explain about ohm's law.​

Answers

Answer 1

Answer:

Statement:

The electric current passing through a conductor is directly proportional to the potential difference across its ends provided temperature and other physical conditions remain constant.

Explanation:

Current is directly proportional to voltage loss through a resistor. That is, if the current doubles, then so does the voltage. To make a current flow through a resistance there must be a voltage across that resistance. Ohm's Law shows the relationship between the voltage (V), current (I) and resistance (R).

V∝I or I∝V⇒V=IR.

Answer 2

Explanation:

Ohm's law states that the current through a conductor is proportional to the voltage across the conductor. This is true for many materials (including metals) provided the temperature (and other physical factors) remain constant. The constant of proportionality, R,R is the resistance and the unit is the ohm, with symbol \Omega,Ω. The relationship can be written as:

V, equals, I, R.

V=IR

where V,V is the voltage across the conductor and I,I is the current flowing through it. If a component is ohmic (it obeys Ohm's Law), then its resistance must be independent of current and voltage.


Related Questions

in scenario a, visible light has a wavelength of 709.4 nm.709.4 nm. determine its frequency, energy per photon, and color.

Answers

The frequency of the visible light is approximately 4.231 x 10^14 Hz, the energy per photon is approximately 2.803 x 10^-19 J, and the color is red.

To determine the frequency of visible light with a wavelength of 709.4 nm, you can use the equation:

c = λ * ν

where c is the speed of light (approximately 3.00 x 10^8 m/s), λ is the wavelength in meters, and ν is the frequency in hertz (Hz).

First, convert the wavelength from nanometers (nm) to meters (m):

709.4 nm = 709.4 x 10^-9 m

Now, substitute the values into the equation:

3.00 x 10^8 m/s = (709.4 x 10^-9 m) * ν

Solve for ν:

ν = (3.00 x 10^8 m/s) / (709.4 x 10^-9 m)

ν ≈ 4.231 x 10^14 Hz

Next, to determine the energy per photon, you can use the equation:

E = h * ν

where E is the energy per photon in joules (J) and h is Planck's constant (approximately 6.626 x 10^-34 J·s).

Substitute the values into the equation:

E = (6.626 x 10^-34 J·s) * (4.231 x 10^14 Hz)

E ≈ 2.803 x 10^-19 J

Finally, to determine the color of the visible light, you can refer to the electromagnetic spectrum. Visible light with a wavelength of 709.4 nm falls within the red portion of the spectrum.

Therefore, the frequency of the visible light is approximately 4.231 x 10^14 Hz, the energy per photon is approximately 2.803 x 10^-19 J, and the color is red.

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what is the value of sin square 60​

Answers

\( \sin(60 ) {}^{2} = \frac{3}{4} \)

Explanation:

\( \sin(60) = \frac{ \sqrt{3} }{2} \\ \\ \sin(60 ) {}^{2} = ( \frac{ \sqrt{3} }{2} ) {}^{2} \\ \\ \sin(60 ) {}^{2} = \frac{3}{4} \)

What is the net force acting upon this object? *

3N : to the left
5 N : to the right
Answers to choose from:
2 N Right
BN
2 N Left
5 N Right

Answers

2 N Right

.. .. .. .. .. .. .. ..

Answer:

2 N Right

Explanation:

Net force = 5 - 3

= 2 N to the Right

A device that is capable of moving atoms and molecules with a laser beam is calleda a push laserb. an optical tweezerc. an atom smasherd. a laser scalpel

Answers

A device that is capable of moving atoms and molecules with a laser beam is called an optical tweezer. The correct option is B)

This technology was first introduced by Arthur Ashkin in 1986 and has since revolutionized the field of physics and biology. Optical tweezers use the force of light to trap and manipulate small particles, such as individual atoms and molecules. The laser beam creates a gradient of light intensity, which generates a force that can move and hold particles in place.

This technique has a wide range of applications, including the study of cell mechanics, protein folding, and the assembly of nanostructures. Optical tweezers have also been used in the development of micro-machines, sensors, and other advanced technologies. This device is not to be confused with an atom smasher, which is used to accelerate subatomic particles to high speeds, or a laser scalpel, which is used for precise surgical procedures.

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based on the data collected and the hypothesis, what happens to the diffraction angle when the wavelength is increased?

Answers

The wavelength will be longer, increasing the diffraction angle.

Define the wavelength?

The separation between two successive wave crests or troughs is known as a wavelength.

Here are some wavelength illustrations: Yellow Light, for instance. All visible light has a wavelength between 400 and 700 nanometers (nm).

Radio waves, light waves, and infrared (heat) waves are examples of electromagnetic radiation that flow through space in distinct patterns.

The symbol for the wavelength in the SI is often the letter m. Additionally, multiples or fractions of a metre are employed when calculating wavelength. The use of exponential powers of 10 is noteworthy when wavelengths are a significant feature.

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Answer:

Simple Response: The diffraction angle of the waves is approximately equal to the wavelength divided by the gap width. Therefore, increasing the wavelength will increase the diffraction angle.

Explanation:

a particle in uniform circular motion has a period of 4.0 seconds. what is the particle's frequency?

Answers

The frequency of a particle in uniform circular motion is determined by dividing the number 1 by the particle's period. In this case, the particle's period is 4.0 seconds, so the frequency can be calculated by dividing 1 by 4.0, resulting in a frequency of 0.25 Hz. It is important to note that the unit of frequency is Hertz (Hz), which represents the number of cycles per second.

A common example of uniform circular motion is a planet orbiting around the sun. The period of a planet's orbit is determined by its distance from the sun and the force of gravity acting upon it.

if 20.0 kj of heat are given off when 2.0 g of condenses from vapor to liquid, what is for this substance?

Answers

a)  ΔHvap for this substance is: -10000 J/mol or -10.00 kJ/mol

b) The molar heat of vaporization for this substance is: 5000 J/mol or 5.00 kJ/mol

c) The substance is: Water.

a) The amount of heat released is given as 20.0 kJ, and the mass of the substance is 2.0 g.

To find ΔHvap, we need to convert the mass of the substance to moles by dividing it by its molar mass, and then use the equation: ΔH = q/moles.

The molar mass of water is 18.02 g/mol, so the number of moles is 2.0 g / 18.02 g/mol = 0.111 mol.

Therefore, ΔHvap = -20.0 kJ / 0.111 mol = -10000 J/mol or -10.00 kJ/mol.

b) The molar heat of vaporization is defined as the amount of heat required to vaporize one mole of a substance.

Since we know ΔHvap for this substance is -10.00 kJ/mol, the molar heat of vaporization is +10.00 kJ/mol.

c) The values obtained for ΔHvap and the molar heat of vaporization are consistent with water, indicating that the substance in question is water.

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The given question is incomplete, so an complete question is written below,

As the question is missing an important part, all the important possibilities which can fill the gap is written below,

a) What is ΔHvap for this substance?

b) What is the molar heat of vaporization for this substance?

c) What is the substance?

is retractable measuring tape a simple machine?

Answers

Answer:

A simple machine is a device that multiply an applied force by the use of the mechanical advantage built into the machine. Therefore, a simple machine changes the direction in which the applied force acts or the magnitude of the applied force, or both in order to do work

A retractable measuring tape is a device used for length measurement such that the direction of the applied force is reversed during retraction, while the magnitude of the output force is constant and dependent on the coil in the measuring

Therefore, the measuring tape does not have a constant mechanical advantage or act as a force multiplier, and therefore;

It is not a simple machine

Explanation:

The angular size of Venus has a maximum value of 55" during "inferior conjunction," when it is 0.3AU from Earth (Venus is 0.7AU from Sun). It’s orbital eccentricity is 0.007

Calculate the Diameter (physical size) of Venus.

Answers

The diameter of Venus can be calculated using the angular size at inferior conjunction and its orbital parameters. With an angular size of 55" and a distance of 0.3 AU from Earth, the physical size of Venus can be determined.

The angular size of an object is the angle it subtends at the observer's location. In this case, the maximum angular size of Venus is given as 55" (arcseconds) during inferior conjunction. Inferior conjunction occurs when Venus is positioned between Earth and the Sun, and its distance from Earth is 0.3 AU (astronomical units). Venus is also stated to be 0.7 AU from the Sun.

To calculate the physical size of Venus, we can use the small-angle formula, which relates the angular size, distance, and physical size of an object. The formula is given by:

Angular size (in radians) = Physical size / Distance

Since the angular size is usually measured in arcseconds, it needs to be converted to radians. One radian is equal to 206,265 arcseconds.

Converting the given angular size of 55" to radians:

Angular size (in radians) = 55" / 206,265 ≈ 0.000266 radians

Using the small-angle formula, we can rearrange it to solve for the physical size:

Physical size = Distance × Angular size

Substituting the values, where the distance is 0.3 AU:

Physical size = 0.3 AU × 0.000266 radians ≈ 0.00008 AU

Finally, to convert the physical size from astronomical units to kilometers, we can use the conversion factor of 1 AU = 149.6 million kilometers:

Physical size = 0.00008 AU × 149.6 million kilometers/AU ≈ 12,000 kilometers

Therefore, the diameter (physical size) of Venus is estimated to be approximately 12,000 kilometers.

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A 1400 kg car traveling at 17.0 m/s to the south collides with a 4700 kg truck that is at rest. The car and truck stick together and move together after collision. What is the final velocity of the two-vehicle mass? If Kinetic Energy = 0.5 * m * v^2, calculate the KE before the crash and the KE of the combined vehicles after the crash.

Answers

Answer:

Final velocity = 7.677 m/s

KE before crash = 202300 J

KE after crash = 182,702.62 J

Explanation:

We are given;

m1 = 1400 kg

m2 = 4700 kg

u1 = 17 m/s

u2 = 0 m/s

Using formula for inelastic collision, we have;

m1•u1 + m2•u2 = (m1 + m2)v

Where v is final velocity after collision.

Plugging in the relevant values;

(1400 × 17) + (4700 × 0) = (1400 + 1700)v

23800 = 3100v

v = 23800/3100

v = 7.677 m/s

Kinetic energy before crash = ½ × 1400 × 17² = 202300 J

Kinetic energy after crash = ½(1400 + 1700) × 7.677² = 182,702.62 J

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A 15kg block is being pushed up a 20 degrees ramp that has a kinetic coefficient of 0.30. What is the pushing force if the acceleration of the block is 2.0m/s^2?

The answer is 121.7 N, I just need to know how to solve it.

Answers

Answer:

this is just and example of how to solve it

Explanation:

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PLEASE HELP WILL MARK BRAINLIEST IF YOU EXPLAIN HOW TOU GOT THE ANSWER!!!A 15kg block is being pushed

what is the force on a body if the mass of the body is 2300g? (acceleration due to = 9.8ms-1) ​

Answers

Hello jamaicandoll!

\( \huge \boxed{\mathfrak{Question} \downarrow}\)

What is the force on a body if the mass of the body is 2300g? (acceleration due to gravity = - 9.8m/s²) .

\( \huge \boxed{\mathfrak{Answer} \downarrow}\)

Given,

Mass (m) = 2300 g = 2.3 kgAcceleration (a) = -9.8 m/s²Force (F) = ?

We know that, force = mass × acceleration.

So,

F = ma

F = 2.3 × -9.8

F = \(\boxed{\underline{\bf \: -22.54\:N}}\)

__________________

Hope it'll help you!

ℓu¢αzz ッ

How
fast does this station say the wind is blowing?
How fast does this station say the wind is blowing? 61 cvs

Answers

The given information says that the wind is blowing at 61 cvs. Therefore, the speed of the wind blowing is 61 cvs.

Wind speed is usually measured in miles per hour (mph), kilometers per hour (km/h), meters per second (m/s), or knots (nautical miles per hour, abbreviated kt or kts). To find the speed of the wind, these measurements use different mathematical formulas and conversion factors.It is stated in the given question that the wind speed is 61 cvs. However, this unit of wind speed is not commonly used, as it is not a standard unit of wind speed measurement.

The speed of the wind is an essential factor in predicting weather conditions and determining their potential impact on people, structures, and the environment. Wind speed is typically measured in units such as miles per hour (mph), kilometers per hour (km/h), meters per second (m/s), and knots. According to the given information, the wind speed is 61 cvs. This unit of wind speed is not widely used, as it is not a standard unit of wind speed measurement. To determine the wind speed, it is necessary to employ various mathematical formulas and conversion factors that differ depending on the unit of measurement used.

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The star Betelgeuse is 6.1 x 10^18 m away from Earth. How old is the light we see from that star when it reaches us? There are 3.2 x 10^7 seconds in a year (1 point)

635 years old

481 years old

727 years old

559 years old

Answers

Answer:

635 years old

Explanation:

The light reaching the earth from the sun will travel at a speed called the speed of light, and this has a universal value of 3 × 10⁸ m/s. Bearing this in mind, let us calculate the age of the light reaching the Earth from the sun:

Distance of star from Earth = 6.1 × 10⁸m

Speed of light = 3 × 10⁸ m/s

We have distance and speed, let us calculate the time of travel of the light from the star to the earth.

Distance = speed × time

6.1 × 10⁸ = 3 × 10⁸ × time

\(time = \frac{6.1 \times 10^{18}}{3 \times 10^8}\)

In order to do the division above, we will divide the whole numbers normally, then we will apply the law of indices to the power that says:

Xᵃ ÷ Xᵇ = X⁽ᵃ⁻ᵇ⁾

\(\therefore time = \frac{6.1 \times 10^{18}}{3 \times 10^8}\\= \frac{2.03 \times 10^{(18-8)}}{1} \\= 2.03 \times 10^{10}}\ seconds\)

Next, we are told that there are 3.2 × 10⁷ seconds in a year.

∴ The number of years travelled by the light from the star:

\(3.2\ \times 10^7\ seconds = 1\ year\\1\ second = \frac{1}{3.2\ \times 10^7} \\\therefore 2.03 \times 10^{10}\ seconds = \frac{2.03 \times 10^{10}}{3.2\ \times 10^7}\)

please note that:

2.03 × 10¹⁰ = 20300000000

3.2 × 10⁷ = 32000000

\(\therefore \frac{2.03 \times 10^{10}}{3.2\ \times 10^7}\\= \frac{20300000000}{32000000} \\\\= \frac{20300}{32} \\= 634.347\ years\\\)

The closest answer in the option is 635 years, and we are short of this by some points due probably to approximations in the calculation.

The coordinates of an object moving in the xy plane Q/C vary with time according to the equations x 5 25.00 sin vt and y 5 4.00 2 5.00 cos vt, where v is a constant, x and y are in meters, and t is in seconds. (a) Determine the components of velocity of the object at t 5 0. (b) Determine the components of acceleration of the object at t 5 0. (c) Write expres- sions for the position vector, the velocity vector, and the acceleration vector of the object at any time t. (d) Describe the path of the object in an xy plot.

Answers

The object's position in the xy plane is described by the equations \(x = 25.00 sin(vt)\) and \(y = 4.00 + 5.00 cos(vt)\), where v is a constant. At t = 0, the components of velocity and acceleration can be determined. Expressions for the position, velocity, and acceleration vectors at any time t can also be derived. The path of the object can be described by plotting its x and y coordinates on an xy graph.

(a) To determine the components of velocity at t = 0, we need to find the derivatives of x and y with respect to time (t). Taking the derivatives, we get the velocity components as follows:

\(Vx = dx/dt = v * 25.00 cos(vt) = 25.00v\)

\(Vy = dy/dt = -v * 5.00 sin(vt) = -5.00v\)

(b) To find the components of acceleration at t = 0, we differentiate the velocity components with respect to time:

\(Ax = dVx/dt = 0\)(since Vx is constant)

\(Ay = dVy/dt = -v^2 * 5.00 cos(vt) = -5.00v^2\)

(c) The position vector r(t) is given by \(r(t) = x(t)i + y(t)j\), where i and j are unit vectors in the x and y directions, respectively. The velocity vector V(t) is given by \(V(t) = Vx(t)i + Vy(t)j\), and the acceleration vector A(t) is given by \(A(t) = Ax(t)i + Ay(t)j\).

(d) The path of the object can be determined by plotting its x and y coordinates on an xy graph. The equation \(x = 25.00 sin(vt)\) represents oscillatory motion along the x-axis, while the equation \(y = 4.00 + 5.00 cos(vt)\) represents oscillatory motion along the y-axis. Combining these motions, the object follows a curved path in the xy plane. The specific shape of the path depends on the value of the constant v.

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- A spherical spacecraft is placed in a polar coordinate in Low Earth Orbit (LEO). The orbit altitude is around 240 km. The spacecraft is coated with a black paint finish. Using the given information, determine the spacecraft's equilibrium temperature:

- Given
- Sun's solar radiation intensity, J S =1371 W/m 2 (average value at 1AU distance)
- Earth's planetary radiation intensity, J p​ =237 W/m 2 (ignoring orbital altitude effects)
- Earth's albedo, a = 0.33
- Visibility factor, F=0.15
- Stefan-Boltzmann's constant, σ=5.67.10 −8W/m 2K 2
- Black paint properties: α=0.9,ε=0.9

Answers

The spacecraft's equilibrium temperature is determined by ((1 - α) × Jₛ × F / (ε × σ))^(1/4) using the given values.

To determine the spacecraft's equilibrium temperature, we need to consider the balance between the incoming solar radiation and the outgoing planetary radiation.

The incoming solar radiation can be calculated using the solar radiation intensity (Jₛ) and the visibility factor (F). The solar radiation reaching the spacecraft can be given by Jₛ × F.

The outgoing planetary radiation consists of two components: the radiation emitted by the Earth and the radiation reflected by the Earth's albedo. The total outgoing planetary radiation can be calculated as Jp + a × Jₛ, where Jp is the Earth's planetary radiation intensity and a is the Earth's albedo.

Now, let's calculate the equilibrium temperature using the Stefan-Boltzmann law, which states that the power radiated by a black body is proportional to the fourth power of its temperature.

Let T be the equilibrium temperature of the spacecraft.

The power radiated by the spacecraft can be calculated as ε × σ × A × T^4, where ε is the emissivity of the spacecraft (given as 0.9), σ is the Stefan-Boltzmann constant, and A is the surface area of the spacecraft.

The power absorbed by the spacecraft can be calculated as (1 - α) × Jₛ × F × A, where α is the absorptivity of the spacecraft (given as 0.9).

Setting the absorbed power equal to the radiated power, we have:

(1 - α) × Jₛ × F × A = ε × σ × A × T^4

Simplifying and solving for T, we get:

T^4 = ((1 - α) × Jₛ × F) / (ε × σ)

T = ((1 - α) × Jₛ × F / (ε × σ))^(1/4)

Substituting the given values, we can calculate the equilibrium temperature of the spacecraft using the formula above.

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When you push a box with 20 N of force, what force does the box apply back on you?

Answers

Remember Newton’s third law: for every force, there is an equal and opposite reaction.

The force being applied back is also 20N

when you are on the top floor of a building, your weight is how large compared to when you are on the ground floor?

Answers

When you are on the top floor of a building, your weight is the same as when you are on the ground floor.

What is weight?

The weight of an object is the measure of the force of gravity acting on the object. The weight of an object is proportional to its mass and the acceleration due to gravity acting on it. The mass of an object is the measure of the amount of matter it contains. The mass of an object is constant, whereas its weight varies with the acceleration due to gravity acting on it.

Since the acceleration due to gravity acting on an object near the surface of the Earth is almost constant, the weight of an object on the ground floor of a building is the same as its weight on the top floor of the same building. In other words, the weight of an object does not change with height as long as the object is at rest or moving with a constant velocity.

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Light travels through air and is incident upon the surface of a diamond at angle of 30 degrees. If the index of refraction for a diamond is 2.42. Calculate angle of refraction as the light travels into the diamond.

Answers

As light enters the diamond, it is refracted at an angle of 12.3 degrees.

Definition of refractive index Diamond has a refractive index of 2.42. What does this statement actually mean?

According to the aforementioned assertion, the speed of light in a diamond is 1.42 times that of light in a vacuum. The speed of light in a diamond will be 2.42 times slower than it is in air due to the high refractive index of diamonds.

\(heta2 = 12.3 degrees\)

When we simplify the equation, we obtain:

\((1/2.42) x Sin(30) = Sin(theta2)\)

\(Theta2 sin(2) = 0.208\)

When we take the inverse sine of both sides, we obtain:

\(12.3 degree theta2\)

Using both sides' inverse sine,

\(theta2 = 12.3 degrees\)

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A spherical balloon is inflating with helium at a rate of 192 pi ft^3/min. How fast is the balloon's radius increasing at the instant the radius is 4 ft? The balloon's radius is increasing at a rate of ft/min at the instant the radius is 4 ft. (Simplify your answer.)

Answers

The balloon's radius is increasing at a rate of 3ft/min at the instant the radius is 4 ft.

Given: A spherical balloon is inflating with helium at a rate of 192π ft³/min.

We have to find how fast the balloon's radius is increasing at the instant the radius is 4 ft.

The formula for volume of a sphere is given as:V = 4/3πr³

Differentiate with respect to time t on both sides,dV/dt = 4πr²(dr/dt)

Given, dV/dt = 192π ft³/min and r = 4ftSo,192π = 4π(4²)(dr/dt)dr/dt = 192/(4²) = 3 ft/min

Therefore, the balloon's radius is increasing at a rate of 3ft/min at the instant the radius is 4 ft.

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A point charge of magnitude 2q exerts an electrostatic force of magnitude F on a point charge of magnitude q that is a distance R away. What is the magnitude of the force that the 29 point charge exerts on a point charge of magnitude 3 that is a distance r/5 away?

Answers

The magnitude of the force that the 2q point charge exerts on the 3 point charge is 6F.

The force between two point charges is given by Coulomb's law:

F = k * (q₁ * q₂) / r²

where:

F is the force in newtons

k is Coulomb's constant, which is 8.988 * 10⁹ N m² / C²

q₁ and q₂ are the charges in coulombs

r is the distance between the charges in meters

In this problem, we know that:

q₁ = 2q

q₂ = 3

r = R/5

Plugging these values into the equation for Coulomb's law, we get:

F = 8.988 * 10⁹ N m² / C² * (2q * 3) / (R/5)²

F = 6F

Therefore, the magnitude of the force that the 2q point charge exerts on the 3 point charge is 6F.

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What are all the principles of Cell Theory. Group of answer choices Cell only form from living cells All cells have chromosomes All living things have cells All cells have a nucleus People only have cells Cells are the basic unit of life

Answers

Answer:

Cell theory is the scientific theory that states that all living things are composed of cells and that cells are the basic unit of life. The three principles of cell theory are the cell is the smallest unit of life, all cells come from preexisting cells, and cells are the basic unit of function in living things.

Explanation:

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Stocks a, b and c have betas of 1.5, 0.4, and 0.9 respectively. what is the beta of an equally weighted portfolio of a, b and c?

Answers

the beta of the equally weighted portfolio of stocks a, b, and c is approximately 0.933.

To calculate the beta of an equally weighted portfolio of stocks a, b, and c, you need to find the weighted average of their betas. The beta of an equally weighted portfolio is calculated by taking the average of the betas of the individual stocks.

In this case, the beta of stock a is 1.5, the beta of stock b is 0.4, and the beta of stock c is 0.9.

To find the beta of the equally weighted portfolio, you would add up the betas of the individual stocks and divide by the number of stocks. So, (1.5 + 0.4 + 0.9) / 3 = 2.8 / 3 = 0.933.

Therefore, the beta of the equally weighted portfolio of stocks a, b, and c is approximately 0.933.

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the thermodynamic processes that occur in nature ____________.

Answers

Answer:

The thermodynamic processes that occur in nature convert thermal energy into mechanical energy.

The thermodynamic processes that occur in nature are according to the law of thermodynamics.

The thermodynamics processes seen in nature are guided by the law of thermodynamics. The role of energy and heat transmission in physical systems is guided by these laws.

The laws are:

(1) Energy cannot be created nor destroyed in a system, according to the first law of thermodynamics, Also, referred to as the law of energy conservation. Only from one form to another, the energy can be transmitted or altered. Energy is conserved through natural processes, keeping the overall amount constant.

(2) Second law of thermodynamics: states that the overall entropy of an isolated system tends to increase over time in any natural process. This suggests that processes progress towards a state of increasing disorder.

Hence, the thermodynamic processes are guided by the law of thermodynamics.

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Energy is the energy an object has because of its motion. True or False

Answers

That depends on what word you skipped at the beginning of the question.

If it's supposed to be "Potential" energy, then the statement is false.**

If It's supposed to be "Kinetic" energy, then the statement is true.

** It's also false if the missing word is "Chemical", "Mechanical", "Thermal", "Nuclear", "Electrical", "Electromagnetic", or "Nervous".)

Which of these equations will you used to find the final velocity if the initial
velocity and time is given? *

Which of these equations will you used to find the final velocity if the initialvelocity and time is

Answers

Answer:

2.77 would be the answer for this

A bowling ball is traveling at 3 m/s. It starts to roll up a ramp. How high above the ground will the ball be when it stops rolling? Neglect friction and assume the ramp is plenty long enough to do this. (For this problem your initial kinetic energy can be set equal to your final potential energy. 1/2mv2 = mgh).

Answers

Answer:

h= 0.45 m

Explanation:

PE= 1/2 mv^2             KE= mgh

v= 3m/s

vf= 0 m/s

h=?

PE= 1/2(1kg)(3m/s)^2

PE= 4.5 J

4.5 J/ 1kg(9.8 m/s^2)

h=0.45 m

The height of the ball above the ground when it stops is 0.46 m.

The initial kinetic energy of the ball is equal to the final potential energy of the ball.

⇒ Formula:

mv²/2 = mghv² = 2gh............... Equation 1

⇒ Where:

v = velocity of the ballh = height of the ball above the groundg = acceleration due to gravity.

⇒ make h the subject of the equation

h = v²/2g.............. Equation 2

From the question,

⇒ Given:

v = 3 m/sg = 9.8 m/s²

⇒ Substitute these values into equation 2

h = 3²/(2×9.8)h = 9/19.6h = 0.46 m

Hence, the height of the ball above the ground when it stops is 0.46 m.

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An organized way to collect and record scientific observations is with a(n)
a. model.
b. inference.
C. data table.
d. experiment.
Please select the best answer from the choices provided
O A
ABCO
OD

Answers

An organized way to collect and record scientific observations is with a data table (option C).

What is an experiment?

An experiment is a test under controlled conditions made to either demonstrate a known truth, examine the validity of a hypothesis, or determine the efficacy of something previously untried.

The scientific method involves the collection of data and organizing them in a way that they can be easily interpreted.

However, the best way to collect and record scientific observations is with the aid of a data table.

A data table is any display of information in tabular form, with rows and/or columns named.

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#SPJ1

Calculate the distance the gecko covers when sprinting from rest to 2 m/s in a time of 1.5 s.

I got the answer D = 1.49 m, but i think I may have done something wrong or misinterpreted it.

Thank you!

Answers

Answer:

1.5 m

Explanation:

a = v/t

a = 2/1,5 = 4/3

x = 1/2 a t² + vt + x

x = 1/2 × 4/3 × 9/4 = 3/2 =1.5 m

Distance - 300kms
Time = 1hr 40min
Average Velocity = ?
NEED ASAP!!!!!

Answers

Answer:

3kms  per minute

Explanation:

You divide the distance to the time.

Answer:

3 kilometers a minute

Explanation:

im not sure but i hope it helps

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