Does domain pertaing to the x-value or y-value?
Same question for range.

Answer:

f[g(x)]

7(x^2)-9

Step-by-step explanation:

(fºg)(x) read: f of g of x. And can be seen written like in this format: f[g(x)]. Which I prefer.

The expression f[g(x)] means that you put the expression g(x) into the x variable for f(x). Comment if you need a better explanation :)

So, the solutions to the given rational equation are x = 9/2 or x = -1/2.

To solve the rational equation:

(x/(2x + 1)) - (1/4) = 2/(2x + 1)

First, let's find a common denominator for the fractions on the left side. The common denominator is 4(2x + 1):

[(x * 4) - (1 * (2x + 1))] / (4(2x + 1)) = 2 / (2x + 1)

Simplifying the numerator:

(4x - (2x + 1)) / (4(2x + 1)) = 2 / (2x + 1)

Combining like terms:

(4x - 2x - 1) / (4(2x + 1)) = 2 / (2x + 1)

(2x - 1) / (4(2x + 1)) = 2 / (2x + 1)

Now, we can cross-multiply:

(2x - 1) * (2x + 1) = 2 * (4(2x + 1))

Expanding and simplifying both sides:

\((4x^2 - 1) = 8(2x + 1)\\4x^2 - 1 = 16x + 8\)

Rearranging the equation to set it equal to zero:

\(4x^2 - 16x - 9 = 0\)

Now, we can solve this quadratic equation. Using factoring, completing the square, or the quadratic formula, we find that the solutions are:

x = (-(-16) ± √((-16)² - 4 * 4 * (-9))) / (2 * 4)

x = (16 ± √(256 + 144)) / 8

x = (16 ± √400) / 8

x = (16 ± 20) / 8

x = 36/8 or -4/8

Simplifying the fractions:

x = 9/2 or -1/2

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Answer:

A one tailed test

Step-by-step explanation:

Chi-Square Distributions That Are Positively Skewed Have A Research Hypothesis That Is A One-Tailed Test.

Chi-Square distributions are positively skewed, with the degree of skew decreasing with increasing degrees of freedom.

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One-Tailed Test

Chi-Square distributions that are positively skewed have a research hypothesis that is a One-Tailed Test.

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Therefore, the correct answer is (A).

To parameterize the portion of the plane

\(�+�+�=\)

4

x+y+z=4 that lies in the first octant, we need to find expressions for

\(�x, �y, and �\)

z in terms of parameters

\(�u and �v\)

that satisfy the given conditions.

In the first octant, all three coordinates,

\(�x, �y, and �z,\)

are positive.

Let's consider the parameterization options provided:

\((A) (�,�,4−�−�)(u,v,4−u−v), 0≤�≤10≤u≤1, 0≤�≤10≤v≤1\)

This parameterization satisfies the equation of the plane

\(�+�+�=4x+y+z=4, and the conditions �≥0x≥0, �≥0y≥0, �≥0z≥0\) for the first octant. So, option (A) is a valid parameterization.

To confirm, let's substitute the expressions for

\(�x, �y, and �\)

z into the equation of the plane:

\(�+�+�=�+�+4−�−�=4x+y+z=u+v+4−u−v=4\)

The equation holds true, so option (A) is a valid parameterization for the portion of the plane

\(�+�+�=4x+y+z=4\)that lies in the first octant.

Therefore, the correct answer is (A).

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Answer:

He did not simplify correctly and forgot to place the decimal point correctly.

Step-by-step explanation:

To simplify the equation, one needs to divide both sides of the equal sign by 5.

i.e 5.25/5=5/5

Here we find 1.05=1

Note the placement of the decimal point.

Answer:

2m = m + m

2m = 2m

Step-by-step explanation:

hope that will help you

Nice time

When an aabbccddeeff individual is crossed with an individual with the genotype aabbccddeeff, the probability that their offspring will have the genotype aabbccddeeff would be 1/64.

The genotype of an organism refers to the complete set of genetic material. An offspring's genotype is the result of the combination of genes from their parents.  In order to obtain the overall probability, individual probabilities for each locus will be multiplied. The Parent cross would be AABbccDdEeFF x AaBBCCDdEeff and offspring would be AaBbCcddEEFf.

Multiplying all the probability:

½ * ½ * 1 * ¼ * ¼ * 1 = 1/64

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The ground do the ropes intersect each other is at 4 ft.

AB and ED are the poles (perfectly vertical). BE and DA are the ropes that cross at C.

F is the point directly below C on the ground (line AE), which is perfectly flat and horizontal.

The vertical poles are part of parallel lines.

As a consequence, triangles ABC and DEC have congruent angles at B and E, and at A and D (alternate interior). Of course, ABC and DEC also have congruent angles at C (vertical angles).

Triangles ABC and DEC are similar, with corresponding sides in the ratio 2:1

\(\frac{AB}{DE}= \frac{BC}{EC}= \frac{AC}{DC}= \frac{2}{1}\)

In particular,

BC = 2EC and BE = BC + EC = 2EC + EC = 3EC

Right triangles ABE and FCE, with the same angle at E, are also similar, so

\(\frac{AB}{FC}= \frac{BE}{CE}= \frac{3EC}{EC3.1}\) --> AB = 3FC --> \(FC = \frac{AB}{3}= \frac{12 ft}{3} = 4ft\)

The ropes cross 4 ft above the ground.

Hence the answer is the ground do the ropes intersect each other is at 4 ft.

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Answer:

I think the choose A. ASA

Because they mark two angles and an side between them

I hope I helped you^_^

These triangles are congruent by the triangle postulate ASA.

Option A is the correct answer.

It is a two-dimensional figure which has three sides and the sum of the three angles is equal to 180 degrees.

We have,

From the two similar triangles.

There are two corresponding angles and one corresponding side that are equal.

We see that,

The side is between the two angles.

So,

ASA = Angle - Side - Angle

This postulate is used.

Thus,

These triangles are congruent by the triangle postulate ASA.

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Answer:

D

Step-by-step explanation:

Option A is $6 for two pounds of apples, option B is $5.50 for two pounds of apples, option C is $5.80 for two pounds of apples, and option D is $6.50 for two pounds of apples (9.75/3=3.25x2=6.5). Therefore D is the most expensive.

I hope this helps :)

Answer:

How are we supposted to do your homework if we dont have a picture or explanation of it??

Step-by-step explanation:

The process of adding the matrix is explained blow.

Matrices are powerful tools used to analyze data and solve complex equations.

A 3x3 matrix, or E₁₃, is a matrix composed of 3 rows and 3 columns. It can be used to perform various operations, including adding two rows together.

(a) To answer the first question, a 3x3 matrix E₁₃ can add row 3 to row 1 by performing a row operation. This involves taking the second row and adding it to the first, thus adding the values on each row together.

(b) To answer the second question, a 3x3 matrix E₁₃ can add row 1 to row 3 and at the same time add row 3 to row 1 by performing a row exchange operation. This results in a 3x3 matrix where each value in the first row is equal to the corresponding value in the third row.

(c) To answer the third question, a 3x3 matrix E₁₃ can add row 1 to row 3 and then add row 3 to row 1 by performing two separate row operation and then taking the third row and adding it to the first, thus adding the values of each row together again.

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The position value, r(t) is equals to the (t³/6)k + 2j and velocity value, v(t) is equals to ( t²/2 )k + 4i , for a(t) = tk, v(0) = 4i, r(0) = 2j.

Acceleration is defined as the rate of change of the velocity of an object with respect to time. Accelerations are vector quanty.

a = dv/dt

We have the following informations are available,

Initial velocity, v(0) = 4i

Initial position, r(0) = 2j

Acceleration at any time "t",

a(t) = tk

we have to determine the value of v(t) and r(t).

As we know, a(t) = dv(t)/dt = tk

integrating the above equation ,

v(t) = ∫tk dt = ( t²/2 )k + c

at t = 0 , v(0) = 0 + c = 4i ( since, v(0) = 4i

=> c = 4i

So, v(t) = ( t²/2 )k + 4i

Also, velocity is calculated by derivative of postion (r) with respect to time.

=> v(t) = dr(t) /dt

=> r(t) = ∫ v(t) dt

=> r(t) = ∫ ( t²/2 )k dt

integrating value of the right hand side,

r(t) = ( t³/2×3 )k +d

= (t³/6)k + d

At t = 0, r(0) = (0/6)k + d

=> r(0) = d = 2j

so, r(t) = (t³/6)k + 2j

Hence, the required position and velocity are

(t³/6)k + 2j and ( t²/2 )k + 4i.

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Answer:

24

Step-by-step explanation:

if he can make 4 birdhouses in 1 1/2 hours, 1 1/2 hours x 2 = 3. 8 birdhouses per 3 hours. 3 x 3 = 9 hours, 8 x 3 = 27

Answer:

24 birdhouses

Step-by-step explanation:

This is a proportional relationship.  y = kx, where k is the constant of proportionality.  We can determine k as follows:

4 birdhouses = k(1 1/2  hours), which leads to:

  4 birdhouses

------------------------- = 8/3 birdhouses/hr

    3/2 hours

In 9 hours, Ben can make (8/3)(9) birdhouses:  24 birdhouses

Answer:

-3(2x+3)=21 does not become -6x+9=21 because wrong foiling.

Step-by-step explanation:

When you distribute -3 with 2x+3 you multiply both values by -3.

-3*2x = -6x

-3*3 = -9 <- This is where the error is. It's -9, not +9.

The percent change in height after the second bounce would be:

Percent change = [(h_2 - h_1) / h_1] * 100%

The expression \(25(0.93)^x\)represents the height of the ball after x bounces. To find the percent change in height after each bounce, we need to calculate the ratio of the change in height to the original height and express it as a percentage.

Let's denote the height after the first bounce as h_1, the height after the second bounce as h_2, and so on.

The percent change in height after the first bounce is given by:

Percent change = [(h_1 - original height) / original height] * 100%

Using the given expression, we can substitute x = 1 to find h_1:

h_1 = \(25(0.93)^1\) = 23.25

Therefore, the percent change in height after the first bounce is:

Percent change = [(23.25 - original height) / original height] * 100%

To find the percent change after subsequent bounces, we can continue this process. For example, after the second bounce:

h_2 = \(25(0.93)^2\)

And the percent change in height after the second bounce would be:

Percent change = [(h_2 - h_1) / h_1] * 100%

You can repeat this process for each subsequent bounce to find the percent change in height after each bounce using the given expression.

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Answer:

i think it's 9

Step-by-step explanation:

A=126cm÷by one diagonal 14

=9

Answer:

Yes, because lines m1 and m2 have the same slope of -2

Step-by-step explanation:

For given two lines L1 and L2 with slope m1 and m2 respectively, the condition for the two lines to be parallel is for the two equations to have the same slope. If m1 = m2, the meaning is that the line L1 and L2 are parallel to each other no matter the equation of the lines in question.

The general equation of a line is y = mx+c where;

m is the slope and c is the intercept.

Even though we are not given the equation of both lines, the base line is that for two lines to be parallel to each other, they must have the same slope.

The correct option is therefore "Yes, because lines m1 and m2 have the same slope of -2"

Answer:

d only.

Step-by-step explanation:

lol i know ur map testing, i had the same question yesterday

Answer:

a. the constant is y

b. three terms

c. -7

d. +6y

The alternative hypothesis would be: The proportion of BYU students who identify as Democrat and support the death penalty is significantly less than the proportion of BYU students who identify as Republican and support the death penalty.

The alternative hypothesis for this test would be: The proportion of BYU students who identify as Democrat and support the death penalty (p1) is less than the proportion of BYU students who identify as Republican and support the death penalty (p2). Mathematically, it can be written as:

H1: p1 < p2

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Here, x = 6 is a vertical asymptote of f, so the function approaches infinity as x approaches 6 from both sides.

Let's start by integrating f'(x) to get f(x). We have:

f'(x) = 16(x+2)(6-x)³ - 32(x+6)

Integrating both sides with respect to x:

f(x) = ∫[16(x+2)(6-x)³ - 32(x+6)] dx

Simplifying the integral, we get:

f(x) = -2(x+2)²(6-x)⁴ + 16(x+6) + C

where C is the constant of integration.

Next, we can find the critical points of f(x) by setting f'(x) = 0:

f'(x) = 16(x+2)(6-x)³ - 32(x+6) = 0

Solving for x, we get x = -2 and x = 6 as critical points.

Now, we can use the second derivative f''(x) to determine the concavity of the function. We have:

f''(x) = (6x-x)⁴ = x⁴

Since the second derivative is always positive for x > 0, the function is concave up on the interval (6, ∞).

Similarly, since the second derivative is always negative for x < 0, the function is concave down on the interval (-∞, -2).

At x = -2 and x = 6, the function has an inflection point.

Finally, we know that x = 6 is a vertical asymptote of f, so the function approaches infinity as x approaches 6 from both sides.

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Answer:

1200 centimeters

Step-by-step explanation:

if you have 100 centimeters in 1 meter and there are 12 meters you can just multiply the number of centimeters by 12 or whatever number is needed in this case 12 so when you multiply 12 x 100 you get 1200

Step-by-step explanation:

Divide each term by 3 and simplify. x = 2

Answer:

Step-by-step explanation:

Answer:

1) N^2 + 1

2) 5*N - 9

3) n*5 + 1    (con n entero)

4) n*2 + 1    (con n entero)

Step-by-step explanation:

1)  El cuadrado de un número aumentado en 1.

Podemos definir a N como el número.

El cuadrado de N es:

N^2

Y a esto lo tenemos que aumentar en 1, entonces tenemos:

N^2 + 1

Esto es el cuadrado de un número aumentado en 1.

2)  Cinco veces un número menos 8.

Esto es:

5*N  (5 veces un número)

Y a esto le restamos 8, para obtener:

5*N - 8

3) El número siguiente a un múltiplo de 5

Un multiplo de 5 se escribe como:

n*5

Donde n es un número entero.

El numero siguiente es:

n*5 + 1

4) Un número impar.

Bien, sabemos que un número par es un multiplo de 2.

Entonces:

n*2 es un número par.

Entonces, n*2 + 1 tiene que ser un numero impar.

En este caso la expresión algebraica es:

n*2 + 1

Answer:

Step-by-step explanation:

Volume of cuboid = AC x CD x CG. (Cuboid formula is l x b x h)

Now, given, area of ABCD is 25.

Area of square = a² or AC x CD

Therefore, substituting that in the first line, we get,

25 x CG = volume,

or 25 x 12 = 300 cm³. (Given CG is 12cm)

The correct value of p(x<8) is 1.875.

To determine how probable something is gonna occur, use probability. It is a number between 0 and 1, where 0 denotes the absence of a possibility and 1 denotes the existence of one. By dividing the number of favorable outcomes by the entire number of potential possibilities, the probability of an occurrence is determined.

To find the probability that is greater than 8, we need to integrate this probability density function from 5.5 to 20.5:

P(X < 8) = ∫[5.5,20.5] f(x) dx

= ∫[5.5,20.5] (1/8) dx

= [x/8] from 5.5 to 20.5

= (20.5/8) - (5.5/8)

= 15/8

= 1.875.

Therefore, the correct probability is 1.875.

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The amount that needs to be paid for purchasing 2/4 of sugar when the cost of a kilogram is $47.00 is $23.50.

Given that we buy 2/4 of sugar and the cost of a kilogram is $47.00.

We need to find the total cost of sugar purchased.

First, we need to convert the given fraction to a decimal;

that is 2/4 = 0.5.

The amount of sugar purchased is 0.5 kilogram.

To find the total cost, we multiply the amount of sugar purchased by the cost per kilogram.

Total cost of sugar purchased = Amount of sugar purchased x Cost per kilogram

                                                  = 0.5 x $47.00

                                                  = $23.50

Therefore, the amount that needs to be paid for purchasing 2/4 of sugar when the cost of a kilogram is $47.00 is $23.50.

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To find the class limits for a frequency distribution with a class width of 46 and the first lower class limit of 70, we can determine the upper class limits for each class.

Given:

Class width = 46

First lower class limit = 70

To find the upper class limits, we add the class width to each lower class limit.

First class:

Lower class limit = 70

Upper class limit = Lower class limit + Class width = 70 + 46 = 116

Second class:

Lower class limit = 116 (previous class's upper class limit)

Upper class limit = Lower class limit + Class width = 116 + 46 = 162

Third class:

Lower class limit = 162 (previous class's upper class limit)

Upper class limit = Lower class limit + Class width = 162 + 46 = 208

And so on...

Using this pattern, we can determine the class limits for the remaining classes:

Class 1: 70 - 116

Class 2: 116 - 162

Class 3: 162 - 208

Class 4: 208 - 254

Class 5: 254 - 300

Class 6: 300 - 346

Class 7: 346 - 392

Therefore, the class limits for the frequency distribution with 7 classes are as follows:

Class 1: 70 - 116

Class 2: 116 - 162

Class 3: 162 - 208

Class 4: 208 - 254

Class 5: 254 - 300

Class 6: 300 - 346

Class 7: 346 - 392

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