Evaluate the (base) hydrolysis constant for sodium cyanate, NaOCN.
a. 3.7 × 10−12
b. 6.4 × 10−9
c. 2.9 × 10−11
d. 4.0 × 10−10
e. 6.8 × 10−10

Sodium benzoate is a widely used food preservative. The type of cell that can utilize sodium benzoate as a carbon and energy source is pseudomonas cell.

Psuedomonas cells are simple cell. They are gram-negative or gram-positive bacteria. These cells infect humans, animals, and plants.

They grew on fruits and vegetables. They also infect or contaminate food. So they are very harmful to all living organisms.

Thus, a common food preservative is sodium benzoate. Pseudomonas cells are the only kind of cell that can use sodium benzoate as both a carbon and an energy source.

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Answer:

yes

Explanation:

This is because all living tissues

have magnetic properties that are affected to some extent by the existence of electromagnetic radiation in the environment.

Explanation:

V1/T1 = V2/T2      T  must be in Kelvin

12.78 / (-50 + 273.15)  =  V2 / ( 28+ 273.15)

V2 = 17.25 L

Answer:

a. False

b. True

c. False

d. True

In a 39.0% (v/v) alcohol solution, there are 39.0 mL of alcohol for every 100 mL of solution. To find out how many milliliters of each component are present in 795 mL of the solution, we need to calculate the volume of isopropyl alcohol and water separately.



Step 1: Calculate the volume of alcohol in the solution.
In a 39.0% (v/v) alcohol solution, 39.0 mL of alcohol is present for every 100 mL of solution.
To find the volume of alcohol in 795 mL of the solution, we can set up a proportion:
(39.0 mL alcohol / 100 mL solution) = (x mL alcohol / 795 mL solution)
Cross-multiplying and solving for x, we get:
x = (39.0 mL alcohol / 100 mL solution) * 795 mL solution
x ≈ 309.45 mL alcohol

Step 2: Calculate the volume of water in the solution.
The total volume of the solution is 795 mL, and we have already calculated the volume of alcohol to be 309.45 mL.
To find the volume of water, we can subtract the volume of alcohol from the total volume of the solution:
Volume of water = Total volume of solution - Volume of alcohol
Volume of water = 795 mL - 309.45 mL
Volume of water ≈ 485.55 mL

Therefore, in 795 mL of the 39.0% (v/v) alcohol solution, there are approximately 309.45 mL of isopropyl alcohol and 485.55 mL of water.

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A test tube is heated in a water bath instead of directly over the flame because the water bath provides a more controlled and uniform heating environment, which helps to prevent overheating. Direct heating over the flame can cause uneven heating and may result in cracking or breaking of the test tube.

Test tubes are commonly used in chemistry for conducting various reactions, heating samples, or boiling liquids. When heating a test tube, it is important to ensure that the tube is heated evenly and at a controlled rate to avoid overheating or cracking of the tube.

Heating a test tube directly over a flame can result in uneven heating, as different parts of the test tube may be exposed to different temperatures. Additionally, the intense heat from the flame may cause the test tube to overheat, leading to boiling or cracking of the tube.

A water bath, on the other hand, provides a more controlled heating environment for the test tube. The water in the bath distributes heat more evenly around the tube, allowing for more gradual heating and preventing overheating. The water also helps to maintain a constant temperature, which is important for reactions that require specific temperature ranges.

Furthermore, the water bath also acts as a safety measure, as it provides a barrier between the flame and the test tube, reducing the risk of accidental fires. Overall, heating a test tube in a water bath provides a more controlled and safer heating environment, making it a preferred method for heating test tubes in chemistry.

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Answer:

The answer would be (b)

Explanation:

The mass of MgCO₃ precipitated by mixing 10.00 mL of a 0.200 M Na₂CO₃ solution with 5.00 mL of a 0.0450 M Mg(NO₃)₂ solution is approximately 0.019 g.

To calculate the mass of MgCO₃ precipitated, we need to determine the limiting reactant and then use stoichiometry to calculate the amount of MgCO₃ formed.

Given:

Volume of Na₂CO₃ solution = 10.00 mL = 0.01000 L

Concentration of Na₂CO₃ solution = 0.200 M

Volume of Mg(NO₃)₂ solution = 5.00 mL = 0.00500 L

Concentration of Mg(NO₃)₂ solution = 0.0450 M

Moles of Na₂CO₃ = concentration × volume = 0.200 M × 0.01000 L = 0.00200 moles

Moles of Mg(NO₃)₂ = concentration × volume = 0.0450 M × 0.00500 L = 0.000225 moles

From the balanced equation:

Na₂CO₃ + Mg(NO₃)₂ → MgCO₃ + 2NaNO₃

The ratio between Na₂CO₃ and MgCO₃ is 1:1.

Since the stoichiometric ratio is 1:1, the limiting reactant is the one with fewer moles. In this case, Mg(NO₃)₂ is the limiting reactant.

So, moles of MgCO₃ = Moles of limiting reactant = 0.000225 moles

Molar mass of MgCO₃ = 24.31 g/mol + 12.01 g/mol + (3 × 16.00 g/mol) = 84.31 g/mol

Mass of MgCO₃ = Moles of MgCO₃ × Molar mass of MgCO₃

                 = 0.000225 moles × 84.31 g/mol

                 ≈ 0.019 g

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In the standard welding system, the ground clamp or work clamp connects the reference line to the joint or area to be welded.

In welding, the ground clamp (also known as the work clamp) plays a crucial role in the standard welding system. It is used to establish an electrical connection between the welding machine and the workpiece. The ground clamp is typically connected to the reference line, which is usually the welding machine's negative terminal or ground connection.

The purpose of connecting the ground clamp to the joint or area to be welded is to create a closed electrical circuit. When the welding machine generates an electrical current, it flows through the electrode or welding torch, passes through the workpiece, and returns through the ground clamp to complete the circuit. This circuit allows the welding process to occur, with the heat generated by the electrical current melting the workpiece material and forming a weld.

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Answer:

m(HNO3)=193.41g

Explanation:

HNO3 + H2O produce H3O+ and NO3+

n(H2O)=m/M= 55.3g/(18g/mol) =3.07mol

n(HNO3)/n(H2O)= x/1

n(HNO3)=3.07mol

Mass of HNO3 is given as m(HNO3)= 3.07mol ×63g/mol= 193.41g.

The freezing point of the solution is -0.3462 °C. When, 2. 50 grams of sodium chloride are added to 230. 0 mL of water.

To calculate the freezing point of the solution, we use the freezing point depression equation;

\(ΔT_{f}\) = \(K_{f.m}\)

where \(ΔT_{f}\) is the change in freezing point, \(K_{f}\) is the freezing point depression constant of water (1.86 °C/m), and m is the molality of the solution.

First, we calculate the molality (m) of the solution;

Molar mass of NaCl = 58.44 g/mol

Number of moles of NaCl = 2.50 g / 58.44 g/mol

= 0.0428 mol

Mass of water=230.0 mL x 1.00 g/mL

= 230.0 g

molality (m) = 0.0428 mol / 0.230 kg

= 0.186 mol/kg

Now we can plug in the values into the freezing point depression equation;

\(ΔT_{f}\) = 1.86 °C/m x 0.186 mol/kg = 0.3462 °C

The freezing point of pure water is 0 °C, so the freezing point of the solution is;

Freezing point = 0 °C - 0.3462 °C

= -0.3462 °C

Therefore, the freezing point of the solution is -0.3462 °C.

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Answer:

You can use a PH tester do identify the PH of each solution.  Depending on what solutions ur testing, u shouldn't mix them as for there could be either a minor or bad chemical reaction

Explanation:

Answer:

\(Q=20.6\frac{J}{g}\)

Explanation:

Hello there!

In this case, according to the equation for the calculation of the heat during a heating process:

\(Q=mC(T_f-T_i)\)

It is possible to compute it per gram of ice by just removing m from the equation by dividing at both sides. Next we plug in the given specific heat and the final and initial temperatures to obtain:

\(Q=2.06\frac{J}{g\°C}[-15\°C-(-25\°C)] \\\\Q=20.6\frac{J}{g}\)

Best regards!

The least soluble salt in the list is PbCl2 .

The Pb2+ cation repels water molecules less forcibly than smaller or less charged cations due to its size and high charge density. PbCl2 is hence less soluble in water.

The strength of the ionic bonds between Pb2+ and Cl- ions should also be taken into account. Within the lattice structure of PbCl2, the Pb2+ and Cl- ions are arranged in a regular way to form a crystalline solid.

The strength of the ionic bonds between Pb2+ and Cl- ions accounts for the low solubility

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Answer:

Fossils, the shape of continents, the mid-ocean ridge system, sea floor sediment deposits, and the magnetism of rocks.

Explanation:

Fossils, the continent's shape, the mid-ocean ridge system, sea floor sediment deposits, and the magnetism of rocks on the sea floor are the evidences that support the theory of plate tectonics in the area. Fossils provides information to us when and where plants and animals once existed. Due to diverging plates, some life became isolated, and evolved into new species. Continental ‘fit’ through coastline matching. Some division of continents look as though they should fit together, e.g. South America and Africa.

According to kinetic theory of gases, when samples are heated from liquid to gas phase, particles move faster and spread out more. Hence, option a is correct.

According to kinetic theory of gases. Gaseous substances are made of tiny particles called molecules. The molecules within a container are in a state of random chaotic motion during which they collide with  each other.

At, a particular instant, different molecules in a sample of gas may have different velocities and hence, different kinetic energies.  The kinetic energy of molecules is directly proportional to the temperature.

Hence, the the sample  when heated, the molecules acquire higher kinetic energy and they will move apart. Therefore, option a is correct according to kinetic theory.

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1.0 M NaOH has the highest concentration of dissolved solutes and thus the highest boiling point.

The boiling point of an aqueous solution is determined by the concentration of dissolved solutes in the solution. The higher the concentration of solutes, the higher the boiling point of the solution. The boiling point of an aqueous solution of 1.0 M NaOH is approximately 101.5°C. This is due to the fact that, when an ionic compound is dissolved in water, the ions become surrounded by water molecules and the solution becomes more dense. As a result, the boiling point of the water is increased as the number of molecules per unit volume increases.

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Answer:

atributes  of nonrenewable recources are things you cant re use after 1 use like gas

Explanation:

Answer: the answer is b. Are unlimited

Explanation:

a. OCS would have greater intermolecular forces than CO2 because OCS has a dipole moment due to the difference in electronegativity between carbon and sulfur atoms.

b. SeO2 would have greater intermolecular forces than SO2 because SeO2 has a larger atomic radius and more polarizability than SO2, allowing for stronger dispersion forces.

c. H2NCH2CH2NH2 would have greater intermolecular forces than CH3CH2CH2NH2 because it can form hydrogen bonds between nitrogen and hydrogen atoms.

d. H2CO would have greater intermolecular forces than CH3CH3 because it can form dipole-dipole interactions and hydrogen bonding due to the presence of the polar C=O bond.

e. CH3OH would have greater intermolecular forces than H2CO because it can form hydrogen bonds between oxygen and hydrogen atoms.

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Food/liquid/gas are moving through your stomach to your intestines - stomach growling is a part of digestion. When there is a lot of food in your stomach the sounds are muffled, when your stomach is empty you can hear the “growls” easier.

I learned that the growling does not indicate hunger as we are often told. It indicates your stomach is empty which does not automatically mean you’re hungry. When your stomach has nothing to digest it frees up your body’s energy and focuses it in other areas. This is why people find fasting beneficial.

Thanks,

Eddie

At constant temperature and pressure, the relationship between ∆Suniv (the change in the entropy of the universe) and ∆Gsys (the change in the Gibbs free energy of the system) can be described by the following equation:

∆Suniv = ∆Gsys / T

where T is the temperature in Kelvin.

This equation is derived from the second law of thermodynamics, which states that the entropy of the universe tends to increase for any spontaneous process. The Gibbs free energy of a system, on the other hand, tells us whether a reaction is thermodynamically favorable or not. If ∆Gsys is negative, the reaction is spontaneous and thermodynamically favorable, while if ∆Gsys is positive, the reaction is non-spontaneous and thermodynamically unfavorable.

The equation above shows that as the change in the Gibbs free energy (∆Gsys) becomes more negative (i.e. more thermodynamically favorable), the change in the entropy of the universe (∆Suniv) increases. This means that a spontaneous reaction that releases energy (negative ∆Gsys) will also tend to increase the entropy of the universe, while a non-spontaneous reaction that requires energy input (positive ∆Gsys) will tend to decrease the entropy of the universe.

Explanation:

c=flamda

lamda, wavelength=c/f

=(3×10⁸)/(4.0×1014)

= use a calculator

Answer:

animals

Explanation:

I think I remember this from a quiz I took so exotic species

Answer:

The answer is

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

\(volume = \frac{mass}{density} \)

From the question

mass = 420 g

density = 10.5 g/cm³

The volume is

\(volume = \frac{420}{10.5} \\ \)

We have the final answer as

Hope this helps you

1. 1.90 L . According to Avogadro's law, at constant temperature and pressure, the volume of a gas is directly proportional to the number of moles. Therefore, if 3.50 moles of gas occupy a volume of 1.75 L, the molar volume is 1.75 L / 3.50 mol = 0.50 L/mol. Adding 0.30 moles of gas would increase the volume proportionally: 0.30 mol * 0.50 L/mol = 0.15 L. Hence, the new volume of the balloon would be 1.75 L + 0.15 L = 1.90 L.

2. 36.8 L .Using the combined gas law, (P1 * V1) / T1 = (P2 * V2) / T2, we can calculate the new volume. Plugging in the given values:

(4.11 atm * 25.0 L) / 278 K = (7.00 atm * V2) / 393 K

Solving for V2, we find V2 = (4.11 atm * 25.0 L * 393 K) / (7.00 atm * 278 K) ≈ 36.8 L.

3. 2.35 L .Similar to the first question, the volume of the balloon is directly proportional to the number of moles. Adding 0.70 moles of gas to the initial 3.50 moles would result in a proportional increase in volume: 0.70 mol * 0.50 L/mol = 0.35 L. Therefore, the new volume of the balloon would be 2.00 L + 0.35 L = 2.35 L.

4. 19.5 L. When the temperature changes while the pressure is held constant, the volume of the gas follows Charles's law. Charles's law states that the volume of a gas is directly proportional to its temperature in Kelvin. Using this law, we can calculate the new volume at -32.0 °C (-32.0 °C + 273.15 K = 241.15 K) as follows:

(22.0 L * 241.15 K) / 273.15 K = 19.5 L.

Therefore, the volume of the weather balloon at -32.0 °C would be 19.5 L.

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