draw the structure of the major product formed in the given reaction when the aromatic aldehyde is present in excess. an aldehyde and ester react with methoxide in methanol. the aldehyde consists of two fused benzene rings. if the top fused carbon is arbitrarily numbered 1 and the ring numbered clockwise, there is an aldehyde substituent on carbon 3 and a methoxy substituent on carbon 8. the ester is a carbonyl bonded to methyl and methoxy.

There a bigger increase in second ionization energy for sodium than there is for magnesium because fully filled orbitals have extra stability.

The electronic configuration of Sodium is:

Na = 1s2 2s2 2p6 3s1

After removing one electron, the  electronic configuration is

Na⁺ = 1s2 2s2 2p6   ( I.E 1 = 495)

I.E 1 of sodium = 495 and I.E 2 of sodium = 4562

The electronic configuration of Magnesium is:

Mg = 1s2 2s2 2p6 3s2

There a bigger increase in second ionization energy for sodium than there is for magnesium because:

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The change of enthalpy for the given reaction is equal to -6387 KJ.

Enthalpy can be defined as the sum of internal energy and the product of volume and Pressure, expressed as shown below:

H = U + PV

The change in enthalpy between the beginning and final states can be expressed as:

ΔH = ΔU + ΔPV

Given reactions with enthalpy change are shown below:

2Al (s) + 6HCl (aq) → 2AlCl₃ (aq) + 3H₂ (g)      }×1        ΔH₁ = -1049 kJ

HCl (g) → HCl (aq)                                            } ×6       ΔH₂ = -74.8 kJ/mol

H₂ (g) + Cl₂ (g) → 2HCl (g)                                }× 3      ΔH₃ = -1845. kJ/mol

AlCl₃ (aq)  → AlCl₃ (s)                                      }× 2         ΔH₄ = +323. kJ/mol

\(\triangle H^o_f =1\times \triangle H_1 +6\times \triangle H_2+3\times \triangle H_3+2\times \triangle H_4\)

\(\triangle H^o_f =1\times (-1049) +6\times (-74.8)+3\times (-1845)+2\times (+323)\)

\(\triangle H^o_f =-6387 KJ\)

Therefore, the change of enthalpy for the reaction of the formation of aluminum chloride is -6387 KJ.

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Based on what we did and learned in today's lab, we can predict that when 1-propanol is mixed with distilled water, the mass and volume will be conserved.

This is because 1-propanol and water are both liquids and when they are mixed together, they will form a homogeneous solution. A homogeneous solution is a mixture of two or more substances that have a uniform composition and appearance throughout the entire mixture.

The mass of the solution will be the sum of the masses of the two liquids, and the volume of the solution will be the sum of the volumes of the two liquids. Therefore, the mass and volume will be conserved in this case.

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Answerl

see explanation

Explanation:

Question

4.

How many grams would 0 .50 moles of Mg be?

Mg has  an atomic weight of 24 so 1 mole of Mg weighs 24 gms

0.50 moles weigh 0.50 X24gm = 12 gm                

5.

10 moles of Al = ? atoms

1 mole = 6.02 X10^23 atoms ...Avogadros number

10 moles is 10 X6.02X10^23 = 6.02X10^24

6.

How many atoms are in 10 moles of Zinc?

a mole is Avogadros number

same as 10 moles of Al,10 moles of Zn=  6.02 X10^24 atoms

7.

If you had 3,5 x 10 - atoms of carbon how many grams would you have?

8.

Given 100g of C = ? atoms

Carbon has an atomic of 12  100 gm of C are 100/12 = 8.33 moles of C

each mole comtains Avogadros number so there are

8.33 X 6.02 X10^23 = 5.01 X10^24 atoms of C

Answer: protons

Explanation:

The atomic # identifies the amount of protons in an atom

Answer:

D is the most soluble in water at 60 degrees Celsius

According to the data given in the table, the salt is most soluble at 60o C - salt D.

In the given table it is given that all the salts are soluble in different concentrations in different concentrations of the water at the same temperature of 60 degrees celsius.

Converting them in the same amount of H₂O that is 100 grams in the same ratio:

Thus, the salt D is the most soluble that is 50 grams per 100 gram H₂O.

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Answer:

Presence of an Electrolyte

Metal Surface

Oxygen or Other Oxidizing Agent

Difference in Potential

Electrochemical Pathway

Explanation:

Answer:

pick the second one I've done that test

Answer:

Criminology analyzes how crime affects the community or society as a whole , while forensic science analyzes individual crimes and evidence.

the electronegativity difference (AEN):

<0.5: covalent (non polar)

0.5- 1.7: covalent (polar)

> 1.7 : ionic

CF₄

C =  2.5

F = 4

F - C = 4 - 2.5 = 1.5 (covalent polar)

NH₃

N = 3

H = 2.1

N - H = 3 - 2.1 = 0.9 (covalent polar)

75 liters of a 0.20% (m/v) KCl IV solution can be prepared from 3.0 L of a 5.0% (m/v) stock solution.

To determine the amount of a 0.20% (m/v) KCl IV solution that can be prepared from a 5.0% (m/v) stock solution, the following formula can be used:

C1V1 = C2V2

where C1 is the concentration of the stock solution, V1 is the volume of the stock solution used, C2 is the desired concentration of the final solution, and V2 is the volume of the final solution.

In this case, C1 = 5.0%, V1 = 3.0 L, C2 = 0.20%, and V2 is what we are trying to find.

First, convert the percentages to decimals:

C1 = 0.050

C2 = 0.0020

Now we can plug in the values and solve for V2:

(0.050)(3.0) = (0.0020)(V2)

0.15 = 0.0020V2

V2 = 75 L

Therefore, 75 liters of a 0.20% (m/v) KCl IV solution can be prepared from 3.0 L of a 5.0% (m/v) stock solution.

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75 liters of a 0.20% (m/v) KCl IV solution can be prepared from 3.0 L of a 5.0% (m/v) stock solution.

To determine the amount of a 0.20% (m/v) KCl IV solution that can be prepared from a 5.0% (m/v) stock solution, the following formula can be used:

C1V1 = C2V2

where C1 is the concentration of the stock solution, V1 is the volume of the stock solution used, C2 is the desired concentration of the final solution, and V2 is the volume of the final solution.

In this case, C1 = 5.0%, V1 = 3.0 L, C2 = 0.20%, and V2 is what we are trying to find.

First, convert the percentages to decimals:

C1 = 0.050

C2 = 0.0020

Now we can plug in the values and solve for V2:

(0.050)(3.0) = (0.0020)(V2)

0.15 = 0.0020V2

V2 = 75 L

Therefore, 75 liters of a 0.20% (m/v) KCl IV solution can be prepared from 3.0 L of a 5.0% (m/v) stock solution.


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The final answer is pH = 8.47. The pH of a 0.753 M (CH3)3NHCl aqueous solution at 25°C can be calculated using the equation pH = pKa + log([base]/[acid]), where pKa is the negative logarithm of the acid dissociation constant, [base] is the concentration of the base, and [acid] is the concentration of the acid.

In this case, (CH3)3NHCl is a salt that will hydrolyze in water to produce (CH3)3NH, which acts as a base, and HCl, which acts as an acid.

The Kb for (CH3)3N is given, so we can find the pKa using the equation pKa + pKb = 14. From there, we can use the concentrations of (CH3)3NH and HCl to calculate the pH of the solution.

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Subatomic particles that cause the mass of an atom to change are called isotopes. Isotopes are atoms of the same element that have an unequal number of neutrons in their nuclei.

This difference in the number of neutrons causes the mass of the atom to vary. For example, the most common form of carbon is Carbon-12, which has an atomic mass of 12 and contains 6 protons and 6 neutrons, while Carbon-14 has an atomic mass of 14 and contains 6 protons and 8 neutrons. The extra two neutrons make Carbon-14 slightly heavier than Carbon-12. The number of neutrons in an atom is determined by the number of protons and the element's atomic number, so when the number of neutrons changes, the mass of the atom changes as well. Isotopes can be naturally occurring or artificially created, and their properties may vary depending on the number of neutrons in the nucleus. Overall, isotopes are subatomic particles that cause the mass of the atom to change.

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One analysis technique that could be used to differentiate among these three glycans and determine the structure of each if they were present in a mixed sample is mass spectrometry (MS).

One analysis technique that can be used to differentiate among the three glycans and determine the structure of each if they were present in a mixed sample is mass spectrometry.

Mass spectrometry is a powerful analytical technique that can provide information on the molecular mass, structure, and composition of a molecule. In the case of glycans, mass spectrometry can be used to identify the number and type of monosaccharides, the presence and location of modifications (such as acetylation or sulfation), and the branching pattern of the glycan.

By analyzing the mass spectra of the individual glycans in the mixed sample, it is possible to differentiate among the three glycans and determine the structure of each.

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Answer:

C=m/MV

Explanation:

m= CMV= .01×40×10³=

4000g



We have a gas that we will assume behaves like an ideal gas, so we can apply the ideal gas equation.

Where,

V is the volume of the gas

P is the pressure of the gas=2.2atm

T is the temperature of the gas = 24.5 + 273.15K=297.65K

R is a constan=0.0821atm.L/mol.K

n is the number of moles = 4.1moles

Now, we clear V and replace the known data:

The volume we find is the volume that the gas occupies. Now, gases due to their characteristics occupy the volume of the container where they are contained. Therefore, the volume of the container will also be 45.5L.

Answer: The volume of the container is 45.5L

Answer: I believe the answer is surface tension :)

All of the energy stored or applied on a body cannot be converted tono work done only the available form of energy is converted to work. The remaining part is called unavailable energy which is stored on the body or taken as increase in entropy.

According to thermodynamic concepts, the not all the energy can be converted into useful work .Or in other words only available energy can be converted to work. This available form of energy is called Gibbs energy.

For instance if we take a heat engine, the heat from the hot body is not completely transferred into colder body. According  to third law of thermodynamics, this unavailable work is being considered as gone for increase in entropy.

Therefore, only available energy of the electric drill can be changed to work done and that is 222 J out of 1000 J, remaining goes for an increase in entropy of the system.

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Answer:

Emission of light

color change:)

Explanation:

Answer:

B and C

Explanation:

edge 2021

I just did it

The pH of the solution obtained after diluting the original solution by 100 times will be 7.

This is because the hydrogen ion concentration will decrease from 10⁻⁵ M to 10⁻⁷ M, resulting in an increase of the pH value.

As the concentration of acid molecules decreases, the pH of the solution increases. This is because the pH scale is logarithmic, so a small change in hydrogen ion concentration results in a large change in pH. Additionally, the pH of a solution can be affected by other factors such as the presence of buffers, which act to keep the pH of the solution stable.

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The law of conservation of mass states that the total mass of a system remains constant, regardless of the changes that occur within the system. This means that the total mass of the products of a physical change must be equal to the total mass of the reactants.

For example, consider the process of melting a block of ice. When the ice melts, it changes from a solid to a liquid, but its total mass remains the same. The mass of the water that results from the melting of the ice must be equal to the mass of the ice that was present before the change.

Similarly, other physical changes such as evaporation, condensation, sublimation, and freezing also follow the law of conservation of mass. In each of these processes, the total mass of the system remains constant, even though the physical state of the substance changes.

In conclusion, the law of conservation of mass applies to physical changes as well as chemical reactions, and requires that the total mass of the system remains constant, regardless of the changes that occur within the system.

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Answer:

94.16g of N2O

50.88g of O2

Explanation:

O2 reacts with N2 as follows:

2N2 + O2 → 2N2O

To find moles of N2O produced we need to convert the mass of each gas to moles to find limiting reactant and the moles of N2O that could be produced:

Moles N2 (Molar mass: 28g/mol):

60g N2 * (1mol / 28g) = 2.14 moles N2

Moles O2 (Molar mass: 32g/mol):

85g O2 * (1mol / 32g) = 2.66 moles O2

For a complete reaction of 2.14 moles of N2 are needed:

2.14 mol N2 * (1mol O2 / 2 mol N2) = 1.07 moles of O2.

As there are 2.66 moles of O2, reactant in excess is O2 and will remain:

2.66 moles - 1.07 moles =

1.59 moles O2. The mass is:

1.59 moles O2 * (32g / mol) =

And there are produced:

2.14 mol N2 * (2 moles N2O / 2 moles N2) = 2.14 moles N2O.

The mass is (44g/mol for N2O):

2.14 moles N2O * (44g/mol) =

In Part I, we use different concentrations for sulfuric acid (3 M  H₂SO₄) and sodium hydroxide (6 M NaOH) due to their differences in chemical properties and reactivity.

The main reason for using different concentrations is to achieve the desired neutralization reaction between the acid and the base. Sulfuric acid is a strong diprotic acid, meaning it can donate two protons (H+ ions) per molecule. On the other hand, sodium hydroxide is a strong monoprotic base, meaning it can accept only one proton per molecule.

Using a higher concentration of NaOH (6 M) ensures that there are enough hydroxide ions (OH⁻) to react with the two protons donated by each H₂SO₄ molecule at the 3 M concentration. This allows the neutralization reaction to proceed effectively, forming water and a salt as products.

The different concentrations of 3 M  H₂SO₄ and 6 M NaOH are chosen to account for the differences in chemical properties and reactivity between the acid and base, ensuring an efficient neutralization reaction.

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Explanation:

The given molecule is

H3C - C ≡ C - CH3

The numbering order is shown below:

H3C - C ≡ C - CH3

    1     2     3     4

So, the alkyne group is in the second position.

The carbon chain has four carbons.

Hence, the IUPAC name of the given compound is:

2-butyne.

Answer:

a. glucose c. ribose b. adenine d. two phosphate groups user: all organisms need energy to perform different functions. cells are able to ...

NH₄Cl and NH₄CN will make the solutions slightly acidic, while H₂CO₃, KOH, and KClO₄ will result in basic or neutral solutions.

1. The pH of the final solution will be slightly basic, around 9. This is because NH₄Cl is a salt of a weak acid (NH₃) and a strong base (HCl). When NH₄Cl dissolves in water, it will dissociate into NH₄⁺ and Cl⁻ ions. The NH₄⁺ ions will react with the OH⁻ ions from the water to form NH3 and H₂O. This will increase the concentration of OH⁻ ions in the solution, making it basic.

2. The pH of the final solution will be 10. This is because the H₂CO₃ is a weak acid and the KOH is a strong base. When the two solutions are mixed, the H₂CO₃ will react with the KOH to form K₂CO₃ and H₂O. The K₂CO₃ is a salt that does not hydrolyze, so it will not affect the pH of the solution. The only ions in solution will be K⁺ and OH⁻, which will make the solution basic.

3. The pH of the final solution will be 13. This is because KOH is a strong base. When KOH dissolves in water, it will dissociate completely into K⁺ and OH⁻ ions. The OH⁻ ions will make the solution basic.

4. The pH of a 0.50 M H₃PO₄ solution will be 2.1. This is because H₃PO₄ is a strong acid. When H₃PO₄ dissolves in water, it will dissociate completely into H⁺ and H₂PO₄⁻ ions. The H⁺ ions will make the solution acidic.

5. The pH of a solution of NH₄CN will be < 7. This is because NH₄CN is a salt of a weak acid (NH₄⁺) and a weak base (CN⁻). When NH₄CN dissolves in water, it will dissociate into NH₄⁺ and CN⁻ ions. The NH₄⁺ ions will react with the OH⁻ ions from the water to form NH₃ and H₂O. This will decrease the concentration of OH⁻ ions in the solution, making it acidic.

6. The pH of a solution of KClO₄ will be 7. This is because KClO₄ is a salt of a strong acid (HClO₄) and a strong base (KOH). When KClO₄ dissolves in water, it will dissociate completely into K and ClO₄⁺ ions. The K⁺ and ClO₄⁻ ions will not react with the water, so they will not affect the pH of the solution. The pH of the solution will be determined by the concentration of H⁺ ions in the water, which is 10⁻⁷ M.

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Complete question :

What is the pH of the final solution when 50.0 gNH_4 Cl_(s) dissolved in 1.0 L of a 0.50 M NH_3 solution? (Assume NO CHANGE IN VOLUME) What is the pH of the final solution when 50.0 mL of 0.10 M H_2 CO_3 solution is mixed with 25.0 mL of a 0.20 M KOH solution? What is the pH of a solution made by dissolving 112.2 g KOH_(s) in enough water to make 1.0 L. What is the pH of a 0.50 M H_3 PO_4 solution? Will the pH of a solution of NH_4 CN be > 7, < 7, or = 7? MUST show reasoning. Will the pH of a solution of KClO_4 be > 7, < 7, or = 7? MUST show reasoning.

Answer:

An adaptation occurs if a mutation helps an individual survive and reproduce.

Explanation:

Over generations, the mutation will become more common. An adaptation occurs if a mutation isn't passed on to offspring. Hope this helps! xx

Answer:

The charge of an element is equal to the number of protons minus the number of electrons. The number of protons is equal to the atomic number of the element given in the periodic table. The number of electrons is equal to the atomic number minus the charge of the atom.

Explanation:

Answer:

1001

Explanation:

Zeroes between non zero digits are significant

Answer:

1001 g and 120.0 mL

Explanation:

Zeros in-between natural numbers are significant

If your number has a decimal place, and you have zeroes after a natural number, then all the zeros are sig figs.

Ex: 10000.0 = 6 sig fig

Not: 0.00001 = 1 sig fig

Not: 0012.0 = 3 sig fig