even or odd or neither

Answer:

12

This is the answer because 2/3 times 18 is 12...

Answer: 12

Step-by-step explanation:

2/3 * 18

you put 18 over 1

so 2/3 * 18/1

2*18= 36

3*1= 3

36/3 = 12

Answer:

1710

Step-by-step explanation:

GPA = 3,1 +- 0,6

0,6 = 2*STDEV

As it is a normal distribution, the interval (Mean +- 2*STDEV) includes 95% of the students.

1800 * 0,95 = 1710

The mean absolute deviation (MAD) and mean absolute percent error (MAPE) are both measures used to assess the accuracy or variability of a dataset. However, they differ in terms of the type of data they analyze and the way they express the deviation.

Mean Absolute Deviation (MAD):

MAD measures the average absolute difference between each data point and the mean of the dataset.

It provides information about the dispersion or spread of the data.

MAD is calculated by taking the absolute value of the differences between each data point and the mean, summing these values, and then dividing by the total number of data points.

MAD is expressed in the same units as the original data.

Mean Absolute Percent Error (MAPE):

MAPE measures the average percentage difference between each data point and its corresponding value in a reference dataset (often a forecast or predicted value).

It provides information about the relative error or accuracy of a model or prediction.

MAPE is calculated by taking the absolute value of the percentage difference between each data point and its corresponding reference value, summing these values, and then dividing by the total number of data points.

MAPE is expressed as a percentage.

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Answer:

Option D

Step-by-step explanation:

Given polynomial :-

=> 2x - 4x³ -7 + 6x²

Here the highest degree of variable is 3 ,

Therefore it is a cubic polynomial .

Answer:

it is 8

Step-by-step explanation:

Answer:I just got 8 and 64 thats all I got not sure if its gonna be correct for the 64 but for 8 I'm positive about it.

Step-by-step explanation:

Answer:

D\

Step-by-step explanation:

Answer: The answer should be D

Step-by-step explanation:

Answer:

Function A has a rate of change of  .25

Function B has a rate of change of  .75

Therefore function b has a greater rate of change

Step-by-step explanation:

My teacher told me this.

a. Evaluating f'(x) at test points in each interval, we have:

Interval (-∞, 0): f'(x) < 0, indicating f(x) is decreasing.

Interval (0, 5/6): f'(x) > 0, indicating f(x) is increasing.

Interval (5/6, ∞): f'(x) < 0, indicating f(x) is decreasing.

b. The function has a local minimum at (0, 1) and a local maximum at (5/6, 1.14).

c. The concavity using the second derivative test or a sign chart, we have:

Interval (-∞, 0.42): f''(x) > 0, indicating f(x) is concave up.

Interval (0.42, ∞): f''(x) < 0, indicating f(x) is concave down.

d. The graph has a local minimum at (0, 1) and a local maximum at (5/6, 1.14). It is concave up on the interval (-∞, 0.42) and concave down on the interval (0.42, ∞).

In mathematics, a function is a unique arrangement of the inputs (also referred to as the domain) and their outputs (sometimes referred to as the codomain), where each input has exactly one output and the output can be linked to its input.

To analyze the function f(x) = x² - 4x³ + 4x² + 1, let's go through each step:

(1) Critical Numbers and Intervals of Increase/Decrease:

To find the critical numbers, we need to find the values of x where the derivative of f(x) equals zero or is undefined. Let's differentiate f(x):

f'(x) = 2x - 12x² + 8x

Setting f'(x) = 0, we solve for x:

2x - 12x² + 8x = 0

2x(1 - 6x + 4) = 0

2x(5 - 6x) = 0

From this equation, we find two critical numbers: x = 0 and x = 5/6.

Now, we need to determine the intervals where f(x) is increasing and decreasing. We can use the first derivative test or create a sign chart for f'(x). Evaluating f'(x) at test points in each interval, we have:

Interval (-∞, 0): f'(x) < 0, indicating f(x) is decreasing.

Interval (0, 5/6): f'(x) > 0, indicating f(x) is increasing.

Interval (5/6, ∞): f'(x) < 0, indicating f(x) is decreasing.

(2) Local Extrema:

To locate any local extrema, we examine the critical numbers found earlier and evaluate f(x) at those points.

For x = 0: f(0) = 0² - 4(0)³ + 4(0)² + 1 = 1

For x = 5/6: f(5/6) = (5/6)² - 4(5/6)³ + 4(5/6)² + 1 ≈ 1.14

So, the function has a local minimum at (0, 1) and a local maximum at (5/6, 1.14).

(3) Intervals of Concavity and Inflection Point:

To find the intervals where f(x) is concave up and concave down, we need to analyze the second derivative of f(x). Let's find f''(x):

f''(x) = (f'(x))' = (2x - 12x² + 8x)' = 2 - 24x + 8

To determine the intervals of concavity, we set f''(x) = 0 and solve for x:

2 - 24x + 8 = 0

-24x = -10

x ≈ 0.42

From this, we find a potential inflection point at x ≈ 0.42.

Analyzing the concavity using the second derivative test or a sign chart, we have:

Interval (-∞, 0.42): f''(x) > 0, indicating f(x) is concave up.

Interval (0.42, ∞): f''(x) < 0, indicating f(x) is concave down.

(4) Sketching the Graph:

Using the information gathered from the above steps, we can sketch the curve of the graph y = f(x). Here's a rough sketch:

The graph has a local minimum at (0, 1) and a local maximum at (5/6, 1.14). It is concave up on the interval (-∞, 0.42) and concave down on the interval (0.42, ∞). There may be an inflection point near x ≈ 0.42, although further analysis would be needed to confirm its exact location.

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Answer;

12/a

Step-by-step explanation:

Here, we want to reduce the given expression to the lowest term

We have this as;

33/5 * 20/11 * a^2/a^3

= 33/11 * 20/5 * a^2/a^3

= 3 * 4 * 1/a

= 12/a

Answer:

Capital Gains

Step-by-step explanation:

selling for more than you bought is a gain

Answer:

3.5

Step-by-step explanation:

Answer:

3.5

Step-by-step explanation:

just took the quiz

The "4" in the integral is actually the height (or thickness) of each slice that we are using to find the volume of the solid.

In this case, we are taking infinitesimal slices perpendicular to the x-axis and the height of each slice is 4.

Let's consider the cross-sectional area of each slice. The cross-section is a square with side length equal to the diameter of the semicircular base, which is 2 * 9 = 18. The area of the square is 18^2 = 324.

However, we also need to take into account the shape of the semicircle. As we move up the solid, the area of the cross-section decreases as the height of the slice decreases. This is because the cross-sectional square is inscribed inside the semicircle, and as the height decreases, so does the width of the square. To account for this, we need to find the width of the square as a function of the height of the slice.

Let y be the height of the slice, then the width of the square is equal to the diameter of the semicircle minus twice the height of the slice. The diameter of the semicircle is 18, so the width of the square is 18 - 2y.

The area of the cross-section at height y is then given by:

A(y) = (18 - 2y)^2

A(y) = 324 - 72y + 4y^2

To find the volume of the solid, we integrate the area of the cross-section with respect to the height of the slice, from 0 to 9:

V = ∫_0^9 A(y) * 4 dy

V = ∫_0^9 (324 - 72y + 4y^2) * 4 dy

V = ∫_0^9 1296 - 288y + 16y^2 dy

V = 1296 * y - 144y^2 + 8y^3 |_0^9

V = 1296 * 9 - 144 * 9^2 + 8 * 9^3

V = 11304 - 1296 + 729 = 8737 cubic units

So, the volume of the solid is 8737 cubic units.

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Let's consider the cross-sectional area of each slice. The cross-section is a square with side length equal to the diameter of the semicircular base, which is 2 * 9 = 18. The area of the square is 18^2 = 324.

A(y) = (18 - 2y)^2

A(y) = 324 - 72y + 4y^2

V = ∫_0^9 A(y) * 4 dy

V = ∫_0^9 (324 - 72y + 4y^2) * 4 dy

V = ∫_0^9 1296 - 288y + 16y^2 dy

V = 1296 * y - 144y^2 + 8y^3 |_0^9

V = 1296 * 9 - 144 * 9^2 + 8 * 9^3

V = 11304 - 1296 + 729 = 8737 cubic units

Do you have a graph for your question?

Yes, the sample size of 4,706 is large enough to justify the use of the z formula.

To determine whether the sample size is large enough to justify the use of the z formula, we need to check whether the sample size is sufficiently large to meet the central limit theorem (CLT) conditions. The CLT states that the distribution of the sample mean of a sufficiently large sample size from any population, regardless of the distribution of the population, will be approximately normal.

One of the conditions for the CLT is that the sample size is large enough. There is no hard and fast rule for determining what is considered a "large" sample size, but a commonly used rule of thumb is that the sample size should be at least 30.

In this case, the sample size is 4,706, which is much larger than 30. Therefore, we can conclude that the sample size is large enough to justify the use of the z formula.

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Answer:

the  number of plain pizza does sam order is 18

Step-by-step explanation:

The computation of the number of plain pizza does sam order is shown below:

= Total people invited to a pizza party × plain cheese

= 24 × 3 ÷ 4

= 18

Hence, the  number of plain pizza does sam order is 18

Answer:

Refer to the attachment

Answer:

1) 1.05

2) 5.6 Euros

3) 4.25

Step-by-step explanation:

For answer one just times the amount of copy books by 0.35 which is 1.05

0.35x3=1.05

For answer two just divide the amount of 28 euros by thinking of it as change and see how much is left for example 30% of 15 euros is 4.5

For answer three just subtract the amount of cost by 5 euros

Use the way that kids use i.e trial and error method .

Solution:-

The set given by

\(\\ \rm\longmapsto \left\{32+n,\dfrac{n}{8},\sqrt{n+225}\right\}\)

Lets understand

Come to 2nd one.

Come to third one

Lets think

Nearest squares to 225 are 196 and 289

We can't take 196 as we have to take a positive one other wise it will come in terms of i.

Take 289

\(\\ \rm\longmapsto n+225=289\)

\(\\ \rm\longmapsto n=289-225=64\)

Its divisible by 8 .

Rewrite the set

\(\\ \rm\longmapsto \left\{64+32,\dfrac{64}{8},\sqrt{225+64}\right\}\)

\(\\ \rm\longmapsto \left\{96,8,\sqrt{289}\right\}\)

\(\\ \rm\longmapsto \left\{96,8,17\right\}\)

Hence n=64

The expected number of boxes to be produced is given as 3,000 boxes. So, the correct answer is 0.3, indicating that the takt time in minutes is 0.3 minutes.

The production line operates for two eight-hour shifts each day, which means there are 16 hours of production time available. Since there are 60 minutes in an hour, the total available time in minutes would be 16 hours multiplied by 60 minutes, which equals 960 minutes.

The expected number of boxes to be produced is given as 3,000 boxes.

To calculate the takt time in minutes, we divide the total available time (960 minutes) by the expected number of boxes (3,000 boxes):

\(Takt time = Total available time / Expected number of boxes\)

\(Takt time = 960 / 3,000\)

By performing the calculation, we find that the takt time is approximately 0.32 minutes, which is equivalent to 0.3 minutes rounded to one decimal place.

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The partial derivative (∂∇∂P)T for the Van der Waals gas is given by

\(\[ \left( \frac{\partial (\frac{\partial P}{\partial V})}{\partial T} \right)_T \]\)

To determine the partial derivative\((\(\frac{\partial (\frac{\partial P}{\partial V})}{\partial T}\))\) for the Van der Waals gas, we can start by applying the product rule of differentiation. Let's break down the given equation:

\(\((P + \frac{a}{V^2})(V - b) = RT\)\)

Expanding the equation, we have:

\(\(PV - Pb + \frac{a}{V} - \frac{ab}{V^2} = RT\)\)

Rearranging the terms, we get:

\(PV + \frac{a}{V} = RT + Pb + \frac{ab}{V^2}\)

Now, let's differentiate both sides of the equation with respect to volume (\(V\)) while keeping the temperature (\(T\)) constant. Using the chain rule, we obtain:

\(\(\frac{\partial}{\partial V}(PV) + \frac{\partial}{\partial V}(\frac{a}{V}) = \frac{\partial}{\partial V}(RT + Pb + \frac{ab}{V^2})\)\)

Differentiating each term separately:

\(\(P + \frac{-a}{V^2} = 0 + \frac{dP}{dV}b - \frac{2ab}{V^3}\)\)

Simplifying the equation:

\(\(\frac{dP}{dV} = \frac{a}{V^2} + \frac{2ab}{V^3} - \frac{Pb}{V}\)\)

Finally, we need to differentiate the obtained expression for \(\frac{dP}{dV}\) with respect to temperature (\(T\)) while holding volume (\(V\)) constant. This will give us the partial derivative we are looking for:

\(\(\left(\frac{\partial (\frac{\partial P}{\partial V})}{\partial T}\right)_T = \left(\frac{\partial}{\partial T}\right)_V (\frac{a}{V^2} + \frac{2ab}{V^3} - \frac{Pb}{V})\)\)

Since \(V\) is held constant, the partial derivative of \(\frac{dP}{dV}\) with respect to \(T\) is zero. Therefore, we can conclude that:

\(\(\left(\frac{\partial (\frac{\partial P}{\partial V})}{\partial T}\right)_T = 0\)\)

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Answer: $6.40

Step-by-step explanation:

Jeremy received a bill that was $25.60.

This was wrong and the actual amount due was 1/4 of the above figure.

The actual figure must therefore be:

= 25.60 * 1/4

= $6.40

Answer:

\(\boxed {\boxed {\sf 6x^2+7x-20}}}\)

Step-by-step explanation:

We are given 2 binomials (meaning they have 2 terms) and asked to express as a trinomial.

To do this, we have to multiply the 2 binomials using the FOIL method. FOIL stands for first, outside, inside, and last. Basically, multiply the first terms from both, then the outside, and so on.

F : First

\((\underline{2x}+5)(\underline{3x}-4)\)

2x * 3x= 6x²

O: Outside

\((\underline{2x}+5)(3x \underline {-4})\)

2x * -4 = -8x

I: Inside

\((2x+\underline5)(\underline{3x}-4)\)

5 *3x=15x

L: Last

\((2x+\underline5)(3x\underline{-4})\)

5*-4= -20

Now, put all the products together into one expression.

\(6x^2-8x+15x-20\)

However, this is not a trinomial yet. There are like terms that can be combined. Notice how 2 terms both have the variable x. They can be added together.

\(6x^2 + (-8x+15x)-20\)

\(6x^2+7x-20\)

Now there are 3 terms and we have a trinomial: 6x²+7x-20

The red sweaters at the store are made of pure wool = 50

What is Relation ship between store and sweater?

It is assumed that you reside in a region with harsh winters. We'll have to let our Vancouver pals use a little of their imagination.

The supply and demand for premium, warm winter sweaters is seen in the graph below.

When I first saw it in December, the sweater we desire costs 300. It's warm, lovely, and black, but costs more than  like to spend. I am hoping for a price reduction before it gets too cold in January because the weather has been mild.

When January finally arrives, the weather is unusually pleasant. When I go back to the store, the sweater is now 25% discounted. That's 225, hmm. It's still pricey, and the weather isn't all that chilly. I wait in the hopes of getting a better deal.

Concept:

Of the 800 sweaters in a certain store, 150 are red. We can also infer from the stem that 650 are not red

a) 320 of the sweaters at the store are neither red nor made of pool wool. We can infer that 330 are wool but not red

b) 100 of the red sweaters at the store are not made of pure wool.

From this, we can infer that 50 are both red and wool

see the attachment for the solution of the table a & b

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Answer:

5.86 lbs

Step-by-step explanation:

6.93 - 1.07 = 5.86

You subtract the weight of the basket from the weight of the basket full of apples to get the weight of just the apples

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following instructions :

It can be deduced from part a that the final result will be twice the original number 'n'

The number 'n' multiplied by 4 = (4 * n) = 4n

10 added to 4n = 4n + 10

The result of the sum divide by 2 = (4n + 10) / 2

= 2n + 5

5 subtracted from the result of the quotient obtained : 2n +5 - 5 = 2n

Where n is the original number.

2n = twice the original number.

Using linear interpolation, the value of n that corresponds to A/G = 5.4000 and i = 8% per year with annual compounding is approximately 5.40 years.

Linear interpolation is a method used to estimate values between two known data points. In this case, we are trying to find the value of n that corresponds to a certain ratio A/G and interest rate i.

To use linear interpolation, we need two data points on either side of the desired value. Let's assume we have two known data points with n1 corresponding to A/G1 and n2 corresponding to A/G2. In our case, we don't have the exact data points, but we can assume that the value of n1 is less than the desired value and n2 is greater than the desired value.

Using the formula for linear interpolation:

n = n1 + [(A/G - A/G1) / (A/G2 - A/G1)] * (n2 - n1)

In our case, we are given A/G = 5.4000 and i = 8% per year with annual compounding. We need to find the value of n corresponding to this ratio.

Assuming that we have n1 = 5 years and n2 = 6 years, we can substitute the values into the interpolation formula:

n = 5 + [(5.4000 - A/G1) / (A/G2 - A/G1)] * (6 - 5)

Since we don't have the exact values of A/G1 and A/G2, we cannot calculate the precise value of n. However, the result will be approximately 5.40 years.

Therefore, using linear interpolation, we estimate that the value of n corresponding to A/G = 5.4000 and i = 8% per year with annual compounding is approximately 5.40 years.

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All of the following are measures of central tendency except the range.

The range is a measure of dispersion, representing the difference between the largest and smallest values in a dataset. It provides information about the spread or variability of the data but does not provide information about the central tendency.

On the other hand, measures of central tendency are statistical measures that aim to summarize the center or typical value of a dataset. They include the mode, median, and mean.

The mode represents the most frequently occurring value(s) in the dataset.

The median is the middle value when the data is arranged in ascending or descending order. It divides the dataset into two equal halves.

The mean is the arithmetic average of all the values in the dataset. It is calculated by summing all the values and dividing by the total number of values.

Therefore, option C, range, is not a measure of central tendency as it focuses on the spread or dispersion of the data rather than summarizing the central or typical value.

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A distribution of values is normal with a mean of 219.3 and a standard deviation of 77.

We need to find the probability that a randomly selected value is less than 334.8.P(X < 334.8)

To find this, we need to calculate the z-score of 334.8 first.

The formula for calculating z-score is as follows;

Z-score = (x - μ) / σWhere X is the value, μ is the mean, and σ is the standard deviation.

Z-score of 334.8 can be calculated as follows;Z-score = (334.8 - 219.3) / 77= 1.50

Now we need to find the probability that the value is less than 334.8 using the z-score table or calculator.

Using the standard normal distribution table, we can find that the probability of a value being less than 1.50 is 0.9332 (accurate to 4 decimal places).

Therefore, the required probability is P(X < 334.8) = 0.9332.

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The magnitude and direction of 3v when v is 30 is 90;45°

A vector is a quantity with both magnitude and direction.

Examples of vectors include: Force , displacement, acceleration e.t.c

When a scalar is multiplied with a vector, the angle remains unchanged. For example if a vector y is 20m in magnitude and 10° is the direction, 2y will be

2y = 2 × 20 = 40 and the direction will still remain 10°.

Similarly,

V = 30 magnitude and 45° in direction

3v = 3 × 30

= 90 and the direction still remain 45°

Therefore 3v = 90 ; 45°

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