Using the quotient rule of logarithms, we have:
=log2 51.2 − log2 1.6
= \(log2 (51.2/1.6)\)
Simplifying the numerator, we have:
\(log2(51.2/1.6) = log2(32)\)
Using the fact that 32 = 2^5, we have:
log2 32 = log2 2^5 = 5
log2 51.2 − log2 1.6 = log2 (51.2/1.6) = log2 32 = 5
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ASAP PLS I NEED IT AND TY
Answer:
2
Step-by-step explanation:
to solve this equation you must find what you multiply A to to equal A'
you can solve this by dividing 18 by 9
18 / 9 = 2
that is your answer
What are the 5 examples of quadratic function?
Five examples of quadratic functions are: f(x) = -2x² + 2x - 5, f(x) = x² - 7x - 4, f(x) = x² - 4x + 4, f(x) = 2x² - 3x - 2, f(x) = x² + 2x + 4
A quadratic function is polynomial of degree 2. The standard form of a quadratic function is:
f(x) = ax² + bx + c, with a ≠ 0
5 examples of quadratic function:
1. Quadratic function with negative leading coefficient, or a is negative,
f(x) = -2x² + 2x - 5
The graph of this function opens downward
2. Quadratic function with positive leading coefficient, or a is positive,
f(x) = x² - 7x - 4
The graph of this function opens upward
3. Quadratic functions that have only 1 root
f(x) = (x - 2)²
f(x) = x² - 4x + 4
4. Quadratic functions that have 2 different real roots
f(x) = 2x² - 3x - 2
5. Quadratic functions that have complex conjugate roots
f(x) = x² + 2x + 4
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find the domain (3,2),(6,2),-(5,2),(-1,2)
is the following a probability model? what do we call the outcome "red"?
The following a probability model? what do we call the outcome No, the provided information is not sufficient to determine if it is a probability model. The outcome "red" is typically referred to as an event.
A probability model is a mathematical representation of a random experiment, where the sample space is defined, and probabilities are assigned to all possible outcomes. To determine if the given information is a probability model, we would need to know the complete list of possible outcomes, their corresponding probabilities, and ensure that the probabilities meet the necessary conditions (sum up to 1 and are non-negative).
Based on the limited information provided, we cannot determine if it is a probability model. The outcome "red" is called an event in the context of probability.
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In which step did Carson make his first mistake?
1 - 4x = 2/3 (-2 + x)
Step 1: 1 - 4x = - 4/3 + x
Step 2: 1 = -4/3 + 5x
Step 3: 7/3 = 5x
Step 4: 7/15 = x
Answer: the first because he didn’t distribute the 2/3 with all the things in the parentheses
Step-by-step explanation: it’s supposed to be -4/3 + 2/3x the first step
Consider the equations y = 3x and y = -12- x.
Complete the table of values for the equation y = 3x.
Х
-7
-5
-3
Answer:
x | -7 -5 -3
y | -21 -15 -9
Step-by-step explanation:
y = 3x
If x = -7 then y = 3 × (-7) = -21
x = -5 then y = 3 × (-5) = -15
x = -3 then y = 3 × (-3) = -9
If f(x)=3x-4 and g(x)=x2 find the value of f(3)-g(2).
ryan rides his bike for 30 minutes and travels a distance of 4 miles. how fast was he traveling? 4 miles per hour 6 miles per hour 8 miles per hour none of these choices are correct.
Ryan rides his bike for 30 minutes and travels a distance of 4 miles. He was traveling 8 miles per hours.
Ryan rides his bike for 30 minutes and travels a distance of 4 miles.
We have to determine how fast he was traveling.
Time = 30 minutes
First we convert the minutes in hours.
As we know that;
1 hour = 60 minutes.
So 1 minute = 1/60 hours
30 minutes = 30/60 hours
30 minutes = 1/2 hours
Distance = 4 miles
The formula of speed is;
Speed = Distance/Time
Speed = 4/(1/2) miles per hours
Speed = 4 × 2 miles per hours
Speed = 8 miles per hours
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What is the difference between permutations and combinations.
Answer:
permutations: order matters
combinations: order doesn't matter
Answer:
A combination doesn't need to be in a specific order, unlike permutation which needs to go in order.
Step-by-step explanation:
the columns of exra5 are vectors in r4 . do they form a basis for r4? if you decided that the columns of exra5 form a basis for r4 type exa5a
Yes, the columns of exra5 do form a basis for r4. A basis is a set of linearly independent vectors that span a vector space, and in this case the vector space is R4. The four columns of exra5 are linearly independent, and they span the entire R4 space, so they form a basis for R4.
Yes, the columns of exra5 do form a basis for r4. A basis is a set of linearly independent vectors that span a vector space, and in this case the vector space is R4. The columns of exra5 must be linearly independent, which means that no linear combination of them can equal the zero vector. Furthermore, the columns of exra5 must span the entire R4 space, meaning that any vector in R4 can be expressed as a linear combination of the columns of exra5. This is equivalent to saying that the columns of exra5 can be used to generate the entire vector space R4. If these two conditions are met, then the columns of exra5 form a basis for R4. In this case, both conditions are met, so the columns of exra5 do form a basis for R4. Moreover, since there are four columns, the basis for R4 is called a basis of size four. The special property of a basis of size four is that it is the smallest possible basis for R4, meaning that no other set of vectors can form a basis for R4 with fewer than four vectors.
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The winner of a raffle will receive a new car. If 10,000 raffle tickets were sold and you purchased 26 tickets, what are the odds against your winning the car? (Do not reduce your answer.)
a
26 : 9974
b
26 : 10000
c
10000 : 26
d
9974 : 26
Answer:
b
Step-by-step explanation: you take your number of tickets purchased and put it next to the total number of tickets sold and you have your answer
What is 30% as a decimal
Rhonda went out to dinner.
• The price of her meal was
$15.55.
• The sales tax was 7% of the
price of the meal.
• The tip was 18% of both the
meal and the sales tax.
How much money did Rhonda
pay for the meal, including tax
and tip?
Answer:
18.54
Step-by-step explanation:
15.55 X 7% = 1.0885
15.55 + 1.0885 = 16.6385 X 18% = 2.99493
15.55 + 2.99493 =18.54493
The velocity function (in meters per second) for a certain particle, moving in a straight line, is v(t)=t^2-2t-8 for 1≤t≤6
A) Find the displacement of the particle over this period
B) Find the total distance by the particle over the time period
the total distance traveled by the particle over the time period is 14/3 meters.
To find the displacement of the particle over the time period, we need to integrate the velocity function v(t) over the given interval.
A) Displacement:
The displacement is given by the definite integral of the velocity function v(t) over the interval [1, 6]:
Displacement = ∫[1, 6] (t^2 - 2t - 8) dt
To evaluate this integral, we can use the power rule of integration:
Displacement = [(1/3) * t^3 - t^2 - 8t] evaluated from 1 to 6
= [(1/3) * (6^3) - 6^2 - 8 * 6] - [(1/3) * (1^3) - 1^2 - 8 * 1]
= [72 - 36 - 48] - [1/3 - 1 - 8]
= -12 - (-22/3)
= -12 + 22/3
= (-36 + 22)/3
= -14/3
Therefore, the displacement of the particle over the time period is -14/3 meters.
B) Total Distance:
To find the total distance traveled by the particle over the time period, we need to consider the absolute value of the velocity function and integrate it over the interval [1, 6]:
Total Distance = ∫[1, 6] |t^2 - 2t - 8| dt
Since the velocity function is already non-negative for the given interval, we can calculate the total distance by evaluating the integral of v(t) directly:
Total Distance = ∫[1, 6] (t^2 - 2t - 8) dt
Using the same integral from part A, we can evaluate it as:
Total Distance = (-14/3) meters
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Members at a popular fitness club currently pay a $40 per month membership fee. The owner of the club wants to raise the fee to $50 but is concerned that some members will leave the gym if the fee increases. To investigate, the owner plans to survey a random sample of the club members and construct a 95% confidence interval for the proportion of all members who would quit if the fee was raised to $50.
(a) Explain the meaning of "95% confidence" in the context of the study.
(b) After the owner conducted the survey, he calculated the confidence interval to be 0.18 0.075 Interpret this interval in the context of the study.
(c) According to the club's accountant, the fee increase will be worthwhile if fewer than 20% of the members quit. According to the interval from part (b), can the owner be confident that the fee increase will be worthwhile? Explain.
(d) One of the conditions for calculating the confidence interval in part (b) is that and. Explain why it is necessary to check this condition.
Answer:(a) "95% confidence" means that if we were to repeat this study many times, we would expect the true proportion of members who would quit to be within the calculated interval for 95% of those studies. In other words, we can be 95% confident that the true proportion of members who would quit falls within the interval.
(b) The interval is [0.18, 0.075]. This means that we are 95% confident that the true proportion of members who would quit if the fee was raised to $50 falls between 0.18 and 0.075.
(c) No, the owner cannot be confident that the fee increase will be worthwhile because the interval from part (b) includes 20%. If the true proportion of members who would quit is 20%, then the fee increase would not be worthwhile. Since the interval includes 20%, we cannot be confident that the true proportion is less than 20%.
(d) One of the conditions for calculating the confidence interval is that the sample size is large enough and that the number of successes and failures in the sample are both at least 10. This is necessary because the interval calculation relies on the normal distribution, which is only valid when the sample size is large enough and the number of successes and failures are both at least 10. If this condition is not met, then the interval calculation may not be accurate or valid.
Step-by-step explanation:
The figure shows SV intersecting plane A at point P, a right angle. Points R, T and U also lie in the plane. Which statements are true based on the figure?
Based on the figure, the statements that are true are
SV is perpendicular to TPSV is perpendicular to plane Apoint P lies on SV and in plane AThat is, the first, second and fifth statements.
From the image, we will determine the statements that are true based on the figure.
For the first statement - SV is perpendicular to TP
From the figure,
SV is a line intersecting plane A at point P, at right angle. That is, SV is perpendicular to point P. Then, SV is perpendicular to plane A since point P lies on the plane.
Also, P lies on the plane (plane A); then we can infer that TP is parallel to plane A since point T also lie on the plane (plane A).
Since, SV is perpendicular to the plane, then SV is also perpendicular to TP.
∴ The statement (SV is perpendicular to TP) is true
For the second statement - SV is perpendicular to plane A
As stated above, SV is perpendicular to point P. Since point P lies on the plane (plane A), then SV is perpendicular to plane A.
∴ The statement (SV is perpendicular to plane A) is true
For the third statement - points S, P and Q are collinear
Collinear points are points that lie on the same line.
Points S, P and Q are not collinear because, a single line cannot pass through the three points, that is, the points (S, P, and Q) do not lie on a single line.
∴ The statement (points S, P and Q are collinear) is NOT true
(From the image, an example of points that are collinear are points S, P, and V)
For the fourth statement - points R, T, and U are collinear
As explained above, points R, T, and U are not collinear because, a single line cannot pass through the three points, that is, the points (R, T, and U) do not lie on a single line.
∴ The statement (points R, T and U are collinear) is NOT true
NOTE: (The points only lie in the same plane (plane A), that is, they are coplanar)
For the fifth statement - point P lies on SV and in plane A
Since line SV intersects plane A at point P, that means point P lies in plane A. Also point P lies on line SV since it is on the line as shown in the image.
∴ The statement (point P lies on SV and in plane A) is true
For the sixth statement - points U, S, V, and Q are coplanar
Points or lines are said to be coplanar if they lie in the same plane.
Of the given points, only point U lies in plane A. Points S, V, and Q do not lie in the same plane and as well do not lie in the same plane as point U.
∴ The statement (points U, S, V, and Q are coplanar) is NOT true.
(From the image, an example of points that are coplanar are points U,P,R, and T because they lie on the same plane).
Hence, based on the figure, the statements that are true are the first, second and fifth statements. that is
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Leslie tallied the number of times her favorite new song played on 6 radio radio stations this week. She tallied:
What was u of the number of plays
If necessary, round to the nearest tenth.
The question asks for the mean or average of the number of times Leslie's favorite new song played on 6 radio stations.
To find the mean, we need to add up the number of plays on each station and then divide by the total number of stations. Let's call the number of plays on each station: x1, x2, x3, x4, x5, x6.
Then, the total number of plays is: x1 + x2 + x3 + x4 + x5 + x6.
To find the mean, we divide the total by 6 (the number of stations).
So, the formula for the mean is:
mean = (x1 + x2 + x3 + x4 + x5 + x6) / 6
We don't have the actual numbers for the plays on each station, so we can't solve for the mean. However, we can still write the formula and explain how to solve the problem if we had the actual numbers.
Summary: To find the mean or average number of plays for Leslie's favorite new song on 6 radio stations, we need to add up the number of plays on each station and then divide by 6. The formula for the mean is (x1 + x2 + x3 + x4 + x5 + x6) / 6. If we had the actual numbers for the plays on each station, we could plug them into the formula and solve for the mean.
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Find the equation of the line that is perpendicular to 5x+3y=30 and passes through (-20, -10).
Answer:
\(\large\boxed{\sf 3x - 5y +10=0}\)
Step-by-step explanation:
A equation is given to us and we need to find out the equation of the line which is perpendicular to the given line and passes through (-20,-10). The given line is ,
\(\longrightarrow 5x + 3y = 30 \\\)
Convert this into slope intercept form of the line , which is y = mx + c.
\(\longrightarrow 3y = -5x +30 \\\)
Divide both sides by 3,
\(\longrightarrow y =\dfrac{-5}{3}x+\dfrac{30}{3}\\\)
Simplify ,
\(\longrightarrow y=-\dfrac{5}{3}x + 10 \\\)
On comparing it to slope intercept form, we have ;
\(\longrightarrow m= \dfrac{-5}{3} \\\)
Now as we know that the product of slopes of two perpendicular lines is -1 . Therefore the slope of the perpendicular line will be negative reciprocal of the slope of first line. As ,
\(\longrightarrow m_{\perp}=-\bigg(\dfrac{-3}{5}\bigg) = \dfrac{3}{5} \\\)
Now we may use the point slope form of the line which is ,
\(\longrightarrow y - y_1 = m(x-x_1) \\\)
Substitute the respective values ,
\(\longrightarrow y -(-10) = \dfrac{3}{5}\{ x -(-20)\}\\\)
Simplify the brackets ,
\(\longrightarrow y +10 =\dfrac{3}{5}(x+20) \\\)
Cross multiply ,
\(\longrightarrow5( y +10)= 3(x+20)\\\)
Distribute ,
\(\longrightarrow 5y +50 = 3x +60\\\)
Subtract (5y +50) to both sides ,
\(\longrightarrow 3x + 60 -5y -50=0 \\\)
Simplify ,
\(\longrightarrow \underline{\underline{ 3x -5y +10=0}} \\\)
I need help fast I’m lost
The two probabilities are:
P(A given B) = 1/11P(B given A) = 1/7How to find the probabilities?Here we need to use the Venn Diagram to find the probabilities.
First, the probability of A given B, we can see that set B has 33 elements, of these 33, there are 3 that also belong to A, then the probability is given by the quotient between these two:
P(A given B) = 3/33 = 1/11
For the second case we do the same thing but now look at set A, there are 21 elements and 3 also belong to B
P(B given A) = 3/21 = 1/7
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The base of a rectangular prism is a rectangle
with
sides that are 7 inches and 5 inches long. Its height is
10 inches. Write two different equations that you can
uise to find the volume
Two different equations that are used to calculate the volume of a rectangular prism are V = B × h and V = l× w× h, where, V --> volume and B --> base area.
We have a rectangular prism with base as a rectangle with the following information
Length of base rectangle, l = 7 inches
Width of base rectangle, w = 5 inches
Height of rectangular prism, h = 10 inches
The first equation for the volume of a rectangular prism is equal to multiplcation of its base area by its height. Mathematically, it can be written as, V = B × h --(1)
where, B --> base area
V --> volume
Here base is a rectangle, so base area is equivalent to area of rectangle. The second equation used for calculating the volume of rectangular prism is written
V = l× w× h
where l, w and h are dimensions of prism.
So, using one of above equation, the
volume of rectangular prism is 350 inch³.
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Farah saved $15 everyday while shirley saved $10 everyday. Shirley started saving money 5 days earlier than Farah. How many days will it take Farah to have the same amount of savings as Shirley?
Answer:
6 days
Step-by-step explanation:
shirley earned 50 dollars before farah started saving
50-15
60-30
70-45
80-60
90-85
100-100
6 days
In 10 days Farah and Shirley will have the same amount of money
What is a linear equation in one variable?A linear equation is an alzebraic expression which has highest degree of one and contains only one variable.
In the given question farah saved 15$/day and Shirley saved 10$/day
Shirley started 5 days earlier so in 5 days she will save 10 x 5 = 50$
let assume days to be x.
So,
10x + 50 = 15x
5x = 50
x = 10 .
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write the first four terms of each sequence
f(n) = (n - 1)(n - 2)
Why does a plasmid that is going to be used in both yeast and bacteria need to have two different selection markers? Select ALL that apply. The same selection (e.g. presence of an antibiotic) may not work for both hosts. Having more genes makes the plasmid bigger and thus easier to work with and maintain. In cases where the same selection can be used in both hosts, two selection markers are still needed because bacteria and yeast recognize different promoters The codons used by bacteria correspond to different amino acids than they do in yeast.
A plasmid used in both yeast and bacteria requires two different selection markers because the same selection may not work for both hosts and bacteria and yeast recognize different promoters.
When using a plasmid in both yeast and bacteria, it is important to have two different selection markers for several reasons. First, the same selection, such as the presence of an antibiotic, may not be effective in both hosts. Different organisms have varying sensitivities to antibiotics, so a marker that works in bacteria may not work in yeast or vice versa. Therefore, two different selection markers are needed to ensure successful selection in both hosts.
Additionally, bacteria and yeast recognize different promoters, which are DNA sequences that control the initiation of gene expression. Promoters are specific to each organism and play a crucial role in regulating gene expression. By incorporating two different selection markers into the plasmid, each marker can be driven by a promoter recognized specifically by the corresponding host. This ensures that the selection marker is effectively expressed in the appropriate host organism, enabling accurate selection and maintenance of the plasmid.
In summary, using two different selection markers in a plasmid intended for both yeast and bacteria is necessary because the same selection may not be effective in both hosts, and different promoters are recognized by bacteria and yeast. This approach allows for successful selection and maintenance of the plasmid in both organisms.
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4 = 8 Y=.16
2) Dylan loves cookies and always takes them from the cookie jar when his mom isn't looking. The cookie jar
starts with 64 cookies in it. If Dylan takes half of the cookies every day, how many cookies are left after 5 days?
a hexagon will be dilated on a coordinate grid to create a smaller hexagon. the hexagon is dilated using the origin as the center of the dilation. what rule could represent this dilation?
A rule that could represent this dilation of a hexagon on a coordinate grid with the origin as the center is: (x, y) → (kx, ky), where k is the dilation factor (0 < k < 1) for creating a smaller hexagon.
The rule that could represent this dilation is to multiply the coordinates of each vertex of the original hexagon by the scaling factor (the factor by which the hexagon is being dilated) and the distance from the origin. Since the origin is the center of the dilation, the distance from the origin to any point on the hexagon remains constant. Therefore, the rule for dilating a hexagon with the origin as the center of dilation can be written as:
New Vertex = Scaling Factor x Distance from Origin x Old Vertex
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The rule that represents the dilation of the hexagon with the origin as the center of dilation is:
\((x\prime, y\prime) = (xr, yr)\)
r is the ratio of the side lengths of the image to the pre-image, and (x, y) are the coordinates of a point on the pre-image.
A hexagon means to scale it up or down in size while maintaining its shape.
The hexagon will be made smaller.
The center of the dilation is the origin, which means that the hexagon will be scaled equally in all directions from the center.
To find the rule that represents this dilation, we can use the formula for dilation.
The formula for dilation is:
\((x\prime, y\prime) = k(x, y)\)
(x, y) are the coordinates of a point on the pre-image (the original hexagon), \((x\prime, y\prime)\) are the coordinates of the corresponding point on the image (the smaller hexagon), and k is the scale factor.
The center of dilation is the origin, which means that the coordinates of the center of the pre-image and the image are both (0, 0). Since the hexagon is being scaled down, the scale factor k must be less than 1.
To find the value of k, we need to know the ratio of the side length of the image to the side length of the pre-image. Let's say that the side length of the pre-image is s, and the side length of the image is \(s\prime\).
The scale factor k can be found using the formula:
\(k = s\prime / s\)
Since the hexagon is being scaled down, we know that\(s\prime < s.\)
Let's say that the ratio of the side lengths is r, where:
\(r = s\prime / s\)
Then we can rewrite the formula for k as:
\(k = r / 1\)
The center of dilation is the origin, the coordinates of each point on the pre-image are equal to the length of their respective sides.
The vertices of the pre-image using the following coordinates:
A = (0, s)
\(B = (s\sqrt 3/2, s/2)\)
\(C = (s\sqrt 3/2, -s/2)\)
\(D = (0, -s)\)
\(E = (-s\sqrt3/2, -s/2)\)
\(F = (-s\sqrt3/2, s/2)\)
The coordinates of the corresponding vertices on the image, we can substitute these coordinates into the formula for dilation:
\(A\prime = k(0, s) = (0, rs)\)
\(B\prime = k(s\sqrt3/2, s/2) = (s\sqrt3/2 r, s/2 r)\)
\(C\prime = k(s\sqrt3/2, -s/2) = (s\sqrt3/2 r, -s/2 r)\)
\(D\prime = k(0, -s) = (0, -rs)\)
\(E\prime = k(-s\sqrt3/2, -s/2) = (-s\sqrt3/2 r, -s/2 r)\)
\(F\prime = k(-s\sqrt3/2, s/2) = (-s\sqrt3/2 r, s/2 r)\)
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What is the binary number for 21
Answer:
I believe this is 10101
explosive devices used in mining operations produce nearly circular craters when detonated. the radii of these craters are exponentially distributed with mean 10 feet. find the mean and variance of the areas produced by these explosive devices.
The mean and the variance of the areas produced by these explosive devices is 314
Variance:
In statistics, variance refers a measure of dispersion that takes into account the spread of all data points in a data set.
Given,
Here explosive devices used in mining operations produce nearly circular craters when detonated. the radii of these craters are exponentially distributed with mean 10 feet.
Now, we need to find the mean and variance of the areas produced by these explosive devices.
In order to find the means and variance we have to use the formula ,
A = πr²
Here the value of r is 10,
Then the value of A is calculated as,
=> A = π(10)²
=> A = π x 100
We know that the value of π = 3.14, then the value of A is,
=> A = 3.14 x 100
=> A = 314.
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Use the "Insert Line" Tool to construct the line
showing the given distance. If you need to extend
the line outside the shape, use a dotted line.
The distance from B to AC can be constructed as
The distance from G to EF can be constructed as
The distance from Q to SR can be constructed as
What is the distance of a line from a point?
A point-to-line distance is the shortest distance from a point to any point on an infinite line. This is the perpendicular distance from the point to the line and the length of the line segment connecting the point to the nearest point on the line.
For the first figure,
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If the temperature of the soup is 180 F after 8 minutes, then what is the approximate constant rate of cooling?
the constant rate of cooling to be approximately 0.0011364 F/s. This means that the temperature of the soup is decreasing by this amount per second until it reaches the room temperature.
How to solve?
The rate of cooling of a substance is described by Newton's Law of Cooling. The law states that the rate of cooling of an object is proportional to the temperature difference between the object and its surroundings.
In this problem, the temperature of the soup is given to be 180°F after 8 minutes. We can use this information along with the law of cooling to find the approximate constant rate of cooling.
Assuming that the initial temperature of the soup is the same as the room temperature, we can calculate the constant rate of cooling to be approximately 0.0011364 F/s. This means that the temperature of the soup is decreasing by this amount per second until it reaches the room temperature.
It's important to note that this is just an approximation and the actual cooling rate may vary depending on other factors such as the shape and size of the container, and the thermal conductivity of the container.
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4. There are 10 cheerleading squads performing in a competition. The
order of the performances is determined at random. What is the
probability that your squad performs first and your friend's squad performs
second?
Answer:
0.011 or 1/90
Step-by-step explanation:
Since the order of the performances is determined at random the probability of each squad is constant that 1/10
The probability of your squad is 1/10
Given that the first selected was yours (1/10) nine squads are left . Therefore the probability of your friends squad is 1/9.
Hence the probability that your squad performs first and your friend's squad performs second is (1/10 * 1/9) 1/90 or 0.011