Owen can jog 660 yards in 3 minutes. how many yards would you expect him to jog in 10 minutes?
Answer: 2200 yards
Step-by-step explanation:
First find the unit rate, 660/3 = 220
So, Owen can jog 220 yards in one minute.
220 times 10 to find how much Owen can jog in 10 minutes.
220*10 = 2200.
Answer:
2200
Step-by-step explanation:
a spinner has five equal sections labeled a, b, c, d, and e. a fair coin has faces labeled heads and tails. carlos will spin the arrow of the spinner and flip the coin one time each. what is the probability the arrow will land on the section labeled a and the coin will land on heads?
The probability of the arrow landing on section a is 1/5 since there are 5 equal sections. The probability of the coin landing on heads is 1/2 since there are only 2 possible outcomes (heads or tails) for the coin.
To find the probability of both events happening, we need to multiply the probability of the arrow landing on section a by the probability of the coin landing on heads. This gives us (1/5) * (1/2) = 1/10. So the probability that the arrow will land on the section labeled a and the coin will land on heads is 1/10. In other words, there is a 1 in 10 chance of both events happening. It is important to note that each event is independent of each other, meaning the outcome of one does not affect the other. This is because the spinner and the coin are not connected or related in any way.
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The longer side of a rectangle has a length of 10. the rectangle is rotated around line k at this side. rectangle abcd has a perimeter of 32 units and will be rotated about line k. what is the three-dimensional solid created? what is the radius of a base?
The radius of the base after rotating the rectangle will be 5
What is the radius of the base?Since it has a perimeter of 32 units and it is to be rotated about the line, the solid to be created is a cylinder.
Let's calculate its radius from the perimeter;
\(2p=32\)
\(2(b+h)=32\)
\(b+h=16\)
\(b=16-h\)
Also, \(bh=60\)
Thus;
\(h(16-h)=60\)
\(h^2-16h+60=0\)
Using the online quadratic formula, we have h = 6
Thus; b = 16 - 6 = 10
Since the line of rotation is the center, and the radius is half the line segment of the basis, then the radius is 10/2 = 5.
Thus the radius of the base after rotating the rectangle will be 5
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Answer:
cylinder and 6 units
Step-by-step explanation:
on e2020
Point k is on line segment \overline{jl} jl . given kl=2x-2,kl=2x−2, jl=4x 9,jl=4x 9, and jk=5x 2,jk=5x 2, determine the numerical length of \overline{jl}. jl .
The numerical length of line segment \(\(\overline{JL}\)\) is approximately -11.67 units.
To determine the numerical length of line segment \(\(\overline{JL}\)\), we need to determine the value of JL provided the equations; KL = 2x - 2, JL = 4X-9, and JK = 5X+2.
Since point K is on line segment \(\(\overline{JL}\)\), we can equate the lengths KL and JK and solve for x:
KL = JK
2x - 2 = 5x + 2
By rearranging the equation, we get:
2 - 2 = 5x - 2x + 2
0 = 3x + 2
3x = -2
\(x = -\frac{2}{3}\)\)
Now that we have the value of x, we can substitute it into the equation for JL to calculate its numerical length:
JL = 4x - 9
\(\(JL = 4\left(-\frac{2}{3}\right) - 9\)\\\\\)
\(\\\(JL = -\frac{8}{3} - 9\)\\\\\)
\(\(JL = -\frac{8}{3} - \frac{27}{3}\)\\\\)
\(\(JL = -\frac{35}{3}\)\)
Therefore, the numerical length of line segment \(\(\overline{JL}\)\) is \(\(-\frac{35}{3}\)\) or approximately -11.67 units.
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how does this function compare to the logistic mean response function in part (a) of problem 14.4? b. for what value of x is the mean response equal to .5?
This function compare to the logistic mean response function in part is as following:
The equation is, E{Yi} = πi = Fl = (β0 + β1xi)
E{Yi} = Exp(βo + β1Xi) / 1 + Exp(βo + β1Xi)
A) plot the logistic mean response function. When βo = 20 and β1 = -0.2
Let,
E{Yi} = Exp(βo + β1Xi) / 1 + Exp(βo + β1Xi)
where,
βo = 20
β1 = -0.2
E{Yi} = 1/2
Xi = 100
B) = For what value of X is the mean response equal to 0.5
Mean response = 1/2
= E{Yi} = Exp(βo + β1Xi) / 1 + Exp(βo + β1Xi)
= 1/2
= Exp(βo + β1Xi)
Xi = -βo/β1
c) The odds when x = 125, when x = 126 and the ratio of the odds, when x = 126 to odds when x = 125
Odd = \(e^{\beta o + \beta 1 Xi}\)
Odd(125) = \(e^{\beta o + \beta 1 125}\)
odd(126) = \(e^{\beta o + \beta 1 +126}\)
Rate of odd = Odd126/odd125
Rate of Odd = \(e^{\beta 1}\)
One of the most popular techniques in data mining in general and binary data categorization in particular continues to be logistic regression (LR). The primary goal of this study is to provide an overview of the key LR features when applied to data analysis, specifically from an algorithmic and machine learning standpoint.
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Complete question:
a. Plot the logistic mean response function (14.16) when = 20 and β,--.2
b. For what value of X is the mean response equal to.5:?
c. Find the odds when X 125, when X-126, and the ratio of the odds when X-126 to the odds when X-125. Is the odds ratio equal to exp(B,) as it should be?
Solve this differential equation:
dydt=0.09y(1−y500)dydt=0.09y(1-y500)
y(0)=5y(0)=5
y(t) =
The conclusion is:
y(t) = (500e^(0.09t+ln(99))) / (1 + e^(0.09t+ln(99)))
Find out the solution for this differential equation?We have the differential equation:
dy/dt = 0.09y(1 - y/500)
To solve this, we can separate variables and integrate both sides:
dy / (y(1 - y/500)) = 0.09 dt
We can use partial fractions to break up the left-hand side:
dy / (y(1 - y/500)) = (1/500) (1/y + 1/(500 - y)) dy
Now we can integrate both sides:
∫ (dy / (y(1 - y/500))) = ∫ (1/500) (1/y + 1/(500 - y)) dy
ln |y| - ln |500 - y| = 0.09t + C
where C is the constant of integration.
Simplifying:
ln |y / (500 - y)| = 0.09t + C
Taking the exponential of both sides:
|y / (500 - y)| = e^(0.09t+C)
Since y(0) = 5, we can use this initial condition to find the value of C:
|5 / (500 - 5)| = e^C
C = ln(495/5)
C = ln(99)
So the equation becomes:
|y / (500 - y)| = e^(0.09t + ln(99))
Simplifying further:
y / (500 - y) = ± e^(0.09t + ln(99))
y = (500e^(0.09t+ln(99))) / (1 ± e^(0.09t+ln(99)))
Using the initial condition y(0) = 5, we can determine that the positive sign is appropriate:
y = (500e^(0.09t+ln(99))) / (1 + e^(0.09t+ln(99)))
Therefore, the solution to the differential equation is:
y(t) = (500e^(0.09t+ln(99))) / (1 + e^(0.09t+ln(99)))
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Carlos plans to watch 3 movies each month. Write an equation to represent the total number of movies n that he will watch in m months.
Answer:
Step-by-step explanation:
An=3*n
Answer:
n=3m
Step-by-step explanation:
n represent the number of movies he will watch
m shows the amoutn of month
70 pupils in a sports centre are surveyed. The pupils can only use the swimming pool and the gym. 28 pupils use the swimming pool and the gym. 48 pupils use the swimming pool. 39 pupils use the gym. Find the probability to select a pupil that uses neither the swimming pool nor the gym.
The probability that a pupil uses neither pool nor gym is 11/70
What is Probability?Probability is the likelihood that an event will happen. This can range from an event being impossible to some likelihood to being absolutely certain. In math terms, probability is on a scale from 0 to 1. Zero means the event is impossible, like rolling a seven on a die that only has digits from 1 to 6.
Number of pupil that can use pool and gym = 28
Number of people that can use pool = 48
Number of people that can use gym = 39
Number of people that can use pool only = 48 - 28 which is 20
Number of people that can use gym only = 39 - 28 = 11
Total number of persons that can use either pool, gym or both = 20 + 11 + 28 which is 59
Number of people that cannot use either or both of the facilities = 70 - 59 which is 11.
Probability = required outcome / possible outcome
Required outcome = 11
possible outcome = 70
Probability = 11/70
In conclusion, the probability that a pupil uses neither swimming pool nor gym is 11/70
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What is e in the equation show your work.
Answer:
e = 25/3
Step-by-step explanation:
If you have any questions about the way I solved it, don't hesitate to ask me in the comments below =)
usually, data collection in a functional analysis is based on a. duration b. frequency c. momentary time sampling
The correct answer is b. frequency.
Data collection in a functional analysis typically involves recording the frequency of a target behavior. In functional analysis, the focus is on understanding the function or purpose of a behavior, and frequency data helps to identify patterns and determine the relationship between the behavior and environmental events.
During a functional analysis, various conditions are manipulated to assess how they impact the occurrence of the behavior. The frequency of the behavior is typically recorded within each condition to determine if there are differences in its occurrence based on the specific environmental variables being manipulated.
While duration and momentary time sampling are also data collection methods used in behavioral analysis, they are not specifically associated with functional analysis. Duration refers to measuring the length of time a behavior occurs, while momentary time sampling involves recording whether a behavior is occurring or not at specific intervals of time.
In functional analysis, frequency data is typically the primary method for collecting and analyzing data to understand the relationship between behavior and environmental variables.
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Data collection in a functional analysis is usually based on three components: duration, frequency, and momentary time sampling. Duration observes the amount of time a behavior occurs. Frequency measures how often a behavior occurs. Momentary time sampling observes the existence of behavior at specified time intervals.
Explanation:In the context of a functional analysis, typically the data collection methods revolve around three primary types: duration, frequency, and momentary time sampling.
Duration refers to the total amount of time that a behavior happens. It generally is measured from the moment the behavior begins until it ends. It's important when the length of time that the behavior occurs can impact its functionality.
Frequency records how often a behavior occurs within a set observational period. It’s used when the number of times the behavior occurs is the important aspect to measure.
Momentary time sampling is a method of measuring behavior in which the existence or nonexistence of behaviors are recorded at precisely specified time intervals. This process involves observing whether the behavior occurs or does not occur at the moment the interval ends. This method is beneficial as it does not need continuous observation.
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Calculate the markup on an item that cost a store $300.00 and will be marked up 55%
Answer:
It would be $465 marked up.
Step-by-step explanation:
55% of 300 is 165.
So marked up its 465 and marked down its 135.
Answer:
the answer is yes vfmkvfmfmkrkfm
Step-by-step explanation:
1.
The sales of lawn mowers t years after a particular model is introduced is given by the function y = 5500 ln (9t + 4), where y is the number of mowers sold. How many mowers will be sold 3 years after a model is introduced?
Round the answer to the nearest hundred.
18,100 mowers
40,100 mowers
8,200 mowers
18,900 mowers
Answer:
D - 18,900 mowers
Step-by-step explanation:
To determine the number of lawn mowers sold 3 years after a model is introduced, we can substitute t = 3 into the given function.
y = 5500 ln (9t + 4)
Let's calculate it step by step:
y = 5500 ln (9(3) + 4)
y = 5500 ln (27 + 4)
y = 5500 ln (31)
y ≈ 5500 * 3.4339872
y ≈ 18,886.43
Therefore, approximately 18,886 mowers will be sold 3 years after the model is introduced.
Find the absolute maximum and absolute minimum values of the function f(x)=x^3−12x^2−27x+8 over each of the indicated intervals.
(a) Interval = [−2,0]. (b) Interval = [1,10]. (c) Interval = [−2,10].
The value of Absolute maximum are (a) 8, (b) -30.36, (c) -10 and the Absolute minimum are (a) -10, (b) -362.39, (c) -362.39.
We are given a function:f(x) = x³ - 12x² - 27x + 8We need to find the absolute maximum and absolute minimum values of the function f(x) over each of the indicated intervals. The intervals are:
a) Interval = [-2, 0]
b) Interval = [1, 10]
c) Interval = [-2, 10]
Let's begin:
(a) Interval = [-2, 0]
To find the absolute max/min, we need to find the critical points in the interval and then plug them in the function to see which one produces the highest or lowest value.
To find the critical points, we need to differentiate the function:f'(x) = 3x² - 24x - 27
Now, we need to solve the equation:f'(x) = 0Using the quadratic formula, we get: x = (-b ± √(b² - 4ac)) / 2a
Substituting the values of a, b, and c, we get:
x = (-(-24) ± √((-24)² - 4(3)(-27))) / 2(3)x = (24 ± √(888)) / 6x = (24 ± 6√37) / 6x = 4 ± √37
We need to check which critical point lies in the interval [-2, 0].
Checking for x = 4 + √37:f(-2) = -10f(0) = 8
Checking for x = 4 - √37:f(-2) = -10f(0) = 8
Therefore, the absolute max is 8 and the absolute min is -10.(b) Interval = [1, 10]
We will follow the same method as above to find the absolute max/min.
We differentiate the function:f'(x) = 3x² - 24x - 27
Now, we need to solve the equation:f'(x) = 0Using the quadratic formula, we get: x = (-b ± √(b² - 4ac)) / 2a
Substituting the values of a, b, and c, we get:
x = (-(-24) ± √((-24)² - 4(3)(-27))) / 2(3)
x = (24 ± √(888)) / 6
x = (24 ± 6√37) / 6
x = 4 ± √37
We need to check which critical point lies in the interval [1, 10].
Checking for x = 4 + √37:f(1) = -30.36f(10) = -362.39
Checking for x = 4 - √37:f(1) = -30.36f(10) = -362.39
Therefore, the absolute max is -30.36 and the absolute min is -362.39.
(c) Interval = [-2, 10]
We will follow the same method as above to find the absolute max/min. We differentiate the function:
f'(x) = 3x² - 24x - 27
Now, we need to solve the equation:
f'(x) = 0
Using the quadratic formula, we get: x = (-b ± √(b² - 4ac)) / 2a
Substituting the values of a, b, and c, we get:
x = (-(-24) ± √((-24)² - 4(3)(-27))) / 2(3)x = (24 ± √(888)) / 6x = (24 ± 6√37) / 6x = 4 ± √37
We need to check which critical point lies in the interval [-2, 10].
Checking for x = 4 + √37:f(-2) = -10f(10) = -362.39
Checking for x = 4 - √37:f(-2) = -10f(10) = -362.39
Therefore, the absolute max is -10 and the absolute min is -362.39.
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Find all numbers whose absolute value is 4.
If there is more than one, separate them with commas.
If there are no such numbers, click on "None".
Step-by-step explanation:
-4
4
and those are the only ones i know
The percent of members in a random sample that have an equal chance of being selected: a) 0% b) 33% c) 50% d) 100%
The answer is c) 50%. A random sample means that each member has an equal chance of being selected. This means that out of a sample size of any number, the percentage of members selected will always be 50%.
For example, if we have a random sample of 100 members, 50 of them will be selected. This principle applies to any population size, regardless of whether it's 10 or 10,000. It's important to note that this applies only to random samples, as non-random samples can have a biased selection process which affects the percentage of members selected. In summary, the percent of members in a random sample that have an equal chance of being selected is always 50%.
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Construct a quadratic equation using the following roots
Answer:
1) 63x²+68x+12=0
2) x⁴-8x²+15=0
3) -5x²-(5/x²)+26=0
Step-by-step explanation:
1)
x=-6/7 and x=-2/9
7x=-6 and 9x=-2
7x+6=0 and 9x+2=0
(7x+6)(9x+2)
63x²+14x+54x+12
63x²+68x+12=0
2)
x=√3 and x=√5
x²=3 and x²=5
x²-3=0 and x²-5=0
(x²-3)(x²-5)
x⁴-5x²-3x²+15
x⁴-8x²+15=0
3)
x=\(\sqrt[2]{5}\) and x=\(\sqrt[-2]{5}\)
x²=5 and x⁻²=5
x²=5 and (1/x²)=5
x²-5=0 and (1/x²)-5=0
(x²-5)((1/x²)-5)
1-5x²-(5/x²)+25
-5x²-(5/x²)+26=0
Solve the equation by extracting the square roots. List both the exact solution and its approximation rounded to two decimal places.
(2x − 1)^2 = 18
The exact solution and its approximation rounded to two decimal places are 2. 6213 and 2. 62 respectively.
What is an algebraic expression?An algebraic expression can be described as a mathematical or arithmetic expressions that is composed of arithmetic terms, factors, constants, variables, and coefficients.
These expressions are also made up of arithmetic operations which includes;
DivisionAdditionParenthesesBracketMultiplicationSubtractionFrom the information given, we have that;
(2x − 1)^2 = 18
Find the square root of both sides, we have;
√(2x − 1)^2 = √18
Note that square root rules out the square, we have;
2x - 1 = 4. 24264
collect like terms
2x = 4. 24264 + 1
2x = 5. 24264
Make 'x' the subject
x = 5. 24264/2
x = 2. 6213
Hence, the value is 2. 6213
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A bridge, PR, across a river is 400 m long. Gabe is launching a canoe at point Q.
He will paddle in a diagonal line across the river to point P. He plans to return along a route beside the bridge from P to R, and then along the shore from R back to Q. How far will this be altogether?
Therefore, the total distance Gabe will paddle is 2x + 400 meters. The exact value of x depends on the width of the river, which is not provided in the given information.
To find the total distance Gabe will paddle, we need to consider the distance he will travel from Q to P, then from P to R, and finally from R back to Q.
First, let's consider the distance from Q to P. Since Gabe will paddle in a diagonal line across the river, this distance can be calculated using the Pythagorean theorem.
The length of the bridge (PR) is given as 400 meters, which is the hypotenuse of a right triangle. The width of the river can be considered as the perpendicular side, and the distance Gabe will paddle from Q to P is the other side. Let's call this distance x.
Using the Pythagorean theorem, we have:
x^2 + (width of the river)^2 = PR^2
Since the width of the river is not given, we'll represent it as w. Therefore:
x^2 + w^2 = 400^2
Next, let's consider the distance from P to R. Gabe will paddle along a route beside the bridge, which means he will travel the length of the bridge (PR) again. So, the distance from P to R is also 400 meters.
Finally, Gabe will paddle back from R to Q along the shore. Since he will follow the shoreline, the distance he will paddle is equal to the distance from Q to P, which is x.
To find the total distance, we add up the distances:
Total distance = QP + PR + RQ
= x + 400 + x
= 2x + 400
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will give 15 points and brainliest
Answer:
the answer is A 1390
Answer:
1331π cm³
Explanation:
\(\sf V_{cylinder} = \pi (radius)^2 (height)\)
Here given:
radius: 11 cmheight: 11 cmHence find volume:
\(\sf \rightarrow\pi (11)^2 (11)\)
\(\sf \rightarrow 121\pi ( (11)\)
\(\sf \rightarrow 1331\pi \quad \approx \:\:\ 4181.46 \ cm^3\)
which of these expressions are equal to 3/5×6?Explain why the others aren't equal to this expression.3×(6÷5)3÷(5×6)(3×6)÷53×6/5
Answer:
(3×6)÷5
Step-by-step explanation:
We are given the following expression:
(3/5)*6
The 6 can also be written as a fraction(6/1).
So we have a multiplication of fractions, is which we multiply the numerators and denominators.
So
(3*6)/5
The fraction sign means division
So the answer is:
(3×6)÷5
prove that cn, an n-cycle, has exactly n labeled spanning trees. you may use any method you wish to do this problem. write a good, detailed, and thoughtful proof!
To prove that a cycle graph Cn has exactly n labeled spanning trees, we can use the principle of inclusion-exclusion. First, consider a tree T that is composed of the n edges of Cn. This tree has n edges and is therefore an n-edge tree. In order for it to be a labeled spanning tree, every vertex must be labeled with a distinct label. Since Cn has n vertices, there are n! ways to label the vertices, giving us n! labeled spanning trees.
Now, we can use inclusion-exclusion to determine the number of labeled spanning trees that are a subset of T. For each vertex vi in T, we can choose any label from the set of n labels. For each of these labels, we can choose any edge from the n edges in T. The total number of labeled spanning trees that are a subset of T is therefore: n2 × n!
Now, we can subtract the number of labeled spanning trees that are a subset of T from the total number of labeled spanning trees to get the number of labeled spanning trees that are not a subset of T. The number of labeled spanning trees that are not a subset of T is: n! - n2 × n! = n! - n2! Therefore, the total number of labeled spanning trees of Cn is n!.
This proves that a cycle graph Cn has exactly n labeled spanning trees.
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a circle with a radius 5 cm long is centered at an angle's vertex, and the angle's rays subtend an arc length of 14 cm along the circle. the subtended arc is how many times as long as the circle's radius?
The subtended arc is 2.8 times as long as the circle's radius [r].
What is the area of a circle?The area of a circle is given as follows -
A = πr² = π(d/2)²
where -
r - radius
d - diameter
Given is that a circle with a radius 5cm long is centered at an angle's vertex. The angle's rays subtend an arc length of 14cm along the circle.
Assume that the subtended arc is [x] times as long as the circle's radius [r]. So, we can write -
x = (Arc length)/(radius)
x = 14/5
x = 2.8
Therefore, the arc subtended by the rays is 2.8 times as long as the circle's radius [r].
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Helen and Stephen both simplify the exponential expression 4 ln21 3 e −
Stephen makes the mistake in the expression as he uses the 4 in the root and the 3 in the power and the expression actually is: ∛(16)/e
How to illustrate the information?We start with the expression:
exp( (4/3)*ln(2) - 1)
Here we can use that:
exp(ln(x)) = x.
and e^(a + b) = e^a*e^b.
the first step here is:
e^((4/3)*ln(2) - 1) = e^((4/3)*ln(2)*e^(-1)
So the first step of Stephen is correct, but the first step of Helen is not, you can not simplify the expression in that way.
now, we have that:
a*ln(x) = ln(x^a)
then we can write:
(4/3)*ln(2) = ln(2^(4/3))
and e^(ln(2^(4/3)) = 2^(4/3)
then we have:
e^((4/3)*ln(2)*e^(-1) = 2^(4/3)/e
now we can write this as:
∛(2^4)/e
Here is where Stephen makes the mistake, he uses the 4 in the root and the 3 in the power.
The expression actually is: ∛(16)/e
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how many distinct permutations of the characters in the word apalachicola are there?
The word "apalachicola" has 12 characters, including repeated characters. There are 12!/(4!2!2!2!) = 27,720 distinct permutations of the characters in the word.
To calculate the number of distinct permutations, we need to consider the repeated characters in the word "apalachicola." The word has 12 characters, with the following repetitions: 4 'a's, 2 'c's, 2 'i's, and 2 'l's.
The formula to calculate the number of distinct permutations when there are repeated characters is given by n!/ (r1! * r2! * ... * rk!), where n is the total number of characters, and r1, r2, ..., rk are the frequencies of each repeated character.
Applying the formula, we get 12!/(4!2!2!2!) = 27,720 distinct permutations of the characters in the word "apalachicola." This means that by rearranging the letters in different ways, we can form 27,720 unique combinations of the characters in the word.
In summary, there are 27,720 distinct permutations of the characters in the word "apalachicola," considering the repeated characters.
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Convert the repeating decimals 0.1313 to a fraction.
Answer:
As a fraction 0.13 (13 repeating) is 1399
Step-by-step explanation:
0.13 = 13/99
Solve each equation. -y+13=-67
The solution of the given linear equation is y = 80.
According to the given question.
We have an equation.
-y + 13 = -67
Since, we have to solve the above linear equation in variable.
As we know that, the linear equations in one variable is an equation which is expressed in the form of ax+b = 0, where a and b are two integers, and x is a variable and has only one solution.
Thereofre, the solution of the linear equation in one variable -y + 13 = -67 is given by
-y + 13 = -67
⇒ - y = -67 -13 (subtractting 13 from both the sides)
⇒ -y = -80
⇒ y = 80
Hence, the solution of the given linear equation is y = 80.
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A box is designed to hold pencils the front of the box will be made of a clear material for display. The rest of the box will be made from cardboard
Answer:
100 cm²
Step-by-step explanation:
Given that :
Length of prism = 20 cm
Height, h = 5cm
Width, w = 4 cm
The surface are of the side with clear material can be obtained by calculating the area of rectangule (front)
Area of rectangle = Length * height
Area = 20 * 5 = 100 cm²
Paula reside em uma cidade em que a densidade demográfica é igual a 5 500 hab/km2. Nessa cidade, a população está distribuída em um território de 80 km2. Qual é a população da cidade em que Paula reside? 11 078. 440 000. 880 000. 1 760 000.
Answer:
RESPOSTA:B) 440.000
Step-by-step explanation:
UMA BASICA EXPLICAÇÃO: BASTA PEGAR OS 5 500HAB/KM
E MULTIPLICAR ELE PELO TERRITORIO QUE É:80KM
5 500HAB × 80KM = 440.000
A breadth-first search (BFS) is a traversal that visits a starting vertex, then visits every vertex along each path starting from that vertex to the path's end before backtracking. True False
A breadth-first search (BFS) is a traversal algorithm that visits a starting vertex and then visits every vertex along each path starting from that vertex to the path's end before backtracking.
In a BFS, a queue is typically used to keep track of the vertices that need to be visited. The starting vertex is added to the queue, and then its adjacent vertices are added to the queue. The process continues until all vertices have been visited. This approach ensures that the traversal visits vertices in a breadth-first manner, exploring the vertices closest to the starting vertex first before moving on to the ones further away.
So, A breadth-first search (BFS) is a traversal algorithm that visits a starting vertex, then visits every vertex along each path starting from that vertex to the path's end before backtracking. This approach explores all vertices at the same level before moving on to the next level, ensuring a breadth-first exploration. Therefore, the statement is true.
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The width of a rectangle is 4cm less than the length. If each dimension were increased by 3cm, the width of the new rectangle formed would be 2/3 the length of the new rectangle. Find the dimensions of the original rectangle.
Answer:
The original length is 9 cm and the original width 5 cm
Step-by-step explanation:
The area of a rectangle A is given as the product of its' length L and width W.
Given that the width of a rectangle is 4cm less than the length then
W = L - 4
If each dimension were increased by 3cm, then the new
Length
= L + 3
Width
= W + 3
the width of the new rectangle formed would be 2/3 the length of the new rectangle
W + 3 = 2/3(L + 3)
3W + 9 = 2L + 6
3W = 2L +6 - 9
3W = 2L - 3
Recall that W = L - 4
3(L - 4) = 2L - 3
3L - 12 = 2L - 3
3L - 2L = 12 - 3
L = 9 cm
W = 9 - 4
= 5 cm