₂ = 312 mmHg

The vapor pressure of the  SiCl₄ is 312 mmHg.

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BaSO4 (s) + Cu(NO3)2 (aq)  and KCl (s) + Mg3(PO4)2 (s) is the product of given precipitation reactions.

Ba(NO3)2 (aq) + CuSO4 (aq) → BaSO4 (s) + Cu(NO3)2 (aq)

 K3 PO4 (aq) + MgCl2 (aq) → KCl (s) + Mg3(PO4)2 (s)

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The ionization of the following acids can be represented as:

Tetraoxosulphate (VI) Acid (\(H_{2}SO_{4}\)) ionizes as H+ and SO4^2- ions.

Trioxonitrate (V) Acid (\(HNO_{3}\)) ionizes as H+ and \(NO_{3-}\) ions.

Ethanoic Acid (\(CH_{3}COOH\)) ionizes as H+ and \(CH_{3}COO^{-}\) ions.

Tetraoxosulphate (VI) Acid, also known as sulfuric acid (\(H_{2}SO_{4}\)), ionizes as follows:

\(H_{2}SO_{4}\) → \(H+\) + \(SO_{4}^{2-}\)

In this reaction, sulfuric acid donates two hydrogen ions (H+) to the solution, forming sulfate ions (\(SO_{4}^{2-}\)).

Trioxonitrate (V) Acid, commonly known as nitric acid (\(HNO_{3}\)), ionizes as follows:

\(HNO_{3}\) → \(H+_{}\) + \(NO_{3-}\)

Nitric acid dissociates to release one hydrogen ion (\(H+\)) and a nitrate ion  (\(NO_{3-}\)).

Ethanoic Acid, also known as acetic acid (\(CH_{3}COOH\)), ionizes as follows:

\(CH_{3}COOH\) → H+ + \(CH_{3}COO^{-}\)

Acetic acid donates a hydrogen ion (H+) to the solution, forming an acetate ion (\(CH_{3}COO^{-}\)).

In all cases, the acids dissociate in water, producing hydrogen ions (H+) as positively charged ions and their corresponding anions. The hydrogen ions are responsible for the acidic properties of these substances, while the anions contribute to the overall charge balance in the solution. The ionization of acids allows them to conduct electricity in aqueous solutions and react with other substances.

The question was incomplete. find the full content below:

Indicate the ionization of the following acids,

Tetraoxosulphate (VI) Acid

Trioxonitrate (V) Acid

Ethanoic Acid.​

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Answer: C

l

2

→

H

C

l

O

C

l

2

→

2

H

C

l

O

(Cl balance)

C

l

2

+

2

H

2

O

→

2

H

C

l

O

(O balance)

C

l

2

+

2

H

2

O

→

2

H

C

l

O

+

2

H

+

(H balance)

C

l

2

+

2

H

2

O

→

2

H

C

l

O

+

2

H

+

+

2

e

−

(Charge balance)

C

l

2

+

2

H

2

O

→

2

H

C

l

O

+

2

H

+

+

2

e

−

balanced half-reaction)

Explanation: