Maximum work represents the highest amount of work that can be obtained from a system, while no work refers to the complete absence of energy transfer between the system and the surroundings.
Differences:
Maximum work and no work are two extremes in the context of thermodynamics, specifically in relation to energy transfer.
Maximum work refers to the amount of work that can be obtained from a system undergoing a thermodynamic process, assuming that the process is reversible and is carried out under conditions of maximum efficiency. This means that the system is able to convert all the available energy into work, without any losses due to irreversibility or inefficiency.
On the other hand, no work refers to the situation where there is no energy transfer between the system and the surroundings. This can occur when the system is in a state of equilibrium, and there is no net flow of energy between the two. In this case, the system is said to be in a state of thermal, mechanical, and chemical equilibrium.
In summary, maximum work represents the highest amount of work that can be obtained from a system, while no work refers to the complete absence of energy transfer between the system and the surroundings.
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Moving a magnet in and out of a coil will make the needle on the galvanometer move to either side. Explain what is happening in terms of magnetic induction.
Moving a magnet in and out of a coil will make the needle on the galvanometer move to either side. This phenomenon can be explained in terms of magnetic induction. When the magnet is moved into the coil, the magnetic field lines of the magnet cut across the coil's wire.
This cutting of magnetic field lines induces an electric current in the coil, according to Faraday's law of electromagnetic induction. This induced current flows through the galvanometer, causing the needle to move. The direction of the needle's movement depends on the direction of the current.
When the magnet is moved out of the coil, the magnetic field lines again cut across the coil's wire, inducing a current in the opposite direction. This causes the needle on the galvanometer to move in the opposite direction. In summary, the movement of the magnet in and out of the coil induces an electric current in the coil, which is detected by the galvanometer and causes the needle to move.
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how fast is moving light that has traveled through transparent glass and exited on the opposite side with respect to the incoming speed?
The light that has traveled through transparent glass and exited on the opposite side will move at the same speed as it was moving before entering the glass, but it would have traveled slower while inside the glass.
The speed of light changes when it travels through a transparent medium like glass. The speed of light in vacuum or air is approximately 299,792,458 meters per second (often rounded to 3.00 x 10⁸ m/s), but it slows down when it passes through a medium like glass. The amount of slowing down depends on the refractive index of the material, which is a measure of how much the speed of light is reduced as it passes through the material.
For typical glasses, the refractive index is around 1.5, which means that the speed of light is reduced by a factor of about 1.5 when it passes through the glass. So, if the speed of light in vacuum or air is taken as 1, the speed of light in glass would be approximately 2/3 (or 0.67) of its original speed.
When the light exits the glass on the opposite side, it returns to its original speed in air or vacuum. Therefore, the light exits the glass with the same speed it had before it entered the glass, as long as it is not absorbed or scattered by the glass.
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Which conclusion has been made by the world’s major scientific bodies about climate change?
a.
The recent harsh winters have placed some doubt on projected atmospheric warming.
b.
Climate change is projected to slow down during the latter half of this century.
c.
The current climate change is caused primarily by natural processes.
d.
We do not know enough about how climate works to make any definite conclusions.
e.
Climate change is real and is happening now.
The conclusion made by the world's major scientific bodies about climate change is that it is real and is happening now.
So, the correct answer is E.
There is overwhelming evidence that human activities, such as burning fossil fuels and deforestation, are the primary cause of the current climate change. While some may point to recent harsh winters as evidence against climate change, this is actually a result of the destabilization of the polar vortex due to warming.
Scientific models project that climate change will continue to worsen if significant action is not taken to reduce greenhouse gas emissions. The consensus among the scientific community is clear: climate change is a major threat to our planet and urgent action is needed to mitigate its effects.
Hence , the answer of the question is E.
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The voltage across a membrane forming a cell wall is 77.7 mV and the membrane is 9.02 nm thick. What is the electric field strength?
The electric field strength across the membrane is approximately 8.612 × 10⁶ V/m, given a voltage of 77.7 mV and a membrane thickness of 9.02 nm.
To determine the electric field strength across a membrane, we can use the formula:
Electric field strength = Voltage / Distance
Given that the voltage across the membrane is 77.7 mV (millivolts) and the membrane thickness is 9.02 nm (nanometers), we need to convert the units to be consistent.
1 mV = 0.001 V (volts)
1 nm = 1e-9 m (meters)
Converting the units:
Voltage = 77.7 mV × 0.001 V/mV = 0.0777 V
Distance = 9.02 nm × 1e-9 m/nm = 9.02e-9 m
Plugging the values into the formula:
Electric field strength = 0.0777 V / 9.02e-9 m
Calculating the electric field strength:
Electric field strength = 8.612 × 10⁶ V/m
Therefore, the electric field strength across the membrane is approximately 8.612 × 10⁶ V/m.
In summary, the electric field strength across the membrane is approximately 8.612 × 10⁶ V/m when the voltage across the membrane is 77.7 mV and the membrane thickness is 9.02 nm.
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What is the current in a 110V circuit with resistance is 10Ω?
Answer:
using V= IR
I= 11Ampere
what is the heat change in kj associated with 37.19 g of liquid water at 5.00 ° c changing to solid water at -5.00 °c?
The heat change associated with 37.19 g of liquid water at 5.00 °C changing to solid water at -5.00 °C is approximately 12.4007 kJ.
The heat change associated with a phase change can be calculated using the heat of fusion, which is the amount of heat required to change a given mass of a substance from a solid to a liquid, or vice versa. The heat of fusion for water is approximately 333 J/g.
The heat change associated with 37.19 g of liquid water at 5.00 °C changing to solid water at -5.00 °C can be calculated as:
q = m * ΔHfusion
where m is the mass of the water and ΔHfusion is the heat of fusion. In this case, m = 37.19 g and ΔHfusion = 333 J/g, so:
q = 37.19 g * 333 J/g = 12400.07 J
To convert the heat change from joules to kilojoules, divide by 1000:
q = 12400.07 J / 1000 = 12.4007 kJ
So the heat change associated with 37.19 g of liquid water at 5.00 °C changing to solid water at -5.00 °C is approximately 12.4007 kJ.
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Why would it be incorrect to say that the bulb supplies 60 J of light energy energy each second
Answer:
Explanation:
A 60W bulb , consumes electrical energy of 60 J per second but it does not give out all the energy in the form of light . Most of the energy consumed by it is wasted in the form of heat . Only a fraction of energy is converted into light energy .
Hence, it is wrong to say that bulb supplies 60 J of light energy each second .
Two equal forces act at the same time on the same motionless object, but in opposite directions. Which statement best describes the object’s resulting motion?
A. The object will accelerate.
B. The object will move at a constant speed.
C. The object will remain motionless.
D. The object will change direction.
The slowly fluctuating harmonic patterns by composer philip glass, used in his quatsi trilogy, represent what musical style?
The slowly fluctuating harmonic patterns by composer philip glass, used in his quatsi trilogy, represent minimalism musical style.
A minimalist, Philip Glass is, was, or never was. He does not appreciate being categorized, like most artists and most individuals. He has long denied being a minimalist, particularly with regard to his work produced after the mid-1970s. The Qatsi Trilogy, directed by Godfrey Reggio, begins with the 1983 release of Koyaanisqatsi. Over the two decades it took to get the movies made, the Qatsi music changed, reflecting the evolution of both Glass's overall style and the films' own, as well as of what quickly developed into a particularly symbiotic collaboration between Glass and Reggio, a composer and a director who seemed destined to work together.Learn more about the music composition with the help of the given link:
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A box with a total surface area of 1.2 m2 and a wall thickness of 4 cm is made of an insulating material. A 10 W electric heater inside the box maintains the inside temperature at 15 oC above the outside temperature. What is the thermal conductivity of the insulating material in units of kcal/(s oC m)
For a box with a total surface area of 1.2 m2, the thermal conductivity of the insulating material is mathematically given as
k=5.29*19^{-6} kcal/(s oC m)
What is the thermal conductivity of the insulating material?Generally, the equation for the is mathematically given as
P=Ka dT/L
Therefore
k=10*4*10^{-2}/1.2*1.5
k=5.29*19^{-6} kcal/(s oC m)
In conclusion, the thermal conductivity
k=5.29*19^{-6} kcal/(s oC m)
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The work done by a conservative force is indicated in FIGURE 8-23 for a variety of different paths connecting the points A and B. What is the work done by this force (a) on path 1 and (b) on path 2 ?
Since work is defined as the product of force and displacement, the work performed in moving from A to B is 15 J, and the work done in going from B to A is -15 J.
What is work?In physics, work is a measure of the energy transferred when a force acts on an object and causes it to move through a distance. Work is defined as the product of the force applied to an object and the distance through which that force acts. Mathematically, work is given by the formula:
W = F x d x cosΘ
where W is work, F is the force applied, d is the displacement of the object, and theta is the angle between the force and the displacement vectors. The unit of work is the joule (J), which is defined as the work done when a force of 1 newton (N) acts on an object to move it through a distance of 1 meter (m).
If the force is applied in the same direction as the displacement, then the angle theta is 0 degrees and cosΘ is equal to 1, so the formula for work simplifies to:
W = F x d
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A 65-cm-diameter wheel accelerates uniformly about its center
from 150 rpm to 340 rpm in 4.0 s
Part A
Determine its angular acceleration.
Express your answer using two significant figures.
Part B
Determine the radial component of the linear acceleration of a
point on the edge of the wheel 1.0 ss after it has
started accelerating.
Express your answer to two significant figures and include the
appropriate units.
Part C
Determine the tangential component of the linear acceleration of
a point on the edge of the wheel 1.0 ss after it has
started accelerating.
Express your answer using two significant figures.
The angular acceleration of the wheel is 5.01 rad/s² (two significant figures).
The radial component of the linear acceleration of a point on the edge of the wheel 1.0 s after it has started accelerating is 1.62 m/s² (to two significant figures).
The tangential component of the linear acceleration of a point on the edge of the wheel 1.0 s after it has started accelerating is 404.7 m/s² (two significant figures).
Part A:
To determine the angular acceleration, we can use the formula:
angular acceleration (α) = (change in angular velocity)/(change in time)
The change in angular velocity is calculated by subtracting the initial angular velocity (ω1) from the final angular velocity (ω2):
change in angular velocity = ω2 - ω1
Given:
Initial angular velocity (ω1) = 150 rpm
Final angular velocity (ω2) = 340 rpm
Change in time (Δt) = 4.0 s
Converting the angular velocities from rpm to rad/s:
ω1 = (150 rpm) × (2π rad/1 min) × (1 min/60 s) = 15.708 rad/s
ω2 = (340 rpm) × (2π rad/1 min) × (1 min/60 s) = 35.751 rad/s
Calculating the change in angular velocity:
change in angular velocity = ω2 - ω1 = 35.751 rad/s - 15.708 rad/s = 20.043 rad/s
Now we can calculate the angular acceleration:
angular acceleration (α) = change in angular velocity/change in time
α = 20.043 rad/s / 4.0 s = 5.01 rad/s²
Therefore, the angular acceleration of the wheel is 5.01 rad/s² (two significant figures).
Part B:
The radial component of linear acceleration (ar) at the edge of a rotating object can be calculated using the formula:
ar = r × α
where r is the radius of the wheel and α is the angular acceleration.
Given:
Diameter of the wheel = 65 cm
Radius (r) = diameter/2 = 65 cm / 2 = 32.5 cm = 0.325 m
Angular acceleration (α) = 5.01 rad/s² (from Part A)
Calculating the radial component of linear acceleration:
ar = r × α = 0.325 m × 5.01 rad/s² = 1.62 m/s²
Therefore, the radial component of the linear acceleration of a point on the edge of the wheel 1.0 s after it has started accelerating is 1.62 m/s² (to two significant figures).
Part C:
The tangential component of the linear acceleration (at) at the edge of a rotating object can be calculated using the formula:
at = r× ω²
where r is the radius of the wheel and ω is the angular velocity.
Given:
Radius (r) = 0.325 m
Angular velocity (ω) = ω2 = 35.751 rad/s (from Part A)
Calculating the tangential component of linear acceleration:
at = r × ω² = 0.325 m × (35.751 rad/s)² = 404.7 m/s²
Therefore, the tangential component of the linear acceleration of a point on the edge of the wheel 1.0 s after it has started accelerating is 404.7 m/s² (two significant figures).
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pulls a wagon a distance of 32 meters the handle is above an angle of 20 degrees above horizontal if you pull on it with a force of 27 N what work is it
Hi there!
When finding work (J) given force (N), we use the equation:
W = FdcosФ <-- Only take into account the force in the direction of motion
Plug in the given values:
W = 27(32)cos(20) = 811.89 J
Explanation:
Here,
Given that,
pulls a wagon a distance of 32 meters the handle is above an angle of 20 degrees above horizontal if you pull on it with a force of 27 N
To find,
The total work doneAs we know that,
\({\boxed{\sf{W=f.d.cos\theta }}}\)
According to the question,
\(W=27(32)cos{20}\\\\w=811.89J\)
what is the difference between the pressure exerted by a soild and by a liquid ?
show that the transition matrix is regular and find its steady-state vector.
To show that a transition matrix is regular by raising the matrix to different powers until you find a power with all positive elements and its steady-state vector is equation πP = π while ensuring the elements of π sum to 1.
A transition matrix is regular if some power of the matrix has only positive elements, a steady-state vector is a probability vector that remains unchanged after being multiplied by the transition matrix. To demonstrate that the transition matrix is regular, raise the matrix to different powers until you find a power with all positive elements. If such a power exists, the matrix is considered regular.
Next, to find the steady-state vector, solve the following equation: πP = π, where π is the steady-state vector, and P is the transition matrix. Additionally, ensure the elements of π sum to 1, representing the total probability, you can solve this system of linear equations using methods like Gaussian elimination, matrix inversion, or iterative techniques. In summary, to show that a transition matrix is regular, find a power of the matrix with all positive elements, then, to find the steady-state vector, solve the equation πP = π while ensuring the elements of π sum to 1.
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Among the many discoveries made with the Hubble Space Telescope are four new moons of Saturn, the largest being just about 70.0 km in diam-eter. Suppose this moon is covered by a highly reflective coating, thus forming a spherical convex mirror. Another moon happens to pass by at a distance of 1.00 × 10? km. What is the image distance?
The approximate image distance (di) of the passing moon when reflected off the highly reflective coating on the spherical convex mirror is approximately 0.0286 km, or 28.6 meters.
To determine the image distance of the passing moon when reflected off the highly reflective coating on the spherical convex mirror (the large moon with a diameter of 70.0 km), we can use the mirror equation:
1/f = 1/do + 1/di,
where f is the focal length, do is the object distance, and di is the image distance.
Since we are dealing with a convex mirror, the focal length (f) is positive. For a spherical convex mirror, the focal length is half the radius of curvature (R). However, the radius of curvature is not given in the information provided, so we cannot directly calculate the focal length.
However, we can make use of the fact that a convex mirror always produces a virtual image. In this case, the image distance (di) will be negative, indicating a virtual image formed behind the mirror.
Given:
Diameter of large moon = 70.0 km
Distance of passing moon = 1.00 × 10? km
Since the distance of the passing moon is much greater than the diameter of the large moon, we can approximate the object distance (do) as the distance of the passing moon (1.00 × 10? km).
Substituting these values into the mirror equation:
1/f = 1/do + 1/di,
we can rearrange the equation to solve for the image distance (di):
1/di = 1/f - 1/do.
Since a convex mirror has a positive focal length and we have a virtual image, the term 1/f will be positive and 1/do will be negative.
Substituting the values and performing the calculations:
1/di = 1/f - 1/do
= 1/2f - 1/do
≈ 1/2f (assuming 1/do is negligible compared to 1/2f)
Now, we need to determine the approximate value of 1/2f. Since we don't have the radius of curvature or focal length information, we cannot calculate an exact value. However, we can make an estimation based on the given information.
Assuming the large moon is roughly spherical, we can consider its diameter of 70.0 km as the approximate diameter of its curvature. The radius of curvature (R) would be half the diameter, or 35.0 km.
Since the focal length (f) of a spherical convex mirror is half the radius of curvature, we can estimate the focal length as 17.5 km.
Substituting this estimated value into the equation:
1/di ≈ 1/2f
= 1/(2 * 17.5 km)
≈ 1/35.0 km^-1
= 0.0286 km^-1.
Therefore, the approximate image distance (di) of the passing moon when reflected off the highly reflective coating on the spherical convex mirror is approximately 0.0286 km, or 28.6 meters.
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The block and the spool have the same mass. The strings are pulled with the same constant tension and start pulling at the same instant. Make the approximation that the strings and the hook are Blo Same Same a. Does the spool cross the finish line before, after, or at the mass same instant as the block? Explain Spool b. Consider the following dialogue between two students: Student "I think that there's the same amount of work done on block and spool as they both move the same distance
Student 2:"I disagree. I think that the hand pulling the spool does more work than the hand pulling the block since the string unwinds as the spool is pulled. With which student, if either, do you agree? c. When each crosses the finish line, is the total kinetic energy of the spool greater than, less than, or equal to that of the block? Explain. D. When each crosses the finish line, is the translational kinetic energy of the spool greater than, less than, or equal to that of the block? Explain
a. Does the spool cross the finish line before, after, or at the same instant as the block? Explain: Since the strings are pulled with the same constant tension, the spool and the block will start moving at the same time and will cover the same distance. Therefore, they will cross the finish line at the same instant.
b. Consider the following dialogue between two students:
Student: "I think that there's the same amount of work done on block and spool as they both move the same distance."
Student 2: "I disagree. I think that the hand pulling the spool does more work than the hand pulling the block since the string unwinds as the spool is pulled."
In this scenario, student 2 is correct. The work done on the spool is greater than the work done on the block because the spool unwinds as it is pulled, which means that more energy is required to move the spool a given distance than to move the block a given distance. Therefore, the spool will cross the finish line after the block.
c. When each crosses the finish line, is the total kinetic energy of the spool greater than, less than, or equal to that of the block? Explain:
The total kinetic energy of an object is equal to its mass times its velocity squared. Therefore, the total kinetic energy of the spool is greater than the total kinetic energy of the block since the spool is moving faster than the block.
d. When each crosses the finish line, is the translational kinetic energy of the spool greater than, less than, or equal to that of the block? Explain:
The translational kinetic energy of an object is equal to its mass times its velocity. Therefore, the translational kinetic energy of the spool is greater than the translational kinetic energy of the block since the spool is moving faster than the block.
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four particles enter a region of uniform magnetic field with velocities perpendicular to magnetic field lines. the particles have the following masses and charges:
The ranking of radii of their paths for these particles, largest to smallest is r4 > r2 > r3 > r1.
Determining the radius of the trajectories. For determining it we use the following formula that should be perpendicular and contained the magnetic field:
r = mv/qB
Where
m represents the mass of the particle
v represents the speed of the particle
q represents charge
B represents the magnitude of the magnetic field
Determining the charge one
\(r1 = m * v/(B * q)\)
Determining the charge two
\(r2 = 2m * 2v/(2Bq)\)
= 2mv/Bq
Determining the charge three
\(r3 = 3/2 * mv/(B*q)\)
Determining the charge four
\(r4 = 6 mv/(2 * B * q)\)
= 3 mv/(B*q)
Therefore, the ranking of the radii is r4 > r2 > r3 > r1
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Complete Question:
Four particles enter a region of uniform magnetic field with velocities perpendicular to magnetic field lines. The particles have the following masses and charges:
1 : charge q; velocity v and mass m
2: charge 29 velocity 2v and mass 2m
3: charge q: velocity 3v, mass m/2
4: charge 2q: velocity 30, mass 2m
Rank the radii of theirs paths for these particles, largest to smallest
why is skipping quicker than running
Answer:
because you are taking longer and faster strides
Explanation:
Answer:
you are taking longer to skip.
Explanation:
An unknown substance was observed to have the following properties: colorless liquid that feels slippery, pH of 8.5, turns red litmus to blue. Based on these properties, what is the best classification of this substance?
acid
base
element
salt
Answer:
It is a base
Explanation:
Because
Answer:it’s a base
Explanation: this is because the bases have a very bitter taste but a very slippery feel at the same time leading to a substance with a ph of 8.5 and the red turning to blue so this is a base
name six kinds of simple machines.
Answer:
the wheel and axle, the lever, the inclined plane, the pulley, the screw, and the wedge
Explanation:
Draw conclusions: Objects falling through air are slowed by the force of air resistance. Which objects were slowed the most by air resistance
Due to this air resistance, Galileo discovered that heavier or more dense things fall more quickly than less dense ones. Together, a brick and a feather fell. The feather falls more slowly due to air resistance.
Descending against air resistance an object often experiences some air resistance as it falls through the air. The leading surface of the object collides with air molecules, creating air resistance. Several variables affect how much air resistance the object really experiences.
Therefore, heavier things fall quicker than lighter ones because the force of gravity acting on them is greater. As a result, heavier objects accelerate at faster speeds until the force of air resistance acts on them.
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The absolute temperature of a gas is t. in order to double the rms speed of its molecules, what should be the new absloute temperature?
The new absloute temperature should be 4t.
TemperatureThe hotness of matter or radiation is expressed by the physical quantity known as temperature.
There are three different types of temperature scales: those, like the SI scale, that are defined in terms of the average translational kinetic energy per freely moving microscopic particle, like an atom, molecule, or electron in a body; those that solely depend on strictly macroscopic properties and thermodynamic principles, like Kelvin's original definition; and those that are not defined by theoretical principles but rather by useful empirical properties of particula.
Using a thermometer, one can gauge temperature. It is calibrated using different temperature scales, each of which historically defined itself using a different set of reference points and thermometric materials.
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Which was a belief of Copernicus's model of the solar system?
The planets move in perfect circles.
All planets orbit the Sun at the same speed.
The outer planets move in epicycles.
Earth is fixed to a crystalline sphere.
Answer:
The planets move in perfect circles.
Explanation:
In the 1500s Copernicus reintroduced the heliocentric model and suggested that the planets all orbit around the Sun in perfect circles.
A jet is flying from atlanta to gulfport and is cruising at Mach .79 or 844 km/hr. During the last 89 km it reduces its speed for landing at a rate of -2780 km/hr^2. How long will it take for the jet to reach landing speed? What was the landing speed of the jet?
Answer:
The time it takes for the jet to reach landing speed is approximately 0.136 hours which is approximately 489 seconds
The landing speed is approximately 466.365 km/hr
Explanation:
The given parameters are;
The initial cruising speed of the jet = Mach 0.79 = 844 km/hr
The rate of speed reduction in the last 89 km = -2780 km/hr²
The distance it takes the jet to reduce its speed for landing = 89 km
Given the above information, we make use of the following equation of motion;
s = u·t - 1/2·a·t²
v² = u² - 2·a·s
Where;
s = The distance over which the acceleration (deceleration) is applied = 89 km
u = The initial velocity = 844 km/hr
t = The time taken for the accelerating/decelerating motion
v = The final velocity (landing speed)
Substituting the values gives;
v² = 844² - 2·(2780)·89 = 217496
v = √217496 = 466.365 km/hr
v ≈ 466.365 km/hr
Therefore, the landing speed, v ≈ 466.365 km/hr
The time it takes is given by the equation, v = u - a·t
Therefore;
t = (u - v)/a = (844 - 466.365)/2780 ≈ 0.136 hours
The time it takes for the jet to reach landing speed ≈ 0.136 hours
From, s = u·t - 1/2·a·t², we have
89 = 844·t - 1/2 × 2780 × t²
89 = 844·t - 1390 × t²
1390 × t² - 844·t + 89 = 0
Solving with an online application gives;
t = 211/695 + (√(27187/2))/695 = 0.4715 hours or t = 211/695 - (√(27187/2))/695 = 0.136 hours
We note that the second time is for the time it will take the jet to get back to 89 km after reaching a speed of 0
Therefore, the correct time is t = 0.136 hours
The time it takes for the jet to reach landing speed ≈ 0.136 hours
I need the question of this page filled with steps...... I'm confused
i) The velocity of the particle at 17 sec is 17m/s.
ii) The total distance travelled is 190 m.
iii) The total displacement is -10m.
What is the difference between distance and displacement?Distance is the length of any path connecting any two places. As measured along the shortest path between any two points, displacement is the direct distance between them.
The direction is ignored when calculating distance. The direction is accounted for in the displacement calculation.
Since it solely depends on magnitude and not direction, distance is a scalar number. Since displacement varies on both magnitude and direction, it is a vector quantity.
Distance provides specific directions that must be taken when moving from one location to another. Displacement only provides a partial description of the route because it pertains to the quickest way.
Velocity of particle = Slope of the object =Δ \(\frac{y}{x}\)
Velocity = \(\frac{95-10}{20-15}\) = 17m/s
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33] You have long hair, you should:
a
Tuck it behind your ears.
b) Pull it back into a pony tail so that it is up out of the
way.
c) Don't worry about it, most labs aren't dangerous.
Answer:
B
Explanation:
hair can be a safety hazard
A + 9.4 nC point charge and a - 2.31 nC point charge are 4.94 cm apart. What is the electric field strength at the midpoint between the two charges?
Given:
The charge is q1 = 9.4 nC
The charge q2 = -2.31 nC
The distance between them is r = 4.94 cm
To find the electric field strength at the midpoint between two charges.
Explanation:
The electric field strength at the midpoint will be the sum of electric field strength due to q1 and q2.
The electric field strength can be calculated by the formula
\(E=\frac{kq}{r^2}\)Here, k is the electrostatic constant whose value is
\(k=9\times10^9\text{ N m}^2\text{ /C}^2\)The electric field strength due to the charge q1 is
\(\begin{gathered} E_1=\frac{kq1}{(\frac{r}{2})^2} \\ =\frac{9\times10^9\times9.4\times10^{-9}}{(\frac{4.94}{2}\times10^{-2})^2} \\ =1.39\times10^5\text{ V/m} \end{gathered}\)The electric field strength due to the charge q2 is
\(\begin{gathered} E_2=\frac{kq2}{(\frac{r}{2})^2} \\ =\frac{9\times10^9\times2.31\times10^{-9}}{(\frac{4.94}{2}\times10^{-2})^2} \\ =3.4\times10^4\text{ V/m} \end{gathered}\)The electric field strength at the midpoint will be
\(\begin{gathered} E=E_1+E_2 \\ =(1.39\times10^5)+(3.4\times10^4) \\ =173000\text{ V/m} \end{gathered}\)Thus, the electric field strength at the midpoint between the two charges is 173000 V/m
During a live action show, an acrobatic performer will fall from heights onto a large foam mat. While these falls would normally injure a person, the performer is unharmed. From the perspective of momentum, what is the best explanation for this?.
The following relationship between impulse and momentum enables for the proper outcome to be determined: The average force Impulse falls as impact time increases.
The impulse, which is connected to the fluctuation in the quantity of movement, is calculated by multiplying the applied force by the time interval. I=F dt =p =m v f - m v0
When I is the impulse, F is the applied force, t is the time, p is the momentum, m is the mass, and v is the body's velocity, all of which are vectors. When the body stops, its speed is zero, and the height of the body affects how quickly it strikes the foam bed. A certain amount of force must be applied in order for someone to be hurt.
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what is the gpe of a 200g ball that is 10m off the ground
Answer:
gpe gained = 20J
Explanation:
gpe = mass * gravity * height
gpe = (200/1000) kg * 10 * 10
gpe = 20J