During the Contact Process SO3 is produced from SO2 in a reversible reaction: 2SO2(g) + O2(g) ⇌ 2SO3(g) Write an expression for the equilibrium constant, Kc, and derive its units.

Answers

Answer 1

Equilibrium constant is the only concept that is to be used here to calculate partial pressure of nitrogen. Therefore,  Kc, equilibrium constant with respect to concentration is [SO\(_3\)]²÷[SO\(_2\)]²[O₂].

What is equilibrium constant?

Equilibrium constant is a rate constant at equilibrium shows the values of reaction with respect to the atmospheric pressure and concentration. Kc is equilibrium constant with respect to concentration. Kp is equilibrium constant with respect to atmospheric pressure.

Mathematically,

Kc= Product of concentration of all products÷ Products of concentration of all reactant

Kc=[SO\(_3\)]²÷[SO\(_2\)]²[O₂]

Therefore,  Kc, equilibrium constant with respect to concentration is [SO\(_3\)]²÷[SO\(_2\)]²[O₂]

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Related Questions

What is happening to the electrons between several atoms of Copper?

A.nothing happens to the electrons
B.the electrons become delocalized and form a "sea"
C.they are shared between two atoms
D.the electrons are transferred from one atom to another

Answers

Answer:

\(\color{Blue}\huge\boxed{Answer} \)

B.the electrons become delocalized and form a "sea"

Which statement about the scientific consensus is true

Answers

Answer:

u forgot send the exercise.. try it again

Draw a structural formula for the major product of the reaction shown.

Answers

Draw a structural formula for the major product of the reaction shown:

The structural formula for the major product (2-butene) of the given reaction is as follows:$$\ce{CH3CH2CH=CH2}$$

The given reaction is an acid-catalyzed dehydration reaction.

During the reaction, the hydroxyl group (OH) and the adjacent hydrogen atoms (H) on the reactant alcohol (2-butanol) undergo dehydration (loss of water) to form an alkene (2-butene) as the major product.

The reaction is shown below:$$\ce{CH3CH2CH2CH2OH + H2SO4 ->[\Delta] CH3CH2CH=CH2 + H2O}$$To draw the structural formula for the major product of the given reaction, we need to consider the following points:

1. The reactant alcohol (2-butanol) is a four-carbon alcohol with the hydroxyl group (OH) attached to the second carbon atom (C2) of the chain.

2. The product alkene (2-butene) will be a four-carbon alkene with a double bond between the second and third carbon atoms (C2 and C3) of the chain.

The other two carbon atoms will have a single bond with the adjacent carbon atoms and a hydrogen atom each attached to them.

3. The major product will be formed via the elimination of water (dehydration) between the hydroxyl group (OH) and the adjacent hydrogen atoms (H) on the second carbon atom (C2) of the reactant alcohol (2-butanol).

4. The acid catalyst (H2SO4) does not participate in the reaction and remains unchanged. It only facilitates the formation of the alkene by providing a proton (H+) to the hydroxyl group (OH) and a medium for the elimination of water.

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you find a mysterious white powder in your kitchen. it could be cream of tartar (pH=5), sugar (pH=7), baking soda (pH=8), or drain cleaner (pH=14). explain which pH indicator(s) you would use to determine the unknown substance.

Answers

The pH indicators that would be used to determine the unknown substance are :

Litmus Methyl orangePhenol Red

pH Indicators

The pH indicators that can be used to identify the mysterious white powder in the kitchen must be an acid-base indicator such as Litmus or other form of effective pH indicators like methyl orange and Phenol red.

The pH value of the substance as indicated by the acid-base indicators will help to determine what the mysterious white powder is based on the varying pH of the substances resembling the white powder.

Hence we can conclude that The pH indicators that would be used to determine the unknown substance are :Litmus , Methyl orange, Phenol Red.

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If the hydronium ion concentration of a substance is 1.0 X 10-6 M, what would be the pH of that substance??
Show/Describe your work.

Answers

Fam fam fam fam fam just trust bruh I did the work

3.00 L of a gas is collected at 35.0 C and 0.93 atm. What is the volume at STP

Answers

2.47L

Hope this helped have a great day :)

Nitrogen and hydrogen combine at a high temperature, in the presence of a catalyst, to produce ammonia.

N2(g)+3H2(g)⟶2NH3(g)

There are four molecules of nitrogen and nine molecules of hydrogen present in the diagram.

When the reaction is complete, how many molecules of NH3 are produced?
What is the limiting reactant?
How many molecules of each reactant are remain after the reaction is complete?

Answers

After the reaction is complete, no nitrogen and no hydrogen molecules remain, and 8.00 x 1014 molecules of NH3 are produced.

In the equation, nitrogen and hydrogen react at a high temperature, in the presence of a catalyst, to produce ammonia, according to the balanced chemical equation:N2(g)+3H2(g)⟶2NH3(g)The coefficients of each molecule suggest that one molecule of nitrogen reacts with three molecules of hydrogen to create two molecules of ammonia.

So, to determine how many molecules of ammonia are produced when four nitrogen and nine hydrogen molecules are present, we must first determine which of the two reactants is the limiting reactant.

To find the limiting reactant, the number of moles of each reactant present in the equation must be determined.


Calculations:
Nitrogen (N2) molecules = 4Hence, the number of moles of N2 = 4/6.02 x 1023 mol-1 = 6.64 x 10-24 mol
Hydrogen (H2) molecules = 9Hence, the number of moles of H2 = 9/6.02 x 1023 mol-1 = 1.50 x 10-23 mol


Now we have to calculate the number of moles of NH3 produced when the number of moles of nitrogen and hydrogen are known, i.e., mole ratio of N2 and H2 is 1:3.


The mole ratio of N2 to NH3 is 1:2; thus, for every 1 mole of N2 consumed, 2 moles of NH3 are produced.
The mole ratio of H2 to NH3 is 3:2; thus, for every 3 moles of H2 consumed, 2 moles of NH3 are produced.
From these mole ratios, it can be observed that the limiting reactant is nitrogen.


Calculation for NH3 production:
Nitrogen (N2) moles = 6.64 x 10-24 moles
The mole ratio of N2 to NH3 is 1:2; therefore, moles of NH3 produced is 2 × 6.64 × 10−24 = 1.33 × 10−23 moles.


Now, to determine how many molecules of NH3 are produced, we need to convert moles to molecules.
1 mole = 6.02 x 1023 molecules
Thus, 1.33 x 10-23 moles of NH3 = 8.00 x 1014 molecules of NH3 produced.


To find the amount of each reactant remaining after the reaction is complete, we must first determine how many moles of nitrogen are consumed, then how many moles of hydrogen are consumed, and then subtract these from the initial number of moles of each reactant.

The moles of nitrogen consumed = 4 moles × 1 mole/1 mole N2 × 2 mole NH3/1 mole N2 = 8 moles NH3
The moles of hydrogen consumed = 9 moles × 2 mole NH3/3 mole H2 × 2 mole NH3/1 mole N2 = 4 moles NH3
Thus, the moles of nitrogen remaining = 6.64 × 10−24 mol – 8 × 2/3 × 6.02 × 10^23 mol-1 = 5.06 × 10−24 mol
The moles of hydrogen remaining = 1.50 × 10−23 mol – 4 × 2/3 × 6.02 × 10^23 mol-1 = 8.77 × 10−24 mol

Finally, the number of molecules of each reactant remaining can be calculated as follows:
Number of N2 molecules remaining = 5.06 × 10−24 mol × 6.02 × 10^23 molecules/mol = 3.05 × 10−1 molecules ≈ 0 molecules
Number of H2 molecules remaining = 8.77 × 10−24 mol × 6.02 × 10^23 molecules/mol = 5.28 × 10−1 molecules ≈ 0 molecules.

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A tumor marker is being developed to detect early breast cancer. Of the 400 women who volunteered for the study, 350 tested negative for the marker. Of these women, three developed breast cancer. The 50 women who tested positive for the marker underwent further tests, of these 50 women, 48 were diagnosed with early breast cancer, and the other two women were found to not have breast cancer. Use enclosed excel sheet for your answers (including your calculations)

Answers

While tumor marker test results can be useful, they are not conclusive. A low result does not imply that you do not have cancer or that you are in remission.

CA 15-3, for example, is raised in less than half of patients with early breast cancer and in more than 80% of those with metastatic breast cancer. Three tumor markers, cancer antigen 15-3 (CA 15-3), cancer antigen 27.29 (CA 27.29), and carcinoembryonic antigen (CEA), have been used in breast cancer care to help monitor metastatic breast cancer (advanced disease), but they have not been found to be useful in detecting a breast cancer recurrence or extending lives. If the level falls, the treatment is effective. If it rises, the cancer may be spreading.

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2) A solution was made by dissolving 755 g of Na₂SO4 in 53, 100 g of
water. Calculate the morality, molality, and mole fraction of Na₂SO4.
A) Molarity
B) Molality
c) Mole fraction

Answers

Answer:

0.101 M

0.1 mol/kg

0.644

Explanation:

To calculate the molarity, molality, and mole fraction of Na2SO4 in a solution, you need to know the moles of Na2SO4 in the solution and the volume or mass of the solution.

A) Molarity: Molarity (M) is defined as the number of moles of solute per liter of solution. To calculate molarity, we need to divide the number of moles of Na2SO4 by the volume of the solution in liters.

First, calculate the number of moles of Na2SO4:

mass of Na2SO4 = 755 g

molecular weight of Na2SO4 = 142 g/mol

number of moles = mass/molecular weight = 755 g / 142 g/mol = 5.34 moles

Next, calculate the volume of the solution:

mass of water = 53,100 g

density of water = 1 g/mL

volume of water = mass/density = 53,100 g / 1 g/mL = 53,100 mL = 53.1 L

Finally, calculate the molarity:

molarity = number of moles / volume of solution = 5.34 moles / 53.1 L = 0.101 M

B) Molality: Molality (m) is defined as the number of moles of solute per kilogram of solvent. To calculate molality, we need to divide the number of moles of Na2SO4 by the mass of the solvent in kilograms.

mass of water = 53,100 g

mass of solvent in kilograms = mass in grams / 1000 g/kg = 53,100 g / 1000 g/kg = 53.1 kg

Finally, calculate the molality:

molality = number of moles / mass of solvent = 5.34 moles / 53.1 kg = 0.1 mol/kg

C) Mole fraction: The mole fraction (X) is defined as the ratio of the number of moles of solute to the total number of moles of solute and solvent in a solution. To calculate the mole fraction of Na2SO4, we need to divide the number of moles of Na2SO4 by the total number of moles of Na2SO4 and water.

number of moles of Na2SO4 = 5.34 moles

number of moles of water = 53.1 kg * 1000 g/kg / 18.015 g/mol = 2.96 moles

total number of moles = number of moles of Na2SO4 + number of moles of water = 5.34 moles + 2.96 moles = 8.30 moles

Finally, calculate the mole fraction:

mole fraction of Na2SO4 = number of moles of Na2SO4 / total number of moles = 5.34 moles / 8.30 moles = 0.644

The molarity of Na2SO4 in the solution is 0.101 M, the molality is 0.1 mol/kg, and the mole fraction of Na2SO4 is 0.644.

At constant temperature, the behavior of a real gas more closely approximates that of an ideal gas as its volume increases due to which of the following?

Answers

At Constant temperature, the behavior of a Ideal gas more closely approximates that of an ideal gas as its volume increases due to the average distance between the molecule becomes greater.

According to the Molecular Theory of gases, at constant temperature the behavior of a sample of a real gas more closely approximates that of an ideal gas as its volume is increased because the average distance between molecules becomes greater. The temperature did not change, so the average kinetic energy and average molecular speed did not change. The molecule size does not change either, so the molecule could not have expanded. The distance between the molecules increases causing a decrease in intermolecular forces, thus reducing the interaction between the molecules.

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Using the evidence provided, generate a pattern that describes the chemical reactivity of metals.


A

As you go from left to right, reactivity of metals increases. As you go down in a group, reactivity of metals increases.


B

As you go from left to right, reactivity of metals increases. As you go down in a group, reactivity of metals decreases.


C

As you go from left to right, reactivity of metals decreases. As you go down in a group, reactivity of metals increases.


D

As you go from left to right, reactivity of metals decreases. As you go down in a group, reactivity of metals decreases

Answers

Answer:

B)As you go from left to right, reactivity of metals increases. As you go down in a group, reactivity of metals decreases.

Explanation:

reactivity of metals can be explained as how it can easily lose electron, i.e oxidize as well as reaction with non-metals.

There are factors that influence the reactivity of metals such as

1)atomic radius

2)nuclear charge

3)shielding effect

4) The sublevel arrangement of electrons

In the periodic table,the group 1, known as alkali metals, are the most reactive metals

Therefore, as we from left to right, reactivity of metals increases. As we move down in a group, reactivity of metals decreases.

The figure below shows the rotation curves of several spiral galaxies, extending to the very edge of their visible disks. What do these curves tell us about the distribution of dark matter in these galaxies?



Group of answer choices

Most of the dark matter is in the bulge.

Most of the dark matter is in the galaxies’ outskirts.

Most of the dark matter is near stars.

Most of the dark matter is in clumps.

Answers

The thing that the curves tell us about the distribution of dark matter in these galaxies is option B: Most of the dark matter is in the galaxies’ outskirts.

Why do galaxy rotation curves suggest the existence of dark matter?

Beyond the visible borders of galaxies, the velocity of stars remains relatively constant, suggesting that there must be more matter present than what we can see as stars and gas.

When the impact of DE became noticeable, the rotation curves are shown to dip at a specific distance. r. These flat, v = constant, rotation curve data suggest that the amount of dark matter is increasing linearly with r up to great distances from the spiral galaxies' centers.

From the graph you can see they all pointing or going one direction, hence we can deduce that it is option B.

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1. a Use the valence electron molecular orbital diagram for F2 to propose ground state F2ions that satisfy the following conditions

(1.5 points) (i) A F2 ion that is paramagnetic and that has a non-integer bond order.
(1.5 points) (ii) A F2 ion that is paramagnetic and that has an integer bond order.
(1.5 points) (iii) A F2 ion that is diamagnetic and that has a bond order of 3.

Clearly show the charge on your ion, label all valence molecular orbitals, and show the corresponding electrons in their orbitals. Full calculations for bond orders must be included.

b) Using only the valence electron molecular orbital diagram for F2, is a ground state diamagnetic ion with a bond order of 2 possible? Write one or two sentences to explain why or why not.

Answers

If 2.34 moles of Mg react with 3.56 moles of l2 and 1.76 moles of Mgl2 form, what is the percent yield?

A reaction occurs in a calorimeter, resulting in the starting temperature of 38.8 ℃ and final temperature 21.0 ℃. What can you say about the reaction and the enthalpy change (ΔH) during the reaction?

Answers

Answer:

hola comoe stas

Explanation:

gracias x los puntos

which element can form an oxide with the general formula m2o or mo where m is a metal

Answers

Answer:

Because the compound has a formula of M2O, the number of valence electrons of M should be 1. Therefore, (1) Group 1 is the correct answer because elements in group 1 have 1 valence electron.

Explanation:

Directions: The picture below shows a model of Earth's layers. Use the picture to answer
any questions that follow.
Layer 5
Layer 4
Layer 3
Layer 2
Layer 1
1. Which layers compose the lithosphere?
A layers 6 and 4
B layers 4 and 3
a layers 3 and 2
D layers 2 and 1

Answers

Answer:

hfghfhjcbnggf

Explanation:

layer1

layer 2

magnetic field on iron man

Answers

Answer:

ok that makes sense

Explanation:

elect me for president

Answer:

Sheesh

Explanation:

Which option is formed by the process of fusion in stars?
O compounds
Oelectrons
O quarks
Oelements

Answers

D. The option that is formed by the process of fusion in stars is elements.

How fusion in stars form elements

When the new star reaches a certain size, a process called nuclear fusion ignites, generating the star's vast energy.

The fusion process forces hydrogen atoms together, transforming them into heavier elements such as;

helium, carbon and oxygen.

Thus, the option that is formed by the process of fusion in stars is elements.

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What is the main purpose of a leaf

Answers

Explanation:

for respiration(exchange of gases)

Actually, all leaves have the same structure. The main purpose is to carry the photosynthesis out, that provides food that needs to survive. :)

Starting with 0.3500 mol CO(g) and 0.05500 mol COCl2(g) in a 3.050 L flask at 668 K, how many moles of CI2(g) will be present at equilibrium?
CO(g) + Cl2(g)》COCl2(g)
Kc= 1.2 x 10^3 at 668 K

Answers

At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

1: Write the balanced chemical equation:

\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)

2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.

Initial:

\(C_O\)(g) = 0.3500 mol

\(Cl_2\)(g) = 0.05500 mol

\(C_OCl_2\)(g) = 0 mol

Change:

\(C_O\)(g) = -x

\(Cl_2\)(g) = -x

\(C_OCl_2\)(g) = +x

Equilibrium:

\(C_O\)(g) = 0.3500 - x mol

\(Cl_2\)(g) = 0.05500 - x mol

\(C_OCl_2\)(g) = x mol

3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:

Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]

4: Substitute the given equilibrium constant (Kc) value into the expression:

1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)

5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:

1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x

6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.

7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.

8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):

\(Cl_2\)(g) = 0.05500 - x

9: Calculate the value of \(Cl_2\)(g) at equilibrium:

\(Cl_2\)(g) = 0.05500 - x

\(Cl_2\)(g) = 0.05500 - (positive value of x)

10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.

Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

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. How many moles of oxygen (O) are in 1 mole of calcium carbonate (CaCO3)?

Answers

In 1 mole of calcium carbonate, there are approximately 18.066 x 10^23 moles of oxygen.

To determine the number of moles of oxygen (O) in 1 mole of calcium carbonate (CaCO3), we need to examine the chemical formula of calcium carbonate and identify the number of oxygen atoms present.

The chemical formula of calcium carbonate is CaCO3. In this formula, we have one calcium atom (Ca), one carbon atom (C), and three oxygen atoms (O).

The subscript numbers in the formula indicate the number of atoms for each element. Therefore, we have:

1 calcium atom (Ca)

1 carbon atom (C)

3 oxygen atoms (O)

To calculate the number of moles of oxygen in 1 mole of calcium carbonate, we multiply the number of oxygen atoms (3) by the Avogadro's number, which is approximately 6.022 x 10^23 molecules/mol.

Number of moles of oxygen (O) in 1 mole of calcium carbonate (CaCO3) = 3 moles of oxygen x (6.022 x 10^23 molecules/mol)

Calculating this value, we find:

Number of moles of oxygen (O) in 1 mole of calcium carbonate (CaCO3) ≈ 18.066 x 10^23 moles of oxygen

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When a cloud becomes too heavy with water droplets it can rain hail or snow this is known as what?

Answers

Answer:sunny days

Explanation:meow

Answer:

This is condensation.

Explanation:

The process of water vapour turning back into liquid water.

At constant current is passed through an electrolytic cell containing molten MgCl2 for 18 hr. if 4.8 x 105 g of Cl2
are obtained. Calculate the current in Amperes.

Answers

The current passing through the electrolytic cell is approximately 2.02 x 10^4 Amperes.

To calculate the current in amperes, we need to use Faraday's laws of electrolysis and the stoichiometry of the reaction.

Faraday's laws state that the amount of substance produced or consumed during electrolysis is directly proportional to the quantity of electricity passed through the cell. The relationship is given by:

Q = nF

Where Q is the electric charge in coulombs (C), n is the number of moles of substance involved in the reaction, and F is Faraday's constant, which is equal to 96,485 C/mol.

In this case, the substance being produced is Cl2, and we know the mass of Cl2 produced, which is 4.8 x 10^5 g.

First, we need to calculate the number of moles of Cl2 produced:

Molar mass of Cl2 = 35.45 g/mol

Moles of Cl2 = mass / molar mass = (4.8 x 10^5 g) / (35.45 g/mol) ≈ 1.354 x 10^4 mol

Now we can calculate the quantity of electricity passed through the cell using Faraday's laws:

Q = nF

Q = (\(1.354 x 10^4\)mol) * (96,485 C/mol)

Q ≈ 1.308 x 10^9 C

The quantity of electricity is given in coulombs. To find the current, we need to divide this value by the time in seconds.

Given that the time is 18 hours, we convert it to seconds:

Time = 18 hours * 60 minutes/hour * 60 seconds/minute

Time = 6.48 x 10^4 seconds

Finally, we can calculate the current:

Current (I) = Q / Time

I = (1.308 x 10^9 C) / (6.48 x 10^4 s)

I ≈ 2.02 x 10^4 Amperes

Therefore, the current passing through the electrolytic cell is approximately 2.02 x 10^4 Amperes.

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A balanced equation has

Answers

Answer:

A balanced equation is an equation for a chemical reaction in which the number of atoms for each element in the reaction and the total charge is the same for both the reactants and the products.In other words, the mass and the charge are balanced on both sides of the reaction.

Explanation:

If a car travels at 32.1km/hr, what is the car’s velocity in m/sec?

Answers

A car travels at 32.1 km/hour. The velocity of car in m/sec is 8.92 m/s.

What is velocity?

Velocity is defined as the pace at which an object's location changes in relation to a frame of reference and time.

It can also be defined as the directional speed of a moving item as an indication of its rate of position change as seen from a specific frame of reference.

As we know 1 km = 1000m

                     1 hour = 3600 sec

So, 32.1 km = 32100 m

Velocity = distance / time

Velocity = 32100 / 3600

Velocity = 8.92 m/sec.

Thus, a car travels at 32.1 km/hour. The velocity of car in m/sec is 8.92 m/s.  

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How many hydrogen molecules (h2) are needed to convert the triacylglycerol shown to saturated fat

How many hydrogen molecules (h2) are needed to convert the triacylglycerol shown to saturated fat

Answers

We would need about 16 hydrogen atoms so that we can convert the compound to a saturated fat.

What is a saturated fat?

In animal products like meat and dairy, saturated fat is a form of dietary fat that is normally solid at room temperature. It is known as being "saturated" because each molecule of fat has the most hydrogen atoms possible, giving it a stable structure.

We can see this by counting the number of double bonds in the fat and there are eight of them so sixteen hydrogen atoms are needed for saturation.

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Parallel structure aids the reader's comprehension of ideas and their relative importance True or False​

Answers

Answer:

This question is obviously true

Explanation:

I would expect

Which adjective describes variation?

A. different

B. consistent

C. similar

D. untrustworthy

Answers

Answer:

A

Explanation:

I just know it because i am smart, trust me I know this is correct.

a i think if i am wrong i am truly sorry but i dont think i am wrong

Show how you would convert 3-cyclopentylbutanal to a carboxylic acid.​

Answers

Conversion of 3-cyclopentylbutanal to a carboxylic acid will be made possible through oxidation.

What is Oxidation?

This is the process in a chemical reaction which involves the gain of oxygen atoms.

3-cyclopentyl butanal  is oxidized to carboxylic acids using potassium dichromate(VI) solution which turns green in the presence of dilute sulfuric acid.

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Pls help I’ll brainlest and add extra points

Pls help Ill brainlest and add extra points

Answers

Answer:

a top predator, fighting

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