energy from motion and position.

from flocabulary

Answer:

I HOPE THE ABOVE INFORMATION WILL HELP YOU A LOT.

The following statements on HPLC modes are true is more polar compounds elute first in normal-phase HPLC (Option E).

The liquid chromatography (HPLC) is a technique in analytical chemistry employed for the separation, identification, and quantification of elements. It is considered a highly sensitive method, and it works by separating the components in a mixture with the assistance of a solvent under high pressure.

There are two modes of HPLC: Reversed-Phase HPLC (RP-HPLC) and Normal-Phase HPLC (NP-HPLC). In RP-HPLC, a nonpolar stationary phase, such as C18, is used, and polar solvents, such as water, are used as mobile phases. Polar stationary phases, such as silica gel, are used in NP-HPLC, while nonpolar solvents, such as hexane, are used as mobile phases.

More polar compounds have a greater affinity for the polar stationary phase than less polar compounds, which have a higher affinity for the nonpolar mobile phase in NP-HPLC. As a result, less polar compounds elute first in normal-phase HPLC.

Thus, the correct option is E.

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Answer:

A, D, E

Explanation:

Answer:

Made of cells

Explanation:

cells are the basic building blocks of life

Option (d), P=ATC=MR=MC, accurately represents the long-run equilibrium condition for perfect competition, reflecting the balance between price and cost for firms operating in a competitive market.

The long-run equilibrium condition for perfect competition is that price (P) is equal to average total cost (ATC), which is also equal to marginal cost (MC), and marginal revenue (MR).

Option (d), P=ATC=MR=MC, best represents the long-run equilibrium condition for perfect competition. In perfect competition, firms operate at the minimum point of their average total cost curve, where price equals both average total cost and marginal cost. This condition ensures that firms are earning zero economic profit and are producing at an efficient level.

In the long run, if firms are earning economic profit, new firms will enter the market, increasing competition and driving prices down. Conversely, if firms are experiencing losses, some firms may exit the market, reducing competition and causing prices to rise. This process continues until firms reach a state where price equals average total cost, marginal cost, and marginal revenue, ensuring a long-run equilibrium.

Therefore, option (d), P=ATC=MR=MC, accurately represents the long-run equilibrium condition for perfect competition, reflecting the balance between price and cost for firms operating in a competitive market.

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a. The element has a total of 6 valence electrons (2 in the ns orbital and 4 in the np orbital).b. The element that has a valence electron configuration of ns2np4 could be Selenium (Se), which has 6 valence electrons.c. The element, which has a valence electron configuration of ns2np4, will form an ionic compound with potassium by losing all its valence electrons to potassium. Hence, the compound formed will be K2Se.

d. The radius of an element depends on the number of electrons and energy levels, among other factors. Barium (Ba) is an element found in period 6 of the periodic table. In contrast, the unknown element is found in period 3. Thus, it can be concluded that the element has a smaller radius than Barium (Ba).e. Fluorine (F) is one of the most electronegative elements known. As a result, it has the highest ionization energy. The element with a valence electron configuration of ns2np4 is more significant than fluorine, but it has a lower ionization energy.

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The process of cellular respiration, which converts simple sugars such as glucose into co2 and water, is an example of a catabolic pathway.

As byproducts, water as well as carbon dioxide are produced. The general formula for aerobic cellular respiration would be, that during cellular respiration, oxygen as well as glucose combine to create ATP. Byproducts include the discharge of water as well as carbon dioxide.

The process of breathing is exothermic. As a result of the transformation of glucose molecules into all the other molecules during respiration, CO2 as well as H2O are produced.

Therefore, the process of cellular respiration, which converts simple sugars such as glucose into co2 and water, is an example of catabolic pathway.

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i. Ionic bond: bond between an anion and a cation. ii. Polar covalent: bond between atoms of the same element but different electronegativities. iii. Non-polar covalent: weak intramolecular bond. iv. Hydrogen: bond between the hydrogen atom in one molecule and a more electronegative atom in another molecule

Based on their properties, chemical bonds are classified into four major types. These include Ionic bonds, covalent bonds, polar covalent bonds, and hydrogen bonds. Some characteristics of the four types of chemical bonds are as follows:

i. Ionic bond: An ionic bond is formed when electrons are transferred from one atom to another atom. The resulting ions are attracted to each other and form an ionic bond. Ionic bonds are typically between metals and nonmetals.

ii. Polar covalent bond: Polar covalent bonds occur when atoms of the same element but different electronegativities bond. The atoms share the electrons unequally in a polar covalent bond, creating a partial positive charge on the less electronegative atom and a partial negative charge on the more electronegative atom. Polar covalent bonds typically occur between nonmetals.

iii. Non-polar covalent bond: Non-polar covalent bonds occur between two atoms of the same element or between different elements with the same electronegativity. The sharing of electrons between the atoms in a nonpolar covalent bond is equal. As a result, there is no net charge distribution across the molecule, and the bond is nonpolar. Nonpolar covalent bonds typically occur between nonmetals.

iv. Hydrogen bond: Hydrogen bonds are weak intramolecular bonds that occur between the hydrogen atom in one molecule and a more electronegative atom in another molecule. Hydrogen bonds are important in the secondary and tertiary structures of proteins and the structure of water.

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Answer:

they improve soil texture

Explanation:

that's it helps to hold

water longer and and increase the soil bacteria and fungal activity in the soil so they do not only assist your plants , they help the soil.

When atoms or molecules absorb energy, it is often released as light energy

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Answer

Number 1. increase

number 2 . decrease

number 3. decrease

If there are no chemical controls which can be implemented at your worksite than one should wear recommended PPE for protection .

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Answer:

sorry I don't know how can do this for me

Answer:

A pH scale is used to measure acidity.

Answer:

How acidic or alkaline a substance is.

Explanation:

1 = Strong acid e.g. Stomach acid

7 = Neutral e.g. Water

14 = Strong alkaline e.g. Sodium hydroxide

The concentration of H+ ions in a solution can be calculated using the formula: [H+] = 10^(-pH). For soil with a pH of 8.1, the concentration of H+ ions would be approximately 7.94 x 10^(-9) moles/L.

The pH of a solution is a measure of the concentration of hydrogen ions (H+) present. The pH scale is logarithmic, with a pH of 7 considered neutral, values below 7 acidic, and values above 7 basic (alkaline). To determine the concentration of H+ ions in moles per liter (mol/L), we can use the equation [H+] = 10^(-pH)

Substituting the given pH value of 8.1 into the equation [H+] = 10^(-8.1)

Calculating this expression:

[H+] ≈ 7.943 x 10^(-9) mol/L

Therefore, the concentration of H+ ions in the calcareous soil is approximately 7.943 x 10^(-9) mol/L.

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Physical chemistry a  major branch of chemistry would be most concerned with studying a series of chemical reactions in order to measure the amount of heat being released in each one.

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Potassium chloride can be extracted from Layer C.

The given flowchart describes a separation process involving dissolution in diethyl ether, followed by liquid-liquid extraction using HCl and H2O, and finally evaporation. Layer A (ether layer) results from the first extraction step, where 2-octanol is likely to be present due to its solubility in diethyl ether. Layer B (ether layer) results from the second extraction step using NaOH, where cyclohexylamine is expected to be present, as it would form a soluble salt with NaOH. Layer C (aqueous layer) is where potassium chloride can be extracted, as it is a water-soluble salt and would remain in the aqueous phase throughout the process.

To extract potassium chloride from the mixture, focus on Layer C, as this is the layer where it is most likely to be found after the separation process.

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a. Since bοth substances are isοlated and insulated, the heat transfer οccurs frοm the hοt side (argοn) tο the cοld side (helium).

b. The final temperature is apprοximately 550 K.

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The empirical formula of the compound is CH₂O. This means that for every one carbon atom, there are two hydrogen atoms, and one oxygen atom.

To determine the empirical formula, we need to find the simplest ratio of atoms in the compound. We can assume we have 100 grams of the compound, which means we have 54.5 grams of carbon, 9.1 grams of hydrogen, and 36.1 grams of oxygen.

Next, we calculate the number of moles for each element by dividing the mass by their respective molar masses: carbon (12 g/mol), hydrogen (1 g/mol), and oxygen (16 g/mol).

Carbon: 54.5 g / 12 g/mol = 4.54 mol

Hydrogen: 9.1 g / 1 g/mol = 9.1 mol

Oxygen: 36.1 g / 16 g/mol = 2.26 mol

To obtain the simplest whole-number ratio, we divide the number of moles of each element by the smallest number of moles (2.26 mol in this case).

Carbon: 4.54 mol / 2.26 mol = 2

Hydrogen: 9.1 mol / 2.26 mol ≈ 4

Oxygen: 2.26 mol / 2.26 mol = 1

Thus, the empirical formula of the compound is CH₂O, indicating that it contains two carbon atoms, four hydrogen atoms, and one oxygen atom.

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Answer:

A/An  

✔ binary

star system is made of two stars.

A/An  

✔ open cluster

star system is made of no more than a few thousand stars.

A/An  

✔ globular cluster

star system is made of more than a million stars.

Explanation:

Answer:

A/An

✔ binary

star system is made of two stars.

A/An

✔ open cluster

star system is made of no more than a few thousand stars.

A/An

✔ globular cluster

star system is made of more than a million stars.

Explanation:

Answer:

Distance cover by school bus = 149.5 miles

Explanation:

Given:

Velocity of school bus = 65 mph

Time taken by school bus = 2.3 hours

Find:

Distance cover by school bus

Computation:

Distance cover = Velocity x Time taken

Distance cover by school bus = Velocity of school bus x Time taken by school bus

Distance cover by school bus = 65 x 2.3

Distance cover by school bus = 149.5 miles

Answer:

reduce the distance by the factor of 5

Answer:

The answer is 720 seconds :)

Explanation:

the ph of a base solution is pH= 6.92.

The base is so dilute that we must also consider the OH- that comes from the autoionization of water.

H2O⇌H++OH-

Kw=[H+][OH-]

[OH-]= 8.3 x 10-8 m

pOH=-log(8.3 x 10-8)= -7.08

pH=14.00 - pOH

pH= 14.00 - 7.08

pH= 6.92

The Henderson-Hasselbach Equation can be used to determine the pH of a buffer solution and its conjugate base. It can be approximated because equilibrium between a weak acid and the base that serves as its conjugate permits the solution's pH to remain constant even after the addition of modest amounts of a strong acid or base.

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The entropy change of the universe is zero, which is consistent with the second law of thermodynamics. Therefore, the entropy of the universe remains constant or the change in entropy is zero.

Answer:AScoffee = -1.71 J/K, ASroom = 1.71 J/K, ASuniverse = 0.

According to the second law of thermodynamics, entropy of an isolated system always increases. In the given question, we need to calculate the entropy change of coffee, room, and universe. Let's solve this problem.

Given: Mass of coffee = 170 g (density of water = 1 g/cm³)

Specific heat of coffee = specific heat of water = 4.18 J/(g·°C)

Temperature of coffee = 88°C

Temperature of room = 20°C

The initial temperature of coffee = 88°C

The final temperature of coffee = 20°C

Change in temperature of coffee (ΔT) = final temperature - initial temperature = 20°C - 88°C = -68°C

Let's calculate the entropy change of coffee. Entropy change of coffee:

AScoffee = -[170 g/(1000 g/1 kg)](4.18 J/(g·°C))ln[(20°C + 273 K)/(88°C + 273 K)]

AScoffee = -[0.17 kg](4.18 J/(g·°C))ln(293 K/361 K)

AScoffee = -1.71 J/K

Now, let's calculate the entropy change of the room. The change in entropy of the room would be equal and opposite to the change in entropy of coffee (based on the principle of energy conservation).

ASroom = -AScoffeeASroom = 1.71 J/K

The entropy change of the universe would be the sum of entropy change of coffee and entropy change of the room.

ASuniverse = AScoffee + ASroomASuniverse = -1.71 J/K + 1.71 J/KA

Suniverse = 0

The entropy change of the universe is zero, which is consistent with the second law of thermodynamics. Therefore, the entropy of the universe remains constant or the change in entropy is zero.

Answer:AScoffee = -1.71 J/K, ASroom = 1.71 J/K, ASuniverse = 0.

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Answer:

studying chemistry successfully means learning a lot of facts ! it also means developing analytical and didactic skills in filtering out fiction from fact . you will need to Learn to argue a position based on fact. all of these skills are highly sought after in all business and indeed all life

The molecular formula for Adenine with molecular mass of 135.1 and consist of 44. 45% C, 3. 73% H, and 52. 82% N by mass is C₃H₃₆N₂.

The molecular formula expresses the number of atoms of each element in one chemical molecule.

The definition of a molecular formula is the formula that shows the exact number of atoms in a molecule.

The empirical formula is used to derive the Molecular Formula when the molar mass value is known.

n=empirical formula molar mass/mass

The molecular formula is frequently the same as or an exact multiple of an empirical formula.

We have molecular formula = 135.14

so we need to find each atoms contribution so,

C = 135.14 /44.45 = 3.03

H = 135.14 /3.73 = 36.21

N = 135.14 / 52.82 = 2.55

So we have molecular formula as,

C₃H₃₆N₂.

Adenine is a nucleic acid component, specifically the nitrogenous base in the structure. Adenine is a nitrogenous base present on both DNA and RNA molecules (examples of nucleic acids). Adenine is a compound of Carbon, Hydrogen, and Nitrogen atoms, and elemental analysis can assist in determining the chemical formula.

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The empirical formula is therefore CH.Now we can calculate the empirical formula. Divide the number of moles of each element by the smallest number of moles to get a simple whole number ratio:
Carbon: 0.5250 mol C / 0.5250 mol = 1
Hydrogen: 0.5242 mol H / 0.5250 mol = 0.997

To find the empirical formula for the hydrocarbon, we need to determine the moles of each element present in the combustion reaction.
First, let's determine the moles of oxygen used:
18.214 g of O2 x 1 mol O2/32.00 g = 0.5698 mol O2
Next, let's determine the moles of carbon dioxide produced:
23.118 g of CO2 x 1 mol CO2/44.01 g = 0.5250 mol CO2
Finally, let's determine the moles of water produced:
4.729 g of H2O x 1 mol H2O/18.02 g = 0.2621 mol H2O
To find the moles of carbon present in the hydrocarbon, we can use the fact that the amount of carbon in the hydrocarbon equals the amount of carbon in the carbon dioxide:
0.5250 mol CO2 x (1 mol C/1 mol CO2) = 0.5250 mol C
To find the moles of hydrogen present in the hydrocarbon, we can use the fact that the amount of hydrogen in the hydrocarbon equals the amount of hydrogen in the water:
0.2621 mol H2O x (2 mol H/1 mol H2O) = 0.5242 mol H
Now we can calculate the empirical formula. Divide the number of moles of each element by the smallest number of moles to get a simple whole number ratio:
Carbon: 0.5250 mol C / 0.5250 mol = 1
Hydrogen: 0.5242 mol H / 0.5250 mol = 0.997
The empirical formula is therefore CH.

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Answer:

Nucleus is known as the brain of the cell.

correct option is B letter