Without going above the maximum permitted radial acceleration, the flywheel can store a maximum of kinetic energy of 7,000 J.
The maximum permitted radial acceleration of a location on the flywheel's rim must be taken into account in order to calculate the maximum amount of kinetic energy that can be stored there.
This is crucial because if the acceleration goes beyond this point, the flywheel may distort or even disintegrate.
We can use the formula to determine the maximum permitted radial acceleration.
a = \(v^2\) / r
where a is the radial acceleration,
v is the velocity of a point on the rim, and
r is the radius of the flywheel.
Rearranging the formula, we get
v = \(\sqrt{(ar)}\)
where the square root function is represented by sqrt.
Now that we know the radial acceleration limit, we can figure out the highest velocity that a spot on the rim can reach.
Assume that 100 rad/s is the maximum permitted radial acceleration. (this value can vary depending on the specific design and materials of the flywheel).
Using this number and the flywheel's radius, which is assumed to be 0.5 meters, we obtain
v = \(\sqrt{(100 \times 0.5)}\) = 10 m/s.
Next, we can use the formula to determine the maximum kinetic energy that the flywheel can store.
E = 1/2 x I x \(w^2\)
where w is the angular velocity,
I is the flywheel's moment of inertia, and
E is the kinetic energy.
The moment of inertia for a solid disc is 1/2 x m x \(r^2\)
where m is the mass of the flywheel and
r is the radius.
Plugging in the values (m = 70.0 kg, r = 0.5 m), we get I = 8.75 kg \(m^2\).
The maximum angle at which the flywheel can rotate before a spot on the rim's velocity exceeds the predetermined limit must now be determined.
Since the angular velocity times the radius are equivalent to the linear velocity of a point on the rim, we obtain
w x r = 10 m/s.
Solving for w, we get w = 20 rad/s.
Finally, we can calculate the maximum kinetic energy using the formula
E = 1/2 x I x \(w^2\)
Putting the values in (I = 8.75 kg \(m^2\), w = 20 rad/s),
we get E = 7,000 J.
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what is the difference between a galaxy and a star
The main difference between a galaxy and a star lies in their size, composition, and structure.
A star is a luminous sphere of plasma held together by its own gravity. Stars generate energy through nuclear fusion in their cores, primarily converting hydrogen into helium. They emit light and heat, appearing as individual points of light in the night sky. Stars come in various sizes, ranging from relatively small ones like our Sun to massive giants.
On the other hand, a galaxy is a vast collection of stars, gas, dust, and other celestial objects bound together by gravitational forces. Galaxies can be enormous, containing billions or even trillions of stars. They come in different shapes and sizes, such as spiral, elliptical, or irregular. Galaxies also contain other components like nebulae, stellar clusters, and dark matter.
While stars are found within galaxies, galaxies themselves are distinct entities that contain numerous stars. Galaxies are often considered as separate systems with their own structures and dynamics, while stars are individual celestial bodies that are part of these larger galactic systems.
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A monorail train traveling at 44 m/s must be stopped in a distance of 220 m. What average acceleration is required, and what is the stopping time?
Answer: The average acceleration required to stop the monorail train is approximately -4.4 m/s².
The stopping time of the monorail train is approximately 10 seconds.
Explanation:
To find the average acceleration required to stop the monorail train, we can use the equation:
v²-u² = 2as
where:
- v is the final velocity (0 m/s, as the train finally stops)
- u is the initial velocity (44 m/s) (given)
- a is the average acceleration
- s is the distance covered (220 m) (given)
Substituting the acquired values:
→0² = 44² + 2a(220)
Simplifying the equation:
→0 = 1936 + 440a
Rearranging the equation:
→440a = -1936
→a = -1936÷440
→ a = -4.4 m/s² (approx.)
∴The average acceleration required to stop the monorail train is approximately -4.4 m/s².
To find the stopping time, we can use the equation:
v = u + at
where:
- v is the final velocity (0 m/s)
- u is the initial velocity (44 m/s)
- a is the average acceleration -4.4m/s²
- t is the stopping time (To Find)
Substituting the known values:
→0 = 44 + (-4.4)t
Simplifying the equation:
→ -4.4t = -44
→t = -44÷ (-4.4)
→ t = 10 sec (approx.)
∴The stopping time of the monorail train is approximately 10 seconds.
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A 24 kg crate is moving at a constant speed because it is being pushed with a force of 53n. What would be the coefficient of kinetic friction between the crate and the floor?
Answer:
The coefficient of kinetic friction between the crate and the floor can be calculated using the formula μ = Ff / N, where Ff is the frictional force, N is the normal force, and μ is the coefficient of kinetic friction.
In this case, the normal force is equal to the weight of the crate, which is 24 kg * 9.8 m/s2 = 235.2 N. The frictional force can be calculated using the formula Ff = μ * N, where μ is the coefficient of kinetic friction and N is the normal force.
If we substitute the values for N and Ff into the formula for the coefficient of kinetic friction, we get:μ = 53 N / 235.2 N = 0.225
Therefore, the coefficient of kinetic friction between the crate and the floor is 0.225.
4) An astronaut drops a hammer from 2.0 meters above the surface of the
moon. If the acceleration due to gravity on the moon is 1.62 m/s2, how long
will it take for the hammer to fall to the Moon's surface? (Show your work)
Answer: The time, t, is approximately 1.57 seconds
Explanation:
The data we have from the question;
Displacement = 2.0 meters
Acceleration due to gravity on the moon = 1.62
Initial velocity = 0 m/s
We can use the second equation of motion for this one;
S = ut + 1/2at²
Where:
- S is the displacement.
- u is the initial velocity.
- a is the acceleration.
- t is the time measured in seconds.
We are now ready to substitute;
2 = 0(t) + 1/2(1.62)t²
==> 2 = 0 + 0.81t²
==> 2/0.81 = 0.81t²/0.81
==> \(\sqrt{2.47}\) = \(\sqrt{t ^{2}\)
==> The time, t, is approximately 1.57 seconds
Hope this helped! Have a good day :D
find the relationship between the height at which the ball is released and distance it rolls along the artificial turf it stops
Answer:
The height at which a ball is released affects its rolling distance on artificial turf. Factors such as the angle of release, initial velocity, surface characteristics of the turf, and friction play a role. Generally, a higher release height gives the ball more potential energy, converting to kinetic energy as it moves towards the turf, resulting in a longer rolling distance. However, air resistance and turf surface characteristics can affect the rolling distance. Wind can also be a factor. Therefore, the relationship is complex and dependent on multiple factors.
WORK ENERGY & POWER CROSSWORD
NEED HELP ASAP
To complete the energy crossword puzzle, fix the meanings with the relevant definitions provided. For instance,
2. The four sources of all energy are Electricity, renewables, fossils, and nuclear power.
4. It is impossible for any machine to be 100% efficient
5. The name sometimes given to the sum of potential and kinetic energy is Mechanical energy.
How to fill a crossword puzzleTo fill a crossword puzzle, you have to follow the clues provided in the text. For example, the first clue shows that the word or words for box 2 are or are related to the four sources of all energy.
Also, the word in the 4th box will be impossible because it is impossible for any machine to be 100% efficient.
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A film with maximum contrast is required. The original technique is: 80 kV; 20 mAs; all other factors being equal. In order to enhance the contrast, the new technique should be: O 70 kV; 15 mAs O 70 kV; 30 mAs O 80 kV; 15 mAs O 60 kV; 60 mAs
The correct option for maximizing contrast is 70 kV and 15 mAs. A film with maximum contrast requires a new technique that involves the reduction of kV and mAs parameters. The new technique should be 70 kV and 15 mAs.
Radiography is a technique that enables the creation of medical images of the human body, using an X-ray beam. X-rays are an example of ionizing radiation, and their interaction with the tissues in the body results in the formation of an image. Contrast is the difference in tone between adjacent areas in the image, and it is essential to obtain high contrast in radiography, to ensure the visualization of the structures of interest and to make it possible to detect abnormalities.
Maximizing contrast is a common technique used in radiography, and it involves the adjustment of parameters such as kV, mAs, and exposure time. A high-contrast image can be achieved by reducing kV and mAs and increasing exposure time. The kV and mAs settings are the most important variables to adjust to enhance contrast. A high-kV setting will result in a low-contrast image, while a low-kV setting will produce a high-contrast image.In the given scenario, the original technique is 80 kV and 20 mAs, and all other factors are equal. To enhance the contrast, the new technique should be a combination of reduced kV and mAs. The possible options for a new technique are:
70 kV and 15 mAs70 kV and 30 mAs80 kV and 15 mAs60 kV and 60 mAs
The best option for maximizing contrast is the first option, which is 70 kV and 15 mAs. This is because the kV value has been reduced by 10, and the mAs has been reduced by 5, which will result in an increase in contrast.
The new technique to enhance contrast requires a reduction in kV and m As parameters, and the best option for maximizing contrast is 70 kV and 15 mAs.
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A grinding wheel starts from rest and reaches an angular speed of 30 rad/s after turning through 13 revolutions. What is the angular acceleration if the angular acceleration is constant
The angular acceleration of the grinding wheel is approximately 43.2 rad/s².
The angular acceleration of the grinding wheel can be found using the following formula:
angular acceleration = (final angular speed - initial angular speed) / time
To use this formula, we need to determine the initial angular speed and the time it takes for the wheel to turn through 13 revolutions.
The initial angular speed is zero, since the wheel starts from rest. To find the time it takes for the wheel to turn through 13 revolutions, we need to know the angle turned in radians. One revolution is equal to 2π radians, so 13 revolutions is equal to 26π radians.
We can use the following formula to find the time it takes to turn through a given angle at a constant angular acceleration:
time = (final angular speed - initial angular speed) / angular acceleration
Since the initial angular speed is zero, this formula simplifies to:
time = final angular speed / angular acceleration
Plugging in the given values, we get:
time = 26π / 30
time = 13π / 15 seconds
Now we can calculate the angular acceleration:
angular acceleration = (30 - 0) / (13π / 15)
angular acceleration = 450 / 13π
angular acceleration ≈ 43.2 rad/s²
Therefore, the angular acceleration of the grinding wheel is approximately 43.2 rad/s².
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i need to speak with zuka
Answer:
DMs are not accessible anymore. I assume Zuka is a staff member? the only way to talk to a staff member anymore is to report something, but even then, the probably won't even look at what they're deleting :/
May I have brainliest please? :)
suppose that each component of a vector is doubled, does the magnitude of the vector increase, decrease, or stay the same
The magnitude of a vector does not change if each of its components is doubled. Therefore, the answer is, "stay the same". This is due to the Pythagorean Theorem, which states that the magnitude of a vector is determined by the square root of the sum of the squares of its components.
Because the square of a number is greater than the number itself, squaring each component and then taking the square root of the sum results in the same magnitude as before.
Let's suppose that the vector is defined as follows: a = (a₁, a₂, a₃)
The magnitude of this vector is given by the following formula:|a| = √(a₁² + a₂² + a₃²)
Now suppose that each component is doubled. Then the new vector b is defined as follows: b = (2a₁, 2a₂, 2a₃)
The magnitude of this vector is given by the following formula: |b| = √(4a₁² + 4a₂² + 4a₃²)
Notice that each term under the square root has been multiplied by 4. However, this is balanced out by the fact that we are taking the square root of the sum. Thus, we can factor out the 4 and simplify as follows:|b| = 2√(a₁² + a₂² + a₃²)
This expression is twice the magnitude of the original vector a.
Therefore, we conclude that doubling each component of a vector doubles its magnitude. Therefore, the answer is, "stay the same".
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Whats the answer to 10a² - 6ab + 10 -2a² - 4ab +15b?
Question 17 (Essay Worth 5 points)
(02.06 HC)
Choose two spheres of Earth which interact when hot springs are formed. Use complete sentences to explain how they interact during this process
X2
= 12 Source
ус
cM
В І
U S XX T
.
Styles
Format
Font
Size
A- A -
Increase Indent
Answer:
geosphere and hydrosphere
Explanation:
The half life of a radioactive substance is the time taken for the activity to halve. Use the graph to calculate the half life of the radioactive isotope.
Radioactive element which keeps on decaying over the time. Decay of radioactive element always comes under first order kinetics. Therefore the half life time of radioactive substance is 2seconds.
What is half life?Half life tells about the time at which the radioactive material decays to half of its initial concentration.
Mathematically,
half life time=0.693/ rate constant of the decay
The half life of a radioactive substance is the time taken for the activity to halve. Using the graph to calculate the half life of the radioactive isotope, we find that activity that is 3500 so, half of this activity is 17500 which is corresponding to time 2 seconds.
Therefore the half life time of radioactive substance is 2seconds.
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Which of the following has the longest wave length and the lowest frequency
A.infrared waves
B.radio waves
C.x-ray waves
D.microwaves
Answer:
B. radio waves
Explanation:
Trust me It's correct
A car has a speed of 20 m/s. If the speed of the car increases to 30 m/s in 5 seconds, what is the car’s acceleration?
2
Explanation:
2 times 5 is 10/ 20+10=30
(6) Different colors of light correspond to different: (I) frequencies (II) intensities (III) wavelengths (A) I only (B) Il only (C) Ill only (D) I and IlI (E) all of the above
Answer:e all of the above
Explanation:
In the geologic past, abiotic factors such as volcanic eruptions have had an impact on the availability of resources. How can volcanic eruptions impact the availability of resources?
by disrupting the sunlight from reaching producers
by decreasing the thickness of soil
by causing more heavy rains to erode topsoil
by causing the surface of Earth to be warmer than usual
Volcanic eruptions can have significant impacts on the availability of resources by disrupting the sunlight from reaching producers, By decreasing the thickness of soil, By causing more heavy rains to erode topsoil, By causing the surface of the Earth to be warmer than usual.
Firstly, volcanic eruptions can disrupt the sunlight from reaching producers. When volcanoes erupt, they release vast amounts of ash, gases, and aerosols into the atmosphere. These particles can scatter and absorb sunlight, reducing the amount of solar radiation reaching the Earth's surface. As a result, photosynthesis in plants, which relies on sunlight for energy, can be hindered. Secondly, volcanic eruptions can decrease the thickness of soil. The volcanic ash and other ejected materials settle on the land, creating a layer of new soil. However, this newly formed soil may be thin and lacking in essential nutrients, which are crucial for plant growth. Thirdly, volcanic eruptions can cause increased rainfall and subsequent erosion of topsoil. The immense heat and energy released during eruptions can lead to the formation of convective clouds and heavier rainfall. These intense rains can cause erosion of the topsoil, washing away valuable nutrients and organic matter. Lastly, while volcanic eruptions can release enormous amounts of heat initially, their long-term impact on the Earth's surface temperature is relatively short-lived. The ash and gases ejected during eruptions can temporarily block incoming solar radiation, causing a slight cooling effect on the surface.know more about Volcanic eruptions here:
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An observer sitting at a bus stop sees the bus drive by at 30 m/s to the east. He also sees a
passenger on the bus walking to the back at 2 m/s. What is the passenger's velocity relative
to the bus?
Answer:
32 m/s
Explanation:
The speed of a bus is 30 m/s due East wrt the passenger
He also sees a passenger on the bus walking to the back at 2 m/s.
We need to find the passenger's velocity relative to the bus. As the observer sees that the bus and the passenger are moving in opposite direction. Let v is the relative velocity. So,
v = 30 m/s + 2 m/s
v = 32 m/s
Hence, the passenger's velocity relative to the bus is 32 m/s.
a system has poles at 1 hz and 8 hz and a zero at 0.01 hz. what is the approximate phase response at 100 hz?
Given system has poles at 1Hz and 8Hz and a zero at 0.01Hz.We know that the phase of the output signal with respect to the input signal is called the phase response of the system.
The general form of transfer function can be written as:H(s)=\frac{(s-z_1)(s-z_2)\dots(s-z_m)}{(s-p_1)(s-p_2)\dots(s-p_n)}
where z and p are the zeros and poles of the transfer function. The phase response of the system can be obtained from its transfer function.
Let's first calculate the transfer function of the given system: H(s)=\frac{(s-0.01)}{(s-1)(s-8)}At s = 100 Hz, the phase angle of the system can be calculated as:\angle H(j100)=\angle \frac{j100-0.01}{j100-1} + \angle \frac{j100-0.01}{j100-8}
Let's calculate the phase angle of each term separately:
\angle \frac{j100-0.01}{j100-1} = \tan^{-1} \left(\frac{100-0.01}{100-1}\right) - \tan^{-1} \left(\frac{-0.01}{1}\right) = 88.68° - (-1.79°) = 90.47°\angle \frac{j100-0.01}{j100-8} = \tan^{-1} \left(\frac{100-0.01}{100-8}\right) - \tan^{-1} \left(\frac{-0.01}{8}\right) = 85.62° - (-0.71°) = 86.33°
Therefore, the approximate phase response at 100 Hz is approximately equal to 90.47° + 86.33° = 176.8°. Hence, the correct option is (d) 176.8°.
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In order to precipitate all of the carbonate ions from an aqueous solution of sodium carbonate, the calcium chloride solution that is added must be the excess reactant.
a) Write a complete balanced equation for this reaction.
b) If 30.0ml of 0.300 M CaCl2 are added to an aqueous solution having 0.800g of sodium carbonate, will this be enough reactant to precipitate all of the carbonate ions?
c) Theoretically, how many grams of CaCo3 precipitate will be produced in the reaction above?
d) The silver from a 200.0g sample of silver ore was converted to 9.10g of AgCl. Calculate the percent by mass of silver in this ore. Ag(ore)--> AgCl(s)
Balanced chemical equation: Na_2CO_3(aq) + CaCl_2(aq) → 2NaCl(aq) + CaCO_3(s)b)
Calculate the number of moles of CaCl_2:0.300 mol/L × 0.030 L = 0.009 mol of CaCl_2
Number of moles of Na_2CO_3: 0.800 g ÷ 105.99 g/mol = 0.0075 mol
Since the stoichiometry of the reaction is 1:1 between CaCl_2 and Na_2CO_3, the reaction will not precipitate all of the carbonate ions as calcium chloride is less in amount than sodium carbonate
c) Number of moles of CaCO_3: 0.0075 mol × 1 mol
mol of Na_2CO_3 = 0.0075 mol of CaCO_3
Mass of CaCO_3 produced: 0.0075 mol × 100.09 g/mol
= 0.750675 g of CaCO_3
d) Since AgCl is obtained from the ore, it means that the mass of silver in the ore is equal to the mass of AgCl obtained. Mass percent of silver = mass of Ag/mass of sample × 100
Mass of silver = 9.10 g
Mass of sample = 200 g
Mass percent of silver = 9.10 g/200 g × 100 = 4.55%
Therefore, the percent by mass of silver in the ore is 4.55%.
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Question 2
2. There is 100g mass on your desk to which you apply a 5N force. What is the acceleration
of the 100g mass? (Ignore friction)
Taking into account the Newton's second law, the acceleration of the 100 g mass is 50 m/s².
Newton's second lawNewton's second law states that this force will change the speed of an object because the acceleration and/or direction will change.
So, Newton's second law defines the relationship between force and acceleration mathematically. This law says that the acceleration of an object is directly proportional to the sum of all the forces acting on it and inversely proportional to the mass of the object:
F= m×a
where:
F = Force [N]m = Mass [kg]a = Acceleration [m/s²]Acceleration in this caseIn this case, you know:
F= 5 Nm= 100 g= 0.1 kg (being 1000 g= 1 kg)a= ?Replacing in Newton's second law:
5 N= 0.1 kg× a
Solving:
a= 5 N÷ 0.1 kg
a= 50 m/s²
Finally, the acceleration is 50 m/s².
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.Out of the following, the best way to do the experiment on finding the focal length of a concave mirror
by obtaining the image of a distant object, is to
a) hold the mirror in hand and keep the screen in a stand kept behind the mirror.
b) hold the mirror in a stand and hold the screen in hand, with the screen in front of the mirror.
c) keep both the mirror and the screen in suitable stands with the screen put in front of the mirror.
d) keep both the mirror and the screen in suitable stands with the screen put behind the mirror.
The best way to do the experiment on finding the focal length of a concave mirror by obtaining the image of a distant object is to keep both the mirror and the screen in suitable stands with the screen put behind the mirror, hence option D) is correct
The best way to do the experiment on finding the focal length of a concave mirror by obtaining the image of a distant object is to keep both the mirror and the screen in suitable stands with the screen put behind the mirror, which is option (d). This is because a concave mirror forms a real image of a distant object at its focus, and the light rays from the object converge to the focus after reflecting from the mirror. In this case, the distant object should be placed at a distance greater than the focal length of the mirror, and the screen should be placed at the position of the focus of the mirror to obtain a sharp image. By keeping both the mirror and the screen in suitable stands with the screen put behind the mirror, we can ensure that the distance between the mirror and the screen is equal to the focal length of the mirror, which is required to obtain a sharp image of the distant object.
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how much force must be applied to accelerate a 3 kg remote control car from rest to 10 m/s in 5 seconds
A refrigerator uses 200 j of energy per hour and takes 1200 j to get started. write an equation which expresses the amount of energy the refrigerator has used as a function of time. assume that the time is given in hours.
The equation that expresses the amount of energy the refrigerator has used as a function of time can be derived by considering two components: the energy used per hour and the initial energy required to start the refrigerator.
Let's denote the energy used per hour as E_hour and the initial energy required to start the refrigerator as E_start.
The total energy used by the refrigerator, E_total, can be calculated by multiplying the energy used per hour by the time in hours, t, and adding the initial energy required:
E_total = E_hour * t + E_start
In this case, the energy used per hour is given as 200 j, and the initial energy required is given as 1200 j. Therefore, the equation becomes:
E_total = 200t + 1200
This equation expresses the amount of energy the refrigerator has used as a function of time, where time is given in hours.
To calculate the energy used by the refrigerator at a specific time, substitute the desired value for t into the equation and solve for E_total.
For example, if you want to calculate the energy used after 3 hours:
E_total = 200 * 3 + 1200
= 600 + 1200
= 1800 j
So, after 3 hours, the refrigerator will have used 1800 joules of energy.
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Humpback whales are known to produce a collection of elaborate
and repeating sounds with frequencies ranging from 20 Hz to 10 kHz. The sound
waves travel through water at speeds of approximately 1400 m/s. Determine the
wavelengths of the waves at the lower and the upper end of this frequency
range.
Answer:
70 m.
Explanation:
Given,
Frequency, f = 20 HZ
speed of sound, v = 1400 m/s
wavelength of the waves = ?
we know,
v = f λ
Hence, the wavelength of the wave is equal to 70 m.
In every population there is variation. It is important that this variation.
Answer:
Genetic variation is an important force in evolution as it allows natural selection to increase or decrease frequency of alleles already in the population.
rate the ans plz.
A 10 nC charge sits at a point in space where the magnitude of the electric field is 1900 N/C. What will the magnitude of the field be if the 10 nC charge is replaced by a 20 nC charge? Assume the system is big enough to consider the charges as small test charges. E= ____ N/C?
Assume the system is big enough to consider the charges as small test charges. E= 3.8 × 10^4 N/C
The magnitude of the electric field at a point in space due to a point charge is given by the Coulomb's law as:
E = k * Q / r^2
where k is Coulomb's constant, Q is the charge, and r is the distance from the point charge.
In this case, the electric field magnitude at the point due to the 10 nC charge is given as 1900 N/C. So we can solve for k using the given values:
k = E * r^2 / Q
k = 1900 N/C * (1 m)^2 / (10 nC)
k = 1.9 × 10^11 N·m^2/C^2
Now, we can use this value of k to find the magnitude of the electric field when the charge is replaced by 20 nC:
E' = k * Q' / r^2
E' = (1.9 × 10^11 N·m^2/C^2) * (20 nC) / (1 m)^2
E' = 3.8 × 10^4 N/C
Therefore, the magnitude of the electric field when the 10 nC charge is replaced by a 20 nC charge would be 3.8 × 10^4 N/C.
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STT 13.2 Water is slowly poured into the container until the water level has risen into tubes 1, 2 and 3. The water doesn't overflow from any tubes. How do the water depths in the three columns compare to each other?A d1>d2>d3B D1 d3E D1=d2
Water is slowly poured into the container until the water level has risen into tubes 1, 2 and 3. The water doesn't overflow from any tubes. We have to compare the water depths in the three columns.
Since the water level has risen into all three tubes, the pressure at the bottom of all three tubes is the same.
The pressure at the bottom of each tube is given by the height of the water column multiplied by the density of the water and the acceleration due to gravity.
Since the density and acceleration due to gravity are the same for all three tubes, the pressure at the bottom of each tube depends only on the height of the water column. Therefore, the water depths in the three columns must be the same, i.e., D1 = D2 = D3.
So, the correct answer is: D1 = D2 = D3.
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Some one please help me :(
What level of demand is placed on a CPU by media development software
and games?
OA. High
OB. Medium
OC. Low
OD. Low to medium
The level of demand placed on a CPU by media development software and games is typically considered to be high. Therefore, option D is correct.
Media development software, such as video editing programs or 3D modeling software, often requires significant processing power to handle complex tasks like rendering graphics, processing large files, and performing real-time calculations.
Similarly, games, especially modern and graphics-intensive ones, can put a heavy load on the CPU. Games require processing power to handle tasks like physics simulations, AI calculations, rendering high-resolution graphics, and running multiple threads simultaneously.
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A stopped object starts moving. After 3.2 s, it’s moving 18 m/s. The net force acting on it is 328 N. What is its mass?
The mass of the object would be 58.4 kg.
Mass/force problemThe problem can be solved using Newton's second law of motion, which states that the net force (F_net) acting on an object is equal to the mass (m) of the object multiplied by its acceleration (a):
F_net = m*a
We are given that the net force acting on the object is 328 N, and we know the object's acceleration from the change in velocity over time:
a = (final velocity - initial velocity) / time
a = (18 m/s - 0 m/s) / 3.2 s
a = 5.625 m/s^2
Substituting these values into the equation for Newton's second law, we get:
328 N = m * 5.625 m/s^2
Solving for m, we get:
m = 328 N / 5.625 m/s^2
m ≈ 58.4 kg
Therefore, the mass of the object is approximately 58.4 kg.
More on Newton's second law can be found here: https://brainly.com/question/13447525
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