Evaluate E = t

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Answer:

he can order 2 of the extra toppings

After approximately 12.13 years, the revenue of this firm is going to drop to $1 million.

The value of shares t years after their floatation on the stock market, is modelled by V = 10e0.09t

The initial value of shares = V when t = 0. So, putting t = 0 in V = 10e0.09t,

we get

V = 10e0.09 × 0= 10e0 = 10 × 1 = 10 million dollars.

The values after 5 years, 10 years and 12 years, respectively are:

For t = 5, V = 10e0.09 × 5 ≈ 19.65 million dollarsFor t = 10, V = 10e0.09 × 10 ≈ 38.43 million dollarsFor t = 12, V = 10e0.09 × 12 ≈ 47.43 million dollars

The total revenue (TR) in t years' time is modelled as TR = 10e−0.19t (in million dollars)

The current revenue is the total revenue when t = 0.

So, putting t = 0 in TR = 10e−0.19t, we get

TR = 10e−0.19 × 0= 10e0= 10 million dollars

Revenue in 5 years' time is TR when t = 5.

So, putting t = 5 in TR = 10e−0.19t, we get

TR = 10e−0.19 × 5≈ 4.35 million dollars

To find when the revenue of this firm is going to drop to $1 million, we need to solve the equation TR = 1.

Substituting TR = 1 in TR = 10e−0.19t, we get1 = 10e−0.19t⟹ e−0.19t= 0.1

Taking natural logarithm on both sides, we get−0.19t = ln 0.1 = −2.303

Therefore, t = 2.303 ÷ 0.19 ≈ 12.13 years.

So, after approximately 12.13 years, the revenue of this firm is going to drop to $1 million.

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Answer:

Measure ment is required

Step-by-step explanation:

But for the volime for tin when it is

Cuboid= l*b*h

Cylinder=pie*radius square*height

The p-value of the test statistic is 0.0512

We can conduct a hypothesis test for the proportion using a z-test.

The null hypothesis is that the proportion of readers who own a particular make of car is equal to 70%:

H0: p = 0.7

The alternative hypothesis is that the proportion is different from 70%:

Ha: p ≠ 0.7

The test statistic is calculated as:

z = (p' - p) / sqrt(p*(1-p)/n)

where p' is the sample proportion, p is the hypothesized proportion under the null hypothesis, and n is the sample size.

Plugging in the values from the problem, we get:

z = (0.64 - 0.7) / sqrt(0.7*(1-0.7)/200) = -1.96

Using a standard normal distribution table or calculator, we can find that the probability of getting a z-score of -1.96 or lower (or 1.96 or higher) is 0.0256. Since this is a two-tailed test, we double the probability to get the p-value:

p-value = 2*0.0256 = 0.0512

Therefore, the p-value of the test statistic is 0.0512, rounded to four decimal places.

Since the p-value is greater than the commonly used significance level of 0.05, we do not reject the null hypothesis and conclude that there is not enough evidence to support the claim that the proportion of readers who own a particular make of car is different from 70%.

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By using compatible numbers, the estimate is 900

From the question, we have the following expression that can be used in our computation:

92 x 12

From the question, we are to make use of compatible numbers

This means that we have the following approximation

92 = 90

12 = 10

Next, we estimate the product using approximated values

i.e.

Product = Approximation of 92 x Approximation of 12

Substitute the known values in the above equation, so, we have the following representation

Product = 90 x 10

Evaluate the products

Product = 900

Using a calculator, we have

Product = 92 * 12

Evaluate the products

Product = 1104

900 is less than 1104

Hence, the estimate is less than the actual product

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Answer:

four less than three times a number

Answer:

Step-by-step explanation:

The rejection region in a one-tailed hypothesis test with a significance level of 0.05 is the upper 5% of the distribution. The correct answer is option A.

Thus, the rejection region in a one-tailed hypothesis test with a significance level of 0.05 is the upper 5% of the distribution.

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Answer:

22.5 degrees and 67.5 degrees

Step-by-step explanation:

complementary angles add up to 90°

x + 3x = 90°

4x = 90

90/4 = x

x = 22.5

The first angle is 22.5

The second angle is 3 times as much

22.5 x 3 = 67.5

If my answer is incorrect, pls correct me!

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-Chetan K

The value of the series is: ∑ 1/n(n+2) = lim N→∞ S(N) = 1/2.

The series ∑ 1/n(n+2)n=1 converges. To determine its value, we can use the partial fraction decomposition:

1/n(n+2) = 1/2 * (1/n - 1/(n+2))

Using this decomposition, we can rewrite the series as:

∑ 1/n(n+2) = 1/2 * (∑ 1/n - ∑ 1/(n+2))

The first series ∑ 1/n is the harmonic series, which diverges. However, the second series ∑ 1/(n+2) is a shifted version of the harmonic series, and it also diverges. But since we are subtracting a divergent series from another divergent series, we can use the limit comparison test to determine whether the original series converges or diverges. Specifically, we can compare it to the series ∑ 1/n, which we know diverges. This gives:

lim n→∞ 1/n(n+2) / 1/n = lim n→∞ (n+2)/n^2 = 0

Since the limit is less than 1, we can conclude that the series ∑ 1/n(n+2) converges. To find its value, we can evaluate the partial sums:

S(N) = 1/2 * (∑_{n=1}^N 1/n - ∑_{n=1}^N 1/(n+2))
    = 1/2 * (1/1 - 1/3 + 1/2 - 1/4 + ... + 1/(N-1) - 1/(N+1))

As N approaches infinity, the terms in the parentheses cancel out except for the first and last terms:

S(N) → 1/2 * (1 - 1/(N+1))

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Therefore, the solar flux density for mercury after the calculation is 9.12 x 10⁻³ W/m².

The solar flux density also referred to as the solar constant is the total amount of energy derived from the sun per unit area per given unit of time. It is considered to be equal to solar luminosity divided by the surface area of a given sphere that has a radius equivalent to the distance between the respective planet from the sun.

using the formula for finding the solar flux density,

solar flux density =  solar luminosity /(4 x π x distance between mercury and the sun)

solar flux density =  3.865 x \(10^{26}\) /(4 x π x ( 5.791 x \(10^{10}\)))

solar flux density = 9.12 x 10⁻³ W/m²

Therefore, the solar flux density for mercury after the calculation is 9.12 x 10⁻³ W/m².

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Answer:

\(4 \: \: ft\)

Step-by-step explanation:

\(64 = x \times x \times x \\ {x}^{3} = 64 \\ x = 4\)

to check whether the answer correct or wrong

\(x \times x \times x \\ 4 \times 4 \times 4 \\ 16 \times 4 \\ = 64\)

Answer:

-10r-32

Step-by-step explanation:

12-(3r+2)+-7(r+6)

12-3r-2-7(r+6)

12-3r-2-7r-42

-32-3r-7r

-32-10r

-10r-32

lets remember what it means compound continuously,

the interest never stopped, the balance is earning interest at all time

Joseph is 22 and he wants to know how much money he will have at 55

55-22=33

his balance will gain interest for 33 years, this is our time

there is a 7% rate

the formula is

P(t)= P(0) e ^rt

our t is 33

rate=7%

Joseph will have a balance at age 55, 45,334.99 dollars

The length L of an edge of each small cube if adjacent cubes touch but don't overlap is 3.45 nm.

The formula to be used for calculation is -

PV = Nkt, where P is pressure, V is volume, N is number of molecules, k is Boltzmann constant and T is temperature in Kelvin.

T = 273 + 27

Performing addition on Right Hand Side of the equation

T = 300 K

P = 101325 Pa

k = 1.38 × \( {10}^{-23} \) J/K

Now finding the volume

V = (1 × 1.38 × \( {10}^{-23} \) × 300)/101325

Performing multiplication and division on Right Hand Side of the equation

V = 4.09 × \( {10}^{-3} \) m³

As we know, V = L³

So, L = \( {V}^{1/3} \)

Keep the value of volume

L = \( { (4.09/1000) }^{1/3} \)

Performing calculations

L = 3.45 × \( {10}^{-9} \) m

Hence, length is 3.45 nm.

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Answer: C - If the null hypothesis is true, the probability of observing a test statistic pf 1.592 or greater is 0.059

Step-by-step explanation:

The correct interpretation of the p-value is option C. If the null hypothesis is true, the probability of observing a test statistic of 1.592 or greater is 0.059.

In hypothesis testing, the p-value helps us determine the likelihood of obtaining a test statistic at least as extreme as the one observed, assuming the null hypothesis is true. In this case, the null hypothesis (H₀) states that B1 = 0, meaning there is no relationship between the number of times a song is listened to and recording sales. The alternative hypothesis (H₁) states that B1 > 0, suggesting a positive linear relationship between the variables. Since the test is one-tailed and we are testing for a positive relationship, we are looking for a test statistic of 1.592 or greater.

Based on the given p-value of 0.059, we can conclude that if the null hypothesis is true, there is a 5.9% chance of observing a test statistic of 1.592 or greater. This helps us to assess the strength of the evidence against the null hypothesis and make a decision whether to reject or fail to reject it based on a chosen significance level.

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Answer:

20, 10,0, -10

-20, -30,

-40, -50

-60

Step-by-step explanation:

Answer:48

Step-by-step explanation:

Answer:

27

Step-by-step explanation:

3^2(2^3+4)/2^2

3^2(8+4)/2^2

3^2(12)/2^2

9(12)/4

108/4

27

Answer:

x=2

Step-by-step explanation:

isolate variable and solve for x

first you would add -x+5x and subtract 1/5 from each side

you would get 4x=40/5

multiply each side by 5

20x=40

x=2

Hence,\($V_1(f) = 0$ and $V_2(f) = 0$ for $|f| > a$.\) \($V(f) = \frac{1}{2\pi} \int_{-a}^{a} V_1(\lambda) V_2(f-\lambda) d\lambda$.\)

is the convolution formula in the irequency domain

The given functions are

\($V_1(f) = F[v_1(t)]$ and $V_2(f) = F[v_2(t)]$. Let $V(f) = F[v_1(t) v_2(t)]$.\)

We need to show that

\($V(f) = \frac{1}{2\pi} \int_{-a}^{a} V_1(\lambda) V_2(f-\lambda) d\lambda$.\)

The convolution theorem states that if f and g are two integrable functions then

\($F[f * g] = F[f] \cdot F[g]$\)

where * denotes the convolution operation. We know that the Fourier transform is a linear operator.

Therefore,

\($F[v_1(t)v_2(t)] = F[v_1(t)] * F[v_2(t)]$\)

Thus,

\($V(f) = \frac{1}{2\pi} \int_{-\infty}^{\infty} V_1(\lambda) V_2(f-\lambda) d\lambda$\)

Now we need to replace the limits of integration by a to obtain the desired result.

Since \($V_1(f)$\) and \($V_2(f)$\)are Fourier transforms of time-domain signals \($v_1(t)$\) and \($v_2(t)$,\)

respectively,

they are band-limited to \($[-a, a]$.\)

Hence,\($V_1(f) = 0$ and $V_2(f) = 0$ for $|f| > a$.\)

Therefore, \($V(f) = \frac{1}{2\pi} \int_{-a}^{a} V_1(\lambda) V_2(f-\lambda) d\lambda$.\)

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Using strong induction, we can prove that the square root of -2 is irrational by showing that it cannot be expressed as a fraction of coprime odd integers.

To prove that √-2 is irrational using strong induction, we need to show that for any natural number n, if the square root of -2 can be expressed as a fraction a/b, where a and b are coprime integers, then a and b must be odd.

We can start by using the base case, n = 1. Assume that √-2 can be expressed as a fraction a/b where a and b are coprime integers. Then, we have

√-2 = a/b

Squaring both sides gives

-2 = a^2/b^2

Multiplying both sides by b^2 gives

-2b^2 = a^2

This implies that a^2 is even, and therefore a is also even. We can express a as 2k for some integer k, which means

-2b^2 = (2k)^2

Simplifying, we get

-2b^2 = 4k^2

Dividing both sides by -2 gives

b^2 = -2k^2

This implies that b^2 is even, which means that b is also even. However, this contradicts our assumption that a and b are coprime integers. Therefore, √-2 cannot be expressed as a fraction a/b where a and b are coprime integers.

Now, let's assume that for all n ≤ k, the square root of -2 cannot be expressed as a fraction a/b where a and b are coprime integers with a and b odd. We want to prove that this also holds for n = k+1.

Assume that √-2 can be expressed as a fraction a/b where a and b are coprime integers with a and b odd. Then, we have

√-2 = a/b

Squaring both sides gives

-2 = a^2/b^2

Multiplying both sides by b^2 gives

-2b^2 = a^2

This implies that a^2 is even, and therefore a is also even. We can express a as 2k for some integer k, which means

-2b^2 = (2k)^2

Simplifying, we get

-2b^2 = 4k^2

Dividing both sides by -2 gives

b^2 = -2k^2

This implies that b^2 is even, which means that b is also even. However, this contradicts our assumption that a and b are coprime integers with a and b odd. Therefore, √-2 cannot be expressed as a fraction a/b where a and b are coprime integers with a and b odd.

By strong induction, we have proven that for any natural number n, the square root of -2 cannot be expressed as a fraction a/b where a and b are coprime integers with a and b odd. Therefore, √-2 is irrational.

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Answer:

8x^2-7x-4

Step-by-step explanation:

Answer:

8x^2 - 7x -4

Step-by-step explanation:

Answer:

1.15

Step-by-step explanation:

(1.8*10-3)/(2*10-7)

(18-3)/(20-7)

15/13

1.15

..................

You can suggest that managers should avoid the quick-fix mentality that makes management by best-seller so tempting by implementing the following strategies:

1. Understand the Unique Nature of Your Business: Managers should take the time to understand the unique nature of their business. They should realize that what worked for another company may not work for their own company.

2. Avoid Short-Term Solutions: Managers should avoid short-term solutions that provide quick results. They should focus on long-term solutions that will benefit the organization in the long run.

3. Develop a Comprehensive Strategy: Managers should develop a comprehensive strategy that includes long-term goals and objectives. They should also have a plan in place to achieve those goals.

4. Invest in Employee Development: Managers should invest in employee development by providing training and development opportunities. This will help to build a strong workforce that is capable of handling complex challenges.

5. Encourage Collaboration: Managers should encourage collaboration among team members. This will help to create a culture of teamwork and cooperation.

6. Monitor Progress: Managers should monitor progress and adjust strategies as necessary. This will help to ensure that the organization is on track to achieving its goals.

By following these strategies, managers can avoid the quick-fix mentality that makes management by best-seller so tempting. They can focus on long-term solutions that will benefit the organization in the long run.

Hope this helped you...

The new mixture exists 56.5% peanuts.

The first batch of 9 lb of mixed nuts possesses 40% peanuts.

This means the quantity of peanuts exists:

9 \(*\) 40/100 = 3.6 lb

The second batch of 9 lb of mixed nuts possesses 73% peanuts.

This means the quantity of peanuts exists:

9 \(*\) 73/100 = 6.57 lb

The total quantity of peanuts in the mix exists

3.6 lb + 6.57 lb = 10.17 lb

There exist 9 lb + 9 lb = 18 lb of mix.

Therefore, the percent of peanuts in the mix exists:

10.17 / 18 \(*\) 100 = 56.5%

The new mixture exists 56.5% peanuts.

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Answer:

80 m high and 157 m away

hope this helped