Express 10x - x^2 in the form
a - (x + b)^2

Answers

Answer 1

Answer:

\( - (x - 5) {}^{2} + 25\)

Step-by-step explanation:

note:

may want to check if it suits your question or if you phrased the question wrongly

Express 10x - X^2 In The Form A - (x + B)^2

Related Questions

A school needs to buy new notebook and desktop computers for its computer lab. The notebook computers cost $350 each, and the desktop computers cost $375 each. How many total computers would someone buy if they get 10 notebooks and 19 desktop computers? How many total computers would someone buy if they get � n notebooks and � d desktop computers? Total computers, 10 notebooks and 19 desktop computers: Total computers, � n notebooks and � d desktop computers:

Answers

1)  The total number of computers they would buy if they get 10 notebooks and 19 desktop computers is: 54 computers

2) The total number of computers they would buy if they get n notebooks and d desktop computers is: (350/n) + (375/n)

How to solve Algebraic expressions?

The parameters given are:

Cost of notebook Computers = $350

Cost of Desktop desktop = $375

Thus, if they  get 10 notebooks and 19 desktop computers, then:

Total number of computers is:

(350/10) + (375/19) = 35 + 19

= 54 computers

(375/19) was approximated to 19 because we must use a whole number and not a decimal.

If they buy n notebooks and d desktop computers, then total computers will be:

(350/n) + (375/n)

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Tell whether the relation is a function. Explain your reasoning.
{(-1, 7), (9, 4), (3, -2), (5, 3), (9, 1)}

Answers

The relation is not a function. In order for a relation to be a function, the x-inputs of all ordered pairs must not repeat, and if they do, they must have only one output. In this problem, however, (9,4) and (9,1) both have different outputs (y-values). Therefore, there is no function present.

Anybody knows 3x^2+6x-10 + 3x+5

Answers

solution:

3x^2+9x-5

i hope this helps

:)

students in a statistics class are conducting a survey to estimate the mean number of hours each week that students at their college study. the students collect a random sample of 49 students. the mean of the sample is 12.2 hours. the standard deviation is 1.6 hours. what is the 95% confidence interval for the number of hours students in their college study?

Answers

We can say with 95% confidence that the true mean number of hours that students at the college study is between 11.76 and 12.64 hours per week.

What is confidence interval?

Based on a sampling from the population, a confidence interval is a range of values that is likely to include the real population parameter (such as the population mean). The confidence level, which is often stated as a percentage (e.g., 95%), expresses how confident we are in the interval.

The likelihood that a finding arose by accident or as a result of random variation in the data is referred to as statistical significance, on the other hand. In general, if a result is unlikely to have happened by chance, it is deemed statistically significant.

The 95% confidence interval is given as:

CI = X ± Zα/2 (σ/√n)

The critical value for 95% is 1.96.

Substituting the value:

CI = 12.2 ± 1.96 (1.6/√49)

CI = 12.2 ± 0.44

CI = (11.76, 12.64)

Hence, we can say with 95% confidence that the true mean number of hours that students at the college study is between 11.76 and 12.64 hours per week.

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PLEASE HELP!!!!!!!!
There are 76 students in the Breezewood Middle School chorus. The number of girls in the chorus is 13 more than twice the number of boys.

Write an expression that represents the number of girls in the chorus if b represents the number of boys.
Using your expression from Part A, write an equation that could be used to determine the number of girls and boys in the chorus. Hint: the only variable in your equation should be b.
Use your equation to determine the number of boys and girls in the chorus. Show your work.

Answers

Answer:

There are 76 students:

g + b = 76

 

girls is 13 more than twice the boys:

g = 2b + 13

 

replace g with 2b + 13 in 1st equation

 

2b+13+b = 76

3b + 13 = 76

3b = 63

b = 21 boys

 

g = 76-21 = 55 girls

Step-by-step explanation:

Based on recent demand for single family homes in a growing city, it is recommended potential home buyers put 20 percent down when making an offer. A mortgage loan officer would like to test the claim that the average percent down on a single family home purchase is greater than the recommended 20 percent. To test this claim, at the 5% significance level, the mortgage loan officer collects the following data on a sample of 22 recent home purchases and records the percent down. The following is the data from this study: Sample size =22 recent home purchases Sample mean =24 percent down Sample standard deviation =9 percent down Identify the null and alternative hypothesis for this study by filling in the blanks with the correct symbol (=,≠,<, or > to represent the correct hypothesis.)

Answers

This enabled the borrower to obtain 90 percent financing while avoiding the additional cost of pmi. these loans are more commonly referred to as  piggyback mortgage loans.

A loan is the lending of cash via one or more individuals, organizations, or different entities to other individuals, corporations, etc. The recipient incurs a debt and is normally susceptible to pay hobby on that debt till it is repaid as well as to repay the foremost amount borrowed.

A mortgage is a shape of debt incurred by using an character or different entity. The lender—commonly a business enterprise, economic organization, or authorities—advances a amount of money to the borrower. In return, the borrower agrees to a sure set of phrases together with any finance charges, hobby, repayment date, and different situations.

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Rewrite the following equation in slope-intercept form. 2x + 16y = 11 Write your answer using integers, proper fractions, and improper fractions in simplest form.

Answers

Answer:

y=-1/8x+11/16

Step-by-step explanation:

The slope-intercept form is y=mx+b. You have to move over 2x to the other side. After that you have to divide both sides by 16 to get to the y intercept form, so it would end up as y=-1/8x+11/16, where -1/8=m and 11/16=b

A map saying that 4 centimeters represent 10 kilometer what is the real distance that 18 centimeters represents

Answers

Answer:

18cm = 45km

Step-by-step explanation:

Divide 18 by 4 to get 4.5. Multiply 4.5 by 10 to get 45km.

Please help with this
On what interval is the function h(x) = -2|x + 2| + 2 increasing?


(2, ∞)

(-2, ∞)

(-∞, -2)

(-∞, 2)

Answers

Answer:

Step-by-step explanation:

what grade is this ...

this look hard

Find the area of the following trapezoid

Find the area of the following trapezoid

Answers

The formula to calculate the area of a trapezoid is as follow:

4 * (8 + 16) * 1/2

Answer:

trapezoid area :(a+b)/2 ×h

(16+ 8)/2 ×4

=48

Please explain your answer, I need to upload notes.

Please explain your answer, I need to upload notes.

Answers

Answer:

Step-by-step explanation:

well the x is 1/1 and the 2 is over 1 so divided and it is B is what i got

If Y=8 cm, what is the area of the blue section of this shape?

If Y=8 cm, what is the area of the blue section of this shape?

Answers

Explanation

As you can see we have a trapezoid inside a rectangle. The blue section is equivalent to the area of the rectangle that it's not covered by the trapezoid. Then the area of this section is equal to the area of the rectangle less the area of the trapezoid. Then we just need to find the areas of both figures. Remember than the area of a rectangle is given by the product between its height and its base:

\(A_r=h\cdot b\)

Trapezoids are figures with two parallel sides known as bases. The area of a trapezoid is given by product between the sum of its bases and its height divided by 2:

\(A_t=\frac{(a+b)\cdot h}{2}\)

Then the area of the rectangle in the picture is given by:

\(A_r=10\cdot y=10\cdot8=80\)

So it's 80 cm².

The area of the trapezoid considering that its base has the same length as the rectangle is:

\(A_t=\frac{(4+10)\cdot3}{2}=\frac{14\cdot3}{2}=21\)

So its area is of 21 cm².

Finally the area of the blue section is given by:

\(80-21=59\)Answer

Then the answer is 59cm².

What is the answer to this problem -13c+8-18c+5 ?

Answers

Answer:

-31 c + 13

Step-by-step explanation:

-13c+8-18c+5

combine like terms

-18c and -13c combined is -31c

8 + 5 = 13

-31 c + 13

Answer

-31c+13 is your answer (see explanation below!)

Step-by-step explanation:

1) Add the numbers:

\(-13c + 8 - 18c + 5\\-13c + 13 -18c\\\)

2) Combine like terms:

\(-13c+13-18c\\-31c+13\\\)

\(A: -31c+13\)

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find the taylor polynomial t1(x) for the function f(x)=ln(1+x) based at b=0.

Answers

The Taylor polynomial t1(x) for the function f(x) = ln(1+x) based at b = 0 is given by t1(x) = x.

The Taylor polynomial represents an approximation of a function around a specific point using a polynomial. The first-order Taylor polynomial, also known as the linear approximation, involves considering only the first derivative of the function. In this case, the function is ln(1+x), and the approximation is centered at b = 0.

To find the first-order Taylor polynomial, we start by evaluating the function and its derivative at the point of interest. The function ln(1+x) evaluated at x = 0 is ln(1+0) = ln(1) = 0. The first derivative of ln(1+x) is 1/(1+x), and evaluating it at x = 0 gives 1/(1+0) = 1.

Thus, the first-order Taylor polynomial t1(x) = x is obtained by taking the linear term of the Taylor series expansion. It provides a good approximation of the function ln(1+x) in the neighborhood of x = 0.

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If you had money in a savings account earning 9% interest per year, how much would you make in interest on a deposit of $60.00 over two years?

Answers

The amount of interest earned on a deposit of $60.00 at a rate of 9% per annum for 2 years is $108.

As per the given problem:

Amount deposited = $60.00

Interest rate per year = 9%

The formula for calculating the interest is given by:

Interest = (Principal × Rate × Time)/100

Where Principal is the initial amount invested or deposited

Rate is the percentage of interest that you earn per annum

Time is the duration for which you want to calculate the interest

Putting the values in the above formula, we get:

Interest = (60 × 9 × 2)/100= (108 × 1)/1= $108

So, the amount of interest earned on a deposit of $60.00 at a rate of 9% per annum for 2 years is $108.

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what is the correct path to get to the end

Answers

The picture isn’t showing up…

Find the second Taylor polynomial P2(x) for the function f (x) = ex cos x about x0 = 0.
a. Use P2(0.5) to approximate f (0.5). Find an upper bound for error |f (0.5) − P2(0.5)| using the error formula, and compare it to the actual error.
b. Find a bound for the error |f (x) − P2(x)| in using P2(x) to approximate f (x) on the interval [0, 1].
c. Approximate d. Find an upper bound for the error in (c) using and compare the bound to the actual error.

Answers

a) An upper bound for error |f (0.5) − P2(0.5)| using the error formula is 0.0208

b) On the interval [0, 1], we have |R2(x)| <= (e/6) √10 x³

c) The maximum value of |f(x) - P2(x)| on the interval [0, 1] occurs at x = π/2, and is approximately 0.1586.

a. As per the given polynomial, to approximate f(0.5) using P2(x), we simply plug in x = 0.5 into P2(x):

P2(0.5) = 1 + 0.5 - (1/2)(0.5)^2 = 1.375

To find an upper bound for the error |f(0.5) - P2(0.5)|, we can use the error formula:

|f(0.5) - P2(0.5)| <= M|x-0|³ / 3!

where M is an upper bound for the third derivative of f(x) on the interval [0, 0.5].

Taking the third derivative of f(x), we get:

f'''(x) = ex (-3cos x + sin x)

To find an upper bound for f'''(x) on [0, 0.5], we can take its absolute value and plug in x = 0.5:

|f'''(0.5)| = e⁰°⁵(3/4) < 4

Therefore, we have:

|f(0.5) - P2(0.5)| <= (4/6)(0.5)³ = 0.0208

b. For n = 2, we have:

R2(x) = (1/3!)[f'''(c)]x³

To find an upper bound for |R2(x)| on the interval [0, 1], we need to find an upper bound for |f'''(c)|.

Taking the absolute value of the third derivative of f(x), we get:

|f'''(x)| = eˣ |3cos x - sin x|

Since the maximum value of |3cos x - sin x| is √10, which occurs at x = π/4, we have:

|f'''(x)| <= eˣ √10

Therefore, on the interval [0, 1], we have:

|R2(x)| <= (e/6) √10 x³

c. To approximate the maximum value of |f(x) - P2(x)| on the interval [0, 1], we need to find the maximum value of the function R2(x) on this interval.

To do this, we can take the derivative of R2(x) and set it equal to zero:

R2'(x) = 2eˣ (cos x - 2sin x) x² = 0

Solving for x, we get x = 0, π/6, or π/2.

We can now evaluate R2(x) at these critical points and at the endpoints of the interval:

R2(0) = 0

R2(π/6) = (e/6) √10 (π/6)³ ≈ 0.0107

R2(π/2) = (e/48) √10 π³ ≈ 0.1586

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very fast
Show, by induction, that \( T(n)=10 n^{2}-3 n \quad \) if \( n=1 \)

Answers

Given that \(\(T(n)\) = \(10n^2-3n\)\) if (\(\(n=1\)\)), you have to prove it by induction. So, we have proved it by induction that  \($$\(T(n)=10n^2-3n\)$$\)  if ( n= 1). The given statement is true for all positive integers n

Let's do it below: The base case (n=1) is given as follows: \(T(1)\) =\(10\cdot 1^2-3\cdot 1\\&\)=\(7\end{aligned}$$\). This implies that \(\(T(1)\)\) holds true for the base case.

Now, let's assume that \(\(T(k)=10k^2-3k\)\) holds true for some arbitrary \(\(k\geq 1\).\)

Thus, for n=k+1, T(k+1) = \(10(k+1)^2-3(k+1)\\&\) = \(10(k^2+2k+1)-3k-3\\&\)=\(10k^2+20k+7k+7\\&\) = \(10k^2-3k+20k+7k+7\\&\) = \(T(k)+23k+7\\&\) = \((10k^2-3k)+23k+7\\&\) =  \(10(k+1)^2-3(k+1)\).

Therefore, we have proved that the statement holds true for n=k+1 as well. Hence, we have proved it by induction that  \($$\(T(n)=10n^2-3n\)$$\)  if (n=1). Therefore, the given statement is true for all positive integers n.

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A city has a population of 1.5 million people. If the monthly incomes of these inhabitants follow a normal distribution with a mean of £2,075 and a standard deviation of £162, how many people from this city will have a monthly income between £2,000 and £2,300?
a. Between 260,000 and 270,000 people
b. Between 620,000 and 630,000 people
c. None of the above
d. Exactly half of the population
e. Between 890,000 and 900,000 people

Answers

The correct answer is (e) Between 890,000 and 900,000 people.

To find out how many people from this city will have a monthly income between £2,000 and £2,300, we need to use the z-score formula:

z = (x - μ) / σ

where x is the value we are interested in, μ is the mean, and σ is the standard deviation.

First, we'll find the z-score for £2,000:

z = (2000 - 2075) / 162 = -0.46

Next, we'll find the z-score for £2,300:

z = (2300 - 2075) / 162 = 1.39

Using a z-table, we can find the corresponding probabilities for these z-scores. The probability for a z-score of -0.46 is 0.3228, and the probability for a z-score of 1.39 is 0.9177.

To find the probability of having a monthly income between £2,000 and £2,300, we need to subtract the smaller probability from the larger probability:

0.9177 - 0.3228 = 0.5949

This means that approximately 59.49% of the population will have a monthly income between £2,000 and £2,300. To find out how many people this represents, we'll multiply the probability by the total population:

0.5949 * 1,500,000 = 892,350

Therefore, the answer is (e) Between 890,000 and 900,000 people.

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Help asap!!!!!!Order the number below from least to greatest

Help asap!!!!!!Order the number below from least to greatest

Answers

Answer:

B.

Step-by-step explanation:

Answer:

B.) -9/7, -1, 1/4, √7, 4.8

Step-by-step explanation:

Turn all the values into decimals first to make things easier:

1/4 = 0.25

-1 = -1

√7 = 2.7

4.8 = 4.8

-9/7 = -1.3

So, from least to greatest on a number line it'd be:

-1.3, -1, 0.25, 2.7, 4.8 or -9/7, -1, 1/4, √7, 4.8

(Sorry if it doesn’t show up, I’m having tech issues :/)
Question above.

(Sorry if it doesnt show up, Im having tech issues :/)Question above.

Answers

Answer:

m<PQT = 56

Step-by-step explanation:

Angles PQS and SQT are shown to be congruent in the figure, so their measures are equal.

m<PQS = m<SQT

3x + 13 = 6x - 2

Subtract 6x from both sides.

-3x + 13 = -2

Subtract 13 from both sides.

-3x = -15

Divide both sides by -3.

x = 5

m<PQT = m<PQS + m<SQT

m<PQT = 3x + 13 + 6x - 2

m<PQT = 3(5) + 13 + 6(5) - 2

m<PQT = 15 + 13 + 30 - 2

m<PQT = 28 + 28

m<PQT = 56

Micheal has 10$ in his account. Option one adds 100 dollars to his account each week. Option 2 will double the amount in his account at the end of each week

Answers

If Michael selects option one, his account balance after 4 weeks will be $410, and if he selects option two, his account balance after four weeks will be $160.

Micheal has two options to increase his account balance. The first option is to add $100 to his account each week, while the second option is to double the amount in his account at the end of each week. We need to find Michael's account balance after 4 weeks if he follows either of these two options.

Option 1: If Micheal selects option one, he will add $100 to his account each week, and after 4 weeks, his account balance will be:

10 + (100 * 4) = $410

Option 2: If Micheal selects option two, the amount in his account will double after each week. Therefore, his account balance will be:

Week 1: $10 * 2 = $20

Week 2: $20 * 2 = $40

Week 3: $40 * 2 = $80

Week 4: $80 * 2 = $160

Michael's account balance after four weeks will be $160 if he follows option 2.

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Note: The complete question is - If Micheal has $10 in his account and has the option to add $100 to his account each week or to double the amount in his account at the end of each week, what would be his account balance after 4 weeks?

write the approximate change formula for a function z=f(x,y) at the point (a,b) in terms of differentials.

Answers

The approximate change formula for a function z=f(x, y) at the point (a, b) in terms of differentials is given by Δz ≈ ∂z/∂x |(a, b) dx + ∂z/∂y |(a, b) dy

Function is equal to,

z=f(x, y)

In terms of differential the approximate change formula at (a, b) is,

Δz ≈ ∂z/∂x |(a, b) dx + ∂z/∂y |(a ,b) dy

where,

Δz is the approximate change in z

∂z/∂x is the partial derivative of z with respect to x

∂z/∂y is the partial derivative of z with respect to y

dx is the small change in x

dy is the small change in y

The vertical bars indicate that the partial derivatives are evaluated at the point (a, b).

This formula represents the total differential of z at the point (a, b).

Which is the linear approximation of the change in z due to small changes in x and y.

It is based on the assumption,

That the change in z is approximately proportional to the changes in x and y and is valid for small changes in x and y.

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Proportions . Please click on image

Proportions . Please click on image

Answers

Answer:

3/1.5=h/5

Step-by-step explanation:

3/1.5=h/5. Solving for the height, you get that h is 5*2=10 m long.

A flower that can be split vertically through its axis into two equal halves but has unequal halves if split in any other way is said to

Answers

A flower that can be split vertically through its axis into two equal halves but has unequal halves if split in any other way is said to be bilaterally symmetrical.


1. Bilateral symmetry is a characteristic of many organisms, including flowers.
2. It means that the organism can be divided into two equal halves along a vertical axis.
3. However, if the organism is divided in any other direction, the resulting halves will be unequal.

Therefore, a flower that can be split vertically through its axis into two equal halves but has unequal halves if split in any other way is said to be bilaterally symmetrical. This means that its symmetry is only evident when divided vertically.

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A regular hexagon has an apothem of 14.7 inches and a perimeter of 101.8 inches. what is the area of the hexagon? square inches

Answers

Answer:

748.23 in^2.

Step-by-step explanation:

Area = 1/2 * apothem * perimeter

        = 1/2 * 14.7 * 101.8

        =  748.23 in^2.

Answer:

748.23

Step-by-step explanation:

A regular hexagon has an apothem of 14.7 inches and a perimeter of 101.8 inches. what is the area of

3. How could you adapt the rule for division by 3 to decide easily when
a number is divisible by 9?

Answers

A divisibility rule is a simple method for determining whether or not an integer is divisible by a fixed divisor without having to divide it by looking at its digits.

The three-digit divisibility rule asserts that if the sum of a whole number's digits is a multiple of three, the original number is also divisible by three.

The total of all the digits in 1377 is 1+3+7+7 = 18. Because 18 is divisible by three, 1377 is likewise divisible by three. The quotient is 1377 3 = 459, and the remainder is 0.

The divisibility rule of 9 asserts that if a number's sum of digits is divisible by 9, the number is divisible by 9 as well.

The three-digit divisibility rule and the nine-digit divisibility rule are quite similar. As previously stated, the divisibility rule for the divisibility test of 3 asserts that if a number's sum of all digits is divisible by 3, the number is also divisible by 3. The divisibility rule of 9 is similar to the divisibility rule of 3, in that a number is said to be divisible by 9 if the sum of all of its digits is divisible by 9.

Take 52884 for example. 52884 is divisible by three since the total of all digits is 5+2+8+8+4 = 27. The quotient is 52884 ÷ 3 = 17628, and the remainder is 0. It's worth noting that the sum of the digits is 27 is 2 + 7 = 9, which is likewise divisible by three.

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A die is weighted so that the odd numbers are 3 times as likely to come up as the even numbers. All the even numbers are equally likely, and all the odd numbers are equally likely. What probabilities w1, W2, W3, W4, W5, W6 should be assigned to the outcomes 1, 2, 3, 4, 5, 6, respectively?

Answers

The probabilities that should be assigned to the outcomes 1, 2, 3, 4, 5, and 6 are -1/12, 1/3, 1/6, 1/8, 5/8, and 1/8, respectively.

Let W1, W2, W3, W4, W5 and W6 be the probabilities that each of the outcomes 1, 2, 3, 4, 5, and 6 is assigned, respectively.

A die is weighted so that odd numbers are 3 times as likely to come up as even numbers. Hence, we can express the probabilities of each of the odd outcomes as 3x and each of the even outcomes as x.

Since the die has 6 faces and is unbiased, we know that the sum of the probabilities of all possible outcomes should be equal to 1.

Thus, we have:

W1 + W2 + W3 + W4 + W5 + W6 = 1

The probability that the odd numbers will come up is equal to the sum of the probabilities of outcomes 1, 3, and 5.

Since all odd outcomes are equally likely, we can set this probability equal to 3 times the probability of any individual odd outcome.

Thus, we have:

W1 + W3 + W5 = 3(W3)

Similarly, the probability that the even numbers will come up is equal to the sum of the probabilities of outcomes 2, 4, and 6.

Since all even outcomes are equally likely, we can set this probability equal to 2 times the probability of any individual even outcome.

Thus, we have:W2 + W4 + W6 = 2(W2)Adding the two equations, we get:W1 + W2 + W3 + W4 + W5 + W6 = 3(W3) + 2(W2)

Since the sum of the probabilities of all outcomes is equal to 1, we know that:W1 + W2 + W3 + W4 + W5 + W6 = 1

Substituting this into the previous equation, we get:

1 = 3(W3) + 2(W2)Solving for W2, we get:

W2 = (1 - 3(W3))/2

Substituting this into the equation for the probability of even outcomes, we get:

W4 + W6 = W2

Thus, we have:

W4 + W6 = (1 - 3(W3))/2

Since all even outcomes are equally likely, we know that:

W4 = W6

Thus, we have:

2W4 = (1 - 3(W3))/2

Solving for W4, we get:

W4 = (1 - 3(W3))/4

Substituting this back into the equation for W2, we get:

W2 = (1 + 3(W3))/4

Now, we can use the equation for the probability of odd outcomes to solve for W3:

W1 + W3 + W5 = 3(W3)

Substituting the expressions for W2 and W4 into this equation, we get:

W1 + (1 - 3(W3))/4 + 3(W3) = 9(W3)/4 + (1 - 3(W3))/4 + 3(W3)

Simplifying, we get:W1 + (1 - 3(W3))/4 = 1

Thus, we have:W1 = (3(W3) - 1)/4

Now we can express all the probabilities in terms of W3:

W1 = (3(W3) - 1)/4W2 = (1 + 3(W3))/4W3 = W3W4 = (1 - 3(W3))/4W5 = (3 - 3(W3))/4W6 = (1 - 3(W3))/4

We know that the sum of the probabilities of all outcomes should be equal to 1, so we can use this fact to solve for W3:

W1 + W2 + W3 + W4 + W5 + W6 = (3(W3) - 1)/4 + (1 + 3(W3))/4 + W3 + (1 - 3(W3))/4 + (3 - 3(W3))/4 + (1 - 3(W3))/4= 1

Multiplying through by 4, we get:

3(W3) - 1 + 1 + 3(W3) + 4(W3) - 3 + 1 - 3(W3) + 1 - 3(W3) = 4

Simplifying, we get:

6W3 = 2W3 = 1/3

Thus, we have:

W1 = (3(W3) - 1)/4 = (1/3 - 1)/4 = -1/12W2 = (1 + 3(W3))/4 = (1 + 1)/12 = 1/3W3 = W3 = 1/6W4 = (1 - 3(W3))/4 = (1 - 1/2)/4 = 1/8W5 = (3 - 3(W3))/4 = (3 - 1/2)/4 = 5/8W6 = (1 - 3(W3))/4 = (1 - 1/2)/4 = 1/8

Therefore, the probabilities that should be assigned to the outcomes 1, 2, 3, 4, 5, and 6 are -1/12, 1/3, 1/6, 1/8, 5/8, and 1/8, respectively.

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Find the a=0.01 critical value for the chi-square statistic with 13 degrees of freedom. A) 27.688 B) 4.107 C) 26.217 D) 29.819

Answers

The a = 0.01 critical value for the chi - square statistic with 13 degrees of freedom is given by 27.688.

Hence the correct option is (A).

Here given distribution is Chi - squared distribution.

two parameters of chi - squared distribution are given by ' a ' and ' d ' where d is degree of freedom.

The critical value against chi squared distribution changes according to the change of the values of a and d.

The table chi squared distribution is given by,

Here we have to find the critical value for the chi - squared statistic with 13 degrees of freedom when a = 0.01.

Therefore, a = 0.01 and d = 13

From the given table we can see that when a = 0.01 and d = 13 the critical value is given by 27.688.

Hence the correct option is (A).

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Find the a=0.01 critical value for the chi-square statistic with 13 degrees of freedom. A) 27.688 B)

Vectors u, v, and w are shown in the graph. What are the magnitude and direction of u + v + w?

Vectors u, v, and w are shown in the graph. What are the magnitude and direction of u + v + w?

Answers

Magnitude and direction of u + v + w is equals to 57.871 and 19°.

What is vectors?

"Vectors are those quantity of which represents both direction as well magnitude."

According to the question,

As shown in diagram we have,

u + v + w

   = (wcos30°)\(\^{i}\) + (wsin30°)\(\^{j}\) +(vcos20°)\(\^{j}\) - (vsin40°)\(\^{i}\) -(ucos40°)\(\^{i}\) -(usin40°)\(\^{j}\)

  = ( wcos30° - vsin40° - ucos40°)\(\^{i}\) + (wsin30°+ vcos20° - usin40°)\(\^{j}\)

   

Substitute the value of ║w║ = 40 ,║v║=60,and ║u║= 90 we get,

u + v +w

= (  40cos30° - 60sin40° - 90cos40°)\(\^{i}\) + (40sin30°+ 60cos20° - 90sin40°)\(\^{j}\)

= (20√3 - 20.5212 - 68.9440)\(\^{i}\) + ( 20 +56.3816 - 57.8509)\(\^{j}\)

= ( -54.8242)\(\^{i}\) + (18.5307)\(\^{j}\)

Therefore,

Magnitude = √(-54.8242)² +(18.5307)²

                  =√3349.0798

                  = 57.8712

   tanθ = ( 0.3380)

⇒θ = tan⁻¹ (0.3380)

     = 18.67

    ≈ 19°

Hence, magnitude and direction of u + v + w is equals to 57.871 and 19°.

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Vectors u, v, and w are shown in the graph. What are the magnitude and direction of u + v + w?
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