explain how the diffraction of waves plays a role in radio transmission and cellphone service

Explanation:

current = velocity/resistance

I = V/R

15/4

current = 3.75A

hope this helps...

The component vr of velocity vector v along the radial direction from the radar gun to the car is the component of the velocity that is in the direction of the radial line that connects the radar gun to the car.

It can be calculated by taking the dot product of the velocity vector and the unit vector of the radial line.

The unit vector of the radial line is a vector that has a magnitude of one and that is pointing in the direction of the radial line.

The dot product of two vectors is equal to the magnitude of the first vector multiplied by the projection of the second vector on the first vector.

Thus, the component of velocity vr along the radial line is calculated by taking the magnitude of v multiplied by the projection of the unit vector of the radial line on v.

The component vr can be used to determine the speed of the car from the radar gun. The speed of the car is equal to the magnitude of vr divided by the speed of light.

By knowing the speed of the car, the speed limit can be compared to it in order to determine if the car is driving at a legal speed.

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The correct option that accurately summarizes the cause of continental drift is:

Tectonic plates are in motion due to convection currents in Earth's mantle. This motion causes the continents to slowly drift away from each other. This statement reflects the theory of plate tectonics, which explains that the Earth's lithosphere is divided into several large plates that are in constant motion. These plates are driven by convection currents in the underlying mantle, leading to the movement and interaction of continents over geological time scales.

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Answer:

Decrease in acceleration

Explanation:

Answer:

a) the most dangerous combination of tires and roads surfaces are old tires on wet concrete because it shows the longest distance moved by a car when the brake is pushed

b) Old tires on wet concrete

c) wet tires require longer braking distance than dry tires because the wet surface on the tires slide rather

than stopping gradually.

The piece of office telephone equipment commonly used to assist with answering and routing phone calls into the office is called a Private Branch Exchange (PBX) system.

PBX systems are essential in managing incoming and outgoing calls in a professional and organized manner.

A PBX system can be hardware-based or software-based, offering flexibility in terms of installation and maintenance. It supports multiple phone lines, enabling businesses to have separate lines for different departments or employees. The system also provides features like call transferring, call forwarding, voicemail, and automated call routing, ensuring that all incoming calls are directed to the appropriate party efficiently.

Furthermore, PBX systems can be integrated with other office communication tools like email, instant messaging, and video conferencing, promoting seamless collaboration among employees. Overall, a PBX system significantly improves office communication and productivity by providing a centralized solution for managing and routing phone calls.

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Answer:

A resistor of 160 ohms should be used to replace the current resistor

Explanation:

Applying,

Ohm's Law

V = IR................... Equation 1

Where V = Voltage of the battery, I = current, R = Resistance

From the question,

Given: I = 0.2 A, R = 120 ohms.

Substitute these values into equation 1

V = 0.2×120

V = 24 V

IF a current of 0.15 A is required,

make R the subject of equation 1

R = V/I............... Equation 2

Given: V = 24 V, I = 0.15 A

Substitute these values into equation 2

R = 24/0.15

R = 160 ohms.

Hence a resistor of 160 ohms should be used to replace the current resistor

Answer:

Earplugs

Explanation:

The objects that absorb the most sound waves are usually soft and flexible or porous. So, the object that satisfies the first two characteristics is Earplugs. It means that the answer is Earplugs.

The  the capacitance of the cable is 18 nF, when the resulting potential difference between the two conductors is 420 V.

The capacitance of a cable is 125 nF when the resulting potential difference between the two conductors is 60 V. If the resulting potential difference between the two conductors is 420 V, what is the capacitance, in nanofarads, of the cable

Given:

Capacitance, C = 125 nF

Initial potential difference, V1 = 60 V

Final potential difference, V2 = 420 V

To find:

The capacitance of the cable is given by the formula:

Capacitance, C = (Charge, Q) / (Potential difference, V)

Or,

Charge, Q = C × V

We know that,

Charge, Q1 = C × V1

Charge, Q2 = C × V2

If we divide Q2 by Q1, then we get:

C × V2 / C × V1

= Q2 / Q1

Or,

C × V2 / C × V1 = (Final charge) / (Initial charge)

From the principle of conservation of charge, we know that:

Charge cannot be created or destroyed; it can only be transferred from one place to another.

Therefore, the initial charge and final charge are the same.

So, we can say that:

Charge, Q2 = Charge, Q1

Hence, C × V2 = C × V1

Or,

C = V1 / V2 × C1

Substituting the values, we get:

C = 60 V / 420 V × 125nF

= 18 nF (approximately)

Therefore, the capacitance of the cable is 18 nF, when the resulting potential difference between the two conductors is 420 V.

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The kangaroo's horizontal speed will be 9.7 m/s and its departure speed will indeed be 10.65 m/s.

By observing the pace at which this compressed region moves through the medium, we may determine the sound speed. The sound wave travels at a speed of around 343 meters per second in low humidity at 20 degrees Celsius.

The following equation relates the distance to the direction and initial velocity:

d = [v₀²sin2θ]/g, where θ – the angle of the jump.

Thus, v₀² = gd / (sin2θ) = (9.8×8)/0.69 = 113.62

v₀ = 10.65 m/s ( the take off speed).

The horizontal velocity equals:

vₓ = v₀cos 22° = 10.65 m/s × 0.92 = 9.7 m/s

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Therefore, the magnitude of the electric field at a point 6.0 m perpendicular from the center of the wire is approximately 9.8 x 10³ N/C, and the direction is inward. The magnitude of the electric field at a point 1.3 m perpendicular from the center of the wire is approximately 4.4 x 10⁴ N/C, and the direction is inward.

Part A:

The formula for the electric field due to a long wire is given by:

E = (2kλ) / r

Using the given values:

k = 9 x 10⁹ N m²/C²

λ = -5.8 μC/m

r = 6.0 m

Substituting the values into the formula:

E = (2 * 9 x 10⁹ * (-5.8 x 10⁻⁶)) / 6.0

E ≈ -9.8 x 10³ N/C (rounded to two significant figures)

Therefore, the magnitude of the electric field at a point 6.0 m perpendicular from the center of the wire is approximately 9.8 x 10³ N/C.

Part B:

The direction of the electric field at a point 6.0 m perpendicular from the center of the wire is radially outward or inward, depending on the sign of the charge distribution.

Since the charge distribution is negative (-5.8 μC/m), the electric field will be directed inward toward the wire.

Therefore, the direction of the electric field at the given point is inward.

Part C:

Using the same formula and approach as in Part A, but with the distance from the wire being r = 1.3 m:

E = (2 * 9 x 10⁹ * (-5.8 x 10⁻⁶)) / 1.3

E ≈ -4.4 x 10⁴ N/C (rounded to two significant figures)

Therefore, the magnitude of the electric field at a point 1.3 m perpendicular from the center of the wire is approximately 4.4 x 10⁴ N/C.

Part D:

As before, the direction of the electric field at a point 1.3 m perpendicular from the center of the wire will be inward due to the negative charge distribution along the wire.

Therefore, the direction of the electric field at the given point is inward.

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The level of pH is 3.5 (c)

Glycolic acid is a type of alpha-hydroxy acid (AHA) that is commonly used in skincare products to exfoliate the skin, improve skin texture, and reduce the appearance of fine lines and wrinkles. The pH level of glycolic acid is important because it can affect its potency and potential side effects on the skin.

The optimal pH level for glycolic acid to be effective is between 3.5 and 4.0. At this pH range, glycolic acid is able to penetrate the skin and effectively exfoliate dead skin cells. A pH level below 3.5 can cause excessive skin irritation and dryness, while a pH level above 4.0 may not be as effective in exfoliating the skin.

Therefore, of the options given, the most appropriate pH level for glycolic acid to have minimal, if any effect on the skin would be option C, 3.5.

pH levels of 1.5, 2.5, and 4.5 are either too acidic or too alkaline for glycolic acid to be effective without causing excessive irritation or reducing its potency.

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48 m/s in terms of km/h is 720.8 km/h. In terms of m/min is 2880 m/min, in terms of km/s is 0.048 km/s and in terms of km/min is 2.88 km/min.

To solve this question, we need to understand some terms. The unit of velocity is measured in m/s. It can be expressed in different units of velocity.

1 km (kilometer) = 1000 meter

1 h (hour) = 3600 seconds

1 minutes = 60 seconds

To convert m/s into km/h,

48 m/s * 3600/1000 =  172.8 km/h

To convert m/s into m/min,

48 m/s * 60 = 2880 m/min

To convert m/s into km/s,

48 m/s ÷ 1000 = 0.048 km/s

To convert m/s into km/minutes,

48 m/s * 60 / 1000 = 2.88 km/min

Therefore, the 48 m/s expressed is 172.8 km/h, 2880 m/min, 0.048 km/s and 2.88 km/min.

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48 m/s is equivalent to  172.8 km/h, 2880 m/min, 0.048 km/s, and 2.88 km/minute.

To express 48 m/s in different units of velocity:

km/h (kilometers per hour):

To convert m/s to km/h, we can use the conversion factor of 3.6 since 1 m/s is equal to 3.6 km/h.

48 m/s * (3.6 km/h / 1 m/s) = 172.8 km/h

Therefore, 48 m/s is equivalent to 172.8 km/h.

m/min (meters per minute):

To convert m/s to m/min, we can use the conversion factor of 60 since there are 60 seconds in a minute.

48 m/s * (60 m/min / 1 s) = 2880 m/min

Therefore, 48 m/s is equivalent to 2880 m/min.

km/s (kilometers per second):

Since 1 kilometer is equal to 1000 meters, to convert m/s to km/s, we divide the value by 1000.

48 m/s / 1000 = 0.048 km/s

Therefore, 48 m/s is equivalent to 0.048 km/s.

km/minute (kilometers per minute):

To convert m/s to km/minute, we first need to convert m/s to km/s (as calculated in the previous step) and then multiply by 60 to convert seconds to minutes.

0.048 km/s * 60 = 2.88 km/minute

So, 48 m/s is equivalent to 2.88 km/minute.

Hence, 48 m/s is equivalent to approximately 172.8 km/h, 2880 m/min, 0.048 km/s, and 2.88 km/minute.

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The correct answer for the (A) Escape velocity is \(570\) (B) Escape velocity is \(0.57\) in Km/h and (c). Escape velocity is \(1.27\) in mph.

Given:

Diameter of asteroid D = \(10\) km

Radius R = \(5\) Km

Density \(\rho\)  = \(3000\) kg/m³

Unit conversion;

\(1\) m/s  = \(0.001\) Km/s

\(1\) m/s  = \(2.23694\) mph

(A)To calculate Escape velocity:

Use the formula;

\(v_e = \sqrt{\dfrac{2GM}{R} }\)

Gravitational Constant \(G\) = \(6.67430\)

To calculate Mass(\(M\)) of the asteroid, Calculate Volume(\(V\)) of the sphere and multiply it with density(\(\rho\)).

\(V= \dfrac{4}{3} \pi R^3 \\\\\rho = \dfrac{M}{V}\)

\(M = \rho*V\)

= \(523598775000\) Kg

Escape velocity:

\(v_e = \sqrt{\dfrac{2*6.67430 * 10^{-11} * 523598775000}{5000} }\)

\(= 570\) m/s

(B)Escape velocity in Km/s:

\(v_e = \dfrac{570}{1000}\)

\(= 0.57\)  Km/s

(B)Escape velocity in mph:

\(v_e = 0.57 * 2.23694\)

\(= 1.27\) mph

Escape velocity is \(570\) m/s. In Km/h is \(0.57\) and In mph is \(1.27\) .

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Answer:

(a). The speed at the moment of being thrown is 30.41 m/s.

(b). The maximum height is 47.18 m.

Explanation:

Given that,

Weight of stone = 3.00 N

Height = 15 m

Speed = 25.0 m/s

(a). We need to calculate the speed at the moment of being thrown

Using work energy theorem

\(W=\dfrac{1}{2}m(v_{2}^2-v_{1}^2)\)

\(-mg\times d=\dfrac{1}{2}m(v_{2}^2-v_{1}^2)\)

Put the value into the formula

\(-9.8\times15=\dfrac{1}{2}\times(v_{2}^2-v_{1}^2)\)

\(-2\times9.8\times15=25^2-v_{1}^2\)

\(-v_{1}^2=-300-25^2\)

\(v_{1}=\sqrt{925}\)

\(v_{1}=30.41\ m/s\)

(b). We need to calculate the maximum height

Using work energy theorem

\(\(W=\dfrac{1}{2}mv_{2}^2-\dfrac{1}{2}mv_{1}^2\)

\(mg\times d=\dfrac{1}{2}mv_{2}^2-\dfrac{1}{2}mv_{1}^2\)

Here, \(\dfrac{1}{2}mv_{2}^2\)=0

\(-(mg)\times d=\dfrac{1}{2}mv_{1}^2\)

\(d=\dfrac{v_{1}^2}{2g}\)

Put the value into the formula

\(d=\dfrac{30.41^2}{2\times9.8}\)

\(d=47.18\ m\)

Hence, (a). The speed at the moment of being thrown is 30.41 m/s.

(b). The maximum height is 47.18 m.

Answer:

ΔV = 1139.3 V = 1.139 KV (+ve sign shows V goes up)

Explanation:

The potential difference while moving from point A to Point B is given as follows:

\(\Delta V = V_B-V_A\)

where,

ΔV = potential difference from A to B = ?

\(V_A\) = Potential at point A = \(\frac{kq}{r_A}\)

\(V_B\) = Potential at point B = \(\frac{kq}{r_B}\)

Therefore,

\(\Delta V = \frac{kq}{r_B}-\frac{kq}{r_A}\\\\\Delta V = kq(\frac{1}{r_B}-\frac{1}{r_A})\)

where,

k = Colomb's Constant = 9 x 10⁹ N.m²/C²

q = magnitude of charge = 4.88 x 10⁻⁸ C

\(r_A\) = distance of point A from charge = 1.36 m

\(r_B\) = distance of point B from charge = 0.538 m

Therefore,

\(\Delta V = (9\ x\ 10^9\ N.m^2/C^2)(4.88\ x\ 10^{-8}\ C)(\frac{1}{0.538\ m}-\frac{1}{1.36\ m})\\\\\Delta V = (439.2 N.m^2/C)(2.59\ /m)\)

ΔV = 1139.3 V = 1.139 KV (+ve sign shows V goes up)

The answer is 492.87.

Correct on Acellus

Answer:

the vertical velocity is constant.

Explanation:

The horizontal velocity of a projectile is constant (a never changing in value), There is a vertical acceleration caused by gravity; thus, the vertical velocity of a projectile changes. and the horizontal motion of a projectile is independent of its vertical motion.

The statement that is true regarding two objects with equal momentum is as follows: the more massive object will have less velocity (option A).

Momentum is the tendency of a body to maintain its inertial motion. It is the product of an object's mass and velocity, or the vector sum of the products of its masses and velocities.

Mass and velocity are both directly proportional to the momentum. This means that if one increases either mass or velocity, the momentum of the object increases proportionally.

According to this question, two objects have equal momentum. This suggests that the objects with the greater mass must have a lesser velocity and vice versa.

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Answer:

Explanation:

frequency  of first body   f₁  = 2 / T  where T is time taken by it for making two orbits

frequency of second body   f₂  = 3 / T

ration of two frequency

f₁ / f₂ = 2 / 3

This ratio is called perfect fifth in musical interval .

Answer:

The particles 'take part' in the wave by bumping into one another and transferring energy. This is why energy can be transferred, even though the average position of the particles doesn't change.

Explanation:

Answer:

31.15%

Explanation:

The formula used was

((Work output)/(Work input))×100

Answer:

C.  31.1 percent

Answer:

800N

Explanation:

as we know that

weight = mass × acceleration due to gravity

= 80kg × 10 m/s^2

= 800N.

The magnitude of this magnetic field would need to be 15.17 tesla in order to exert a force of magnitude 6.16 newtons on a 0.864 meter length of this wire.

The magnitude of this magnetic field can be found by using the equation F = ILBsinθ, where F is the force, I is the current, L is the length of the wire, B is the magnitude of the magnetic field, and θ is the angle between the wire and the magnetic field. Rearranging the equation to solve for B gives us:

B = F / (ILsinθ)

Plugging in the given values gives us:

B = 6.16 N / (0.504 A × 0.864 m × sin(71.7°))

B = 6.16 N / (0.504 A × 0.864 m × 0.944)

B = 15.17 T

Therefore, the magnitude of this magnetic field would need to be 15.17 tesla in order to exert a force of magnitude 6.16 newtons on a 0.864 meter length of this wire.

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A baseball player standing at the edge of a vertical cliff throws a baseball initially in the horizontal direction four times with four different horizontal speeds. Which of the following statements is true in regards to the time of flight?The time of flight is the same for all four baseballs.

The statement, "The time of flight is the same for all four baseballs" is true regarding the time of flight in regards to the four baseballs that the baseball player throws initially in the horizontal direction from the edge of the vertical cliff. This is because the only factor that affects the time of flight is the vertical velocity. Since there was no vertical velocity, the time of flight will remain the same.

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Answer:

Air at higher altitude is under less pressure than air at lower altitude because there is less weight of air above it, so it expands (and cools), while air at lower altitude is under more pressure so it contracts (and heats up).

Explanation:

Hope that helped

To determine the capacitance needed for resonance in a series RLC circuit, we can use the formula:

f = 1 / (2π√(LC))

where:

f = resonance frequency

L = inductance

C = capacitance

In this case, the resonance frequency is given as 1070 Hz and the inductance is given as 13.0 mH. We need to calculate the capacitance (C) that will result in this resonance frequency.

First, convert the inductance to henries (H):

L = 13.0 mH = 13.0 x 10^-3 H

Rearranging the formula, we have:

C = 1 / (4π^2f^2L)

Plugging in the values:

C = 1 / (4π^2 * (1070 Hz)^2 * 13.0 x 10^-3 H)

Calculating the expression, we find:

C ≈ 1.199 x 10^-8 F

Therefore, the capacitance needed for resonance in the series RLC circuit is approximately 11.99 nF.

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The ideal gas constant for air, denoted as R, has a value of 287 J/(kg·K). It is a constant used in gas laws to relate the properties of air to temperature, pressure, and volume.

In this problem, air is modeled as an ideal gas. We are given the following information:

- Inlet conditions: Temperature (T₁) = 270 K, Velocity (V₁) = 180 m/s

- Outlet conditions: Velocity (V₂) = 48.4 m/s

Since the diffuser is well-insulated, we can assume negligible heat transfer (Q) and potential energy effects. Therefore, the process can be considered adiabatic and isentropic.

In an adiabatic and isentropic process, the total energy per unit mass remains constant. Therefore, we can use the stagnation properties (denoted by a subscript "0") to analyze the process.

The stagnation temperature (T₀) is the temperature that the gas would reach if it were brought to rest isentropically. The stagnation temperature is related to the static temperature and velocity by the equation: T₀ = T + (V² / (2·Cp)), where Cp is the specific heat at constant pressure.

Since the process is isentropic, the ratio of specific heats (γ) remains constant. For air, γ ≈ 1.4.

Using the stagnation temperature equation, we can calculate the stagnation temperature at the inlet and outlet:

T₀₁ = T₁ + (V₁² / (2·Cp))

T₀₂ = T₂ + (V₂² / (2·Cp))

Since the process is adiabatic, the stagnation temperature remains constant throughout the diffuser: T₀₁ = T₀₂

By equating the expressions for T₀₁ and T₀₂ and rearranging the terms, we can solve for Cp:

T₁ + (V₁² / (2·Cp)) = T₂ + (V₂² / (2·Cp))

Simplifying the equation and solving for Cp, we get:

Cp = (V₁² - V₂²) / (2·(T₂ - T₁))

Finally, using the ideal gas equation: Cp - Cv = R, where Cv is the specific heat at constant volume, and Cp = γ·Cv, we can substitute Cp with γ·Cv and rearrange the equation to solve for R:

R = Cp - Cv

R = γ·Cv - Cv

R = (γ - 1)·Cv

For air, the value of γ is approximately 1.4. Therefore, we can calculate R as follows:

R = (1.4 - 1)·Cv

The specific heat at constant volume (Cv) for air is approximately 717 J/(kg·K). Substituting this value into the equation, we find:

R = (1.4 - 1)·717 J/(kg·K)

R ≈ 287 J/(kg·K)

Hence, the ideal gas constant for air is approximately 287 J/(kg·K).

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Answer:

2.54 m/s

Explanation:

By conservation of energy,

work done by force due to hand = mechanical energy gained by yo-yo

So Fd = mgh + 1/2m(v₂² - v₁²)

where F = force on string = 0.19 N, d = distance moved by hand = 0.12 m, m = mass of yo-yo = 0.058 kg, g = acceleration due to gravity = 9.8 m/s², h = distance moved by yo-yo = 0.30 m, v₁ = initial speed of yo-yo = 3.4 m/s and v₂ = final speed of yo-yo = unknown

So,  Fd = mgh + 1/2m(v₂² - v₁²)

Fd/m = gh + 1/2(v₂² - v₁²)

Fd/m - gh = 1/2(v₂² - v₁²)

2(Fd/m - gh) = (v₂² - v₁²)

(v₂² - v₁²) = 2(Fd/m - gh)

v₂²  = v₁² + 2(Fd/m - gh)

taking square-root of both sides, we have

v₂  = √[v₁² + 2(Fd/m - gh)]

Substituting the values of the variables into the equation, we have

v₂  = √[(3.4 m/s)² + 2(0.19 N × 0.12 m/0.058 kg - 9.8 m/s² × 0.30 m)]

v₂  = √[(3.4 m/s)² + 2(0.19 N × 0.12 m/0.058 kg - 9.8 m/s² × 0.30 m)]

v₂  = √[(3.4 m/s)² + 2(0.0228 Nm/0.058 kg - 9.8 m/s² × 0.30 m)]

v₂  = √[(3.4 m/s)² + 2(0.393 Nm/kg - 2.94 m²/s²)]

v₂  = √[(3.4 m/s)² + 2(-2.547 m²/s²)]

v₂  = √[11.56 m²/s² - 5.094 m²/s²)]

v₂  = √[6.466 m²/s²]

v₂ = 2.54 m/s