End behavior of polynomial function
Identify the end behavior of the given polynomial function
Answers
I would need to know the specific polynomial function to determine its end behavior. However, in general, the end behavior of a polynomial function can be determined by looking at the degree and leading coefficient of the polynomial.
If the degree of the polynomial is even and the leading coefficient is positive, then the end behavior will be the same on both ends and the function will approach positive infinity as x goes to negative infinity and positive infinity as x goes to positive infinity.
If the degree of the polynomial is even and the leading coefficient is negative, then the end behavior will be the same on both ends and the function will approach negative infinity as x goes to negative infinity and positive infinity as x goes to positive infinity.
If the degree of the polynomial is odd and the leading coefficient is positive, then the end behavior will be different on the left and right ends. As x goes to negative infinity, the function will approach negative infinity, and as x goes to positive infinity, the function will approach positive infinity.
If the degree of the polynomial is odd and the leading coefficient is negative, then the end behavior will be different on the left and right ends. As x goes to negative infinity, the function will approach positive infinity, and as x goes to positive infinity, the function will approach negative infinity.
Step-by-step explanation:
To determine the end behavior of a polynomial function, you need to look at the degree (highest power of x) and the leading coefficient (the coefficient of the term with the highest power of x).
If the degree of the polynomial is even and the leading coefficient is positive, then the end behavior is that the function approaches positive infinity as x approaches both positive and negative infinity.
If the degree of the polynomial is even and the leading coefficient is negative, then the end behavior is that the function approaches negative infinity as x approaches both positive and negative infinity.
If the degree of the polynomial is odd and the leading coefficient is positive, then the end behavior is that the function approaches positive infinity as x approaches both positive infinity and negative infinity, but approaches negative infinity as x approaches negative infinity.
If the degree of the polynomial is odd and the leading coefficient is negative, then the end behavior is that the function approaches negative infinity as x approaches both positive infinity and negative infinity, but approaches positive infinity as x approaches negative infinity.
Here's an example:
Let's consider the polynomial function f(x) = 2x^4 - 3x^3 + 5x - 1.
The degree of this polynomial is 4, which is even, and the leading coefficient is even, and the leading coefficient is positive, which means that as x approaches both positive and negative infinity, the function approaches positive infinity.
Therefore, we can say that the end behavior of the polynomial function f(x) is that f(x) → ∞ as x → ±∞.
Related Questions
Rollin Corporation has 410,000 shares of 5$ per value common stock issued and outstanding. Record the following entries into the general journal
Answers
Answer:3522
Step-by-step explanation:222
2
If f(-5)=7 identify a point on the graph of f
Answers
Answer:
If f(-5) = 7, then the point P(-5, 7) will be on the graph of f
where -5 is the x-coordinate and 7 is the y-coordinate
Step-by-step explanation:
Twenty standard cartons of octal boxes weigh a total of 1,100 pounds. Find the weight per carton.
Answers
Twenty standard cartons of octal boxes weigh a total of 1,100 pounds. The weight per carton is 55 pounds.
Given that twenty standard cartons of octal boxes weigh a total of 1,100 pounds. We need to find the weight per carton.
How to find the weight per carton? To find the weight per carton, we need to divide the total weight of twenty standard cartons of octal boxes by 20.Let's assume the weight of each carton be x.
Therefore, the equation can be formed asx * 20 = 1,100 Solving the above equation for x, x = 1,100/20 Therefore, the weight per carton is 55 pounds. So, twenty standard cartons of octal boxes weigh a total of 1,100 pounds.
The weight per carton is 55 pounds.
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A customer asks for two money orders. The first is for the amount of $637.24 and the second
is for $25.76. If there is a $1.00 charge for each money order, what is the total amount the
customer would owe you?
Answers
Answer:
A customer asks for two money orders. The first is for the amount of $637.24 and the second
is for $25.76. If there is a $1.00 charge for each money order, what is the total amount the
customer would owe you?
A customer asks for two money orders. The first is for the amount of $637.24 and the second
is for $25.76. If there is a $1.00 charge for each money order, what is the total amount the
customer would owe you?
Is the relation shown in the table below a function? (type in yes or no)
Answers
Answer:
Yes
Step-by-step explanation:
To know if a table is a function or not, we have to see if 1 input only has 1 output.
Looking at the table each input only has 1 output, so it is a function.
the Pythagorean theorem is true for
a. true for all triangles
b. true for all right triangle
c. true for some right triangles
d. never true
Answers
It’s true for all right triangles.
A restaurant plans to use a new food delivery service. The food delivery service charges $5.48 for every 2 meals delivered, plus a $3.50 service fee. What is the slope of this situation?
Answers
Answer:
$14.46 total
Step-by-step explanation:
$5.48 x 2 + $3.50, or $5.48 + $5.48 + $3.50 to get $14.46
M
Check all that apply.
Answers
The angles that we have in the image here are:
supplementary angleright angleWhat is a supplementary angle?When two angles are measured, they sum up to 180. They are said to be supplementary angles.
On the question, we have two angles that are 90 degrees on a straight line. Hence they are supplementary.
What is a right angle
This is an angle that is at 90 degrees. We have to two right angles on the diagram that we have here.
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Please solve As soon as possible.
Answers
An equation to match the graph include the following: f(x) = |x + 1| + 1.
What is a translation?In Mathematics and Geometry, the translation a geometric figure or graph to the left simply means subtracting a digit from the value on the x-coordinate of the pre-image while the translation a geometric figure or graph upward simply means adding a digit to the value on the y-coordinate (y-axis) of the pre-image.
Since the parent function is f(x) = |x|, g(x) would be created by translating f(x) the parent function one unit to the left and one unit upward as follows;
f(x) = |x|
g(x) = |x + 1| + 1
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How many elements are in the set ABC
Answers
Answer:
3
Step-by-step explanation:
The set with 4 elements are listened, a,b,c,d
the set that is given is A, b, c.
An isosceles triangle whose sides are 5cm, 5cm and 6cm is inscribed in a circle. Find the radius of the circle.
Answers
Answer:
To find the radius of the circle inscribed in an isosceles triangle, we can use the following formula:
r = (a/2) * cot(π/n)
where r is the radius of the inscribed circle, a is the length of one of the equal sides of the isosceles triangle, and n is the number of sides of the polygon inscribed in the circle.
In this case, we have an isosceles triangle with two sides of 5cm and one side of 6cm. Since the triangle is isosceles, the angle opposite the 6cm side is bisected by the altitude and therefore, the two smaller angles are congruent. Let x be the measure of one of these angles. Using the Law of Cosines, we can solve for x:
6^2 = 5^2 + 5^2 - 2(5)(5)cos(x)
36 = 50 - 50cos(x)
cos(x) = (50 - 36)/50
cos(x) = 0.28
x = cos^-1(0.28) ≈ 73.7°
Since the isosceles triangle has two equal sides of length 5cm, we can divide the triangle into two congruent right triangles by drawing an altitude from the vertex opposite the 6cm side to the midpoint of the 6cm side. The length of this altitude can be found using the Pythagorean theorem:
(5/2)^2 + h^2 = 5^2
25/4 + h^2 = 25
h^2 = 75/4
h = sqrt(75)/2 = (5/2)sqrt(3)
Now we can find the radius of the inscribed circle using the formula:
r = (a/2) * cot(π/n)
where a = 5cm and n = 3 (since the circle is inscribed in a triangle, which is a 3-sided polygon). We can also use the fact that the distance from the center of the circle to the midpoint of each side of the triangle is equal to the radius of the circle. Therefore, the radius of the circle is equal to the altitude of the triangle from the vertex opposite the 6cm side:
r = (5/2) * cot(π/3) = (5/2) * sqrt(3) ≈ 2.89 cm
Therefore, the radius of the circle inscribed in the isosceles triangle with sides 5cm, 5cm, and 6cm is approximately 2.89 cm.
Which of these affect real investment value? Check all that apply.
Answers
Answer:
Fees and expenses
nominal interest rate
taxes
Step-by-step explanation:
I need an answer for this edmentum question I’m stuck on.
Answers
Given:
x-intercept = -1.
y-intercept = -3.
minimum is -4 at x =1.
Required:
We need find the graph of the given parabola.
Explanation:
Recall that the x-intercept is the point where a line crosses the x-axis.
The point is (-1,0).
Recall that the y-intercept is the point where a line crosses the y-axis.
The point is (0,-3).
The minimum is -4 at x =1 is the vertex of the parabola.
Vertex =(1,-4).
Points (-1,0), (0,-3), (1,-4) lies on the parabola.
Points (-1,0), (0,-3), (1,-4) lies on the graph C.
Final answer:
Option C is required parabola.
Find the area of the triangle.
b ft
h yd
Question content area bottom
Part 1
The area of the triangle is
enter your response here or
enter your response here .
Answers
The area of the triangle is 52.32 square units
Finding the area of the trianglefrom the question, we have the following parameters that can be used in our computation:
The triangle (see attachment)
The base of the triangle is calculated as
base = 12 * tan(36)
The area of the triangle is then calculated as
Area = 1/2 * base * height
Where
height = 12
So, we have
Area = 1/2 * base * height
Substitute the known values in the above equation, so, we have the following representation
Area = 1/2 * 12 * tan(36) * 12
Evaluate
Area = 52.32
Hence, the area of the triangle is 52.32 square units
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Please find the derivative h(x)= sinh(x^5)
Answers
Recall that:
\(\frac{d}{du}\sinh (u)=\cosh (u).\)Applying the chain rule we get that:
\(\frac{d}{dx}\sinh (x^5)=\frac{d}{du}\sinh (u)|_{u=x^5}\cdot\frac{d}{dx}(x^5)\text{.}\)Therefore:
\(\frac{d}{dx}\sinh (x^5)=\cosh (u)|_{u=x^5}\cdot5x^{5-1}\text{.}\)Simplifying the above result we get:
\(\begin{gathered} \frac{d}{dx}\sinh (x^5)=\cosh (x^5)\cdot5x^4 \\ =5x^4\cosh (x^5)\text{.} \end{gathered}\)Answer:
\(h^{\prime}(x)=5x^4\cosh (x^5)\text{.}\)
A car travels a distance of 112km at an average Speed of 70km/h. It then Travells Further for 60km at an average Speed of 50 km/hr. Calculate for the entire Journey of the total time taken.
Answers
The total time taken for the entire journey is 2.8 hours.
To calculate the total time taken for the entire journey, we can use the formula:
Time = Distance / Speed
For the first part of the journey, the car travels a distance of 112 km at an average speed of 70 km/h. Using the formula, the time taken for this part is:
Time1 = 112 km / 70 km/h = 1.6 hours
For the second part of the journey, the car travels a further distance of 60 km at an average speed of 50 km/h. Again, using the formula, the time taken for this part is:
Time2 = 60 km / 50 km/h = 1.2 hours
To find the total time for the entire journey, we sum up the times for both parts:
Total Time = Time1 + Time2 = 1.6 hours + 1.2 hours = 2.8 hours
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Sketch a graph of 6 x + 4 y = 4
Answers
The graph of 6x + 4y = 4 can be sketched as shown in the image attached below.
How to Sketch the Graph of a Linear Equation?A linear equation can be expressed in standard form as Ax + By = C, where A, B, and C are integers. Also, it can be rewritten in slope-intercept form as y = mx + b, where b is the y-intercept and m is the slope of the equation.
In order to graph an equation, we can easily determine what the slope (m) and the y-intercept (m) of the graph would be when we rewrite the equation in slope-intercept form.
Given the equation in standard form as, 6x + 4y = 4, rewrite it in slope-intercept form:
6x + 4y = 4
4y = -6x + 4
y = -6x/4 + 4/4
y = -3/2x + 1
This means that the slope of the graph you'd sketch will be -3/2, and the line must intercept the y-axis at 1, because the y-intercept is 1.
The graph is shown below.
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how can you tell if a fracion is a unit fraction
Answers
A unit fraction is any fraction with 1 as its numerator (top number), and a whole number in the denominator (bottom number).
18- A clothing store sells a shirt costing $20 for $33 and a jacket costing $60 for $93.
(i) If the markup policy of the store is assumed to be linear, write an equation that expresses retail price R
in terms of cost C.
(ii) What does a store pay for a suit that retails for $240?
(i) (a) R = 1.5C + 12
(b) R = 1.5C+3
(c) R = 3C + 1.2
(d) R = 3C +1.5
(ii) (a) 158
(b) 185
(c) 155
(d) 188
I cant solve this and I need steps while solving it.
Answers
Match the reasons to the statement ( will mark brainiest if optional)
Match the reasons to the statements.
a) Reflexive Property
b) Angle Congruence Postulate
c) Definition of Supplementary
d) Segment Addition Postulate
e) Definition of Right Angle
f) Symmetric Property
g) Substitution Property of Equality
h) Definition of Complementary
i) Segment Congruence Postulate
j) Angle Addition Postulate
k) Linear Pair Postulate
Answers
The reasons for the possible congruency statements obtained from a similar question on the website are as follows;
Statement \({}\) Reason
7. ∠BAD ≅ ∠CAD
\(\overline{AD}\) ≅ \(\overline{AD}\) ⇒\({}\) Reflexive property
8. ∠2 ≅∠3
m∠2 = m∠3 ⇒ \({}\) Angle congruency postulate
9. \(\overline{BE}\) ≅ \(\overline{CE}\)
\(\overline{DE}\) ≅ \(\overline{AE}\)
\(\overline{BE}\) = \(\overline{CE}\) \({}\) ⇒ Segment Congruence Postulate
\(\overline{DE}\) = \(\overline{AE}\) \({}\) ⇒ Segment Congruence Postulate
10. AE + BE = AB \({}\) ⇒ Segment Addition Postulate
11. \(\overline{AB}\) ≅ \(\overline{DE}\)
\(\overline{DE}\) ≅ \(\overline{AB}\) \({}\) ⇒ Symmetric property
What are congruent geometric figures?Geometric figures are congruent if their shape and or size are the same.
Reflexive property of congruency
The reflexive property of congruency states that a shape is congruent to itself.
Angle congruency postulate
The angle congruency postulate states that if the measure of two angles are the same, then they are congruent
Segment congruency postulate
The segment congruency postulate states that if the length of two segments are the same, then the segments are congruent
Segment Addition Postulate
The segment addition postulate states a point B is located on a segment AC if and only if AB + BC = AC
Symmetric property of congruency
The symmetric property congruency states that if a geometric figure, A, is congruent to another geometric figure, B, then B is congruent to A
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Translate the sentence into an equation.
Two times the sum of a number and 9 equals 3.
Use the variable b for the unknown number.
Answers
Answer:
The equation would be:
2(b + 9) = 3
The digit in the ten's place of a two digit number is one less than the digit in the one's place. If we add this number to the number obtained by reversing its digits, the result is 55, find the number.
Answers
Answer:
23
Step-by-step explanation:
55 = 23 + 32
14 and 41 came into my d, but 1 and 4 are 3 apart from each other
(would really appreciate the brainliest)
Mofor had $21 to spend on two notebooks.
After buying them he had $13. How much
did each notebook cost?
Two-step equations
Answers
Step-by-step explanation:
21-13=8
8÷2=4
A note book costs 4$
Answer:
the unit price of the notebooks: $4
Step-by-step explanation:
Mo starts with $21 and finds himself left with $13 after buying the notebooks. Subtracting $13 from $21 results in $8, the amount he spent on two notebooks. Dividing $8 by 2 yields the unit price of the notebooks: $4
Which values of a,b,and c correctly represent the answer in simplest form 7/9 divied by 4/9 =
Answers
Answer:
\(7/4\)
Solution:
\(\frac{7}{9} /\frac{4}{9}\)
Reciprocal.
\(7/9(9/4)\)
Multiply.
\(\frac{63}{36}\)
Simplify
\(\frac{7}{4}\)
Easy Car Corp. is a grocery store located in the Southwest. It paid an annual dividend of $2.00 last year to its shareholders and plans to increase the dividend annually at the rate of 4.0%. It currently has 2,000,000 common shares outstanding. The shares currently sell for $13 each. Easy Car Corp. also has 30,000 semiannual bonds outstanding with a coupon rate of 10%, a maturity of 23 years, and a par value of $1,000. The bonds currently have a yield to maturity (YTM) of 8%. What is the weighted average cost of capital (WACC) for Easy Car Corp. if the corporate tax rate is 30%?
When answering this problem enter your answer using percentage notation but do not use the % symbol and use two decimals (rounding). For example, if your answer is 0.10469 then enter 10.47; if your answer is 10% then enter 10.00
Answer:_____
Answers
Answer:
Since the instruction in the question indicates that the % symbol should not be used, the weighted average cost of capital (WACC) for Easy Car Corp is therefore 12.07.
Step-by-step explanation:
This can be calculated using the following steps:
Step 1: Calculation of the current bond price
Semiannual coupon amount = Bond face value * Semiannual coupon rate = $1000 * (10% / 2) = $50
Semiannual coupon discount factor = ((1 - (1 / (1 + r))^n) / r) .......... (1)
Where;
r = Semiannual yield to maturity (YTM) = 8% / 2 = 0.08 / 2 = 0.04
n = number of semiannuals = 23 years * 2 = 46
Substituting the values into equation (1), we have:
Semiannual coupon discount factor = ((1-(1/(1 + 0.04))^46) / 0.04) = 20.8846535613106
Present value of coupon = (Semiannual coupon amount * Semiannual coupon discount factor) = $50 * 20.8846535613106 = $1,044.23
Present value of the face value of the bond = Face value / (1 + r)^n = $1,000 / (1 + 0.04)^46 = $164.61
Therefore, we have:
Current bond price = Present value coupon + Present value of the face value of the bond = $1,044.23 + $164.61 = $1,208.84
Step 2: Calculation of weights of each finance source
Market value of common shares outstanding = Number common shares outstanding * Current price per share = 2,000,000 * $13 = $26,000,000.
Market value of bond = Number of bonds * Current bond price = 30,000 * $1,208.84 = $36,265,200
Total financing market value = Market value of common shares outstanding + Market value of bond = $26,000,000 + $36,265,200 = $62,265,200
Weight of Market value of common shares outstanding = Market value of common shares outstanding / Total financing market value = $26,000,000 / $62,265,200 = 0.42
Weight of Market value of bond = Market value of bond / Total financing market value = $36,265,200 / $62,265,200 = 0.58
Step 3: Calculation of return on equity
Current year dividend = Last year dividend * (1 + Dividend growth rate) = $2 * (1 + 4.0%) = $2.08
Next year dividend = Current year dividend * (1 + Dividend growth rate) = $2.08 * (1 + 4.0%) = $2.1632
The return on equity can now be calculated using the following formula:
Current share price = Next year dividend / (Return on equity – Dividend growth rate) ………………….. (2)
Where;
Current share price = $13
Next year dividend = $2.1632
Return on equity = ?
Dividend growth rate = 4.0%, or 0.04
Substituting the values into equation (2) and solve for return on equity, we have:
13 = 2.1632 / (Return on equity - 0.04)
13 * (Return on equity - 0.04) = 2.1632
(13 * Return on equity) – (13 * 0.04) = 2.1632
(13 * Return on equity) – 0.52 = 2.1632
13 * Return on equity = 2.1632 + 0.52
Return on equity = 2.6832 / 13
Return on equity = 0.21
Step 4: Calculation of Weighted average cost of capital
Weighted average cost of capital = (WS * CE) + (WD * CD * (1 – T)) ………………… (4)
Where;
WS = Weight of Market value of common shares outstanding = 0.42
WD = Weight of debt = Weight of Market value of bond = 0.58
CE = Cost of equity = Return on equity = 0.21
CD = Cost of debt = YTM = 8%, or 0.08
T = Tax rate = 30%, or 0.30
Substituting the values into equation (3), we have:
Weighted average cost of capital = (0.42 * 0.21) + (0.58 * 0.08 * (1 - 0.30)) = 0.12068, or 12.068%
Rounding to two decimal places, we have:
Weighted average cost of capital = 12.07%
Since the instruction in the question indicates that the % symbol should not be used, the weighted average cost of capital (WACC) for Easy Car Corp is therefore 12.07.
QUICK I NEED HELP! ILL MARK BRAINLIEST IF CORRECT
Find the amount in a continuously compounded account for the following condition.
Principal, $2000; Annual interest rate, 5.1%; time, 3 years
Whats the balance after 3 years?
Answers
Answer:
The balance in the account after 3 years is approximately $2313.94.
Step-by-step explanation:
The formula for calculating the balance in a continuously compounded account is:
B = Pe^(rt)
Where:
B = balance
P = principal
e = Euler's number (approximately 2.71828)
r = annual interest rate (as a decimal)
t = time in years
Using the given values, we have:
P = $2000
r = 0.051 (5.1% expressed as a decimal)
t = 3
Plugging these values into the formula, we get:
B = 2000e^(0.051*3)
B = 2000e^(0.153)
B = $2313.94 (rounded to the nearest cent)
Therefore, the balance in the account after 3 years is approximately $2313.94.
QUESTION:-↓
The dimensions of a room are 12.5 m by 9 m by 7 m. there are 2 doors and 4 windows in the room; each door measures 2.5 m by 1.2 m and each window 1.5 m by 1 m. Find the cost of painting the walls at Rs. 3.50 per square meter.
no spam!
Answers
Given dimensions of the room:
Length: \(\displaystyle\sf 12.5 \,m\)
Width: \(\displaystyle\sf 9 \,m\)
Height: \(\displaystyle\sf 7 \,m\)
Area of each wall:
\(\displaystyle\sf Area_1 = 12.5 \times 7 = 87.5 \,m^2\)
\(\displaystyle\sf Area_2 = 12.5 \times 7 = 87.5 \,m^2\)
\(\displaystyle\sf Area_3 = 9 \times 7 = 63 \,m^2\)
\(\displaystyle\sf Area_4 = 9 \times 7 = 63 \,m^2\)
Area of each door:
\(\displaystyle\sf Area_{\text{door}} = 2.5 \times 1.2 = 3 \,m^2\)
Area of each window:
\(\displaystyle\sf Area_{\text{window}} = 1.5 \times 1 = 1.5 \,m^2\)
Total area occupied by doors:
\(\displaystyle\sf Total_{\text{doors}} = 2 \times Area_{\text{door}} = 2 \times 3 = 6 \,m^2\)
Total area occupied by windows:
\(\displaystyle\sf Total_{\text{windows}} = 4 \times Area_{\text{window}} = 4 \times 1.5 = 6 \,m^2\)
Total wall area excluding doors and windows:
\(\displaystyle\sf Total_{\text{wall\,area}} = (Area_1 + Area_2 + Area_3 + Area_4) - Total_{\text{doors}} - Total_{\text{windows}}\)
\(\displaystyle\sf = (87.5 + 87.5 + 63 + 63) - 6 - 6\)
\(\displaystyle\sf = 275 - 6 - 6\)
\(\displaystyle\sf = 263 \,m^2\)
Cost of painting the walls:
\(\displaystyle\sf Cost_{\text{painting}} = Total_{\text{wall\,area}} \times 3.50\)
\(\displaystyle\sf = 263 \times 3.50\)
\(\displaystyle\sf = 920.50 \,Rs\)
Therefore, the cost of painting the walls of the room at Rs. 3.50 per square meter is Rs. 920.50.
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85% of the dogs at a park weighed over 50 pounds. If there were 400 dogs at the park, how many dogs at the park weighed over 50 pounds?
Answers
Answer:
425
Step-by-step explanation:
The number of dogs at the park that weighed over 50 pounds will be 332 dogs.
What is the percentage?The amount of any product is given as though it was a proportion of a hundred. The ratio can be expressed as a quarter of 100. The phrase % translates for one hundred percent. It is symbolized by the character '%'.
The percentage is given as,
Percentage (P) = [Final value - Initial value] / Initial value x 100
85% of the dogs at a park weighed over 50 pounds. If there were 400 dogs at the park. Then the number of dogs at the park that weighed over 50 pounds will be given as,
⇒ 85% of 400
⇒ 0.85 x 400
⇒ 332 dogs
The number of dogs at the park that weighed over 50 pounds will be 332 dogs.
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I need an answer for 5/6x4. I appreciate the effort in helping. Sorry im not very good at fractions
Answers
Answer:
3.33
Step-by-step explanation:
Answer:
3 1/3
Step-by-step explanation:
5/6 x 4 = 3 1/3
I have know what is the exact answer for this question
Answers
Answer:
512? Or you using the other way