Draw a basic atom (Bohr model showing me where everything is located in the above chart).

Charge
Location
Size/Mass

Protons






Electrons






Neutrons

Biometrics was first applied to law enforcement by Alphonse Bertillon, a French police officer, and researcher who borrowed the anthropological method of anthropometry to develop a biometric identification system therefore option D. is the right choice.

The police department's use of anthropometry as a means of criminal identification was the first scientific method of its kind. In the past, authorities could only track down offenders using their names or photographs. Fingerprinting ultimately replaced the technique.

Furthermore, he created the first-ever mug shot. Before Bertillon formalized the practice in 1888, offenders had already been photographed as early as the 1840s, just a few years after the introduction of photography.

In the historic Dreyfus case, Alfred Dreyfus has wrongfully convicted thanks to his faulty evidence.

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The charge balance equation for an aqueous solution of MnCl₂ that ionizes to Mn₂⁺, Cl⁻, MnCl⁺, and MnOH⁺ is: 2[Mn₂⁺] + [Cl₋] + [MnCl⁺] + [MnOH⁻] = 2[Cl⁻] + 2[MnCl⁺] + [OH⁻]

To select the charge balance equation for an aqueous solution of MnCl2₂ that ionizes to Mn₂⁺, Cl⁻, MnCl, and MnOH, we need to account for the charges of all the ions present in the solution. Here's the charge balance equation

[Mn₂⁺] + [MnOH] = 2[Cl⁻] + [MnCl]

In this equation:

The equation balances the positive and negative charges in the solution, ensuring that the total charge is neutral.

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Answer: decomposing biomass

To determine the pressure of the ammonia gas at a new volume and temperature, we can use the combined gas law, which states that the ratio of the initial pressure, volume, and temperature is equal to the ratio of the final pressure, volume, and temperature.

Using the combined gas law equation: (P1 * V1) / T1 = (P2 * V2) / T2

Given:

P1 = 585 torr (initial pressure)

V1 = 20.0 ml (initial volume)

T1 = 20.0 °C + 273.15 = 293.15 K (initial temperature)

V2 = 50.0 ml (final volume)

T2 = 50.0 °C + 273.15 = 323.15 K (final temperature)

We need to solve for P2 (final pressure).

Rearranging the equation, we have:

P2 = (P1 * V1 * T2) / (V2 * T1)

Substituting the given values into the equation:

P2 = (585 torr * 20.0 ml * 323.15 K) / (50.0 ml * 293.15 K)

Calculating this expression gives us the final pressure (P2) of the ammonia gas at the new volume and temperature.

In summary, using the combined gas law equation, we can determine the pressure of the ammonia gas at a new volume and temperature. By substituting the given values into the equation and performing the calculation, we can find the final pressure of the gas.

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Answer:

Ss90

Explanation:

Answer:

-8 m/s^2

Explanation:

The formula for acceleration is:

a= v^2 - v^1/t

a= acceleration

v^2- final velocity which in this case would be 0 since the jet comes to a stop.

v^1= original velocity which is 80 m/s.

t=time or 10s

Substitute the letters for the numbers and you get this:

a= 0 - 80/10

0 - 80= -80

-80 divided by 10 is -8.

Hope this helps! :)

Answer:

-1

Explanation:

electrons are negative

Answer:

True

Explanation:

Because the sun is a star, all stars eventually explode after a certain amount of time

Answer:

True

Explanation:

The sun will become a red giant and increase in size. During that time, the earth will increase in 1 degree each day making it inhabitable to live

Answer:

plz I. need a brainliest

Explanation:

I hope you have a good day

Answer:

Explanation:

Given: 1 dietary Calorie = 1000 calories

           1 calorie = 4.184 Joules

But,

1 dietary Calorie = 1 Kcalorie

                           = 1000 x 4.184 Joules

                           = 4184 Joules

                           = 4.184 KJoules

1 dietary Calories contains 4.184 KJ of energy.

A bottle of Coca cola contains 42 Kcalories; thus,

1 Kcalorie = 1000 calories

                = 4.184 KJoules

Energy = 42 x 1 dietary Calories

            = 42 x 4.184 KJoules

            = 175.728 KJoules

Energy ≅ 176 KJ

So that;

In my bottle of coca cola, there are 176 KJ of energy.

The -OH on the end of the pentanol molecule will affect the surface tension as it will be higher as that of as pentane or hexane.

This is referred to as the tension of the surface film of a liquid caused by the attraction of the particles in the surface layer by the bulk of the liquid.

It minimizes the surface area and the higher strength of the intermolecular force is present in the pentanol therefore the surface tension of the pentanol is more than surface tension of the pentane and hexane.

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The reaction \(2H_{2} O_{2}\) → \(2H_{2} O + O_2\) is thermodynamically favorable, meaning it occurs spontaneously in the forward direction under standard conditions.

The signs of ΔG (change in Gibbs free energy) and ΔS (change in entropy) can provide further insights into the thermodynamics of the reaction. In the given reaction, the formation of water and oxygen from hydrogen peroxide is accompanied by a decrease in the system's free energy. Thus, the ΔG value for this reaction is negative, indicating that it is exergonic and releases energy. This negative ΔG indicates that the reaction is thermodynamically favorable and tends to proceed in the forward direction. As for the ΔS value, the reaction involves the formation of two moles of water and one mole of oxygen from two moles of hydrogen peroxide. Since the products have a greater number of moles than the reactants, the ΔS value for this reaction is positive. This positive ΔS indicates an increase in entropy, reflecting a greater degree of randomness or disorder in the system.

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There are 0.0035 moles of Cu+2 in the solution.To find the number of moles of Cu+2 in the solution, we need to use the formula: n = C x V where n is the number of moles, C is the concentration in Molarity, and V is the volume in liters.

First, we need to convert the volume from mL to L:

20.0 mL = 0.020 L

Now we can substitute the given values into the formula:

n = 0.175 M x 0.020 L

n = 0.0035 moles

Since the Cu*2 complex contains one Cu+2 ion, the solution contains 0.0035 moles of Cu+2.

Therefore, the answer is that there are 0.0035 moles of Cu+2 in the solution.

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Answer:

A. 6

Explanation:

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Answer:

A.6 electrons.

Explanation:

To determine whether the forward reaction is exothermic or endothermic, we need to analyze the change in the concentration of nitrogen dioxide with respect to temperature.

If the concentration of nitrogen dioxide increases as the temperature increases, it indicates that the forward reaction is endothermic. Conversely, if the concentration decreases with increasing temperature, the forward reaction is exothermic.

In this case, we observe that as the temperature increases from 25 °C to 100 °C, the concentration of nitrogen dioxide increases from 20% to 90%. This suggests that the forward reaction is endothermic.

The reason for this behavior lies in Le Chatelier's principle, which states that a system at equilibrium will adjust to counteract any change imposed upon it. In an endothermic reaction, heat is absorbed from the surroundings to drive the reaction forward. Increasing the temperature will shift the equilibrium towards the products to absorb more heat, resulting in a higher concentration of nitrogen dioxide.

Therefore, based on the increase in nitrogen dioxide concentration as the temperature rises, we can conclude that the forward reaction is endothermic.

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Answer:

2.122×10^25atoms

Explanation:

number of moles=mass/molar mass

7.05moles= mass of pyridine/79

reacting mass of pyridine=556.95

C5H5N= (12×5)+(5)+(14)=79

C5=60

to find the mass of carbon in 556.95g of pyridine we take the stoichometric ratio

60[C5] -----> 79[C5H5N]

x[C5] --------> 556.95g[C5H5N]

cross multiply

x=(60×556.95)/79

x=423g of carbon

moles=mass/molar mass

moles of carbon=423/12

moles=35.25moles of carbon

moles=number of particles/Avogadro's constant

35.25=number of particles/6.02×10^23

number of particles=2.122×10^25atoms of carbon

The number of carbon atoms present in the 7.05 moles of pyridine is equal to 2.12 ×10²⁵. Therefore, option (D) is correct.

Avogadro’s number can be useful to express the number of particles in 1 mole of a chemical substance. Generally, these particles can be ions, atoms, molecules, electrons, or protons, according to the type of chemical reaction.

Avogadro’s constant is experimentally found approximately equal to 6.022 × 10²³ per mole.

Given, the number of moles of the Pyridine =  7.05 mol

The molar mass of the C₅H₅N = 79 g/mol

On molecule of pyridine has carbon atoms = 5

One mole of pyridine has carbon atoms = 5 × 6.022 × 10²³

Then 7.05 moles of  pyridine have carbon atoms = 7.05 ×5 × 6.022 × 10²³

                                                                             = 2.12 ×10²⁵ carbon atoms

Therefore, 2.12 ×10²⁵ carbons are present in 7.05 moles of pyridine.

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One of the tests that can indicate a problem with carbohydrate metabolism in kidney failure is a blood glucose test. Kidney failure can lead to impaired glucose regulation, resulting in elevated blood glucose levels.

This test measures the concentration of glucose in the blood and can help identify abnormalities in carbohydrate metabolism. Kidney failure, also known as renal failure, can significantly impact the body's ability to regulate glucose levels. The kidneys play a crucial role in filtering waste products and maintaining the balance of various substances in the blood, including glucose. When the kidneys are impaired, they may struggle to efficiently process glucose, leading to elevated blood sugar levels. A blood glucose test is commonly used to assess the concentration of glucose in the bloodstream. This test involves drawing a blood sample and measuring the amount of glucose present. In individuals with kidney failure, the test may reveal high blood glucose levels, indicating a problem with carbohydrate metabolism. The elevated blood glucose levels in kidney failure can be attributed to several factors. The kidneys may have reduced insulin sensitivity or impaired insulin secretion, which are essential for proper glucose utilization. Additionally, the impaired filtration and reabsorption functions of the kidneys can lead to glucose being lost in the urine, further contributing to elevated blood glucose levels. Monitoring blood glucose levels in individuals with kidney failure is crucial as it helps guide treatment and management strategies. Controlling blood glucose levels through dietary modifications, medication, or insulin therapy may be necessary to prevent complications associated with uncontrolled diabetes.In conclusion, a blood glucose test is an important diagnostic tool to assess carbohydrate metabolism in individuals with kidney failure. Elevated blood glucose levels in this population indicate potential abnormalities in glucose regulation due to the impaired kidney function. Proper management of carbohydrate metabolism and blood glucose levels is essential for overall health and preventing complications associated with kidney failure.

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A 1. 30 m solution of the weak acid ha is created. if the ka of the weak acid is 3. 06×10−9, the pH of the solution is 3.71.

Firstly we will get the equilibrium concentration, we will write the ICE chart for the reaction.

HA ------ (H+) + (A-)

1.30 0 0

1.30-x x x

Now,

the equilibrium expression can be given as

Ka = [H+] [A-]/[HA]

3. 06×10−9 = x^2/(1.30-x)

x = 1.99 × 10^(-4)

Therefore, the concentration of [H+] is 1.99 × 10^(-4).

pH = -log[H+]

pH = -log(1.99 × 10^(-4))

pH = 4-0.29

pH = 3.71

Thus, we find that the value pH of the solution is 3.71.

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The concentration of NH3 in the flask is 0.100 M. When titrating NH3 with HCl and using 25.00 mL of NH3 in the flask, it takes 25.00 mL of 0.100 M HCl to reach the equivalence point. This indicates that the concentration of NH3 in the flask is 0.100 M.

When titrating NH3 (ammonia) with HCl (hydrochloric acid), the reaction that occurs is: NH3 + HCl -> NH4Cl
In this reaction, NH3 acts as the base, while HCl acts as the acid. The equivalence point is the point at which the stoichiometric amounts of NH3 and HCl have reacted, resulting in the formation of NH4Cl.
In this specific case, it takes 25.00 mL of 0.100 M HCl to reach the equivalence point with 25.00 mL of NH3 in the flask. This means that the moles of HCl used in the titration are equal to the moles of NH3 present in the flask.

To determine the concentration of NH3 in the flask, we can use the formula:
Moles = Volume (in liters) x Concentration
Since we have 25.00 mL of NH3 in the flask, we need to convert it to liters by dividing by 1000:

25.00 mL / 1000 = 0.025 L
Now, let's substitute the values into the formula: Moles of NH3 = 0.025 L x Concentration of NH3
Since the moles of HCl used in the titration are equal to the moles of NH3, we can write:
Moles of HCl = 0.025 L x 0.100 M
Now, equating the two expressions for moles:
0.025 L x Concentration of NH3 = 0.025 L x 0.100 M
Concentration of NH3 = 0.100 M

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Some types of reactions used to convert straight chain alkanes into branched hydrocarbons and aromatic compounds include dehydrogenation and isomerization reactions.

Dehydrogenation reactions involve the removal of hydrogen atoms from the straight chain alkane to form a double bond, resulting in the formation of a branched hydrocarbon or an aromatic compound. For example, the dehydrogenation of n-butane (C₄H₁₀) can yield isobutene (C₄H₈), which is a branched hydrocarbon.

Isomerization reactions, on the other hand, involve rearranging the carbon atoms within the straight chain alkane to create a different structural isomer. This process leads to the formation of branched hydrocarbons. For instance, the isomerization of n-pentane (C₅H₁₂) can result in the formation of isopentane (C₅H₁₂), which is a branched hydrocarbon.

These reactions are commonly employed in the petrochemical industry to modify the properties of alkanes, such as increasing their octane rating or producing compounds with specific chemical functionalities.

By converting straight chain alkanes into branched hydrocarbons and aromatic compounds, these reactions enable the synthesis of a wide range of valuable products.

Therefore, Dehydrogenation and isomerization reactions are employed to transform linear alkanes into branched hydrocarbons and aromatic compounds. These reactions involve the removal of hydrogen atoms or rearrangement of carbon atoms to create compounds with different structures and properties.

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Answer:

48.075g(or 48g in correct sig figs)***

Explanation:

\(\frac{0.75mol}{1} *\frac{64.1g}{1 mol}\)=48.075g

*64.1g is the mass of SO2 which is calculated by simply taking the mass of sulfur and oxygen(but doubling it since there are two oxygens) and adding them together(32.1+2x16.0)

**btw the mol units cancel because of dimensional analysis in case anyone was wondering why

***if your teacher is like mine and specifically wants your answer in correct sig figs, use the answer in parentheses as the original problem only has 2 sig figs

Increase the temperature of the reactants and result in a faster rate of reaction for gaseous reactants.

Pressure. For a given volume, there are more reactant particles if the pressure of gaseous reactants is raised. Because there will be more collisions, the reaction rate will be higher. The rate of a reaction will increase with the pressure of the reactants.

Because there are more collisions between responding particles in gaseous processes, pressure enhances the pace of reaction.

With rising temperature, exothermic reactions occur more quickly.

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answer:

hope this one helps have a great day !

Peroxidase activity increases and then decreases due to a change from a moderately acidic environment (pH near 6) to a basic environment.

Peroxidase is an enzyme found in a wide variety of organisms, from plants to humans to bacteria. Its function is to decompose hydrogen peroxide (H₂O₂). Hydrogen peroxide is one of the toxins produced as a by-product of using oxygen to breathe. (The fact that hydrogen peroxide is toxic makes it useful in first aid kits.

Peroxidase activity is strongly influenced by pH factors. Peroxidase works best at pH 7, but increasing or decreasing pH adversely affects its activity. Therefore, when moving from a weakly acidic environment close to pH 6 to a basic one, the peroxidase activity increases as the neutral environment approaches and decreases as the basic environment approaches, so that the peroxidase activity varies with the pH of the solution.

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The complete question is as follows:

Researchers investigated the influence of environmental pH on the activity of peroxidase, an enzyme that catalyzes the conversion of hydrogen peroxide to water and oxygen gas. In an experiment, the researchers added a hydrogen peroxide solution containing guaiacol to several identical test tubes and adjusted the solution in each test tube to a different pH . The researchers included the guaiacol because it caused the solutions to change color as the reactions proceeded, which the researchers relied on for measuring reaction rates. Finally, the researchers added the same amount of peroxidase to each test tube and measured the rate of each reaction at 23°C . The results of the experiment are represented in Figure 1.

Based on Figure 1, which of the following statements best predicts the effect that a change from a moderately acidic environment ( pH near 6) to a basic environment will have on peroxidase activity?

answer choices

Peroxidase activity will decrease.

Peroxidase activity will increase.

Peroxidase activity will stay the same.

Peroxidase activity will increase at first and then decrease.

The Haber process involves the following steps:

Preparation of reactants; Compression of gases; Mixing of gases; Reaction; Separation of ammonia; Separation of ammonia

The Haber process is a method used to manufacture ammonia (NH3) from nitrogen gas (N2) and hydrogen gas (H2). The process is named after its inventor, German chemist Fritz Haber, who developed the process in the early 20th century.

The Haber process involves the following steps

The Haber process is an important industrial process for the production of ammonia, which is a vital ingredient in the production of fertilizers and many other chemical compounds.

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The phospholipids are a class of amphipathic molecules that comprise the major lipid components of the cell membrane.

Phospholipids are molecules that are unique in that they have both hydrophilic (water-loving) and hydrophobic (water-fearing) regions, which enable them to form the essential structure of cell membranes.

The hydrophilic region, or head, of a phospholipid molecule consists of a phosphate group and a glycerol molecule, while the hydrophobic region, or tail, consists of two fatty acid chains. Due to their amphipathic nature, phospholipids spontaneously arrange themselves into a bilayer when in an aqueous environment, such as within cells. This arrangement provides stability and selectively permeable barriers for cells, separating the internal cellular environment from the external surroundings.

The phospholipid bilayer allows the passage of certain molecules, such as water and gases, while restricting others, including ions and large polar molecules. This selective permeability is crucial for maintaining cellular homeostasis and regulating the transport of substances in and out of cells.

Furthermore, phospholipids provide a fluid, dynamic structure to the cell membrane, enabling the movement and function of integral membrane proteins. These proteins are essential for various cellular processes, including signal transduction, transport, and cell-to-cell communication. In summary, phospholipids are amphipathic molecules that form the fundamental structure of cell membranes, providing selective permeability and support for various cellular functions.

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TLC means Thin Layer Chromatography. It is a method that can best be described as "Affinity-Based" used in the separation of compounds that are in a mixture.

Unreacted p-nitrobenzaldehyde is simply an organic aromatic compound that contains a nitro group para-substituted to an aldehyde. in this case, if it is unreacted, that means it is the same as before the chemical reation.

Note that the question is missing key information hence the general answer.

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Explanation:

We have a 63.9 g sample of calcium hydroxide. First we have to convert those grams into moles. To do that we have to use the molar mass of calcium hydroxide.

Calcium hydroxide = Ca(OH)₂

molar mass of Ca = 40.08 g/mol

molar mass of O = 16.00 g/mol

molar mass of H = 1.01 g/mol

molar mass of Ca(OH)₂ = 1 * 40.08 g/mol + 2 * 16.00 g/mol + 2 * 1.01 g/mol

molar mass of Ca(OH)₂ = 74.10 g/mol

mass of Ca(OH)₂ = 63.9 g

moles of Ca(OH)₂ = 63.9 g /(74.10 g/mol)

moles of Ca(OH)₂ = 0.862 moles

In 1 molecule of Ca we have 2 atoms of O. So in 1 mol of Ca(OH)₂ we will have 2 moles of O atoms.

1 mol of Ca(OH)₂ = 2 moles of O atoms

moles of O atoms = 0.862 moles of Ca(OH)₂ * 2 moles of O /1 mol of Ca(OH)₂

moles of O atoms = 1.724 moles

One mol is similar to a dozen. When we say that we need a dozen eggs we know that we need 12 eggs. If we want a mol of eggs, we want 6.022*10^23 eggs. So one mol of something is 6.022 * 10^23 of that.

1 mol of O atoms = 6.022 * 10^23 atoms

n° of O atoms = 1.724 moles * 6.022 * 10^23 atoms/1 mol

n° of O atoms = 1.04 * 10^24 atoms

Answer: In a 63.9 g sample of Ca(OH)₂ we have 1.04 *10^24 atoms of oxygen.