Estimate the irrigation interval for mature fruit trees planted at a 4m x 7m spacing in a fine sand soil with a total available water content (TAW) of o.o6 cm/cm and a managed root zone of 1.0m. Assume that the average daily evapotranspiration is 6mm/d occuring during the critical bloom period when soil water depletion should be limited to less than 1/3 of available water. Each tree has a single micro-sprinkler that discharges 40 L/h and with a circle 4.5m in diameter. At each irrigation, the soil is field capacity (FC). Analyze the given information and calculate the water use per tree assuming the 6mm application is equally distributed among trees.
Answers
For mature fruit trees planted at a 4m x 7m spacing in fine sand soil with a TAW of 0.06 cm/cm and a managed root zone of 1.0m, the estimated irrigation interval is every 9 hours, with each tree receiving 2671.20 liters of water per day assuming equal distribution among trees.
To calculate the water use per tree and estimate the irrigation interval, we need to consider the following information:
Tree Spacing: The trees are planted at a spacing of 4m x 7m, resulting in a density of approximately 1 tree per 28 square meters.
Total Available Water (TAW): The fine sand soil has a TAW of 0.06 cm/cm, which represents the amount of water available to the plants in the root zone.
Managed Root Zone: The managed root zone depth is 1.0m, indicating the depth at which the plant's roots can access water.
Average Daily Evapotranspiration (ET): The average daily ET during the critical bloom period is 6mm/d, representing the amount of water lost through evaporation and plant transpiration.
Soil Water Depletion: The soil water depletion during the critical bloom period should be limited to less than 1/3 of the available water (TAW/3) to avoid excessive stress on the plants.
Micro-sprinkler Discharge: Each tree is equipped with a micro-sprinkler that discharges 40 L/h and has a wetted circle with a diameter of 4.5m.
To calculate the water use per tree assuming the 6mm application is equally distributed among trees, we can follow these steps:
Calculate the area covered by each tree: Since the wetted circle has a diameter of 4.5m, the area covered is πr^2, where r = 4.5m/2 = 2.25m. Therefore, the area covered by each tree is approximately 15.90 square meters.
Determine the water applied per tree: Given that the average daily ET is 6mm/d and the irrigation water should be equally distributed among the trees, we can divide the ET by the number of trees per square meter (1/28) to get the water applied per tree. Thus, the water applied per tree is approximately (6mm/d)/(1/28) = 168 mm/d.
Convert the water applied per tree to liters: To convert the water applied from millimeters to liters, we need to multiply by the area covered by each tree. Therefore, the water applied per tree is approximately 168 mm/d * 15.90 m^2 = 2671.20 liters/d.
Based on the water use per tree, we can estimate the irrigation interval. Assuming the soil is at field capacity after each irrigation, we divide the managed root zone depth (1.0m) by the water applied per tree (2671.20 liters/d) to get the irrigation interval. Thus, the estimated irrigation interval for mature fruit trees in this scenario is approximately 0.374 days, or roughly every 9 hours.
Therefore, These calculations provide an estimate, and actual irrigation practices may vary based on local conditions and specific crop requirements.
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Related Questions
If a body of mass 4 kg moves at a velocity of 25 m/s and has a completely inelastic collision with a body of mass 10 kg, the final velocities of both the bodies is 14 m/s. Calculate the initial velocity of the body of mass 10 kg.
Answers
We are given the following information about an inelastic collision.
Mass of 1st object = 4 kg
Mass of 2nd object = 10 kg
Initial velocity of 1st object = 25 m/s
Final velocity of both objects = 14 m/s
Initial velocity of 2nd object = ?
In an inelastic collision, the momentum is conserved but the kinetic energy is not conserved.
Recall that the total momentum is conserved and given by
\(m_1u_1+m_2u_2=(m_1+m_2)v_2\)Let us substitute the given values and solve for initial velocity of the body (u2)
\(\begin{gathered} m_1u_1+m_2u_2=(m_1+m_2)v_2 \\ 4\cdot25+10\cdot u_2=(4+10)\cdot14 \\ 100+10\cdot u_2=196 \\ 10\cdot u_2=196-100 \\ 10\cdot u_2=96 \\ u_2=\frac{96}{10} \\ u_2=9.6\; \frac{m}{s} \end{gathered}\)Therefore, the initial velocity of the body of mass 10 kg is 9.6 m/s
what applied horizontal force will accelerate a 400-kg crate at 1 m/s2 across a factory floor against a friction force half its weight?
Answers
Answer:
The applied horizontal force that will accelerate a 400-kg crate at 1 m/s2 across a factory floor against a friction force half its weight is 800 N.
Explanation:
The friction force is given by:
F_f = μmg
F_f = μmg = 0.5 * 400 kg * 9.8 m/s² = 1960 N
The net force on the crate is given by:
F_net = F_a - F_f
The net force is equal to the mass of the crate times its acceleration, so:
m * a = F_a - F_f
400 kg * 1 m/s² = F_a - 1960 N
F_a = 400 kg * 1 m/s² + 1960 N = 800 N
Therefore, the applied horizontal force that will accelerate a 400-kg crate at 1 m/s2 across a factory floor against a friction force half its weight is 800 N.
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You are designing a spaceship, and you want it to have an artificial gravity of 9.8 m/s2 at the center of mass of an average human. The average human has a center of gravity that is about 90 cm above their feet. Through other engineering constraints, you have determined the rotational speed of the ship to be 0.2 rad/s. What should the radius of the ship be (in m)? (Round your answer to the nearest whole number!)
Answers
Answer:
The tangential acceleration is 0 m/s².
Explanation:
Answer:
The tangential acceleration is 0 m/s².
Explanation:
Ash is working in the lab, and comes across a box of unlabeled resistors (thanks to his messy coworker who never puts them back properly).
He remembers that he can find out the resistance using an ammeter to measure current, and a battery with a known voltage.
Ash picks a resistor of unknown resistance (in Ω), connects it to some wires, and then plugs in a battery with a voltage of 29.7 V. This creates a circuit. Using the ammeter, he finds that the current in the circuit is 4.8 A.
In ohms, what is the resistance of the unknown resistor?
Answer: _____Ω.
Answers
In ohms, the resistance of the unknown resistor is 6.19 amps.
What is the ohm's law?Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points.
Therefore in ohm's law, V = IR
V = voltage
I = current
R = resistance
To calculate the resistance, we have
R = V/I
where Voltage = 29.7
Current , I = 4.8
Resistance= 29.7/ 4.8 = 6.19 amps
In conclusion, Ohm's Law is a formula used to calculate the relationship between voltage, current and resistance in an electrical circuit.
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what value does the image distance approach as the object distance becomes larger? what value does the object
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As the object distance becomes larger, the image distance approaches the focal length of the lens, while the object distance approaches infinity.
What is the value approached by the image distance as the object distance increases?In optics, the relationship between object distance (u), image distance (v), and focal length (f) is given by the lens equation, 1/f = 1/v + 1/u. When the object distance becomes much larger than the focal length, i.e., u >> f, the image distance v approaches the focal length f. This means that the image is formed at a distance from the lens that is approximately equal to the focal length. On the other hand, as the object distance approaches infinity, the image distance approaches the same value as the focal length. This phenomenon is known as the "far point" of the lens and is used to correct for certain types of vision problems, such as nearsightedness.
Therefore, As the object distance becomes larger, the image distance approaches the focal length of the lens, while the object distance approaches infinity.
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would force of gravity be big or small when an object has a seperation distance in 1 meter
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The final gravitational force will be 1/16th of the initial gravitational force. In other words, the gravitational force will decrease when the objects are moved from 1 meter apart to 4 meters apart.
The gravitational force between two objects depends on their masses and the distance between them. According to Newton's law of universal gravitation, the force is inversely proportional to the square of the distance between the objects and directly proportional to the product of their masses.
Let's assume that the masses of the objects remain constant. If the objects are initially placed 1 meter apart and then moved to a distance of 4 meters, we can calculate how the gravitational force changes.
The formula for the gravitational force is:
F = G * (m1 * m2) / r^2
Where:
F is the gravitational force between the objects.
G is the gravitational constant.
m1 and m2 are the masses of the objects.
r is the distance between the objects.
Assuming the masses and the gravitational constant remain constant, we can compare the initial and final gravitational forces.
Let's denote the initial force as F_initial and the final force as F_final. Using the formula above, we can calculate the ratio of the final force to the initial force:
F_final / F_initial = (G * (m1 * m2) / (4^2)) / (G * (m1 * m2) / (1^2))
= (1 / 16) / (1 / 1)
= 1 / 16
This decrease in the gravitational force is a result of the inverse square law. As the distance between the objects increases, the force weakens exponentially. In this case, the force decreases by a factor of 16 because the distance is quadrupled (from 1 meter to 4 meters).
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The probable question may be:
2 objects are initially placed 1 meter apart. By how much will the gravitational force between the objects change if they are moved to 4 meter apart? Explain and state whether it will increase of decrease.
The peak current through a capacitor is 2.0 A. What is the peak current if the capacitance C is doubled?
Answers
If the capacitance is doubled, the peak current will be halved. Therefore, the peak current through the capacitor will be 2.0 A if the capacitance is doubled.
This relationship is governed by the equation for the current in a capacitor in an AC circuit, which is given by:
I = C × dV/dt,
where I is current, C is the capacitance, and dV/dt is the rate of change of voltage with respect to time.
Assuming other factors remain constant if the capacitance is doubled (2C), the equation becomes:
I' = (2C) × dV/dt.
Since dv/dt remains unchanged, we can simplify the equation to:
I' = 2 × (C × dV/dt).
This indicates that the peak current (I') will be twice the original value if the capacitance is doubled (2C).
Therefore, if the original peak current through a capacitor is 1.0 A when the capacitance is doubled, the new peak current will be 2.0 A.
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A contour map has 14 concentric circles, each placed 1/2 centimeters apart. The map's scale indicates 1cm = 10 ft. What is the structure, and what are its dimensions?
Answers
Answer:
B. A hill 70ft tall.
Explanation:
What acceleration does the force of earth's gravity peoduce
Answers
Match each compound name with the correct chemical formula. Drag the items on the left to the correct location on the right. can someone help me with the last 3 please
Answers
Each compound name with chemical formula:
Silicon tetrafluoride - SiF₄
Potassium sulfite - K₂SO₃
Diphosphorous trisulfide - P₂S₃
Siver(II) fluoride - AgF₂
Magnesium perchlorate - Mg(ClO₄)₂
What is chemical formula?A compound's constituent elements and their relative proportions are listed in a chemical formula. No subscript is used when there is only one atom of a particular type. A subscript is added to the symbol for the atom when there are two or more of a particular type of atom present.
A chemical formula lists the constituent elements of a compound along with how many atoms of each are present in the compound's smallest unit, whether it be a molecule or a formula unit. We can name simple compounds given their chemical formulas by using the names of the elements and a few simple rules.
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What is the value of the total orbital angular momentum (L), the total spin (S) and the total angular momentum (J) in the ground state of Ca, O, Ni
Answers
The ground state of an atom refers to the lowest energy level occupied by its electrons. In the case of Calcium (Ca), Oxygen (O), and Nickel (Ni), the values of their respective total orbital angular momentum (L), total spin (S), and total angular momentum (J) can be determined by applying Hund's rules and the Pauli exclusion principle.
For Ca, the electron configuration of the ground state is 1s2 2s2 2p6 3s2 3p6 4s2. Since the 4s orbital is the highest energy level occupied, the total orbital angular momentum (L) is equal to 0. The total spin (S) is equal to 1/2, as there are two unpaired electrons in the 4s orbital. The total angular momentum (J) is therefore equal to 1/2.
For O, the electron configuration of the ground state is 1s2 2s2 2p4. The total orbital angular momentum (L) is equal to 1, as there are two unpaired electrons in the 2p orbital. The total spin (S) is equal to 1, as there are two unpaired electrons with opposite spins in the 2p orbital. The total angular momentum (J) is therefore equal to 0, since L and S cancel out.
For Ni, the electron configuration of the ground state is 1s2 2s2 2p6 3s2 3p6 4s2 3d8. The total orbital angular momentum (L) is equal to 2, as there are eight unpaired electrons in the 3d orbital. The total spin (S) is equal to 1, as there are two unpaired electrons with opposite spins in the 3d orbital. The total angular momentum (J) is therefore equal to 3, since L and S combine.
In summary, the values of L, S, and J in the ground state of Ca, O, and Ni can be determined by analyzing their electron configurations and applying the appropriate principles. These values provide insights into the behavior and properties of these elements in chemical reactions and other physical processes.
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Particles q1 = -20.5 UC, q2 = -9.30 uC, and q3 = -31.6.0 uC are in a line. Particles q, and q2 are separated by 0.980 m and particles q2 and q3 are separated by 0.750 m. What is the net force on particle q2?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
Answers
The net force on particle q2 can be calculated by finding the net electric force acting on it. The net electric force acting on a particle is the vector sum of the forces exerted by all the other charges on it.
The electric force between two charges q1 and q2 is given by Coulomb's law: F = k * (q1 * q2)/r^2, where k is Coulomb's constant, q1 and q2 are the charges, and r is the distance between them.
The force on particle q2 due to q1 will be:
F1 = k * (q1 * q2) / (0.980m)^2
The force on particle q2 due to q3 will be:
F2 = k * (q2 * q3) / (0.750m)^2
The net force acting on q2 will be the vector sum of F1 and F2.
Keep in mind, q1 and q3 have opposite charges, so they attract each other, while q2 has the same charge as q1, so they repel each other.
Note: The unit of charge is Coulomb (C), but in this problem you are given the charges in microCoulomb (uC) so you need to convert it to Coulomb.
What type of sensor was used to utilize to measure the force of a hand grip or pinch?
Answers
The type of sensor commonly used to measure the force of a hand grip or pinch is called a force sensor or load cell. These sensors convert mechanical force into an electrical signal that can be measured and analyzed. They can be placed within a hand grip device or attached to a surface where the force is being applied, such as a pinch gauge.
Some common types of force sensors used for hand grip and pinch measurement include strain gauges, piezoelectric sensors, and capacitive sensors.
A common type of sensor used to measure the force of a hand grip or pinch is a "force-sensitive resistor" (FSR). This sensor detects changes in resistance based on the pressure applied to it, allowing it to quantify the force exerted during a hand grip or pinch action.
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The nurse assessing an 11-year-old who is having an asthma attack expects to hear adventitious sounds of:_______
Answers
The nurse assessing an 11-year-old who is having an allergies attack expects to hear adventitious sounds of: sibilant wheezes.
Can asthma can be cured?
There's no therapy for asthma. However, it is a especially treatable disease. In fact, some medical doctors say modern day allergies remedies are so effective, many humans have near-complete manipulate of their symptoms
What can be the cause of asthma?Exposure to more than a few irritants and components that set off allergies (allergens) can set off signs and symptoms of asthma.
Asthma triggers are exceptional from character to man or woman and can include: Airborne allergens, such as pollen, dirt mites, mould spores, pet dander or particles of cockroach waste.
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https://brainly.com/question/8473800#SPJ4How much energy is required to move an electron through a potential difference of
12 V?
1) 1.9 x 10^- 18 )
2) 7.5 x 10^- 18 )
3) 1.3 x 10^-20)
4) 7.5 x 10^18 J
Answers
Answer with full steps please!
Answers
Answer:
B
Explanation:
Because B/5
if i'm wrong sorry but i hope it's help^^
A student working with a transmitting apparatus like Heinrich Hertz's wishes to adjust the electrodes to generate electromagnetic waves with a frequency half as large as before.(ii) After she makes the required adjustment, what will the wavelength of the transmitted wave be? Choose from the same possibilities as in part (i).
Answers
The wavelength of the transmitted wave after the adjustment will be twice the wavelength of the original wave.
In part (i), it was mentioned that the student wants to adjust the electrodes to generate electromagnetic waves with a certain frequency. Let's denote this frequency as f.
(i) The original frequency of the electromagnetic waves is f.
(ii) The student wants to generate electromagnetic waves with a frequency half as large as before, which is f/2.
The relationship between frequency (f), wavelength (λ), and the speed of light (c) is given by the equation:
c = f *
where c is the speed of light, which is a constant.
Since the speed of light remains constant, we can write:
c = (f/2) * λ'
where λ' represents the new wavelength.
To find the new wavelength, we rearrange the equation:
λ' = (2 * c) / f
Since the speed of light (c) is a constant, and the frequency is halved (f/2), the new wavelength (λ') will be twice the original wavelength (λ).
Therefore, the wavelength of the transmitted wave after the adjustment will be twice the wavelength of the original wave.
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Why is gravity so weird?
Will mark as brain list
Answers
Answer:
No force is more familiar than gravity — it's what keeps our feet on the ground, after all. And Einstein's theory of general relativity gives a mathematical formulation for gravity, describing it as a “warping” of space.
define transition element
Answers
Answer:
Explanation:
In chemistry, the term transition metal has three possible definitions: The IUPAC definition defines a transition metal as "an element whose atom has a partially filled d sub-shell, or which can give rise to cations with an incomplete d sub-shell".
Answer:
Transition elements (also known as transition metals)
Explanation:
are elements that have partially filled d orbitals. IUPAC defines transition elements as an element having a d subshell that is partially filled with electrons, or an element that has the ability to form stable cations with an incompletely filled d orbital.
Which of the following describes how energy is transferred in a wave? (select all that apply)
Answers
Energy transfer will be greater if the amplitude of the wave is greater.
The particles of the medium vibrate until they transfer the energy and after transferring energy, they return back to their equilibrium position.
Thus, options 3 and 4 are correct.
2) How could a motorcycle (a vehicle with less mass) make a van (a
vehicle with more mass) move? *
Answers
it depends upon what state they are in like in motion or res
Why does a dropped object only fall 5 meters down after 1 second of freefall, yet achieve a speed of 10m/s?
Answers
A dropped object only fall 5 meters down after 1 second of freefall, yet achieve a speed of 10m/s due to acceleration due to gravity.
s = vt - 1 / 2 at²
s = Displacement
v = Final velocity
t = Time
a = Acceleration
s = 5 m
t = 1 s
a = 10 m / s²
5 = ( v * 1 ) - ( 1 / 2 * 10 * 1 * 1 )
5 = v - 5
v = 10 m / s
The equation used to solve the given problem is an equation of motion. In a free fall motion, usually air resistance is not considered for easier calculation. If air resistance is considered acceleration cannot be constant throughout the entire motion.
Therefore, a dropped object only fall 5 meters down after 1 second of freefall, yet achieve a speed of 10m/s due to acceleration due to gravity.
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Why do you think it's important for us to go into such detail on electromagnetic radiation in an astronomy class? Hints: How do we typically detect electromagnetic radiation? Do you foresee any challenges in detecting other kinds of information from astronomical objects?
Answers
Understanding electromagnetic radiation in detail is important in an astronomy class because it is the primary way we detect and study objects in the universe.
Electromagnetic radiation provides crucial information about the properties, composition, and behavior of celestial objects.Detecting other kinds of information from astronomical objects may present challenges due to the limitations of our current technology and the nature of the objects themselves.In astronomy, electromagnetic radiation is the primary means by which we gather information about celestial objects. We typically detect electromagnetic radiation using telescopes and specialized instruments that can capture different wavelengths, such as visible light, radio waves, X-rays, and gamma rays.
By studying the properties of electromagnetic radiation emitted or absorbed by celestial objects, astronomers can gather valuable data about their temperature, composition, motion, and energy.
Detailed knowledge of electromagnetic radiation is crucial because it allows astronomers to interpret and analyze the information received from astronomical observations. By understanding the behavior and characteristics of different types of electromagnetic radiation, astronomers can infer properties like temperature, distance, chemical composition, and even the presence of magnetic fields or energetic events such as supernovae or black holes.
This knowledge helps us build a comprehensive understanding of the universe and the objects within it.
While electromagnetic radiation provides a wealth of information, there are challenges in detecting other kinds of information from astronomical objects. Some types of information, such as gravitational waves or neutrinos, require specialized detectors and observatories that are still in the early stages of development.
These detection methods often require sophisticated technology and precise measurements due to the elusive nature of these signals. Additionally, some astronomical phenomena, such as dark matter or dark energy, cannot be directly detected using electromagnetic radiation and require indirect methods to study their effects on visible matter and light.
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A ball is at the top of the hill. As the ball rolls down the hill, its total mechanical energy will:
Answers
Answer:
To explain what happens with the ball we must remember the Law of Conservation of Energy.
This law states that the energy can be neither created nor destroyed only converted from one form of energy to another.
Then,
At the top of the hill, the potential energy is maximum and the kinetic energy equals to zero.
When the ball starts to roll down the potential energy will be lower and the kinetic energy will have a low value.
At the middle of the hill, both energies have the same values.
At the end of the hill, the potential energy will be equal to zero and the kinetic energy will be maximum.
Correct me if I'm wrong...
hope it helps...
A Carnot heat engine uses a hot reservoir consisting of a large amount of boiling water and a cold reservoir consisting of a large tub of ice and water. In 5 minutes of operation of the engine, the heat rejected by the engine melts a mass of ice equal to 5.00x10-2 kg . Part A During this time, how much work W is performed by the engine?
Answers
The amount of work W is performed by the engine if the mass of ice melted is 5.00 × 10⁻² kg and the time of operation is 5 minutes is 44.12 J.
To calculate the heat absorbed from the hot reservoir by the heat engine using the formula:
q₁ = m × L
Where L is the latent heat of the fusion of ice, which is 3.33 × 10⁵ J/kg.
Therefore:
q₁ = m × Lq₁ = (5.00 × 10⁻²) × (3.33 × 10⁵)
q₁ = 166.5 J
Now, let's calculate the work done by the heat engine using the formula:
η = W/q₁
Where η is the efficiency of the engine, which is given as the Carnot cycle. Hence,
η = (T₁ - T₂)/T1
Where T₁ is the temperature of the hot reservoir (boiling water), and T₂ is the temperature of the cold reservoir (ice and water mixture).
Hence,
η = (373 - 273)/(373)
η = 0.265 or 26.5%
This is the efficiency of the engine, and thus:
η = W/q₁
W = η × q₁
W = (0.265) × (166.5)
W = 44.12 J
Therefore, the work performed by the engine is 44.12 J.
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Energy is the energy an object has because of its motion. True or False
Answers
That depends on what word you skipped at the beginning of the question.
If it's supposed to be "Potential" energy, then the statement is false.**
If It's supposed to be "Kinetic" energy, then the statement is true.
** It's also false if the missing word is "Chemical", "Mechanical", "Thermal", "Nuclear", "Electrical", "Electromagnetic", or "Nervous".)
A sample of 0.351 mol of a metal M
reacts completely with excess fluorine to form 27.4 g of M
F
2
. Identify the metal M
.
Answers
The metal M in the given reaction is likely Calcium (Ca).
To identify the metal M, we need to determine its atomic mass and the atomic mass of M can be calculated using molar mass of MF₂.
The molar mass of MF₂ can be calculated as:
Molar mass of MF₂ = Molar mass of M + 2 × Molar mass of F
= M + 2 × 18.998 g/mol
= M + 37.996 g/mol
Given, mass of MF₂ formed = 27.4 g
We know that 0.351 mol of M reacts with excess fluorine to form 27.4 g of MF₂. Therefore, we can use the molar mass of MF₂ and the mass of MF₂ formed to find the moles of MF₂ as;
27.4 g / (M + 37.996 g/mol) = 0.351 mol
M + 37.996 = 27.4 / 0.351
Solving for M, we get:
M = (27.4 / 0.351) - 37.996
= 40.07 g/mol
Therefore, the metal M has an atomic mass of 40.07 g/mol. Looking at the periodic table, we see that the only metal with a similar atomic mass is Ca (Calcium).
Therefore, the metal M is likely Calcium (Ca).
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As a wave moved from one medium to another there was a change in the wave’s speed. If the frequency of the wave does not change, what property of the wave must change, causing the change in speed?
Answers
Answer:
V = f λ expresses wave speed where f is frequency and λ wavelength
If the frequency is unchanged across the boundary then the wavelength must change to account for the change in speed.
i) Show that total energy of the body at points A, B and C during the fall is same. ii) Find the distance from A to B and final velocity of the ball just reach before C. mass =5 kg, total height (h)= 100m
Answers
The total energy of the body at evevry point is remained same due to the law of conservation of energy. Distance from A to B and final velocity of the ball just reach before C is 44.3 m/s.
d (distance) from A to B is = √2gh
In this case given are, g = 9.8 m/s² and h = 100m,
so here d = √(2⋅9.8⋅100) = 44.3m.
Final velocity ,v = √2gh
Here given are , v is the velocity, g is the acceleration due to gravity, and h is the height. In this case,
g = 9.8 m/s² ,h = 100m,
v = √(2⋅9.8⋅100)
= 44.3 m/s (final velocity)
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Why aren’t the Appalachian Mountains still as tall as the Himalayas?
Answers
Answer:
mountains are limited in their theoretical height by several processes. First is isostasy: the bigger a mountain gets, the more it weighs down its tectonic plate, so it sinks lower. ... Bottom line: mountains can get taller than Mount Everest in earth gravity, like the Appalachians probably did—but not much taller.
Answer:
It probably won't get any taller, though. From a geological standpoint, the Appalachians haven't seen much growth in quite a while. Since the dawn of the dinosaurs about 225 million years ago, this range has been getting whittled down by weathering forces.
Explanation: