If Dylan were to triple his distance from the center of the Earth by flying in a spacecraft, his weight on the surface of the Earth would decrease to one-ninth of his original weight, which is approximately 69 N.
According to the law of universal gravitation, the weight of an object is directly proportional to the mass of the planet and inversely proportional to the square of the distance from the center of the planet.
Therefore, if Dylan triples his distance from the center of the Earth by flying in a spacecraft, his weight on the surface of the Earth would be one-ninth of his original weight. This is because the distance has been tripled, and the inverse square of three is nine.
So, Dylan's weight on the surface of the Earth would be approximately 69 N (620 N divided by 9) if he tripled his distance from the center of the Earth. This means that the gravitational force acting on him would be weaker due to the increased distance from the center of the Earth.
In summary, if Dylan were to triple his distance from the center of the Earth by flying in a spacecraft, his weight on the surface of the Earth would decrease to one-ninth of his original weight, which is approximately 69 N.
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Substitute numerical values into the expression in the correct choice in question (2) to find the acceleration of the electron. + (by - vs. 1,602 x 10-19 XC V/m) 550 kg Vm) - (49 m)]} x 101 m/s2 SUBRENNSTON
Acceleration is a measure of the rate of change of velocity, and electrons can be accelerated by applying a voltage across a circuit.
To substitute numerical values into the expression, we need to know the value of the variables. Unfortunately, the question does not provide enough information to determine the values of the variables. Therefore, we cannot find the acceleration of the electron with the given expression.
However, we can discuss the concept of acceleration and the role of electrons in it. Acceleration is the rate at which an object changes its velocity. It is a vector quantity and is measured in meters per second squared (m/s^2). When a force is applied to an object, it can accelerate.
In the case of electrons, they can be accelerated by applying a voltage across a circuit. The force on the electrons is provided by the electric field created by the voltage. The acceleration of the electrons depends on the strength of the electric field, which is measured in volts per meter (V/m).
In summary, acceleration is a measure of the rate of change of velocity, and electrons can be accelerated by applying a voltage across a circuit. Without knowing the values of the variables in the given expression, we cannot find the acceleration of the electron.
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The kangaroo stops at a lake for a drink of water, then starts hopping again to the south. After 5 seconds, the kangaroo is going 2.5 m/s south. What is the kangaroo’s acceleration?
Answer:
A kangaroo hops 60 m to the east in 5 s. What is the kangaroo's average velocity? ... The kangaroo stops at a lake for a drink of water and then starts hopping again to the south. Each second, the kangaroo's velocity increases 2.5 m/s.
There is not really a subject for this but, Theoretically, What black hole would be bigger, m87 aka Messier 87 or Ton 618 aka Tonantzintla 618. Although Messier 87 was the first picture of one, what would the size still be of Tonantzintla 618 I would like to know what you think
The event horizon is directly related to the mass of the black hole, with larger black holes having larger event horizons.
What is Black Hole?
A black hole is an astronomical object that has collapsed to such a small size that its gravitational pull is so strong that nothing, not even light, can escape it. Black holes are formed from the remnants of massive stars that have run out of fuel and undergone a catastrophic collapse, or from the merging of two or more smaller black holes.
M87 and Ton 618 are both supermassive black holes, with masses estimated to be around 6.5 billion and 66 billion times the mass of the Sun, respectively. However, the size of their event horizons would depend not only on their mass but also on their spin and the density of the surrounding matter. It is therefore not possible to predict which black hole would be bigger without additional data and calculations.
It is worth noting that the first image of a black hole that was released in 2019 was actually an image of the event horizon of the black hole in M87, not the black hole itself. The event horizon of M87's black hole was estimated to be around 40 billion km in diameter, which is larger than the entire solar system.
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Kangaroos can jump approximately 2.9 meters high. What is the takeoff speed of the kangaroo? (Note: the acceleration due to gravity on Earth
is 9.81 m/s/s)
6.9 m/s
57 m/s
Оа
Ob
Ос
Od
28 m/s
13 m/s
3.4 m/s
0.30 m/s
33 m/s
OS
On
7.5 m/s
The takeoff speed of the kangaroo is approximately 7.5 m/s (answer On).
To find the takeoff speed of a kangaroo that can jump approximately 2.9 meters high, we can use the following kinematic equation:
v^2 = u^2 + 2as
where v is the final velocity (0 m/s at the peak of the jump), u is the initial takeoff speed, a is the acceleration due to gravity (-9.81 m/s^2), and s is the jump height (2.9 meters). We want to find u.
Rearranging the equation for u, we get:
u^2 = v^2 - 2as
u^2 = 0^2 - 2(-9.81)(2.9)
u^2 = 56.914
Taking the square root of both sides:
u ≈ 7.54 m/s
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A product P is produced from reagents A and B, but unfortunately it can further react with one reagent and degrade at the reaction conditions. The two steps are 1: 2: A + 2B -P 2P +B-X The reaction takes place in liquid phase and B is present in significant excess. The initial concentrations of A and B are, CA = 0.57 mol/L and CB.=55.57 mol/L respectively (there is nothing else in the initial mix). The first step of the reaction is a zero order reaction, while the second step is described by a first order rate at the conditions in the reactor. It is known that at the temperature of operation of 70 °C the two rates are: -11 = = 0.025 mol of A/(L.min) -12 = K2 Cp = 0.0075 CP mol of P/(L.min) a. Determine the net rates of reaction of all components AND the expression for instant selectivity [40 Marks] b. Based on the material balances to a batch reactor that will be used for this reaction, derive the expression with which you can obtain the concentration of P over time. [40 Marks] C. According to the expression you achieved for Co, under which conditions will the desired product P be at its maximum concentration? [20 Marks)
The net rates of reaction for all components and the expression for instant selectivity are determined. The concentration of P over time in a batch reactor is derived, and the conditions for maximum concentration of P are discussed based on the rate-determining step.
a. The net rate of reaction for component A is given by -11 = -0.025 mol of A/(L.min), as it is a zero order reaction. The net rate of reaction for component P is given by -12 = K2 * Cp = 0.0075 CP mol of P/(L.min), as it is a first order reaction. The net rate of reaction for component B can be calculated by considering the stoichiometry of the two steps.
The instant selectivity is the ratio of the net rate of production of P to the net rate of consumption of A, which can be expressed as selectivity = -12 / -11.
b. Based on material balances for a batch reactor, the rate of change of concentration of P over time (dCp/dt) can be expressed as (dCp/dt) = -2 * (-12) = 0.015 CP mol/(L.min), using the stoichiometry of the reaction.
c. To determine the conditions for maximum concentration of P, we need to consider the rate-determining step. Since the second step is first order, it determines the overall rate of the reaction. To maximize the concentration of P, we need to maximize the rate of the second step. This can be achieved by increasing the concentration of P or the concentration of B while keeping the other reactants at their initial concentrations.
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A body weighing 350N runs up a flight of stairs consisting of 10 steps each of 5m height in 5 sec.What is the power of the body?
Power is defined as the rate at which work is done or energy is transferred. The power of the body is 3,500 watts.
It can be calculated using the formula:
Power = Work / Time
In this case, we need to calculate the power of the body.
The work done by the body is equal to the force applied (weight) multiplied by the distance covered. The distance covered is the height of each step multiplied by the number of steps.
Work = Force * Distance
Work = 350 N * (10 steps * 5 m/step)
Work = 350 N * 50 m
Work = 17,500 J (joules)
The time taken to complete the work is given as 5 seconds.
Now we can calculate the power:
Power = Work / Time
Power = 17,500 J / 5 s
Power = 3,500 W (watts)
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which statements are true concerning a substance with a high specific heat? select one or more: the substance cools down slowly after heating. an example substance is aluminum metal. the substance easily gets hot when heat is applied. an example substance is water.
The statement that is true concerning a substance with high specific heat is as follows: the substance cools down slowly after heating. an example substance is aluminum metal (option A)
What is specific heat?Specific heat or specific heat capacity refers to the heat capacity per unit mass of a pure substance.
In other words, specific heat is defined as the amount of heat needed to increase the temperature of 1kg of a material by 1K and is expressed in terms of J/kg·K or equivalently J/kg·°C.
The specific heat capacity of a material is a physical property. It is also an example of an extensive property since its value is proportional to size.
Water is an example of a substance that has an extremely high specific heat capacity, which makes it good for temperature regulation.
Therefore, a substance with high specific heat cools down slowly after heating and an example is aluminum metal.
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Three different resistors are connected in series to a battery. Which of the following statements is correct about this circuit? The equivalent resistance of the circuit is the algebraic sum of all resistors. O All of these options are true. Currents through all resistors are the same. O Total voltage on this combination is an algebraic sum of voltages on each resistor.
When three different resistors are connected in series to a battery, the current through all resistors is the same.
In a series circuit, there is only one path for current to flow through. Current is the same through each component.
In a series circuit, the total voltage is divided across each component, and the voltage drop across each component is proportional to its resistance.
The equivalent resistance of the circuit is the sum of all resistors. It is not an algebraic sum, rather it is the arithmetic sum of the resistors. Hence, option A is incorrect.
The other two statements are also incorrect as the voltage on each resistor is not the same, it is divided across each resistor in proportion to its resistance. Therefore, the correct statement about the given circuit is: Currents through all resistors are the same.
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If you stack 3 nickels on a table, how far above the table is their center of gravity?
Answer:
2.93 mm
Explanation:
If you stack 3 nickels on a table, e the table is their center of gravity 2.93 mm
what is center of gravity?The Centre of gravity is a theoretical term, where the body’s total weight is thought to be concentrated and it predicts the behavior of a moving body when acted on by gravity.
It is also useful in designing static structures like buildings and bridges, the center of gravity is identical to the centre of mass.
For the Moon, the centre of mass is very close to its geometric centre and its centre of gravity is slightly towards the Earth due to the stronger gravitational force on the Moon’s near side.
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What is the wavelength of a 6.00*10^2 Hz sound wave in air at 20C
Answer:
Solution
λ=v/n
Here, v=344 m s−1
n=22 MHz =22×106 Hz
λ=344/22×106=15.64×10−6m=15.64μm.
The wavelength of a 6.00 ×10² Hz sound wave in air at 20° C is 57.17 cm.
What is sound?A sound is a vibration that travels as a mechanical wave across a medium. It can spread through a solid, a liquid, or a gas as the medium. Solids carry sound the quickest, liquids somewhat more slowly, and gases the least slowly.
According to physics, sound is described as a vibration that travels through a material like a gas, liquid, or solid as an audible wave of pressure.
Given parameters:
Frequency of sound wave = 6.00 ×10² Hz.
At 20° C, speed of sound in dry air = 343 m/s.
We have to find, the wavelength of the sound wave at 20° C = ?
For wave motion,
Speed = frequency × wavelength
Hence, the wavelength of the sound wave = speed / frequency
= 343 / 6.00 ×10² meter
= 0.5717 meter
= 57.17 cm.
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Under the Big Top elephant, Ella (2500 kg), is attracted to Phant, the 3,000 kg
elephant. They are separated by 8 m. What is the gravitational attraction between
them?
Under the Big Top elephant, Ella (2500 kg), is attracted to Phant, the 3,000 kg elephant. They are separated by 8
A jumpy squirrel is trying to cross the street. Its velocity vvv as a function of time ttt is given in the graph below where rightwards is the positive velocity direction.
A set of black coordinate axes are given with the vertical axis labeled "v (m/s)" and the horizontal axes labeled "t (s)". A curve that relates v to t is shown in blue. It begins with a straight line of endpoints (0,0) and (1,5). This first line is connected to a second line with endpoints (1,5) and (3,-5). This second line is then connected to a third line of endpoints (3,-5) and (6,-5).
A set of black coordinate axes are given with the vertical axis labeled "v (m/s)" and the horizontal axes labeled "t (s)". A curve that relates v to t is shown in blue. It begins with a straight line of endpoints (0,0) and (1,5). This first line is connected to a second line with endpoints (1,5) and (3,-5). This second line is then connected to a third line of endpoints (3,-5) and (6,-5).
What is the squirrel's displacement \Delta xΔxdelta, x from t=1\,\text st=1st, equals, 1, start text, s, end text to 2\,\text s2s2, start text, s, the answer is 2.5 I solved it
Answer: 2.5
Explanation: cause it is
2.List two changes an unbalanced force can cause.
Answer:
By applying an unbalanced force, you can change the motion of an object. Unbalanced forces can make an object at rest start moving, make a moving object stop, or change the direction and speed of the object.
Explanation:
A particle starts to move in a straight line with a velocity of 10 m/s
and deceleration - 2 m s-2. What will the velocity of particle be after
5 s and after 10 s?
a 30 m/s after 5 s and 20 m/s after 10 s.
b Zero after 5 s and 30m/s after 10 s.
C 20 m/s after 5 s and 30 m/s after 10 s.
d Zero after 5 s and -10 m/s after 10 s.
Answer:
Explanation:
Lol man
Answer: Zero after 5 s and -10 m/s after 10s
Explanation:
a 78.0 kg ice hockey goalie, originally at rest, catches a 0.150 kg hockey puck slapped at him at a velocity of 34.0 m/s. suppose the goalie and the ice puck have an elastic collision and the puck is reflected back in the direction from which it came. what would their final velocities (in m/s) be in this case? (assume the original direction of the ice puck toward the goalie is in the positive direction. indicate the direction with the sign of your answer.)
In an elastic collision between a hockey goalie and a hockey puck, the final velocities of both objects can be calculated. The goalie, initially at rest, catches the 0.150 kg hockey puck slapped at him at a velocity of 34.0 m/s. After the collision, the puck is reflected back in the opposite direction.
In an elastic collision, both momentum and kinetic energy are conserved. We can use the principles of conservation of momentum and kinetic energy to solve for the final velocities. Since the goalie is initially at rest, their final velocity will depend on the mass and velocity of the puck. By setting up momentum and kinetic energy equations and solving them simultaneously, we can calculate the final velocities. The goalie's final velocity will be in the opposite direction of the initial puck velocity, indicated by the negative sign.
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What type of wave is an electromagnetic wave?
transverse
longitudinal
both
neither
HELP is it impossible to experience free fall near the earths surface? why?
Dancers experience large forces associated with the jumps they make. For example, when a dancer lands after a vertical jump, the force exerted on the head by the neck must exceed the head’s weight by enough to cause the head to slow down and come to rest. The head is about 9.4% of a typical person’s mass. Video analysis of a 61 kg dancer landing after a vertical jump shows that her head slows down from 4.2 m/s to rest in a time of 0.19 s .What is the magnitude of the average force that her neck exerts on her head during the landing? Express your answer in newtons to three signifcant figures.
The required magnitude of the average force that her neck exerts on her head during the landing is 1915 newtons.
How to find force and its direction?This force will act uniformly and upward on the head. Since deceleration is the same in the first and second halves, force F will likewise be the same.
As a result, the average force is determined by multiplying the body's mass by the object's average velocity during the specified period of time.
According to question:Deceleration = 4.2 - 0 / 0.19 = 22 m/s2 because the head slows down from 4.2 m/s to zero in 0.19 seconds.
F - mg = ma if F is the average force pressing on the head.
F = m ( g + a )\s= 61 ( 9.4 + 22 )\s= 1915 N .
Thus,required force is 1915N.
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which of the four terrestrial planets has or have a global (planetwide) magnetic field?
Tambora volcano on the island of Sumbawa Indonesia has been known to throw ash into the air with the speed of 625 m/s during an eruption, how high could this volcano plume have risen
The maximum height reached by the Tambora volcano after the eruption is 19,929.85 m.
What is the maximum height reached by the Tambora volcano?The maximum height reached by the Tambora volcano is calculated by applying the following kinematic equation as shown below;
v² = u² - 2gh
where;
v is the final velocity of the volcanou is the initial velocity of the volcanoh is the maximum height reached by the volcanog is acceleration due to gravityat maximum height, the final velocity, v = 0
0 = u² - 2gh
2gh = u²
h = u²/2g
h = (625²) / (2 x 9.8)
h = 19,929.85 m
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suppose the string you are using is rated for no more than 60.0 n (approx 12 lb ). how fast could you fly your model plane before the string breaks?
the maximum speed at which the model plane can fly before the string breaks is approximately 23.0 m/s
Calculating the tension in the string at the plane's top speed will allow us to estimate the fastest the model plane can fly before the string snaps. We may use this number to determine the maximum speed of the plane by assuming that the string can withstand a maximum tension of 60.0 N.
Let's say that the model plane has mass m and a top speed of v. Newton's second law of motion may be used to determine the tension in the string at the plane's top speed:
Tension is equal to m*(v2/R) + mg.
where g is the acceleration brought on by gravity and R is the radius of the plane's circular path.
We may assume that the tension in the string is equal to its maximum value of 60.0 N as we are trying to determine the maximum speed of the plane. Rearranging the equation will allow us to find v:
(Tension - mg) * R / m = sqrt(v)
Tension, R, m, and g values are substituted, and the result is:
v is equal to sqrt((60.0 N - (m * 9.81 m/s2))
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describe your results. include: what function did you use to linearize the data? what is the mathematical relationship you found?
This equation demonstrates the relationship between your variables and allows you to make predictions or draw conclusions based on the linearized data.
To answer your question, I would need more specific details about your experiment or the data you are working with. However, I can provide a general explanation using the terms you've provided.
To linearize data, you might have used a specific function such as the logarithmic, exponential, or power function, depending on the context of the data. The choice of function depends on the pattern observed in the data and the best fit for linearization.
The mathematical relationship you found would be represented as an equation, typically in the form of y = mx + b for a linearized function. Here, 'm' represents the slope of the linearized data, and 'b' is the y-intercept. This equation demonstrates the relationship between your variables and allows you to make predictions or draw conclusions based on the linearized data.
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. A student times a car traveling a distance of 2 m. She finds that it takes the car 5 s to
travel the first meter and then another 8 s to travel the second meter. Is the car traveling
at a constant speed? How do you know?
what is mostly likely to be an observation of an anatogy
You would normally find parallels between the two things or concepts being compared while making an observation of an analogy. Here is an illustration of a comparison observation.
What is meant by the term Anatomy?The investigation of an animal's or plant's structure. The organs, tissues, and cells that make up the human body as well as how they are arranged inside it are all included in human anatomy.
The primary categories include comparative anatomy, phytotomy, zootomy, human anatomy, microscopic anatomy, and gross anatomy.
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What must be your average speed in order to travel 350 km in 5.15 h? *
66.0 km/h
67.0 km/h
68.0 km/h
69.0 km/h
A spring with spring constant 110 N/m and unstretched length 0.4 m has one end anchored to a wall and a force F is applied to the other end.
a. If the force FF does 225 JJ of work in stretching out the spring, what is its final length?
Express your answer in meters.
b. If the force FF does 225 JJ of work in stretching out the spring, what is the magnitude of FF at maximum elongation?
Express your answer in newtons.
For (a), The final length of the spring after applying a force that does 225 J of work is approximately 2.02 meters by using Hooke's law. For (b), the magnitude of the force FF at maximum elongation, is approximately 222.2 newtons.
a. The work done by a force on an object is given by the formula W = (1/2)kx^2, where W is the work done, k is the spring constant, and x is the displacement of the object from its equilibrium position. In this case, we know the work done (225 J) and the spring constant (110 N/m). We need to find the final length, which corresponds to the displacement x.
Using the formula W = (1/2)kx^2, we can rearrange the equation to solve for x:
225 = (1/2)(110)x^2
Multiplying both sides by 2/110:
225 * (2/110) = x^2
x^2 = 4.09
Taking the square root of both sides:
x ≈ 2.02 m
Therefore, the final length of the spring is approximately 2.02 meters.
b. At maximum elongation, the force applied to the spring will be equal to the spring force exerted by the spring to oppose the stretching. The magnitude of the force is given by Hooke's Law: F = kx, where F is the force, k is the spring constant, and x is the displacement.
Using the given values, we have:
F = (110 N/m)(2.02 m)
F ≈ 222.2 N
Therefore, the magnitude of the force FF at maximum elongation is approximately 222.2 newtons.
a. The final length of the spring after applying a force that does 225 J of work is approximately 2.02 meters.
b. The magnitude of the force FF at maximum elongation, when the spring has been stretched by 225 J of work, is approximately 222.2 newtons.
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Uniform Circular Motion: You need to design a wheel for testing purposes such that its rim will have an acceleration of 1.5 g when the rim is moving at 37 m/s while spinning. What should be the diameter of this wheel?
Answer:
We want to have an acceleration of:
A = 1.5*g = 1.5*9.8m/s^2 = 14.7 m/s^2
When the rim is moving at 37m/s while spinning.
Now, in circular motion we have two accelerations.
Tangential acceleration, that is the one related to the change of speed, as we have a speed of 37m/s, we can assume that is constant, then the tangential acceleration is zero.
Centripetal acceleration, is the one related to the change in direction, is perpendicular to the velocity vector and is the one that allows the circular motion.
I suppose that in this problem we want to have a centripetal acceleration of 14.7m/s^2
The equation for the centripetal acceleration is:
Ac = v^2/r
Where v = velocity and r = radius.
then we must solve:
14.7m/s^2 = (37m/s)^2/r
r = (37m/s)^2/14.7m/s^2 = 93.13 m
How long is a pendulum with a period of 1.0 s on the moon, which has one-sixth of the earth's gravity?
The length of the pendulum on the Moon with a period of 1.0 s is approximately 0.0163 meters.
On the Moon, which has one-sixth of Earth's gravity, the length of a pendulum with a period of 1.0 s can be determined using the formula for the period of a pendulum:
T = 2π√(L/g)
Where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.
Given that the period of the pendulum on the Moon is 1.0 s and the Moon has one-sixth of Earth's gravity, we can substitute these values into the formula and solve for L:
1.0 = 2π√(L/(1/6g))
Simplifying the equation, we can multiply both sides by (1/6g):
\(1.0 * (1/6g) = 2π√L1/6g = 2π√L\)
Now, let's square both sides to get rid of the square root:
\((1/6g)^2 = (2π√L)^21/(6g)^2 = (2π)^2L1/(36g^2) = 4π^2L\)
Simplifying further:
\(L = 1/(4π^2(36g^2))L = 1/(144π^2g^2)L ≈ 0.0163 m\)
Therefore, the length of the pendulum with a period of 1.0 s on the Moon, which has one-sixth of Earth's gravity, is approximately 0.0163 meters.
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What does the word vector mean?
Answer:
Vector, in physics, a quantity that has both magnitude and direction. It is typically represented by an arrow whose direction is the same as that of the quantity and whose length is proportional to the quantity's magnitude. Although a vector has magnitude and direction, it does not have position
One light-year is the distance light travels in one year. This distance is equal to 9.461 1015 m. After the sun, the star nearest to Earth is Alpha Centauri, which is about 4.35 light-years from Earth. Express this distance in a. megameters. b. picometers.
Answer:
A.) 411.6 Mega metres
B.) 411.6 × 10^18 Picometers
Explanation:
Given that One light-year is the distance light travels in one year. This distance is equal to 9461 1015 m.
After the sun, the star nearest to Earth is Alpha Centauri, which is about 4.35 light-years from Earth.
The distance travelled will be
Distance = 9461 1015 × 4.35
Distance = 411557915.3 m
To Express this distance in
a. megameters, divide the value by 1000000
411557915.3 / 1000000
411.5579153 Mega metre
411.6 Mega metres approximately
b. picometers, multiply by 10^12
That is, 411557915.3 × 10^12
411.6 × 10^18 Picometers