Explain why a nonconservative force does not conserve energy.

By using the concept of work and energy, the below are the answers

1. 100J

2. 100J

3. 0

4. Total energy = K.E + P.E

5. 1.02 kg

6. 14 m/s

Given that 100 J of work was done to lift a 10-N rock and set it at Position A near the edge of a cliff.

1. If the 100 Joules of work lifted the rock to the top of the cliff, how much potential energy did the rock gain?

Work is the product of force and the distance.

The potential energy gained by the rock will be equal to work done in lifting  up the rock which is 100 J

2. At point C, the rock's potential energy will be equal to the work done.

That is, at point C, P.E = 100J

3. The rock's kinetic energy at point A is Zero.

That is, at point A, K.E = 0

4. At point B, some of the rock's potential energy will be changed to Kinetic energy. Yes. Because the Total energy = K.E + P.E

5. What is the mass of the rock?

Weight W = mg

where g = 9.8m/s^2

W = 10N

Substitute both into the formula

10 = 9.8m

make m the subject of the formula

m = 10/9.8

m = 1.02 kg

6. What is the rock's velocity just before it hits the ground

Work done = Energy

That is, Work done = maximum P.E = maximum K.E

100 = 1/2m\(v^{2}\)

Substitute mass into the formula

200 = 1.02\(V^{2}\)

V = \(\sqrt{196}\)

V = 14 m/s

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A cylinder with a moving piston does 290 J of work on the surroundings while expanding against an external pressure of 1.20 atm. The final volume of the cylinder is 108 mL.

In this problem, a cylinder with a piston expands against external pressure and does work on the surroundings. The work done by the system is given as 290 J, and the initial volume of the cylinder is 0.350 L, with an external pressure of 1.20 atm. We need to determine the final volume of the cylinder.

To solve this problem, we can use the equation:

\(W = -Pext \Delta V\)

where W is the work done by the system, Pext is the external pressure, and ΔV is the change in volume.

Solving for ΔV, we get:

\(\Delta V = -W/Pext\)

Substituting the given values, we get:

\(\Delta V = -(290 J)/(1.20 atm)\)

\(\Delta V = -241.67 mL\)

Since the volume increases, the final volume can be found by adding the change in volume to the initial volume:

\(Vf = Vi + \Delta V\)

Vf = 0.350 L + (-241.67 mL)

Vf = 0.108 L or 108 mL

Therefore, the final volume of the cylinder is 0.108 L or 108 mL.

In summary, a cylinder with a moving piston expands against an external pressure of 1.20 atm, doing 290 J of work on the surroundings. We can use the equation \(W = -Pext \Delta V\) to determine the change in volume, and then add it to the initial volume to find the final volume. The final volume of the cylinder is 0.108 L or 108 mL.

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The energy released by the system is 686 kJ and the energy used is 100 kJ, so the change in internal energy of the system is 586 kJ.

The change in internal energy of the system is equal to the difference between the energy released and the energy used.

Internal energy is the sum of all potential and kinetic energies of the molecules in a system. Potential energy is the energy stored in the system due to the positions and interactions of its particles, while kinetic energy is the energy associated with the motion of the particles.

When energy is released, the internal energy of the system increases, and when energy is used, the internal energy of the system decreases. In this case, energy was released and used, but the release was greater than the use, so the change in internal energy was an increase of 586 kJ.

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A star is 230 light years away. the light we see tonight from that star left it

Instead of time, a light-year counts distance (as the name might imply). One light-year, or roughly 6 trillion miles, is the distance a light beam travels in one year on Earth (9.7 trillion kilometers).

Since light takes around 230 years to travel the distance from the star to us, the light we see tonight departed that star 230 years ago.

Because of this, astronomers frequently discuss the "lookback time" when seeing far-off celestial objects. The older the light we witness from an object, the further away it is, and the further back in time we can see.

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Answer:

i think its b

Explanation:

its been awhile since I've worked on Newton's first law

Answer:

Acceleration, \(a=4\ m/s^2\)

Explanation:

Given that,

Initial velocity, u = 20 m/s

Final velocity, v = 60 m/s

Time, t = 10 s

We need to find the acceleration of the car. It is equal to the change in velocity divided by time.

\(a=\dfrac{v-u}{t}\\\\a=\dfrac{60-20}{10}\\\\a=\dfrac{40}{10}\\\\a=4\ m/s^2\)

So, the acceleration of the car is \(4\ m/s^2\).

Answer:

it is the dependent since it keeps changing over time get it :)

Explanation:

Answer:

A.) 4 revolution

B.) 0.2 revolution

C.) 4 seconds

D.) 2.75 m/s

Explanation:

Given that a merry-go-round a.k.a "the spinny thing" is rotating at 15 RPM, and has a radius of 1.75 m

Solution

1 revolution = 2πr

Where r = 1.75m

A. How many revolutions will it make in 3 minutes?

(2π × 1.75) / 3

10.9955 / 3

3.665 RPM

Number of revolution = 15 / 3.665

Number of revolution = 4 revolution

B. How many revolutions will it make in 10.0 seconds?

First convert 10 seconds to minutes

10/60 = 0.167 minute

(2π × 1.75) / 0.167

10.9955 / 0.167

65.973

Number of revolution = 15 / 65.973

Number of revolution = 0.2 revolution

C. How long does it take for a person to make 1 complete revolution?

15 = 1 / t

Make t the subject of formula

t = 1/15

t = 0.0667 minute

t = 4 seconds

D. What is the velocity in m/s of person standing on its edge?

Velocity in m/ s will be:

Velocity = (15 × 2pi × r) / 60

Velocity = 164.9334 / 60

Velocity = 2.75 m/s

Answer:

Explanation:

Given:

ΔV = 300 km/h = 300 000 m / 3 600 s ≈ 83.3 m/s

Δt = 20 s

_____________

a - ?

The acceleration:

a = ΔV / Δt = 83.3 / 20 ≈ 4.2 m/s

Answer:

C

Explanation:

C should be the right answer

Answer:

1)substance A will require 910 J of heat to increase the temperature by 10°C.

2) Substance B

3) Substance A

Explanation:

1) The meaning of the statement: "specific heat capacity of A is 910 J/kg °C" is that 1 kg of substance A will require 910 J of heat to increase the temperature by 10°C.

2) While heating equal mass of all the three substances supplied with equal amount of heat, Substance B will gain more temperature due to the fact that substances of lesser specific heat capacity always tend to gain or loose heat within a short period of time.

3) While keeping equal mass at the three substances heated for the same temperature of 100°C and kept on a wax slab, substance A will go down more in depth due to the fact that heat is preserved for a longer period of time for substances that have higher specific heat capacity.

The actual volume of the cone is 160/3 cm3, and it increases from the center of the base to the tip. The form of a cone with a dotted line.

The amount of quantity that is gained by the solid or object when it is located in three-dimensional space is referred to as the volume of the solid.

The volume of the cone may be calculated using the formula below, which is as follows:

\(V=\frac{\pi r^2 h}{3}\)

The radius of the cone's base is denoted by the symbol (r), while the height of the cone is denoted by the symbol (h).

The picture of the cone, the volume of which has to be determined, is attached further down.

The height of the cone is 10 centimeters, while the radius measures 4 centimeters. Thus, enter these numbers into the formula shown above as,

\(& V=\frac{\pi(4)^2(10)}{3} \\& V=\frac{160}{3} \pi \mathrm{cm}^3\)

As this is the case, the precise volume of the cone in which the outline of a cone with a dotted line rises from the center of the base to the tip is 160/3 cm3.

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1. Various methods of starting a polyphase induction motorThe polyphase induction motors are generally started in any of the following ways:Direct-on-line startingStar-delta startingRotor resistance starting Autotransformer startingSoft-startingDirect-on-line starting

The most simple and economical method of starting a three-phase induction motor is DOL starting. This method is also known as full-voltage starting. In this method, the full voltage of the power supply is applied to the motor terminals. Therefore, the starting current is very large, typically 6 to 8 times the rated current. It is only used for small motors.Star-Delta StartingIn this method, the motor is started by applying the reduced voltage to the stator winding.

However, the rotor's magnetic field is alternating and pulsating in nature. The interaction of these two fields results in the production of torque. The alternating flux induces the current in the rotor. This induced current produces an alternating flux in the rotor that interacts with the stator flux and develops torque. The torque developed is proportional to the product of stator flux and rotor flux.

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Yes, it is true that all of the paranasal sinuses are located either above, in between, or below the optic orbits and in the same frontal plane as the optic orbits.

The paranasal sinuses are air-filled cavities located in the skull, around the nasal cavity. They are located in the bones surrounding the nasal cavity, including the frontal, ethmoid, sphenoid, and maxillary sinuses. All of these sinuses are located either above, in between, or below the optic orbits and in the same frontal plane as the optic orbits.

The functions of the paranasal sinuses include temperature resistance, mucus to clean the nasal cavity, help sound resonance, reduce air pressure changes, help balance the head, and regulate air conditioning.

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After the collision, Q moves off with a speed of 2m/s in the original direction of P, therefore the initial velocity of P is 3 m/s.

The initial velocity is the velocity of an object at the beginning of its motion.

The initial velocity of ball P can be calculated using the conservation of momentum. Momentum is a vector quantity that is equal to the mass of an object multiplied by its velocity. It is conserved in collisions, meaning that the total momentum of all objects before the collision is equal to the total momentum of all objects after the collision.

The momentum of P before the collision is equal to the mass of P multiplied by its velocity (0.25 kg x vP). The momentum of Q before the collision is equal to the mass of Q multiplied by its velocity (0.25 kg x 0 m/s). The total momentum before the collision is therefore equal to 0.25 kg x vP.

After the collision, the momentum of P is equal to the mass of P multiplied by its velocity after the collision (0.25 kg x vP/3). The momentum of Q after the collision is equal to the mass of Q multiplied by its velocity after the collision (0.25 kg x 2 m/s). The total momentum after the collision is therefore equal to 0.50 kg x 2 m/s.

By equating the total momentum before and after the collision, we can calculate the initial velocity of P.

0.25 kg x vP = 0.50 kg x 2 m/s

vP = 8 m/s

Therefore, the initial velocity of ball P is 8 m/s./s

vP = 8 m/s

Therefore, the initial velocity of ball P is 8 m/s.

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Answer:

A. Constructive

B. Destructive

C. Destructive

D. Constructive

Explanation:

Constructive interference takes place at locations along the path of two superposed waves where the waves are in phase such that a high or low point of one of the waves corresponds with a high or low point of the other wave which gives a resulting wave amplitude which is the sum of the amplitudes of the individual waves

Destructive interference takes place at locations along the path of two superposed waves where one wave is out of phase with the other wave such that a high or low point of one of the waves coincides with a low or high point of the other wave respectively thereby cancelling the effect of the other wave and giving a resulting wave that has an amplitude which is the difference in the amplitudes of the individual waves

Therefore;

At point A, the peak of each wave partially coincides resulting in constructive interference

At point B, the peak of the blue wave and the trough of the red wave partially coincides resulting in destructive interference

At point C, the through of the blue wave and the peak of the back wave partially coincides resulting in destructive interference

At point D, the trough of each wave partially coincides resulting in constructive interference.

The assignment most likely to carry a works cited page is a research paper or an essay that requires the use of external sources.

A works cited page is essential in such assignments because it provides a list of the sources that have been referenced throughout the paper, acknowledging the original authors and their work. This practice is crucial in maintaining academic integrity and avoiding plagiarism. The works cited page should follow a specific citation style, such as APA, MLA, or Chicago, depending on the assignment guidelines provided by the instructor or institution.

In a research paper or essay, a works cited page helps readers verify the accuracy and credibility of the information presented, as well as locate the original sources for further study or understanding. Overall, a works cited page is an essential component of any assignment that relies on external sources to support arguments, ideas, or research findings.

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The part of the microscope that the objectives are attached to is called the (C) nosepiece.

The nosepiece is a rotating mechanism located below the microscope's body tube. It holds the objectives, which are the lenses responsible for magnifying the specimen. The nosepiece typically has multiple positions, allowing the user to switch between different objective lenses for varying levels of magnification.

This convenient feature eliminates the need to manually remove and replace objectives when changing magnification. By rotating the nosepiece, different objectives can be brought into position above the specimen. This allows for quick and efficient adjustments in magnification without disrupting the viewing process.

Hence, the nosepiece plays a critical role in the microscope's functionality by providing a convenient way to switch between objectives and adjust the magnification level.

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Here is the complete question:

What is the name of the part of the microscope that the objectives are attached to? (Choose the best answer)

A. Ocular

B. Stage

C. Nosepiece

D. Arm

The particle moves to the right through a potential difference of Vb-Va = 3.20×10^-19 J / q.

The particle, initially at rest, is acted upon only by the electric force and moves from point a to point b along the x axis, increasing its kinetic energy by 3.20×10^-19 J. To determine the direction and potential difference through which the particle moves, we can use the relationship between electric potential difference (V) and electric force (F) on a charged particle.

The electric potential difference between two points is defined as the work done per unit charge to move a particle from one point to the other. The work done on a charged particle by an electric force is given by the equation

W = Fdcos(theta)

where F is the electric force, d is the distance moved by the particle, and theta is the angle between the direction of the force and the direction of the displacement.

In this case, since the particle is only acted upon by the electric force and moves along the x-axis, the angle between the direction of the force and the direction of the displacement is 0, and the work done by the electric force is given by W = Fdx.

Therefore, the potential difference between point a and point b is given by Vb - Va = W/q, where q is the charge of the particle.

Given that the particle's kinetic energy increases by 3.20×10^-19 J and the work-energy principle states that work done on a particle is equal to the change in kinetic energy, we can say that the work done on the particle is equal to 3.20×10^-19 J.

Now, the direction of the force can be determined by the sign of the potential difference, since the electric force is given by

F = -q(dV/dx).

Given that the potential difference is positive, the electric force is negative, meaning that the force is directed opposite to the direction of motion of the particle, therefore the direction of motion is to the right.

Therefore, the particle moves to the right through a potential difference of Vb-Va = 3.20×10^-19 J / q.

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F = 1520N

explanation:

by newton third law of motion every action has equal and opposite reaction so truck exert on it so F = 1520N

that's my answer

Answer:

The work done by the engine is 50 J.

Explanation:

Given;

amount of heat energy added to the heat engine, Q = 75 J

energy lost in the process, E = 50 J

let the work done by the engine (system) = W

Apply the first law of thermodynamic;

ΔU = Q - W

where;

ΔU is change in internal energy = 75 J - 50 J = 25 J

25 = 75 - W

25 - 75 = - W

-50 J = - W

W = 50 J

Therefore, the work done by the engine is 50 J.

Explain more. I can't understand

The ladder is not long enough to reach the cat. The cat would not be rescued with the ladder available.

The term "displacement" refers to a shift in an object's position. It is a vector quantity with a magnitude and direction. An arrow pointing from the starting point to the finishing point serves as its symbol.

When an atom or group of atoms in a molecule are replaced by another atom, this is referred to as a displacement reaction. For instance, copper metal is displaced when iron is added to a solution of copper sulphate.

To determine if the cat can be rescued using the 95-foot ladder, we need to calculate the reach of the ladder, which is the distance from the base of the ladder to the highest point it can reach.

The ladder starts 8 feet above ground, so the reach of the ladder is 95 feet (the length of the ladder) + 8 feet (the distance above ground) = 103 feet.

Now, we need to calculate the horizontal distance between the base of the ladder and the tree. This distance is the sum of the distance between the fire truck and the tree (75 feet) and the distance between the base of the ladder and the fire truck (8 feet).

So, the horizontal distance between the base of the ladder and the tree is 75 feet + 8 feet = 83 feet.

Now we have to check the reach of the ladder is greater than the horizontal distance between the base of the ladder and the cat and the height of the cat.

103 feet (reach of ladder) > 83 feet (horizontal distance) + 60 feet (height of cat)

103 > 143

which is not true.

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Option Z is correct. The stainless steel container was likely the hottest. Stainless steel is an excellent heat conductor because it quickly warms the substance.

Stainless steel is an excellent heat conductor because it quickly warms the substance or allows heat to travel through it. Stainless steel is also corrosion-resistant.

Foam, glass, and plastic, on the other hand, are all poor heat and electrical conductors. As a result, they do not allow heat to travel through.

As a result, we may deduce that, among the available possibilities, the stainless steel container was most likely the hottest.

Hence Option Z is correct. The stainless steel container was likely the hottest.

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As the units for acceleration are metres per second squared, we must first convert the distance from feet to metres. We know that 3.28084 feet are equal to 1 metre, so we can calculate: 212.0 feet (1 m / 3.28084 ft) = 64.6218 m.Hence, the car's total distance travelled was 64.6218 metres.

How quickly does a car travelling along a straight road accelerate to reach 100 km/h in 10 seconds? 6 m/s.

The acceleration a (in ms 2) of a body, starting from rest varies with time t (ins) following the equation a= 3t+4.

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Answer:

Continental polar Cp

Explanation:

the primary function of a wave is to carry energy

Answer:

Can you explain this better?

Explanation:

Answer:Along line 1, the motion is steady. Along line 2, the motion speeds up. Along line 3, the motion slows down.

Explanation: Answer straight from plato Hope it helped!