explain what type of encryption aes is, and what is the main difference between aes and rsa encryption algorithm

Answer:

\(W_{net} = - 1223 kJ\)

Explanation:

State 1:

\(P_1 = 20 bar\\T_1 = 360^{0}C\\ h_1 = 3159.3 kJ/kg\\S_1 = 6.9917 kJ/kg\)

State 2:

\(P_2 = 20 bar\\x_2 = 1 \\ h_2 = 2799.5 kJ/kg\\u_2 = 2600.3 kJ/kg\\v_2 = 0.09963m^3/kg\)

State 3:

\(P_2 = 5 bar\\v_2 = v_3 \\v_3 = v_f + x_3 (v_g - v_f)\\0.09963 = (1.0926 * 10^{-3}) +x_3 (0.3749 - (1.0926 * 10^{-3}))\\x_3 = 0.263\)

\(u_{3} = u_f + x_3 ( u_g - u_f)\\u_{3} = 639.68 + 0.263 (2561.2 - 639.68)\\u_{3} = 1146.2 kJ/kg\)

State 4:

\(P_{4} = 5 bar\\T_4 = 360^0 C\\h_4 = 3188.4 kJ/kg\\S_4 = 7.660 kJ/kg-K\\Q_{12} = h_2 - h_1 = 2799.5-3159.3 = -359 kJ/kg\\Q_{23} = u_3 - h_2 =1146.2-2006.3 = -1454.1 kJ/kg\\Q_{34} = h_4 - h_3 = 3188.4-1196.04 = 1992.36 kJ/kg\\Q_{41} = T(S_1 - S_4) = (360 + 273) (6.9917 - 7.660) = -423.04 kJ/kg\)

Calculate the network done for the cycle

\(W_{net} = m( Q_{12} + Q_{23} + Q_{34} + Q_{41})\\W_{net} = 5( -359.8 - 1454.1 + 1992.36 - 423.04)\\W_{net} = -1223 kJ\)

The sampling technique that can be used to selecting the participants will be a random sampling.

It should be noted that sampling simply a method in statistical analysis that predetermined observations are taken from the population.

In this case, the sampling technique that can be used to selecting the participants will be a random sampling. This is need to give everyone an equal chance of being selected.

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Answer:

a building project...

Explanation:

The concentration ratio for the PTC is approximately 1.48, and the length of the parabolic surface is approximately 5.2 meters.

To determine the concentration ratio and length of the parabolic surface for a Parabolic Trough Collector (PTC) with the given parameters, we can use the following formulas:

Concentration Ratio (CR) = Rim Angle / Aperture Angle

Length of Parabolic Surface (L) = Aperture^{2} / (16 * Focal Length)

First, let's calculate the concentration ratio:

Given:

Rim Angle (θ) = 80º

Aperture Angle (α) = 5.2 m

Concentration Ratio (CR) = 80º / 5.2 m

Converting the rim angle from degrees to radians:

θ_rad = 80º * (π / 180º)

CR = θ_rad / α

Next, let's calculate the length of the parabolic surface:

Given:

Aperture (A) = 5.2 m

Receiver Diameter (D) = 50 mm = 0.05 m

Focal Length (F) = A^{2} / (16 * D)

L = A^{2} / (16 * F)

Now we can substitute the given values into the formulas:

CR =\((80º * (π / 180º)) / 5.2 m\)

L = \((5.2 m)^2 / (16 * (5.2 m)^2 / (16 * 0.05 m))\)

Simplifying the equations:

CR ≈ 1.48

L ≈ 5.2 m

Therefore, the concentration ratio for the PTC is approximately 1.48, and the length of the parabolic surface is approximately 5.2 meters.

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Answer:

Conflicting goals. Specialised jargon. Unequal responsibilities

The teacher is demonstrating her understanding that is thematic units are an effective way to integrate different subjects.

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Answer:

d) "Napoleon Declares Himself Holy Roman Emperor"

Explanation:

The French Revolution is defined as a period of the major social upheaval which began in the year 1787 and lasted till year 1799. This revolution completely redefined the the very nature of the political power in France. and also the relationship between the rulers of France and the people they governed.

The 1789 Estates-General was the 1st meeting since year 1614 of the French Estates-General. It is a general assembly which represents the French estates of  realm.

During the French revolution was at peak, the National Assembly issued the Declaration of the rights of the man to the public.

Maximilien Robespierre was considered to be one of the most influential figure and most important statesman during the French Revolution.

Thus all the options (a),(b) and (c) are headlines about the French Revolution, except option (d).

(a) Yes, the consensus AB is an implicant of the function f. An implicant is a product term that covers at least one minterm of the function. Since xA and x'B are both implicants, they must both cover at least one minterm of the function. When two implicants have the same variable values, it means that they both cover the same minterm, and their consensus is also an implicant.

(b) It is not necessarily a Prime Implicant. A prime implicant is an implicant that cannot be further reduced without losing any of the minterms it covers. The consensus AB may or may not be a prime implicant depending on whether it can be reduced further.

For example, if xA = x'y and x'B = xy, then their consensus AB = xy is a prime implicant, because it covers the same minterm as xA and x'B, but it cannot be reduced further.

However, if xA = x'y and x'B = x'y, then their consensus AB = y is not a prime implicant, because it can be reduced further to y' (or to 0).

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The temperature of the system remains unchanged during expansion. There is heat exchange between both the system and the environment during the process. The system should be compressed or expanded at a slow pace so that the system allows appropriate heat exchange and keep the temperature constant.

The P-V curve in an isothermal process where:

PV = constant = C

⇒ dP / dV = – P / V

Work done in the isothermal process:

In this process, the gas follows Boyle’s law, and the work done by the gas is,

\(W = nRTln(\frac{V_2}{V_1} )\)

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Answer:

George Washington was the first president

The IndexedListInterface is a sub-interface of the ListInterface that adds methods for accessing elements of the list by their index.

The methods required by the IndexedListInterface but not by the ListInterface are:get(index: int): E: Returns the element at the specified position in the list.set(index: int, element: E):

Replaces the element at the specified position in the list with the specified element.add(index: int, element: E):

Inserts the specified element at the specified position in the list.remove(index: int):

Removes the element at the specified position in the list and shifts any subsequent elements to the left to fill the gap.

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The IndexedListInterface is a collection interface that extends ListInterface with the added feature of indexing elements and being able to retrieve them by their indices.

The IndexedListInterface can perform all operations that the ListInterface does, plus indexing operations.What operations are required by our IndexedListInterface but not by our ListInterface?The additional operations that are required by our IndexedListInterface but not by our ListInterface are the ability to retrieve an element at a specific index, set the element at a specific index, add an element at a specific index, and remove an element at a specific index. These methods are not available in the ListInterface but are necessary in an indexed list because they allow elements to be accessed, updated, and added at specific positions in the list, rather than just at the beginning or end.As a result, the IndexedListInterface is more versatile than the ListInterface, as it allows for greater control over the position of elements within the collection. However, the IndexedListInterface is more complex to implement because it must maintain the integrity of the indices even as elements are added, removed, or reordered within the list.

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A current value of 0.000005 A is equal to 5 HA.

Current is a measure of rate. In physics, there are various rate quantities. For instance, velocity, which measures how quickly an item changes position, is a rate quantity.

Velocity is defined mathematically as the position change to time ratio. The rate at which an object changes its velocity is called acceleration, which is a rate quantity.

Acceleration is defined mathematically as the ratio of velocity change to time. Power, which measures the rate at which work is done on an object, is a rate quantity.

A current value of 0.000005 A is equal to 5 HA.

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At a radius of 100 mm, the balancing mass is 0.0089 m from the rotational axis.

Due to the gravity, it has no tendency to rotate. In order to disperse the centre of mass to the centre of the wheel, reflective plates are positioned opposing valves on bicycle wheels. Car wheels, discs, and grindstones are more examples.

Let's denote the angular positions of mass "a" as zero degrees, mass "b," mass "c," and mass "d," respectively, as 60 degrees, 135 degrees, and 270 degrees. Given that mass "a" is at the centre, the moment caused by it is zero. The moment that the masses "b," "c," and "d" are due is determined by:

Moment due to mass "b": M_b = m_b * g * r_b * sin(60°)

Moment due to mass "c": M_c = m_c * g * r_c * sin(135°)

Moment due to mass "d": M_d = m_d * g * r_d * sin(270°)

The net moment about the centre of rotation is zero since the system is balanced, which means:

M_b + M_c + M_d = m * g * r * sin(theta)

where theta is the angle at which the balancing mass "m" is located.

By entering the specified values, we obtain:

\((120 kg * 9.81 m/s^2 * 0.04 m * sin(60°)) + (10 kg * 9.81 m/s^2 * 0.05 m * sin(135°)) + (15 kg * 9.81 m/s^2 * 0.03 m * sin(270°)) = m * 9.81 m/s^2 * 0.1 m * sin(theta)\)

After simplifying and finding "m" and "theta," we obtain:

m = 20.082 kg

theta = 311.86°

We must apply the formula to determine the location of the balancing mass at a radius of 100 mm: r = (M - m) * r_m / M

where M is the system's total mass, r m is the distance of mass "a" from the centre of rotation, and r is the distance of the balancing mass from the centre of rotation.

By entering the specified values, we obtain:

r = (120 kg + 10 kg + 15 kg - 20.082 kg) * 0.04 m / 145 kg

r = 0.0089 m

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Answer:

a. will be damaged if energized

Explanation:

A hermetic compressor needs a coolant to prevent overheating of the motor. The cooling of the compressor depends on the flow of the refrigerant through the compressor hence when under a deep vacuum,  the motor winding of a hermetic compressor can overheat.  

A crankcase heater is used to prevent the mixing of refrigerant and oil at low temperatures. The mixing of refrigerant and oil can cause oil foaming in the vacuum. When under a deep vacuum,  the motor winding of a hermetic compressor can overheat if the crankcase heater is energized.

Answer: 75,000 Hz

Explanation:

To calculate the frequency of the supply voltage, we need to use the formula:

frequency = 1 / time period

where the time period is the time it takes for one complete cycle of the waveform. For a sine wave, the time period is given by:

time period = 2π / angular frequency

where the angular frequency is the rate of change of the angle with respect to time and is given by:

angular frequency = 2π × frequency

Comparing the given voltage expression v = 240 sin (471,239t) V to the general form of a sine wave:

v = Vm sin(ωt + θ)

where Vm is the amplitude, ω is the angular frequency, t is time, and θ is the phase angle, we can see that the amplitude is 240 V, the angular frequency is 471,239 rad/s, and there is no phase angle (θ = 0).

Using the formula for angular frequency, we can find the frequency:

angular frequency = 2π × frequency

471,239 = 2π × frequency

frequency = 471,239 / (2π) ≈ 75,000 Hz

Therefore, the frequency of the supply voltage is approximately 75,000 Hz.

Hope this helps, :^)

Explanation:

Since the rollers are identical and the surfaces are smooth, the reaction forces at points A and C must be equal and vertical.

Let's call this force R. At point B, the reaction force is perpendicular to the inclined plane, so we can use trigonometry to find its magnitude.

Let's call this force T. Using the forces in the vertical direction, we can write: 2R + T = 2Q Using the forces in the horizontal direction

we can write: T = R tanθ where θ is the angle of inclination of the plane. Substituting the second equation into the first, we get: 2R + R tanθ = 2Q Simplifying: R (2 + tanθ) = 2Q R = 2Q / (2 + tanθ)

Plugging in the values: R = 2(100N) / (2 + tanθ) We can use trigonometry to find the value of tanθ: tanθ = opposite / adjacent = BC / AB

Since the rollers are identical, BC = AB, so: tanθ = AB / AB = 1 Therefore, R = 2(100N) / (2 + 1) = 50N and T = R tanθ = 50N * 1 = 50N

So the reaction forces at points A and C are both equal to 50N and vertical, while the reaction force at point B is equal to 50N and perpendicular to the inclined plane.

Answer:

a warmer earth due to fossil fuel emissions has milder winters and earlier springs

Explanation:

fossil fuels cause global warming which would make the winters less cold and spring and summer hotter.

Answer:It was B

Explanation:i took it on apec

and got A wrong so it told it was B

The action that is an example of how engineering affects science is designing an infrared camera that can record animal behavior in darkness. The correct option is B.

Engineering is the process of using mathematical and scientific principles to solve issues in the real world and create novel products and processes for use in a variety of fields and applications.

Engineering is the use of science and math to address issues. Engineers analyze how things operate and use scientific discoveries in real-world settings.

Strong problem-solving skills are among the most important traits an engineer can have. A substantial portion of an engineer's duties involve analyzing a situation, spotting issues, and then coming up with solutions.

Designing an infrared camera that can capture animal behavior in the dark is an example of how engineering influences research.

Thus, the correct option is B.

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The rating of the service disconnecting means for a single-family home must be at least 100 amperes, 3-wire.Therefore, 100 amperes is the required minimum rating of service size for a one-family home.

What is the service's required minimum ampere rating?

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Answer:

Weight Percentage of Ash = 3.4

Explanation:

Given - Coal containing 21% ash is completely combusted, and the ash is 100% removed in a water contact scrubber. If 10,000 kg of coal is burned per hour with a scrubber flow rate of 1.0 m3/min.

To find - the weight percentage of the ash in the water/ash stream leaving the scrubber is most nearly ?

Solution -

Given that,

Coal Burned Rate = 10,000 kg/hr

                              = \(\frac{10,000}{60 min} * 1 hr *\frac{kg}{hr}\)

                              = 166.6666 kg/min

⇒Coal Burned Rate = 166.6666 kg/min

Now,

Given that,

Ash content in coal = 21 %

⇒Ash in (coal that burned) = 166.6666 × \(\frac{21}{100}\) kg/min

                                             = 34.9999 ≈ 35 kg/min

⇒Ash in (coal that burned) = 35 kg/min

Now,

We know,

Density of water = 1000 kg/m³

Now,

Water flow Rate = \(1\frac{m^{3} }{min} * density\)

                           = 1000 kg/min

⇒Water flow Rate = 1000 kg/min

Now,

Total Mass flow Rate of (Water + Ash stream) = ( 1000 + 35) kg/min

                                                                           = 1035 kg/min

⇒Total Mass flow Rate of (Water + Ash stream) = 1035 kg/min

So,

Weight Percentage of Ash = (Weight of Ash ÷ Total weight of Stream) × 100

                                            = (35 ÷ 1035) × 100

                                            = 3.38 ≈ 3.4

∴ we get

Weight Percentage of Ash = 3.4

Answer:

SECTION LEARNING OBJECTIVES

By the end of this section, you will be able to do the following:

Distinguish between static friction and kinetic friction

Solve problems involving inclined planes

Section Key Terms

kinetic friction static friction

Static Friction and Kinetic Friction

Recall from the previous chapter that friction is a force that opposes motion, and is around us all the time. Friction allows us to move, which you have discovered if you have ever tried to walk on ice.

There are different types of friction—kinetic and static. Kinetic friction acts on an object in motion, while static friction acts on an object or system at rest. The maximum static friction is usually greater than the kinetic friction between the objects.

Imagine, for example, trying to slide a heavy crate across a concrete floor. You may push harder and harder on the crate and not move it at all. This means that the static friction responds to what you do—it increases to be equal to and in the opposite direction of your push. But if you finally push hard enough, the crate seems to slip suddenly and starts to move. Once in motion, it is easier to keep it in motion than it was to get it started because the kinetic friction force is less than the static friction force. If you were to add mass to the crate, (for example, by placing a box on top of it) you would need to push even harder to get it started and also to keep it moving. If, on the other hand, you oiled the concrete you would find it easier to get the crate started and keep it going.

Figure 5.33 shows how friction occurs at the interface between two objects. Magnifying these surfaces shows that they are rough on the microscopic level. So when you push to get an object moving (in this case, a crate), you must raise the object until it can skip along with just the tips of the surface hitting, break off the points, or do both. The harder the surfaces are pushed together (such as if another box is placed on the crate), the more force is needed to move them.

Answer:

True

Explanation:

they put it through a process to be able to reuse it

To cool a given room it is necessary to provide 4 ft³/s of air through an 8-inches diameter pipe, for this Entrance length in this pipe = 17.7 ft

Q = 4ft³/s

Diameter = D = 8 inches

Entrance length in this pipe = \(l_{e}\) = ?

By using flow rate formula:

V = Q/A

V= Q/ π/4*D²

= 4ft³/s / π/4 (8/12 ft)²

V= 11.5 ft/s

Thus, with ν = 1.57 x 10⁻⁴ft²/s (value from table)

Re = VD/ν

Re = 11.5 ft/s (8/12 ft)/1.57x10⁻⁴ft²/s

Re = 48,800 > 4000 (based on the criteria)

so, the flow is turbulent

Hence,

\(l_{e} / D\) = \(4.4 R_{e}^{1/6}\)

\(l_{e}\) = 4.4 (48,800)\(^{1/6}\) (8/12)

\(l_{e}\) = 17.7 ft

Entrance Length of an 8-inch diameter pipe = 17.7 ft

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Answer: hello your question lacks the required diagram attached below is the diagram

answer :  29528.1  N/m^2

Explanation:

Given data :

dimensions of tank :

Length = 5-m

Width = 4-m

Depth = 2.5-m

acceleration of tank = 2m/s^2

Determine the maximum gage pressure in the tank

Pa ( pressure at point A )  = s*g*h1

    = 10^3 * 9.81 * 3.01

    = 29528.1  N/m^2

attached below is the remaining part of the solution

Answer:

consistent; dependent; infinite

Explanation:

Subtract the first equation from the third equation.

3x + 2y − 2z  =  3  

− (x − 3y − 8z  =  −10)  

2x + 5y + 6z  =  13  Subtract.

Because the resulting equation is identical to the second equation, the system is consistent and dependent with infinitely many solutions.

The method that would be helpful in locating the top of a tunnel is (d) seismic reflection.

Seismic reflection is a geophysical method used to image subsurface structures by measuring the reflection of seismic waves off various layers and interfaces within the Earth. In the context of locating the top of a tunnel, seismic reflection can be used to identify the presence of a void or cavity, such as the tunnel roof, by analyzing the reflection pattern of seismic waves.

Permeability refers to the ability of a material to allow fluids (such as water or gas) to flow through it and is not directly related to locating the top of a tunnel. Saturation is a term used in hydrogeology to describe the amount of pore space in a rock or soil that is filled with water, which is also not specifically applicable to locating the top of a tunnel.

Seismic refraction is a method used to determine the subsurface structure and composition by analyzing the bending or refraction of seismic waves as they pass through different layers of the Earth. While seismic refraction can provide information about subsurface features, it may not be the most suitable method for specifically locating the top of a tunnel.

Therefore, the method most helpful in locating the top of a tunnel would be seismic reflection (d), as it can provide direct information about the presence and position of the tunnel roof by analyzing the reflected seismic waves. The other options, permeability (a), seismic refraction (b), and saturation (c), may not be as directly applicable to this specific task.

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Water flows through two connected identical pipes at a rate of 3 kg/s. The first pipe has smooth walls, the second pipe has rough walls. Assuming that water may be treated as an incompressible fluid, the water velocity will be higher in the rough pipe.

Water velocity can be defined as the amount of water that passes through a unit area of a pipe per unit time. It is the ratio of the volume flow rate to the area of the pipe. The relationship between water velocity, pressure, and cross-sectional area is given by the continuity equation.The continuity equation states that the product of the area of a pipe and the velocity of water flowing through it is constant. Therefore, as the area of the pipe decreases, the water velocity increases, and as the area of the pipe increases, the water velocity decreases.

The equation is expressed as follows:A1V1 = A2V2Where A1 and V1 are the cross-sectional area and velocity of water flowing through the first pipe, respectively. A2 and V2 are the cross-sectional area and velocity of water flowing through the second pipe, respectively.As the pipes are identical, their cross-sectional areas are the same. Therefore, to maintain the continuity equation, the water velocity will be higher in the rough pipe than in the smooth pipe. Hence, the correct option is B. the rough pipe.

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Answer:

A =41 .....

......

......

....C=21