Figure 2 shows how the velocity of a train on a model railway changes with time.
0.6-
a
velocity
(m/s)
0.5-
0.4
0.3
0.2-
0.1
0
0
5 10
A between Os-5s
B between 5s-15s
15
Figure 2
Deduce the time when the train is travelling at its highest speed.
Tick one box.
between 15s-30s
OD between 30s-45s
20 25 30
time (s)
35
40 45
b Show that the magnitudes of the train's accelerations after 10s and after 35s are in the ratio 2:1.
c Show that the model train travelled a distance of 4 m between the times 30s and 40 s.

I got you

Explanation:

normal force = 400 g cos 35

friction force up slope = .6 (400 g) cos 35

weight component down slope = 400 g sin 35

400 a = 400 g sin 35 - .6 (400 g cos 35)

a = g (sin 35 - .6 cos 35) = .082 g

I hope this helps you

The acceleration of the block is 0.082g.

The definition of force in physics is: The push or pull on a massed object changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.

Given that:

Mass of the slab: m = 400 kg.

Angle of inclination: θ = 35°.

Coefficient of kinetic friction: μ  = 0.60

Hence, the normal force = 400 g cos 35° N.

The friction force acting on the slab= 0.6× (400 g) ×cos 35° N.

The component of weight in the direction of motion= 400 g sin 35° N.

Let the acceleration of the slab = a.

Now from Newton's 2nd law of motion:

Σ F = ma

400 g sin 35° - 0.6 (400 g cos 35°) = 400 a

a = g (sin 35 - .6 cos 35)

= 0.082 g

Hence, the acceleration of the block is 0.082g.

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Answer:

D hope this helps

Explanation:

Answer:

D

Explanation:

The amount of matter in the bowling ball remains the same.

Answer:

The separation between the two stones is 36 m, when the second stone is approximately 10.9 m below the top of the cliff

Explanation:

The given parameters are;

The height of the cliff from which the stones are dropped, h = 60 m

The time at which the second stone is dropped = 1.6 seconds after the first

The distance below the top of the cliff when the distance between the two stones is 36 m = Required

We have;

The kinematic equation of motion that can be used is s = u·t - (1/2)·g·t²

For the first stone, we have, s₁ = u·t₁ - (1/2)·g·t₁²

For the second stone, we get; s₂ = u·t₂ - (1/2)·g·t₂²

t₁ = t₂ + 1.6

g = The acceleration due to gravity ≈ 9.81 m/s²

s = The distance below the cliff top

The initial velocity of the stones, u = 0

Let t represent the time from which the second stone is dropped at which the distance between the two stones is 36 m, we have;

s₁ = u·(t + 1.6) + (1/2)·g·(t + 1.6)²

s₂ = u·t + (1/2)·g·t²

u = 0

∴ s₁ - s₂ = 36 =  (1/2)·g·(t + 1.6)² - (1/2)·g·t²

2 × 36/(g) = (t + 1.6)² - t²  = t² + 3.2·t + 2.56 - t² = 3.2·t + 2.56

2 × 36/(9.81) = 3.2·t + 2.56

t = (2 × 36/(9.81) - 2.56)/3.2 =  ≈ 1.49 s

t ≈ 1.49 s

s₂ = (1/2)·g·t²

∴ s₂ = (1/2) × 9.81 × 1.49² ≈ 10.9

The distance below the top of the cliff of the second stone when the the separation between the two stones is 36 m, s₂ ≈ 10.9 m.

365.25 or 366.25 in a leap year

The correct answer is 36 m.

If the two ratios are equivalent to one another, proportion validates. It determines whether two ratios are equivalent. Now, for illustration, imagine that you are given two sets of numbers that are increasing or decreasing in the same ratio. As a result, we will refer to the ratios as being directly proportionate to one another.

The third tick mark on the horizontal axis represents a time interval of 15 seconds.

3 Unit ( 5 s/unit ) = 15 sec

The slope of the line will represent the speed = m = Δy /Δx

= (4)(9)/(9)(5)

= 36/45

= 0.8 m/s

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Adding the values of all the data points and dividing by the number of data points dividing the value of each data point by the total value of all the data points multiplying the values of the highest and lowest data point, and then dividing by two subtracting the highest value among the data points from the lowest value.

A scientific model is a bodily and/or mathematical and/or conceptual representation of a system of ideas, occasions, or procedures. Scientists are seeking to perceive and recognize patterns in our world by drawing on their scientific understanding to offer motives that enable the styles to be anticipated.

Benefits of modeling and simulation :

* Can be more secure and less expensive than the real international.

* Able to test a product or device that works earlier than building it.

* Can use it to discover unexpected troubles.

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Making a conical motion with limb as drawing a circle is called the humerus.

Humerus is the largest bone in the arm and the only bone in the upper arm. Movement of the humerus is essential for all varied activities. Humerus is the only bone in the upper arm. This bone has many uses because it is directly related to the human hand, which plays a very important role for humans.

From the statement above, we get various important information. Mandible is the lower jawbone which is the largest and strongest bone in the facial area. This bone is useful for helping humans in chewing food, speaking, and other activities that require the use of the lower jaw.

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1. The Schrödinger equation is a fundamental equation in quantum mechanics that describes the behavior of particles. The general solution represents the wave function of a particle and provides information about its position and momentum.

3.Tunneling is a phenomenon in quantum mechanics where a particle can pass through a potential barrier even though it does not have enough energy to overcome the barrier classically.

1. The Schrödinger equation is a partial differential equation that was developed by Erwin Schrödinger in 1925 as a mathematical formulation of quantum mechanics. It describes how the wave function of a particle evolves over time. The equation takes the form:

Ĥψ = Eψ

Where Ĥ is the Hamiltonian operator, ψ is the wave function, E is the energy of the particle, and Ĥψ represents the operation of the Hamiltonian on the wave function.

The general solution to the Schrödinger equation represents the wave function of a particle. The wave function provides information about the probability distribution of the particle's position and momentum. It contains both real and imaginary components and is typically represented as a complex-valued function.

The wave function, ψ, can be written as a product of a spatial part and a temporal part:

ψ(x, t) = Ψ(x) * Φ(t)

The spatial part, Ψ(x), represents the probability amplitude of finding the particle at position x, while the temporal part, Φ(t), describes how the wave function evolves over time.

The Schrödinger equation and its general solution are essential tools in quantum mechanics, as they allow us to predict the behavior of particles on a microscopic scale. By solving the equation, we can determine the wave function of a particle and calculate probabilities associated with its position and momentum.

2.Case 1: Particle in a Box

In the case of a particle confined to a one-dimensional box, the potential energy is zero within the box and infinite outside of it. This situation can be represented by the following potential function:

V(x) = 0,  0 < x < L

V(x) = ∞,  x ≤ 0 or x ≥ L

To solve the Schrödinger equation for this case, we need to find the wave function (Ψ) and the corresponding energy levels (E). The general form of the wave function inside the box is given by:

Ψ(x) = A * sin(kx)

Where A is a normalization constant, and k = (2π/L).

Applying the boundary conditions, we find that the wave function must go to zero at both ends of the box (x = 0 and x = L). This leads to the quantization of the wave vector k:

k = nπ/L,  where n = 1, 2, 3, ...

The corresponding energy levels are given by:

E = (ħ²π²/2mL²) * n²

Where ħ is the reduced Planck's constant and m is the mass of the particle.

Case 2: Harmonic Oscillator

In the case of a particle in a harmonic oscillator potential, the potential energy can be described by:

V(x) = (1/2)kx²

Where k is the spring constant. To solve the Schrödinger equation for this potential, we use the harmonic oscillator equation:

- (ħ²/2m) * (d²Ψ/dx²) + (1/2)kx²Ψ = EΨ

The solutions to this equation are given by Hermite polynomials, and the corresponding energy levels are quantized. The wave function for the harmonic oscillator potential can be expressed as a product of a Gaussian function and a Hermite polynomial:

Ψ(x) = (A/π)\(^{(1/4)\) * exp(-αx²/2) * Hₙ(√αx)

Where A is a normalization constant, α = (√(mk/ħ)), and Hₙ is the Hermite polynomial of degree n.

The energy levels in the harmonic oscillator potential are given by:

E = (n + 1/2)ħω

Where n = 0, 1, 2, ... and ω = (√(k/m)) is the angular frequency of the oscillator.

These solutions provide insights into the behavior of electrons traveling in these potential systems, including the quantization of energy levels and the spatial distribution of the wave functions.

3. Tunneling is a phenomenon in quantum mechanics where a particle can pass through a potential barrier even though it does not have enough energy to overcome the barrier classically. This effect arises from the wave nature of particles, as described by the Schrödinger equation.

Tunneling has important implications in various areas of physics, such as nuclear fusion, quantum computing, and scanning tunneling microscopy. It allows for phenomena such as alpha decay, where alpha particles escape from atomic nuclei, and the operation of tunneling diodes in electronic devices.

Overall, tunneling is a fascinating quantum mechanical phenomenon that challenges our classical intuition and plays a crucial role in understanding the behavior of particles in the presence of potential barriers.

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Answer:

2 m/s

Explanation:

Given that,

Mass of a man, m₁ = 75 kg

Mass of object, m₂ = 5 kg

Velocity of the object, v₂ = 30 m/s

We need to find the recoil velocity of the man. Let it is v₁. In the whole process, the momentum of the system will remain conserved such that,

\(m_1v_1=m_2v_2\\\\v_1=\dfrac{m_2v_2}{m_1}\\\\v_1=\dfrac{5\times 30}{75}\\\\v_1=2\ m/s\)

So, the recoil velocity of the man is 2 m/s

Answer: Unemployment has both individual and social consequences that require public policy interventions.

For the individual, unemployment can cause phycology distress which can lead to a decline in life satisfaction it can also lead to mood disorders and substance abuse

Answer:12

Explanation:

A. The SI unit of force is the newton, symbol N.
b. The SI unit for distance is the meter (m)
c. The SI unit of work is joule (J). 
or Sometimes, newton-metre (N-m) is also used for measuring work.

In series.

Single-pole and single-throw switch:

A switch with only one input and one output is referred to as a Single Pole Single Throw (SPST) switch. This indicates that it has a single output terminal and a single input terminal.

A single pole, one throw switch functions as an on/off switch in circuits. The circuit is turned on when the switch is closed. The circuit is shut off when the switch is open.

Thus, SPST switches are relatively basic in design.

Circuit for a single-pole, single-throw (SPST) switch

Types:

According to the application, it can be divided into three categories, including:

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7.11 meters

Explanation

to solve this we need to use this formula:

Step 1

Let

now,replace and calculate

therefore, the answer is

7.11 meters

I hope this helps you

Lightning is an electrostatic discharge which occurs naturally within the storm. The electrostatic discharge is due to electrically charged regions in the storm.

Lightning can be defined as the naturally occurring electrostatic discharge during which two electrically charged regions positive and negative, both in the same atmosphere or with one on the ground, and other at a certain distance which temporarily neutralize each other, causing the instantaneous release of an average of about one gigajoule of energy from the effect.

The electric field within the storm is not the only field which develops. Below the negatively charged storm base in this region, positive charge begins to pool within the surface of the earth. This positive charge will then shadow the storm whichever direction it goes, and is responsible for the cloud-to-ground lightning.

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First, let's prove that if \($\sum_{n=1}^\infty |a_n|$\) is absolutely convergent and \($(b_n)$\) is a bounded sequence, then  \($\sum_{n=1}^\infty a_n b_n$\) is convergent.

Since \($(b_n)$\) is bounded, there exists some positive constant \($M$\) such that \($|b_n| \leq M$\) for all \($n \in \mathbb{N}$\). Then, for any \($n \in \mathbb{N}$\), we have:

\($$|a_n b_n| \leq |a_n| \cdot |b_n| \leq M \cdot |a_n|$$\)

Since \($\sum_{n=1}^\infty |a_n|$\) is absolutely convergent, we know that \($\sum_{n=1}^\infty M|a_n|$\) is also convergent, by comparison. Thus, by the comparison test, we can conclude that \($\sum_{n=1}^\infty |a_n b_n|$\) is convergent.

Now, to give an example to show that if \($\sum_{n=1}^\infty a_n$\) is conditionally convergent and \($(b_n)$\) is a bounded sequence, then \($\sum_{n=1}^\infty a_n b_n$\) may diverge, consider the following:

Let \($a_n = \frac{(-1)^n}{n}$\) and \($b_n = 1$\) for all \($n \in \mathbb{N}$\). Then \($\sum_{n=1}^\infty a_n = -\ln(2)$\) is conditionally convergent, and \($(b_n)$\) is clearly a bounded sequence. However,

\($\sum_{n=1}^\infty a_n b_n = \sum_{n=1}^\infty \frac{(-1)^n}{n} = \ln(2)$\)

which diverges.

Finally, to give an example of a convergent series \($\sum_{n=1}^\infty a_n$\)  that \($\sum_{n=1}^\infty |a_{2n}|$\) diverges, consider the following:

Let \($a_n = \frac{(-1)^n}{n}$\) for all \($n \in \mathbb{N}$\). Then \($\sum_{n=1}^\infty a_n$\) converges conditionally to \($-\ln(2)$\), but \($\sum_{n=1}^\infty |a_{2n}| = \sum_{n=1}^\infty \frac{1}{2n}$\) diverges.

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The car will accelerate from rest at a constant rate of \(5 m/s^2\) for about 4.4 seconds until it reaches a speed of 79.2 km/h (49.2 mph or 22.0 m/s).

Using the following equation of motion, we can estimate how long it would take for your car to accelerate from rest to a speed of 79.2 km/h (49.2 mph or 22.0 m/s):

v = u + at

Where:

v = final velocity

u = initial velocity

a = acceleration

t = time

Since the car is at rest, the initial velocity in this scenario is 0 m/s, the acceleration is \(5 m/s^2\), and the final velocity is 22.0 m/s.

Plugging the values into the equation, we have:

22.0 = 0 + 5t

5t = 22.0

t = 22.0 / 5

t ≈ 4.4 seconds

As a result, your car will accelerate from rest at a constant rate of \(5 m/s^2\) for about 4.4 seconds until it reaches a speed of 79.2 km/h (49.2 mph or 22.0 m/s).

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Answer:

Just in 1 dimension  

Vpg = Vps + Vsg

Where

Vpg= relative to the ground

Vps= person relative to the ship

Vsg= ship relative to the ground

Vpg= Vps+Vsg ;

Vpg= 0.5 + 6  

Vpg= 6,5 m/s

Answer:

0.5*10uF * 16*16 =0.0128

Explanation:

I have no explanation just like my soul.

A toggle clamp is a tool that you use to firmly secure components or pieces in place, frequently but not always as part of a production process.

A toggle clamp is a device that you employ, often but not exclusively as part of a production process, to firmly place components or parts in place. A toggle clamp's main characteristics are its rapid action and ability to be easily turned on and off by an operator.

Toggle clamps also lock in place firmly. Because of this, toggle clamps are frequently employed in production lines where components need to be held firmly and quickly removed during routine manufacturing procedures.

Toggle clamps come in six primary categories: vertical toggle clamps, horizontal toggle clamps, plunger toggle clamps (also known as push action toggle clamps), hook action toggle clamps, plier action toggle clamps, and cam action toggle clamps.

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Answer:

\(\huge\boxed{\sf P = 1.4\ W}\)

Explanation:

Time = t = 50 sec

Force = F = 10 N

Height = 7 m

Power = P = ?

\(\displaystyle P =\frac{W}{t}\)

We know that,

Here, distance is covered in the form of height.

So,

Work = Force × Height

Work = 10 × 7

W = 70 Joules

Now,

P = W/t

P = 70 / 50

\(\rule[225]{225}{2}\)

The heat of reaction for Reaction A can be calculated by finding the difference between the initial energy of the reactants and the final energy of the products.

The heat of reaction for Reaction A is -100 kJ/mol.

The heat of reaction for Reaction B is -100 kJ/mol.

a. Heat of Reaction A

The heat of reaction for Reaction A can be calculated by finding the difference between the initial energy of the reactants and the final energy of the products.

The initial energy of the reactants is 150 kJ/mol and the final energy of the products is 50 kJ/mol.

Therefore, the heat of reaction for Reaction A is:

Heat of reaction A = Final energy of products – Initial energy of reactants= 50 kJ/mol – 150 kJ/mol= -100 kJ/mol

Therefore, the heat of reaction for Reaction A is -100 kJ/mol.

b. Heat of Reaction B

The heat of reaction for Reaction B can be calculated by finding the difference between the initial energy of the reactants and the final energy of the products.

The initial energy of the reactants is 200 kJ/mol and the final energy of the products is 100 kJ/mol.

Therefore, the heat of reaction for Reaction B is:

Heat of reaction B = Final energy of products – Initial energy of reactants= 100 kJ/mol – 200 kJ/mol= -100 kJ/mol

Therefore, the heat of reaction for Reaction B is -100 kJ/mol.

Energy diagrams

Energy diagrams are a graphical representation of the energy changes that take place during a chemical reaction.

The energy diagram shows the potential energy of the reactants and the products during the reaction.

The reactants have a higher potential energy than the products because the reactants have not yet undergone a reaction.

The activation energy is the energy required to initiate the reaction.

Once the activation energy has been reached, the reaction proceeds and the products have a lower potential energy than the reactants.

The energy diagram can also be used to calculate the heat of reaction.

The heat of reaction is the difference between the initial energy of the reactants and the final energy of the products.

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Answer:

hope this will help you

Explanation:

here,

mass(m)=25kg

g=10m/s

height (h)=30m

we know that,

potential energy=mgh

=25*10*30

=7500J

Answer:

In series connection the current flow throughout the circuit is same and thus the voltage divides equally between both bulbs because of same rating.

Explanation:

The minimum period for a satellite in orbit around a spherical planet of uniform density can be derived by considering the gravitational force and the centripetal force acting on the satellite. By equating these forces, the minimum period can be determined.

The gravitational force acting on the satellite is given by the equation F_grav = (G * M * m) / r^2, where G is the gravitational constant, M is the mass of the planet, m is the mass of the satellite, and r is the distance between the center of the planet and the satellite.

The centripetal force required to keep the satellite in orbit is given by F_centripetal = (m * v^2) / r, where v is the velocity of the satellite.

By equating the gravitational force and the centripetal force, we have (G * M * m) / r^2 = (m * v^2) / r.

Simplifying the equation, we can solve for the velocity of the satellite, v, in terms of the gravitational constant, the mass of the planet, and the distance between the satellite and the planet.

The period of the satellite is given by the equation T = (2 * pi * r) / v, where T is the period and r is the distance between the center of the planet and the satellite.

By substituting the expression for v into the period equation, we can derive the minimum period for a satellite in orbit around a spherical planet of uniform density.

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0.072 J is the work would the spring take to set the object into an oscillation with amplitude 0.02 m

A periodic variable's amplitude is a gauge of its change over a single period. A non-periodic signal's magnitude in relation to a standard value is its amplitude. There are several ways to define amplitude, and they are all dependent on how much the extreme values of the variable deviate from one another.

The stiffness of the spring is how we determine spring constant. In other words, we can define the spring constant as the force used to produce the specified displacement when the spring's displacement is one unit. It follows that a spring's spring constant will increase with increasing spring stiffness.

Now to calculate the work done by spring we use the Hookes’s law

F=kx

Where F is the force required

K is the spring constant

X is the amplitude or distance

So F=kx

F=180x0.02

F=3.6 N

Now to calculate work :

Work = Force × Distance.

Work=3.6 N x0.02m

Work =0.072 J

Hence, 0.072 J is the work would the spring take to set the object into an oscillation with amplitude 0.02 m

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Answer:hope this helps

pleasee i need the brainliest

Explanation: Warm air rises and is replaced by cooler air from the surrounding area. The warm air eventually cools off, falling down and replacing more warm air. This causes a constant upward flow sometimes called a thermal that allows large birds to soar without effort.

No, that's not the solution to this query. Instead, your electricity bill will be greater.

Whether you are importing or exporting power is irrelevant to the measurements made by a standard electricity metre, which just monitors the quantity of power flow through it. Therefore, the excess energy that your solar power system produces will be charged to your electricity account.

The plant owner can restrict the plant's ability to generate power thanks to a gadget called ZED Advance. This means that this device will regulate the solar inverter's (string inverter's) output power generation in accordance with the load. Or, to put it another way, it will prevent any surplus power from being generated by keeping the solar power plant's generating power below the load.

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The surface temperature of our Sun, a class G star, is 5800 K. Since it is hotter than a type M star, we can infer that it is cooler than a type O star. Williamina Fleming developed a system to categorize stars in the 1880s based on the potency of hydrogen absorption lines.

The stars with the strongest hydrogen lines were designated as "A" stars, followed by "B" stars with the second-strongest hydrogen lines, and so on until "O" stars with the weakest hydrogen lines.

However, as we saw above, hydrogen lines by themselves are not a very reliable indicator for classifying stars since they vanish from the visible light spectrum when stars get too hot or too cool.

A, B, F, G, K, M, and O were the only letters from the old system that Annie Jump Cannon focused on when she redesigned this classification system in the 1890s.

Instead of beginning over, Cannon also rearranged the existing classes into the order we are familiar with: O, B, A, F, G, K, M, in decreasing order of temperature.

In her lifetime, she classified over 500,000 stars, classifying up to three stars each minute by examining the stellar spectra, as you can read in the piece on Annie Cannon: Classifier of the Stars later in this section.

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Our Sun is a class G star with a surface temperature of 5800 K. We may conclude that it is colder than a type O star since it is hotter than a type M star.

In the 1880s, Williamina Fleming created a classification system for stars based on the strength of hydrogen absorption lines.

The stars were categorized as "A" stars, "B" stars with the second-strongest hydrogen lines, "C" stars with the strongest hydrogen lines, and so on until "O" stars with the weakest hydrogen lines.

Since they disappear from the visible light spectrum when stars get too hot or too cold, hydrogen lines by themselves are not a particularly accurate signal for categorizing stars, as we have shown above.

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