Draw the organic product(s) formed when CH3CH2CH2OH is treated with each reagent. a. H2SO4 e. SOCl2, pyridine i. [1] TsCl, pyridine; [2] NaSH b. NaH f. PBr3 j. POCl3, pyridine c. HCl ZnCl2 g. TsCl, pyridine d. HBr h. [1] NaH; [2] CH3CH2Br

Answer:

24.31 g/mol.

Explanation:

moles =mass/molar mass

n=w/m

The balanced chemical equation for the reaction between strontium and oxygen can be written as follows: 2 Sr (s) + \(O_2\)(g) → 2 SrO (s).

In this equation, solid strontium (Sr) reacts with gaseous oxygen (\(O_2\)) to produce solid strontium oxide (SrO).

To determine the mass of product expected to form in this reaction, we need to consider the molar ratio between strontium and strontium oxide. From the balanced equation, we can see that 2 moles of strontium react to produce 2 moles of strontium oxide.

The molar mass of strontium (Sr) is 87.62 g/mol, and the molar mass of strontium oxide (SrO) is 119.62 g/mol. Since the molar ratio is 1:1 between strontium and strontium oxide, the mass of strontium oxide formed will be equal to the mass of strontium used.

In this case, the student added 4.93 g of strontium to the crucible. Therefore, the expected mass of strontium oxide formed will also be 4.93 g.

It's important to note that this calculation assumes that the reaction proceeds to completion, meaning that all of the strontium reacts with oxygen. In actual laboratory conditions, the yield of the reaction may be less than 100% due to factors such as incomplete reaction, side reactions, or product loss.

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Answer:

A. 4

Explanation:

We know that Tommy purchased a 2 liter bottle, in which pours 500ml of said bottle in cups, following asked of how many cups would he need before finishing the soda.

First off, 1 liter is 1,000 millileters, therefore that dividing a two liter bottle (2000ml) by 500ml will give us our answer :

2000/500

A. 4

Answer:

I can not see the file

Explanation:

the answer is air is solid

From the solubility curve, it is clear that 84 g of potassium nitrate can be dissolved in 100 g of water at 50°C.

Solubility is defined as the ability of a substance which is basically solute to form a solution with another substance. There is an extent to which a substance is soluble in a particular solvent. This is generally measured as the concentration of a solute present in a saturated solution.

The solubility mainly depends on the composition of solute and solvent ,its pH and presence of other dissolved substance. It is also dependent on temperature and pressure which is maintained.Concept of solubility is not valid for chemical reactions which are irreversible. The dependency of solubility on various factors is due to interactions between the particles, molecule or ions.

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Answer:is 15.2%

Explanation:

Got it wrong and this the correct answer it told me

The percentage of water in the original sample is 15.2 %.

From the information provided in the question;

Weight of the wet sample = 5.00g

Weight of the dried sample = 4.24g

Loss in mass =  5.00g - 4.24g = 0.76 g

percentage of water in the original sample = Difference in mass between wet and dry sample/ mass of wet sample × 100/1

Hence, when we substitute values;

percentage of water in the original sample =  0.76 g/5.00g × 100/1

percentage of water in the original sample = 15.2 %

So, the percentage of water in the original sample is 15.2 %.

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The 5 moles of water is equal to 90.075 grams of water and 220 J of energy is equal to 52.636 calories.

To change moles of water to grams, it is required to find the molar mass of the substance. The molar mass of water (H2O) is equal to 18.015 grams/mol.

To change 5 moles of water to grams, by using the following calculation:

5 moles × 18.015 grams/mol = 90.075 grams of water

Thus, 5 moles of water is equal to 90.075 grams of water.

To change joules to calories,  by using the conversion factor:

1 cal = 4.184 J.

To change 220 J of energy to calories, by using the following calculation:

220 J ×  (1 cal / 4.184 J) = 52.636 cal

Thus, 220 J of energy is equal to 52.636 calories.

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Answer:  \(\left( \ce{F} \right)\), chlorine \(\left( \ce{Cl} \right)\), bromine \(\left( \ce{Cl} \right)\), iodine \(\left( \ce{I} \right)\), and astatine \(\left( \ce{At} \right)\)

Explanation:

Answer:

major ecological grouping of plants and animals

food chain

*biome*

bacteria and fungi that break down dead matter

*decomposers*

a state of change in which the end result is equal or

balanced

*dynamic equilibrium*

the basic relationships that show how a community of plants,

animals, and bacteria live and grow and how these living

*ecosystem*

things are dependent on each other as well as the Sun, soil,

and other nonliving parts of their environment; a cycle of

relationships

line of plants and animals that shows the order in which

*Food chain*

organisms are eaten

a condition or conditions of the nonliving surroundings, such

*environmental factor*

Explanation:

The equilibrium constant for the system at this temperature is\(1.17 × 10^-31 mol^2/L^2\).

For the chemical equation:

N2(g) + O2(g) ⇌ 2NO(g)

The equilibrium mixture at a temperature of 1500 K is determined to contain 6.4 × 10^-3 mol/L of N2,\(1.7 × 10^-3\)mol/L of O2 and 1.1 × 10^-5 mol/L of NO.  First, we need to calculate the concentration of N2 and O2 required to produce

1.1 × 10^-5 mol/L of NO:

2NO(g) = N2(g) + O2(g)

Given that there are 1.1 × 10^-5 mol/L of NO, the number of moles of N2 and O2 are equal since the stoichiometric ratio is 1:1. Therefore:

\(1.1 × 10^-5 mol/L\) = [N2][O2]Kc = \(([NO]^2)/([N2][O2])Kc\)= \((1.1 × 10^-5 mol/L)^2/(6.4 × 10^-3 mol/L)(1.7 × 10^-3 mol/L)Kc\) =

1.17 × 10^-31 mol^2/L^2.

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The diagram shows a picture of a compound.

A compound is a substance that is made up of two or more different elements that are chemically bonded together in a specific ratio.

This means that the elements are combined in a way that creates a new substance with different physical and chemical properties than the individual elements.

Compounds can be formed through a variety of chemical reactions, such as combining elements through a chemical bond or through a reaction between an acid and a base.

So for the given diagram, we can see that it represents two or more elements chemically combined.

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Answer:

[Cl⁻] = 0.016M

Explanation:

First of all, we determine the reaction:

Pb(NO₃)₂ (aq) + MgCl₂ (aq) → PbCl₂ (s) ↓  +  Mg(NO₃)₂(aq)

This is a solubility equilibrium, where you have a precipitate formed, lead(II) chloride. This salt can be dissociated as:

           PbCl₂(s)  ⇄  Pb²⁺ (aq)  +  2Cl⁻ (aq)     Kps

Initial        x

React       s

Eq          x - s              s                  2s

As this is an equilibrium, the Kps works as the constant (Solubility product):

Kps = s . (2s)²

Kps = 4s³ = 1.7ₓ10⁻⁵

4s³ = 1.7ₓ10⁻⁵

s =  ∛(1.7ₓ10⁻⁵ . 1/4)

s = 0.016 M

Answer:

It transports nutrients and waste in the body

It regulates body temperature

Explanation:

Water can be regarded as one of the basic substance needed by biological organism to survive, and for growth of vegetation. Biological process such as regulation of body temperature and transportation of nutrients into the body's blood for growth of different organisms is been aided by water.

Answer:

A, B, and D

Explanation:

Answer:

4 5 6

Explanation:

The correct options that will result in mole are option B, C, and H

To know the options that will result in mole, do the following:

Ideal gas law states as follow:

PV = nRT

Where

PV = nRT

Make n the subject by dividing both sides by RT

n = PV / RT (option B)

Mole, mass and molar mass are related according to the following formula:

Mole = mass / molar mass (option C)

Molarity is defined as mole per unit volume as shown below:

Molarity = mole / volume

Make mole the subject by cross multiplying.

Mole = Molarity × volume (option H)

Thus, from the above illustrations, we can conclude that the correct options which will result in mole are option B, C, and H

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Stilbene dibromide includes (1R,2S)-1,2-dibromo-1,2-diphenylethane, (1R,2R)-1,2-dibromo-1,2-diphenylethane, (1S,2S)- It has three stereoisomers. 1,2-dibromo-1,2-diphenylethane.

Bromination of trans-stilbene primarily yields meso-1,2-dibromo-1,2-diphenylethane. Electrophilic bromine addition reaction. Stilbenes can exist as both trans and cis stereoisomers, but they naturally occur predominantly as the trans isomer due to their greater thermodynamic stability compared to the cis isomer.

If a molecule has two stereocenters there should be four possible stereoisomers. If a molecule has 3 stereocenters, there should be up to 8 stereoisomers. Therefore, the maximum number of stereoisomers for a given configuration is 2n. where n is the number of chiral centers.

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Answer:

it's non-spontaneous

Explanation:

I hope it helps you

Charles's law of gases states that the density of an ideal gas is inversely proportional to its temperature at constant pressure.

The equation is as follows;

Va/Ta = Vb/Tb

Where;

0.67/362 = 1.12/Tb

0.00185Tb = 1.12

Tb = 605.41K

This temperature in °C is 605.41 - 273 = 332°C

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Answer: Ammonia Ice

Explanation: Like Jupiter, Saturn boasts layers of clouds. The upper layers of clouds are made up of ammonia ice. Traveling toward the core, clouds of water ice form, with bands of ammonium hydrosulfide ice intermixed. The lower layers of Saturn see higher temperatures and pressures.

Answer:

To resolve this, we need to place the coefficient “2” in front of the sodium in the reactant, to give the equation shown below. 2 Na (s) + Cl 2 (g) → 2 NaCl (s) In this equation, there are two sodiums in the reactants, two sodiums in the products, two chlorines in the reactants and two chlorines in the products; the equation is now balanced.

Explanation:

7.24 moles of NaOH can produce 3.62 moles of Na3AlO3.

To determine the number of moles of Na₃AlO₃ formed from 7.24 moles of NaOH, we need to consider the balanced chemical equation for the reaction. The reaction between NaOH and Al₂(SO₄)₃ produces Na₃AlO₃ and H₂O.

The balanced chemical equation is:

6 NaOH + Al₂(SO₄)₃ → 3 Na₃AlO₃ + 3 H₂O

From the equation, we can see that 6 moles of NaOH react to produce 3 moles of Na₃AlO₃. This means that the mole ratio of NaOH to Na₃AlO₃ is 6:3, which simplifies to 2:1.

Therefore, if we have 7.24 moles of NaOH, we can calculate the moles of Na₃AlO₃ formed by dividing the number of moles of NaOH by 2:

7.24 moles NaOH / 2 = 3.62 moles Na₃AlO₃

Thus, 7.24 moles of NaOH can produce 3.62 moles of Na₃AlO₃ according to the balanced chemical equation.

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Explanation:

As I think Option C is correct i.e. NH4+.

Answer:

0.375 J/g°C

Brass

Explanation:

To identify the unknown metal, you first need to calculate the specific heat capacity using the following equation:

Q = mcΔT

In this equation,

-----> Q = heat energy (J)

-----> m = mass (g)

-----> c = specific heat capacity (J/g°C)

-----> ΔT = change in temperature (°C)

You can find the specific heat capacity by plugging the given values into the equation and simplifying to find "c".

Q = 150 J                        c = ? J/g°C

m = 20.0 g                     ΔT = 50°C - 30°C = 20°C

Q = mcΔT                                           <----- Given equation

150 J = (20.0 g)c(20°C)                      <----- Insert values

150 J = (400 g°C)c                             <----- Multiply 20.0 g and 20°C

0.375 J/g°C = c                                  <----- Divide both sides by 400 g°C

The specific heat capacity of the unknown metal is 0.375 J/g°C. According to my research, there is no metal with this exact specific heat capacity. However, the closest I could find was brass (0.377 J/g°C).

At equilibrium, the number of moles of Cl2(g) present is approximately 347.37 mol.

To determine the number of moles of Cl2(g) at equilibrium, we need to use the given equilibrium constant (Kc) and set up an ICE table to track the changes in the reactants and products.

The balanced equation for the reaction is:

CO(g) + Cl2(g) ⇌ COCl2(g)

Let's set up the ICE table:

  CO(g)     +     Cl2(g)     ⇌     COCl2(g)

Initial: 0.3500 0.05500 0

Change: -x -x +x

Equilibrium: 0.3500 - x 0.05500 - x x

Using the equilibrium concentrations in the ICE table, we can write the expression for the equilibrium constant (Kc) as:

Kc = [COCl2(g)] / [CO(g)][Cl2(g)]

Substituting the values into the equation, we have:

1.2 × 10^3 = (0.05500 - x) / [(0.3500 - x)(0.05500 - x)]

Simplifying the equation, we can cross-multiply and rearrange:

1.2 × 10^3 × (0.3500 - x)(0.05500 - x) = 0.05500 - x

Expanding and rearranging, we get:

0 = (1.2 × 10^3 × 0.05500 - 1.2 × 10^3x + 0.05500x) - x

Simplifying further:

0 = 66 - 1.245x + 0.05500x - x

0 = 66 - 0.19x

0.19x = 66

x = 66 / 0.19

x ≈ 347.37

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Answer:

Explanation:Two pre-requisite skills needed for students to learn the process of writing balanced chemical and ionic equations are:

1. Understanding of the periodic table and elements: Students must have a solid foundation in the periodic table, including recognizing elements by their symbols and understanding their properties, groups, and electron configurations.

2. Knowledge of chemical bonding and compound formation: Students should be familiar with the different types of chemical bonds (ionic, covalent, and metallic) and know how to construct chemical formulas for compounds based on their component elements and valence electrons.

Answer:

a. HCl.

b. 0.057 g.

c. 1.69 g.

d. 77 %.

Explanation:

Hello!

In this case, since the reaction between magnesium and hydrochloric acid is:

\(Mg+2HCl\rightarrow MgCl_2+H_2\)

Whereas there is 1:2 mole ratio between them.

a) Here, we can identify the limiting reactant as that yielded the fewest moles of hydrogen gas product via the 1:1 and 2:1 mole ratios:

\(n_{H_2}^{by\ HCl}=0.025L*2.27\frac{molHCl}{1L}*\frac{1molH_2}{2molHCl} =0.0284molH_2\\\\n_{H_2}^{by\ Mg}=2.38gMg*\frac{1molMg}{24.3gMg}*\frac{1molH_2}{1molMg}=0.0979molH_2\)

Thus, since hydrochloric yields fewer moles of hydrogen than magnesium, we realize it is the limiting reactant.

b) Here, we use the molar mass of gaseous hydrogen (2.02 g/mol) to compute the mass:

\(m_{H_2}=0.0284molH_2*\frac{2.02gH_2}{1molH_2}=0.057gH_2\)

c) Here, we compute the mass of magnesium associated with the yielded 0.0248 moles of hydrogen:

\(m_{Mg}^{reacted}=0.0284molH_2*\frac{1molMg}{1molH_2}*\frac{24.3gMg}{1molMg} =0.690gMg\)

Thus, the mass of excess magnesium turns out:

\(m_{Mg}^{excess}=2.38g-0.690g=1.69gMg\)

d) Finally, we compute the percent yield, considering 0.044 g is the actual yield and 0.057 g the theoretical yield:

\(Y=\frac{0.044g}{0.057g} *100\%\\\\Y=77\%\)

Best regards!

a) The limiting reactant would be HCl

From the equation of the reaction:

\(Mg (s) + 2 HCl (aq) ---> MgCl_2 (aq) + H_2 (g)\)

The mole ratio of Mg to HCl is 1:2.

Mole = mass/molar mass = molarity x volume

Mole of Mg = 2.38/24.3

                     = 0.098 moles

Mole of HCl = 2.27 x 25/1000        

                     = 0.057 moles

Thus, HCl is limiting while Mg is in excess.

b) Since the mole ratio of HCl to H2 is 2:1:

Mole of H2 produced = 0.057/2

                                    = 0.028 moles

Mass of H2 produced = mole x molar mass

                                    = 0.028 x 2

                                     = 0.057 g

c) Actual mole of Mg that should react = 0.057/2

                                                                    = 0.028 moles

Excess mole of Mg = 0.098 - 0.028

                                   = 0.07

Mass of excess Mg = 0.07 x 24.3

                                 = 1.701 g

d) Percentage yield if 0.044 g of hydrogen is obtained = yield/theoretical x 100

                     = 0.044/0.057 x 100

                       = 77.19%

This extremely high temperature indicates that under normal conditions, you do not need to worry about your car tire bursting from overheating as it is unlikely to reach such extreme temperatures.

To determine the temperature at which the tire will burst, we can use the ideal gas law equation:

PV = nRT

Where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

Rearranging the equation to solve for temperature, we have:

T = PV / (nR)

Given that the pressure threshold for bursting is 1.4 x 10^3 kPa, the volume is 30 L, and the number of moles of air is 2.5 mol, we can substitute these values along with the ideal gas constant R = 8.314 J/(mol K) into the equation.

T = (1.4 x 10^3 kPa) * (30 L) / (2.5 mol * 8.314 J/(mol K))

Converting kPa to Pa and L to m^3, and simplifying the equation, we find:

T ≈ 20,993 K

This extremely high temperature indicates that under normal conditions, you do not need to worry about your car tire bursting from overheating as it is unlikely to reach such extreme temperatures.

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