Answer:
\( {f}^{ - 1} (x) = \frac{1}{8} x + \frac{7}{8} \)
What are inverse functions?Inverse functions undo the operation of the original function. That is, if x undergoes function f to become f(x), then the inverse function (denoted by f⁻¹) reverse what function f does. Thus, the inverse function of f changes f(x) back into x.
Obtaining the expression for inverse functionsThe inverse of a function can be found in 3 main steps, which is to first let y= f(x), then make x the subject of formula before replacing x with f⁻¹(x) and y with x.
Let's apply the above steps to solve the question!
Given: f(x)= 8x +7
Step 1: Let y= f(x).
y= 8x +7
Step 2: Make x the subject of formula.
Start by subtracting 7 from both sides:
8x= y -7
Divide both sides by 8:
\(x = \frac{1}{8} y + \frac{7}{8} \)
Step 3: Replace x with f⁻¹(x) and y with x.
\( {f}^{ - 1} (x) = \frac{1}{8} x + \frac{7}{8} \)
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Sophie is buying a used car for 4500 dollars. The car is depreciating at a rate of 5% each month.
a) write an equation that models the value of the car after "x" months.
b) how much will the car be worth after 8 months
c) when will the car's value be $2,000
Answer: a) To model the value of the car after "x" months, we can use the formula for exponential decay:
value after x months = initial value * (decay rate)^x
where the initial value is $4500 and the decay rate is 0.95 (100% - 5% = 95%):
value after x months = 4500 * 0.95^x
b) To find the value of the car after 8 months, we can substitute x = 8 into the equation above:
value after 8 months = 4500 * 0.95^8
value after 8 months = 4500 * 0.6634
value after 8 months = $2985.30
Therefore, the car will be worth approximately $2,985.30 after 8 months.
c) To find when the car's value will be $2,000, we can set the equation above equal to 2000 and solve for x:
2000 = 4500 * 0.95^x
0.95^x = 2000/4500
0.95^x = 0.4444
Taking the logarithm of both sides with base 0.95:
x = log(0.4444)/log(0.95)
x ≈ 14.8
Therefore, the car's value will be $2,000 after approximately 15 months (rounded to the nearest whole month).
Step-by-step explanation:
Write the polynomial in factored form.
x^3−3x^2−10x
Answer:
x( x − 5 ) ( x + 2 )
Step-by-step explanation:
Answer:
x (x - 5)(x + 2)
Step-by-step explanation:
xion orders 5 loves of bread from the website bakery the total shipping weight is 9 pounds as model of the bread what is in pounds each of the lovaes
Find an LU factorization of the matrix A (with L unit lower triangular). A=
⎣
⎡
4
−8
10
−8
8
−4
3
5
−7
7
6
−7
0
3
−3
⎦
⎤
The LU factorization of matrix A is A = LU, where L = [[1, 0, 0], [-2, 1, 0], [1.5, -3, 1]] and U = [[4, -8, 10], [0, 24, -27], [0, 0, -12.5]].
Let's go step by step to find the LU factorization of matrix A.
Matrix A:
A =
[4, -8, 10]
[-8, 8, -7]
[6, -7, 3]
Step 1:
Initialize the L matrix as an identity matrix of the same size as A.
L =
[1, 0, 0]
[0, 1, 0]
[0, 0, 1]
Step 2:
Perform Gaussian elimination to obtain U.
- Multiply the first row of A by (1/4) and replace the first row of A with the result.
A =
[1, -2, 2.5]
[-8, 8, -7]
[6, -7, 3]
- Subtract 8 times the first row of A from the second row of A and replace the second row of A with the result.
A =
[1, -2, 2.5]
[0, 24, -27]
[6, -7, 3]
- Subtract 6 times the first row of A from the third row of A and replace the third row of A with the result.
A =
[1, -2, 2.5]
[0, 24, -27]
[0, 5, -12.5]
Step 3:
Update the L matrix based on the operations performed during Gaussian elimination.
L =
[1, 0, 0]
[0, 1, 0]
[0, 0, 1]
Step 4:
The resulting matrix A is the upper triangular matrix U.
U =
[1, -2, 2.5]
[0, 24, -27]
[0, 5, -12.5]
Therefore, the LU factorization of matrix A is:
L =
[1, 0, 0]
[0, 1, 0]
[0, 0, 1]
U =
[1, -2, 2.5]
[0, 24, -27]
[0, 5, -12.5]
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Write a number with one decimal place, that is bigger than 5 1/3 but smaller than 5. 5
The number that is bigger than 5 1/3 but smaller than 5.5 and has one decimal place is 5.4.
To find a number that is bigger than 5 1/3 but smaller than 5.5, we need to consider the values in between these two numbers. 5 1/3 can be expressed as a decimal as 5.33, and 5.5 is already in decimal form.
We are looking for a number between these two values with one decimal place.
Since 5.4 falls between 5.33 and 5.5, and it has one decimal place, it satisfies the given conditions.
The digit after the decimal point in 5.4 represents tenths, making it a number with one decimal place.
Therefore, the number 5.4 is bigger than 5 1/3 but smaller than 5.5 and fulfills the requirement of having one decimal place.
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The function f(x) is exponential and the function g(x) is linear, These functions have the following values: f(1) = 2 g(1) - 2.5 f(2)= 6 g(2) = 4 It follows that there must be a solution to f(x) = g(x) between x = 1 and x = 2.
True
False
Answer:
Step-by-step explanation:
There does not exist any solution of as thir graphs do not intersect.
Step-by-step explanation:
We are given that,
The values of the exponential function f(x) are f(1)= 2 and f(2)= 6.
That is, we get,
So, the function f(x) is .
Moreover, the values of the linear function g(x) are g(1) = 2.5 and g(2) = 4.
That is, the slope = = 1.5
Substituting the slope and point (1,2.5) in the linear equation , where m is the slope, we get,
i.e. b= 1
Thus, the function g(x) is .
Consider,
i.e.
Now, the function f(x) is exponentially increasing and the linear function g(x) is increasing between x= 1 and x= 2, but there is no point where the graphs of the functions are intersecting.
Thus, there is no solution of the equation .
Help PLEASE( HELP WITH BOTH)
Check the picture below.
\(\textit{Law of sines} \\\\ \cfrac{\sin(\measuredangle A)}{a}=\cfrac{\sin(\measuredangle B)}{b}=\cfrac{\sin(\measuredangle C)}{c} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{39}{\sin(53^o)}=\cfrac{JN}{\sin(65^o)}\implies \cfrac{39\sin(65^o)}{\sin(53^o)}=JN\implies 44.3\approx JN \\\\\\ \cfrac{39}{\sin(53^o)}=\cfrac{JS}{\sin(62^o)}\implies \cfrac{39\sin(62^o)}{\sin(53^o)}=JS\implies 43.1\approx JS\)
Make sure your calculator is in Degree mode.
Ms. Wells is going to order 4 large cheese pizzas for a class pizza party at the end of the school year. She expects she'll spend at least $40 on the pizzas. Let x represent how much ms. Wells expects each pizza to cost. Which inequality describes the problem?.
The correct inequality that describes the problem is 4x ≥ 40. Thus, the correct answer is A.
The answer is A because Ms. Wells is ordering 4 large cheese pizzas, and she expects to spend at least $40 on the pizzas. The inequality 4x ≥ 40 represents the total cost of the pizzas, which is 4 times the cost of each pizza (4x) and should be greater than or equal to $40. This inequality tells us that the total cost of the pizzas is at least $40, which is what Ms. Wells expects.
Option B, 4x > 40x, is incorrect because it doesn't make sense mathematically. The right side of the inequality is 40x, which is not related to the problem, and it also doesn't make sense that each pizza will cost 40 dollars.
Option C, 4x ≤ 40, is incorrect because it represents the total cost of the pizzas as less than or equal to $40, which doesn't match with Ms. Wells' expectation that she expects to spend at least $40 on the pizzas.
This question should be provided with answer choices, which are:
A. 4x ≥ 40B. 4x > 40xC. 4x ≤ 40The correct answer is A.
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Write a quadratic function in standard form that passes through (-7,0) , (-1,0) and (-6,-20)
Answer:
y = 4x^2 + 32x + 28
Step-by-step explanation:
Before we can find the standard form of the quadratic function with the given coordinates, we must first start with the intercept form, whose general equation is
y = a(x - p)(x - q), where
a is a constant determining concavity (essentially, whether the parabola opens upward or downward)(x, y) are any point on the parabola,and p and q are the x-intercepts/rootsStep 1: We can plug in (-6, -20) for x and y, -7 for p and -1 for q into the intercept form. This will allows us to solve for a:
-20 = a(-6 - (-7))(-6 - (-1))
-20 = a(-6 + 7)(-6 + 1)
-20 = a(1)(-5)
-20 = -5a
4 = a
Thus, the full equation in vertex form is
y = 4(x + 7)(x + 1).
Step 1: The general equation for standard form is
y = ax^2 + bx + c.
We can convert from vertex to standard form by simply expanding the expression. Let's ignore the 4 for a moment simply focus on (x + 7)(x + 1).
We can expand using the FOIL method, where you multiply
the first terms, the outer terms,the inner terms, and the last terms,then simplify by combining like termsWe see that the first terms are x and x, the outer terms are x and 1, the inner terms are 7 and x and the last terms are 7 * 1. Now, we multiply and simplify:
(x * x) + (x * 1) + (7 * x) + (7 * 1)
x^2 + x + 7x + 7
x^2 + 8x + 7
Step 3: Now, we can distribute the four to each term with multiplication:
4(x^2 + 8x + 7)
4x^2 + 32x + 28
Optional Step 4: We can check that our quadratic function in standard form, by plugging in -7, -1, and -6 for x and seeing that we get 0 as the y value for both x = -7 and x = -1 and -20 as the y value for x = -6:
Checking that (-7, 0) lies on the parabola of 4x^2 + 32x + 28:
0 = 4(-7)^2 + 32(-7) + 28
0 = 4(49) - 224 + 28
0 = 196 - 196
0 = 0
Checking that (-1, 0) lies on the parabola of 4x^2 + 32x + 28:
0 = 4(-1)^2 + 32(-1) + 28
0 = 4(1) - 32 + 28
0 = 4 - 4
0 = 0
Checking that (-6, -20) lies on the parabola of 4x^2 + 32x + 28:
-20 = 4(-6)^2 + 32(-6) + 28
-20 = 4(36) -192 + 28
-20 = 144 -164
-20 = -20
I attached a graph from Desmos to show how the function y = 4x^2 + 32x + 28 contains the points (-7, 0), (-1, 0), (-6, 20), further proving that we've correctly found the quadratic function in standard form passing through these three points
Stevens high school has 800 students every Wednesday 3% of the students stay after for chess club how many students attend chess club on Wednesdays
Answer: To find out how many students attend chess club on Wednesdays, we need to calculate 3% of the 800 students at Steven's high school. To do this, we multiply the number of students by 3% (which is equivalent to 0.03):
800 x 0.03 = 24
So, 24 students attend chess club on Wednesdays.
Step-by-step explanation:
Answer:
Step-by-step explanation:
Ryosuke is picking up his friend from work. The odometer reads 74,568 when he picks his friend up, and it reads 74,592 when he drops his friend off at his house. Ryosuke's car gets 28 miles per gallon and the price of one gallon of gas is $\$4.05$. What was the cost of the gas that was used for Ryosuke to drive his friend back home from work
Ryosuke drove his friend 24 miles, which used 1.14 gallons of gas. The total cost of the gas was $4.64, calculated by multiplying 1.14 gallons by the price of one gallon which was $4.05.
1. Calculate the number of miles driven: Subtract the odometer reading when Ryosuke picked his friend up (74,568) from the odometer reading when he dropped his friend off (74,592). This gives us the total number of miles driven (24).
2. Calculate the number of gallons used: Divide the total number of miles driven (24) by the car's gas mileage (28). This gives us the number of gallons used (1.14).
3. Calculate the cost of the gas: Multiply the number of gallons used (1.14) by the price of one gallon of gas ($4.05). This gives us the cost of the gas used ($4.64).
28 miles
= \($\frac{74,592-74,568}{28}$\)
= 1.14 gallons
Cost of gas
= 1.14 gallons x\($\$4.05$\)
= \($\$4.64$\)
1. 74,592 - 74,568 = 24
2. 24 / 28 = 1.14
3. 1.14 x $4.05 = $4.64
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Annette cycles a distance of 70 km from Midville to Newtown. Leaving Midville, she cycles for 1 hour 30 minutes at a constant speed of 20 km/h and then stops for 30 minutes. She then continues the journey to Newtown at a constant speed of 16 km/h.
Therefore, Annette cycles a total distance of 30 km from Midville to Newtown.
What is addition?Addition is an arithmetic operation that combines two or more numbers (called addends) to find their sum. The operation is denoted by the symbol "+". Addition is a fundamental operation in mathematics and is used in many different areas, such as algebra, calculus, and geometry. It is also an essential tool in everyday life, such as when adding up prices at the grocery store or calculating the total amount of money in a bank account.
Here,
We can use the formula:
distance = speed x time
to solve this problem. We can split the journey into two parts: the first part where Annette cycles at a speed of 20 km/h for 1 hour 30 minutes, and the second part where she cycles at a speed of 16 km/h for the remaining time.
First part of the journey:
distance = speed x time
distance = 20 km/h x 1.5 h
distance = 30 km
Annette cycles 30 km in the first part of the journey.
Second part of the journey:
Annette stops for 30 minutes, or 0.5 hours. So the total time for the second part of the journey is:
time = total journey time - time for first part - time for stop
time = (70 km / 16 km/h) - 1.5 h - 0.5 h
time = 2 h - 1.5 h - 0.5 h
time = 0 h
Note that the second part of the journey takes zero time because Annette has already used up all of her allotted time for the journey. Therefore, she does not cycle any further in the second part of the journey.
Total distance traveled:
The total distance traveled is the sum of the distances traveled in the two parts of the journey:
total distance = distance in first part + distance in second part
total distance = 30 km + 0 km
total distance = 30 km
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#4: Find the absolute value.
|4|
Answer:
4
The absolute value of 4 is the same since there is no negative
Answer:
4REMEMBER =
The absolute value is the positive of ANY NUMBER!
EXAMPLE =
| 6 | = 6
| -1,000,000 | = 1,000,000
| -7 | = 7
Hope this helps! <3
A soccer player is going to kick a soccer ball from one corner of a field to the opposite corner. If the field is 80 meters long and 60 meters wide, how far will the soccer player have to kick the ball
Answer:
100 meters
Step-by-step explanation:
To figure this out, do the Pythagorean theorem
a^2 + b^2 = c^2
60^2 + 80^2 = c^2
3600 + 6400 = c^2
10000 = c^2
c = 100
Answer:
100 meters
Step-by-step explanation:
a^2 + b^2 = c^2
Topology question. Answer only subpart a. Need Asap.
3. Let (X, Jx) and (Y, Ty) be topological spaces defined as follows: X = {D, O, R, K} Tx = {Ø, {0}, {D, O}, {O, R}, {D, O, R}, X} Y = {M, A, T, H} Jy = {0, {M}, {M, A}, {M, A, T}, Y} (a) Let E= {0, K
Given the topological spaces X = {D, O, R, K} with the topology Tx and Y = {M, A, T, H} with the topology Jy, we are asked to determine whether the set E = {0, K} is open in X and open in Y.
To determine whether the set E = {0, K} is open in the topological spaces X and Y, we need to check if E belongs to the respective topologies, Tx and Ty.
In X, the topology Tx is given by: Tx = {Ø, {0}, {D, O}, {O, R}, {D, O, R}, X}. We can see that E = {0, K} is not explicitly listed in Tx. Therefore, E is not open in X since it does not belong to the topology.
In Y, the topology Ty is given by: Jy = {0, {M}, {M, A}, {M, A, T}, Y}. Again, E = {0, K} is not explicitly listed in Ty. Hence, E is not open in Y as it does not belong to the topology.
In both cases, the set E = {0, K} is not open in the respective topological spaces X and Y because it is not a member of the defined topologies.
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Which one of the following options regarding the binary operation * is FALSE? binary operations
a. (a * b) * (c * d) = (a * (b * d)) * (d * c)
b. (a * b) ≠ (b * a) can be used as a counterexample to prove that the binary operation * is not commutative.
c. (a * b) * d = a * (b * d) proves that the binary operation * is associative.
d. The binary operation * does not have an identity element.
THe false statement among the given options regarding the binary operation * is d.
A binary operation is an arithmetic operation which is defined on a set of elements, also called operands. Binary operations are used in various branches of mathematics, including computer science, algebra, and geometry. The false statement among the following options regarding the binary operation * is:
The binary operation * does not have an identity element.
Definition of an identity element:
In mathematics, an identity element or neutral element is a special type of element in a set with respect to a binary operation. It leaves other elements unchanged when combined with them through a specific binary operation. A counter example can disprove a statement. If a * b = b * a for every a and b in a binary operation, then the binary operation is commutative.
The statement (a * b) ≠ (b * a) is a counterexample to prove that the binary operation * is not commutative. As the associative property states that the grouping of numbers does not matter, the statement (a * b) * d = a * (b * d) proves that the binary operation * is associative.
In the case of the binary operation * defined on the set S, if there exists an element e such that for every element a in S, a * e = e * a = a, then the element e is called the identity element. Since binary operations usually have identity elements, it is incorrect to claim that the binary operation * does not have an identity element.
Consequently, the false statement among the given options regarding the binary operation * is d. The binary operation * does not have an identity element.
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Among the given options, the statement (a * b) * (c * d) = (a * (b * d)) * (d * c) is false because it does not follow the associative property of binary operations.
Explanation:The false statement among the given options regarding the binary operation * is: (a * b) * (c * d) = (a * (b * d)) * (d * c). This is because it does not follow the associative property, rather it seems to be a random arrangement of the variables a, b, c and d. The associative property states that the way numbers are grouped does not change their result ( (a * b) * d = a * (b * d) ) but not the way it is represented in this option.
The option (a * b) ≠ (b * a) could be used as a counterexample to prove that the binary operation * is not commutative, indicating that order may matter in the operation. Option c is a representation of the associative property, and option d is a possibility depending on what the operation * actually is.
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Population density is the number of people per unit of area. The population density of a certain region is 45 people per square kilometer. If the region covers 31 square kilometers, what is the population of the region?
The population of the region is 1395 people.
What is a unit rate?It is the quantity of an amount of something at a rate of one of another quantity.
In 2 hours, a man can walk for 6 miles
In 1 hour, a man will walk for 3 miles.
We have,
The population density of a certain region is 45 people per square kilometer.
This means,
1 square km = 45 people
Multiply 31 on both sides.
31 square km = 31 x 45 people
31 square km = 1395 people
Thus,
The population of the region is 1395 people.
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a population is modeled by the differential equation dp dt = 1.2p 1 − p 4300 .
(a) For what values of P is the population increasing and for what values of P is
the population decreasing?
(b) If the initial population is 5500, what is the limiting pupulation?
(c) What are the equilibrium solutions?
a) the population cannot be negative, the limiting population is 4300.
b)the population is increasing when 0 < p < 4300 and decreases when p > 4300.
c)the equilibrium solutions are p = 0 and p = 4300.
(a) To determine when the population is increasing or decreasing, we need to look at the sign of dp/dt.
\(\frac{dp}{dt} = 1.2p(1 - \frac{p}{4300})\)
For dp/dt to be positive (i.e. population is increasing),
we need\(1 - \frac{p}{4300} > 0, or \ p < 4300.\)
For dp/dt to be negative (i.e. population is decreasing),
we need\(1 - \frac{p}{4300} < 0, or p > 4300.\)
Therefore, the population is increasing when 0 < p < 4300 and decreases when p > 4300.
(b) To find the limiting population, we need to find the value of p as t approaches infinity.
As t approaches infinity,\(\frac{dp}{dt}\)approaches 0. Therefore, we can set \(\frac{dp}{dt}\) = 0 and solve for p.
0 = 1.2p(1 - p/4300)
Simplifying, we get:
0 = p(1 - p/4300)
So, either p = 0 or 1 - p/4300 = 0.
Solving for p, we get:
p = 0 or p = 4300.
Since the population cannot be negative, the limiting population is 4300.
(c) Equilibrium solutions occur when\(dp/dt = 0.\)We already found the equilibrium solutions in part (b): p = 0 and p = 4300.
Therefore, the equilibrium solutions are p = 0 and p = 4300.
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a) The population is increasing when 0 < p < 4300, and decreasing when p > 4300.
b) The population cannot be negative, the limiting population is 4300.
c) these are the equilibrium solutions. At p = 0, the population is not
increasing or decreasing, and at p = 4300, the population is decreasing
but not changing in size.
(a) To determine when the population is increasing or decreasing, we
need to find the sign of dp/dt. We have:
dp/dt = 1.2p(1 - p/4300)
This expression is positive when 1 - p/4300 > 0, i.e., when p < 4300, and
negative when 1 - p/4300 < 0, i.e., when p > 4300.
Therefore, the population is increasing when 0 < p < 4300, and
decreasing when p > 4300.
(b) To find the limiting population, we need to solve for p as t approaches infinity. To do this, we set dp/dt = 0 and solve for p:
1.2p(1 - p/4300) = 0
This equation has two solutions: p = 0 and p = 4300. Since the population cannot be negative, the limiting population is 4300.
(c) To find the equilibrium solutions, we need to solve for p when dp/dt = 0. We already found that the only solutions to dp/dt = 0 are p = 0 and
p = 4300.
Therefore, these are the equilibrium solutions.
At p = 0, the population is not increasing or decreasing, and at p = 4300,
the population is decreasing but not changing in size.
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the largest of these five squares has side length 27 units, and each additional square's side length is 2/3 as large as the one before. What is the perimeter and area of the entire shape?
The total area is 1289.41 units².
The total perimeter is 281.32 units.
What is the total area and perimeter?The first step is to determine the side lengths of the other squares:
Length of the second square = 2/3 x 27 = 18 Length of the third square = 2/3 x18 = 12 Length of the fourth square = 2/3 x 12 = 8Length of the fifth square = 2/3 x 8 = 5.33Area of a square = length²
Perimeter of a square = 4 x length
Area of the first square = 27² = 729 Area of the second square = 18² = 324Area of the first square = 12² = 144 Area of the first square = 8² = 64Area of the first square = 5.33² = 28.41Total area = sum of the areas of the 5 squares = 1289.41 units²
Perimeter of the first square = 4 x 27 = 108 unitsPerimeter of the second square = 4 x 18 = 72Perimeter of the third square = 4 x 12 = 48 Perimeter of the fourth square = 4 x 8 = 32 Perimeter of the fifth square = 4 x 5.33 = 21.32Total perimeter = 281.32 units
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Answer:
PERIMETER: 584/3, AREA: 11605/9
Step-by-step explanation:
PERIMETER: The side lengths form a geometric series with a = 27, and r = 2/3. Along the bottom we see all five lengths, and those same lengths are seen along the top. The sum of these lengths is 27+18+12+8+16/3=211/3.
We can also calculate this as the sum of the geometric series:
27 (1 - (2 / 3) ^ 5)/ 1 - (2 / 3) = 27(1 - 32 / 243)/ (1 / 3) = 81 x 211/243 = 211/3
We see these lengths twice, once along the bottom and once as horizontal segments on the top. We also add the left side of 27. The vertical segments on the right must also have a total length of 27, since they cover the same ground as the left side.
The total perimeter: 2 x 211/3 + 2 x 27 = 584/3
AREA: 27^2 + 18^2 + 12^2 + 8^2 + (16/3)^2 = 11605/9
A $86 ,000 trust is to be invested in bonds paying 9% , CDs paying 6% , and mortgages paying 10% . The bond and CD investment together must equal the mortgage investment. To earn a $7180 annual income from the investments, how much should the bank invest in bonds?
Answer:
to earn a $7180 annual income from the investments, the bank needs to invest $10,000 into the bonds.
Step-by-step explanation:
Let the mortgage investment be X
The Bond to be Y
and the CDs to be Z
Thus;
X+Y+Z = 86000 ------- (1)
Y + Z = X ------------(2)
10X + 9Y + 6Z = 7180 × 100 ------ (3)
So;we now have:
X+Y+Z = 86000 ------- (1)
Y + Z = X ------------(2)
10X + 9Y + 6Z = 718000 ------ (3)
Let ; replace X with Y+Z in equation (1) and (3)
Y+Z + Y+Z = 86000
2Y + 2Z = 86000
Divide both sides by 2
Y+Z = 43000 ------ (4)
From equation (3)
10X + 9Y + 6Z = 718000
10(Y+Z) + 9Y + 6Z = 718000
10Y +10Z + 9Y +6Z = 718000
19Y + 16Z = 718000 -----(5)
Y+Z = 43000 ------ (4)
19Y + 16Z = 718000 -----(5)
Using elimination method; multiply (-16) with equation (4) and (5) ; so, we have:
-16 Y -16 Z = -688000
19Y + 16Z = 718000
3Y + 0 = 30000
3Y = 30000
Y = 30000/3
Y = 10000
From (4);
Y+Z = 43000
So; replace Y with 10000; we have:
10000 + Z = 43000
Z = 43000 - 10000
Z = 33000
From (1) ;
X+Y+Z = 86000
X + 10000 + 33000 = 86000
X + 43000 = 86000
X = 86000 - 43000
X = 43000
Since we assume the bond to be Y and Y = $10000;
Thus; to earn a $7180 annual income from the investments, the bank needs to invest $10,000 into the bonds.
consider the infinite geometric series infinite e n=1. a. Write the first four terms of the series.
b. Does the series diverge or converge?
c. If the series has a sum, find the sum.
a. The first four terms of an infinite geometric series can be found using the formula a, ar, ar^2, ar^3, where 'a' is the first term and 'r' is the common ratio.
b. To determine if the series converges or diverges, we need to examine the value of the common ratio (r). If the absolute value of r is less than 1 (|r| < 1), the series converges. If the absolute value of r is greater than or equal to 1 (|r| ≥ 1), the series diverges.
c. If the series converges, we can find the sum using the formula S = a / (1 - r), where 'S' is the sum of the series.
Now, let's apply these concepts to the given infinite geometric series.
a. The first term of the series is 'e', and the common ratio is 'e'. Thus, the first four terms of the series are:
e, e * e, e * e^2, e * e^3
Simplifying this, we have:
e, e^2, e^3, e^4
b. To determine if the series converges or diverges, we need to check the absolute value of the common ratio. In this case, the common ratio is 'e', which is greater than 1. Therefore, the series diverges.
c. Since the series diverges, there is no finite sum (S) for this infinite geometric series. The sum keeps increasing without bounds as more terms are added.
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Consider the infinite geometric series infinity sigma n=1 -4(1/3)^n-1. In this, the lower limit of the summation notion is "n=1".
a. Write the first four terms of the series.
b. Does the series diverge or converge?
c. If the series has a sum, find the sum.
Jeremy spent the entire weekend earning money by working around his neighborhood 15% of his total earnings was from raking leaves and $36 mowing lawns and earn the rest of his money walking dogs the end of the weekend with earning $90 how much money did he earn by walking dogs?
Answer: $40.50
Step-by-step explanation:
Since 15% of his total earnings was from raking leaves. The earning from taking leave will be:
= 15% × $90
= 0.15 × $90
= $13.50
Earnings from mowing lawns = $36
The earnings from walking dogs will be:
= $90 - $36 - $13.50
= $40.50
describe one situation where parametric equations can describe a physical situation where a standard relationship between two variables will not suffice
Consider presenting a particle moving through three dimensions as an illustration. Several x, y, and z-based equations could be used to describe its path.
Explain the term parametric equations?There are two kinds of parametric equations which are frequently encountered in practical applications.
The concept problem described the first as circular motion.Projectile motion is the second type.Circular Motion:
In parametric equations that model circular motion, sine and cosine have periodic functions for x and y.
Either x is a sine function and y is a cosine function, or vice versa.Thus, Consider presenting a particle moving through three dimensions as an illustration. Several x, y, and z-based equations could be used to describe its path.Projectile Motion:
The vertical component of projectile motion is quadratic, and the horizontal component is linear.
This is due to the fact that starting height, starting velocity, and gravitational force are the three variables that have the most impact on an object's location throughout flight. The vertical component has no bearing on the horizontal component.To know more about the parametric equations, here
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Select the correct answer.
Solve the quadratic equation given below. (9x+13)^2=49
X= -2/3; -20/9
X= 2/3; 20/9
X= 2/3; -20/9
X= -2/3; 20/9
Answer:
x = -2/3; -20/9 so A
Step-by-step explanation:
im 100% percent sure:)
The dimension of the row space of a 3 x 3 matrix A is 2. (a) What is the dimension of the column space of A? (b) What is the rank of A? (c) What is the nullity of A? (d) What is the dimension of the solution space of the homogeneous system Ax = 0?
a) the dimension of its column space is also 2. b) the rank of A is 2. c) the nullity of matrix A is 1. d) the dimension of the solution space of the homogeneous system \(A_x = 0\) is also 1.
(a) The dimension of the row space of a matrix is equal to the dimension of its column space. So, if the dimension of the row space of matrix A is 2, then the dimension of its column space is also 2.
(b) The rank of a matrix is defined as the maximum number of linearly independent rows or columns in the matrix. Since the dimension of the row space of matrix A is 2, the rank of A is also 2.
(c) The nullity of a matrix is defined as the dimension of the null space, which is the set of all solutions to the homogeneous equation Ax = 0. In this case, the matrix A is a 3 x 3 matrix, so the nullity can be calculated using the formula:
nullity = number of columns - rank
nullity = 3 - 2 = 1
Therefore, the nullity of matrix A is 1.
(d) The dimension of the solution space of the homogeneous system Ax = 0 is equal to the nullity of the matrix A. In this case, we have already determined that the nullity of matrix A is 1. Therefore, the dimension of the solution space of the homogeneous system \(A_x = 0\) is also 1.
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What is another name for a dependent samples t-test?Select one:a. Freed sampleb. Paired samplec. Single sampled. Double sample
Another name for a dependent samples t-test is a paired samples t-test. It is a statistical test used to determine if there is a significant difference between two related variables from the same sample.
A dependent samples t-test is a statistical test used to compare the means of two related variables from the same sample. It is used when the two variables being compared are dependent on each other, such as pre- and post-test scores for the same group of individuals or the same group of subjects being measured under different conditions.
The term "paired samples" refers to the fact that each observation in one sample is matched with a corresponding observation in the other sample, creating a pair. The dependent samples t-test is used to determine if the mean difference between the two variables is statistically significant, indicating that there is a significant change between the two related variables.
In conclusion, a dependent samples t-test is also known as a paired samples t-test, which is used to determine if there is a significant difference between two related variables from the same sample. The term "paired samples" refers to the matching of each observation in one sample with a corresponding observation in the other sample, creating a pair.
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Can somebody who remembers how to do this plz answer correctly thx!!!!
(Will mark as brainliest)
:D
Answer:
11.
\(1 \times \frac{3}{8} \)
12.
\(2 \times \frac{5}{6} \)
identify the parts of each algebraic expression given below.
8. 14k + m + n - 12
9. 5w - 4
Hello!
Let's identify the parts of all the algebraic expressions below.
Please remember that
Variables are lettersCoefficients are numbers before variablesConstants are numbers without any variablesA term can be a variable, a constant, or a coefficient and a variable.#1:
4x+7y+8
Variables: x, y
Coefficients: 4, 7
Constant: 8
Number of Terms: 3
\(\rule{300}{1}\)
#2:
Variables: a, b, c
Coefficients: 9, 3
Constants: No constants here!
Number of terms: 3
\(\rule{300}{1}\)
#3:
Variables: d, x
Coefficients: 3, 1
Constant: 10
Number of terms: 3
_________________________________________
#4:
variables: x, y
coefficients: 2, 6
constant: 2
number of terms: 3
______________________________________
#5:
variables: b, c, d
coefficients: 8, -7, 11
constants: -5
number of terms: 4
________________________
#6:
variables: s, t
coefficients: 18, 2
constant: -8
number of terms: 3
Hope everything is clear.
Let me know if you have any questions!
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00:00
Which of the following are partial products for 43 x 17? Choose all that apply.
✓
A 3
U
B. 21
с.
28
✓
D. 40
E 400
Answer:
the answer is D. 40
Step-by-step explanation:
Which of the following is not a standard metric unit? a. kilogram b. meter c. second d. gram
Exactly D
well i dont know why gram is non standard
hope it helps.
The correct answer is d. gram. The gram is indeed a metric unit; however, it is not considered a standard metric unit in the International System of Units (SI).
It is equal to one thousandth of a kilogram. The kilogram (a), meter (b), and second (c) are all standard metric units and form the basis of the International System of Units (SI). The kilogram is the unit of mass, the meter is the unit of length, and the second is the unit of time. These units are universally recognized and used in scientific, engineering, and everyday measurements.
Therefore, the gram (d) is the correct option as it is not considered a standard metric unit.
The rest of the options are as follows:
a. kilogram: The kilogram is the standard unit for mass in the International System of Units (SI). It is defined as the base unit for mass.
b. meter: The meter is the standard unit for length in the SI. It is defined as the base unit for length and is commonly used to measure distances.
c. second: The second is the standard unit for time in the SI. It is defined as the base unit for time and is commonly used to measure durations and intervals.
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