Draw a complete circuit. Label all the parts. Use a crayon to trace the path electricity takes to light the bulb.

Answer:

Balanced Forces

But what exactly is meant by the phrase unbalanced force? What is an unbalanced force? In pursuit of an answer, we will first consider a physics book at rest on a tabletop. There are two forces acting upon the book. One force - the Earth's gravitational pull - exerts a downward force. The other force - the push of the table on the book (sometimes referred to as a normal force) - pushes upward on the book.

Since these two forces are of equal magnitude and in opposite directions, they balance each other. The book is said to be at equilibrium. There is no unbalanced force acting upon the book and thus the book maintains its state of motion. When all the forces acting upon an object balance each other, the object will be at equilibrium; it will not accelerate.

Consider another example involving balanced forces - a person standing on the floor. There are two forces acting upon the person. The force of gravity exerts a downward force. The floor exerts an upward force.

Since these two forces are of equal magnitude and in opposite directions, they balance each other. The person is at equilibrium. There is no unbalanced force acting upon the person and thus the person maintains its state of motion.

Unbalanced Forces

Now consider a book sliding from left to right across a tabletop. Sometime in the prior history of the book, it may have been given a shove and set in motion from a rest position. Or perhaps it acquired its motion by sliding down an incline from an elevated position. Whatever the case, our focus is not upon the history of the book but rather upon the current situation of a book sliding to the right across a tabletop. The book is in motion and at the moment there is no one pushing it to the right. (Remember: a force is not needed to keep a moving object moving to the right.) The forces acting upon the book are shown below.

The force of gravity pulling downward and the force of the table pushing upwards on the book are of equal magnitude and opposite directions. These two forces balance each other. Yet there is no force present to balance the force of friction. As the book moves to the right, friction acts to the left to slow the book down. There is an unbalanced force; and as such, the book changes its state of motion. The book is not at equilibrium and subsequently accelerates. Unbalanced forces cause accelerations. In this case, the unbalanced force is directed opposite the book's motion and will cause it to slow down.

To determine if the forces acting upon an object are balanced or unbalanced, an analysis must first be conducted to determine what forces are acting upon the object and in what direction. If two individual forces are of equal magnitude and opposite direction, then the forces are said to be balanced. An object is said to be acted upon by an unbalanced force only when there is an individual force that is not being balanced by a force of equal magnitude and in the opposite direction.

Based on the information provided, the two bottom gears in Set B will be cooler compared to the two bottom gears in Set A.

This is because the two bottom gears in Set B are in direct contact with the cooler gears on top, which creates a better heat transfer pathway.

The gears in Set B form a continuous chain of contact with the cooler gears above, allowing for efficient heat dissipation.

In contrast, the gears in Set A are not in direct contact with the cooler gears on top, resulting in less effective heat transfer and slower cooling.

Therefore, the continuous contact between the gears in Set B facilitates better heat conduction and ultimately leads to lower temperatures compared to Set A.

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Answer:

40 m/s

Explanation:

Answer:

amplitude: how dense the medium is in the compression part of the wave, and how empty the rarefied area is

frequency: the number od wavelengths that pass a position in 1 second

pitch: the quality of the sound that is most likely linked to the frequency of the sound wave

period: the amount of time it takes one wave length to pass by a position

loudness: the quality of the sound most closely linked to the amplitude of the sound waves

The correct match for the column 1 with the column 2 is A-1,B-2,C-4,D-3,E-5. All definitions are related to sound wave.

A wave is a phenomenon that flows across a material medium without leaving any lasting mark.

A disturbance that travels through a medium with a transfer of matter and without a transfer of energy best describes a wave.

A. Amplitude - 1.how dense the medium is in the compression part of the wave, and how empty the rarefied area is

B. Frequency: 2. The number of wavelengths that pass a position in 1 second.

C. Pitch: 4. The quality of the sound, that, is most likely linked to the frequency of the sound wave.

D. Period -3. The amount of time it takes one wave length to pass by a position.

E.loudness-5. The quality of the sound, most closely linked to the amplitude of the sound waves.

Hence,the correct match for the column 1 with the column 2 is A-1,B-2,C-4,D-3,E-5.

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Answer:

D all of these

Explanation:

Extrinsic statements originate in parents ,society and teachers. Option D is correct.

Extrinsic motivation is defined as conduct motivated by external incentives. Extrinsically driven people will continue to do something even if it isn't pleasurable or rewarding in and of itself.

These incentives might be monetary or intangible in nature, such as acclaim or renown. Extrinsic motivation is distinct from intrinsic motivation in that it is only motivated by external incentives.

Extrinsic statements originate in;

a. Parents

b. Society

c. Teachers.

Extrinsic statements originate in all of the above given option.

Hence, option D is correct.

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Answer:

C

Explanation:

C should be the right answer

Finally, we can solve for the specific enthalpy of the feedwater at 100°C and conclude that the feedwater at 100°C is the desired outcome.

An adiabatic open feedwater heater in an electric power plant is a device that mixes steam and feedwater to produce feedwater at a specific temperature. In this case, 0.2 kg/s of steam at 100 kPa and 160°C is mixed with 10 kg/s of feedwater at 100 kPa and 50°C to produce feedwater at 100°C.
To solve this problem, we can use the principle of energy conservation. The energy gained by the feedwater is equal to the energy lost by the steam.
First, we need to determine the specific enthalpy of the steam and feedwater at their respective temperatures and pressures. We can use steam tables to find these values.

For the steam, at 100 kPa and 160°C, the specific enthalpy is h1.

For the feedwater, at 100 kPa and 50°C, the specific enthalpy is h2.

Next, we can use the mass flow rate of the steam and feedwater to calculate the energy gained by the feedwater.

Energy gained by feedwater = mass flow rate of feedwater * (specific enthalpy of feedwater at 100°C - specific enthalpy of feedwater at 50°C)

Now, we can equate the energy gained by the feedwater to the energy lost by the steam.

Energy lost by steam = mass flow rate of steam * (specific enthalpy of steam at 100°C - specific enthalpy of steam at 160°C)

Since the process is adiabatic (no heat transfer), the energy lost by the steam is equal to the energy gained by the feedwater.

Setting the two equations equal to each other, we can solve for the specific enthalpy of the feedwater at 100°C.

mass flow rate of feedwater * (specific enthalpy of feedwater at 100°C - specific enthalpy of feedwater at 50°C) = mass flow rate of steam * (specific enthalpy of steam at 100°C - specific enthalpy of steam at 160°C)

Finally, we can solve for the specific enthalpy of the feedwater at 100°C and conclude that the feedwater at 100°C is the desired outcome.

Please note that I cannot provide an exact numerical answer without the specific values of the specific enthalpy at different temperatures. However, by following the steps outlined above, you should be able to determine the specific enthalpy of the feedwater at 100°C.

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When Galileo observed Venus, he saw something that didn't fit with the Ptolemaic model for the Solar System and it was option a. Venus shows phases, instead of always looking nearly full at times.

In October 1610, Galileo made his first telescopic views of Venus. He was eager to find out if Venus has phases like the Moon did. Before the telescope was created, Venus and the other planets appeared to be blazing stars. Galileo was able to determine that Venus circled the Sun, not the Earth, by observing the phases of the planet.

The centuries-old notion that the sun and planets rotated around Earth were disproved by Galileo Galilei's observation that Venus appeared in our sky in phases that were comparable to those of the Earth's Moon. This proved that Venus orbited the sun.

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The maximum possible speed of the train at the end of the first 4.0 km of the journey is 0 m/s.

To calculate the maximum possible speed of the train at the end of the first 4.0 km of the journey, we can apply the principle of conservation of energy.

Assuming there are no external forces like friction or air resistance, the initial potential energy of the train will be converted into kinetic energy.

The potential energy (PE) of the train at the beginning of the journey can be calculated as PE = mgh, where m is the mass of the train, g is the acceleration due to gravity (approximately \(9.8 m/s^2\)), and h is the height difference (in this case, we assume it to be zero).

The kinetic energy (KE) of the train at the end of the 4.0 km journey can be calculated as \(KE = (1/2)mv^2\), where v is the velocity of the train.

Since the potential energy is converted into kinetic energy, we can equate the two expressions:

PE = KE

\(mgh = (1/2)mv^2\)

Simplifying and canceling out the mass:

\(gh = (1/2)v^2\)

Substituting the values, \(g = 9.8 m/s^2\)and h = 0, we get:

\((9.8 m/s^2)(0) = (1/2)v^2\)

Simplifying further:

\(0 = (1/2)v^2\)

This equation tells us that the maximum possible speed of the train at the end of the first 4.0 km of the journey is 0 m/s.

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Contaminants are substances or agents that are present in a material or environment, frequently in unwanted or hazardous proportions, and which may harm the environment, and human health.

They include pollutants that are released from industrial operations, agricultural practices, or human activities, such as pesticides, heavy metals, volatile organic compounds (VOCs), and polychlorinated biphenyls (PCBs).

They include pollutants that are released from industrial operations, agricultural practices, or human activities, such as pesticides, heavy metals, volatile organic compounds (VOCs), and polychlorinated biphenyls (PCBs).

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Answer:

The required steady force of each rocket is 28.79 N

Explanation:

mass of the satellite, M=3900 kg

radius, r=4.3 m

mass of rocket, m=210 kg

time, t=5.4 min

Moment of Inertia:

I = 1/2 (Mr^2) + 4mr^2

I = 1/2 ( 3900* (4.3)^2) + 4 (210)*(4.3)^2

I = 51587.1 kg m^2

the angular acceleration is:

a= w/t

here w= 2*π*30

so,

a= 2*π*30 / 5.4* 3600

a=0.0096 rad/ s^2

the Torque becomes:

T=I*a = 4r*F

( 51587.1 )*(0.0096) = 4*4.3* F

F= 28.79 N

the required steady force of each rocket is 28.79 N

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Lake Mead, the reservoir above the Hoover Dam, has a surface area of approximately 640 km2, so here is the gravitational potential energy of the top 1 meter of water in Lake Mead: 1.42 x \(10^1^7\) J.

Here the calculation for the gravitational potential energy is given below,  

PE = m × g × h

Here,  m = density of water × volume of water                    

m= 1000 kg/\(m^3\) × 640 \(km^2\)× 1 m

m= 640,000,000,000 kg

PE = 640,000,000,000 kg * 9.8 m/\(s^2\) * 220 m

PE= 1.42 x\(10^1^7\) J

Hence, Lake Mead, the reservoir above the Hoover Dam, has a surface area of approximately 640 km2, so here is the gravitational potential energy of the top 1 meter of water in Lake Mead: 1.42 x \(10^1^7\) J.

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The recommended minimum internal cooking temperature for ground beef, including chopped sirloin, is 160°F (71°C). This temperature should be measured using a food thermometer inserted into the thickest part of the meat.

The minimum internal cooking temperature and holding time for chopped sirloin (ground beef) depend on food safety guidelines to ensure that harmful bacteria, such as E. coli, are sufficiently destroyed.

In terms of holding time, it is generally recommended to cook ground beef until it reaches the minimum internal temperature of 160°F (71°C) and then maintain that temperature for at least 15 seconds to ensure any potential pathogens are killed.

It's important to note that these guidelines are based on food safety recommendations, and following them helps reduce the risk of foodborne illnesses. Cooking ground beef, like chopped sirloin, to the proper internal temperature is crucial for food safety.

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By Using Euler's method with two steps, we can find the approximate value of Y(2) is 2.125. , where Y is the solution of the initial value problem dy/dx = x - y, and Y(1) = 3.

Euler's method is defined as a numerical technique which is  used to approximate solutions into ordinary differential equations. The method includes dividing the interval of interest into smaller steps and thereafter approximating the solution at each step by using the derivative of the function.

In this case, we are given the initial value problem dy/dx = x - y, with the initial condition Y(1) = 3. To approximate Y(2) using Euler's method with two steps, we will divide the interval [1, 2] into two equal steps.

Step 1:

We start with the initial condition Y(1) = 3. Using the differential equation dy/dx = x - y, we can approximate the value of Y at the midpoint of the interval [1, 2].

Using the step size h = (2 - 1) / 2 = 0.5, we can calculate Y(1.5) as follows:

Y(1.5) ≈ Y(1) + h × (x - y) = 3 + 0.5 × (1.5 - 3) = 3 + 0.5 × (-1.5) = 2.25

Step 2:

Now, using the value of Y(1.5) as the new approximation, we calculate Y(2) using the same process:

Y(2) ≈ Y(1.5) + h × (x - y) = 2.25 + 0.5 × (2 - 2.25) = 2.25 + 0.5 × (-0.25) = 2.125

Thus,  by using Euler's method with two steps, the approximate value of Y(2) is 2.125.

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The complete question is

Use Euler's Method With Two Steps To Approximate Y(2), Where Y Is The Solution Of The Initial Value Problem: Dy : X − Y, Y(1) = 3

The force acting on the copper wire with a magnetic flux density of 3.6×10⁻² T acting at right angles to the wire of length 24 m is 4.15×10⁻² N

The following data were obtained from the question:

We know that force, length of wire and magnetic flux density are related according to the following equation:

F = BIL

Inputting the given parameters, the force actin on the wire can be obtained as follow:

F = 3.6×10⁻² × 0.048 × 24

F = 4.15×10⁻² N

Thus, we can conclude that the force acting on the wire is 4.15×10⁻² N

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Answer:

Any medium or material of high refractive density e.g Water which refracts the light rays 1&2 away from their normal

We know that substances expand with high temperatures and contract with low temperatures, therefore, the bridge will contract and the answer is b.

The current in the wire can be calculated using the formula I = Q/t, where I represents the current, Q represents the charge, and t represents the time. In this case, the charge passing through the wire is 8.0 c and the time period is 2.0 s.

Using the formula, we can substitute the values and calculate the current:

I = 8.0 c / 2.0 s = 4.0 A

Therefore, the current in the wire is 4.0 Amperes.

The current in the wire is 4.0 Amperes.

The current in a wire is a measure of the flow of electric charge through it. It is measured in Amperes (A) and is calculated using the formula I = Q/t, where I represents the current, Q represents the charge passing through the wire, and t represents the time period.

In this case, the charge passing through the wire is given as 8.0 coulombs (c) and the time period is given as 2.0 seconds (s). By substituting these values into the formula, we can calculate the current: I = 8.0 c / 2.0 s = 4.0 A. Therefore, the current in the wire is 4.0 Amperes.

The current in the wire is found to be 4.0 Amperes.

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Answer:

i cant see the picture clearly can u resend it?

Explanation:

Answer:

Protons and Electrons

For every proton in an atomic center, somewhere, in an orbital, there will be an electron. A proton carries a positive charge (+) and an electron carries a negative charge (-), so the atoms of elements are neutral, all the positive charges canceling out all the negative charges.

Explanation:

thank me later

Answer:

A or C

Explanation:

Answer:

Explanation: The expression would be

M1V1 = M2V2

a. \({p + a(n/V)^2} (V - nb) = nRT\), b. We cannot use the ideal gas equation for water because water is not an ideal gas, c. Volume 0.0679 m³/kg. d charts is 0.001303 m³/kg, e. Three parameter Z = Z(TR, PR, ω)

Van der Waals equation Van der Waals equation is given as: \({p + a(n/V)^2} (V - nb) = nRT\)

where p is the pressure,

V is the volume,

n is the number of moles,

R is the universal gas constant,

T is the temperature, a and b are constants for the particular gas. Here, we are required to evaluate v in m³/kg for water at T = 400°C, P = 200 bar. We cannot use Van der Waals equation for water. This equation is valid for gases that do not undergo liquefaction.

b) Ideal gas equation is given as:

\(PV = nRT\)

where P is the pressure,

V is the volume,

n is the number of moles,

R is the universal gas constant,

T is the temperature. Here, we are required to evaluate v in m³/kg for water at T = 400°C, P = 200 bar. We cannot use the ideal gas equation for water because water is not an ideal gas.

c) Steam tables : Steam tables are used to obtain thermodynamic properties of water and steam. Here, we are required to evaluate v in m³/kg for water at T = 400°C, P = 200 bar. The steam table shows the specific volume of water (v) at 400°C and 200 bar as 0.0679 m³/kg.

d) Two-parameter general compressibility charts,

\(Z = Z(TR, PR)Z\)factor is the compressibility factor, which is defined as the ratio of the actual volume of gas to the volume predicted by the ideal gas law at the same pressure vapor and temperature. Two-parameter general compressibility charts show the relationship between Z factor, reduced temperature (Tr), and reduced pressure (Pr). We can use this chart to obtain the value of Z factor. Once we have Z factor, we can use the ideal gas equation to obtain the value of specific volume (v) of water.Here, we are required to evaluate v in m³/kg for water at T = 400°C, P = 200 bar. Using the two-parameter general compressibility charts, we find the value of Z as 0.8385. Now, using the ideal gas equation:

\(PV = nRTn/V \\ nV = P/RT\)

= (200 × 10⁵)/(461.518 × (400 + 273))

= 0.015 kg/mol V

= n × v

= 0.015 × 0.0869/0.997

= 0.001303 m³/kg

Therefore, the value of v in m³/kg for water at T = 400°C, P = 200 bar using the two-parameter general compressibility charts is 0.001303 m³/kg.

e) Three-parameter general compressibility tables: Z = Z(TR, PR, ω)Three-parameter general compressibility tables show the relationship between Z factor, reduced temperature (Tr), reduced pressure (Pr), and the acentric factor (ω). We can use this table to obtain the value of Z factor. Once we have Z factor, we can use the ideal gas equation to obtain the value of specific volume (v) of water.

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The distance your vehicle travels from the time the eyes see a hazard to the time the brain knows it's a hazard is called perception distance.

Distance perception refers to a process in which a viewer perceives an interval between two points in space. Perception distance is the distance a vehicle travels from the moment you see a hazard until your brain recognizes it. For an alert driver, this is about 3/4 of a second. The velocity of your car affects the distance needed to stop it. The stopping distance is persistent by three factors: perception distance, reaction distance, and braking distance. Perception time is how long it endures to recognize a condition and comprehend that you require to stop.

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a) The tension in the stick when the ball is at twelve o'clock is 6N.

b) And at the six o'clock position is also 16N.

To determine the tension in the stick when the ball is at the three o'clock, twelve o'clock, and six o'clock positions, we can use the equation:

T = m × v² / r

where T is the tension in the stick, m is the mass of the ball, v is the speed of the ball, and r is the radius of the circle.

In this case, the mass of the ball is 0.22 kg, the speed of the ball is constant, and the radius of the circle is the same at all positions. Therefore, the tension in the stick will be the same at all positions.

Plugging the values for the mass and radius of the circle into the equation gives us the following:

T = 0.22 kg × v² / r = 16 N

Therefore, the tension in the stick when the ball is at the three o'clock, twelve o'clock, and six o'clock positions is 16 N.

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Answer:

A. 10m/s

Explanation:

1 km/h = 5 / 18 m/s

36 km/h

= 36 x 5 / 18

= 2 x 5

= 10 m/s

The resistance of the person is 9200 Ω if a fault in the switch is caused by a householder to receive a mild electric shock with the mean power transfer to the person as 5.75 W and potential difference across the person as 230 V.

The resistance of the person can be calculated using Ohm’s law.

Ohm’s law states that the potential difference across a conductor is directly proportional to the current flowing through it, provided that its temperature and other physical conditions remain constant.

It can be expressed as: V = IR,

where V is the potential difference, I is the current, and R is the resistance of the conductor.

Rearranging the equation, we get: R = V/ I.

Given that the mean power transfer to the person was 5.75 W and the potential difference across the person was 230 V, the current flowing through the person can be calculated using the formula:

P = IV

where P is the power ,V is the potential difference and I is the current flowing through the person

Rearranging the equation, we get: I = P/V

Substituting the given values, we get:

I = 5.75/230 = 0.025 A

Therefore, the resistance of the person can be calculated as:

R = V/I = 230/0.025 = 9200 Ω

Hence, the resistance of the person is 9200 Ω.

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Answer: D

Explanation: Force can do everything else.

Answer:

D. Force causes objects at rest to remain stationary.

Explanation: