Answer:
Total resistance = 96 Ohms
Explanation:
Given the following data;
Resistance = 12 Ohms
Number of resistors = 8
To find the total resistance;
Method I.
Since the resistors are connected in series, we would simply multiply the resistance by the number of resistors.
Total resistance = 12 * 8
Total resistance = 96 Ohms.
Method II.
We would add the resistance of all the eight resistors together.
Total resistance = 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12
Total resistance = 96 Ohms.
The total resistance of the circuit will be "96 Ω".
Resistance and Current:Resistance: The amount of resistance to current flow throughout an electrical circuit.
Current: The movement of electrical charge carriers such as electrons has been referred to as current. The flow of current seems to be from negative (-) to positively (+) locations.
According to the question,
Resistance = 12 Ω
No. of resistor = 8
The total resistance be:
= \(Resistance\times Number \ of \ resistors\)
By substituting the values,
= \(12\times 8\)
= \(96 \ \Omega\)
Thus the above answer is right.
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If an action potential takes 50 milliseconds to travel 20
centimetres along an axon, what is the conduction velocity of the
axon in metres per second (m s-1)?
The conduction velocity of the axon is 0.4 m/s.
Conductive velocity = Distance / Time
= 20 cm / 50 milliseconds
= 0.4 m/s
The conduction velocity of an axon is determined by its diameter and its degree of myelination. Myelin is a fatty sheath that surrounds axons and helps to insulate them, which speeds up the conduction of action potentials.
Unmyelinated axons have a conduction velocity of about 0.5 to 10 m/s, while myelinated axons can have a conduction velocity of up to 150 m/s.
The conduction velocity of axons is important for the nervous system to function properly. It determines how quickly signals can travel from one part of the body to another.
For example, the conduction velocity of axons in the spinal cord determines how quickly pain signals can travel from the skin to the brain.
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2. A uniform rod of weight 5N and length 1m is pivoted at a point 20cm from one of its ends. A weight is hung from the other end so that the rod balances horizontally. What is the value of the weight?
Answer:
The weight is 7.5 N
Explanation:
Since the rod is uniform, its weight applies downwards at its middle (i.e 50 cm mark). The diagram attached to this answer shows the appropriate sketch.
Applying the principle of moment to the question, let the weight by represented by W.
Total clockwise moment = Total counterclockwise moment
\(F_{1}\) x \(d_{1}\) = \(F_{2}\) x \(d_{2}\)
5 x 0.3 = W x 0.2
1.5 = 0.2 W
W = \(\frac{1.5}{0.2}\)
= 7.5 N
The value of the weight is 7.5 N.
How many newtons of force
does a truck need to move a
S large boulder 12 meters
across a lawn, using 2,400
joules of energy?
The amount of force needed by the truck to move the boulder is 200 N.
Force:
This can be defined as the product of mass and acceleration. The S.I unit of force is Newton or kgm/s²
To calculate the newton's of force a block needs to move, we use the formula below.
Formula:
W = Fd............. Equation 1Where:
W = Work done by the truckF = Force applied on the boulderd = Distance moved by the boulderMake F the subject of the equation
F = W/d................. Equation 2From the question,
Given:
W = 2400 Jd = 12 metersSubstitute these values into equation 2
F = 2400/12F = 200 NHence, the amount of force needed by the truck to move the boulder is 200 N.
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Fossil's are the remains of ancient plants and animals which type of rock do you think is mostly likely to contain fossils?
Answer:
Sedimentary rocks.
Explanation:
A rock cycle can be defined as a concept used to describe the continuous process that leads to a rock's creation, formation, transformation from one form to another, destruction and reformation over a specific period of time. The natural phenomenons that influences the rock cycle are weathering, plate tectonic activity, erosion, etc.
A fossil can be defined as the mineral impression or remains of living organisms such as plants and animals that are prehistoric in nature.
Basically, the three (3) main types of rocks are; igneous rock, sedimentary rock and metamorphic rock.
Sediments come from living organisms such as plants to form organic sedimentary rocks and they are usually formed at pressure and temperature that doesn't destroy the fossils contained therein. Organic sedimentary rocks includes chalk, fossiliferous, coal, diatomite, etc. Also, some examples of inorganic land-derived sedimentary rocks are conglomerate, brescia and sandstone.
Hence, an organic sedimentary rock is a type of rock that contains or comprises of fossils.
12 A car travels in a straight line at speed v along a horizontal road. The car moves
against a resistive force F given by the equation
F = 400+kv²
where F is in newtons, v in ms-1 and k is a constant.
At speed v = 15ms-1, the resistive force F is 1100 N.
a
Calculate, for this car:
i the power necessary to maintain the speed of 15ms-¹,
ii the total resistive force at a speed of 30 ms-¹,
iii the power required to maintain the speed of 30ms-¹.
Answer:
i) Power = Force * Velocity = 1100 * 15 = 16500 W = 16.5 kW(ii) Find the value of k first: F = 400 + k(15^2) k = 28/9 F = 400 +(28/9)(30^2) = 320
Explanation:
What does this diagram represent?
A.) a turbine
B.) a motor
C.) a generator
D.) an electromagnet
The image shown in the question is a clear depiction of a generator.
What is a generator?A generator is an equipment that has to do with the production of electricity by the use of electromagnetic induction. The generator has split rings that make contact with the exterior.
The image shown in the question is a clear depiction of a generator.
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Answer:
Explanation:
C. Generator
A uniform electric field of magnitude 1.1 x 104 N/C is perpendicular to a square sheet with sides 2.0 m long. What is the electric flux through the sheet?
The electric flux through the square sheet is \(4.4 * 10^4 Nm^2/C\), when a uniform electric field of magnitude \(1.1 * 10^4 N/C\) is perpendicular to a square sheet with sides 2.0 m long.
The electric flux through a closed surface is given by the formula:
\(\[ \Phi = \mathbf{E} \cdot \mathbf{A} \]\)
where \(\(\Phi\)\) is the electric flux, \(\(\mathbf{E}\)\) is the electric field, and \(\(\mathbf{A}\)\) is the area vector of the surface. In this case, the electric field \(\(\mathbf{E}\)\) is perpendicular to the square sheet, and the magnitude of the electric field is given as \(1.1 * 10^4 N/C\).
The area of the square sheet is \(\(A = (2.0 \, \text{m})^2 = 4.0 \, \text{m}^2\)). Since the electric field is perpendicular to the surface, the angle between the electric field and the area vector is 0 degrees.
Substituting the values into the formula, we have:
\(\[ \Phi = (1.1 \times 10^4 \, \text{N/C}) \cdot (4.0 \, \text{m}^2) = 4.4 \times 10^4 \, \text{N} \cdot \text{m}^2/\text{C} \]\)
Therefore, the electric flux through the square sheet is \(4.4 * 10^4 Nm^2/C\).
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Which of the following is NOT common of elite Shang burials?
A. Objects of wealth
B. Large, above ground mausoleums
C. Elaborate pit tombs
D. Builders buried alive
Answer:
Large above ground mausoleums were not common in the elite Shang burials.
Explanation:
Large, above the ground mausoleums were not common so the answer is option B.
An unknown element X has the following isotopes: ¹²⁶X (22.00% abundant), ¹²⁸X (34.00% abundant), ¹³⁰X (44.00% abundant). What is the average atomic mass in amu of X?
The average atomic mass of element X is approximately 128.44 amu. The average atomic mass takes into account the relative abundances of the isotopes.
The average atomic mass is calculated by multiplying the mass of each isotope by its abundance and summing up these values. In this case, element X has three isotopes:
¹²⁶X, ¹²⁸X, and ¹³⁰X, with abundances of 22.00%, 34.00%, and 44.00% respectively.
To calculate the average atomic mass, we multiply the mass of each isotope by its abundance and sum up these values. The atomic mass of ¹²⁶X is 126 amu, ¹²⁸X is 128 amu, and ¹³⁰X is 130 amu.
Using the given abundances and atomic masses, we can calculate the average atomic mass as follows:
Average Atomic Mass = (126 amu × 0.22) + (128 amu × 0.34) + (130 amu × 0.44)
= 27.72 amu + 43.52 amu + 57.20 amu
= 128.44 amu
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Calculate the wavelength of the photons with the given frequencies and determine the type of electromagnetic radiation for each combination.
frequency: 4.38 × 10¹4 Hz
wavelength: m
type
frequency: 4.14 x 1020 Hz
wavelength: m
type
frequency: 3.24 × 1012 Hz
wavelength: m
type
Frequency: 4.38 × 10¹⁴ Hz
Wavelength: m
Type:
To calculate the wavelength, we can use the formula: λ = c / f, where λ represents the wavelength, c is the speed of light (approximately 3 × 10^8 m/s), and f is the frequency.
λ = c / f
λ = (3 × 10^8 m/s) / (4.38 × 10¹⁴ Hz)
λ ≈ 6.85 × 10^-7 m
The wavelength of the photons with a frequency of 4.38 × 10¹⁴ Hz is approximately 6.85 × 10^-7 meters.
Based on the calculated wavelength, this falls in the range of the visible light spectrum. The photons with this frequency would correspond to violet light.
Frequency: 4.14 × 10²⁰ Hz
Wavelength: m
Type:
Using the same formula, we can calculate the wavelength:
λ = c / f
λ = (3 × 10^8 m/s) / (4.14 × 10²⁰ Hz)
λ ≈ 7.25 × 10^-9 m
The wavelength of the photons with a frequency of 4.14 × 10²⁰ Hz is approximately 7.25 × 10^-9 meters.
This wavelength is in the range of X-rays. The photons with this frequency would correspond to X-ray radiation.
Frequency: 3.24 × 10¹² Hz
Wavelength: m
Type:
Using the same formula, we can calculate the wavelength:
λ = c / f
λ = (3 × 10^8 m/s) / (3.24 × 10¹² Hz)
λ ≈ 9.26 × 10^-4 m
The wavelength of the photons with a frequency of 3.24 × 10¹² Hz is approximately 9.26 × 10^-4 meters.
This wavelength falls in the microwave region. The photons with this frequency would correspond to microwave radiation.
In summary, the type of electromagnetic radiation for each combination is as follows:
1. Frequency: 4.38 × 10¹⁴ Hz, Wavelength: 6.85 × 10^-7 m, Type: Visible light (violet).
2. Frequency: 4.14 × 10²⁰ Hz, Wavelength: 7.25 × 10^-9 m, Type: X-rays.
3. Frequency: 3.24 × 10¹² Hz, Wavelength: 9.26 × 10^-4 m, Type: Microwave radiation.
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How do we weigh planets? Explain your thinking
What is the mass for both??
Answer:
forever alone uwu......
A +35 µC point charge is placed 46 cm from an identical +35 µC charge. How much work would be required to move a +0.50 µC test charge from a point midway between them to a point 12 cm closer to either of the charges?
Answer:
512.5 mJ
Explanation:
Let the two identical charges be q = +35 µC and distance between them be r₁ = 46 cm. A charge q' = +0.50 µC located mid-point between them is at r₂ = 46 cm/2 = 23 cm = 0.23 m.
The electric potential at this point due to the two charges q is thus
V = kq/r₂ + kq/r₂
= 2kq/r₂
= 2 × 9 × 10⁹ Nm²/C² × 35 × 10⁻⁶ C/0.23 m
= 630/0.23 × 10³ V
= 2739.13 × 10³ V
= 2.739 MV
When the charge q' is moved 12 cm closer to either of the two charges, its distance from each charge is now r₃ = r₂ + 12 cm = 23 cm + 12 = 35 cm = 0.35 m and r₄ = r₂ - 12 cm = 23 cm - 12 cm = 11 cm = 0.11 cm.
So, the new electric potential at this point is
V' = kq/r₃ + kq/r₄
= kq(1/r₃ + 1/r₄)
= 9 × 10⁹ Nm²/C² × 35 × 10⁻⁶ C(1/0.35 m + 1/0.11 m)
= 315 × 10³(2.857 + 9.091) V
= 315 × 10³ (11.948) V
= 3763.62 × 10³ V
= 3.764 MV
Now, the work done in moving the charge q' to the point 12 cm from either charge is
W = q'(V' - V)
= 0.5 × 10⁻⁶ C(3.764 MV - 2.739 MV)
= 0.5 × 10⁻⁶ C(1.025 × 10⁶) V
= 0.5125 J
= 512.5 mJ
Work done will be: \(512.5 \mu J\).
Given:
q = +35 µC
q' = +0.50 µC
r₁ = 46 cm
r₂ = 46 cm/2 = 23 cm = 0.23 m
The electric potential at this point due to the two charges q is thus
\(V = \frac{kq}{r_2}+\frac{kq}{r_2}\\\\ V= \frac{2kq}{r_2}\\\\V= \frac{2 * 9 * 10^9Nm^2/C^2 * 35 * 10^{-6} C}{0.23 m}\\\\V= \frac{630}{0.23*10^3}V\\\\V= 2739.13 * 10^3 V\\\\V= 2.739 \mu V\)
When the charge q' is moved 12 cm closer to either of the two charges, its distance from each charge is now;
r₃ = r₂ + 12 cm = 23 cm + 12 = 35 cm = 0.35 m and
r₄ = r₂ - 12 cm = 23 cm - 12 cm = 11 cm = 0.11 cm.
Thus, the new electric potential at this point is
\(V' = \frac{kq}{r_3} + \frac{kq}{r_4}\\\\V= kq(\frac{1}{r_3}+\frac{1}{r_4})\\\\V= 9 * 10^9 Nm^2/C^2 * 35 * 10^{-6} C (\frac{1}{0.35m}+\frac{1}{0.11m})\\\\V= 315 * 10^3(2.857 + 9.091) V\\\\V= 315 * 10^3 (11.948) V\\\\V= 3763.62 * 10^3 V\\\\V= 3.764 \mu V\)
Now, the work done in moving the charge q' to the point 12 cm from either charge is:
\(W = q'(V' - V)\\\\W= 0.5 * 10^{-6} C(3.764 MV - 2.739 MV)\\\\W= 0.5 *10^{-6} C(1.025 * 10^6) V\\\\W= 0.5125 J\\\\W= 512.5 \mu J\)
Thus, the work done will be: \(512.5 \mu J\).
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Calculate the speed of a bus that travels a distance of 55 miles in 0.75 hours.
During a canoe trip camper paddles distance of 406 M and 70 seconds what is the average speed of the canoe
Answer:
The average speed is 5.8 m/s
Explanation:
I just did it
two objects in thermal equilibrium with a third object are in thermal equilibrium with each other."" which law of thermodynamics is this?
The zeroth law of thermodynamic states that if two systems are in thermal equilibrium in equilibrium. with a third system, they are. with each other".
One of the four fundamental laws of thermodynamics is the zeroth law. It offers a stand-alone definition of temperature that excludes the second law's concept of entropy. Ralph H. Fowler created the law in the 1930s, many years after the first, second, and third laws had gained widespread acceptance.
According to the zeroth law, if two thermodynamic systems are in thermal equilibrium with one another and with a third system separately, then all three systems are in thermal equilibrium with one another.
The mathematical representation of thermodynamics depends on the zeroth law. It mathematically transforms the relationship between systems' thermal equilibrium into an equivalence relation, which can symbolize the equality of a particular quantity related to each system.
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24 1 point
Complete the fission reaction below by choosing the right isotope to go in the blank.
23U+n-
+Sr +3 n
What is the average speed of a race car that moved 20 kilometers in 10 minutes?
Answer:21
Explanation:every body said
(a) what is the wavelength of a 1.00-ev photon? (b) find its frequency in hertz. (c) identify the type of em radiation.
(a) The wavelength of a 1.00 eV photon is approximately 7.76 x 10^-7 meters.
(b) The frequency of the photon is approximately 3.86 x 10^14 Hz.
(c) The type of electromagnetic radiation corresponding to a 1.00 eV photon is within the visible light spectrum, specifically in the red part of the spectrum.
(a) To calculate the wavelength of a 1.00 eV photon, we use the equation λ = hc/E, where λ represents the wavelength, h is the Planck's constant, c is the speed of light, and E is the energy of the photon. By substituting the given values and converting eV to joules, we find that the wavelength is approximately 7.76 x 10^-7 meters.
(b) The frequency of the photon can be determined using the equation f = c/λ, where c is the speed of light and λ is the wavelength. By substituting the known values, we calculate the frequency to be approximately 3.86 x 10^14 Hz.
(c) Based on the obtained wavelength and frequency, we can identify the type of electromagnetic radiation. A 1.00 eV photon falls within the visible light spectrum. Specifically, it is in the red part of the spectrum, which has longer wavelengths and lower frequencies compared to higher-energy photons such as those in the ultraviolet or X-ray range.
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A ball is thrown straight up from the ground with an unknown velocity. It returns to the ground after 4.0 s. With what velocity did it leave the ground?
Answer:
It must return at the same velocity with which it was thrown or else there would be a preferred direction of motion leading to perpetual motion.
a = (v2 - v1) / t = (v2 - 0) / 2 = v2 / 2 for a falling object
v2 = 2 a = 2 sec * 9.8 m/sec^2 = 19.6 m/s
You can check with
H = V0 t - 1/2 g t^2 (V0 and g are in different directions)
H = 0
V0 = 1/2 g * 4 = 19.6 m/s
Engineers often build a prototype perfectly. It is rare that they have to improve their product.
True or false
Answer:
false
Explanation:
most prototypes are and perfect and they are build to find our mistakes
When do sea breezes occur
Four toy cars are moving at a constant speed until they experience an unbalanced force of 12 n each. Which toy car would have an acceleration of 3 m/s2 ?.
Answer: the car mass with four would have an accelaration
Explanation:
Một điện tích q=20uc trong chân không
a) tìm cường đọ điện trường tại M cách A đoạn 40cm
b) điện chế tại A là 10V. Thế năng tại tại A bằng bao nhiêu
Answer:
hi please write in english
Explanation:
fraction that occurs in gases and liquids is called what
plzz help meeeee
Answer:
it is called fluid friction.
The period of a pendulum of length 0.500 m is
14.2 s
7.02 s
1.42 s
0.702 s
0.450 s
Answer:
C. 1.42 s
Explanation:
Givens:
length = 0.5m
gravity = 9.807 m/s
Solve:
T = 2π√(L/g)
T = 2π√(0.5/9.807)
T = 2π√(0.0509)
T = 2π * 0.22579
T = 6.28318 * 0.22579
T = 1.418 ≈ 1.42s
What is leadership? Why is leadership important in the health sciences? First to answer brainliest
the action of leading a group of people or an organizaton, leadership is important during sciences because, if someone doesn’t know what to do you can lead them in the right way
Explanation:
Answer:
Within healthcare, skilled leaders motivate staff to work at their highest potential to benefit patients, their colleagues, and the organization as a whole.
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What happens to the boat when its weight is greater than the buoyant force?
What happens to the boat when its weight is less than the buoyant force?
What happens to the boat when its weight is equal to the buoyant force?
Answer:
1. and 2. If the buoyant force is greater than the object's weight, the object rises to the surface and floats. If the buoyant force is less than the object's weight, the object sinks. If the buoyant force equals the object's weight, the object can remain suspended at its present depth.
3. When the buoyant force equals one ton, it will sink no further. When any boat displaces a weight of water equal to its own weight, it floats. This is often called the “principle of flotation” where a floating object displaces a weight of fluid equal to its own weight.
Explanation:
Can anyone help me with my history question.
Hello everyone, I just want to know the formula to solve this problem:
What is the speed of sound at 62°C?
and how to solve this kind of problem? My brain isn't working.. :)
Answer:
367 m/sExplanation:
Use simplified formula:
\(v=331.3\sqrt{1+T/273.15}\) , where T- temperature in Celsiusyou have a 1.30-m-long copper wire. you want to make an n-turn current loop that generates a 0.700 mt magnetic field at the center when the current is 1.20 a . you must use the entire wire.
The magnetic field generated by a current loop is given by the equation:
B = (μ0 * n * I * A) / (2 * R)
where μ0 is the permeability of free space (4π x 10^-7 T·m/A), n is the number of turns, I is the current, A is the area of the loop, and R is the distance from the center of the loop to the point where the magnetic field is measured.
In this case, we want to make a loop with a length of 1.30 m, so the circumference of the loop will be C = 2πr = 1.30 m, where r is the radius of the loop. Solving for r, we get:
r = C / (2π) = 1.30 m / (2π) = 0.2077 m
The area of the loop is given by A = πr^2, so:
A = π(0.2077 m)^2 = 0.1358 m^2
Now we can plug in the values given and solve for the number of turns:
0.700 T = (4π x 10^-7 T·m/A) * n * 1.20 A * 0.1358 m^2 / (2 * 0.2077 m)
Solving for n, we get:
n = (0.700 T * 2 * 0.2077 m) / [(4π x 10^-7 T·m/A) * 1.20 A * 0.1358 m^2]
n = 147.4 turns
Therefore, you need to make a current loop with 147 turns to generate a 0.700 mT magnetic field at the center of the loop using the entire 1.30 m long copper wire.
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