Elliot is promoting a concert and needs to print posters to put up aro und the city. He gets information from two companies on printing costs. APlus Printing charges a setup fee of $20 and 10 cents for each poster printed. PrintMore, a competing company, charges $55.00 for setup and five cents per poster. How can Elliot determine which plan will be cheaper?

The answer is "false". The interval [1, 2] contains all the real numbers between 1 and 2 including the endpoints.

An interval notation is used for representing the continuous set of real values. This is the shortest way of writing inequalities.

Intervals are represented within the brackets such as square brackets or open brackets(parenthesis).

The given interval is [1, 2]

The given statement is - 'the interval [1, 2] contains exactly two numbers - the numbers 1 and 2'

The given statement is 'false'.

This is beacuse, an interval consists set of all the real values in between the two values given.

So, according to the definition, there are not only the end values but also many real values in between them.

Thus, the answer is "false". The interval [1, 2] consists of all the real values between 1 and 2 including 1 and 2.

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Answer:

(2,0)

Step-by-step explanation:

Solve your system by substitution.

x=2 and y=0

Answer:

0.122

Step-by-step explanation

12/98=0.122

If the angle G is moved to a different spot in the circle the angle FGH and angle FEH in the cyclic quadrilateral will change to make it supplementary.

A cyclic quadrilateral is quadrilateral inscribed in a circle. It has all its vertices on the circumference of the circle.

Opposite angles in a cyclic quadrilateral are supplementary angles. That means they add up to 180 degrees.

Therefore, if he adjust point G to a different spot on the circle, angle FGH and FEH will adjust to become supplementary.

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In Tableau, a filter allows a visualization developer or user to dynamically remove rows from the visualization.  Thus, Option A is the answer.

What is Tableau?

Tableau is an interactive and intuitive data visualization tool that enables people to see and understand data. It provides a variety of data exploration, modelling, and visualization options. Tableau is one of the best data visualization software available in the market. It provides an easy way to integrate data from various sources. With Tableau, you can easily create interactive and visually appealing charts, graphs, and other types of visualizations that are easy to understand and interpret.

What is a filter?

In Tableau, a filter is a tool that allows you to selectively display data from a larger dataset based on certain conditions. Filters help you to narrow down your data to the most relevant information so you can make better decisions based on your analysis. Filters can be applied to different dimensions and measures to help you get a better view of your data. Tableau allows you to filter your data using various types of filters such as categorical, continuous, and relative filters. You can also create custom filters using calculated fields and parameters.

A filter allows a visualization developer or user to dynamically remove rows from the visualization. Therefore, the correct option is (a) Filter.

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Answer:

(x/4)+10

Step-by-step explanation:

Quotient=division, so x/4

Increased by 10, so (x/4)+10

Answer:925

Step-by-step explanation

Answer:

What square ?

Step-by-step explanation:

Answer:

75%

Step-by-step explanation:

Answer:

14

Step-by-step explanation:

because the side length are 5 and 5 and 4 which is 14.

plz mark the brainliest

Answer:

\(\huge\boxed{4}\)

Step-by-step explanation:

=> \(\sqrt{b^2-4ac}\)

Given that a = 3 , b = 8 and c = 4

=> \(\sqrt{(8)^2-4(3)(4)}\)

=> \(\sqrt{64-48}\)

=> \(\sqrt{16}\)

=> 4

Answer:

0.9

Step-by-step explanation:

We can tell straight away which is greater.

Like I said, fractions are like money

:$

9/10 is 0.9

Which means

0.9 IS a positive number

Remember

THE P-BODY RULE

A POSITIVE NUMBER, NO MATTER HOW LOW IT IS

will always ALWAYS

be greater than a negative number.

Answe

22 is your answers ....

Answer:

D

Step-by-step explanation

B. \( |2x + 1| + 1\)

\(( |2x + 1| + 3) - 2\)

\( |2x + 1| + 3 - 2\)

\( |2x + 1| + (3 - 2)\)

\( = |2x + 1| + 1\)

Answer:

Step-by-step explanation:

0.04

All the numbers that show 4% as an equivalent fraction, decimal or percent from the listed options are:

Percent counts the number compared to 100.

So, if we have a%, that means for each 100, there are 'a' parts. If we divide each of them with 100, we get:

For each 1, there are a/100 parts.

Thus, 50% = 50/100 = 0.50 (in decimal)

For this case, the percent we have is 4%

That shows that for each 100 items, we have 4 of them. This can be written in fraction as 4/100

Solving this division, we get the result in decimal as 0.04

Thus, all the numbers that show 4% as an equivalent fraction, decimal or percent from the listed options are:

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The speed of the man's shadow's tip at a distance of 10 feet from the light's base is given by dy/dt = 10 ft/s.

AB is equal to 15 feet in height.

Man's height in CD is 6 feet.

From the diagram attached, if BE = y, we may use the ratio of related triangles to obtain,

15/y = 6/(y - x) (y - x)

to obtain, cross-multiply;

15(y - x) = 6y

15y - 15x = 6y

15y - 6y = 15x

9y = 15x

To get, multiply both sides by 3.

3y = 5x

separating the two sides according to t provides;

dy = dt + dx = 3.

(5/3)(dx/dt dy/dt)

putting yields for dx/dt at 6 ft/s;

dy/dt = (5/3)(6) (6)

dy/dt equals 10 ft/s

One of the many real-world applications of trigonometry is the study of heights and distance. The terms height and distance are frequently used while discussing the applications of trigonometry.

The following ideas are incorporated in the trigonometry application for height and distance:

Measurement of the separation between two heavenly bodies

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Answer:

She will need to fill her spoon twice, once adding in the full amount, and the second adding half the amount.

3/4  ÷ 4/8

=3/4 * 2/1

=6/4

=1.5

So, that much amount would be needed o be added to the recipe during the two times

Estimating the doubling time for the given investment Assuming that an amount P is invested at r% per annum and compounded continuously then, the amount of investment in t years is given byA = Pe^(rt).

Here, the amount is doubled, so, we have to find t such that A = 2P.

A = Pe^(rt)2P = Pe^(rt)2 = e^(rt) Taking natural logarithm on both sides, we getln 2 = ln e^(rt)= rt  t = (ln 2) / rHere, P = $15,000, r = 6% per annum = 0.06 per annum So, the doubling time t = (ln 2) / r= (ln 2) / 0.06≈ 11.55 years (approx.)

b) Estimating the time required for $15,000 to grow to $240,000Here, the present value of the investment is $15,000 and the future value is $240,000.

Assuming that the investment is for t years at 6% per annum and compounded continuously, we can write:240,000 = 15,000e^(rt)Dividing both sides by 15,000, we get16 = e^(rt)ln 16 = ln e^(rt)ln 16 = rtTherefore, t = ln 16 / r

Here, r = 6% per annum = 0.06So, t = ln 16 / r= ln 16 / 0.06≈ 24.44 years (approx.)So, it will take around 24.44 years (approx.) for $15,000 to grow to $240,000 at 6% per annum compounded continuously.

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Answer:

Steepest to most gentle: W, Z, U, Y

Step-by-step explanation:

Answer: WZUY

Step-by-step explanation: On Edgenuity!!!!!!!!!!!

a) For labeled objects and boxes, there are 5⁶ = 15,625 possible distributions. b) For labeled objects and unlabeled boxes, there are 792 possible distributions. c) For unlabeled objects and labeled boxes, there are 5C6 = 5 possible distributions.d) There is only 1 possible distribution.

a) When both the objects and boxes are labeled, each object can be placed in any of the five labeled boxes, giving us 5 choices for each object. Since there are six objects in total, the total number of distributions is 5⁶ = 15,625.

b) When the objects are labeled but the boxes are unlabeled, we can use a technique called stars and bars. We have 6 objects (stars) and 5 boxes (bars). The objects can be distributed by placing the bars between the objects, so there are (6 + 5 - 1) choose (5 - 1) = 792 possible distributions.

c) When the objects are unlabeled but the boxes are labeled, we have 5 boxes, and we need to choose 6 objects to fill them. This can be thought of as choosing a subset of 6 objects out of 5, which can be done in 5C6 = 5 ways.

d) When both the objects and the boxes are unlabeled, there is only one possible distribution. Since the objects and boxes are indistinguishable, it does not matter which object goes into which box, resulting in a single distribution.

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Answer: Yes

Step-by-step explanation: Well 25% off of $20 is $15.

The mean squared error is 4.67. So the option a is correct.

In the given question, demand for a product and the forecasting department's forecast for a product are given.

We have to compute the mean squared error.

Period          Actual        Forecasted      Error       Absolute      Squared

                 Demand(E)    Demand (F)     (E-F)        Error |E-F|    Error |(E-F)|^2

1                12    

2                15                12              3               3             9

3                14                15              -1                1              1

4                18                16              2                2              4

                                                                Total=6        Total=14

Now we finding the mean squared error (MAE)

Mean squared error = ∑|(E−F)|^2/n

Mean squared error = 14/3

Mean squared error = 4.67

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the reference points for the transformation given by g(x) = 2*f(x) + 2 are (0, 4) and (1, 6).

The given function f has reference points (0, 1) and (1, 2). To find the reference points for the transformation given by g(x) = 2*f(x) + 2, we need to apply the transformation to each of the original reference points.

For the first reference point (0, 1), we have:

g(0) = 2f(0) + 2 = 21 + 2 = 4

So the transformed point is (0, 4).

For the second reference point (1, 2), we have:

g(1) = 2f(1) + 2 = 22 + 2 = 6

So the transformed point is (1, 6).

Therefore, the reference points for the transformation given by g(x) = 2*f(x) + 2 are (0, 4) and (1, 6).

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The graph of the inequality ­y > -3x + 5 is added as an attachment

From the question, we have the following parameters that can be used in our computation:

­y > -3x + 5

The above expression is a linear inequality that implies that

Next, we plot the graph

See attachment for the graph of the inequality

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Answer:

6

Step-by-step explanation:6/3= 2

The post-test measures the dependent variable.

In an experiment, the post-test measures refer to the data collected after the intervention or treatment has been given to the participants. Question 10 options may include choices related to the variables and groups involved in the experiment. Option a) the dependent variable is the variable being measured and is often affected by the independent variable. Option b) the independent variable is the variable being manipulated by the researcher to see its effect on the dependent variable. Option c) the experimental group is the group that receives the treatment or intervention, and option d) the control group is the group that does not receive the treatment or intervention and is used as a comparison to the experimental group. The question 10 options can help researchers determine the effects of the content loaded in an experiment on the variables and groups involved.

In an experiment, the post-test measures:

Question 10 options:
a) the dependent variable

Your answer: The post-test measures the dependent variable. This is because the dependent variable is the outcome that researchers are interested in measuring, and the post-test is conducted after the experiment to assess the effects of the independent variable on the dependent variable.

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The total area covered by the yard by the 3 sprinkler heads such that each covers a circular area with no overlap is 5892.857 ft².

The area of a circle is the area covered by the circle with radius r. It is given by the formula,

\(\text{Area of circle} = \pi r^2\)

As it is given that the area covered by a single sprinkler system is of the radius of 25 feet, therefore, the area covered by a singular sprinkler system can be written as,

Area of sprinkler = Area of a circle with radius 25 feet

 \(\begin{aligned}\text{Area of sprinkler}&= \pi r^2\\&=\pi (25^2)\\&= 1964.2857 \approx 1964.286\rm\ ft^2\end{aligned}\)

Now, as we know that the yard has three such sprinkler systems, therefore, the area covered by the sprinkler will be thrice the area covered by a single sprinkler,

The total area covered by the sprinkler = 3 x Area of sprinkler

                                                                   = 3 x 1964.286

                                                                   = 5892.857

Thus, the total area covered by the yard by the 3 sprinkler heads such that each covers a circular area with no overlap is 5892.857 ft².

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Answer:

The equation x²+12x+43=0 is a quadratic equation that can be solved by factoring or using the quadratic formula.

Factoring the equation:

x²+12x+43=(x+7)(x+6)=0

x+7=0 or x+6=0

x=-7 and x=-6

Therefore, the solutions for the equation are x=-7 and x=-6.

Alternatively, you can use the quadratic formula:

x = (-b± √(b²-4ac))/2a

Where a=1, b=12, c=43

x = (-12± √(12²-4143))/2*1

x = (-12± √(144-172))/2

x = (-12± √(-28))/2

x = (-12± i*√28)/2

x = (-12+ i2√7)/2 or x = (-12- i2√7)/2

These solutions are complex numbers, x = (-6+2i√7) or x = (-6-2i√7)