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Answer:

El Niño Events: results from weakening easterly trade winds. The easterly trade winds are driven by a surface pressure pattern of higher pressure in the eastern Pacific and lower pressure in the west. ... The weakened trade winds allow warmer water from the western Pacific to surge eastward, so the sea level flattens out. Tropical weather pattern across the equator during El Niño. With a deeper thermocline and decreased westward transport of water, the sea surface temperature increases to greater than normal in the Eastern Pacific. This is the warm phase of ENSO, called El Niño.

Explanation:

The lb/amp/ara plate fluoresces because it contains the ara gene whereas the lb/amp plate does not fluoresce due to the absence of the ara gene.  

The ara or arabinose gene must be added to turn on the operon and make the E. coli glow. Green fluorescent protein (GFP) is a protein that glows with a bright green fluorescence and was first isolated from the marine jellyfish Aequorea victoria. Ara gene encodes the regulatory protein that binds to the pBAD promoter; the pBAD promoter binds arabinose and encourages RNA polymerase binding. When arabinose binds to the Ara gene, the production of GFP is switched on.

Because the second plate is the lb/amp plate there is no ara gene or arabinose, this hinders the binding of the RNA polymerase. As the RNA polymerase is not bound the green fluorescent protein or GFP will not be expressed. Thus the lb/amp plate also will not be showing any sort of fluorescence.

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Answer:

Angle of light source

Explanation:

Independent variable is the variable that the experimenter changes or manipulates in an experiment in order to bring about a measurable response, which is the dependent variable.

In this question, a student wants to investigate the effects of phototropism in bean plants. She places a light source directly above one plant, at a forty-five degree angle to another, and at a ninety-degree angle from the third. This shows that the variable being manipulated (independent variable) is the ANGLE OF THE LIGHT SOURCE.

Option C & D. Cell growth means that a cell gets bigger (gains mass), while cell division means that a mother cell splits into two daughter cells.

Cell division is the process of making more cells, which is what cell proliferation is. So that our bodies can grow and change, they need to make new cells and let old ones die. Cell division is also an important part of healing wounds. If our cells couldn't divide and make new ones, our bodies couldn't make new skin cells to heal a road rash or grow a fingernail back.

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Answer:

the process by which amino acids are linearly arranged into proteins through the involvement of ribosomal RNA, transfer RNA, messenger RNA, and various enzymes.

Explanation:

Answer:  

Earth's energy budget accounts for the balance between the energy that Earth receives from the Sun, and the energy the Earth radiates back into outer space after having been distributed throughout the five components of Earth's climate system. This system is made up of Earth's water, ice, atmosphere, rocky crust, and all living things. Read It And Get your answer

Explanation:

Answer:

Its either A or B Sorry if im wrong

Explanation:

Have a good day!

Answer:

b

Explanation:

The correct answer is option D

In cells treated with toxic rotenone, the concentration of NADH will increase.

Rotenone is the active chemical substance that inhibits the complex 1 electron transport chain activity of the mitochondria.

Mitochondria is the power of the house that helps in the production of ATP. Nicotinamide Adenine Dinucleotide hydrogen (NADH) produced from the citric acid cycle is given to the mitochondrial complexes.

In complex 1 of the mitochondria, NADH is converted into NAD and the hydrogen is liberated. The liberated hydrogen helps in the creation of the proton motive force. With the proton motive force, Complex 5 generates the energy currency of the cell Adenosine triphosphate (ATP).

As this conversion of NADH to NAD is inhibited by rotenone the amount of NADH in the cell will increase.

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What will happen if the cell is treated with the toxin rotenone that inhibits the electron transport chain?

A) concentration of pyruvate will decrease

B)Concentration of ATP will increase

C) Concentration of oxygen will increase

D) Concentration of NADH will increase

The smooth endoplasmic reticulum (SER) and the rough endoplasmic reticulum (RER) are involved in different processes within the cell, and their interaction depends on the cell's specific needs. the SER provides the RER with the lipids required for membrane synthesis.

The SER is responsible for lipid metabolism, whereas the RER is responsible for protein synthesis and folding. As a result, the SER provides the RER with the lipids required for membrane synthesis. The endoplasmic reticulum (ER) is a network of membranes that extends from the nucleus throughout the cytoplasm. It's divided into two types, the rough endoplasmic reticulum (RER) and the smooth endoplasmic reticulum (SER), which differ in their structure and function. The RER is studded with ribosomes, which give it a rough appearance. Ribosomes are involved in protein synthesis, and the RER is responsible for the production and folding of proteins. The SER, on the other hand, lacks ribosomes and appears smooth. The SER is involved in lipid synthesis, detoxification, and the storage of calcium ions. The interaction between the SER and RER within a cell is dependent on the cell's requirements. In certain cells, the RER may need lipids from the SER for the production of cell membranes. In such a situation, the SER will supply the RER with the required lipids. As a result, option 1 is the best predictor of how the SER and RER will interact within a cell.

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complete question: which of the following best predicts how the smooth endoplasmic reticulum (ser) and the rough endoplasmic reticulum (rer) will interact within a cell?

1. The SER will provide the RER with lipids for membrane synthesis.

2. The SER will transport materials around the cell for the RER to process.

3. The SER will provide the RER with proteins for folding and modification.

4. The RER will provide the SER with energy for processes

Agriculture is the cultivation of soil, through its own procedures, methods and techniques, which seek to produce food for human consumption.

With this information, we can conclude that agriculture is the cultivation of soil, through its own procedures, methods and techniques, which seek to produce food for human consumption.

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The loss of Artic ice is negative between human population. It will cause human population who live in coastal areas in the artic circle will have to deal with erosion on the coast lines.

Answer: carbon dioxide, water molecules, glucose, and oxygen

Explanation: Energy is used to convert carbon dioxide into oxygen and glucose.

Answer:

The correct answer is biological.

Explanation:

When any pathogen invades the body, it has to pass several lines of defence. The first barrier is the skin and mucous membrane which is a physical and chemical barrier. The second line of defence is the non-specific response by macrophages, neutrophils and interferon. After crossing these two barriers the third line of defence comes into action in which, the B- cells and T-cells act specifically on the pathogen and destroy it.

Answer:

\(\huge\boxed{\sf Biological}\)

Explanation:

When first and second line of defense is passed by the bacteria, the third line of defense will come into action which is a biological barrier which includes antigen which are anti-bodies generating substances.

\(\rule[225]{225}{2}\)

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Answer:

B

Explanation:

Both traits on the left are dominant meaning the offspring would take on that trait no matter what.

The loss of water in the urine due to unreabsorbed solutes is known as osmotic diuresis. Osmotic diuresis refers to the increased production of urine caused by the presence of osmotically active substances in the renal tubules.

Normally, the kidneys reabsorb water and solutes from the filtrate to maintain water balance in the body. However, in certain conditions, such as uncontrolled diabetes mellitus or the administration of certain medications, high levels of solutes, such as glucose or mannitol, may be present in the renal tubules. These solutes create an osmotic gradient that prevents the reabsorption of water, resulting in increased urine production. As a consequence, excessive amounts of water are lost in the urine, leading to dehydration and electrolyte imbalances if not managed appropriately.

Osmotic diuresis can occur in conditions like uncontrolled diabetes mellitus, where glucose levels in the blood are elevated. In this case, the renal threshold for glucose reabsorption is exceeded, leading to glucose spilling into the urine. The presence of glucose in the renal tubules creates an osmotic force that prevents the reabsorption of water, resulting in increased urine output. Similarly, the administration of certain medications, such as mannitol, can also cause osmotic diuresis by increasing the osmotic pressure in the renal tubules. It is important to address the underlying cause of osmotic diuresis and manage it accordingly to prevent dehydration and electrolyte imbalances.

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Answer:

DNA Analysis

Explanation:

Electron microscopy has enabled the greatest advances in understanding law of inheritance.  Thus, option D is correct.

Inheritance can be defined as the process by which an offspring can carry genetic information from their parent.

Gregor Mendel who first postulated laws of inheritance while doing hybridization experiment on garden pea plant.

He proposed three laws

First Law of Dominance states that In an organism, a character express in two forms or allele.  

In F1-progeny the allele which is expressed is called dominant, while the other remain masked is called recessive allele.

Second Law of segregation which states the alleles do not show any mixing and both the traits are appeared in F2-generation.

Third Law of Independent Assortment states that when two pairs of characters are combined, separation of one pair of trait is independent of other pair segregation of one pair of character.

Thus, option D is correct.

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The answer is : I- P+ O+ Z-Y+

The lac operon genes, which encode vital enzymes for lactose absorption and processing, must be expressed for the bacteria to utilise lactose. E. coli should only express the lac operon when two conditions are met in order to be as effective as possible:

Glucose is not readily available, but lactose is.

The Y gene  codes for lactose permease.

In the operon I- P+ O+ Z-Y+, I codes for repressor protein, therefore I- implies this lacks repressor means operon is not inhibited so it is always active. 

Z codes for beta-galactosidase in this operon.

This haploid species can produce permease persistently but do not produce -galactosidase since this operon has no functioning Z gene but does have a functional Y gene.

So the answer is : I- P+ O+ Z-Y+

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Answer:

choice A the cell will not change .

explanation

because isotonic solution is one where the concentrations are balance

The complex of a transverse tubule and two adjacent terminal cisternae is known as a triad.

The muscle cell has distinct regions called terminal cisternae. When an action potential travels down the transverse tubules, eliciting muscle contraction, they release calcium, increasing the sarcoplasmic reticulum's capacity to release calcium.

A triad is a T-tubule that is surrounded by two adjacent terminal cisternae. The mechanisms that convert a nervous impulse into an actual muscle contraction are the terminal cisternae and the transverse tubules Calcium can enter the cell by activating the L-type calcium channel. Because there are more L-type calcium channels in T-tubules than in the rest of the sarcolemma, T-tubules carry the majority of calcium into the cell.

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Answer:

The correct answer would be - three chromosomes.

Explanation:

Meiosis is the type of cell division that takes place in only sex cells and called reduction division as a single parent cell divide into four daughter cell that contains a half number of chromosomes as the parent cell.

The daughter cells are always haploid and have the half number of chromosomes. If an organism has 2n number of in its parent sex cell the daughter cells after meiosis will have n number of chromosomes

Therefore, mosquito = 2n = 6

after meiosis = n = 6/2 = 3

Thus, the correct answer would be - 3 chromosomes.

Heterosporous plants are the ones that produces two different type of spores. Spores can be different in shape and size and that's the name heterosporous. It produces two different shaped spores to differentiate between male and female gametophytes

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Meiosis and mitosis are forms of cell divisions that occurs in cells in eukaryotes. This forms of division enables growth and development.

The major way meiosis ii differ from mitosis is that in meiosis II, the daughter cells formed are haploid cells.

Mitosis is also termed as an equational division meaning that the end result yields the same number as the beginning, there is no reduction and resulting cells are still diploid.

In meiosis, there is the reduction in half first in meiosis I then the homologous chromosomes separates at the centromeres in meiosis II resulting in haploid cells.

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The standard plate count approach is better for assessing food and water safety since it counts only live bacteria. The classic plate count method includes inoculating a diluted sample onto an agar medium and letting the bacteria develop into visible colonies.

Each colony is a live, potentially harmful bacterium. Counting colonies estimates the sample's live bacteria. For sample safety, this approach counts live bacteria. Living bacteria can grow and reproduce, making them most likely to cause foodborne or waterborne infections. The standard plate count approach better estimates sample risk by counting only live bacteria.

Microscopic examination or DNA-based approaches may count living and dead bacteria or non-viable cells. These approaches may overestimate bacterial density and safety by not distinguishing viable from non-viable bacteria.

Thus, the standard plate count method targets living bacteria, making it easier to assess food or water sample safety.

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To implement PRE principles, students squeeze a clothespin until fatigued, rest, and repeat. They should gradually increase the resistance of the clothespins they are squeezing over time.

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We require information on the inheritance patterns of the questioned characteristic in order to examine the four hypotheses.

For instance, to determine if a certain trait is X-linked dominant, it is necessary to compare the frequency of the characteristic in males and females to the frequency that would be anticipated if the trait were inherited randomly.

We can identify which hypothesis cannot be rejected based on the evidence. For instance, it is possible that a characteristic is X-linked dominant if the frequency of the trait in men is much greater than would be predicted if the trait were inherited randomly. On the other hand, if the trait's prevalence in men is comparable to its projected prevalence.

If we continue to test the other hypotheses (X-linked recessive, autosomal recessive) based on the observed data, we can determine which one cannot be rejected. The hypothesis that cannot be rejected is the one that is most consistent with the observed data.

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True. Muscle burns three times more calories than fat on a daily basis.

It's true that the quantity of muscle mass and the rate at which it is used affects how many calories are burned. To put it another way, muscles burn more calories than fat. As a result, the more muscle you have, the more calories you burn even when you're resting.

According to studies, a pound of muscle burns six calories each day, while a pound of fat only burns two calories per day. This suggests that by converting fat into muscle, you can burn more calories, even when you're not working out. As a result, it's important to consider strength training as part of your fitness routine. Regular strength training workouts can help you build muscle, burn fat, and increase your metabolism. As a result, it's easier to maintain a healthy weight.

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Wood frogs are found in the United States throughout the forests of Alabama and Northwest into Idaho. Wood frogs are the only frogs that live North of the Arctic Circle. Adults usually live in woodlands and lay in vernal pools.

Wood frogs live in a variety of habits, from forests to bogs to tundra. They hibernate on land and breed in water.

The Wooded frog does adapt in warmer climates by hibernating by nestling down into the leafy litter on the forest floor.

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Oxaloacetate is converted to Acetyl-CoA or malate, which are transported to the cytoplasm via transporter proteins for gluconeogenesis.

Oxaloacetate, which is produced in the mitochondrial matrix during the TCA cycle, needs to be transported to the cytoplasm for gluconeogenesis to occur.

There are two ways in which oxaloacetate can leave the mitochondria: it can be converted to Acetyl-CoA by the enzyme pyruvate carboxylase, which is then transported to the cytoplasm via a transporter protein; or it can be converted to malate by malate dehydrogenase, which is then transported to the cytoplasm via a different transporter protein.

Once in the cytoplasm, Acetyl-CoA or malate can be converted back to oxaloacetate, which is a key intermediate in the process of gluconeogenesis.

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Oxaloacetate is an important intermediate in gluconeogenesis, which takes place in the cytoplasm of the cell. However, oxaloacetate is generated in the mitochondrial matrix during the Krebs cycle.

The most common mechanism by which oxaloacetate is transported to the cytoplasm is through conversion to malate. The enzyme malate dehydrogenase converts oxaloacetate to malate in the mitochondrial matrix. Malate is then transported out of the mitochondria into the cytoplasm via a specific transporter protein in the inner mitochondrial membrane. Once in the cytoplasm, malate is converted back to oxaloacetate by cytoplasmic malate dehydrogenase.Alternatively, oxaloacetate can be converted to Acetyl-CoA in the mitochondria. Acetyl-CoA can then be transported to the cytoplasm via a specific transporter protein in the inner mitochondrial membrane. Once in the cytoplasm, Acetyl-CoA can be converted back to oxaloacetate by a series of enzymatic reactions.In summary,

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Answer:

water velocity decreases

Explanation:

Sediment deposition will occur along the inner meander bends where the velocity is low.