During a snowball fight two balls
with masses of 0.4 and 0.6 kg,respectively,are thrown in such a manner that they meet head-on

Answers

Answer 1
not completely understanding what the question is

Related Questions

What characteristics determine how easily two substances change temperature? Check all that apply.
volume of the two substances in contact
amount of time the two substances are in contact
Oarea in contact between the two substances
specific heat of the material that makes up the substances
density of the two substances in contact

Answers

Answer:

The characteristics that determine how easily two substances change temperature are:

specific heat of the material that makes up the substancesarea in contact between the two substances

The volume and density of the substances and the amount of time they are in contact do not directly affect how easily they change temperature.

Explanation:

An ideal gas undergoes an isothermal (constant-temperature) compression at temperature T, with its volume changing from V1 to V2. (i) Prove that the work done during this process is given by an expression =12. (5) (ii) Is the work done positive or negative? Give reasons.

Answers

The effort required to compress an ideal gas is therefore given by W = -1/2 nRT ln(V2/V1) during an isothermal process.

What labour is involved in an ideal gas's isothermal expansion and compression?

When an ideal gas is subjected to isothermal expansion (T = 0) in a vacuum, the work done is equal to zero as pex=zero. Joule established q = 0 empirically; hence, U = 0. Equation 1 can be written as: for both reversible and irreversible isothermal changes. Reversible isothermal change q = -w = pex (Vf-Vi)

nRT = ln(V2/V1) - W

If we solve for W, we obtain:

W = ln(V1/V2)nRT (v) If we condense this phrase, we get:

W=-nRT ln(V2/V1).

W=-RT ln(V2/V1).

W=-1/2nRT ln(V2/V1)

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if the hoist h is moving upward at 6 ft/s , determine the speed at which the motor m must draw in the supporting cable. if the hoist is moving upward at 6 , determine the speed at which the motor must draw in the supporting cable. vp/h

Answers

The magnitude of the motor shaft's rotational velocity is used to describe a motor's speed.

The motor velocity of the supporting cable exists 18 ft/s.

What is meant by Motor velocity?

A motor's speed is defined as the magnitude of the motor shaft's rotational velocity. The number of full rotations per unit of time for an axis rotation in a motion application depends on the motor's speed.

When given 11.1 V and a motor with a velocity constant and back EMF constant of 5,700 rpm/V, the motor will spin at a nominal speed of 63,270 rpm (= 5,700 rpm/V 11.1 V). The non-linear mechanical losses may prevent the motor from operating at this theoretical speed.

Motor velocity = Number of vertical strings × upward velocity

substitute the values in the above equation, we get

18 fp/s = 3 × 6

3 × 6 = 18 fp/s.

The motor velocity of the supporting cable exists 18 ft/s.

Therefore, the correct answer is option [D]. VP/H = 18 ft/s.

The complete question is:

If the hoist H is moving upward at 6 ft/s, determine the speed at which the motor M must draw in the supporting cable.

[A]. VP/H = 6 ft/s

[B]. VP/H = 2 ft/s

[C]. VP/H = 12 ft/s

[D]. VP/H = 18 ft/s

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if the hoist h is moving upward at 6 ft/s , determine the speed at which the motor m must draw in the


Burns are a particular safety hazard when handling

Burns are a particular safety hazard when handling

Answers

Answer:

flammable  liquids

Explanation:when it catches on fire your going to get burned.hope this helps.

An ant crawls 50 cm to the right, stops, and then crawls 30 cm to the left. Calculate the distance that the ant travels, and calculate the displacement of the ant.

Answers

Answer and Explanation:

If the ant was to crawl 50cm to the right, then come back 30 cm, then the total distance walked would be 80cm.

- Combine 50cm and 30cm to get 80 cm.

For displacement, the answer is 20 cm.

- When calculating displacement, you use the initial (starting) distance. and subtract that from the final distance, giving you the displacement, or the amount traveled from the starting point to the final point if you were to make a straight line from the starting point to end point. (0 to 50, then back 30 the same direction, so subtract 30 from 50 to get 20)

#teamtrees #PAW (Plant And Water)

I hope this helps!

Answer:

Distance = 80cm

Displacement = 20cm

Explanation:

Distance does not depend on direction, its the total amount traveled.

Displacement has a direction. Displacement is how far your stopping point is from the beginning point.

The ant could have walked 50cm to the east, stopped and turned around, walked 50cm to the west, walking a total distance of 100cm, but the displacement would be 0 because he ended up at the same spot that he started. It can get much more complicated than this, but this is a good start.

2 points
All of the following are correct except:
The earth's surface absorbs visible light and gives off infrared energy
most short wave radiation that enters the atmosphere doesn't get to the earth's surface as it is either reflected, scattered, or absorbed by the atmosphere
Light that reaches the earth's surface is mainly visible light
Greenhouse gases absorbs energy mainly from visible light reflected off the earth's surface
4

Answers

The statement that is not correct is "Greenhouse gases absorb energy mainly from visible light reflected off the earth's surface," which is in the last option or option D, as the greenhouse gases actually absorb and re-emit infrared radiation, not visible light.

What is a greenhouse gas?

Greenhouse gases absorb IR radiation because the bonds between their atoms and molecules can vibrate in response to electromagnetic radiation that causes the molecules to gain energy and vibrate more vigorously, which generates heat, and the absorbed energy is then re-emitted in all directions, including back towards the Earth's surface, creating a warming effect.

Hence, the statement that is not correct is "Greenhouse gases absorb energy mainly from visible light reflected off the earth's surface," which is in the last option that is option D.

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The question is incomplete, the complete question is below

All of the following are correct except:

A)The earth's surface absorbs visible light and gives off infrared energy

B)most short wave radiation that enters the atmosphere doesn't get to the earth's surface as it is either reflected, scattered, or absorbed by the atmosphere

C)Light that reaches the earth's surface is mainly visible light

D)Greenhouse gases absorbs energy mainly from visible light reflected off the earth's surface

A wagon, Initially traveling at a constant 3.6 m/s, starts going down a hill that creates an acceleration of
1.6 m/s2. What is the wagon's velocity 4.8 s after it starts accelerating down the hill?

Answers

To determine the wagon's velocity 4.8 seconds after it starts accelerating down the hill, we can use the following kinematic equation:

v = u + at

where:
v is the final velocity,
u is the initial velocity,
a is the acceleration, and
t is the time.

Given:
u (initial velocity) = 3.6 m/s (constant velocity)
a (acceleration) = 1.6 m/s²
t (time) = 4.8 s

Using the equation and substituting the values, we have:

v = 3.6 m/s + (1.6 m/s²)(4.8 s)

v = 3.6 m/s + 7.68 m/s

Performing the addition:

v = 11.28 m/s

Therefore, the wagon's velocity 4.8 seconds after it starts accelerating down the hill is 11.28 m/s.

The semi major axis of an orbiting body is 3.01 AU. What is the period of this object's orbit?

a 6.01 years
b 5.01 years
c 4.97 years
d 5.22 years

Answers

Answer: 4.97 years

Explanation: I got the answers right

By the use of the Kepler's laws, the period of the orbit is 5.22 years. Option D

What is the period?

We know that when we are dealing with the orbits that our mind would have to be turned to the Kepler's law. In the Keplers law, we see the relationship that cold be used in the attempt to connect the period of the orbit to the radius of the semi major axis of an orbiting body.

By the application of the Keplers third law;

T^2 = r^3

The statement of the law is that the square of the period of the objects orbit is equal to the cube of the length of the semi major axis.

We then know that;

T = period

r = distance

Hence;

T = r^3/2

T = (3.01 )^3/2

T = 5.22 years

The period of the object is seen to be 5.22 years from the calculation above.

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Which of the following is an example of an unbalanced force?
a. book sitting on a table
b. car sitting in the garage
c. person on an elevator going down
d. person leaning on a wall

Answers

Answer:

Answer C : person on an elevator going down

Explanation:

We look for a change in state of motion in order to have a net force different from zero in the system. The state of motion doesn't change in any of the examples a, b, or d. But there is a change in the state of motion in case c where initially the person and elevator where in static equilibrium, and later the elevator started going down and accelerating from zero speed to another non zero speed.

While sitting in a boat, a fisherman observes that 2 complete waves pass by his position every 4 seconds. What is the period of these waves?A)2s B)8s C) 0.5 s D) 4s​

Answers

Answer:

2

Explanation:

Because 2 waves 4 secs means 1 in 2s

The period of these waves is 2s. and The right option is A)2s.

The period of a wave is the time taken by a wave to complete one cycle.

The formula of period from the question is given below.

⇒ Formula:

T = t/2.................... Equation 1

⇒ Where:

T  = Period of the wavet = time taken for two complete oscillation

From the question,

⇒ Given:

t = 4 seconds.

⇒ Substitute these value above into equation 1

T = 4/2T = 2 seconds.

Hence, The period of these waves is 2s.

The right option is A)2s

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What type of electromagnetic wave is sent as a signal by a cell phone to the
nearest cell tower?
A. Gamma rays
B. Microwaves
C. X-rays
D Ultraviolet

Answers

Answer:B. Microwaves

Explanation:

Hope this helped you. Pls brainliest! :D

Consider the circuit in Figure 5 with e(t) = 12sin(120pit) V. When S1 and S2 are
open, i leads e by 30°. When SI is closed and S2 is open, i lags e by 30°. When S1 and S2 are closed, i has an amplitude 0.5A. What are R, L, and C?

Consider the circuit in Figure 5 with e(t) = 12sin(120pit) V. When S1 and S2 areopen, i leads e by 30.

Answers

Based on the information, it should be noted that the resistance R is 0.5 Ω.

How to calculate the resistance

When S1 and S2 are open, i leads e by 30°. In this case, the circuit consists of only the inductor (L) and the capacitor (C) in series. Therefore, the impedance of the circuit can be written as:

Z = jωL - 1/(jωC)

Since i leads e by 30°, we can express the phasor relationship as:

I = k * e^(j(ωt + θ))

Z = jωL - 1/(jωC) = j(120π)L - 1/(j(120π)C)

Re(Z) = 0

By equating the real parts, we get:

0 = 0 - 1/(120πC)

Let's assume that there is a resistance (R) in series with the inductor and capacitor. The impedance equation becomes:

Z = R + jωL - 1/(jωC)

Z = R + jωL

Im(Z) = ωL > 0

Substituting the angular frequency and rearranging the inequality, we have:

120πL > 0

L > 0

This condition implies that the inductance L must be greater than zero.

When S1 and S2 are closed, i has an amplitude of 0.5 A. In this case, the impedance is:

Z = R + jωL - 1/(jωC)

Since the amplitude of i is given as 0.5 A, we can express the phasor relationship as:

I = 0.5 * e^(j(ωt + θ))

By substituting this phasor relationship into the impedance equation, we can determine the value of R. The real part of the impedance must be equal to R:

Re(Z) = R

Since the amplitude of i is 0.5 A, the real part of the impedance must be equal to 0.5 A: 0.5 = R

Therefore, the resistance R is 0.5 Ω.

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1. What are the things needed by plants to make their own food?
A. water, chemicals and oxygen
B. oxygen and carbon dioxide
C. oxygen and chemicals
D. carbon dioxide, soil and sunlight
of
2. What kind of interaction is shown when worms live in the guts and flesh
a fish?
A. mutualism
B. commensalism
C. predation
D. parasitism
3. What kind of interaction is shown when monkeys in tropical rainforest
compete for food with other animals?
A. mutualism
B. commensalism
C. competition
D. predation


answer quickly.​

Answers

Answer:

1.d   2.d 3.c

Explanation:

Explain how we could test for the accuracy of the period you calculated (and don't mean by using a calculator). How could you experimentally find it?

Answers

Answer:

Here are the steps to perform the experiment:

1. Set up a pendulum by suspending a weight from a fixed point using a string or a rod. Ensure that the length of the string or the rod is constant.

2. Displace the weight by a small angle and release it to allow it to oscillate back and forth.

3. Use a stopwatch or a timer to measure the time it takes for the pendulum to complete one full oscillation (i.e., from one extreme position to the other and back to the original position).

4. Repeat the measurement several times to get an average value for the time period.

5. Compare the measured time period to the calculated value using the formula T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.

If the measured value is close to the calculated value, then the calculated period can be considered accurate. However, if the measured value is significantly different from the calculated value, then the calculated period may need to be revised or further experiments may need to be performed to determine the source of the error.

It is important to note that experimental errors such as human error in measuring the time or the length of the pendulum can affect the accuracy of the measurement. Therefore, it is recommended to repeat the experiment several times to minimize these errors and obtain a more accurate value.

If a wave has speed of 235 m/s with a wavelength of 3 m, what is the frequency of the wave?

Answers

I think it’s 25 but I don’t know


PLEASE HELP AND SHOW WORK,THANK YOU!!
4) Suppose that two identical
mass planets are sitting
million miles apart. At that
distance the planets have a
gravitational force of 1,000,000 N.
If the planets are moved
to two million miles apart, what
is the new gravitational force
between them?

Answers

The new gravitational force between the two planets, when they are moved to two million miles apart, is 250,000 N

The gravitational force between two objects can be calculated using Newton's Law of Universal Gravitation, which states that the force is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

Given:

Initial distance between the planets = 1 million miles

Initial gravitational force = 1,000,000 N

Final distance between the planets = 2 million miles

To determine the new gravitational force, we need to compare the ratios of the distances and apply the inverse square law.

Let's denote the initial distance as d1, the initial gravitational force as F1, the final distance as d2, and the unknown final gravitational force as F2.

According to the inverse square law, the ratio of the gravitational forces is the square of the ratio of the distances:

(F2/F1) = (d1/d2)²

Substituting the given values:

(F2/1,000,000 N) = (1 million miles / 2 million miles)²

Simplifying:

(F2/1,000,000 N) = (1/2)²

(F2/1,000,000 N) = 1/4

F2 = (1/4) * 1,000,000 N

F2 = 250,000 N

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The figure below shows electrons moving along an electric current towards and away from the light bulb.

Electrons traveling along an electric current. Arrow under electrons points right and left both towards and away from the light bulb.

Does this figure show a direct or alternating current? Explain your response.

Answers

Based on the information provided, it is likely that the figure shows an alternating current (AC). The arrows under the electrons pointing right and left, both towards and away from the light bulb, indicate that the direction of the electron flow is changing periodically. This is a characteristic of alternating current, where the flow of electric charge reverses direction periodically, typically in a sinusoidal manner.

In an AC circuit, the voltage also changes direction periodically, which is consistent with the changing direction of the electron flow shown in the figure.

In an alternating current, the flow of electrons periodically reverses direction, causing the current to switch between positive and negative values. This is different from direct current (DC), where electrons flow in a single, constant direction.

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Calculate the wave speed (in m/s) for the following waves:


a) A sound wave in steel with a frequency of 500 Hz and a wavelength of 3.0 meters. (2pts)







b) a ripple on a pond with a frequency of 2 Hz and a wavelength of 0.4 meters. (2pts)









Calculate the wavelength (in meters) for the following waves:



A wave on a slinky spring with a frequency of 2 Hz travelling at 3 m/s. (2pts)







An ultrasound wave with a frequency 40,000 Hz travelling at 1450 m/s in fatty tissue. (2pts)









Calculate the frequency (in Hz) for the following waves:



A wave on the sea with a speed of 8 m/s and a wavelength of 20 meters. (2pts)







A microwave of wavelength 0.15 meters travelling through space at 300,000,000 m/s. (2pts)

Answers

Answer: A : 250 is the answer

B; The frequency of a wave is the number of complete oscillations (cycles) made by the wave in one second.

Instead, the wavelength is the distance between two consecutive crests (highest position) or 2 troughs (lowest position) of the wave.

In this problem, we are told that the leaf does two full up and down bobs: this means that it completes 2 full cycles in one second. Therefore, its frequency is

where  is called Hertz (Hz). So, the correct answer is

Explanation:

#Wavespeed

#1

\(\\ \rm\Rrightarrow v=\nu\lambda=500(3)=1500m/s\)

#2

\(\\ \rm\Rrightarrow v=2(0.4)=0.8m/s\)

#Wavelength

#1

\(\\ \rm\Rrightarrow \lambda=\dfrac{v}{\nu}=\dfrac{3}{2}=1.5m\)

#2

\(\\ \rm\Rrightarrow \lambda= \dfrac{1450}{40000}=0.03625m\)

#Frequency

\(\\ \rm\Rrightarrow \nu=\dfrac{v}{\lambda}=\dfrac{8}{20}=0.4Hz\)

#2

\(\\ \rm\Rrightarrow \nu=\dfrac{3\times 10^8}{15\times 10^{-2}}=0.2\timee 10^{10}=2\times 10^9Hz\)

Who discovered the laws of planter motion ?


Answers

Answer: Johannes Kepler

Explanation:

Kepler discovered that Mars' orbit was an ellipsoid using the exact data that Tycho had obtained.

Rita raises a 10kg package to a height of 2.5 m in 2.0 s.
(a) How much work did she do on the package?
(b) How much power was expended on the package?
(c) It she were to raise the package in 1.0 s rather than 2.0 s, how do the work and power change?

Answers

Answer:

A) W =250J B) Power = 125 J/s  C) Work = 250 J Power = 250 J/s

Explanation:

Work = Force*distance

A:

\(W = 10kg*10m/s^2*2.5m\\W = 250 J\\\)

B:

Power is J/s

Power = 250J/2.0s = 125 J/s

C:

Work stays the same

Power increases to 250 J/s

A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J

Answers

The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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How have astronomers used models to explain galactic evolution through mergers and collisions? Use this model to explain how astronomers might test their understanding of the physical processes of the universe.

Answers

Answer:

Astronomers use computer models to simulate the process of galactic evolution through mergers and collisions. These models are based on our current understanding of the physical laws that govern the behavior of matter and energy in the universe. By running simulations of galactic mergers and collisions, astronomers can test their understanding of how these physical processes work in practice and how they contribute to the formation and evolution of galaxies.

One way that astronomers might test their understanding of the physical processes of the universe is by comparing the predictions of their models to observations of real galaxies. For example, if a model predicts that a particular type of galaxy should have a certain shape, size, or distribution of stars, astronomers can compare these predictions to observations of actual galaxies to see if they match up. If there is a discrepancy between the model's predictions and the observations, this can indicate that there are some physical processes that are not well understood or included in the model.

Another way that astronomers might test their understanding is by looking for patterns or trends in the properties of galaxies that are consistent with the predictions of their models. For example, if a model predicts that galaxies that have undergone a recent merger should have a particular distribution of gas and dust, astronomers can look for evidence of this pattern in observations of real galaxies. If they find that the predicted pattern is consistently observed in a large sample of galaxies, this can provide support for the model's predictions and the physical processes that it includes.

Overall, computer models of galactic evolution through mergers and collisions provide a powerful tool for astronomers to test their understanding of the physical processes of the universe. By comparing the predictions of their models to observations of real galaxies and looking for consistent patterns and trends, astronomers can refine their understanding of how galaxies form and evolve over time.

39. What is the change in momentum for a 5,000 kg ship in

outer space that experiences no net force over a 1 hr

period?

Answers

Answer:

Change in momentum is zero.

Explanation:

The following data were obtained from the question:

Mass (m) = 5000 kg

Time (t) = 1 h

Net force (F) = 0

Change in momentum =?

Force = Rate of change of momentum

0 = change in momentum

Change in momentum = 0

We can see from the above illustration that the net force is zero. Thus, the change in momentum is also zero.

If you know the answer please tell me ASAP

If you know the answer please tell me ASAP

Answers

3. Fulcrum left

Explanation:

if i put my spoon in the microwave what will happen

Answers

If you put your spoon in the microwave, nothing will happen to it as long as it has round edges and it is not touching any sides of the microwave.

Putting a spoon in the microwave

Spoons are generally made from stainless steel. Stainless steels are iron and chromium. In some cases, other metals such as nickel are thrown into the mix.

Thus, being made of metals, these stainless steels are good conductors of heat and electricity.

A microwave works by heating foods put into it using electromagnetic radiation in the microwave frequency range. Electromagnetic radiation causes the molecules of food to rotate and produce thermal energy.

If the spoon touches the side of the microwave, sparks may result. Otherwise, it is totally fine because spoons usually have round edges. With rough edges,  the waves may be reflected back and forth and create sparks.

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A helium-neon laser (λ = 633 nm) illuminates a single slit and is observed on a screen 1.50 m behind the slit. The distance between the first and second minima in the diffraction pattern is 3.75 mm .

Required:
What is the width (in mm) of the slit?

Answers

Answer:

d = 0.25 mm

Explanation:

The position that the Minimal fall in single silt diffraction pattern can be written as

y=λmD/d ..........eqn(1)

(y2 - y1 )= difference of y that exist between first and second minima

D= distance of slit from the screen=1.50m

d= width of the slit

λ= 633 nm = 633×10^-9m

y= position of pth minimal

eqn(1) can be written as

(y2 - y1)= λmD/d .........eqn(2)

If we substitute the given values we have

(y2 - y1 )= [ (2×633×10^-9 × 1.50) /d] -[ (1×633×10^-9 × 1.50) /d]

Simplyfying

(y2 - y1)=(9.495×10^-7)/d

But The distance between the first and second minima in the diffraction pattern = 3.75, which implies that (y2 - y1) = 3.75mm=

✓ we can substitute (y2 - y1)= 3.75mm=3.75 ×10^-3 into expression above

3.75 ×10^-3 =(9.495×10^-7)/d

The we can make "d" subject of the formula

d=(9.495×10^-7)/ (3.75 ×10^-3)

d=0.00025m

d=0.25×10^-3 m

d=0.25 mm

Hence, the width (in mm) of the slit is 0.25mm

a)List the names of three nonmetals you are familiar with in your daily life.

b)for each nonmetal you listed, describe two different uses for each.

Answers

Answer:

food and water

Explanation:

health and starvation and for theist most important thing

Which of the following is NOT true about the mass of an object?

A)
Mass is measured in kilograms.
B)
Mass is a measurement of force.
C)
Mass is a measurement of the amount of matter in an object.
D)
Mass does not change based on your location.

Answers

Answer:

B) Mass is a measurement of force

Explanation:

Mass is not a measurement of force, mass is a measurement of the amount of matter in an object.

a 40 g superball strikes a wall with a velocity of 10 m/s that is normal to the wall. it bounces away at a velocity of 7 m/s, still normal to the wall. what is the ball's change in momentum? if the bounce lasted 0.1 s, what is the force between the ball and the wall?

Answers

The momentum of the ball in motion is -0.68 kg m/s, and the force between the ball and the wall is -6.8 N.

What is momentum?

The state of motion of an object with a certain mass is termed as momentum. It is the product of the mass and velocity of the moving object and is a vector quantity.

It is expressed as: p = m × v

First, let's calculate the initial momentum of the ball before it strikes the wall:

p₁ = m₁× v₁ = 40 g × 10 m/s = 0.04 kg ×  10 m/s = 0.4 kg m/s

Where  m₁ is the mass of the ball and v₁ is its initial velocity.

Next, let's calculate the final momentum of the ball after it bounces off the wall:

p₂ = m₁× v₂= 40 g × (-7 m/s) = -0.04 kg × 7 m/s = -0.28 kg m/s

where v₂ is the velocity of the ball after it bounces off the wall.

The change in momentum of the ball is then:

Δp = p₂- p₁ = (-0.28 kg m/s) - (0.4 kg m/s) = -0.68 kg m/s

Note that the change in momentum is negative, indicating that the ball's momentum has decreased in magnitude and changed direction.

To calculate the force between the ball and the wall,

J = Δp

where J is the impulse and Δp is the change in momentum.

The impulse is also equal to the force multiplied by the time during which the force is applied:

J = F × Δt

where F is the force and Δt is the time during which the force is applied.

Setting these two equations equal to each other, we get:

F × Δt = Δp

Solving for the force, we get:

F = Δp / Δt = (-0.68 kg m/s) / (0.1 s) = -6.8 N

The negative sign indicates that the force exerted by the ball on the wall is directed opposite to the direction of the ball's motion, as expected.

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The change in the momentum of the ball will be 0.68kgm/sec. While the force that acts on the body will be 0.68 N.

What is momentum?

The measurement of mass in motion is called momentum. Momentum is equal to its mass multiplied by its velocity. Mathematically it is given as;

Momentum = Mass x Velocity

The given data in the problem is

ball mass ( m)= 40 g=0.040 kg

speed of the ball(v) = 10 m/s

rebound speed(V )= -7 m/s

The change in the momentum of the body is given by,

ΔP = mv - mv'

Δp= 0.040 x 10 - 0.057 x (-7)

ΔP = 0.68 kg.m/s

Hence the change in the momentum of the body will be 0.68 kg.m/s.

Impulse is defined as the product of force and time interval of contact.

ΔP = force *time

force = ΔP/time

force = 0.68/1

force = 0.68

Hence the force that acts on the body will be 0.68 N.

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A 2.03 kg particle has a velocity (1.90 i - 2.91 j) m/s, and a 3.02 kg particle has a velocity (0.92 i 6.00 j) m/s. Find the x component of the velocity of the center of mass.

Answers

Answer: \(= (1.31i+2.42j)m/s\\\)

Explanation:

GIVEN DATA:

\(m1 = 2.03kg\\m2 = 3.02kg\\v1 = 1.90 i - 2.91 j) m/s\\v2 = (0.92 i -6.00 j) m/s\\\)

Solution:

the velocity for centre of the mass

\(vcm= \frac{m1v1+m2v2}{m1+m2}\)

input the values into the formula.

\(vcm=\frac{(2.03)(1.90 i - 2.91 j)+(3.02)(0.92 i -6.00 j) }{2.03+3.02}\)

open the bracket

\(= \frac{3.86i-5.91j +2.78i+18.12j}{5.05}\)

collect like terms

\(= \frac{6.64i+12.21j}{5.05}\)

\(= (1.31i+2.42j)m/s\)

total momentum

\(p= (m1+m2)vcm\\= (2.03+3.02) (1.31i+2.42j)\\= 5.05 (1.31i+2.42j)\\=(6.62i+12.22j)kg.m/s\)

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