Does the culture distinction of a certain role still exist in the community?

The given reaction releases 906 kJ of heat energy when 4 moles of ammonia react.

So, the amount of heat energy released when 1 mole of ammonia reacts is:

906 kJ ÷ 4 mol = 226.5 kJ/mol

To produce 453 kJ of heat energy, we can use the following proportion:

226.5 kJ/mol = 453 kJ/x

where x is the number of moles of ammonia required.

Solving for x, we get:

x = (453 kJ × 4 mol) ÷ 906 kJ

x ≈ 2 mol

Therefore, 2 moles of ammonia must react to produce 453 kJ of heat energy.

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The given reaction releases 906 kJ of heat energy when 4 moles of ammonia react.

So, the amount of heat energy released when 1 mole of ammonia reacts is:

906 kJ ÷ 4 mol = 226.5 kJ/mol

To produce 453 kJ of heat energy, we can use the following proportion:

226.5 kJ/mol = 453 kJ/x

where x is the number of moles of ammonia required.

Solving for x, we get:

x = (453 kJ × 4 mol) ÷ 906 kJ

x ≈ 2 mol

Therefore, 2 moles of ammonia must react to produce 453 kJ of heat energy.

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Glycolysis and photosynthesis are fundamental processes that are necessary for the survival of living organisms. They are similar in that they both involve the conversion of energy, but differ in the source of energy used, the location of the process, and the requirement for oxygen.

Glycolysis and photosynthesis are two necessary fundamental processes. Glycolysis is a metabolic pathway that occurs in the cytoplasm of cells. The glycolysis process is necessary because it produces ATP, which is the energy required for all cellular activities.

The energy is produced by breaking down glucose into two pyruvate molecules.Photosynthesis is the process by which green plants make their food. During photosynthesis, light energy is converted into chemical energy, which is stored in glucose molecules. This process is also necessary as it provides food and oxygen for most living organisms to survive.In terms of similarities, both glycolysis and photosynthesis are processes that involve the conversion of energy.

In glycolysis, glucose is converted into pyruvate and ATP, while in photosynthesis, light energy is converted into chemical energy. Both processes are also vital to the survival of living organisms.The primary difference between the two processes is the source of energy used. Glycolysis uses glucose as the primary energy source while photosynthesis uses light energy from the sun.

Glycolysis occurs in the cytoplasm of cells while photosynthesis takes place in the chloroplasts of plant cells. Glycolysis is an anaerobic process that does not require oxygen, while photosynthesis is an aerobic process that requires oxygen and releases it as a byproduct.

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It is fundamental to distinguish science from pseudoscience because science can help us to understand questions from the real world.

The term 'science' makes reference to all the body of knowledge obtained by using the scientific method, which is based on collecting empirical evidence that helps to test hypotheses or explanations (either confirm or reject them), that emerged by observing the real world.

Conversely, pseudoscience is not a discipline because it is not based on scientific evidence and therefore this type of data cannot be tested or verified, which is fundamental to progress in our understanding of the tangible characteristics of the real world.

In conclusion, it is important to distinguish science from pseudoscience because science can help us to understand questions from the real world and solve problems associated with our health and the environment.

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Answer:

Because the total energy of the enzyme has been used up and actions already complete

Explanation:

Catalyst are substance known to speed up rate of chemical reaction just like taking a short pathway. When velocity of catalyzed reaction reach maximum, at that moment reaction has reach it full potential (there is an equilibrium in reaction). there won't be any changes on further addition, and mostly indicate that Reaction is Complete

Answer:

there are approximately 0.004118 moles in 0.1 g of magnesium.

Explanation:

The molar mass of magnesium is approximately 24.31 g/mol. To calculate the number of moles in 0.1 g of magnesium, we can use the following formula:

Number of moles = Mass / Molar mass

Number of moles = 0.1 g / 24.31 g/mol

Number of moles = 0.004118 mol (rounded to 3 significant figures)

Therefore, there are approximately 0.004118 moles in 0.1 g of magnesium.

Answer:

Explanation:

To calculate the number of moles of magnesium in 0.1 g of magnesium, we first need to determine the molar mass of magnesium. The molar mass of magnesium is 24.31 g/mol.

Using this information, we can use the following formula to calculate the number of moles of magnesium:

moles of magnesium = mass of magnesium / molar mass of magnesium

moles of magnesium = 0.1 g / 24.31 g/mol

moles of magnesium ≈ 0.00412 mol

Therefore, there are approximately 0.00412 moles of magnesium in 0.1 g of magnesium.

A sample of \(F_2\) gas that occupies 25.0 mL at a pressure of 1.2 atm will occupy 2.73 mL at a pressure of 5.5 atm, assuming the temperature remains constant.

To solve this problem, we can use the combined gas law, which relates the pressure, volume, and temperature of a gas before and after a change in one or more of these properties. The combined gas law is given by:

\((P_1 * V_1) / T_1 = (P_2 * V_2) / T_2\)

where\(P_1\) and \(V_1\) are the initial pressure and volume, \(T_1\) is the initial temperature, \(P_2\) and \(V_2\) are the final pressure and volume, and \(T_2\) is the final temperature.

In this problem, we are given the initial volume of \(F_2\) gas as 25.0 mL at a pressure of 1.2 atm. We want to find the final volume of the gas at a pressure of 5.5 atm. The temperature is not given, but we can assume that it remains constant.

We can rearrange the combined gas law to solve for\(V_2\):

\(V_2 = (P_1 * V_1 * T_2) / (P_2 *T_1)\)

Plugging in the values, we get:

\(V_2\) = (1.2 atm x 25.0 mL x \(T_2\)) / (5.5 atm x \(T_1\))

We can simplify the expression by canceling out the units of atm and mL:

\(V_2\) = (1.2 x 25.0 x \(T_2\)) / (5.5 x \(T_1\)) mL

\(V_2\)= (30 x \(T_2\)) / (11 x\(T_1\)) mL

We can see that the final volume of the gas is proportional to the ratio of the temperatures \(T_2\)/\(T_1\). Since we are assuming that the temperature remains constant, this ratio is equal to 1, and we can simply calculate the final volume as:

\(v_2\) = (30 mL) / (11) = 2.73 mL

Therefore, a sample of\(F_2\) gas that occupies 25.0 mL at a pressure of 1.2 atm will occupy 2.73 mL at a pressure of 5.5 atm, assuming the temperature remains constant.

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The heat energy given off when liquid mercury at 28.9 °C is converted to solid mercury at its melting point is 284.2 J.

The heat energy given off when liquid mercury at 28.9 °C is converted to solid mercury at its melting point is determined as follows:

Moles of Mercury:

14.0 g Hg x 1 mol Hg/201 g = 0.0697 moles

Heat released:

q = heat = m x C x ∆T

25ºC = 298.15K

25ºC = 298.15K

∆T = 234.32  K- 298.15 K

∆T = 63.83 K

q = (0.0697 mol)(28.0 J/molK)(63.83K) = 124.6 J

The heat released from liquid to solid:

q = m x ∆H fusion = (0.0697 mol)(2.29 kJ/mol)

q = 0.1596 kJ

q  = 159.6 J

The total heat energy is given off:

Qtotal = 124.6 J + 159.6 J

Qtotal = 284.2 J

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Complete question:

Calculate the heat energy released when 14.0 g of liquid mercury at 28.9 °C  °C is converted to solid mercury at its melting point.

Answer: A

Explanation:

As one increases the other goes in a straight line.  It is called a direct proportionality.  Forms a linear graph.

The equilibrium amounts of each substance in the reaction are the following: the amounts of moles of HI, H₂ and I₂ at equlimbrium are 0.19 moles, 0.005 moles and 0.105 moles respectively.

We have an equilibrium reaction and initial amounts reactants and products are provide.

Initial amount of moles of hydrogen gas, H₂ = 0.10

Initial amount of moles of iodine gas, I₂ = 0.20

Temperature = 300K

Equilibrium constant, K꜀ at 300 K = 70

Let the moles of products at equilibrium be x.

H₂ + I₂ ⇌ 2 HI

at t = 0 0.1 0.2

at eqᵐ, (0.1 - x) (0.2 - x) 2x

For an equilibrium equation aA + bB ⇌ cC + dD, the equilibrium constant, can be determined using the formula K = [C]ᶜ[D]ᵈ/ [A]ᵃ[B]ᵇ , where K꜀ is a constant. Comparing the equations we get

K꜀ = [HI]²/ [H₂][I₂]

=> 70 = (2x)²/ (0.1 - x)(0.2 - x)

=> 70(0.1 - x)(0.2 - x) = 4x²

=> (7 - 70x)(0.2 - x) = 4x²

=> 70 x² - 21 x + 1.4 = 4x²

=> 66x² - 21x + 1.4 = 0 , which is an quadrtic equation. On solving this equation by quadrtic formula, we get x = 0.095.

So, the amounts of moles of HI at equlimbrium

= 2× 0.095 = 0.19 moles

the amounts of moles of H₂ at equlimbrium = 0.1 - 0.095 = 0.005 moles

the amounts of moles of I₂ at equlimbrium = 0.2 - 0.095 = 0.105 moles.

Hence, required amounts of each substance obtained.

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ANSWER

Photon

EXPLANATION

Answer:

3287.04 grams

Explanation:

The mass of 3.21 × 10²⁴ molecules of potassium hydroxide is equal to  298.5 g.

Avogadro’s constant can be explained as the proportionality factor that can be used to count the number of particles such as molecules, atoms, or ions in a given sample with a definite amount of substance.

Avogadro's number can be described as the approximate number of nucleons in 1 gram of substance. The value of the Avogadro constant can be expressed as the mass of one mole of a compound, in grams.

The value of Avogadro’s number is found about 6.022×10²³ mol⁻¹.

Given, the number of molecules of the KOH = 3.21 × 10²⁴

The mass of the one mole of KOH = 56 g/mol

The 6.022 × 10²³ molecules of KOH has mass = 56 g

The mass of 3.21 × 10²⁴ molecules of KOH = 56×(3.21× 10²⁴/6.022 × 10²³)

= 298.5 g

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Answer:

A different atomic mass, which means that there is a varying number of nuetrons in the nucleus between isotopes.

Explanation:

Answer:

I'm good, sorry though lol.

Answer:

approximately 251.55 grams of AuCl3 would contain 5.0 x 10^23 molecules.

Answer:25.75

Explanation:

The equation that relates A and W, considering the desired 15% acetic acid concentration, is 3W = 2.55M.

The equation A = (3/17)W represents the relationship between the mass of acetic acid (A) and the mass of water (W) in the mixture. It states that the mass of acetic acid is equal to three seventeenths (3/17) of the mass of water.

Since the company wants the acetic acid to be 15% of the total mass of the mixture, we can set up another equation to represent this requirement. Let M be the total mass of the mixture. The mass of acetic acid (A) is 15% of the total mass, so we have A = 0.15M.

Now we can substitute A in terms of W from the first equation into the second equation: (3/17)W = 0.15M. We can simplify this equation by multiplying both sides by 17 to get 3W = 2.55M.

This equation allows the company to calculate the mass of water (W) required for a given mass of acetic acid (A) to maintain the desired concentration in the mixture.

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Answer:

Explanation:

The pH of 0.02 M hydrochloric acid is approximately 1.7.

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Answer:

15. Velocity = 3 X 10^8

     Distance = 1580 m

time = distance / velocity

t = 1580 / 3 * 10^8

t =  1580 * 10^-8 / 3

t = 158 * 10^-7/3

t = 5.26 * 10^-8 seconds  

16. Converting the distance to 'm'

Given distance (in miles), multiplying by 1.609 to convert to  km and also multiplying by 1000 to convert to 'm'

s= 4.8 * 1.609 * 10^7 * 1000

v = 3 * 10^8

t =  4.8 * 1609  * 10^7 / 3 * 10^8

t = 1.6 * 1609 * 10^-1

t = 2574.4 * 10^ -1

t = 2.5744 * 10^-4 s

17. Mass in 1 tsp of medicine = 5 mL at a density of 25 mg/mL

Mass in 1 tsp of medicine = 5 * 25 = 125 mg

Mass prescribed by the doctor  = 375 mg

Number of table spoons required = Mass prescribed / Mass in 1 tsp

N = 375/125 = 3 table spoons of the medicine

18. Density of medicine = 400g/ 5mL = 80g / mL

Medicine required = 1500 g

Volume of medicine required = Medicine Required / Density of medicine

Volume = 1500 / 80 = 18.75 mL of medicine is required

Hence, the volume of the suspension should be at least 18.75 mL

19. Volume of 10 drops = 1 mL

Volume of 5 drops = 1/2 mL

The faucet is leaking 5 drops or 1/2 mL water per minute

Number of minutes in a day = 60 * 24  = 1440 minutes in a day

Water leaked in 1440 minutes = 1440 * 1/2 = 720

0.720 L (720 mL) Water leaked from the faucet in a day

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Answer:

The new volume of the gas is 156.25 mL.

Explanation:

According to Boyle's Law, at constant temperature and number of moles, the pressure and volume of a gas are inversely proportional.

So, we can use the following equation to solve for the new volume (V2):

P1V1 = P2V2

Where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume, respectively.

Substituting the given values:

(1.25 atm) x (250.0 mL) = (2.00 atm) x V2

Solving for V2:

V2 = (1.25 atm x 250.0 mL) / (2.00 atm)

V2 = 156.25 mL

Therefore, the new volume of the gas is 156.25 mL.

Answer:

0.00500M of Na₂C₂O₄

Explanation:

When are dissolved in 150 mL of 1.0 M H2SO4.

We can solve this problem finding molarity of sodium oxalate: That is, moles of Na2C2O4 per liter of solution. Thus, we need to convert the 0.1005g to moles using molar mass of sodium oxalate (134g/mol) and dividing in the 0.150L of the solution:

0.1005g * (1mol / 134g) = 7.5x10⁻⁴ moles of Na₂C₂O₄

In 0.150L:

7.5x10⁻⁴ moles of Na₂C₂O₄ / 0.150L =

The concentration of the solution is 0.005 M.

From the information available in the question;

We know that;

Mass of  Na2C2O4 = 0.1005 g

Volume of solution = 150 ml

To obtain the number of moles of Na2C2O4;

Number of moles = mass/molar mass

Molar mass of Na2C2O4  = 134 g/mol

Number of moles =  0.1005 g /134 g/mol = 0.00075 moles

Concentration = number of moles/volume

Volume of solution = 150ml or 0.15 L

Concentration =  0.00075 moles/0.15 L

= 0.005 M

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Missing parts

An acidic solution of sodium oxalate (Na2C2O4) was prepared by dissolving ~0.100 g of Na2C2O4 in 150 mL of 1.0 M H2SO4 in a 250 mL Erlenmeyer flask. Calculate the concentration of the resulting sodium oxalate solution if 0.1005 g of Na2C2O4 was used.

Answer:

False, the nucleus is not inside the chromosomes, but the chromosomes are inside the nucleus.

Answer:

The answer is 2,200ºC

Explanation:
I took the assignment for Edge, I don't think I can send the image because it might pick up on that and get reported, sorry!

The only other rationale that I have is that it's boiling because the graph shows that it's at a constant temperature/rate at 2,200ºC for quite a while. Typically when something boils, it stays at that constant rate of boiling, unless you turn the temperature up or it's finally able to peak..?

Answer:

C. 2,200

Explanation:

Ed22

Answer: C7H16 + 11O2 = 7CO2 + 8H2O

Explanation:

Explanation attached:

Answer: The activation energy, Ea, of the reaction is 89195 Joules

Explanation:

The effect of temperature on rate constant is given by Arrhenius equation:

\(ln \frac{k_{2}}{k_{1}} = \frac{-E_{a}}{R}[\frac{1}{T_{2}} - \frac{1}{T_{1}}]\)

where  

\(k_2\) = rate constant at temperature \(T_2\)

\(k_1\) = rate constant at temperature \(T_1\)

\(E_a\)= activation energy

R= gas constant

\(T\) = temperature  

\(ln \frac{17k_1}{k_{1}} = \frac{-E_{a}}{8.314}[\frac{1}{300} - \frac{1}{278}]\)

\(2.83=\frac{-E_{a}}{8.314}[\frac{1}{300} - \frac{1}{278}]\)  

\(E_a=89195J\)

The activation energy, Ea, of the reaction is 89195 Joules

Answer:

the total number of protons and neutrons in a nucleus.

The mass number, also called atomic mass number or nucleon number, is the total number of protons and neutrons in an atomic nucleus. It is approximately equal to the atomic mass of the atom expressed in atomic mass units.

Answer:

204g of NH3

Explanation:

The balanced equation for the reaction is given below:

N2 + 3H2 —> 2NH3

Next, we shall determine the number of mole NH3 produced by reacting 6moles of N2. This is illustrated below:

From the balanced equation above,

1 mole of N2 reacted to produce 2 moles of NH3.

Therefore, 6 moles of N2 will react to produce = 6 x 2 = 12 moles of NH3.

Finally, we shall convert 12 moles of NH3 to grams. This is illustrated below:

Number of mole of NH3 = 12 moles.

Molar mass of NH3 = 14 + (3x1) = 17g/mol

Mass of NH3 =..?

Mass = mole x molar mass

Mass of NH3 = 12 x 17

Mass of NH3 = 204g.

Therefore, 204g of NH3 will be produced from the reaction.

The ionization of the following acids can be represented as:

Tetraoxosulphate (VI) Acid (\(H_{2}SO_{4}\)) ionizes as H+ and SO4^2- ions.

Trioxonitrate (V) Acid (\(HNO_{3}\)) ionizes as H+ and \(NO_{3-}\) ions.

Ethanoic Acid (\(CH_{3}COOH\)) ionizes as H+ and \(CH_{3}COO^{-}\) ions.

Tetraoxosulphate (VI) Acid, also known as sulfuric acid (\(H_{2}SO_{4}\)), ionizes as follows:

\(H_{2}SO_{4}\) → \(H+\) + \(SO_{4}^{2-}\)

In this reaction, sulfuric acid donates two hydrogen ions (H+) to the solution, forming sulfate ions (\(SO_{4}^{2-}\)).

Trioxonitrate (V) Acid, commonly known as nitric acid (\(HNO_{3}\)), ionizes as follows:

\(HNO_{3}\) → \(H+_{}\) + \(NO_{3-}\)

Nitric acid dissociates to release one hydrogen ion (\(H+\)) and a nitrate ion  (\(NO_{3-}\)).

Ethanoic Acid, also known as acetic acid (\(CH_{3}COOH\)), ionizes as follows:

\(CH_{3}COOH\) → H+ + \(CH_{3}COO^{-}\)

Acetic acid donates a hydrogen ion (H+) to the solution, forming an acetate ion (\(CH_{3}COO^{-}\)).

In all cases, the acids dissociate in water, producing hydrogen ions (H+) as positively charged ions and their corresponding anions. The hydrogen ions are responsible for the acidic properties of these substances, while the anions contribute to the overall charge balance in the solution. The ionization of acids allows them to conduct electricity in aqueous solutions and react with other substances.

The question was incomplete. find the full content below:

Indicate the ionization of the following acids,

Tetraoxosulphate (VI) Acid

Trioxonitrate (V) Acid

Ethanoic Acid.​

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